Answer:
242
Step-by-step explanation:
Here, we want to calculate t15 + t25
Mathematically, nth term is
a + (n-1)d
here, a = 26 and d = 31-26 = 5
t15 = 26 + (15-1)5
t15 = 26 + 70
t15 = 96
t25 = 26 + (25-1)5
t25 = 26 + 120
t25 = 146
t15 + t25 = 96 + 146 = 242
In a condominium complex, 2/3 of the women are married to 3/4 of the women. What part of the entire population is married? Please show work
Answer:
(QUESTION CORRECTNESS : 2/3 OF MEN ARE MARRIED TO 3/4 OF WOMEN)
Part of Entire Population married = 12/17 = 70.58%
Step-by-step explanation:
Fraction of men married:
[tex]\frac{2}{3}=\frac{4}{6}=\frac{6}{9}=\frac{8}{12}..........[/tex]
Fraction of women married:
[tex]\frac{3}{4}=\frac{6}{8}=\frac{9}{12}=\frac{12}{16} .........[/tex]
To solve the problem, we know that number of husbands should be equal to number of wives.
Number of husbands and wives are represented by the numerators of both fractions.
We have to find such a multiple of each fraction such that there numerator are same.
Let fraction of men married: [tex]\frac{6}{9}[/tex]
Let fraction of women married: [tex]\frac{6}{8}[/tex]
Add the numerators and denominator to find the solution:
[tex]\frac{6+6}{9+8}= \frac{12}{17}[/tex]
Verify which of the following are identities.
Answer:
Only the second equation is an identity
Step-by-step explanation:
1)
[tex]1+\dfrac{\cos^2\theta}{\cot^2\theta(1-\sin^2\theta)}= \\\\\\1+\dfrac{\cos^2\theta}{\cot^2\theta(\cos^2\theta)}= \\\\\\1+\dfrac{1}{\cot^2 \theta}= \\\\\\1+\tan^2\theta=\sec^2\theta\neq 2\sec^2 \theta[/tex]
This one is not an identity.
2)
[tex]19\cos \theta\left( \dfrac{1}{\cos \theta}-\dfrac{\tan \theta}{\csc \theta} \right)= \\\\\\19\cos \theta \left( \dfrac{1}{\cos \theta}-\dfrac{\sin^2 \theta}{\cos \theta} \right)= \\\\\\19\cos \theta \left( \dfrac{1-\sin^2 \theta}{\cos \theta}\right)= \\\\\\19\cos \theta \left( \dfrac{\cos^2 \theta}{\cos \theta}\right)= \\\\\\19\cos \theta (\cos \theta)= \\\\\\19\cos^2 \theta = 19\cos^2 \theta[/tex]
This one is an identity. Therefore, only the second equation is an identity. Hope this helps!
Answer:
the person above me is right :)
Step-by-step explanation:
which of the following statements are Ture...?
ANWSER:
[] The prime factorization of 14 is 2 times 7.
[] The prime factorization of 21 is 3 times 7.
[] 21 is a prime number.
[] 14 is a composite number
[] The GCF of 14 and 21 is 14.
[] The LCM of 14 and 21 is 42
Answer:
1, 2, 4, 6 are true statements
A cube has an edge length of 7 inches. What is its volume, in cubic inches?
Answer:
343 cubic inches
Step-by-step explanation:
7 times 7 times 7 is 343
Please help! Correct answer only!
In a raffle, one ticket will win a $900 prize, and the remaining tickets will win nothing. There are 500 in the raffle. If you have a ticket, what is the expected payoff?
Answer:
" Expected Payoff " ⇒ $ 1.80 ; Type in 1.80
Step-by-step explanation:
Take the probability of winning into consideration;
[tex]Total Number of Tickets - 500,\\Tickets 1 Person Can Enter - 1 Ticket,\\\\Probability of Winning - 1 / 500,\\Money Won - 900 Dollars,\\\\Proportionality - 1 / 500 = x / 900 - where, x = " Expected Payoff "\\1 / 500 = x / 900 - CrossMultiplication,\\\\500 * x = 900,\\x = 900 / 500,\\x = 1.80 Dollars Won!\\\\Conclusion ; x = 1.80 Dollars[/tex]
Solution ; " Expected Payoff " ⇒ $ 1.80
Quadrilaterals ABCD and PQRS shown below are two similar figures.
Find the values of x and y.
Answer:
x = 12, y = 16
Step-by-step explanation:
Since the figures are similar then the ratios of corresponding sides are equal, that is
[tex]\frac{AD}{PS}[/tex] = [tex]\frac{DC}{SR}[/tex] , substitute values
[tex]\frac{20}{2x+6}[/tex] = [tex]\frac{18}{27}[/tex] ( cross- multiply )
18(2x + 6) = 540 ( divide both sides by 18 )
2x + 6 = 30 ( subtract 6 from both sides )
2x = 24 ( divide both sides by 2 )
x = 12
-------------------------------------------
and
[tex]\frac{AB}{PQ}[/tex] = [tex]\frac{DC}{SR}[/tex] , substitute values
[tex]\frac{y}{24}[/tex] = [tex]\frac{18}{27}[/tex] ( cross- multiply )
27y = 432 ( divide both sides by 27 )
y = 16
Simplify 18x2y/27xy3z
Answer: 2/3xy^-2z
Step-by-step explanation:
18/27 = 2/3
x^2 / x = x
y / y^3 = y^-2
z isn’t changed
Put the variables together after dividing and you get 2/3xy^-2z.
Step-by-step explanation:
do you mean like this?
18x²y/27xy³z =
if yes the answer is like this
18/27 = 2/3
x²/x = x
y/y³ = 1/y²
1/z = 1/z
multiply all and that's the answer
⅔ * x * 1/y² * 1/z =
[tex] \frac{2x}{3 {y}^{2} z} [/tex]
Elsa sold 37 pairs of earrings for $20 each at the craft fair. She is going to use 1/4 of the money to buy new CDs and is going to put the rest of the money in her savings account. How much money will she put in her savings account?
Let “s” stand for he amount of money saved
1. Equation:
2. How much money did she spend on CDs?
3. How much money did she out in her savings account?
Answer:
185 -> Spent on new CD's
$ 555 -> Savings Account
Steps:
37*20 = 740/4 = 185 -> Spent on new CD's
740 - 185 = $ 555 -> Savings Account
Description:
The 2 question is asking that how much money did she spend on her CD. We times 37 and 20 = that will equal 740 then we divide 740 by 4 = 185. Meaning we just solved for question 2. Answer is 185 spent on new CD.
For question 3 this time we get 740 again we do it by 37 times 20 equal 740. we minus it by 185 the spent on new CD answer. so 740-185= $555. So answer for question 3 is $555 to her saving account.
Please mark brainliest
Hope this helps.
Enter a number in the box to complete the sentence. Give your answer to the nearest half-hour.
When lit, a candle loses 5% of its original height every hour. Jennifer lit a candle with an original height of 8 inches.
Until the candle has been burning for at least _____ hours, the height of Jennifer's candle will be more than 7 inches.
Please help me answer this I'm currently taking the end of the year assessment right now!!
Answer:
2.5 hours
Step-by-step explanation:
To solve this question we can use the exponencial function:
P = Po * (1 + r)^t
Where P is the final value, Po is the inicial value, r is the rate and t is the time.
In this case, we have Po = 8, P = 7 and r = -5% = -0.05. So, we can solve for t:
7 = 8 * (0.95)^t
0.95^t = 0.875
log(0.95^t) = log(0.875)
t * log(0.95) = -0.1335
t * (-0.0513) = -0.1335
t = -0.1335 / (-0.0513) = 2.6023 hours
Rounding to the nearest half-hour, we have t = 2.5 hours
Answer:
2.5
Step-by-step explanation:
I had this question and got it right
Tim has to cover 3 tanks completley with paint.
answer:
Total surface area of 3 tanks=34.3 m^27 tins of paint are required.Solution,
diameter of tank=1.4 m
Height of tank=1.9 m
Given tank has top and bottom
Now, The total surface area of cylinder tank is given by:
[tex]tsa = 2\pi \: {r}^{2} + (2\pi \: r \: ) \times h[/tex]
r( radius of tank)=
[tex] \frac{diameter}{2} = \frac{1.4}{2} = 0.7 \: m[/tex]
h(height of tank)=1.9 m
TSA of 1 tank
=
[tex]2 \times 3.14 \times {(0.7)}^{2} + 2 \times 3.14 \times 0.7 \times 1.9 \\ = 11.435 \: {m}^{2} [/tex]
TSA Of 3 tanks
=
[tex]3 \times 11.435 \: {m}^{2} \\ = 34.3 \: {m}^{2} [/tex]
Given a tin of plate covers 5m^2 area.
No.of tins required:
1 tin 5m^2
x tin 34.3 m^2
[tex]5x = 34.3(cross \: multiplication) \\ or \: x = \frac{34.3}{5} \\ x = 6.86 \\ x = 7 \: tins[/tex]
therefore 7 tins are required.
Hope this helps...
Good luck on your assignment....
What is an equation in point-slope form of the line that passes through (1, −6) and (4, 6)
Answer:
Step-by-step explanation:
6--6 = 12
4-1 = 3
12/3 = 4
y=4x
-6-4 = -10
y=4x-10
The formula of slope:
Slope = (d - b) / (c - a)
where (a, b) and (c, d) are the two points.
The equation of the line that passes through (1, -6) and (4, 6) is
y = 4x - 10
What is an equation of a line?
The equation of a line is given by:
y = mx + c
where m is the slope of the line and c is the y-intercept.
Example:
The slope of the line y = 2x + 3 is 2.
The slope of a line that passes through (1, 2) and (2, 3) is 1.
We have,
The line passes through (1, -6) and (4, 6).
The formula of slope:
Slope = (d - b) / (c - a)
where (a, b) and (c, d) are the two points.
Now,
(1, -6) = (a, b) and (4, 6) = (c, d)
Slope = (6 + 6) / (4 - 1) = 12 / 3 = 4
m = 4
The equation of a line is given as y = mx + c.
(1, -6) = (x, y)
-6 = 4 x 1 + c
-6 = 4 + c
-6 - 4 = c
c = -10
Now,
The equation of the line that passes through (1, -6) and (4, 6) is
y = 4x - 10
Learn more about equation of a line here:
https://brainly.com/question/23087740
#SPJ2
a 4cm by 6cm rectangle sits inside a circle with a radius of 11 cm what is the shaded region
Answer:
355.94 cm2
Step-by-step explanation:
if it is the area of the shaded part, you have to find the area of rectangle and the area of the circle, then subtract the rectangle's area from the circle's.
area of circle = 3.14( i used this π because the radius is not divisible by 7) × 11 × 11 = 379.94.
area of rectangle = 6 × 4 = 24cm
379.94 - 24.00 = 355.94cm2.
How many prime numbers have squares between 100 and 300?
Answer:
there are 62 prime numbers with squares
Answer:
i believe it is 3...?
11, 13, and 17
Step-by-step explanation:
11 = 121
13= 169
17 = 289
these are prime numbers
3х + y = 8
x - Зу = 11
Answer:
y = 8-3x and y = -11/3 + x/3
For the first equation you have to subtract 3x from both sides of the equation. for the second equation you have to move all terms that doesn't contain y to the right side and solve
What does this problem equal?
(h-k)(3) =
Answer:
3h−3k
Step-by-step explanation:
if james is 9years old and his sister rose is 15 years . what is the sum of their ages
Answer:
24 years
Step-by-step explanation:
James Age = 9 years
Rose's Age = 15 years
Sum of their Ages = 9+15
Sum of their Ages = 24 years
is the sum of (5x - 6) + (x + 2) 6x-4?
Answer:
Yes.
Step-by-step explanation:
Because the terms inside the parentheses are fully simplified, we can just add up the terms:
(5x - 6) + (x + 2) =
5x - 6 + x + 2 =
5x + x - 6 + 2 =
6x - 4
please need help :(
Answer:I think it's D.
Calculate the exact value of
70/15 × 14/5
Answer:
14^2/15
Step-by-step explanation:
70/15 simplifies to 14/3
14/3 X 14/5
= 14^2/15
someone please help
Answer:
See explanation for answers
Step-by-step explanation:
prism = 12*4 + 5*4 + 12*4 + 5*4 + 12*5 + 12*5 = 256 ft²
lateral surface area of pyramid = 4*1/2*5*5 = 50 ft²
area of square base of the pyramid = 5*5 = 25 ft²
total exposed surface area of the figure = 256 + 50 - 25 = 281 ft²
Help please.... question number 1
Answer:
20
Step-by-step explanation:
The height of the platform is when t=0
h(0) = -4(0)^2 + 75(0) +20
=20
The height of the platform is 20
What is the slope of the line that contains the points (-2, 1) and (0, -3)?
Answer:
-2
Step-by-step explanation:
To find the slope we use the formula
m = (y2-y1)/(x2-x1)
= (-3-1)/(0- -2)
= -4 / (+2)
= -2
Which equation represents the line that passes through (-8.11) and
(4,7/2)?
Answer:
[tex]y=-5/8x+6[/tex]
Step-by-step explanation:
[tex]m=\frac{7/2 - 11}{4--8}[/tex]
[tex]m=\frac{-15/2}{12}[/tex]
[tex]m=-5/8[/tex]
[tex]y=-5/8x+b[/tex]
[tex](-8,11)[/tex]
[tex]11=-5/8 \times -8+b[/tex]
[tex]b=11-(-5/8)(-8)[/tex]
[tex]b=6[/tex]
if a+b=7, and a2+b2 =25 then an=?
Answer:
Solution set: (3, 4) and (4, 3)
Step-by-step explanation:
Please, to indicate exponentiation, use " ^ ": a^2 and b^2
Then you have:
a + b = 7 and a^2 + b^2 = 25.
Let's eliminate b: Solve a + b = 7 for b, obtaining b = 7 - a.
Then we have:
a^2 + (7 - a)^2 = 25, or
a^2 + 49 - 14a + a^2 - 25 = 0, or
2a^2 - 14a + 24 = 0, or
a^2 - 7a + 12 = 0, which factors as follows:
(a - 3)(a - 4) = 0
This results in a = 3 and a = 4, in which case the equation a + b = 7 tells us that the b values are 4 and 3 respectively.
Solution set: (3, 4) and (4, 3)
The length of the rectangular fence is 4 feet greater than its width. The perimeter of the fence is less than 42 feet. What is the range of the lengths of the fence?
Answer: 4 feet < Length < 21 feet
Step-by-step explanation:
From the question, the length of the rectangular fence is 4 feet more than its width and the perimeter of the fence is less than 42 feet. The range of the lengths of the fence will be:
Length is greater than 4 feet (4 feet more than the width. This means that the length must be at least 4 feet) and less than 21 feet i.e the length must be less than 1/2 of the perimeter which is 42/2 = 21. Therefore, the answer will be:
4 feet < Length < 21 feet
Answer:
12.5
its right
Step-by-step explanation:
Can someone please help me with my homework.
Answer:
Step-by-step explanation:
a = 22 cm
b = 12 cm
h = 8 cm
[tex]Area=\frac{(a+b)*h}{2}\\\\=\frac{(22+12)*8}{2}\\\\=\frac{34*8}{2}\\\\=34*4[/tex]
= 136 cm²
Write each statement as an algebraic expression.The quotient of the number that is 1 greater than a number b and the number that is twice as large as b.
(b+1)/2b
quotient = divided by
we're dividing a number that is 1 more than b (b + 1), with a number twice as large as b (2b).
X/5=3 anyone know this??
X/2=8.5 and this ??
Answer:
15
17
Step-by-step explanation:
x/5=3 ⇒ x=5*3=15
x/2=8.5 ⇒ x= 2*8.5=17
Select the correct answer from each drop-down menu.
Samuel received $250 as prize money for winning the St. Peterson High School Badminton Tournament. The money was deposited in a special scholarship account that offered an annual interest of 1.8% compounded semiannually. The amount he will have in the account after t years can be calculated using the expression below.
Use the given expression to complete the statements below.
The expression is the of the amount initially deposited and the of one and the rate of increase raised to the number of.
The choices are for 1 are sum, quotient, square, product. Choices for 2 is quotient, sum, product, difference. Choices for 3 are compounding periods, months, years.
Complete Question:
sierrac3000
06/28/2019
Select the correct answer from each drop-down menu.
Samuel received $250 as prize money for winning the St. Peterson High School Badminton Tournament. The money was deposited in a special scholarship account that offered an annual interest of 1.8% compounded semiannually. The amount he will have in the account after t years can be calculated using the expression below.
250(1+0.018/2)^2t
Use the given expression to complete the statements below.
The expression is the *blank* of the amount initially deposited and the *blank* of one and the rate of increase raised to the number of *blank*
1st Blank:
Product
Sum
Quotient
Square
2nd Blank:
Quotient
Product
Difference
Sum
3rd Blank:
Compounding Periods
Years
Months
Answer:
1st blank = product
2nd blank = sum
3rd blank = years
Step-by-step explanation:
The expression given above is :
250(1+0.018/2)^2t
The expression can thus be explained as:
The *product* of the amount initially deposited and the *sum* of one and the rate of increase raised to the number of *years*
Samuel received $250 as prize money for winning the St. Peterson High School Badminton Tournament. The money was deposited in a special scholarship account that offered an annual interest of 1.8% compounded semiannually. The amount he will have in the accoutnt after t years can be calculated using the expression below. Use the given expression to complete the statements below. The expression is the of the amount initially deposited and the of one and the rate of increase raised to the number of .
Complete Question
Samuel received $250 as prize money for winning the St. Peterson High School Badminton Tournament. The money was deposited in a special scholarship account that offered an annual interest of 1.8% compounded semiannually. The amount he will have in the accoutnt after t years can be calculated using the expression below.
[tex]250(1+\frac{0.018}{2})^{2t}[/tex]
Use the given expression to complete the statements below.
The expression is the___(Product , Sum , Quotient , Square) of the amount initially deposited and the____(Quotient , Product , Difference , Sum) of one and the rate of increase raised to the number of ___.(Compounding Periods , Years, Months)
Answer:
ProductSumCompounding PeriodsStep-by-step explanation:
For an amount invested at compound interest at a rate of r% with period for t years,
Amount [tex]=P(1+\frac{r}{k})^{tk}[/tex]
Comparing with the given expression: [tex]250(1+\frac{0.018}{2})^{2t}[/tex]
Period =2
Rate =0.018
Total Compounding Period =2 X t, where t=Number of years
Therefore:
The expression is the Product of the amount initially deposited and the Sum of one and the rate of increase raised to the number of Compounding Periods .
