Which of the following statements is/arel correct:
A. Entropy increases with the number of energetically equivalent ways to arrange the components of a system.
B. A given set of conditions such as P, V, T defines a microstate of a system.
C. The change represented below has a positive AS. 04
a. A only
b. A and C only
c. A and B only
d. A, B, and C
There is an increase in entropy because the energetically equivalent ways to arrange the components of the system increased. Option A and C.
What is entropy?The term entropy refers to the degree of disorder in a system. Thus we know that any change that leads to an increase in the number of particles will lead to an increase in entropy.
Hence, we can see from the diagram that the energetically equivalent ways to arrange the components of the system increased hence there is a positive increase in entropy. The correct options are therefore A and C.
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What occurs during interphase? (Select all that apply.)
cells store up energy
cells produce eight daughter cells
cells take in nutrients
cells grow
Answer:
during interphase the cells start to grow
cells grow, store up energy, and take in nutrients
hope it helped :)
What is the molarity of a solution containing 20moles of NaCl dissolved in 10 liters of water?
10 mol/L
2 mol/L
5mol/L
0.5 mol/L
The molarity of a solution containing 20moles of NaCl dissolved in 10 liters of water is 2 mol/L.
How do we calculate molarity?Molarity of any solution will be calculated by using the below formula:
M = n/V, where
n = moles of solute = 20 mol
V = volume of solution or solvent = 10 L
On putting values on above equation, we get
M = 20 / 10 = 2M
Hence required molarity of NaCl is 2 M.
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(b) the absolute temperature of the gas at which 3.33x103 mol occupies 478 mL at 750 torr,
Explanation:
T=?
Given
n=3.33×10³
V=478mL=4.78L
P=750torr= 0.987 Atm
simply use the formula
PV =nRT
where R is universal gas constant
0.987×4.78= 3.33×10³×8.314×T
T = 0.000170°c
T= 273.15 K!
The absolute temperature of the gas at which 3.33x10³ mol occupies 478 mL at 750 torr is 1.726 × 10-³K
HOW TO CALCULATE TEMPERATURE:
The temperature of a substance can be calculated using the ideal gas law equation as follows:PV = nRT
Where;
P = pressure (atm)V = volume (L)n = number of moles (mol) R = gas law constant (0.0821 molK/Latm)T = temperature (K)According to this question,
P = 750torr = 0.987 atmV = 478mL = 0.478L0.987 × 0.478 = 3.33 × 10³ × 0.0821 × T0.472 = 273.39TT = 0.472 ÷ 273.39T = 1.726 × 10-³KTherefore, the absolute temperature of the gas at which 3.33x10³ mol occupies 478 mL at 750 torr is 1.726 × 10-³KLearn more at: https://brainly.com/question/12124605?referrer=searchResults
A 50.0 mL sample of buffer solution contains 0.120 M acetic acid and 0.150 M sodium acetate. If 5.55 mL of 0.092 M NaOH is added to this solution, identify the resulting number of moles of acetic acid, sodium acetate, and NaOH.
Answer:
see calculations below
Explanation:
Given: HOAc ⇄ [H⁺] + [OAc⁻]
C(i) 0.12M 0M 0.15M
mix => 5.55ml(0.092M NaOH) / (50ml + 5.55ml)
= 0.00555(0.092)mole NaOH / 0.0555 L Soln
= 0.0092M in NaOH is added into the initial buffer solution
= 0.0092M in OH⁻ (NaOH is a strong base => 100% ionized)
Rxn => Addition of 0.0092M OH⁻ will react with 0.0092M H⁺ shifting buffer . equilibrium to the right decreasing [HOAc] and increasing [OAc⁻] by . 0.0092M each.
Therfore ...
Given: HOAc ⇄ [H⁺] + [OAc⁻]
C(i) 0.12M 0M 0.15M
ΔC - 0.0092M +x +0.0092M
C(f) 0.1108M x 0.1592M => New Concentrations . after adding 0.0092M . NaOH
Substituting new acid and ion concentrations into Ka expression ...
Ka = [H⁺][OAc⁻]/[HOAc] = (x)(0.1592M)/(0.1108M) = 1.75 x 10⁻⁵M
=> x = [H⁺](new) = (1.75 x 10⁻⁵M*)(0.1108M)/(0.1592M) = 1.22 x 10⁻⁵M in H⁺ ions
*units of Ka are Molar
FYI => Adding a strong base to a buffer solution will shift pH to more basic.
Adding a strong acid to a buffer solution will shift pH to more acidic.
=> (such is a good way to check that your buffer calculations are correct.)
NOTE => Question asks for moles of HOAc, Na⁺OAc⁻ & NaOH after adding base. Giving answers in terms of Molarity (moles/Liter) is same as moles. Therefore ...
[HOAc] = 0.1108M
[NaOAc] = 0.1592M
[NaOH] = ∅M (from rxn of H⁺ + OH⁻ => H₂O, all NaOH was consumed in acid/base reaction. Remaining are only Na⁺ as a spectator ion and OH⁻ as a function of the new concentration of H⁺ => [OH⁻] = Kw/[H⁺] = 1 x 10⁻¹⁴/1.22 x 10⁻⁵ = 8.2 x 10⁻¹⁰M.
Hope this helps. :-)
The two main categories of energy are ___________________ energy (stored
energy) and __________________________ energy (energy presently doing
work or causing change).
Explanation:
The two main categories of energy are potential energy (stored
energy) and kinetic energy (energy presently doing
work or causing change)...I hope this helps.
You will prepare a 237.5 ml kool-aid solution with a concentration of 1M. The molar mass of kool-aid (or sugar since kool-aid is basically sugar C12H22O11.) is 342 g/mol. Show the
calculations below which helped you create your 1M solution. Note: 237.5 mL is approximately one cup.
Please show your work here.
Liters of water needed __
Molarity of kool-aid needed __
Grams of kool-aid needed __
The mass of the kool aid needed to prepare the solution is 81.2 g.
What is concentration?The term concentration has to do with the amount of substance present in solution. We are told to make calculations regarding the preparation of a 237.5 ml kool-aid solution with a concentration of 1M.
Litres of water needed = 237.5/1000 = 0.2375 L
Molarity of kool-aid needed = 1 M
number of moles = 1 M * 0.2375 L = 0.2375 moles
0.2375 moles = mass of kool aid/molar mass
0.2375 moles = mass/ 342 g/mol
mass = 0.2375 moles * 342 g/mol
mass = 81.2 g
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A gas that exerts a pressure of
15.6 psi in a container with a volume of
L will exert a pressure of
25.43 psi when transferred to a
container with a volume of 1.895 L.
Answer:
3.089 L
Explanation:
From the given information, provided that the no of moles and the temperature remains constant;
[tex]P_1[/tex] = 15.6 psi
[tex]V_1[/tex] = ???
[tex]P_2[/tex] = 25.43 psi
[tex]V_2[/tex] = 1.895 L
Using Boyle's law:
[tex]P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\ V_1 = \dfrac{25.43 \times 1.895}{15.6} \\ \\ \mathbf{ V_1 = 3.089 \ L}[/tex]
What volume in
L
of a 0.724 M Nal solution contains 0.405 mol of Nal ?
Answer:
0.559 L
Explanation:
Step 1: Given data
Moles of sodium iodide (n): 0.405 mol
Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)
Step 2: Calculate the volume of solution (V)
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
V = n/M
V = 0.405 mol/(0.724 mol/L) = 0.559 L
(hope this helps can i plz have brainlist :D hehe)
Can somebody please help me!!
Answer:
acceleration
pls dont report me
Given the balanced reaction: Zn + 2HCl H2 + ZnCl2 How many grams of zinc are needed to produce 5 grams of H2?
Answer:
[tex]161.9gZn[/tex]
Explanation:
Hello there!
In this case, according the given balanced chemical reaction:
[tex]Zn + 2HCl\rightarrow H_2 + ZnCl_2[/tex]
It is possible to evidence the 1:1 mole ratio of hydrogen (molar mass = 2.02 g/mol) to zinc (atomic mass = 65.41 g/mol) which is used to calculate the grams of the latter needed for the production of 5 grams of the former via stoichiometry:
[tex]5gH_2*\frac{1molH_2}{2.02gH_2}*\frac{1molZn}{1molH_2} *\frac{65.41gZn}{1molZn}\\\\=161.9gZn[/tex]
Best regards!
what is reduction potential?
Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
Can somebody please help me!!!!
Answer:
Velocity
Explanation:
Synonyms are words/phrases that mean the exact or nearly exact same in meaning. Velocity, pace, and speed all mean close to the same thing as far as the rate in which something is moving.
need help i only have 5 more minutes left
Answer:
Bleach, seawater, blood, water, coffee, orange, lemon
Explanation:
The pH is a measurement in chemistry defined as the -log [H⁺]. pH is used in quality control of materials. The pH is a scale from 1 (Acids) to 14 (Bases). The pH of 7 is for neutral solutions
Based on the information of the image, the most basic is bleach, then the seawater, the blood, water (Neutral), coffee, orange and, the most acidic is lemon.
The order is:
Bleach, seawater, blood, water, coffee, orange, lemonWhich of the following is/are true?
a
Mixing an acid with base to produce salt and water
is a physical change
b Inflating a volleyball is a chemical change
C Tarnishing of silver is a chemical Change
d All of the above
C
Tarnishing of silver is caused by hydrogen sulfide and other sulfur containing compounds in the air reacting to the silver and resulting in a fine layer of silver sulfide. The other answers don't make sense
Use the standard reduction potentials located in the Tables' linked above to calculate the equilibrium constant for the reaction:
Cd^2+(aq) + H2(g) ----------->Cd(s) + 2H+(aq)
Answer:
3.1 * 10^-14
Explanation:
Note that E°cell = 0.0592/n log K
We can obtain E°cell from the standard reduction potentials of cadmium and hydrogen
Anode reaction
H2(g) ----> 2H+ + 2e
Cathode reaction
Cd^2+(aq) + 2e -----> Cd(s)
E°cell = E°cathode - E°anode
E°cathode = –0.40 V
E°anode = 0 V
E°cell = –0.40 V - 0 V
E°cell = –0.40 V
E°cell = 0.0592/n log K
Where n=2 electrons transferred
–0.40 = 0.0592/2 log K
–0.40 = 0.0296 log K
log K = –0.40/0.0296
log K = -13.5135
K = Antilog ( -13.5135)
K = 3.1 * 10^-14
how many moles are in 1.25x10^20 molecules of HF?
Answer:
1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.
What does the term hospitality mean to you? Give a definition for hospitality.
Answer:
relating to or denoting the business of entertaining clients, conference delegates, or other official visitors.
briefly describe how the pH of a colourless solution could be measured using a universal indicator
Answer:
Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.
Explanation:
~Hope this helps
Use the word bank below to answer the questions that follow:
chemical
mixture
heat capacity
homogeneous viscosity sublimation
physical property compound chemical formula
substance density
mass
temperature
pressure
heterogeneous
The ratio of the mass of a substance to its volume is called
Answer:
The ratio of the mass of a substance to its volume is called...density.
explain why silver chloride cannot be used as an electrolyte
Answer:
This is because .It doesn't reacts with dilute acid .It is a coinage metal.
How much heat is required to raise the temperature of 0.50 kg of liquid water from 15℃ to 90℃?
156.975kj heat is required to raise the temperature of 0.50 kg of liquid water from 15℃ to 90℃.
What is specific heat ?The term specific heat is defined as the quantity of heat required to increase the temperature of one gram of a substance by one Celsius degree.
To calculate the energy required to raise the temperature of any given substance,
Given:
The mass of the material, m
The temperature change that occurs, ΔT
The specific heat capacity of the material, c (which you can look up). This is the amount of heat required to raise 1 gram of that substance by 1°C.
Q = m × c × ΔT
For water, the value of c is 4.186 J/g°C
Therefore,
Q = 500 × 4.186 × 75
= 156,975j
= 156.975kj
Thus, 156.975kj heat is required to raise the temperature of 0.50 kg of liquid water from 15℃ to 90℃.
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If 0.500 mol of acetylene is allowed to completely react with oxygen, what is the final yield of CO2 in moles?
2C2H2(g)+ 5O2(g) - 4CO2(g) + 2H2O(g)
acetylene
Answer:
1.00 moles of CO2 is the final yield.
Explanation:
Based on the reaction:
2C2H2(g)+ 5O2(g) → 4CO2(g) + 2H2O(g)
When 2 moles of acetylene (C2H2) completely reacts with oxygen, 4 moles of CO2 are produced.
To solve this question we must use the chemical equation knowing: 2 moles C2H2 = 4 mol CO2
When 0.500 moles of acetylene react:
0.500 moles C2H2 * (4mol CO2 / 2mol C2H2) =
1.00 moles of CO2 is the final yield3. Calculate the number of nickel atoms in a 5-cent coin of mass 0.942g if it was made of an alloy consisting of 75% copper and 25% nickel.
An unknown substance turns blue litmus paper to red. Which additional test could be used to confirm the substance’s identity?
It should turn phenolphthalein from colorless to pink because it is a base.
It should turn phenolphthalein from pink to colorless because it is a base.
It should turn methyl orange to orange because it is an acid.
It should turn methyl orange to red because it is an acid.
Answer:
D
Explanation:
The isomerization of methyl isonitrile, CH3NC, to acetonitrile, CH3CN, was studied in the gas phase at 215oC, and the following data were obtained: Time (s) [CH3NC] (M) 0 0.0165 2,000 0.0110 5,000 0.00591 8,000 0.00314 12,000 0.00137 15,000 0.00074 (a) Calculate the average rate of reaction, in M/s, for the time interval between each measurement.
Answer:
2.75 × 10⁻⁶ M/s
1.69 × 10⁻⁶ M/s
9.23 × 10⁻⁻⁷ M/s
4.43 × 10⁻⁻⁷ M/s
2.1 × 10⁻⁻⁷ M/s
Explanation:
We have the following information for the isomerization of methyl isonitrile
Time (s) [CH₃NC] (M)
0 0.0165
2000 0.0110
5000 0.00591
8000 0.00314
12000 0.00137
15000 0.00074
To calculate the average rate of reaction (r) for each interval, we need to use the following expression:
r = -Δ[CH₃NC]/Δt
Interval 0-2000 s
r = - (0.0110 M-0.0165 M)/2000 s - 0 s = 2.75 × 10⁻⁶ M/s
Interval 2000-5000 s
r = - (0.00591 M-0.0110 M)/5000 s - 2000 s = 1.69 × 10⁻⁶ M/s
Interval 5000-8000 s
r = - (0.00314 M-0.00591 M)/8000 s - 5000 s = 9.23 × 10⁻⁻⁷ M/s
Interval 8000-12000 s
r = - (0.00137 M - 0.00314 M)/12000 s - 8000 s = 4.43 × 10⁻⁻⁷ M/s
Interval 12000-15000 s
r = - (0.00074 M - 0.00137 M)/15000 s - 12000 s = 2.1 × 10⁻⁻⁷ M/s
The average rates of reactions for the time interval between each measurement are
2.75×10⁻⁶ M/s
1.70×10⁻⁶ M/s
9.23×10⁻⁷ M/s
4.43×10⁻⁷ M/s
2.10×10⁻⁷ M/s
From the question,
We are to calculate the average rate of reaction for each of the measurement.
First, we will create a proper table for the data
Time (s) [CH3NC] (M)
0 0.0165
2,000 0.0110
5,000 0.00591
8,000 0.00314
12,000 0.00137
15,000 0.00074
The average rate of reaction is given by the formula
[tex]Average\ rate\ of\ reaction = \frac{Final\ concentration - Initial\ concentration}{Final\ time - Initial\ time}[/tex]
1.
[tex]Average\ rate\ of\ reaction = \frac{0.0110-0.0165}{2000 -0 }[/tex]
Average rate of reaction = 2.75×10⁻⁶ M/s
2.
[tex]Average\ rate\ of\ reaction = \frac{0.00591-0.0110}{5000 -2000 }[/tex]
Average rate of reaction = 1.70×10⁻⁶ M/s
3.
[tex]Average\ rate\ of\ reaction = \frac{0.00314-0.00591}{8000 -5000 }[/tex]
Average rate of reaction = 9.23×10⁻⁷ M/s
4.
[tex]Average\ rate\ of\ reaction = \frac{0.00137-0.00314}{12000 -8000 }[/tex]
Average rate of reaction = 4.43×10⁻⁷ M/s
5.
[tex]Average\ rate\ of\ reaction = \frac{0.00074-0.00137}{15000 -12000 }[/tex]
Average rate of reaction = 2.10×10⁻⁷ M/s
Hence, the average rates of reactions for the time interval between each measurement are
2.75×10⁻⁶ M/s
1.70×10⁻⁶ M/s
9.23×10⁻⁷ M/s
4.43×10⁻⁷ M/s
2.10×10⁻⁷ M/s
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almunium has a density of 2.70g/cm3. how many moles of aluminium are in a 13.2cm3 block of the metal substances?
Answer:
1.32 moles.
Explanation:
From the question given above, the following data were obtained:
Density of Al = 2.70 g/cm³
Volume of Al = 13.2 cm³
Number of mole of Al =.?
Next, we shall determine the mass of Al.
This can be obtained as follow:
Density of Al = 2.70 g/cm³
Volume of Al = 13.2 cm³
Mass of Al =?
Density = mass / volume
2.7 = mass of Al / 13.2
Cross multiply
Mass of Al = 2.7 × 13.2
Mass of Al = 35.64 g
Finally, we shall determine the number of mole of Al. This can be obtained as follow:
Mass of Al = 35.64 g
Molar mass of Al = 27 g/mol
Number of mole of Al =?
Mole = mass / molar mass
Number of mole of Al = 35.64 / 27
Number of mole of Al = 1.32 moles
Thus, 1.32 moles of aluminum are present in the block of the metal.
the special proteins prevent
a or b
Answer: a
Explanation:
this is common sense
Answer:
C'est fini sous la lettre A. Ice crystals from forming inside it's body
_____________ is a compound that is added in small amount (a
few drops) in acid-base titrations. It changes color over a certain acidity
range, and indicates the end of the titration.
Answer:
Indicator?
Explanation:
not sure though
Water which has soaked into the ground is known as
