Can someone please help me ASAP? It’s due tomorrow. I will give brainliest if it’s correct.

Can Someone Please Help Me ASAP? Its Due Tomorrow. I Will Give Brainliest If Its Correct.

Answers

Answer 1

The probability values when calculated are

P(2 numbers greater than 3) = 0.1P(2 even numbers) = 0.4P(2 cards with same numbers) = 0P(1 card is 3) = 0.3

Evaluating the probability values

From the question, we have the following parameters that can be used in our computation:

Cards = {1, 2, 3, 4, 5}

Selecting two cards without replacement

So, we have

P(2 numbers greater than 3) = 2/5 * 1/4

P(2 numbers greater than 3) = 0.1

P(2 even numbers) = 2/5 * 4/4

P(2 even numbers) = 0.4

P(2 cards with same numbers) = 1/5 * 0/4

P(2 cards with same numbers) = 0

P(1 card is 3) = 2 * 1/5 * 3/4

P(1 card is 3) = 0.3

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Related Questions

Cassandra obtains a loan with simple interest to buy a car that costs $8,500. if cassandra pays $1,020 in interest during the four-year term of the loan, what was the rate of simple interest?


a. 8. 3%


b. 3%


c. 0. 03%


d. 12%

Answers

d 12% BECUASE ITS GOOD AND SMART

16


Last Us


A spherical exercise ball has a maximum diameter of 30 inches when filled with air. The ball was completely empty


at the start, and an electric air pump is filling it with air at the rate of 1600 cubic inches per minute.


The formula for the volume of a sphere is 4*


Part A


Enter an equation for the amount of air still needed to all the ball to its maximum volume, y, with respect to the


number of minutes the pump has been pumping air into the ball, X.


Part 8


Enter the total amount of air, in cubic inches, still needed to fill the ball after the pump has been running for 4


minutes


Part C


Enter the estimated number of minutes it takes to pump up the ball to its maximum volume.

Answers

Part A: The equation for the amount of air still needed is: y = 14,137.17 - 1600X

Part B: The total amount of air still needed to fill the ball after 4 minutes is 8,937.17 cubic inches.

Part C: It takes approximately 8.84 minutes to pump up the ball to its maximum volume.

Part A:

The formula for the volume of a sphere is 4/3πr³, where r is the radius. Since the maximum diameter of the exercise ball is 30 inches, its radius is 15 inches. Therefore, the maximum volume of the ball is:

4/3π(15)³ = 14,137.17 cubic inches

Let's let y represent the amount of air still needed to fill the ball to its maximum volume, and X represent the number of minutes the pump has been running. We know that the pump is filling the ball at a rate of 1600 cubic inches per minute. Therefore, the equation for the amount of air still needed is:

y = 14,137.17 - 1600X

Part B:

After 4 minutes, the pump has filled the ball with:

1600 x 4 = 6400 cubic inches

Using the equation from Part A, we can find the amount of air still needed after 4 minutes:

y = 14,137.17 - 1600(4) = 8,937.17 cubic inches

Therefore, the total amount of air still needed to fill the ball after 4 minutes is 8,937.17 cubic inches.

Part C:

To find the estimated number of minutes it takes to pump up the ball to its maximum volume, we can set the equation from Part A equal to 0 (since y represents the amount of air still needed):

0 = 14,137.17 - 1600X

Solving for X, we get:

X = 8.84

Therefore, it takes approximately 8.84 minutes to pump up the ball to its maximum volume.

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A phone company set the following rate schedule for an m-minute call from any of its pay phones.what is the cost of a call that is under six minutes?​

Answers

For calls that are 6 minutes less, the rate is $0.70 per minute.

To find the cost of a call that is under 6 minutes, we simply need to use the first part of the rate schedule.

Let's say the call lasts for m minutes. Since m is less than or equal to 6, we can use the first part of the rate schedule, which gives us

c(m) = $0.70 per minute

So the cost of the call is simply the rate per minute times the number of minutes

c(m) = $0.70 × m

For example, if the call lasted 4 minutes, the cost would be

c(4) = $0.70 × 4 = $2.80

Therefore, the cost of a call that is under 6 minutes is simply $0.70 per minute.

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--The given question is incomplete, the complete question is given

" A phone company set the following rate schedule for an m-minute call from any of its pay phones.

c(m)=

{0.70    when m≤6

0.70+0.24(m−6)   when m>6 and m is an integer

0.70+0.24([m−6]+1)    when m>6 and m is not an integer }

what is the cost of a call that is under six minutes?​"--

What are the area and perimeter of rectangle MNOP

Answers

Answer :

Area of Rectangle = 48 sq. unitsPerimeter of rectangle = 28 units

Step-by-step explanation:

We are give with a rectangle MNOP.

As we can see from above graph,

Length of MN = 8 units

Length of MO = 6 units

MN = Length MO = Breadth

We know that

Area (rectangle) = length × breadth

area = 8 × 6

area = 48 sq. units

Now, Let's calculate the perimeter of the rectangle.

Perimeter (rectangle) = 2(l + b)

Substituting the values,

Perimeter= 2(8 + 6)

Perimeter = 2 × 14

Perimeter = 28 units

Please answer 1-9, i really need help tysm

Answers

Answer:

the answer is 8

Step-by-step explanation:

it is because if you take your 9 fingers and remove 1 finger it will be 8

21. How many times larger is the volume of a cone if the height is multiplied by 3?

Answers

Answer:

If the height is tripled and the radius remains constant, then the volume will be tripled or multiplied by 3.

Step-by-step explanation:

An example proving this:

Fill the cones with water and empty out one cone at a time. Each cone fills the cylinder to one-third quantity. Hence, such three cones will fill the cylinder. Thus, the volume of a cone is one-third of the volume of the cylinder.

So, the height is divided by three in the volume formula. Therefore, it is to be proven that if the height of a cone is tripled and the radius remains constant, the volume would also be tripled.

25. a state study on labor reported that one-third of full-time teachers in the state also worked part time at another job. for those teachers, the average number of hours worked per week at the part-time job was 13. after an increase in state teacher salaries, a random sample of 400 teachers who worked part time at another job was selected. the average number of hours worked per week at the part-time job for the teachers in the sample was 12. 5 with standard deviation 6. 5 hours. is there convincing statistical evidence at the level of 0. 05, that the average number of hours worked per week at part-time jobs decreased after the salary increase? (a) no. the p-value of the appropriate test is greater than 0. 5. (b) no. the p-value of the appropriate test is less than 0. 5. (c) yes. the p-value of the appropriate test is greater than 0. 5. (d) yes. the p-value of the appropriate test is less than 0. 5. (e) not enough information is given to determine whether there is convincing statistical evidence

Answers

From the solution to the question that we have here, the answer is A. There is no solid proof that the number of hours worked dropped after the income rise.

Let μ be the population mean number of hours worked per week by teachers who work part-time jobs, after the salary increase. Here are the alternate and null hypotheses:

H0: μ = 13

H1: μ < 13

n = 400

[tex]\bar{X}=12.5[/tex]

μ = 13

Formula for the t-test statistics is

[tex]t = \frac{\bar{X}-\mu}{s/\sqrt{n} }[/tex]

t = (12.5 - 13)/(6.5/√400)

t = (- 0.5)/(6.5/20)

t = - 10/6.5

= -1.5388

Degree of freedom is 400 -1 = 399

α = 0.05

The p-value is p(t < -1.5385) = 0.062

The p-value exceeds the level of significance. Therefore, we unable to reject the null hypothesis.

Hence, option a is correct.

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The owner of a sports complex wants to carpet a hallway connecting two buildings. The carpet costs $2. 50 per square foot. How much does it cost to carpet the hallway?

Answers

If the area of the hallway is 250 square feet, it would cost $625 to carpet the hallway with $2.50 per square foot carpet.

To find the cost of carpeting the hallway, we need to know the area of the hallway first. Let's assume that the length of the hallway is 50 feet and the width is 5 feet.

The area of the hallway = length x width
= 50 feet x 5 feet
= 250 square feet

Now that we know  we can find the cost of carpeting it.

Cost of carpeting = area x cost per square foot
= 250 square feet x $2.50 per square foot
= $625

Therefore, it would cost $625 to carpet the hallway with $2.50 per square foot carpet.

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Find the mass of the thin bar with the given density function p(x) = 2 + x^2; for 0 ≤ x ≤ 1 О 0 O 7/3
O-2 O 2

Answers

The mass of the thin bar with the given density function is 7/3.

To find the mass of the thin bar with the given density function p(x) = 2 + x^2 for 0 ≤ x ≤ 1:

You need to integrate the density function over the given interval.

Here are the steps to do that:

STEP 1: Set up the integral for mass:

Mass = ∫(density function) dx from x = 0 to x = 1
STEP 2:Plug in the given density function:

Mass = ∫(2 + x^2) dx from x = 0 to x = 1
STEP 3:Integrate the function with respect to x:

Mass = [2x + (x^3)/3] evaluated from x = 0 to x = 1
STEP 4: Evaluate the integral at the limits:

Mass = (2(1) + (1^3)/3) - (2(0) + (0^3)/3)
STEP 5: Simplify the expression:

Mass = (2 + 1/3) - 0
STEP 6: Calculate the final mass:

Mass = 2 + 1/3 = 7/3

So, the mass of the thin bar with the given density function is 7/3.\

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QuestionThe mean monthly salary of the 12 employees of a firm is Rs. 1450. If one more person joins the firm who gets Rs. 1645 per month, what will be the mean monthly salary of 13 employees?ARs. 1465BRs. 1954CRs. 2175DRs. 2569Medium

Answers

1465 will be the mean monthly salary .The answer is (A) Rs. 1465.

Let the sum of the 12 employees' salaries be S.

Then, the mean monthly salary of the 12 employees is given by:

S/12 = 1450

S = 12 * 1450

S = 17400

If one more person joins with a salary of Rs. 1645, the new sum of the 13 employees' salaries is:

S' = S + 1645

S' = 17400 + 1645

S' = 19045

The new mean monthly salary of the 13 employees is:

S'/13 = 19045/13

S'/13 = 1465

Therefore, the answer is (A) Rs. 1465.

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Solve for all, Identify each part of the circle given its equation.

Answers

5. Center: (9, 4), Radius: 20
6. Center: (-1, 1), Radius: 16
7. Center: (-6, -37), Radius: 0.75
8. Center: (2, -13), Radius: √150 ≈ 12.25
9. Center: (-7, -2), Radius: 3
10. Center: (10, 5), Radius: √28 ≈ 5.29

(If this doesn’t seem right to you make sure you comment!)

Which expression represents the second partial sum for ? 2(0. 4) + 2(0. 4)2 2(0. 4)2 + 2(0. 4)3 2 + 2(0. 4) 0 + 2(0. 4)1


timed

Answers

The second partial sum for the given sequence is 2 + 2(0.4) = 2.8, under the condition that first term a1 = 2 and common ratio r = 0.4.

The given sequence follows geometric progression with first term a1 = 2 and common ratio r = 0.4. Then the formula for the sum of n terms of a geometric progression with first term a1 and common ratio r is
[tex]Sn = a1(1 - r^{n}) / (1 - r)[/tex]
The second partial sum of the given sequence can be evaluated
S2 = a1(1 - r²) / (1 - r)
Staging a1 = 2 and r = 0.4 in the above formula,
S2 = 2(1 - 0.4²) / (1 - 0.4)
= 2 + 2(0.4) = 2.8
Hence, the expression that presents the second partial sum for the given sequence is
2 + 2(0.4) = 2.8.

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Select the equivalent expression. \left(\dfrac{4^{3}}{5^{-2}}\right)^{5}=?( 5 −2 4 3 ​ ) 5 =?

(its khan academy)
(4^3/5^-2)^5 = ?

Answers

The equivalent expression is $\left(\dfrac{4^{3}}{5^{-2}}\right)^{5} = 102400000000000000000$.

Find the simplified equivalent expression of the following?

We can simplify the expression inside the parentheses first:

\begin{aligned} \frac{4^3}{5^{-2}} &= 4^3 \cdot 5^2 \ &= (2^2)^3 \cdot 5^2 \ &= 2^6 \cdot 5^2 \ &= 2^5 \cdot 2 \cdot 5^2 \ &= 2^5 \cdot 10^2 \ &= 3200 \end{aligned}

Now we can substitute this value into the original expression and simplify further:

\begin{aligned} \left(\frac{4^3}{5^{-2}}\right)^5 &= (3200)^5 \ &= (2^8 \cdot 5^2)^5 \ &= 2^{40} \cdot 5^{10} \ &= (2^4)^{10} \cdot 5^{10} \ &= 16^{10} \cdot 5^{10} \ &= (16 \cdot 5)^{10} \ &= 80^{10} \ &= 102400000000000000000 \end{aligned}

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6
lo
r
s
p
m
q
0
-2
mollie claimed that the slope of mq is greater than the slope of qs because triangle mpq is bigger than triangle qrs.
explain the error in mollie's claim and calculate the slope for both mq and qs show all your work.
enter your work and explanation in the space provided.

Answers

Size of triangles doesn't determine slope, mq slope=-2, qs slope=-0.5

How to explain Mollie's incorrect slope claim?

Mollie's claim is incorrect because the size of the triangles does not determine the slope of a line. The slope is calculated by dividing the change in the y-coordinates by the change in the x-coordinates between two points on the line. Therefore, we need to find two points on the lines mq and qs to calculate their slopes.

Let's start by finding the slope of mq. We can identify two points on the line, (0,6) and (2,2). Using these points, we can calculate the slope as:

slope of mq = (change in y-coordinates) / (change in x-coordinates)

slope of mq = (2 - 6) / (2 - 0)

slope of mq = -4 / 2

slope of mq = -2

Now let's find the slope of qs. We can identify two points on the line, (2,2) and (6,0). Using these points, we can calculate the slope as:

slope of qs = (change in y-coordinates) / (change in x-coordinates)

slope of qs = (0 - 2) / (6 - 2)

slope of qs = -2 / 4

slope of qs = -0.5

Therefore, the slope of mq is -2 and the slope of qs is -0.5.

In summary, Mollie's claim is incorrect because the size of the triangles does not determine the slope of a line. We calculated the slopes of lines mq and qs by finding two points on each line and using the formula for slope, which is the change in y-coordinates divided by the change in x-coordinates. The slope of mq is -2, and the slope of qs is -0.5.

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Connie’s team won 12 out of 16 games this season what percentage of game did her team lose

Answers

Connie's team lost 4 out of 16 games this season. To calculate the percentage of games lost, we can divide the number of games lost by the total number of games and then multiply by 100.

In this case, 4 divided by 16 is equal to 0.25, or 25% as a percentage. Therefore, Connie's team lost 25% of their games this season.

We first note that the total number of games played is 16. Connie's team won 12 of these games, so the number of games they lost is 16 - 12 = 4. To calculate the percentage of games lost, we divide the number of games lost by the total number of games and then multiply by 100. This gives:

(4 / 16) * 100 = 25%

Therefore, Connie's team lost 25% of their games this season.

It is important to understand how to calculate percentages in order to solve problems like this. In this case, we used the formula:

percentage = (part / whole) * 100

where the "part" is the number of games lost and the "whole" is the total number of games played. By substituting the appropriate values into this formula, we were able to calculate the percentage of games lost by Connie's team.

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Jewelers consider weight, cut grade, color, and clarity when pricing diamonds. In researching jewelry prices, Sandra makes the following statements based on her observations. Which of the statements are statements of causation? Select all that apply.


A. A particular diamond costs $264.


B. A darker color decreases a diamond's clarity.


C. Higher clarity drives up the price of a diamond.


D. Heavier diamonds tend to be sold at higher prices.


E. There appears to be a relationship between color and price.


F. Diamonds with lower cut grades seem to sell at lower prices

Answers

Statements C and D are statements of causation, while statements A, B, E, and F are not.

Causation refers to the relationship between cause and effect, where a change in one variable causes a change in another variable. Statements of causation imply a cause-and-effect relationship between two variables.

Based on the given statements, the statements of causation are C and D. Statement C implies that higher clarity causes an increase in the price of a diamond, and statement D implies that a higher weight causes an increase in the price of a diamond.

Statements A, B, E, and F are not statements of causation. Statement A only provides information about the cost of a particular diamond and does not explain the reason behind the cost. Statement B suggests a relationship between color and clarity, but it does not imply a cause-and-effect relationship.

Statement E also suggests a relationship between color and price, but it does not imply causation. Statement F only suggests an observation about the relationship between cut grade and price, but it does not imply causation.

In summary, statements C and D are statements of causation, while statements A, B, E, and F are not.

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Rectangular prism



Your cousin is building a sandbox for his daughter.



How much sand will he need to fill the box? Explain.


How much paint will he need to paint all six surfaces of the sandbox? Explain.


and dont forget to explain

Answers

The formula to calculate surface area is 2(Length × Width) + 2(Length × Height) + 2(Width × Height) and the length, width, and height of the sandbox is required to calculate rectangular area.

To determine how much sand your cousin will need to fill the rectangular prism-shaped sandbox, we first need to calculate its volume. To do this, we need the dimensions of the sandbox (length, width, and height). The formula for the volume of a rectangular prism is:

Volume = Length × Width × Height

Once we have the volume, we can determine the amount of sand needed to fill the sandbox in cubic units.

To find out how much paint is needed to paint all six surfaces of the sandbox, we need to calculate its surface area. The formula for the surface area of a rectangular prism is:

Surface Area = 2(Length × Width) + 2(Length × Height) + 2(Width × Height)

Once we have the surface area, we can determine the amount of paint required, usually measured in square units. Note that the amount of paint needed also depends on the coverage rate of the paint, which is typically listed on the paint container.

Please provide the dimensions of the sandbox (length, width, and height) so I can provide specific calculations for the sand and paint required.

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Consider the following function.
p-5/p^2+1
Find the derivative of the function.
h(p) =
h'(p) =
Find the values of p such that h'(p) = 0. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
p =
Find the values of x in the domain of h such that h'(p) does not exist. (Enter your answers as a comma-separated list. If an answer does not exist, enter DE.)
p =
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
p =

Answers

To find the derivative of the function h(p) = -5/(p^2+1), we will use the quotient rule:

h'(p) = [(-5)'(p^2+1) - (-5)(p^2+1)'] / (p^2+1)^2

Simplifying this expression, we get:

h'(p) = (10p) / (p^2+1)^2

To find the values of p such that h'(p) = 0, we will set the numerator equal to 0 and solve for p:

10p = 0

p = 0

Therefore, h'(p) = 0 when p = 0.

To find the values of p in the domain of h such that h'(p) does not exist, we need to find the values of p where the denominator of h'(p) becomes 0:

p^2+1 = 0

This equation has no real solutions, so there are no values of p in the domain of h such that h'(p) does not exist. Therefore, we enter DE (does not exist).

To find the critical numbers of the function, we need to find the values of p where h'(p) = 0 or h'(p) does not exist. We have already found that h'(p) = 0 when p = 0, and we have determined that h'(p) does not exist for any values of p in the domain of h. Therefore, the only critical number of the function is p = 0.
Let's first find the derivative of the given function, h(p) = (p - 5)/(p^2 + 1).

Using the quotient rule, h'(p) = [(p^2 + 1)(1) - (p - 5)(2p)]/((p^2 + 1)^2).

Simplifying, h'(p) = (p^2 + 1 - 2p^2 + 10p)/((p^2 + 1)^2) = (-p^2 + 10p + 1)/((p^2 + 1)^2).

To find the values of p such that h'(p) = 0, set the numerator of h'(p) equal to zero:

-p^2 + 10p + 1 = 0.

This is a quadratic equation, but it does not have any real solutions. Therefore, there are no values of p for which h'(p) = 0, so the answer is DNE.

To find the values of p where h'(p) does not exist, we look for where the denominator is zero:

(p^2 + 1)^2 = 0.

However, this equation has no real solutions, as (p^2 + 1) is always positive. Therefore, there are no values of p for which h'(p) does not exist, so the answer is DE.

Since there are no values of p for which h'(p) = 0 and no values of p for which h'(p) does not exist, there are no critical numbers of the function. The answer is DNE.

Your answer:
h(p) = (p - 5)/(p^2 + 1)
h'(p) = (-p^2 + 10p + 1)/((p^2 + 1)^2)
p (h'(p) = 0) = DNE
p (h'(p) does not exist) = DE
Critical numbers = DNE

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A fountain is in the shape of a right triangle. The area of the fountain is
12 square meters. One leg of the triangle measures one and a half times the
length of the other leg. What are the lengths of all three sides of the fountain?

Answers

Answer:

4,6,[tex]\sqrt{52} \\[/tex]

Step-by-step explanation:

Area of right triangle= base x height/2=12, but if we remove the division then it's:

base x height=24

factors of 24= 6,4  8,3 24,1 and 12,2

we have the rule that "One leg of the triangle measures one and a half times the length of the other leg." and the pair that matches that is 6 and 4.

So leg a=4 and leg b=6. Using the Pythagorean theorem(a^2+b^2=c^2) we have:

4^2+6^2=c^2=16+36=52 so the answer is 4,6,[tex]\sqrt{52} \\[/tex]

select all the quations that would be correct with fraction 2/9 81x_=18
900x_=200
72x_=16
450x_=100

Answers

The equations that would be correct with fraction 2/9 are:

81*x=18

45*x=100

900*c=200

How can the fractions be known?

Based on the given equation from the question, it can be seen that the fraction that is needed to complete the X is required, that will give the correct answer to each of the equation.

From the question, we can see that if we put X= 2/9 into the space above, we will have the correct solution. which is been performed below.

81*2/9=18

45*2/9=100

900*2/9=200

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Help asap


if someone has the correct answer in the next 20 mins they will be awarded brainiest



insert a monomial so that the result is an identity.


(... - b 4)(64 + ....) = 121a 10 – 68

Answers

We can replace the ellipsis with -49a4 to get: (7/4)a 10 - 2 = -49a4 - b 4, missing monomial is -49a4.

To find the missing monomial, we need to use the distributive property to expand the left side of the equation:

(... - b 4)(64 + ....) = 121a 10 – 68

Expanding the left side gives:

64(... - b 4) + ....(... - b 4) = 121a 10 – 68

Now we need to find a monomial to replace the ellipsis that will make the left side of the equation equal to the right side of the equation, no matter what value is substituted for a and b.

Looking at the constants in the equation, we can see that 121 and 68 have a common factor of 17. Therefore, we can divide both sides of the equation by 17 to simplify the coefficients:

7a 10 - 4 = 4(... - b 4) + 4

Simplifying further, we get:

7a 10 - 8 = 4(... - b 4)

Dividing both sides by 4, we get:

(7/4)a 10 - 2 = ... - b 4

Now we need to find a monomial to replace the ellipsis that will make the left side of the equation equal to the right side of the equation, no matter what value is substituted for a and b.

Since we want the left side of the equation to have a degree of 4 (because the right side has a term of -b4), we need to choose a monomial of degree 4 that will cancel out the terms of degree 10 on the left side. One possible monomial is:

-49a4

Therefore, we can replace the ellipsis with -49a4 to get: (7/4)a 10 - 2 = -49a4 - b 4

So the missing monomial is -49a4.

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What is the length of segment sr?
units
r
t
q
2x + 8
8x - 4
s

Answers

The length of segment SR is 90x - 4s, which can be determined by analyzing the given expression for units RT and QT: 2x + 88x - 4s.

Step 1: Identify the segment
In this problem, we need to find the length of segment SR.

Step 2: Understand the given information
We are given the lengths of two segments, RT and QT, as follows:
- RT = 2x
- QT = 88x - 4s

Step 3: Analyze the relationship between segments
Since SR is the segment that includes both RT and QT, we can express the length of segment SR as the sum of the lengths of RT and QT.

Step 4: Add the lengths of RT and QT
To find the length of segment SR, add the lengths of RT and QT:
SR = RT + QT
SR = (2x) + (88x - 4s)

Step 5: Simplify the expression
Combine like terms in the expression:
SR = 90x - 4s

The length of segment SR is 90x - 4s.

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Consider the graph of function g
y4
If f(x)=x², which equation represents function g?
OA. g(z) f(27)
OB. g (2) f(42)
M
2
O C. g(z) = 2 f(z)
(2)
D. 9(2) -

Answers

Answer:

D

Step-by-step explanation:

Ration Recone


Question 4


Name and describe the transformation of Figure Q to Figure R.


Reflection Figure Q was flipped


over the y-axis, the line of reflection


Translation. Figure Q slid 6 units to


the right to Figure R.


Reflection Figure Q was flipped


over the x-axis, the line of reflection.


Fig


Fig R


Translation. Figure Q slid 4 units to


the right to Figure R.

Answers

Q to R transformation: Reflection, translation.

How were Figure Q and Figure R transformed?

The transformation of Figure Q to Figure R involves a combination of reflection and translation. Firstly, Figure Q was flipped over the y-axis, which means that all the points of the figure on the left side of the y-axis were moved to the right side and vice versa.

Then, the figure was translated 6 units to the right, resulting in Figure R. Secondly, Figure Q was flipped over the x-axis, which means that all the points of the figure above the x-axis were moved below it and vice versa.

Finally, the figure was translated 4 units to the right, resulting in Figure R. These transformations are important in geometry as they allow us to create new figures that are related to the original ones.

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There are 4 mathematics books, 5 science books and 3 english books in the library. In how many ways can you arrange these so that the books are arranged in this order: Mathematics, Science, and English, and books of the same subjects are together?

Answers

To arrange the books in the specified order (Mathematics, Science, and English), you need to determine the number of arrangements for each subject's books and then multiply them together.

For the 4 mathematics books, there are 4! (4 factorial) ways to arrange them, which is 4 × 3 × 2 × 1 = 24 ways.

For the 5 science books, there are 5! (5 factorial) ways to arrange them, which is 5 × 4 × 3 × 2 × 1 = 120 ways.

For the 3 English books, there are 3! (3 factorial) ways to arrange them, which is 3 × 2 × 1 = 6 ways.

To find the total number of ways to arrange all the books in the required order, multiply the arrangements for each subject together: 24 (Mathematics) × 120 (Science) × 6 (English) = 17,280 ways.

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Please help I will mark brainliest



In a lab,a scientist puts x bacteria on a culture at 1:00 pm. The amount of


bacteria triples every hour. At 7:00 pm when there are 255,150 bacteria in


the culture. What is the value of x? Enter numbers only pleaseee

Answers

The value  bacteria of x is 150.

How did we arrive at the value of 150 for x?

To calculate the initial exponential growth value of bacteria, x, we can use the formula for exponential growth: N(t) = N₀ × [tex]3^(t/h)[/tex], where N(t) is the population at time t, N₀ is the initial population, and h is the time for the population to triple.

We know that at 7:00 pm, the population was 255,150 bacteria, and since the experiment started at 1:00 pm, it lasted for 6 hours. During this time, the population tripled every hour, so h is 1 hour. Plugging in these values, we can solve for N₀:

255,150 = x × [tex]3^(6/1)[/tex]

255,150 = x × 729

x = 255,150 / 729

x ≈ 349.7 ≈ 150 (rounded to the nearest whole number)

Therefore, the initial value of bacteria, x, is approximately 150.

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A supplier to a car manufacturer produces a certain valve and seal used in their cars. The sizes of these seals and


valves are closely monitored to ensure the parts actually work. Here are summary statistics on the diameters for


these valves and seals (in millimeters).


Mean


Standard deviation


Valve


Hv = 50


OV = 0. 3


Seal


Ils = 51


Os = 0. 4


Both distributions are approximately normal. A seal properly fits a valve if the seal's diameter is larger than the


valve's diameter, but the difference can't be more than 2 mm. Suppose we choose a valve and seal at random


and calculate the difference between their diameters. We can assume that their diameters are independent.

Answers

The probability that a seal properly fits a valve is approximately 0.9332 or 93.32%.

How to find the  difference between their diameters?

To determine the probability that a seal properly fits a valve, we need to calculate the probability that the difference in diameter between the seal and valve is less than or equal to 2 mm.

Let X be the diameter of the valve and Y be the diameter of the seal. Then, the difference in diameter between the seal and valve can be expressed as Z = Y - X. We want to find P(Z ≤ 2).

We know that X ~ N(50, 0.3²) and Y ~ N(51, 0.4²), and since Z = Y - X, we have:

Z ~ N(51 - 50,  √(0.3² + 0.4²)²) = N(1, 0.5²)

To find P(Z ≤ 2), we standardize Z by subtracting the mean and dividing by the standard deviation:

(Z - 1)/0.5 ~ N(0, 1)

P(Z ≤ 2) = P((Z - 1)/0.5 ≤ (2 - 1)/0.5) = P(Z ≤ 1.5)

Using a standard normal table or calculator, we find that P(Z ≤ 1.5) ≈ 0.9332.

Therefore, the probability that a seal properly fits a valve is approximately 0.9332 or 93.32%.

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The town of Knappville has a landmark, L, an amusement park, AP, a high school, HS, a city hall, CH, and a city park, P. Herberto is at the amusement park and wants to go to the city hall. Name a path he could travel

Answers

Herberto travelled through Amusement Park (AP), City Park (P), Landmark (L), High School (HS), City Hall (CH).

Herberto can take the following path to travel from the amusement park (AP) to the city hall (CH):

Amusement Park (AP) -> City Park (P) -> Landmark (L) -> High School (HS) -> City Hall (CH)

This path takes him through the city park, then to the landmark, followed by the high school, and finally to the city hall.

Please note that without a specific map or layout of Knappville, there could be multiple valid paths from the amusement park to the city hall. The path provided above is just one example.

When Herberto travels from the amusement park to the city hall, he can choose various paths depending on the specific layout of Knappville. The path mentioned earlier is just one example, but the actual paths could differ based on the town's infrastructure and the locations of the landmarks.

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an army has 200 tanks. tanks need maintenance 10 times per year, and maintenance takes an average of 2 days. the army would like to have an average of at least 180 tanks working. how many repairmen are needed? assume exponential interarrival and service times. (hint: use a oneway data table.)

Answers

Here is the expected number of broken machines or tanks and K is the total number of tanks. So (K-L) gives the number of tanks in working condition.

The number of repairmen (R) needed to have an average of at least 180 tanks working is to be determined. Thus as observed from the results obtained for one-way data table, the value of R such that (K-L) is at least 180 is R = 11 repairmen

The Expected number of broken or bad machines (L) is

[tex]L=\sum j\pi_i[/tex]

The Expected number of machines waiting for service (1) is

[tex]L=\sum (j-R)\pi_i[/tex]

An expected number of words is often used as a guideline to ensure that the content is neither too long nor too short. In this case, the expected number is 150 words. A 150-word piece of writing can be considered a short composition. It is long enough to convey a basic idea or message, but not so long that it becomes tedious to read. This length is often used in blog posts, news articles, and social media updates.

When writing a 150-word piece, it is important to make every word count. The writing should be clear and concise, with each sentence contributing to the overall message. It may also be helpful to outline the main points before starting to write to ensure that the piece stays focused.

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If f(x) = x2 − 6x − 4 and g(x) = 5x + 3, what is (f + g)(−3)? (1 point)
41
35
11
−35

Answers

As per the given information in the question, we can compute that the correct option is C) 11.

According to the question:

[tex]f(x)=x^{2} -6x-4[/tex]

[tex]g(x)=5x+3[/tex]

Therefore,

[tex](f+g)(x)= f(x)+g(x) \\

          =x^{2} -6x-4+5x+3 \\

          =x^2-x-1[/tex]

Now, to find (f+g)(-3):

substituting x=-3 in the above equation

we get,

[tex](f+g)(-3)= (-3)^2-(-3)-1 \\

                         = 9+3-1 \\

                         =11[/tex]

Hence  (f+g)(-3)=11

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