Select the correct answer.
Identify the end behavior and the zeros of function h.
h(1) = -1³ - 91² +41 +96
Based on these key features, which statement is true about the graph representing function h?
A.
The graph is negative on the intervals (- infinity, -8) and (-4, 3).
B. The graph is positive on the intervals (-8, -4) and (3, infinity).
OC. The graph is negative on the intervals (-3, 4) and (8, ∞).
D. The graph is positive on the intervals (-infinity ,-8) and (-4, 3).

Subdivide the interval [0, 3] into 6 subintervals of equal length, ∆x = (3 - 0)/6 = 1/2. Then the partition is

[tex]\left[0,\dfrac12\right] \cup \left[\dfrac12,1\right] \cup \left[1,\dfrac32\right] \cup \cdots \cup \left[\dfrac52,3\right][/tex]

The right endpoint of the [tex]i[/tex]-th subinterval is

[tex]r_i = \dfrac12 + (i-1)\times\dfrac12 = \dfrac i2[/tex]

with [tex]i\in\{1,2,3,\ldots,6\}[/tex].

Then the area under the [tex]y=x^2[/tex] on the interval [0, 3] is approximately

[tex]\displaystyle \int_0^3 x^2 \, dx \approx \sum_{i=1}^6 (r_i)^2 \Delta x = \frac18 \sum_{i=1}^6 i^2[/tex]

Recall that

[tex]\displaystyle \sum_{n=1}^N n^2 = \frac{N(N+1)(2N+1)}6[/tex]

Then the approximate value of the area is

[tex]\displaystyle \int_0^3 x^2 \, dx \approx \frac{6\times7\times13}{48} = \boxed{\frac{91}8}[/tex]

The actual value of the area is 9, so this approximation is an overestimation, as is always the case when using a right endpoint sum for an increasing function.

Answer:

1/3

Step-by-step explanation:

We multiply 33(Figure A side) by 1 /3 to get 11(Figure B side).

Answer: 1

Step-by-step explanation:

[tex]2x-\sqrt{5}=2x^{1}-\sqrt{5}[/tex], and thus the highest exponent of x is 1

The equation representing the value of the collection after 7 years is  value of collection = 430 + (0.04 * 430 )* 7 or value of collection = $550.4

An equation is a mathematical statement , where the algebraic expression is equated to another algebraic expression.

It is given that

Ella has a collection of vintage action figures that is worth $430.

collection

appreciates at a rate of 4% per year

equation representing the value of the collection after 7 years is

value of collection = 430 + (0.04 * 430 )* t

value of collection = 430 + (0.04 * 430 )* 7

= $550.4

Therefore the equation representing the value of the collection after 7 years is  value of collection = 430 + (0.04 * 430 )* 7 or value of collection = $550.4

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Answer:

-2090

Step-by-step explanation:

1)  Remove parentheses.

-2 -8 -32 -2048

2) Simplify - 2 - 8 to -10.

-10 - 32 - 2048

3) Simplify -10-32 to -42.

-42 - 2048

4) Simplify.

-2090

72

x varies directly as y

hence x=k y

k=6

y=12

x=6×12

x=72

Answer:

11

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= x² - 6x - 4 +5x + 3 ← collect like terms

= x² - x - 1

then

(f + g)(- 3) = (- 3)² - (- 3) - 1 = 9 + 3 - 1 = 11

Answer:

11

Step-by-step explanation:

F(–3)=(–3)²–6(–3)–4===> 9+18–4=23

g(–3)=5(–3)+3=‐15+3=–12

23–12=11

Answer:

(5,18)  & (-5 , 38)

Step-by-step explanation:

  A linear equation represented by a line in a graph intersect the quadratic equation represented by a parabola zero, one or two times.

f(x) = x² - 2x + 3   -------------------(I)  

f(x) = -2x + 28   ---------------------(II)

x² - 2x + 3 = -2x + 28

x² - 2x + 2x + 3 - 28 = 0

x² - 25 = 0

x²         = 25

         x = √25 = √5*5

        x = ± 5

Plugin x = 5 in equation (II),

                    f(5) = -2*5 + 28

                          = -10 + 28

                          = 18

(5 , 18)

Plugin x = -5 in equation (II),

 f(-5) = -2*(-5) + 28

         = 10 + 28

         = 38

(-5, 38)

Answer:

(5, 18) and (-5, 38)

Step-by-step explanation:

Given system of equations:

1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3

2) f(x) = -2x + 28 ⇒ y = -2x + 28

Solve using the Substitution Method:

Step 1: Substitute the the first equation into the second equation.

⇒ x² - 2x + 3 = -2x + 28

Step 2: Solve for x.

x² - 2x + 3 = -2x + 28 [ Add 2x to both sides. ]

x² - 2x + 2x + 3 = -2x + 2x + 28

⇒ x² + 3 = 28 [ Subtract 28 from both sides. ]

x² + 3 - 28 = 28 - 28

⇒ x² - 25 = 0 [ Factor using the following rule: a² - b² = (a - b)(a + b). ]  

(x - 5)(x + 5) = 0

⇒ x - 5 = 0, x + 5 = 0 [ Solve for the values of x. ]

x - 5 + 5 = 0 + 5, x + 5 - 5 = 0 - 5

⇒ x = 5, x = -5

Step 3: Solve for y.

Substitute the found x-values into one of the given equations.

y = x² - 2x + 3 ⇒ y = (5)² - 2(5) + 3 ⇒ y = 25 - 10 + 3 ⇒ y = 18

y = x² - 2x + 3 ⇒ y = (-5)² - 2(-5) + 3 ⇒ y = 25 + 10 + 3 ⇒ y = 38

The solutions to the system of equations are:

⟹ x₁ = 5, y₁ = 18 ⇒ (5, 18)

⟹ x₂ = -5, y₂ = 38 ⇒ (-5, 38)

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2x² + 2x + ? = x

⇒ ? = x - 2x² - 2x

⇒ ? = -2x² - x

Your answer is incorrect because 2x² - x² would mean x² is part of the answer, which is clearly incorrect.

Answer:

81

Step-by-step explanation:

27 people will tell 3 people each. 3x27=81

Answer:

81

Step-by-step explanation:

Answer:

-x+4, 4+-x

Step-by-step explanation:

Obtain these answers by moving the X and 4 around and multiplying the equation by -1

Answer:

[tex]x = -\frac{15}{2}[/tex]

Step-by-step explanation:

Hello!

The formula for the AOS is given to you, and you simply have to plug in the information given by the equation.

Equation of a Parabola (Standard): [tex]y = ax^2 + bx + c[/tex]

Comparing it to our equation:

Plug it in to the AOS formula:

You only have to input 15 in to the correct box since the negative sign is already placed for you.

The correct answer is option A which is the value a₃₂ = 7.

A matrix is a specific arrangement of items, particularly numbers. A matrix is a row-and-column mathematical structure. The a_{ij} element in a matrix, such as M, refers to the i-th row and j-th column element.

In the given matrix the value of a₃₂ means that the element of the third row and the second column.

So the value of a₃₂ will be 7. which is present in the third row and the second column.

Therefore the correct answer is option A which is the value a₃₂ = 7.

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Answer: 14

Step-by-step explanation:

because 8 +4 is 14

Step-by-step explanation:

rewrite the equation as follows

c2d = a - b

divide both sides by 2d

c = (a - b)/2d

Answer:

This point is not on the line, NOT TRUE

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

           b represents the y-intercept

where the format of a point is (x, y)

Given: y = 7x (6/7, -1/4)

we can plug in the point (6/7, -1/4)

-1/4 = 7(6/7)

-1/4 = 6

-1/4 does not equal 6 so this point is not on the line

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Answer:

y=-2/3x-13/3

Step-by-step explanation:

parralel line have the same gradient

y=mx+c is the general straight line equation

m represents the gradient

if the equation is y=-2/3x+3/2

m=-2/3

the coordinates (4,-7)

x=4

y=-7

substitute into equation

-7=-2/3×4+c

-7=-8/3+c

c=-7+8/3

c=-13/3

so the equation is :

y=-2/3x-13/3

In the diagram, the value of the last angle will be 158°.

It should be noted that the total angle is a quadrilateral is 360°.

In this case, the value of the last angle will be:

= 360° - (76° + 110° + 116°)

= 360° - 302°

= 158°

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Answer:

I believe you're trying to say 5+x= 3/4

Answer:

[tex]y=-8x+5[/tex]

Slope-intercept form:

[tex]\implies y=mx+b[/tex] [tex](\text{m=slope};\text{b=y-intercept})[/tex]

Using the slope-intercept form, let's identify the other slopes:

Option A:

[tex]y=-8x+5[/tex]  

[tex]\text{slope}=-8[/tex]

Option B:

[tex]y-9=-2(x+1)[/tex] (This equation is in point-slope form, the slope it too the left, making it -9)

[tex]\text{slope}=-9[/tex]

Option C:

[tex]y=7x-3[/tex]

[tex]\text{slope}=7[/tex]

Option D:

[tex]y+2=6(x+10)[/tex]

[tex]\text{slope}=2[/tex]  (Using point-slope terms, we can find the slope.)

⇒ A 'steep'est slope is closest to almost having a vertical slope or pitch, or  relatively high gradient, as a hill, an ascent, stairs, etc.

[tex]\text{This could be a line }[/tex] ⇒ ([tex]\text{positive or negative}[/tex])

Hence, the linear function with the steepest slope is Option A: [tex]y=-8x+5[/tex].

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Answer:

what?????????????????

Answer:

jackson sold 27 pounds of bananas and 12 pounds of grapes :D

Step-by-step explanation:

Taking into account the definition of a system of linear equations, the number of pounds of bananas and grapes sold are 36 and 16 respectively.

A set of two or more first-degree equations with two or more connected unknowns is referred to as a system of linear equations.

Finding the value of each unknown in order to satisfy all of the system's equations constitutes the process of solving an system of equations. To put it another way, it is necessary to find the values of the unknowns, as they must be replaced with values that, when used to solve the equations, is the process of solving a system of equations

In this case, a system of linear equations must be proposed taking into account that:

You know:

The system of equations to be solved is

x +y= 52

x + 2.25y= 72

There are several methods to solve a system of equations, it is decided to solve it using the graphical method. The system's equations are graphically represented by graphs in the graphical method. The solution of the system is the point of intersection between the graphs, since the coordinates of said point satisfy both equations.

Graphically, it can be seen that the intersection point is (36; 16). That is, the value of x is 36 and the value of y is 16.

Finally, the number of pounds of bananas sold are 36 and the number of pounds of grapes sold are 16.

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Answer:

Range: (-10 , 14)

Step-by-step explanation:

Given information:

Range: (x , y)?

Plug in domain of x = -4 and x = 4 into equation to find range.

f(-4) = 3 * -4 + 2 = -10

f(4) = 12 + 2 = 14

Range: (-10 , 14)

£36

20+25=45          Take away 13 and it's 32.   32+4 (the shipping charge) is 36. So Ruth pays 36 pounds.

Answer:

Bricks for 1 wall= 405

If there are 5 rooms with 4 walls,

Walls= 5 x 4= 20

Bricks= 405 x 20

= 8100

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Answer:

difference-of-squares

Step-by-step explanation:

Use the change-of-basis identity,

[tex]\log_x(y) = \dfrac{\ln(y)}{\ln(x)}[/tex]

to write

[tex]xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}[/tex]

Use the product-to-sum identity,

[tex]\log_x(yz) = \log_x(y) + \log_x(z)[/tex]

to write

[tex]xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}[/tex]

Redistribute the factors on the left side as

[tex]xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}[/tex]

and simplify to

[tex]xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)[/tex]

Now expand the right side:

[tex]xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}[/tex]

Simplify and rewrite using the logarithm properties mentioned earlier.

[tex]xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1[/tex]

[tex]xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}[/tex]

[tex]xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}[/tex]

[tex]xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)[/tex]

[tex]\implies \boxed{xyz = x + y + z + 2}[/tex]

(C)

Let's see

Answer:

53 the correct answer off your question.