Answer:
N(Au) = 1,20 × 10²²
Explanation:
1) n(Au) = m ÷ M = 4.60 g ÷ 197 g/mol = 0,02 mol
2) N(Au) = n(Au) × N(a) = 0,02 × 6.02*10²³ = 1,20 × 10²²
Why do you think the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene?
Answer:
See explanation
Explanation:
The reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate as well as the reaction of tetraphenylcyclopentadienone and diphenylacetylene are Diels Alder reactions. The former is performed in presence of a solvent while the former is performed neat.
The reaction of tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate leads to the formation of a more resonance-stabilized aromatic ring(lower energy product) compared to the reaction of tetraphenylcyclopentadienone and diphenylacetylene.
Hence, the reaction between tetraphenylcyclopentadienone and dimethyl acetylenedicarboxylate can be conducted at relatively lower temperature compared to the reaction between tetraphenylcyclopentadienone and diphenylacetylene.
Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 12 moles of Al react with 12 moles of HBr, what is the limiting reactant?
Answer:
the limiting reactant is HBr
Explanation:
if you tried to make the products using 12 mol Al and 12 mol HBr, the HBr will run out first
How much water needs to be added to 100 mL of a 20%w solution of copper (II) sulfate to prepare a 0.01-M solution?
Answer:
12430mL of water must be added
Explanation:
To solve this question we need to convert the 20%w of CuSO₄ to molarity. Then, using the diulution factor we can find the amount of water required:
20g CuSO₄ / 100mL * (1mol / 159.609g CuSO₄) = 0.1253 moles / 100mL = 0.1253mol / 0.1L =
1.25M is the concentration of CuSO₄. To dilute this concentration to 0.01M, the dilution factor must be of:
1.25M / 0.01M = 125 times must be diluted the solution.
As the volume of the concentrated solution is 100mL, the total volume of the solution to have a 0.01M solution must be of:
100mL * 125 times = 12530mL is the final volume of the solution. That means the amount of water added must be of:
12530mL - 100mL =
12430mL of water must be addedWhen a chemical reaction occurs, what happens to the atoms of the two substances?
Answer:
In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.
Explanation:
looking at the pure subtances :water,oxygen,copper, can you tell by looking at them if it is pure or not ? explain your answer using example...
Answer:
Yes water is a pure, Water, H2O, is a pure substance, a compound made of hydrogen and oxygen. Although water is the most abundant substance on earth, it is rarely found naturally in its pure form. Most of the time, pure water has to be created. Pure water is called distilled water or deionized water.
Oxygen is a chemical element – a substance that contains only one type of atom. Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus. Oxygen is a gas at room temperature and has no colour, smell or taste
Usually by pure substances we mean either pure elements (all one type of atom), regular crystals (atoms arranged in a repeating pattern), or things made of only one type of molecule (a tightly bound structure of one or more types of atoms). So copper is a pure substance in any form (only copper atoms).
19. 1 mole = _____________________ _________________ g
Answer:
344.1g
Explanation:
A sample of acid rain turned
universal indicator yellow. What would you expect its pH to be? Is it a strong or a weak acid?
Answer:
i think it would be 3 or lower
Answer:
A universal indicator shows a greenish-yellow colour for pH 6 and orange yellow for pH 5. This means that if the indicator turns yellow, the pH should be between these two values. Hence, it must have a pH value between 5 and 6. As the pH is closer to 7 (between 5 and 6), it is a weak acid.Explanation:
Trust the correct answer
Excess silver(I) nitrate was added to a 8.500 g mixture containing some amount of barium chloride, and 7.123 g of silver chloride was obtained. The unbalanced equation is
AgNO3 + BaCl2(aq) --> Ba(NO3)2(aq) + AgCl(s).
What is the mass% of BaCl2 in the mixture?
Answer:
60.88%
Explanation:
The balanced equation of the reaction is given as;
2 AgNO3 (aq) + BaCl2 (aq) → 2 AgCl (s) + Ba(NO3)2 (aq)
Since AgNO3 is in excess, the limiting reactant is BaCl2. From the reaction;
1 mol of BaCl2 produces 2 mol of AgCl
Converting to masses;
Mass = Number of mol * Molar mass
BaCl2;
Mass = 1 * 208.23 g/mol = 208.23 g
AgCl;
Mass = 2 * 143.32 g/mol = 286.64 g
208.23 g BaCl2 produces 286.64 g of AgCl
x g BaCl2 produces 7.123 g of AgCl
Solving for x;
x = 7.123 * 208.23 / 286.64 = 5.1745 g
Mass percent = Mass / Total mass of Mixture * 100
Mass Percent = 5.1745 / 8.500 = 0.6088 * 100 = 60.88%
In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?
Answer:In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?
Explanation:
I need help answering that middle question
Answer: 153
Explanation:
californium is a synthetic radioactive element found on the bottom row of the periodic table, along with other actinides.
It was first discovered in 1950 at the University of California Radiation Laboratory in Berkeley by bombarding curium with alpha particles (helium nuclei). Pure californium metal has a silvery-white appearance and is soft enough to be easily cut with razor blade.
In initial experiments with californium in its concentrated form began in 1958.
Since then, 20 isotopes of californium have been characterize, with mass numbers ranging from 237 to 256. One of these isotopes is californium-252, which was first isolated from a neutron-irradiated sample of plutonium-239. As an exclusively synthetically made element (it cannot be found in nature),
californium-252 is very rare an is produced via neutron bombardment in high flux isotope reactor or particle accelerators.
On this,page we walk through some of the properties and uses of his unique isotope and provide additional resources for your reference.
Hope this helps! :)
How are algae and polyps related?
The polyps receive carbon dioxide from the algae.
The polyps receive shelter from the algae.
The polyps get most of their food from the algae.
The polyps embed themselves in the flesh of the algae.
Answer:
The polyps get most of their food from the algae.
Explanation:
How many moles are there in 2.30 x 1024 atoms of silver?
Answer:
Step 1 should be convert atoms to moles (n). Step 2 should be convert moles (n) to mass (m).
Step 1
Use dimensional analysis to convert the number of atoms to moles.
1 mole atoms = 6.022 × 10²³ atoms
n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms) = 3.8193 mol Ag
Step 2
Convert the moles of Ag to mass.
mass (m) = moles (n) × molar mass (M)
n(Ag) = 3.8193 mol Ag
M(Ag) = atomic weight on the periodic table in g/mol = 107.868 g Ag/mol Ag
m(Ag) = 3.8193 mol × 107.868 g/mol = 412 g Ag = 410 g Ag rounded to two significant figures
The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.
Explanation:
The number of moles that are present is 2.3 × 10²⁴ atoms of silver are 3.8193 moles that can be determined using Avogadro's law.
The calculation for number of moles:One mole:
A mole is defined as 6.022 × 10²³ of some chemical unit, be it atoms, molecules, ions, or others.
1 mole = 6.022 × 10²³ atoms
n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms)
n(Ag) = 3.8193 mol Ag
Thus, the number of moles is 3.8193 moles.
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The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.
Answer: The empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
Explanation:
Mass of C= 17.900 g
Mass of H = 1.680 g
Mass of O = 4.225 g
Mass of N = 1.228 g
Step 1 : convert given masses into moles.
Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{17.990g}{12g/mole}=1.5moles[/tex]
Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.680g}{1g/mole}=1.680moles[/tex]
Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{4.225g}{16g/mole}=0.264moles[/tex]
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{1.228g}{14g/mole}=0.087moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{1.5}{0.087}=17[/tex]
For H = [tex]\frac{1.680}{0.087}=19[/tex]
For O =[tex]\frac{0.264}{0.087}=3[/tex]
For N = [tex]\frac{0.087}{0.087}=1[/tex]
The ratio of C : H: O: N = 17: 19: 3: 1
Hence the empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
Plz help it over science stuff
Answer:9.012
Explanation:
I used the periodic table, the mass is 9.012
Answer:
Pretty sure it would be 69(nice).
Explanation:
You add the number of protons and neutrons to find the mass
10 points Part F
Identify at least two limitations of the simulation. How do these limitations influence the
simulation's ability to model the synthesis of ammonia?
Answer and Explanation:
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
When using simulations, it is important that the researcher knows some limitations. This is because the simulations do not behave exactly like what they represent, in addition to not presenting very important details for analysis and without approximations of what really happens with what they are representing. When modeling the synthesis of Ammonia, for example, these limitations can cause inaccuracies that will compromise the entire analysis.
I have calculated 23 grams of water in a laboratory. What is the amount of molecules
present in this amount?
a. None of the above
b. 8.3x10^24 molecules
c. 6.9x10^23 molecules
d. 7.7x10^23 molecules
e. 5.6x10^25 molecules
Answer:
d. 7.7x10^23 molecules
Explanation:
Given the following data:
Mass of water (H2O) = 23g
To find the number of molecules;
First of all, we would determine the number of moles;
[tex] Number \; of \; moles = \frac {mass}{molar mass} [/tex]
Molar mass of water (H2O) = (1 * 2) + 16 = 18 g/mol
Substituting into the equation, we have
[tex] Number \; of \; moles = \frac {23}{18} [/tex]
Number of moles = 1.2778 moles
Now, to find the number of water molecules;
We know that Avogadro constant is equal to 6.02 * 10^23 mol¯¹
Number of water molecules = number of H2O moles * Avogadro constant
Substituting into the equation, we have;
Number of water molecules = 1.2778 × 6.02 * 10^23
Number of water molecules = 7.7 × 10^23 atoms.
Indicate whether each structure is aromatic, nonaromatic, or antiaromatic. Assume planarity. Compound A is a 5 membered heterocyclic ring containing two pi bonds. On one of the pi bonds is a sulfur with one lone pair and a positive charge. There is an N H group between the two pi bonds with one lone pair. Compound B is a 6 membered ring with three pi bonds. One of the ring atoms is a protonated oxygen with one lone pair. Compound C is an 8 membered ring with a double bond between carbons 2 and 3, between carbons 5 and 6 and between carbons 7 and 8. There is a positive charge on carbon 4 and a negative charge and lone pair on carbon 1. Compound D is a 7 membered ring with three pi bonds. In between two alkenes is a boron attached to a hydrogen. Comppound E is a 7 membered ring with three pi bonds. In between two alkenes is a negative charge with a lone pair.
Answer:
this some next level stuff homie
Explanation:
imma just guess 7?
The thing being described is shaped like a ring with five parts. Inside the ring, there are two special types of bonds. This has a sulfur that is positively charged and has one unshared pair, also it has an NH group with one unshared pair.
What is the structureCompound B is a substance that is made up of two or more different elements or molecules.
The thing being described has a ring with six members and three pi bonds. It has an oxygen atom with an extra proton and one extra electron. This substance is not aromatic.
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Krypton occupies 10.8 L at a pressure of 0.38 atm. Find the volume, in liters, of the krypton when the pressure is increased to 1.6 atm at the same temperature.
Answer:
New volume V2 = 2.565 L
Explanation:
Given:
Old volume V1 = 10.8 L
Old pressure P1 = 0.38 atm
New presuure P2 = 1.6 atm
Find:
New volume V2
Computation:
P1V1 = P2V2
So,
10.8 x 0.38 = V2 x 1.6
New volume V2 = 2.565 L
How does the chemical formula relate to the number of particles that result from the dissociation of a molecule
A chemist determined by measurements that 0.0650 moles of gallium participated in a chemica reaction. Calculate the mass of gallium that participated in the chemica reaction
Answer:
4.53gm
Explanation: n=m/M
n is # of moles
m is mass
M is molar mass
so m=n*M when you rearrange the equation
You dissolve 0.64 g of potassium chloride (KCl) in 725 ml of water.
What is the molarity of the solution?
(From the periodic table: 1 mol K = 39.10 g; 1 mol Cl = 35.453 g)
Enter the value rounded to three decimal places with no units
Will give BRAINLEST
Answer:
0.012 M
Explanation:
Step 1: Given and required data
Mass of KCl (m): 0.64 gVolume of water (V): 725 mL (We will assume it is equal to the volume of the solution)Molar mass of KCl (M): 74.553 g/molStep 2: Calculate the moles (n) of solute (KCl)
We will use the following expression.
n = m/M = 0.64 g / (74.553 g/mol) = 8.6 × 10⁻³ mol
Step 3: Calculate the molar concentration (C) of the solution
The molarity is equal to the moles of solute divided by the liters of solution.
C = 8.6 × 10⁻³ mol/0.725 L = 0.012 M
1) _PA+ __02 → _P,03
Tengo que resolver con procedimiento
1. Un automóvil viaja a una velocidad de 100 Km/h durante dos horas. Calcular la distancia recorrida.
2. Un automóvil viaja a una velocidad de 68 Km/h durante tres horas. Calcular la distancia recorrida.
3. Un auto recorre 154 Km en dos horas. ¿Cuál fue su velocidad?
4. Un auto recorre 1500 Km, si lo hace a una velocidad de 70 Km/h, ¿cuánto tardo en hacerlo?.
Answer:
Distance = 200 km
Distance = 204 km
Speed = 77 km/h
Time = 21.42 h
Explanation:
Given:
A.
Speed = 100 km/h , Time = 2 h
Find:
Distance
B.
Speed = 68 km/h , Time = 3 h
Find:
Distance
C.
Distance = 154 km , Time = 2 h
Find:
Speed
D.
Distance = 1500 km speed = 70 km/h
Find:
Time
Computation:
Speed = distance / time
A.
Distance = 100 x 2
Distance = 200 km
B.
Distance = 68 x 3
Distance = 204 km
C.
Speed = 154 / 2
Speed = 77 km/h
D.
Time = 1500 / 70
Time = 21.42 h
The proteins of all living things require
geometry of amino acids.
As the building blocks of proteins , amino acids are linked to almost every life process, but they also have key roles as precursor compounds in many physiological processes.
Answer:
L
Explanation:
How might the shoot systems and the digestive system in a human be similar? Help please
Answer: The both Deal with digesting and getting rid of waste
Explanation:
Digestive system deals with getting rid of waste in your body and breaking down food.
The digestive system in a human is similar to the shoot system in a plant because both systems are involved in the transport of food materials and waste products in the organism.
The plant is composed of the root system and shoot system. The root system is beneath the ground while the shoot system is above the ground.
In humans, the digestive system carries food materials and waste from the alimentary canal to the small intestine. In plants, the shoot system also performs the same function of carrying food materials and waste products.
Hence, In the shoot system in plants performs a similar function to the digestive system in humans.
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Detection of iron ions Fe+3 and Fet+2
Answer:
The diffrence between Fe2+ and Fe3+ is the Fe2+has a pale green color and turns violet when water is added to it. While Fe3+ forms blood red when it reacts with thiocyanate ions.
Fe2+ has paramagnetic properties whereas
Fe3+ has diamagnetic properties.
Explanation:
I may not be correct.
Answer:
ok ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
cuantas moléculas de aspartame están presente en 10.00 gramos de aspartame
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 1.98×10²²molecules of aspartame are present in 10.00 grams of aspartame.
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.
Mathematically,
mole =given mass ÷ molar mass
=10.00 ÷ 294.30
=0.033moles
number of molecules= Avogadro's number × number of moles
=6.022×10²³× 0.033
= 1.98×10²²molecules
Therefore, 1.98×10²²molecules of aspartame are present in 10.00 grams of aspartame.
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What is the difference between an introduced species and an invasive species?
Answer and Explanation:
The introduced species is, literally, a species that was introduced into an environment by human action. In other words, an introduced species is one that is not native to a region, does not occur naturally, but has been taken by humans to that region.
An invasive species, on the other hand, is one that was introduced naturally in an environment, but multiplied in a harmful way, causing a strong imbalance in the region.
1. What would be the molarity of the sodium ion in solution.
3
A student has a 5.00 gram sample of calcium chloride (CaCl2) solid. How many moles of calcium chloride are
contained in this sample?
Answer: 0.0450 moles of [tex]CaCl_2[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]\text{Number of moles of} CaCl_2=\frac{5.00g}{110.98g/mol}=0.0450moles[/tex]
Thus there are 0.0450 moles of [tex]CaCl_2[/tex]
