Is vinegar and rubbing alcohol soluble or insoluble?
Iodine shines like metals but is not metal what is its basis
Answer:
Iodine is a non-metal, but it is lustrous (lustrous is the property of metal) in nature.
A mixture of 2.0 moles of H2, 2.0 moles of NH4, 4.0 moles of CO2, and 5.0 moles of
N2 exert a total pressure of 800 torr. What is the partial pressure of each gas in the
mixture respectively?
Answer:
0.01125
Explanation:
:b
Which measurement occurs last when collecting data to determine the
percentage by mass of a solution?
mass percent = (mass of element in 1 mole of compound / mass of 1 mole of compound) x 100. The formula for a solution is:
mass percent = (grams of solute / grams of solute plus solvent) x 100. or.
mass percent = (grams of solute / grams of solution) x 100. The final answer is given as %.
Hope this helps!!
The oxidation state for Cl is A. -1 as a reactant and +1 as a product B. -1 as a reactant and 0 as a product C. -1 as a reactant and -1 as a product D. +1 as a reactant and +1 as a product
Answer:
no sure
Explanation:
Given the following chemical reaction:
N2 + 202 --> 2 NO2
How many liters of N2 are needed to react with 10 liters of Q? Explain
Answer:
1
Explanation:
one volume of nitrogen to react
8. The density of a gas at 350 C is 0,087 g/L. Compute the density at STP.
Answer:
0.20 g/L
Explanation:
Step 1: Calculate the molar mass of the gas (M)
At T = 350 °C = 623 K and P = 1 atm (we will assume this data), the density (ρ) of the gas is 0.087 g/L. We can calculate the molar mass of the gas using the following expression.
ρ = P × M/R × T
M = ρ × R × T/P
M = 0.087 g/L × (0.0821 atm.L/mol.K) × 623 K/1 atm = 4.5 g/mol
Step 2: Calculate the density of the gas at STP
At standard temperature (T = 273.15 K) and standard pressure (P = 1 atm), the density of the gas is:
ρ = P × M/R × T
ρ = 1 atm × 4.5 g/mol /(0.0821 atm.L/mol.K) × 273.15 K = 0.20 g/L
Which of the following is a job that bones do?
a.provide the body with shape and protection
b.store minerals
c.produce supply of daily blood cells
d.all of the above
Answer:
a.Provide the body which shape and protection.
Explanation:
Bones usually gives us shape as well as protects our innner organs.
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Energy resources are required for which of the following ?
Answer: An energy resource is something that can produce heat, power life, move objects, or produce electricity
160 mL of a 37.5 % (m/v) LiNO3 solution
Answer:
60g of LiNO3 are required
Explanation:
Calculate the amount of solute, in grams or milliliters, to prepare...
The percentage mass/volume %(m/v) is defined as the mass in grams of the solute in 100mL of solution
To solve this question we must know that in a 37.5% (m/v) of LiNO3 you have 37.5g of LiNO3 in 100mL of solution.
Thus, to prepare 160mL are required:
160mL * (37.5g / 100mL) =
60g of LiNO3 are requiredHow many grams of calcium chloride would be dissolved in 1.0L of a 0.10m solution of calcium chloride?
Answer:
2365 g
Explanation:
What is another name for a mole?
O A. Rutherford's number
O B. Mendeleev's number
O C. Dalton's number
D. Avogadro's number
Answer: D Avogadro’s Number
Explanation:
Another name for a mole is Avogadro's number. option D) is correct.
What is a Mole?
A mole refers to the amount of a substance that contains as many elementary units as can be found in 12g of Carbon-12. It can also be a number of a substance /particles, such as atoms or ions. molecules or electrons. The number of particles is approximately 6.02* 10²³ in magnitude and is called Avogadro's number of particles. it can be denoted with 'mol'.
Formula for calculating mole.
n = N/Nₐ
Where,
n = number of moles of the substance (or elementary entity)
N = total number of elementary entities in the sample
Nₐ= Avogadro constant.
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In the context of a balanced chemical equation, a____is a number to the lower right of an element or ion within formula and it applies to____. A____is a number to the left of a formula and it applies to_____. Only_____should be added or changed when balancing chemical equations.
Answer:
Explanation:
The preceding chapter introduced the use of element symbols to represent individual atoms. When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. Extending this symbolism to represent both the identities and the relative quantities of substances undergoing a chemical (or physical) change involves writing and balancing a chemical equation. Consider as an example the reaction between one methane molecule (CH4) and two diatomic oxygen molecules (O2) to produce one carbon dioxide molecule (CO2) and two water molecules (H2O). The chemical equation representing this process is provided in the upper half of Figure 1, with space-filling molecular models shown in the lower half of the figure.
The parts of DNA that give instructions for making proteins are called ________.
a genes
b dominant trait
c recessive trait
d mutation
Answer:
A
Explanation:
Each DNA sequence that contains instructions to make a protein is known as a gene. The size of a gene may vary greatly, ranging from about 1,000 bases to 1 million bases in humans.
Describe two realistic demands protestors could bring forward in their peaceful protest so that they dont face the same situation in future
Answer:
I do not know the Answer I'm just trying to get my point
Explanation:
Thank You
The two realistic demands protestors could bring forward in their peaceful protest include:
Adequate securityProvision of social amenities.Who is a Protester?Thus it is referred to an individual which publicly demonstrates opposition to something.One of the roles of the government is to protect lives and properties.
Making realistic demands during a peaceful protest is looked into in most cases.
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What is the scaling factor if the molar mass of
this compound, having an empirical formula of
ch2o, is 150 g/mol?
Answer:
The scaling factor is 5.
Explanation:
Hello there!
In this case, since the scaling factor is defined as the ratio of the molar mass of the molecular formula (complete) to the empirical formula (simplified), it is possible to compute it for the empirical formula of CH2O whose molar mass is 30 g/mol (12+2+16) as shown below:
[tex]sf=150/30=5[/tex]
Therefore, we can also infer that the molecular formula would be:
[tex]C_5H_1_0O_5[/tex]
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5. What physical property of foam makes it a good choice to
use in life vests?
A. Foam has a relative density less than water.
B. Foam is a good thermal insulator.
C Foam is non-magnetic.
D. Foam is soluble in water.
A compound with an approximate molar mass of
65.0g/mol is made up of C, H and Cl. This same
Compound contains 55% of Cl by mass .lf 9g
of the compound contains 4.19 x 10²³ atoms,
determine the compound's:
a empirical formular and molecular formular
2) A balloon was inflated to a volume of 5.0 liters at a temperature of
7.0°C. It landed in an oven and was heated to 147°C. What is its new
volume?
Answer:
[tex]V_1=7.5L[/tex]
Explanation:
Hello there!
In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:
[tex]\frac{V_2}{T_2}= \frac{V_1}{T_1}[/tex]
Thus, by solving for the initial volume, V1, and making sure we use the temperatures in Kelvin, we can calculate the final volume as shown below:
[tex]V_1= \frac{V_2T_1}{T_2} \\\\V_1= \frac{5.0L*(147+273)K}{(7.0+273)K} \\\\V_1=7.5L[/tex]
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Is anyone good at chemistry if so can someone help me please ?
(NO LINKS)
As provided in the question, the pH of a solution is equal to the negative logarithm of the H₃O⁺ concentration in the solution (the square brackets denote the molar concentration).
We are given a solution with an H₃O⁺ concentration of 5.6 × 10⁻⁹ M. So, the pH of this solution would be:
pH = -log[H₃O⁺] = -log(5.6 × 10⁻⁹ M) = 8.25.
A pH that is equal to 7 is neutral; less than 7, acidic; and greater than 7, basic. As 8.25 is greater than 7, this solution is basic.
What mineral property is being tested below?
Answer:
Streak
Explanation:
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A rigid, insulated vessel is divided into two compartments connected by a valve. Initially, one compartment, occupying one-third of the total volume, contains air at 500oR, and the other is evacuated. The valve is opened and the air is allowed to fill the entire volume. Assuming the ideal gas model with variable specific heats. Determine: a. the final temperature of the air (in oR) b. the amount of specific entropy produced (in Btu/lbm oR)
Answer:
a) the final temperature of the air is 500° R
b) the amount of specific entropy produced is 0.0758 Btu/lb-°R
Explanation:
Given the data in the question;
Air at 500° R = [tex]T_i[/tex]
Using first law of thermodynamic;
δQ = dU + W
now, since the vessel is insulated, the transfer is zero, work done also is zero since there is also no external work done.
δQ = dU + W
0 = dU + 0
dU = 0
[tex]u_f[/tex] - [tex]u_i[/tex] = 0
[tex]u_f[/tex] = [tex]u_i[/tex]
hence, change in internal energy is 0
Now, since the ideal internal energy is a function of temperature, the temperature will also remain the same;
[tex]T_f = T_i[/tex]
F = 500° R
Therefore, the final temperature of the air is 500° R
b)
given that; initial volume is one-third of the total volume
V₁ = [tex]\frac{1}{3}[/tex]V₂
3V₁ = V₂
3 = V₂/V₁
Now, we take the value of gas constant R from air property table; gas constant R = 0.069 Btu/lb-R
so we calculate the entropy change;
Δs = [tex]c_v[/tex]In( [tex]\frac{T_2}{T_1}[/tex] ) + R.In( [tex]\frac{V_2}{V_1}[/tex] )
we substitute
Δs = [tex]c_v[/tex]In( [tex]\frac{500}{500}[/tex] ) + 0.069 × In( 3 )
Δs = 0 + [0.069 × In( 3 )]
Δs = 0 + [0.069 × 1.0986]
Δs = 0.0758 Btu/lb-°R
Therefore, the amount of specific entropy produced is 0.0758 Btu/lb-°R
Insulated vessels separate the environment of the outer and the inner system. The final temperature is 500 degrees R and 0.0758 Btu/lb- degree R is the entropy.
What is temperature?The temperature is the measure of the hot or the coldness of the system. The first law of the thermodynamics is used to measure the final temperature of the system:
[tex]\rm \Delta Q = \rm \Delta U + W[/tex]
The work done will be zero as the system is insulated and no external work is being done.
[tex]\begin{aligned} \rm 0 &= \rm \Delta U + 0\\\\\rm U_{f} - U_{i} &= 0\\\\\rm U_{f} &= \rm U_{i} \end{aligned}[/tex]
Hence, the change in the internal energy is zero. Thus, the final temperature will remain the same,
[tex]\rm T_{f} = \rm T_{i} = 500 ^{\circ} \rm R[/tex]
Now, as we know, the initial volume is one-third of the total volume then,
[tex]\begin{aligned} \rm V_{1} &= \rm \dfrac{1}{3} V_{2}\\\\\rm 3V_{1}&= \rm V_{2}\\\\3 &= \rm \dfrac{V_{1}}{V_{2}}\end{aligned}[/tex]
The change in entropy is calculated as:
[tex]\begin{aligned} \rm \Delta S &= \rm C_{v} ln ( \dfrac{T_{2}}{T_{1}}) + R \times ln ( \dfrac{V_{2}}{V_{1}}) \\\\&= 0 + [0.069 \times \rm ln( 3 )]\\\\& = 0.0758 \;\rm Btu/lb-^{\circ}R \end{aligned}[/tex]
Therefore, the entropy produced is 0.0758 Btu/lb- degree R.
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What kind of intermolecular forces act between a nitrogen trichloride molecule and a hydrogen sulfide molecule
Answer:
Dipole induced dipole force of attraction.
Explanation:
This is because dipole induced dipole attraction is a weak force of attraction or london force that occur when a polar molecule causes a form induction in a dipole in an atom or in a nonpolar molecule by altering the arrangement non polar electrons.
why can't we humans live without oxygen? Can't we rely on something else? Why? Why oxygen out of all?
Answer:
because we need it to breathe
Explanation:
we breathe in oxygen and release carbon dioxide
Answer:
Ok i have a really weird theory.
Oxygen actually kills us we just don't know it yet. We need it too live but something in it also poisons us and causes us to die in around 100 years from birth. that's why we all die
real answer
we need it to breathe, when we breath we inhale in oxygen and release carbon dioxide which allows trees to grow and they produce more oxygen. We cant rely on anything else because oxygen is important and without it we die. Oxygen is one of the purist airs.
3.88g of NaOH is required to neutralize a spill of hydrochloric acid. A 0.516M solution of NaOH is available for use.
A. Determine the number of moles needed to complete the reaction.
B. What volume of NaOH solution is needed for this reaction?
C. What volume of a stock 1,15M solution would be used to make the solution used in the reaction?
Answer:
ftb
Explanation:
HELP I DON'T HAVE LONG LEFT AND I'M STRUGGLING SO BAD PLEASE I BEG U TO HELP
Please balance the equation C7H16 + CoF3 = C7F16 + HF +CoF2
with solutions
b. how many grams of CH6 is needed to react with 20.0 grams of HF?
C. how many particles of CoF3 is needed to react with 40.0 grams of CzF16?
d. how many grams of CH16 will be produce from 2.03 x 10 molecule of CoFs?
e. Find the Limiting reactant and exXcess reactant in CF16?
6g of CH16
6g of CoFa
f. Find the theoretical yield from CzFi6?
g. What is the percent yield of C;F16 if the actual yield is 1.28 g ?
How many grams of nitrogen in 7.3 x 10^24 molecules of NaNO3
Answer:
Explanation:
Convert molecules to moles:
1 mole of NaNO₃= 6.02 x 10^23 molecules of NaNO₃
7.3 x10^24/(6.02 x 10^23)=12mol NaNO₃
Find molar mass:
NaNO₃=1 mole of Na and 1mole of N and 3mole of O
Find grams:
14.01g x 12= 168.12 g of N
Which of the following descriptions is correct?
А. a mixture consists of two or more pure substances which can only be separated by chemical methods
B. a colloid is a 'cloudy' mixture containing particles which will not easily settle out when the colloid is left standing
C. a solution consists of a solvent dissolved in a solute
D. a suspension contains particles which will not settle out if the suspension is left standing
C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion
Answer:
[tex]\Delta H_{comb}=2043.85kJ/mol[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:
[tex]\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}[/tex]
Thus, given the values of the enthalpies of formation on the attached file, we obtain:[tex]-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol[/tex]
Best regards!