Answer:
0.30 L
Explanation:
First we convert 75.0 g of Al₂(SO₄)₃ into moles, using its molar mass:
75.0 g ÷ 342.15 g/mol = 0.219 mol Al₂(SO₄)₃Then we can calculate the volume of the solution, by using the definition of molarity:
Molarity = moles of solute / liters of solution0.72 M = 0.219 mol / VolumeWe solve for Volume:
Volume = 0.30 LWhich factors play a role in creating ocean waves?
Choose all answers that are correct.
wind duration
wind speed
wind change
wind elevation
wind direction
wind fetch
Answer:
1. Wind speed
2. Wind change
3. Wind elevation
4. Wind direction
Answer:
For k12 its::
Explanation:
wind direction
wind speed
wind fetch
wind duration
Yw guys! ^^
Explain how the Octet Rule would say that the elements of potassium and chlorine would react.
Answer:
The octet rule is only applicable to the main group elements. The molecules of the halogens, oxygen, nitrogen, and carbon are known to obey the octet rule. In general, the elements that obey this rule include the s-block elements and the p-block elements (except hydrogen, helium, and lithium).
Explanation:
I hope this helps and pls mark me brainliest :)
Calculate the mass, in grams, of 912 atoms of iron, Fe (1 mol of Fe
has a mass of 55.85 g).
Answer:
8.45 × 10⁻²⁰ g
Explanation:
Step 1: Given data
Number of atoms of Fe (N): 912 atomsMolar mass of Fe (M): 55.85 g/molStep 2: Calculate the mass, in grams, of 1 atom of Fe
We will use Avogadro's number: there are 6.02 × 10²³ atoms of Fe in 1 mole of Fe.
55.85 g/mol × 1 mol/6.02 × 10²³ atom = 9.27 × 10⁻²³ g/atom
Step 3: Calculate the mass corresponding to 912 atoms
9.27 × 10⁻²³ g/atom × 912 atom = 8.45 × 10⁻²⁰ g
WILL MARK BRAINLIST
If a car travels 60 miles for two hours, what is the average speed?
15 mi/hr
30 mi/hr
45 mi/hr
60 mi/hr
Answer:
The average speed must be 30mph so this means the car traveled for 2hrs 60/30
According to the graph, what is the instantaneous speed of the object at 5 seconds? *
Captionless Image
4 m/s
7 m/s
0.25 m/s
3 m/s
Answer:4m/s
Explanation:The reason why that the answer is because I am Smart.
Kinematics equations are used only by physicists and people who work in
space.
A. True
B. False
Answer:
FALSE
Explanation:
false. kinematics equations are used for many purposes.it is used to drive equations and to find the motion of an object. but it is used more in physics rather than maths.
The following table lists molecular weight data for a polypropylene material. Molecular Weight Range (g/mol) xi wi
8,000 - 16,000 0.07 0.03 16,000 - 24,000 0.15 0.09 24,000 - 32,000 0.26 0.21 32,000 - 40,000 0.27 0.27 40,000 - 48,000 0.18 0.28 48,000 - 56,000 0.07 0.12
Click here to access Table 14.3. Atomic weights for several elements are included in the following table: Carbon 12.01 g/mol Chlorine 35.45 g/mol Fluorine 19.00 g/mol Hydrogen 1.008 g/mol Oxygen 16.00 g/mol Nitrogen 14.01 g/mol Compute the following:
(a) the number-average molecular weight, Enter your answer for part (a) in accordance to the question statement g/mol
(b) the weight-average molecular weight, Enter your answer for part (b) in accordance to the question statement g/mol
(c) the degree of polymerization.
Answer:
a) the number-average molecular weight is 32,400 g/mol
b) the weight-average molecular weight is 36,320 g/mol
c) the degree of polymerization is 770
Explanation:
Given the data in the question;
Molecular Mean Number Weight Number Weight
weight average average
(g/mol) Mi(g/mol) xi wi xiMi wiMi
8,000-16,000 12,000 0.07 0.03 840 360
16,000-24,000 20,000 0.15 0.09 3000 1800
24,000-32,000 28,000 0.26 0.21 7280 5880
32,000-40,000 36,000 0.27 0.27 9720 9720
40,000-48,000 44,000 0.18 0.28 7920 12320
48,000-56,000 52,000 0.07 0.12 3640 6240
∑ Mn=32,400 Mw=36,320
so;
a) the number-average molecular weight
Mn = ∑Mixi
so from the table above; summation of Row Mixi
Mn = ∑Mixi = 32,400
Therefore, the number-average molecular weight is 32,400 g/mol
b) the weight-average molecular weight
Mw = ∑Miwi
so from the table above; summation of Row Miwi
Mw = ∑Miwi = 36,320
Therefore, the weight-average molecular weight is 36,320 g/mol
c) the degree of polymerization
the degree of polymerization of polypropylene can be determined using number-average molecular and repeat unit molecular weight.
now, for polypropylene { CH₂ = CH - CH₃ }
the repeat unit consist of 3 carbon atoms and 6 hydrogen atoms
given that;
Atomic weight of Carbon mC = 12.01 g/mol and
Atomic weight of Hydrogen mH = 1.008 g/mol
now we find the repeat unit molecular weight of polypropylene
m = nCmC + nHmH
where n is the number of repeat of atoms
so we substitute
m = ( 3 × 12.01) + ( 6 × 1.008)
m = 36.03 + 6.048
m = 42.078 g/mol
now we calculate the degree of polymerization;
DP = Mn / m
so we substitute
DP = 32,400 / 42.078
DP = 769.9985 ≈ 770
Therefore, the degree of polymerization is 770
Please answer ASAP! thanks
I need help explaining what are the differences between Solids, Liquids, and Gases.
Explanation: solids are frozen like if you freeze tea it becomes a solid , liquids is like tea and gases is like when you boil water and it becomes a gas
Determine the empirical and molecular formulas of the mandelic acid
Answer:
Both empirical and molecular are C₈H₈O₃.
Explanation:
Hello!
In this case, according the attached picture, it is possible to figure out the molecular formula of the mandelic acid by counting each carbon, hydrogen and oxygen in the molecule.
In such a way, we can see the presence of eight carbon atoms, eight hydrogen atoms and three carbon atoms; thus, the molecular formula is:
C₈H₈O₃
Furthermore, since the empirical formula is the smallest representation of the molecular formula when we are able to simplify it, we evidence no simplification is possible, consequently, the empirical formula equals the molecular one.
Best regards!
Write the word equation for
the reaction between sodium
hydrogen carbonate and
sulfuric acid.
Answer:
NaHCo3+Na2So4---Nna2So4+H2O+CO2
Answer:
sodium two sulphate+Carbondioxed gas +water
A car changes its velocity from 0 m/s to 14 m/s in 2 seconds.
What is the acceleration
Answer:
7
Explanation:
You divide the 14m/s by 2 and get the answer of the acceleration of 7
Which word best describes the relationship between polyps and algae
exoskeletal
Bleached
Photosynthetic
Symbiotic
Answer:
symbiotic
Explanation:
There like a close friendship
Steam is collected and observed to condense into liquid water. Which of the following would you expect to observe if a thermometer recorded the temperature of the substance?
SELECT AN ANSWER
The temperature would decrease.
The temperature would remain the same.
It would depend on the amount of steam.
The temperature would increase.
the water will be increased
50 POINTS
Which of the following correctly describes a compound?
A. The atoms are bonded together, and the compound has different physical and chemical properties than the individual elements.
B. The atoms have no set ratio for how the atoms can combine, and they are not chemically bonded together.
C. The atoms can only combine in fixed ratios, and they retain their individual chemical and physical properties.
D. The atoms retain their individual chemical properties, and they can only be separated from each other by a chemical change.
Answer: A chemical compound can be described as substance composed of atoms from more than one element held together by chemical bonds in a fixed stoichiometric proportion. A compound has different physical and chemical properties from its constituent elements.
For example : compound water is made up of H and O bonded together and it has different properties from O and H.
Thus, among the given options, the one coreectly describing a compound is
a) The atoms are bonded together, and the compound has different physical and chemical properties than the individual elements.
Calculate the volume in mL of 0.100 of CaCl2 needed to produce 1.00 g of CaCO3. there is an excess of Na2CO3
Answer:
100. mL
Explanation:
The computation of the volume in mL is shown below:
The balance equation of the double displacement reaction is
[tex]CaCl_{2} + Na_{2}CO_{3} \rightarrow 2 NaCl + CaCO_{3}[/tex]
Now determine the moles that corresponding to 1.00 g of CaCO₃
As,
The molar mass of CaCO₃ is 100.09 g/mol.
So,
= 1.00 g × 1 mol/100.09 g
= 0.0100 mol
Now
the moles of CaCl₂ needed to generate 0.0100 moles of CaCO₃
As we know that
The molar ratio of CaCl₂ to CaCO₃ is 1:1.
So, The moles of CaCl₂ needed is
= 1 ÷ 1 × 0.0100 mol
= 0.0100 mol.
Now volume of 0.100 M CaCl₂ that contains 0.0100 mol is
= 0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L
= 100. mL
On the basis of the information above, a buffer with a pH = 9 can best be made by using
A pure NaH2PO4
B H3PO4 + H2PO4–
C H2PO4– + PO42–
D H2PO4– + HPO42–
E HPO42– + PO43
Answer:
D H2PO4– + HPO42–
Explanation:
The acid dissociation constant for [tex]\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}[/tex] are [tex]\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}[/tex] respectively.
[tex]\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}[/tex]
[tex]\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}[/tex]
[tex]\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}[/tex]
The reason while option D is the best answer is that, the value of pKa for both
[tex]\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}[/tex] lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.
Using Henderson-Hasselbach equation:
[tex]\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}[/tex]
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex]. Thus, option D is correct.
The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.
Which compound is used for pH 9 buffer?The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.
For the formulation of buffer of specific pH, the acid and base solutions are required.
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex], as they are able to provide acid and base to the solution.
Thus, option D is correct.
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If 0.64 mol PCl5 is placed in a 1.0 L flask and allowed to reach equilibrium at a given temperature, what is the final concentration of Cl2 in the flask?
PCl5 (g)→ PCl3 (aq) + Cl2 (g) Kc= 0.47
Answer: The final concentration of [tex]Cl_2[/tex] at equilibrium is 0.36 M
Explanation:
Moles of [tex]PCl_5[/tex] = 0.64 mole
Volume of solution = 1.0 L
Initial concentration of [tex]PCl_5[/tex] = [tex]\frac{moles}{Volume}=\frac{0.64mol}{1.0L}=0.64 M[/tex]
The given balanced equilibrium reaction is,
[tex]PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)[/tex]
Initial conc. 0.64 M 0M 0M
At eqm. conc. (0.64-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
[tex]K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}[/tex]
Now put all the given values in this expression, we get
[tex]0.47=\frac{(x)\times (x)}{(0.64-x)}[/tex]
By solving the term 'x', we get :
x = 0.36
Thus, the final concentration of [tex]Cl_2[/tex] at equilibrium is x = 0.36 M
The concentration of Cl2 is 0.36M.
Number of moles of PCl5 = 0.64 mol
Volume = 1.0 L
Concentration of PCl5 = 0.64 mol/1.0 L = 0.64 M
The equation of the reaction is;
PCl5 (g)→ PCl3 (aq) + Cl2 (g)
I 0.64 0 0
C -x +x +x
E 0.64 - x x x
Kc = [PCl3] [Cl2]/[PCl5]
0.47 = x^2/0.64 - x
0.47(0.64 - x) = x^2
0.3 - 0.47x =x^2
x^2 + 0.47x - 0.3 = 0
x = 0.36 M
The concentration of Cl2 is 0.36M.
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What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?
Answer:
What is the functional groups of CH3CH2CH(OH)CH2C(CH3)2Br?
What happens to algae when the temperature in the ocean becomes too hot?
O The algae are susceptible to infection.
O The algae become pale.
O The algae photosynthesize faster.
O The algae lose their ability to photosynthesize
Answer:
The algae lose their ability to photosynthesize.
Explanation:
Because the algae turn the energy from the sunlight into chemicals.
Hoped this helped!
The yield for a particular well is 280 gallons per minute (gpm). Of the drawdown for this well is 23 feet, what is the specific yield in gpm/ft?
Answer:
[tex]Y=12.2 \frac{gpm}{ft}[/tex]
Explanation:
Hello!
In this case, since we can find that the well produces 280 gpm, and the given drawdown is 23 ft, we need to divide 280 by 23 to obtain the yield in gmp/ft as shown below:
[tex]Y=\frac{280gpm}{23ft} \\\\Y=12.2 \frac{gpm}{ft}[/tex]
Best regards!
Name the compound AgF
Answer: Silver (I) fluoride molecule · AgF
Classification: Inorganic compound (Could be salt)
Ionic compound (Silver is a metal)
Valence of F (F must form an octet): 7
Valence of Ag: 11
Total valence electrons: 18
Molar mass: 126.87 g/mol
Explanation:
Prokaryotic cell division is a___________process involving onc chromosom.
A. simple
B. complex
C. unusual
Answer:
It’s is a simple
Explanation:the prokaryotic cell involves a simple process which intern involves one chromosom
Question 6 of 25
When nonionizing radiation is absorbed by matter, it usually becomes which
type of energy?
A. Thermal
B. Mechanical
C. Electromagnetic
O D. Chemical
Answer:
thermal
Explanation:
a p e x
Which of the following are true about an atom? Choose all that apply.
Answer:
Explanation:
Atoms are the building blocks of matter.
They are the smallest particles of an element that still have the element's properties.
All atoms are very small, but atoms of different elements vary in size.
Three main types of particles that make up all atoms are protons, neutrons, and electrons.
An aqueous solution of nitric acid is standardized by titration with a 0.174 M solution of barium hydroxide. If 13.9 mL of base are required to neutralize 28.7 mL of the acid, what is the molarity of the nitric acid solution?
Answer:
Explanation:
2HNO₃ + Ba( OH)₂ = Ba( NO₃ )₂ + 2H₂O .
2 mole 1 mole
13.9 mL of .174M barium hydroxide contains .0139 x .174 moles
= 2.42 x 10⁻³ moles .
1 mole of barium hydroxide reacts with 2 moles of nitric acid
2.42 x 10⁻³ moles of barium hydroxide will react with 2 x 2.42 x 10⁻³ moles of nitric acid
= 4.84 x 10⁻³ moles
4.84 x 10⁻³ moles of nitric acid is contained in 28.7 mL
molarity of nitric acid = 4.84 x 10⁻³ / 28.7 x 10⁻³
= .169 M .
Look at sample problem 19.10 in the 8th ed Silberberg book. Write the Ksp expression. Find the concentrations of the ions you need (in this case Ca2 and F-). Put those concentrations into the Ksp expression to calculate Q. Compare Q to K A common laboratory method for preparing a precipitate is to mix solutions containing the component ions. Does a precipitate form when 10. ml of 0.0010 M Ca(NO3)2 is mixed with 10. ml of 0.00010 M NaF
Answer:
Explanation:
From the information given:
[tex]CaF_2 \to Ca^{2+} + 2F^-[/tex]
[tex]Ksp = 3.2 \times 10^{-11}[/tex]
no of moles of [tex]Ca^{2+}[/tex] = 0.01 L × 0.0010 mol/L
no of moles of [tex]Ca^{2+}[/tex] = [tex]1 \times 10^{-5} \ mol[/tex]
no of moles of [tex]F^-[/tex] = 0.01 L × 0.00010 mol/L
no of moles of [tex]F^-[/tex] = [tex]1 \times 10^{-6}\ mol[/tex]
Total volume = 0.02 L
[tex][Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\ \\ \[[Ca^{2+}}] = 0.0005 \ mol/L[/tex]
[tex][F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}[/tex]
[tex][F^{-}] = 5 \times 10^{-5} \ mol/L[/tex]
[tex]Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}[/tex]
Since Q<ksp, then there will no be any precipitation of CaF2
Titanium(IV) chloride decomposes to form titanium and chlorine, like this:
TiCl4(l) → Ti(s)+ 2Cl2(g)
At a certain temperature, a chemist finds that a reaction vessel containing a mixture of titanium(IV) chloride, titanium, and chlorine at equilibrium has the following composition:
Compound Amount
TiCl4 4.18g
Ti 1.32g
Cl2 1.08g
Required:
Calculate the value of the equilibrium constant for this reaction.
The full question is shown in the image attached to this answer
Answer:
6.2 * 10^-3
Explanation:
The reaction at equilibrium is as follows;
TiCl4(l) → Ti(s)+ 2Cl2(g)
We have to obtain the concentration of chlorine gas as follows;
[Cl2] = 1.08/70.91 g/mol × 5.2 L
[Cl2] = 0.079 M
Kc = [Cl2]^2
Kc = [ 0.079]^2
Kc = 6.2 * 10^-3
What are bacteria? Are they good or bad?
Answer:
Bacteria are a type of biological cell. They constitute a large domain of prokaryotic microorganisms
some are good some are bad
Explanation:
This is the chemical formula for Chormium (III) nitrate Cr(NO3)3Calculate the mass percent of nitrogen in chromium(III) nitrate.
Answer:
The percent composition for nitrogen in chromium(III) nitrate is 6%.
Explanation:
The mass percent of nitrogen in chromium(III) nitrate is 17.655%.
Calculation,
Molar mass of one oxygen = 16 g
molar mass of nine oxygen = 9 × 16 g = 144 g
molar mass of one nitrogen atom = 14 g
molar mass of three nitrogen atom = 3 × 14 g = 42 g
molar mass of one chromium atom = 51.99 g
molar mass of chromium (III) nitrate molecule = 144 g + 42 g + 51.99 g = 237.99 g
Mass percent of nitrogen = mass of three nitrogen atom× 100 /mass of chromium(III)nitrate
Mass percent of nitrogen = 42 g/237.99 g × 100 = 17.655%
What is mass percentage?The percentage of the mass of the element or solute divided by the mass of the compound or solute is called mass percentage
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