BRAIN-COMPATIBLE
Directions: Arrange the sentences in the box to form a problem. Then solve each problem.
Write your answer in your activity notebook.
1. If she leaves home at 6:00 in the morning
What time will she arrive?
Zaira goes to her grandmother's house
She cycles 30 km at a steady speed of 10 km
Problem
Solution
2. I had an average speed of 55 kph for 2 hours in the afternoon
What was the total distance covered by the bus
A bus had an average speed of 65 kph for 1. 5 hours in the morning.
Problem:
Solution:
3 What was the average speed of the train?
The distance between the two stations is 14 km
A train left Station X at 9:00 a. M. And arrived station Y ay 9:30 a. M. ​

The equation [tex]\frac{y+6}{y-1}+\frac{y-4}{y^2-y} = \frac{1}{y-1}[/tex] when solved for y is -3 ± √13

From the question, we have the following parameters that can be used in our computation:

[tex]\frac{y+6}{y-1}+\frac{y-4}{y^2-y} = \frac{1}{y-1}[/tex]

Simplify the denominators

So, we have

[tex]\frac{y+6}{y-1}+\frac{y-4}{y(y-1)} = \frac{1}{y-1}[/tex]

This gives

y + 6 + (y - 4)/y = 1

Subtract 1 from both sides

y + 5 + (y - 4)/y = 0

So, we have

y² + 5y + y - 4 = 0

Evaluate

y² + 6y - 4 = 0

When solved, we have

[tex]y = \frac{-b \pm \sqrt{b^2 -4ac} }{2a}[/tex]

So, we have

[tex]y = \frac{-6 \pm \sqrt{6^2 -4(1)(-4)} }{2(1)}[/tex]

Evaluate

[tex]y = \frac{-6 \pm \sqrt{52} }{2}[/tex]

Evaluate

[tex]y = -3 \pm \sqrt{13}[/tex]

Hence, the solution is -3 ± √13

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The values of a, b, and c that represent the perimeter of the pool are a = 80, b = 0, and c = 100.

Step 1: Add the three dimensions together to find the total length of one side of the perimeter:
(4x^2 + 15) + (8x^2 + 10) + (8x^2) = 20x^2 + 25

Step 2: Since the perimeter has 4 equal sides (it's a rectangle), multiply the total length of one side by 4:
Perimeter = 4(20x^2 + 25) = 80x^2 + 100

Now, compare the perimeter polynomial with the general form ax^2 + bx + c:
80x^2 + 100 = ax^2 + bx + c

From this comparison, you can see that:
a = 80
b = 0 (since there is no term with x)
c = 100

So, the values of a, b, and c that represent the perimeter of the pool are a = 80, b = 0, and c = 100.

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The statement "Dilation 2 has a scale factor 2" (option b).

Dilation is a transformation that changes the size of an object but not its shape. It is a type of transformation that enlarges or reduces an object by a certain factor called the scale factor. The scale factor is a ratio of the size of the dilated image to the size of the original image.

Now, let's talk about the scale factor for each dilation you asked about.

For dilation 1, the scale factor is 1. This means that the size of the dilated image is the same as the size of the original image. In other words, there is no change in size. This type of dilation is often referred to as the identity transformation because it doesn't change the shape or size of the original object.

For dilation 2, the scale factor is 2. This means that the size of the dilated image is twice as large as the size of the original image. In mathematical terms, if the original object has a length of 'x', then the length of the dilated image will be '2x'. Similarly, if the original object has a width of 'y', then the width of the dilated image will be '2y'.

For dilation 3, the scale factor is 3. This means that the size of the dilated image is three times as large as the size of the original image. In mathematical terms, if the original object has a length of 'x', then the length of the dilated image will be '3x'. Similarly, if the original object has a width of 'y', then the width of the dilated image will be '3y'.

Hence the correct option is (b).

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Answer:

Dilation 1 has a scale factor between 0 and 1

Dilation 2 has a scale factor greater than 1

Dilation 3 has a scale factor equal to 1

Step-by-step explanation:

The cost of one pine tree is $17.50.

To find the cost of one pine tree, we can use the information provided about the orders from the Greenery Landscaping Company. We have the following two equations:

1) 2P + 5H = $150 (2 pine trees and 5 hydrangea bushes)

2) 3P + 4H = $144.50 (3 pine trees and 4 hydrangea bushes)

Now, let's solve these equations using the substitution or elimination method. Here, we'll use the elimination method.

Step 1: Multiply the first equation by 3 and the second equation by 2 to make the coefficients of H the same:

1) 6P + 15H = $450

2) 6P + 8H = $289

Step 2: Subtract the second equation from the first equation:

(6P + 15H) - (6P + 8H) = $450 - $289

0P + 7H = $161

Step 3: Divide by 7 to find the cost of one hydrangea bush (H):

H = $161 / 7

H = $23

Step 4: Substitute the value of H back into one of the original equations to find the cost of one pine tree (P). We'll use the first equation:

2P + 5($23) = $150

2P + $115 = $150

Step 5: Subtract $115 from both sides of the equation:

2P = $35

Step 6: Divide by 2 to find the cost of one pine tree (P):

P = $35 / 2

P = $17.50

So, the cost of one pine tree is $17.50.

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The width of the toy train track is 4 cm.

To find the width of the toy train track, we need to consider the inner radius, the arc length of the inner sector, and the arc length of the outer sector.

Given:
Inner radius (r1) = 6 cm
Inner arc length (s1) = 33 cm
Outer arc length (s2) = 55 cm

Step 1: Find the central angle (θ) using the inner arc length and inner radius.
θ = s1/r1 = 33 cm / 6 cm = 5.5 radians

Step 2: Find the outer radius (r2) using the central angle and the outer arc length.
s2 = r2 × θ
55 cm = r2 × 5.5 radians
r2 = 55 cm / 5.5 radians = 10 cm

Step 3: Calculate the width of the track.
Width = Outer radius - Inner radius
Width = r2 - r1 = 10 cm - 6 cm = 4 cm

The width of the toy train track is 4 cm.

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The calculated value of the number of cows that can graze on 720 acres of land is 18

From the question, the statements that can be used in our computation are given as

The area of grazing needed by each cow is 40 acres

From the above statement, the equation to use is

Cows = Area of land/Unit rate of cows

By substituting the given values in the above equation, we have the following equation

Cows = 720/40

Evaluate

Cows = 18

Hence, the calculated number of cows is 18

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The rate of interest that Neil gets, r%, comes out to be 3.18%

Compound interest is calculated as follows:

A = P[tex](1+r)^t[/tex]

where A is the amount

P is the principal

r is the rate of interest

t is the time

Simple interest can be calculated as:

A = P (1 + r * t)

where A is the amount

P is the principal

r is the rate of interest

t is the time

For Kay,

P = £1500

t = 5 years

r = 3% compound annually

A = 1500 [tex](1+0.03)^5[/tex]

= 1500 * [tex]1.03^5[/tex]

= £ 1,738.91

For Neil,

P = £1500

t = 5 years

r = r% simple interest

According to the question,

A = 1738.91

1500 ( 1 + r * 5) = 1738.91

1 + 5r = 1.159

5r = 0.159

r = 0.0318

r% = 3.18%

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We can expect the world's population to exceed 10 billion around the year 2038, based on the given growth rate and exponential growth model.

Using the exponential growth model, the world's population (P) can be projected with the formula P = P0 * e^(rt), where P0 represents the initial population, r is the growth rate, t is time in years, and e is the base of the natural logarithm (approximately 2.718).

In this case, the initial population (P0) at the start of 2022 is 7.95 billion, and the current growth rate (r) is 1.8%, or 0.018 in decimal form.

To estimate when the population will exceed 10 billion, we can rearrange the formula as follows: t = ln(P/P0) / r. We want to find the year (t) when the population (P) surpasses 10 billion.

By plugging in the values, we get: t = ln(10/7.95) / 0.018. Calculating this, t ≈ 15.96 years.

Since we're starting from 2022, we need to add this value to the initial year: 2022 + 15.96 ≈ 2038.

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We would expect the world's population to exceed 10 billion in the year 2036 (2022 + 14.6).

The exponential growth model is given by:

P(t) = P0 * [tex]e^(^r^t^)[/tex]

where P0 is the initial population, r is the annual growth rate as a decimal, and t is the time in years.

From the problem, we know that:

P0 = 7.95 billion

r = 0.018 (1.8% as a decimal)

P(t) = 10 billion

We want to solve for t in the equation P(t) = 10 billion. Substituting in the values we know, we get:

10 billion = 7.95 billion *[tex]e^(0^.^0^1^8^t^)[/tex]

Dividing both sides by 7.95 billion, we get:

1.26 = [tex]e^(0^.^0^1^8^t^)[/tex]

Taking the natural logarithm of both sides, we get:

ln(1.26) = 0.018t

Solving for t, we get:

t = ln(1.26)/0.018

Using a calculator, we get:

t ≈ 14.6 years

So, we would expect the world's population to exceed 10 billion in the year 2036 (2022 + 14.6).

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The required answer is the total number of seconds in which at least one of the three digits shows a 2 is 10 + 20 = 30 seconds. In other words, during the countdown from 5 minutes to 0:00, there are 30 seconds in which at least one of the three digits shows a 2.

To determine the number of seconds in which at least one of the three digits on a digital timer shows a 2 while counting down from 5 minutes (5:00) to 0:00, we need to consider the various possibilities.

Step 1: Determine the total number of seconds in 5 minutes.

There are 60 seconds in a minute, so 5 minutes would be equal to 5 * 60 = 300 seconds.

Step 2: Consider each second from 0 to 300 and check if any of the three digits (hundreds, tens, or ones) contains the digit 2.

To simplify the calculation, we can focus on the ones digit for the first 60 seconds (from 0:00 to 0:59). In this range, the ones digit contains the digit 2 ten times (2, 12, 22, 32, 42, 52, 62, 72, 82, 92). So, in the first minute, there are 10 seconds in which the ones digit shows a 2.

For the remaining 240 seconds (from 1:00 to 4:59), we need to consider both the tens and ones digits. In each minute within this range, the tens digit can have a digit 2 for all ten seconds (20, 21, 22, ..., 29). Additionally, the ones digit can have a digit 2 for ten seconds in each minute. So, in the remaining 240 seconds, there are 10 * 2 = 20 seconds in which at least one of the tens or ones digits shows a 2.

Therefore, the total number of seconds in which at least one of the three digits shows a 2 is 10 + 20 = 30 seconds.

Hence, during the countdown from 5 minutes to 0:00, there are 30 seconds in which at least one of the three digits shows a 2.

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Answer:

f¹(12) = 20

Step-by-step explanation:

f(-2) = 24

f(-1) = 17

f(0) = 12

f(1) = 9

f¹(x) = 2x - 4

f¹(12) = 20

To find the value of tan(θ), we first need to calculate the values of sine and cosine for the given point (4, 3) terminal side. We can use the Pythagorean theorem to find the length of the hypotenuse (r):

r = √((4)^2 + (3)^2) = √(16 + 9) = √25 = 5

Now, we can find sin(θ) and cos(θ) at the terminal side:

sin(θ) = opposite/hypotenuse = 3/5
cos(θ) = adjacent/hypotenuse = 4/5

Then, we can calculate tan(θ):

tan(θ) = sin(θ) / cos(θ) = (3/5) / (4/5) = 3/4

Now we need to find tan(2θ). We can use the double-angle formula for tangent:

tan(2θ) = (2 * tan(θ)) / (1 - tan^2(θ))

Substitute the value of tan(θ):

tan(2θ) = (2 * (3/4)) / (1 - (3/4)^2) = (3/2) / (1 - 9/16) = (3/2) / (7/16)

Now, we'll multiply by the reciprocal to solve for tan(2θ):

tan(2θ) = (3/2) * (16/7) = 24/7

So, tan2θ = 24/7. Your answer is: 24/7

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Answer:

To evaluate the expression −8−10×(−1)+7×(−1), you should follow the order of operations, which is often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) 1. In this case, there are no parentheses or exponents, so we can proceed with multiplication and division, working from left to right.

1. Perform the multiplication operations:

−8−10×(−1)+7×(−1)=−8+10−7

2. Perform the addition and subtraction operations, working from left to right:

−8+10−7=2−7=−5

So, the value of the expression is −5.

The linear equation from the given scatterplot will be y = -0.1x + 9.

On the given scatterplot we have the song released details on the x-axis and the average rating of the songs by the family members on the y-axis.

To get the linear equation from the given scatterplot we have to find the y-intercept of the equation.

The general form of the equation is y = mx + c

here, m is the slope and c is the y-intercept.

By, the given graph we can say that y is intercepting at the value '9'. So, the y-intercept is 9.

To find the slope we have to take two points,

Let's take two points as (1970, 7) and (1990, 5).

From the points slope = (5-7)/(1990-1970)

                                     = -2/20 = -1/10 = -0.1

So, the equation from the given scatterplot is y = mx+c

So, y = -0.1x + 9.

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If Clare's average number of strokes per hole is 3, it means that the total number of strokes she took in the round divided by the number of holes she played is equal to 3.

Let's say Clare played n holes in total and took a total of s strokes in the round. Then we can write:

s/n = 3

Multiplying both sides by n, we get:

s = 3n

This means that Clare took 3 strokes per hole on average, and a total of 3n strokes in the round. If she were to redistribute the strokes on different greens, the total number of strokes would still be 3n, and her average number of strokes per hole would remain 3.

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The diameter of approximately 3.58.

The circumference of a circle is the distance around its edge or perimeter. The diameter of a circle is the distance across it, passing through the center. These two measurements are related by the mathematical constant pi (π), which is the ratio of the circumference of any circle to its diameter.

The formula to find the diameter of a circle from its circumference is:

diameter = circumference/pi

So, if you know the circumference of a circle, you can simply divide it by pi to find the diameter. In the case of the given circumference of 11.27, dividing it by pi gives us the diameter of approximately 3.58.

It's important to note that the diameter of a circle is twice the length of its radius, which is the distance from the center of the circle to its edge. So, if you know the diameter of a circle, you can find its radius by dividing the diameter by 2:

radius = diameter / 2

In this case, the radius of the circle would be approximately 1.79 (since 3.58 / 2 = 1.79).

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To use the Integral Test, we need to find an integral that is comparable to the series. We can do this by using a basic comparison test and comparing it to the p-series with p=2.

n^2 / (n^3 + 3) < n^2 / n^3 = 1/n
The series 1/n is a divergent p-series with p=1, so we can conclude that the original series is also divergent.
To find the corresponding integral, we can integrate the function 1/n^2:
∫(n=1 to ∞) 1/n^2 dn = [-1/n] (n=1 to ∞) = 1/1 - 0 = 1
Since the improper integral converges to 1, we can conclude that the infinite series is divergent by the Integral Test.
Hi there! To use the Integral Test to determine whether the given infinite series is convergent, first rewrite the series as a function:
f(x) = x^2 / (x^3 + 3)

Next, we need to check that the function is continuous, positive, and decreasing on the interval [1, ∞). This function satisfies these conditions.
Now, we will calculate the improper integral:
∫(from 1 to ∞) (x^2 / (x^3 + 3)) dx
Let's use substitution: u = x^3 + 3, so du = 3x^2 dx, and x^2 dx = (1/3)du.
Now, the integral becomes:
(1/3) ∫(from 1 to ∞) (1/u) du
This integral is the same as the integral of 1/u from 1 to ∞, which is a well-known improper integral that diverges (ln(u) evaluated from 1 to ∞ results in ∞).

Therefore, by the Integral Test, the infinite series ∑(from n=1 to ∞) (n^2 / (n^3 + 3)) diverges. So the correct answer is B. Diverges.

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Answer: x² + y²=6.25²

Step-by-step explanation:

Formula for a circle:

(x-h)²+(y-k)²=r²

where (h, k) is the center    yours: (0,0)

r is the raidus                                 r=6.25

Plug in:

x² + y²=6.25²

Cathy served 32 more people on Tuesday than on Monday.

Given, on Monday, Cathy served 9 tables with 6 people at each table. On Tuesday, Cathy served 86 people. We have to find the number of people she served more on Tuesday than on Monday.

So, on Monday she served = 9 tables x 6 people per table

= 54 people.

To find out how many more people Cathy served on Tuesday than on Monday, we can subtract the number of people served on Monday from the number served on Tuesday.

i.e. 86 - 54 = 32.

Therefore, Cathy served 32 more people on Tuesday than on Monday.

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Answer:

The last one.Because the experimental probability is 11 ÷ 50, which is 22%, and the theoretical probability is 1 ÷ 8, which is 12.5%

A measure of goodness of fit for the estimated regression equation is the residual standard error (RSE)

It is a measure of goodness of fit for the estimated regression equation. It measures the average amount that the response variable (y) deviates from the estimated regression line, in the units of the response variable.

The RSE is calculated as the square root of the sum of squared residuals divided by the degrees of freedom. A smaller RSE indicates a better fit of the regression line to the data.

It represents the proportion of the variation in the dependent variable that is explained by the independent variable(s) in the model. The value of R-squared ranges from 0 to 1, with higher values indicating a better fit of the model to the data.

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The new coordinate of the vertex after dilation is (-5, -3).

To find the new coordinate, you'll need to use the given scale factor of 1/3 and apply it to the original vertex coordinates (-15, -9). Here's a step-by-step explanation:

1. Identify the original vertex coordinates: (-15, -9).
2. Identify the scale factor for dilation: 1/3.
3. Apply the scale factor to the x-coordinate: (-15) * (1/3) = -5.
4. Apply the scale factor to the y-coordinate: (-9) * (1/3) = -3.
5. The new coordinates after dilation are (-5, -3).

By following these steps, you can find the new coordinates of the vertex after dilation at the origin using the given scale factor.

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The closest measurement to the circumference of the parachute in feet is 78.54 feet. The calculation was done by multiplying the radius by 2π (the constant pi, approximately equal to 3.14), which gives the circumference of a circle is 78.54 feet.

The circumference of the parachute can be calculated using the formula

C = 2πr

where r is the radius of the parachute.

Given that the radius of the parachute is 12.5 feet, we can substitute this value in the formula and calculate the circumference

C = 2πr

C = 2π(12.5)

C ≈ 78.54 feet

Therefore, the circumference of the parachute is closest to 78.54 feet.

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--The given question is incomplete, the complete question is given

" Which measurement is closest to the circumference of circumference of the parachute in feet if radius is 12.5.  "--

The quadratics that would not have 5 and -7 as zeros are (1) and (3)

From the question, we have the following parameters that can be used in our computation:

Zeros: 5 and -7

This means that

x = 5 and x = -7

Rewrite as

x - 5 = 0 and x + 7 = 0

Multiply both equation

This gives

(x - 5)(x + 7) = 0

Rewrite as

f(x) = (x - 5)(x + 7)

When expanded, we have

f(x) = x² + 2x - 35

So, we have

(2) f(x) = x² + 2x - 35

(4) f(x) = 2(x + 7)(x - 5)

Hence, the quadratics that would not have 5 and -7 as zeros are (1) and (3)

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The estimated volume of the snowpack in the park is approximately 1.94 billion cubic meters.

To estimate the volume of the snowpack in the park, we need to calculate a double integral of the function d(x, y) over the domain D:

V = ∬_D d(x, y) dA

We can evaluate this integral by using iterated integrals. First, we integrate with respect to x over the interval [0, 30] (since the line y = 180 - 2x intersects the x-axis at x = 90):

V = ∫_0^30 (∫_0^(180-2x) (-0.024x + 0.012y + 1.2) dy) dx

Simplifying the inner integral:

V = ∫_0^30 [-0.024xy + 0.006y^2 + 1.2y]_0^(180-2x) dx

V = ∫_0^30 (-0.432x^2 + 21.6x - 5832) dx

Simplifying the integral:

V = [-0.144x^3 + 10.8x^2 - 5832x]_0^30

V = -0.144(30)^3 + 10.8(30)^2 - 5832(30)

V = 1.942592 billion cubic meters (rounded to nine decimal places)

Therefore, the estimated volume of the snowpack in the park is approximately 1.94 billion cubic meters.

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The exponential function y = [tex]2700(1.02)^t[/tex] models the growth of bacteria cells in a petri dish over time, with an initial population of 2700 cells and a growth rate of 2% per hour.

Exponential functions are often used to model situations where the growth or decay of a quantity depends on a constant proportionality factor.

In this case, the proportionality factor is the growth rate, which is represented by the constant 0.02 in the function. The factor (1 + r) represents the growth factor, which is the multiplier for the initial population to calculate the population after t hours. The larger the growth rate, the faster the population will grow, and the steeper the graph of the exponential function will be.

The equation y = [tex]2700(1.02)^t[/tex] can be used to make predictions about the growth of the bacteria population over time. For example, after one hour, the number of bacteria cells would be y = [tex]2700(1.02)^1[/tex] = 2754 cells. After two hours, the number of cells would be y = [tex]2700(1.02)^2[/tex] = 2812 cells, and so on.

It's worth noting that exponential growth cannot continue indefinitely, as there are always limiting factors that will eventually constrain the growth of a population. In the case of bacteria, the petri dish may eventually become overcrowded or run out of nutrients, which will slow or stop the growth of the bacteria population. Therefore, the exponential function y = [tex]2700(1.02)^t[/tex] is a model that is only valid for a certain range of values of t, beyond which other factors may come into play.

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This relationship between slopes can be explained by the fact that the curves y = x^2 and x = y are perpendicular to each other.

To calculate the slope of the curve y = x^2 at the point (3,9), we need to take the derivative of the equation with respect to x. This gives us y' = 2x. At the point (3,9), the slope would be y'(3) = 2(3) = 6.

To calculate the slope of the curve x = y at the point (9,3), we need to rewrite the equation in terms of y. This gives us y = x, and taking the derivative of y with respect to x gives us y' = 1. So the slope at the point (9,3) would be y'(9) = 1.

The simple relationship between these answers is that they are reciprocals of each other. The slope of the curve y = x^2 at a certain point is the inverse of the slope of the curve x = y at the same point.

To illustrate this principle with two more points on these curves, let's choose a second-quadrant point on y = x^2, such as (-2,4), and a corresponding point on x = y, which would be (4,-2).

At the point (-2,4) on y = x^2, the slope would be y'(-2) = 2(-2) = -4. At the corresponding point (4,-2) on x = y, the slope would be y'(4) = 1. Again, we can see that these slopes are reciprocals of each other.

This means that the slopes of the tangent lines at any two intersecting points will always be reciprocals of each other.

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The equation of the line representing that best fit the given scatterplot is given by option d. y = -0.005x + 22.5.

Consider the two points from the attached scatterplot.

Let the coordinates of the two point be ( x₁ , y₁) = ( 1500 , 12.5 )

And other point be ( x₂ , y₂) = ( 2000 , 10 )

Slope of the line 'm'  = ( y₂ - y₁ ) / ( x₂ - x₁ )

                                  = ( 10 - 12.5) / ( 2000 - 1500 )

                                  = -2.5 / 500

                                  = -0.005

From the attached scatterplot we have,

y-intercept 'c' where x = 0 is equals to 22.5.

The equation best which represents the line of best fit for the scatterplot is equals to,

y = mx + c

Substitute the value we have,

y = -0.005x + 22.5

Therefore, the equation of the line representing scatterplot is equals to option d. y = -0.005x + 22.5.

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The above question is incomplete, the complete question is:

Which equation best represents the line of best fit for the scatterplot?

a) y = 2.5x + 25 b) y = −2.5x + 20 c) y = −0.05x + 20 d) y = −0.005x + 22.5

Attached scatterplot.

The statement about the chances of occurrence of nonmoving violations more on a weekend than on a weekday in past ten years is cannot be answered using only the information in the database. So, option(b) is provide the right answer.

Database: The database is a large collection of data and it is used to store and retrieve the accordingly. It has an organization of a certain amount of data that needs and it contains. We have a database of all traffic tickets that were issued over the past ten years in a city. The informations including are

2) nonmoving violations

We have to recongise the statement which is not answering by the above informations in database. First statement is can be answerable, because we have data of year in which tickets are issued. Similarly, statements third and fourth related to data of tickets issued in month and year in past ten years. So, both are answerable statements. Therefore, the second statement

is cannot be answerable here.

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Complete question:

a city maintains a database of all traffic tickets that were issued over the past ten years. the tickets are divided into the following two categories. moving violations nonmoving violations the data recorded for each ticket include only the following information. the month and year in which the ticket was issued the category of the ticket which of the following questions cannot be answered using only the information in the database? responses

a) have the total number of traffic tickets per year increased each year over the past ten years?

b) in the past ten years, were nonmoving violations more likely to occur on a weekend than on a weekday?

c) in the past ten years, were there any months when moving violations occurred more often than nonmoving violations?

d) in how many of the past ten years were there more than one million moving violations?