The equation of the line passing through point P and parallel to line A is
y = (5/7)x + 2
How to find the equationLine A passed through points (0, -1) and (7, 4), hence equation of line passing through point (0, -1) and (7, 4).
find the slope of the line:
m = (y2 - y1) / (x2 - x1)
m = (4 - (-1)) / (7 - 0)
m = 5/7
use the point-slope form of the equation of a line with the point (0, -1):
y - (-1) = (5/7)(x - 0)
y + 1 = (5/7)x
y = (5/7)x - 1
Therefore, the equation of the line passing through the points (0, -1) and (7, 4) is y = (5/7)x - 1.
for a line parallel to line A passing through point P we change the intercept to give
y = (5/7)x + 2
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22. Katie is 6 feet tall and casts a shadow that is 2. 5 feet. If the palm tree next to her casts a shadow of 8. 75 feet at the
same time of day, how tall is the palm tree?
Please help me this due today
No links or I will report you
The palm tree is 21 feet tall.
To find the height of the palm tree, we can use the concept of similar triangles, where the ratio of corresponding sides is equal. In this case, the terms we need are Katie's height, her shadow length, the palm tree's shadow length, and the palm tree's height.
Step 1: Set up the proportion using the given information.
(Katie's Height / Katie's Shadow Length) = (Palm Tree Height / Palm Tree Shadow Length)
Step 2: Plug in the given values.
(6 ft / 2.5 ft) = (Palm Tree Height / 8.75 ft)
Step 3: Solve for Palm Tree Height.
(6 ft / 2.5 ft) * 8.75 ft = Palm Tree Height
2.4 * 8.75 ft = Palm Tree Height
Step 4: Calculate the height.
21 ft = Palm Tree Height
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X-1 if x < 2 Let f(x)=1 if 2sxs6 X+4 if x > 6 a. Find lim f(x). X-+2 b. Find lim f(x). X-6 Select the correct choice and, if necessary, fill in the answer box to complete your choice. O A. lim = X-2 O B. The limit is not - oo or co and does not exist. Select the correct choice and, if necessary, fill in the answer box to complete your choice. O A. lim = X-6 OB. The limit is not - oor oo and does not exist.
a. The limit does not exist.
b. The limit is equal to 4.
a. To find the limit as x approaches 2, we need to evaluate the left-hand and right-hand limits separately and check if they are equal.
Left-hand limit: lim f(x) as x approaches 2 from the left
We have f(x) = x - 1 for x < 2. So, as x approaches 2 from the left, f(x) approaches 1.
Right-hand limit: lim f(x) as x approaches 2 from the right
We have f(x) = 1 for 2 ≤ x ≤ 6 and f(x) = x + 4 for x > 6. So, as x approaches 2 from the right, f(x) approaches 6.
Since the left-hand and right-hand limits are not equal, the limit as x approaches 2 does not exist.
b. To find the limit as x approaches 6, we need to evaluate the left-hand and right-hand limits separately and check if they are equal.
Left-hand limit: lim f(x) as x approaches 6 from the left
We have f(x) = 1 for 2 ≤ x ≤ 6 and f(x) = x + 4 for x > 6. So, as x approaches 6 from the left, f(x) approaches 1.
Right-hand limit: lim f(x) as x approaches 6 from the right
We have f(x) = x + 4 for x > 6. So, as x approaches 6 from the right, f(x) approaches 10.
Since the left-hand and right-hand limits are not equal, the limit as x approaches 6 does not exist.
Therefore, the correct choices are:
a. The limit is not -oo or co and does not exist.
b. lim = 4.
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1. Sanchez deposited $3,000 with a bank in a 4-year certificate of deposit yielding 6% interest
compounded daily. Find the interest earned on the investment. (4pts)
The compound interest generated on the investment is roughly $813.67, which is the solution to the question based on compound interest.
What is Principal?The initial sum of money invested or borrowed, upon which interest is based, is referred to as the principle. The principal is then periodically increased by the interest, often monthly or annually, to create a new principal sum that will accrue interest in the ensuing period.
Using the compound interest calculation, we can determine the interest earned on Sanchez's investment:
[tex]A = P(1 + \frac{r}{n} )^{(n*t)}[/tex]
where A is the overall sum, P denotes the principal (the initial investment), r denotes the yearly interest rate in decimal form, n denotes the frequency of compounding interest annually, and t denotes the number of years.
In this case, P = $3,000, r = 0.06 (6%), n = 365 (compounded daily),
and t = 4.
Plugging in the values, we get:
[tex]A = 3000(1 + \frac{0.06}{365} )^{(365*4)}[/tex]
A= $3813.67
The difference between the final amount and the principal is the interest earned.
Interest = A - P
Interest = $3813.67 - $3000
Interest = $813.67
As a result, the investment's interest yield is roughly $813.67.
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) g(v) v³ - 48v + 6
The critical numbers are 4, -4.
To find the critical numbers of the function g(v) = v³ - 48v + 6, follow these steps:
1. Find the derivative of the function, g'(v).
2. Set g'(v) equal to 0 and solve for v.
3. List the critical numbers as a comma-separated list.
Step 1: Find the derivative of the function.
g(v) = v³ - 48v + 6
Using the power rule, the derivative is:
g'(v) = 3v² - 48
Step 2: Set g'(v) equal to 0 and solve for v.
3v² - 48 = 0
Divide both sides by 3:
v² - 16 = 0
Factor the equation:
(v - 4)(v + 4) = 0
Solve for v:
v = 4, -4
Step 3: List the critical numbers.
The critical numbers of the function g(v) = v³ - 48v + 6 are v = 4, -4.
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HERE IS A HARD QUESTION , COULD U PLEASE ANSWER B PLEASE? I DID A ! 1ST ANSWER WOULD BE MARKED BRAINLIEST AND GET 5/5 WITH A THANKS! ILL ALSO COMMENT ON YOUR ANSWER ! BUT IF IT ISNT CORRECT , I WONT MARK BRAINLIEST! Thank you for your answers!!!!
Answer:
D(6,4).
Step-by-step explanation:
The shape ABCD is a square.
By definition, the diagonals are equal.
The diagonal from A to C is 6 units long. Therefore, you should get your point D by drawing across from B to the right by 6.
D(6,4).
Consider a metal plate on [0,1] ×[0,1] with density rho(x,y) = αx
+ βy g/cm2, where α and β are positive constants. Show that the
center of mass must lie on the line x + y = 7/6 .
The center of mass of the metal plate with density rho(x,y) = αx+ βy g/cm2 must lie on the line x + y = 7/6.
To find the center of mass of the metal plate, we need to calculate the coordinates of its centroid (X, Y). The coordinates of the centroid are given by:
X = (1/M) ∬(R) x ρ(x,y) dA, Y = (1/M) ∬(R) y ρ(x,y) dA
where M is the total mass of the plate, R is the region of integration (0 ≤ x ≤ 1, 0 ≤ y ≤ 1), and dA is the differential area element.
We can calculate the total mass M of the plate as follows:
M = ∬(R) ρ(x,y) dA = α/2 + β/2 = (α + β)/2
Using the given density function, we can calculate the integrals for X and Y:
X = (1/M) ∬(R) x ρ(x,y) dA = (2/αβ) ∬(R) x(αx+βy) dA = (2/3)(α+β)
Y = (1/M) ∬(R) y ρ(x,y) dA = (2/αβ) ∬(R) y(αx+βy) dA = (2/3)(α+β)
Thus, the coordinates of the centroid are (X, Y) = ((2/3)(α+β), (2/3)(α+β)).
Now, if we substitute X + Y = (4/3)(α+β) into the equation x + y = 7/6, we get:
x + y = 7/6
2x + 2y = 7/3
2(x+y) = 4/3(α+β)
x+y = (2/3)(α+β)
which shows that the centroid lies on the line x + y = 7/6. Therefore, the center of mass must also lie on this line.
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The box-and-whisker plot below represents some data set. What percentage of the data values are between 25 and 45?
Thus, approximately 33.33% of the data values are between 25 and 45.
What is box-and-whisker plot?A box-and-whisker plot, also known as a box plot, is a graphical representation of a set of data that shows the distribution of the data along a number line. The plot is composed of a box that represents the middle 50% of the data, along with two "whiskers" that represent the lowest and highest values in the data set. The box is drawn between the first and third quartiles of the data, with a line inside the box representing the median value. The distance between the first and third quartiles is known as the interquartile range (IQR), which can be used to identify outliers in the data. Box-and-whisker plots are useful for comparing the distribution of data between different groups or data sets.
Here,
To find the percentage of the data values that are between 25 and 45 on the given box-and-whisker plot, we need to find the area of the box that is between the lower quartile (Q1) and the median (Q2). From the plot, we can see that the lower quartile (Q1) is at 30, and the median (Q2) is at 40. The interquartile range (IQR), which is the distance between Q1 and Q3, is 20.
Therefore, the box extends from 30 to 40, which is a distance of 10. The total length of the plot is 30 (from 25 to 55), so the percentage of data values between 25 and 45 is:
10/30 * 100% = 33.33%
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Complete question:
The box-and-whisker plot below represents some data set. What percentage of the data values are between 25 and 45?
Caroline works in a department store selling clothing. She makes a guaranteed salary
of $200 per week, but is paid a commision on top of her base salary equal to 25% of
her total sales for the week. How much would Caroline make in a week in which she
made $1575 in sales? How much would Caroline make in a week if she made a dollars
in sales?
The amount made by Caroline is $593.75 and 200 + 0.25x when she made $1574 and $x in sales respectively.
The total amount will be given by the formula using percentage -
Total amount = Base salary + 25% × her total sales
Keep the value in equation when she made $1575
Total amount = 200 + 25% × 1575
Total amount = 200 + 393.75
Total amount = $593.75
Keep the value in equation when she made $x
Total amount = 200 + 25% × x
Total amount = 200 + 0.25x
Hence, the earned amount is $593.75 and 200 + 0.25x.
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The complete question is -
Caroline works in a department store selling clothing. She makes a guaranteed salary of $200 per week, but is paid a commision on top of her base salary equal to 25% ofher total sales for the week. How much would Caroline make in a week in which she made $1575 in sales? How much would Caroline make in a week if she made x dollars in sales?
Given the circle below with tangent GH and secant JIH. If GH = 8 and
12, find the length of IH. Round to the nearest tenth if necessary.
JH
=
H
The value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)
What are circle theoremsCircle theorems are a set of rules that apply to circles and their constituent parts, such as chords, tangents, secants, and arcs. These rules describe the relationships between the different parts of a circle and can be used to solve problems involving circles.
GH² = IH × JI {secant tangent segments}
JI = 12 - IH, we shall represent IH with x so that;
8² = x(12 - x)
64 = 12x - x²
x² - 12x + 64 = 0 {rearrange to get a quadratic equation}
with the quadratic formula;
x = [12 + √(-112)]/2 or x = = [12 - √(-112)]/2
√(-112) = 4i√7 {where i = √(-1)}
so;
x = (6 + 2i√7) or x = (6 - 2i√7)
Therefore, the value of the segment IH for the circle with secant through H which intersect the circle at points I and J is (6 + 2i√7) or (6 - 2i√7)
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a time capsule has been buried 98m away from the cave at a bearing of 312 degrees how far west of the cave is the time capsule buried? give your answer in 1 decimal places
If a time capsule has been buried 98m away from the cave at a bearing of 312. the time capsule is buried about 82.2 meters west of the cave.
What is the time capsule?To find how far west the time capsule is buried, we need to find the horizontal component of the displacement vector that points from the cave to the location of the time capsule. We can use trigonometry to do this:
cos(312°) = adjacent/hypotenuse
The hypotenuse is the distance between the cave and the time capsule, which is 98m. The adjacent side represents the horizontal distance between the two points, which is what we want to find. Rearranging the equation, we get:
adjacent = cos(312°) x hypotenuse
adjacent = cos(312°) x 98
adjacent ≈ 82.2
Therefore, the time capsule is buried about 82.2 meters west of the cave.
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Let
Ф(u, v) = (3u + 9v, 9u + 9v). Use the Jacobian to determine the area of
Ф(R) for: (a)R = [0,91 × [0, 6]
(b)R = [2,20] × [1, 17]
(a)Area (Ф(R)) =
(b) Area (Ф(R)) =
a) Area (Ф(R)) = 5184 (b) Area (Ф(R)) = 25920
Let J be the Jacobian of Ф. We have J = det(DФ) = det([3 9; 9 9]) = -72.
(a) For R = [0,9] × [0,6], we have
Ф(R) = {(3u+9v,9u+9v) | 0 ≤ u ≤ 9, 0 ≤ v ≤ 6}.
The area of Ф(R) is given by the double integral over R of the Jacobian:
Area (Ф(R)) = ∬R |J| dudv
= ∫0^9 ∫0^6 72 dudv
= 5184.
Therefore, the area of Ф(R) is 5184.
(b) For R = [2,20] × [1,17], we have Ф(R) = {(3u+9v,9u+9v) | 2 ≤ u ≤ 20, 1 ≤ v ≤ 17}. The area of Ф(R) is given by the double integral over R of the Jacobian:
Area (Ф(R)) = ∬R |J| dudv = ∫2^20 ∫1^17 72 dudv = 25920.
Therefore, the area of Ф(R) is 25920.
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Pls Answer Soon!
A college professor asked every student in his statistics class to flip a coin 100 times and report how many times the coin landed on heads. The results followed a normal distribution, with a mean of 50 and a standard deviation of 5.
If there were 70 students in the class, how many of the students most likely got heads between 45 times and 60 times?
Round your answer to the nearest whole number of students
57 students most likely got heads between 45 and 60 times.
To determine the number of students who got heads between 45 and 60 times, we'll use the normal distribution properties. First, we need to calculate the z-scores for 45 and 60:
Z = (X - μ) / σ
For 45 heads:
Z1 = (45 - 50) / 5 = -1
For 60 heads:
Z2 = (60 - 50) / 5 = 2
Next, we need to find the probability that a student falls between these z-scores. We can do this by looking up the z-scores in a standard normal distribution table or using a calculator. The probabilities corresponding to these z-scores are:
P(Z1) = 0.1587
P(Z2) = 0.9772
Now, subtract P(Z1) from P(Z2) to get the probability of a student's result falling between 45 and 60 heads:
P(45 ≤ X ≤ 60) = P(Z2) - P(Z1) = 0.9772 - 0.1587 = 0.8185
Finally, multiply this probability by the total number of students (70) and round to the nearest whole number:
Number of students = 0.8185 * 70 ≈ 57
So, approximately 57 students most likely got heads between 45 and 60 times.
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The base radius and height of a right circular cone are measured as 10 cm and 25 cm, respectively, with a possible error in measurement of as much as 0.1 cm in each dimension. Use differentials to estimate the maximum error in the calculated volume of the cone. (Hint: V = 1/3 πr²h)
The estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.
How to estimate the maximum error in the calculated volume of the cone?Let V = (1/3)πr²h be the volume of the cone, where r and h are the base radius and height of the cone, respectively.
Let dr and dh be the possible errors in the measurements of r and h, respectively.
Then, the actual dimensions of the cone are (r+dr) cm and (h+dh) cm, respectively.
The differential of V is given by:
dV = (∂V/∂r)dr + (∂V/∂h)dh
We have:
∂V/∂r = (2/3)πrh and ∂V/∂h = (1/3)πr²
Substituting the given values, we get:
∂V/∂r = (2/3)π(10 cm)(25 cm) = 500π/3
∂V/∂h = (1/3)π(10 cm)² = 100π/3
Substituting into the differential equation, we get:
dV = (500π/3)dr + (100π/3)dh
Using the given maximum error of 0.1 cm for both r and h, we have:
|dr| ≤ 0.1 cm and |dh| ≤ 0.1 cm
Therefore, the maximum possible error in V is given by:
|dV| = |(500π/3)(0.1 cm) + (100π/3)(0.1 cm)|
|dV| = 50π/3 + 10π/3
|dV| = 60π/3
|dV| = 20π cm³
Therefore, the estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.
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the sales tax rate in your city is 7.5%. What is the total amount you pay for a $6.84 item.
Answer:
$7.35
Step-by-step explanation:
MARKING BRAINLEIST IF CORRECT PLS ANSWER ASAP
Answer:
7.6 cm
Step-by-step explanation:
[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]
[tex]a^{2}[/tex] + [tex]6.5^{2}[/tex] = [tex]10^{2}[/tex]
[tex]a^{2}[/tex] + 42.25 = 100 Subtract 42.25 from both sides
[tex]a^{2}[/tex] = 57.57
[tex]\sqrt{\a^{a} }[/tex] = [tex]\sqrt{57.57}[/tex]
a ≈ 7.6
Helping in the name of Jesus.
Answer:
7.6 cm
Step-by-step explanation:
a^2+ b^2=c^2
a^2+6.5^2=10^2
a^2+42.25=100 subtract 42.25 from both sides
a^2=57.57
a=√57.57
a=7.6 cm
A square pyramid is contained within a cone such that the vertices of the base of the pyramid are touching the edge of the cone. They both share a height of 20 cm. The square base of the pyramid has an edge of 10 cm. Using 3.14 as the decimal approximation for T, what is the volume of the cone? 1046.35 cubic centimeters 2093.33 cubic centimeters O 4185.40 cubic centimeters 06280.00 cubic centimeters
To find the volume of the cone, we first need to find its radius. Since the pyramid is contained within the cone such that the vertices of the base of the pyramid are touching the edge of the cone, the diagonal of the square base of the pyramid is equal to the diameter of the base of the cone. The diagonal of the square base of the pyramid is:
d = √(10^2 + 10^2) = √200 = 10√2 cm
Therefore, the diameter of the base of the cone is 10√2 cm, and the radius is 5√2 cm.
The volume of the cone can be calculated using the formula:
V = (1/3)πr^2h
where r is the radius of the base of the cone and h is the height of the cone.
Substituting the given values, we get:
V = (1/3)π(5√2)^2(20)
V = (1/3)π(50)(20)
V = (1/3)(1000π)
V = 1000/3 * π
Using 3.14 as the decimal approximation for π, we get:
V ≈ 1046.35 cubic centimeters
Therefore, the volume of the cone is approximately 1046.35 cubic centimeters. The answer is A.
Given that f(x) = (h(x))10 = h(-1) = 3 h'(-1) = 6 Calculate f'(-1).
The final value is f'(-1) = 16,777,2160.
We can use the chain rule and the power rule of differentiation to find f'(-1).
Recall that the chain rule states that if f(x) = g(h(x)), then f'(x) = g'(h(x)) h'(x). Applying this rule to f(x) = (h(x))^10, we get:
f'(x) = 10(h(x))^9 h'(x)
Now, we can substitute x = -1 into the above equation, since we are asked to find f'(-1). Thus, we have:
f'(-1) = 10(h(-1))^9 h'(-1)
We are given that h(-1) = 3 and h'(-1) = 6, so we can substitute these values to get:
f'(-1) = 10(3)^9 (6)
Simplifying, we get:
f'(-1) = 16,777,2160
Therefore, f'(-1) = 16,777,2160
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Part D
The rectangular bases of the treasure box will be cut from wooden planks
4 1/8 feet long and 4 1/8 feet wide. How many planks will Mr. Penny need for his
18 students to each
make one treasure box?
Answer:
Step-by-step explanation:
Find the average x-coordinate of the points in the prism D={(x,y,z):0 ≤ x ≤ 6,0 ≤ y ≤ 18-3x, 0 ≤ z ≤ 4}. The average x-coordinate of the points in the prism is (Simplify your answer.)
The average x-coordinate of the points in the prism is 3.
What is a prism?A prism is a polyhedron that has two parallel and congruent polygonal bases that are linked by parallelogram faces that are lateral. The height of the prism is the perpendicular distance between the bases.
The formula for calculating the average x-coordinate of the points in the prism D = {(x,y,z):0 ≤ x ≤ 6,0 ≤ y ≤ 18-3x, 0 ≤ z ≤ 4} is$$\frac{\text{sum of all x-coordinates}}{\text{number of vertices}}$$
The vertices of a prism are the points where two adjacent edges meet. There are eight vertices in a rectangular prism, and the x-coordinate of each vertex is either 0 or 6. The x-coordinates of the vertices are $$0,0,0,0,6,6,6,6.
$$The sum of all the x-coordinates is 24. Thus, the average x-coordinate of the points in the prism is$$\frac{24}{8}=\boxed{3}.
$$Hence, the average x-coordinate of the points in the prism is 3.
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The height of Mount Rushmore is 5900 feet. What is the height of Mount Rushmore in
centimeters? (1 in = 2. 54 cm)
Answer:
the answer is 14,986 centimetres
Part C
What does the absolute value of the correlation coefficient say about the predictions in part B? How do you know? Write
an explanation of about one to two sentences.
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The shows that Luther can expect the speed to be 51 miles/hour when he throws 80 pitches and 64 miles/hour when he throws 54 pitches.
How to calculate the speed?The average speed of Luther's pitches when he throws 80 pitches will be:
y = -0.511x + 91.636
= -0.511(80) + 91.636
= 50.756
= 51
Also, the number of pitches that Luther can throw when the speed is 64 miles per hour will be:
y = -0.511x + 91.638
64 = -0.511x + 91.638
0.511x = 91.638 - 64
0.511x = 27.636
x = 54
Therefore, the number of pitches will be 54.
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Answer:
Because the absolute value of the correlation coefficient, 0.9672, is very close to 1, Luther can be very confident in the predictions.
Step-by-step explanation: Edmentum Answer
The ratio of runners to walkers at the 10k fund-raiser was 5 to 7. if there
were 350 runners, how many walkers were there?
There were 490 walkers at the 10k fund-raiser.
The ratio of runners to walkers is 5:7, that means that the every five runners, there are 7 walkers so therefore we will use ratio formula.
If there have been 350 runners, we can use this ratio to discover what number of walkers there were:
5/7 = 350/x
Where x is the number of walkers.
To solve for x, we will cross-multiply:
5x = 7 * 350
5x = 2450
x = 490
Consequently, there were 490 walkers at the 10k fund-raiser.
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In a class of students, the following data table summarizes how many students passed a test and complete the homework due the day of the test. What is the probability that a student chosen randomly from the class passed the test and completed the homework? Passed the test Failed the test Completed the homework 11 3 Did not complete the homework 2 5
The probability that a student chosen randomly from the class passed the test or completed the homework is 20/27.
What is the probability?The probability that a student chosen randomly from the class passed the test or completed the homework is calculated as follows:
Let the probability that a student completed the homework be P(B).
Also, let the probability that a student passed the test be P(A)
P(A or B) = P(A) + P(B) - P(A * B)
From the data table:
The number of students who passed the test = 18
The number of students who completed the homework = 17
The number of students who both passed the test and completed the homework = 15.
Total number of students = 27
P(A) = 18/27
P(B) = 17/27
P(A*B) = 15/27
Therefore,
P(A or B) = 18/27 + 17/27 - 15/27
P(A or B) = 20/27
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(15 POINTS) Zachary is an American traveling with a tour group in Southeast Asia.
During a stop in Malaysia, he purchases a souvenir that is priced at 58 Malaysian riggits using his credit card. If the exchange rate that day is USD to MYR = 3. 04, which is the best estimate of the charge Zachary will later find on his credit card statement? (3 points)
$20
$55
$61
$180
The best estimate of the charge Zachary will later find on his credit card statement is $20
The formula to be used is -
Amount in USD = Amount of MYR/Value of one MYR
As, 3.04 MYR is 1 USD performing money conversion of 58 MYR
So, 58 MYR will be = 58/3.04
Divide the values in Right Hand Side of the equation to find the value of MYR in USD
Value in USD = $19.07
Hence, the credit card statement will reflect usage of $20 (since it is the closes correct option and we have been asked the best estimate).
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hello! are these correct?
if you can not see my answers :
1. right triangle
2. isosceles triangle
3. equilateral triangle
4. acute triangle
5. isosceles triangle
6. right triangle
( if im incorrect, please tell me the correct answer )
Answer: Yes those are correct good job
Step-by-step explanation:
What is a way you can find the vaule of x
Answer:To find the value of x, bring the all the variable to the left side and bring all of the remaining values to the right side. You then simplify the values to find the answer.
Step-by-step explanation:
Answer:
im not sure bud because i don't know what is the full question?
Step-by-step explanation:
Color the stars, so it is unlikely impossible to choose a red one.
HERE IS A HARD QUESTION , COULD U PLEASE ANSWER B PLEASE? I DID A ! 1ST ANSWER WOULD BE MARKED BRAINLIEST AND GET 5/5 WITH A THANKS! ILL ALSO COMMENT ON YOUR ANSWER ! BUT IF IT ISNT CORRECT , I WONT MARK BRAINLIEST! Thank you for your answers!!!!
Step-by-step explanation:
The coordinates of point B: (0,6)
Coordinates of point C: (3,8)
A kite has 4 sides, of which we have 2 equal pairs, thus the coordinates of point D must be (6,6)
Answer:
(6,6)
Step-by-step explanation:
The question is asking us to complete the half figure, and make it a kite. We can see that the 2 lines AB and BC are half of the shape. In the attachment, I drew a line of symmetry down the middle of the shape.
I also created a point, Y, down the red line, AC, to represent the perpendicular bisector of the 2 diagonals. We can see that line segment BY is the radius of the entire line BD.
This radius is 3 units, so we now know that the diameter horizontally is 6 units. We can draw this on the other side to create point D.
This means that point D is at (6,6).
See attachment for more information, hope this helps!
Complete the proof that △QST≅△QRT.
The congruent triangles is solved and the triangles are congruent by AAS postulate
Given data ,
Let the two triangles be represented as ΔRQT and ΔTQS
And , the side TQ is the common side of both the triangles
Now , the measure of ∠TQR ≅ measure of ∠TQS ( given )
And , the measure of ∠TRQ ≅ measure of ∠TSQ ( given )
So , Two angles are the same and a corresponding side is the same (ASA: angle, side, angle)
Hence , the triangles are congruent by ASA postulate
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"The times for the mile run of a large group of male college students are approximately Normal with mean 7. 06 minutes and standard deviation 0. 75 minutes. Use the 68-95-99. 7 rule to answer the following questions. (Start by making a sketch of the density curve you can use to mark areas on. ) (a) What range of times covers the middle 95% of this distribution
According to the 68-95-99.7 rule, approximately 68% of the distribution falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
In this case, the mean is 7.06 minutes and the standard deviation is 0.75 minutes. Therefore, the range of times that covers the middle 95% of the distribution would be from the mean minus two standard deviations (7.06 - 2 x 0.75 = 5.56 minutes) to the mean plus two standard deviations (7.06 + 2 x 0.75 = 8.56 minutes).
In other words, 95% of the male college students' mile run times are expected to fall between 5.56 and 8.56 minutes. This means that most of the students' mile run times will be within this range, and only a small percentage will be outside of it.
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