Answer:
A) 2
Step-by-step explanation:
Because the slope is negative of line 2 the distance is getting smaller
On a coordinate plane, the x-axis is labeled minutes and the y-axis is labeled Blocks. Line A goes through points (10, 4), (15, 12), and (20, 20). Line B goes through points (5, 8), (10, 16), (15, 24). Line C goes through points (5, 24), (15, 16), (20, 12).
The table shows Jose’s rate of bicycle riding.
A 2-column table with 3 rows. Column 1 is labeled Minutes with entries 5, 10, 15. Column 2 is labeled Blocks with entries 8, 16, 24.
Which line on the graph shows the proportional relationship in the table?
Line
on the graph shows the proportional relationship.
Answer:
wait lang yong tppp heheehhehe
Answer:
b is the awancer yw
Step-by-step explanation:
help i will mark as branliest
Answer:
(a) DE = 7.5 cm
(b) Area of ΔABE = 9.33 cm2
Step-by-step explanation:
(a) [tex]\frac{AE}{DE} =\frac{BE}{CE}[/tex]
[tex]\frac{5}{DE} =\frac{4}{6}[/tex]
[tex]DE=\frac{(5)(6)}{4} =\frac{30}{4} =7.5[/tex]
(b) measurements of similar triangles have a ratio of 2/3
The ratio between areas is
[tex](\frac{2}{3} )^{2} =\frac{4}{9}[/tex]
If the area of ΔCDE = 21
Then the área of ΔABE is:
[tex]21(\frac{4}{9})=\frac{(21)(4)}{9} =\frac{84}{9} =9.33[/tex]
Hope this helps
Consider an investment of $6000 that earns 4.5% interest
What is the value of the investment after
15 years if the interest is compounded
annually?
Answer:
$11,611.69
Step-by-step explanation:
Compound Interest Formula
[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]
where:
A = final amountP = principal amountr = interest rate (in decimal form)n = number of times interest applied per time periodt = number of time periods elapsedGiven:
P = $6,000r = 4.5% = 0.045n = 1 (annually)t = 15 yearsSubstitute the given values into the formula and solve for A:
[tex]\implies \sf A=6000\left(1+\frac{0.045}{1}\right)^{(1 \times 15)}[/tex]
[tex]\implies \sf A=6000(1.045)^{15}[/tex]
[tex]\implies \sf A=11611.69466...[/tex]
Therefore, the value of the investment after 15 years will be $11,611.69 to the nearest cent.
Sam is baking cakes at her parents' bakery. She gets paid $20 a week in addition to $4 for every cake she bakes. She made $60 this week. Write an equation to show how many cakes Sam baked this week
An equation is formed of two equal expressions. The number of cakes that are made by Sam this week is $10.
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Sam gets paid $20 a week in addition to $4 for every cake she bakes. Let y be the total amount that is made by Sam this week, while x represents the number of cakes she bakes. Therefore, the equation for the total amount made by sam in a week can be written as,
y = 20 + 4x
Since her total income for this week is $60, therefore, we can write,
60 = 20 + 4x
40 = 4x
x = 10
Hence, the number of cakes that are made by Sam this week is $10.
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help help help help help
Answer:
2/3 + 9.26 is rational
:)
a father is twice as old as his son. 20 yrs ago the father was four times as old as his son. find their present ages
Answer:
son's present age = 30
father's present age=60
Step-by-step explanation:
his son's present age = x years
his father's present age = 2x years
before 20 years his son's age=(x-20) years
before 20 years father's age=(2x-20) years4(x-20)=(2x-20)
4x-80=2x-20
4x-2x=80-20
2x=60
x=30
It costs $15 to get into the county fair and $2 per pack of ride tickets, t. If you buy 10 packs of ride tickets, how much total would you spend?
Answer:
35$
Step-by-step explanation:
You multiply $2 x 10 = 20$ then add 15$ + 20$ = 35$
The area of a rectangular carpet is 252 square feet. The length is nine feet more than the width. Find the length and the width of the carpet.
Answer:
Length = 30 feet Width = 21 feetGiven - Length is nine feet more
Area is 252
To find - Value of length and width
Solution-
let the width of the carpet be X
therefore length = 9 + X
Area of carpet = Length * width
252 = (9+x) * X
252 = 9x + x²
Solving the equation by splitting middle term
x² + 9x - 252 = 0
x²- 21x + 12x - 252= 0
x ( x - 21) + 12( x - 21) = 0
(x -21)( x + 12) = 0
X = 21 or X = (-12)
Length = 9 + X
= 30 or (-3)
negative is not possible so
length = 30
width = 21
what is the price of a $90 mobile phone after a 30% discount
Answer:
$ 63
Step-by-step explanation:
Let the new price ( price after the discount ) be x.
Old price Discount New price
100 30 70
90 30 x
Now we can make an expression like this to solve this
100 ⇒ 70
90 ⇒ x
Use cross multiplication to solve for x.
100x = 70 × 90
100x = 6300
Divide both sides by 100.
x = $ 63
Answer:
Discount: $27.00
Final Price: $63.00
Step-by-step explanation:
Discount = Original Price x Discount %/100
Discount = 90 × 30/100
Discount = 90 x 0.3
You save = $27.00
Final Price = Original Price - Discount
Final Price = 90 - 27
Final Price = $63.00
helen rolls a dice and flips a coin.
calculate the probability
Answer:
1/12
Step-by-step explanation:
dice rolling=1/6
coin flipping=1/2
Hence probability=1/6×1/2
Answer:
Dice roll = 1/6
Coin flip = 1/2
The Volume of a cube depends on the length of its sides.This can be written in function notation as v(s).What is the best interpretation of V(3)=27
Answer and Step-by-step explanation:
There is a cube with side length 3. The volume of this cube is 27.
PLEASE HELP ME!
3 markers cost $5.79 Which proportion would help determine the cost of 13
markers?
A:
13/5.79=x/3
B:
x/13=3/5.79
C:
3/5.79=13/x
D:
13/x=5.79/3
E:
None of the Above
Answer:
C: 3/5.79=13/x
Step-by-step explanation:
Two ratios are said to be in proportion when the two ratios are equal
3 markers cost $5.79 in which the proportion price is unknown
13 markers cost x
markers / cost = markers / cost
3 / $5.79 = 13 / x
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What IS the slope of a line that is perpendicular to the line y= --x + 5?
• -2
-1/2
1/2
• 2
Let k: y = a₁x + b₁ and l: y = a₂x + b₂. Then
k ║ l ⇔ a₁ = a₂k ⊥ l ⇔ a₁ · a₂ = -1We have the line y = -x + 5 ⇒ a₁ = -1.
Therefore
a₂ · (-1) = -1
-a₂ = -1 Ichange the signs
a₂ = 1Which best describes why the function is nonlinear? the rate of change between 1 and 2 trees is different than the rate of change between 2 and 3 trees. the rate of change between 1 and 2 trees is different than the rate of change between 1 and 3 trees. the rate of change between 2 and 3 trees is different than the rate of change between 3 and 4 trees. the rate of change between 2 and 3 trees is different than the rate of change between 3 and 5 trees.
The function is nonlinear because: D. the rate of change between 2 and 3 trees is different than the rate of change between 3 and 5 trees.
What is a nonlinear function?A nonlinear function can be defined as a type of function whose rate of change (increase or decrease) are not the same i.e they are different.
The rate of change between 2 and 3 trees is given by:
R₂₃ = (180 - 120)/(3-2)
R₂₃ = 60.
Also, the rate of change between 3 and 5 trees is given by:
R₃₅ = (290 - 180)/(5-3)
R₃₅ = 110/2
R₃₅ = 55.
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Complete Question:
A tree company charges a delivery fee for each tree purchased in addition to the cost of the tree. The delivery fee decreases as the number of trees purchased increases. The table below represents the total cost of x trees purchased, including delivery fees. Which best describes why the function is nonlinear?
The function is nonlinear because: D. the rate of change between 2 and 3 trees is different than the rate of change between 3 and 5 trees.
What is a nonlinear function?
A nonlinear function can be defined as a type of function whose rate of change (increase or decrease) are not the same i.e they are different.
The rate of change between 2 and 3 trees is given by:
R₂₃ = (180 - 120)/(3-2)
R₂₃ = 60.
Also, the rate of change between 3 and 5 trees is given by:
R₃₅ = (290 - 180)/(5-3)
R₃₅ = 110/2
R₃₅ = 55.
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Complete Question:
A tree company charges a delivery fee for each tree purchased in addition to the cost of the tree. The delivery fee decreases as the number of trees purchased increases. The table below represents the total cost of x trees purchased, including delivery fees. Which best describes why the function is nonlinear?
Helen bought 3 books and 2 pencil cases. the pencil case cost $8 less than the book. if helen spent $74, how much did a book cost?
The cost of book case be $ 11.6.
What is linear equation?A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form
Ax + B = 0.
Here, let the cost of book case be $ x
and the cost of pencil case be $ y
Now, Helen purchased 3 books and 2 pencils in $ 74.
3x + 2y = 74 .......(i)
Cost of pencil case $ 8 less than the book.
y - 8 = x ............(ii)
put the value of x in equation (i), we get
3(y - 8) + 2y = 74
3y - 24 + 2y = 74
5y = 74 + 24
5y = 98
y = 98/5
y = $ 19.6
put the value of y in equation (ii), we get
x = y -8
x = 19.6 - 8
x = $ 11.6
Thus, the cost of book case be $ 11.6.
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Calculate the following limit:
[tex]\displaystyle \lim_{x \to \infty}{\dfrac{\log(x^8 - 5)}{x^2}}[/tex]
If we evaluate at infinity, we have:
[tex]\bf{\displaystyle L = \lim_{x \to \infty}{\frac{\log(x^8 - 5)}{x^2}} = \frac{\infty}{\infty} }[/tex]
However, the infinity of the denominator has a higher order. Therefore, we can conclude that [tex]\boldsymbol{L = 0.}[/tex]
However, proving that the limit is 0 without using L'Hopital or the "order" criterion is complicated. To do so, let us denote:
[tex]\boldsymbol{\displaystyle f(x) = \frac{\log(x^8 - 5)}{x^2} }[/tex]
To find the limit, we must look for two functions h(x) and g(x) such that h(x)≤ f(x)≤ g(x) and
[tex]\boldsymbol{\displaystyle \lim_{x \to \infty}{h(x)} = 0, \qquad \lim_{x \to \infty}{g(x)} = 0}[/tex]
If we find these functions, then we can conclude that [tex]\bf{\lim_{x \to \infty}{f(x)} = 0.}[/tex]
First, let's note that when x⁸ - 5 > 1, then log(x⁸ - 5) > 0 (and this is true when x is large). Likewise, we have that x² > 0 for x > 0. Therefore, we have:
[tex]\boldsymbol{\displaystyle f(x) = \frac{\log(x^8 - 5)}{x^2} \geq 0}[/tex]
when x "is big enough". Thus, we have h(x) = 0 where it is clear that [tex]\bf{\lim_{x \to \infty}{h(x)} = 0.}[/tex]
To find the second function, let's first note that \log is an increasing function, so since x⁸ ≥ x⁸ - 5, then log(x⁸) ≥ log(x⁸ - 5). So we have to
[tex]\boldsymbol{\displaystyle \frac{\log(x^8 - 5)}{x^2} \leq \frac{\log(x^8)}{x^2} }[/tex]
now, if we take y = e^y, then we can write
[tex]\boldsymbol{\displaystyle \frac{\log(x^8)}{x^2} = \frac{\log(e^{8y})}{e^{2y}} = \frac{8y}{e^{2y}}}[/tex]
A very important property about the exponential function is
[tex]\boldsymbol{\displaystyle e^x > \frac{x^n}{n!}}[/tex]
For any n [tex]\bf{n \in \mathbb{N}}[/tex] and x > 0. If we take n = 2, then we have
[tex]\boldsymbol{\displaystyle e^{2y} > \frac{(2y)^2}{2!} = \frac{4y^2}{2} = 2y^2}[/tex]
From this it follows that
[tex]\boldsymbol{\displaystyle \frac{1}{e^{2y}} < \frac{1}{2y^2} }[/tex]
Therefore, we have to
[tex]\boldsymbol{\displaystyle \frac{\log(x^8 - 5)}{x^2} \leq \frac{\log(x^8)}{x^2} < \frac{8y}{2y^2} = \frac{4}{y} = \frac{4}{\log x} }[/tex]
yes, [tex]\bf{g(x) = 4/\log x}[/tex] where [tex]\bf{\lim_{x \to \infty}{g(x)} = 0}[/tex]. Also, [tex]\bf{h(x) \leq f(x) < g(x)}[/tex]. Therefore, [tex]\bf{\lim_{x \to \infty}{f(x)} = 0}[/tex].
[tex]\red{\boxed{\green{\boxed{\boldsymbol{\sf{\purple{Pisces04}}}}}}}[/tex]
When you multiply a number by 12 and subtract the product from 360, the difference is 216. Find the number.
The equation will be 12a – 360 = 216. Then the value of the variable a will be 48.
What is the solution of the equation?The solution of the equation means the value of the unknown or variable.
When you multiply a number by 12 and subtract the product from 360, the difference is 216.
Let the number be a.
Then we have the equation
12a – 360 = 216
By solving the equation, we have
12a = 216 + 360
12a = 576
a = 576/12
a = 48
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Can someone help please?
Thank you.
Answer:
B and C are the answers.
Step-by-step explanation:
3b+b = 4b because the value of B or any variable is 1 so 3 +1 is four and 4b is our answer.
2(2b) the brackets tell the number before brackets should be multiplied and 2 × 2 is 4 so the answer is 4b
Using circle P with a radius of 7 cm, find the EXACT
measure/length for each of the following.
8.
9
10
11.
12
The diameter of circle P
The circumference of circle P
The area of circle P
The length of RS
The area of sector MPR
P
45
30
S
M
R
Answer:
8. 14
9. 14π
10. 49π
11. 1.75π
12. [tex]\frac{49}{12}[/tex] π
Step-by-step explanation:
If the radius is 7, the diameter is 14.
Circumference is pi * diameter, so 14π
Area is π r², so 49π
Arc length is [tex]\frac{n}{360}[/tex] * 2πr, so [tex]\frac{45}{360}[/tex] * 14π = 1.75π
Sector Area is [tex]\frac{n}{360}[/tex] * πr², so [tex]\frac{30}{360}[/tex] * 49π = [tex]\frac{49}{12}[/tex]π
The terms of a particular sequence are determined according to the following rule: If the value of a given term $t$ is an odd positive integer, then the value of the following term is $3t -9$; if the value of a given term $t$ is an even positive integer, then the value of the following term is $2t -7$. Suppose that the terms of the sequence alternate between two positive integers $(a, b, a, b, \dots )$. What is the sum of the two positive integers
More plainly, the sequence is defined recursively by
[tex]a_{n+1} = \begin{cases} 3a_n - 9 & \text{if } a_n \text{ is odd} \\ 2a_n - 7 & \text{if } a_n \text{ is even} \end{cases}[/tex]
and some starting value [tex]a_1[/tex].
We're given that the sequence alternates between two constants, [tex]a[/tex] and [tex]b[/tex], so that [tex]a_1 = a[/tex].
• If [tex]a[/tex] is even, then the second term [tex]b[/tex] must be odd, since
[tex]a_2 = 2a_1 - 7[/tex]
by the given rule, and 2×(even) - (odd) = (odd). So
[tex]a_2 = 2a-7 = b[/tex]
In turn, the third term is even, since we jump back to [tex]a[/tex]. From the given rule,
[tex]a_3 = 3a_2 - 9[/tex]
and so
[tex]3b-9 = 3(2a-7)-9 = a \implies 6a-30=a \implies 5a=30 \implies a=6[/tex]
[tex]3b-9 = 6 \implies 3b = 15 \implies b = 5[/tex]
Then the sum of the two integers is [tex]a+b=\boxed{11}[/tex]
• You end up with the same answer in the case of odd [tex]a[/tex], so I'll omit this part of the solution. (It's almost identical as the even case.)
Weiming receives a weekly pocket money of $28. If he decides to save 20% of it, find his saving in a year and spendings in a year
Welming's spending is $1164.8 and his savings is $291.2
How to determine the savings and the spending?The given parameters are:
Weekly pocket = $28
Save = 20%
There are 52 weeks in a year.
So, the yearly pocket is:
Yearly pocket = $28 * 52
Evaluate
Yearly pocket = $1456
He saves 20%.
So, we have:
Savings = 20% * $1456
Evaluate
Savings = $291.2
His spending is then calculated as:
Spending = $1456 - $291.2
Evaluate
Spending = $1164.8
Hence, Welming's spending is $1164.8 and his savings is $291.2
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Carefully follow the steps to find the solution to the three equation system.
1.2x+y+3:= 12
2. x-2y+z=-5
3.5.x- y+ 2z = 5
a. Use equations 2 and 3 and eliminate the z by multiplication and addition, creating a new equation with only two variables.
b. Use equations 1 and 2 and eliminate the z by multiplication and addition, creating a second equation with only two variables.
c. Use the two new equations, and eliminate the x-variable by multiplication and addition, finding the value for the y-variable.
d. Substitute y-value in the second new equation and find the x-value.
e. Substitute the z-and y-values into original equation 2 to find the z-value
Answer:
This answer assumes that the first equation is meant to read:
2x + y +3z = 12, and not
1.22x+y+3:= 12
Spoiler Alert: x = 1, y=4, and z=2
Step-by-step explanation:
1. 2x + y +3z = 12
2. x - 2y + z = -5
3. 5x - y+ 2z = 5
==============
Use equations 2 and 3 to eliminate z:
2. x - 2y + z= -5
3. 5x - y+ 2z = 5
-2(x - 2y + z) = -2(-5) [Multiply equation 2 by -2]
5x - y+ 2z = 5
Now subtract this new equation from equation 3:
-2x + 4y - 2z = 10 (Eq 3)
5x - y+ 2z = 5 [
3x +3y = 15 [Equation A]
=================
Use equations 1 and 2 to eliminate z:
2x + y +3z = 12 (Eq. 1)
x - 2y + z = -5 (Eq. 2)
2x + y +3z = 12
(-3)(x - 2y + z = -5) [Multiply Eq. 2 by (-3)]
-3x + 6y -3z = 15
Now add the resulting two equations.
2x + y + 3z = 12 (Eq. 1)
-3x + 6y -3z = 15 (Eq,2 times -3)
-x +7y = 27 [Equation B]
=============
Eliminate x with the 2 resulting equations (from above)
3x +3y = 15 [Equation A]
-x +7y = 27 [Equation B]
----
3x +3y = 15
3*(-x +7y = 27) [Multiply the Equation B by 3]
-3x +21y = 81 [Aha - this equation has a -3x term, exactly what we need to eliminate the x term in Equation A]
---
Now add the two resulting equations:
3x +3y = 15
-3x +21y = 81
24y = 96 [The x term disappears. But we'll "find x" later]
y = 4 [Divide both sides by 24]
Find y and z:
Since y = 4,
-x +7y = 27 (From above, Equation B]
-x = -7y + 27
x = 7y - 27
x = 7(4)-27
x = 1 [Looking good]
=====
Find z: (Use y = 4 and x = 1)
x - 2y + z = -5 [Equation 2]
(1) -2*(4) + z = -5
1 - 8 + z = -5
z = 2
Check:
Do the original equations work when x = 1, y = 4, and z = 2?
Results:
1. 2x + y +3z = 12
(1) + (4) +3(2) YES, this equals 12
2. x - 2y + z = -5
(1) -2*(4) + (2) YES, this equals -5
3. 5x - y+ 2z = 5
5(1) - (4) + 2(2) YES, this equals 5
x = 1, y=4, and z=2
please help!! i’lol give brainliest
Answer:
×=20
Step-by-step explanation:
180-110=70
70+70=140
180-140=40
40÷2=20
Answer:
x = 20°
Step-by-step explanation:
110° and the interior angle of the triangle are a linear pair and sum to 180°
interior angle + 110° = 180° ( subtract 110° from both sides )
interior angle = 70°
the larger triangle is therefore isosceles, 2 base angle are congruent, then
2x = 180° - 140° = 40° ( sum of angles in Δ is 180° )
divide both sides by 2
x = 20°
a Each exterior angle of a regular polygon measures 20° How many sides
does the polygon have?
Answer:
18
Step-by-step explanation:
The exterior angles of any regular polygon add to 360°, so the answer is 360/20 = 18
Natalie works in a toy shop and earns $43 per day. she earns an extra $3 for each toy she sells. if natalie wants to earn at least $70 per day, which inequality shows the minimum number of toys, n, that she should sell?
(a+b)^2=10
and ab=1
then find a^2+b^2
[tex] \underline{\large \bf{Required \: Answer}} : - [/tex]
[tex] \dashrightarrow \: \red{\large8}[/tex]
[tex] \sf[/tex]
[tex] \underline{ \large{ \rm \pink{SolutioN}}} \: -[/tex]
[tex] \quad \qquad\sf \: {(a + b)}^{2} = 10[/tex]
[tex] \qquad \: \: \to\: \: \sf{a}^{2} + {b}^{2} + 2ab = 10[/tex]
[tex] \qquad\: \: \to\: \: \sf{a}^{2} + {b}^{2} + 2(1) = 10[/tex]
[tex] \qquad\: \: \to\: \: \sf \: {a}^{2} + {b}^{2} = 10 - 2[/tex]
[tex] \qquad\: \:\bf \to\: \: \: {a}^{2} + {b}^{2} = 8[/tex]
[tex] \sf[/tex]
[tex] \sf \therefore \: 8 \: \: is \: \: the \: \: required \: \: answer[/tex]
[tex] \rule{200pt}{2pt}[/tex]
In (x, y), if x is _____________, then (x, y) lies either in the 2nd quadrant or in the 3rd quadrant.
Negative
there are four quadrant in the coordinate plan systemvalues of X and y 1st quadrant - ++ 2nd - - + third - - fourth + -The students in Class A and Class B were asked how many pets they each have. The dot plots below show the results.
Students in Class A
A dot plot titled Students in Class A. A number line going from 0 to 5 labeled Number of pets. There are 5 dots above 0, 5 above 1, 4 above 2, 1 above 3, and 0 above 4 and 5.
Students in Class B
A dot plot titled Students in Class B. A number line going from 0 to 5 labeled Number of pets. There is 1 dot above 0, 2 above 1, 2 above 2, 4 above 3, 3 above 4, 3 above 5.
What is the difference between the ranges in the dot plots?
0
2
3
4
Unmark this
Answer:
The difference between the Ranges in the dot plots is 2.
Explanation:The range is the distinction between the greatest or highest value and the minimum or lowest value.I've included a figure with the two-dot plots explained for easier comprehension.
Students from Class A.
The value on the far left of the numbered line that contains at least one point is the minimum value for students in Class A, and the maximum value is three (the value to the extreme right of the numbered line that contains, at least, one point).
Range = 3 - 0 = 3
Students from Class B.The value to the far left of the numbered line that has at least one point is the minimum value for students in Class B, and the maximum value is 5. (the value to the extreme right of the numbered line that contains, at least, one point).
Range = 5 - 0 = 5
Variations in the rangesThe dot plots' range differences are 5 - 3 = 2, which is a difference of two.
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Hurry pleaeeeee show your work
117n + 90=
Answer:
n=-0.769
Step-by-step explanation:
Since there is no number after the equal sign in the equation given, we can put a zero in that place.
117n+90=0
Subtract 90 from both sides.
117n=-90
Divide 117 and -90
n=-0.769
Hope this helps!
If not, I am sorry.
In parallelogram MNPQ if m/PQM = 140°
find m/MNP.
Answer: 140
Step-by-step explanation:
A parallelogram means the sides are parallel, so PQM would have the same angle as MNP since they are opposite, just like NPQ and QMN.
Answer: 140°
Detailed Explanation with Figure:
In a Parallelogram, the Opposite Angles are Equal. Therefore, ∠PQM = ∠MNP, which is equal to 140°.
Here’s the Figure :-