WILL GIVE BRAINLIEST

Given the parent function g(x) = log2 x

What is the equation of the function shown

in the graph?

**Answer:**

To determine the equation of the function shown on the graph, we need to analyze its characteristics. From the graph, we can see that the function passes through the point (2, 0) and has a vertical asymptote at x = 1. This information allows us to conclude that the function is a transformation of the parent function g(x) = log2 x. Specifically, it appears to be a horizontal compression and a vertical translation.

To find the equation of the function, we can start by applying the horizontal compression. Let k be the compression factor, then the function can be written as f(x) = log2(kx). Next, we can apply the vertical translation by adding or subtracting a constant, let h be the vertical shift, then the equation becomes f(x) = log2(kx) + h.

To determine the values of k and h, we can use the point (2, 0) and the fact that the vertical asymptote is at x = 1. Setting k = 1/2 since 2k = 1 (corresponding to a horizontal compression by a factor of 1/2), we can find h by substituting the point (2,0) into the equation and solving for h:

0 = log2(1) + h

h = 0

Therefore, the equation of the function shown on the graph is f(x) = log2(1/2 x), which can also be written as f(x) = log2(x) - 1.

**Answer:**

log2 (x - 3) - 2

**Step-by-step explanation:**

When x = 4

log2 of (4 - 3) - 2

= log2 1 - 2

= 0 - 2

So we have the point

(4, -2)

and when x = 7

we have y = log2(7-3) - 2

= log2 4 - 2

= 2-2

= 0

- so we have the poin7 (7,0)

Suppose the length of voicemails (in

seconds) is normally distributed with a mean

of 40 seconds and standard deviation of 10

seconds. Find the probability that a given

voicemail is between 20 and 50 seconds.

10

20

30

40

50

60

P = Г?1%

Hint: Use the 68 - 95 - 99.7 rule

70

Enter

The **probability** that a given voicemail is between 20 and 50 seconds is 0.8185, or 81.85%.

To find the** probability** that a voicemail is between 20 and 50 seconds, we need to standardize the values and use a standard normal distribution table.

First, we find the z-scores for 20 seconds and 50 seconds:

z1 = (20 - 40) / 10 = -2

z2 = (50 - 40) / 10 = 1

Using a standard** normal distribution** table, we can find the area to the left of each z-score:

Area to the left of z1 = 0.0228

Area to the left of z2 = 0.8413

To find the probability between 20 and 50 seconds, we subtract the area to the left of z1 from the area to the left of z2:

P(20 < x < 50) = P(-2 < z < 1)

= 0.8413 - 0.0228

= 0.8185

Therefore, the **probability** that a given voicemail is between 20 and 50 seconds is 0.8185, or 81.85%.

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All the 4-digit numbers you could make using seven square tiles numbered 2, 3, 4, 5, 6, 7, and 8

Using the seven **square** tiles numbered 2, 3, 4, 5, 6, 7, and 8, we can make 1260 different 4-digit numbers.

To create a 4-digit number using these seven **square** tiles, we have to consider the following:

- The first digit cannot be 2 because then the number would only have three digits.

- We can choose any of the remaining six tiles for the first digit, which means there are 6 choices.

- We can **choose** any of the seven tiles for the second digit, which means there are 7 choices.

- We can choose any of the remaining six tiles for the third digit, which means there are 6 choices.

- We can choose any of the remaining five tiles for the fourth digit, which means there are 5 **choices**.

Therefore, the total number of 4-digit numbers we can make is:

6 x 7 x 6 x 5 = 1260

So, using the seven square **tiles** numbered 2, 3, 4, 5, 6, 7, and 8, we can make 1260 different 4-digit numbers.

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Please help me with this math problem!! Will give brainliest!! It's due tonight and it's the last problem!!! :)

part a.

the **percentage** of eggs between 42 and 45mm is **48.48%**

part b.

The **median width** is approximately (42+45)/2 =** 43.5mm.**

The median length is approximately (56+59)/2 = **57.5mm.**

part c.

The width of grade A chicken eggs has a range of about **24mm.**

part d.

I think its impossible to determine because we don't have the value for the **standard deviation**.

The second option should be correct.

What is a histogram?A **histogram** is described as an approximate representation of the distribution of n**umerical data.**

part a.

From the **histogram**, we see that the frequency for the bin that ranges from 42 to 45mm is 4 and we have a total of 33 eggwe use this values and calculate the **percentage** of eggs between 42 and 45mm is 48.48%.

part b.

we have an estimation that the median of the width is 48mm and the median of the length is around 60mm.

part c.

Also from the **histogram**, we notice that the smallest value is around 36mm and the largest value is around 66mm, hence the width of grade A chicken eggs has a range of about 24mm.

In a** histogram**, the range is the width that the bars cover along the x-axis and these are approximate values because histograms display bin values rather than **raw data** values.

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1. In Circle O shown below, with a radius of 12 inches, a sector has been defined by two radii oB and o4 with a central angle of 60° as shown. Determine the area of shaded sector.

B

Step 1: Determine the area of the entire circle in terms of pi.

Step 2: Determine the portion (fraction) of the shaded sect in the circle by using the central angle value.

Step 3: Multiply the area of the circle with the portion (fraction) from step 2.

The **area** of the **shaded sector** of the given **circle** would be = **42,593.5 in²**

To calculate the **area** of the given **sector** the **formula** that should be used is given as follows;

The **area of a sector =( ∅/2π) × πr²**

where;

π = 3.14

r = 12 in

∅ = 60°

**Area** of the **sector** = (60/2×3.14)b × 3.14× 12×12

= 94.2× 452.16

= 42,593.5 in²

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Will give brainliest!

given that the slope of the consecutive sides is -2/3 and 3/2

can you prove that it is a parallelogram or a rectangle.

explain your answer.

A figure with **slope** of consecutive sides -2/3 and 3/2 is a rectangle and it is not a parallelogram.

To prove that it is a **parallelogram** or a rectangle, we need to show that the opposite** sides** are parallel and the adjacent sides are perpendicular.

Let's first check if the opposite sides are parallel. The **slope** of one side is -2/3, and the slope of the adjacent side is 3/2. For opposite sides to be parallel, the slopes must be equal. However, -2/3 and 3/2 are not equal, so we can conclude that the given figure is not a parallelogram.

Now, let's check if the adjacent sides are perpendicular. The product of the slopes of the adjacent sides is

(-2/3) x (3/2) = -1, which is the slope of a line perpendicular to both sides. Since the product of the slopes is -1, we can conclude that the adjacent sides are perpendicular.

Therefore, figure is not a parallelogram, but it is a rectangle.

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Can someone please help me ASAP? It’s due tomorrow

**Answer:**

**Step-by-step explanation:**

tried my best as the first two got me stuck

wouldn't recommend trying my answer and Id wait for another answer

Help with problem in photo

The measures of the arc **angle** AP is 63° using the Angles of Intersecting **Chords** Theorem

What is the Angles of Intersecting Chords Theorem

The Angles of Intersecting Chords Theorem states that the angle formed by the intersection of the **chords** is equal to half the sum of the intercepted arcs, and conversely, that the measure of an intercepted arc is half the sum of the two **angles** that intercept it.

109° = (AP + RQ)/2

109 = (AP + 155)/2

AP + 155 = 2 × 109 {cross multiplication}

AP + 155 = 218

AP = 218 - 155 {collect like terms}

AP = 63°

Therefore, the measures of the arc **angle** AP is 63° using the Angles of Intersecting **Chords** Theorem

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Edro, Lena, Harriet, and Yermin each plot a point to approximate StartRoot 0. 50 EndRoot.

Pedro A number line going from 0 to 0. 9 in increments of 0. 1. A point is between 0. 2 and 0. 3.

Lena A number line going from 0 to 0. 9 in increments of 0. 1. A point is between 0. 4 and 0. 5.

Harriet A number line going from 0 to 0. 9 in increments of 0. 1. A point is at 0. 5.

Yermin A number line going from 0 to 0. 9 in increments of 0. 1. A point is just to the right of 0. 7.

Whose point is the best approximation of StartRoot 0. 50 EndRoot?

Pedro

Lena

Harriet

Yermin

Yermin's point is the best **approximation **of the **square root** of 0.50.

To know whose point is the best approximation of the **square root **of 0.50 on a **number line**. We have the points plotted by Pedro, Lena, Harriet, and Yermin.

Step 1: Calculate the **square root** of 0.50.

[tex]\sqrt{0.50} = 0.707[/tex]

Step 2: Compare the **plotted points** to the calculated square root value.

Pedro: Between 0.2 and 0.3

Lena: Between 0.4 and 0.5

Harriet: At 0.5

Yermin: Just to the right of 0.7

Step 3: Determine the closest approximation.

Yermin's point (just to the right of 0.7) is the closest to the calculated value of 0.707.

Your answer: Yermin's point is the best approximation of the square root of 0.50.

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What is the missing value of G if G is two and one-half times smaller than 19. 02 cm? A. 7. 608 cm B. 7. 808 cm C. 8. 608 cm D. 9. 51 cm

Therefore, **the missing value of G** is 7.608 cm, which is option A.

If **G** is two and one-half times smaller than 19.02 cm, we can find the value of G by **multiplying** 19.02 cm by 2/5, since two and one-half is equal to five halves, or 2/5 when expressed as a **fraction**.

G = (2/5) x 19.02 cm

Simplifying this expression:

G = 7.608 cm

Therefore, the missing value of G is 7.608 cm, which is option A.

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Write a function to model the volume of a rectangular prism if the length is 26cm and the sum of the width and height is 32cm. what is the maximum possible volume of the prism?

To model the **volume of a rectangular prism** with length 26cm and width w and height h such that the sum of the width and height is 32cm, we can use the following function:

V(w, h) = 26wh

subject to the constraint:

w + h = 32

We can solve for one of the variables in the constraint equation and substitute it into the volume equation, giving us:

w + h = 32 => h = 32 - w

**V(w) = 26w(32 - w) = 832w - 26w^2**

To find the maximum possible volume, we can take the derivative of this function with respect to w and set it equal to zero

**dv/dw= 832 - 52w = 0**

Solving for w, we get:

w = 16

Substituting this value back into the constraint equation, we get:

h = 32 - w = 16

Therefore, the maximum possible volume of the prism is:

V(16, 16) = 26(16)(16) = 6656 cubic cm

So the function to model the volume of the rectangular prism is V(w) = 832w - 26w^2, and the maximum possible volume is 6656 cubic cm when the width and height are both 16cm.

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Given that in an arithmetic series a8 = 1 and a30=-43, find the sum of terms 8 to 30.

The sum of terms 8 to 30 in the **arithmetic** **series** is -826.

In an arithmetic series, the nth **term** is given by the formula an = a1 + (n-1)d, where a1 is the first term and d is the common difference between terms.

We are given that a8 = 1 and a30 = -43. Using the formula above, we can write:

a8 = a1 + 7d = 1 (1)

a30 = a1 + 29d = -43 (2)

Subtracting equation (1) from equation (2), we get:

22d = -44

d = -2

Substituting d = -2 into equation (1) and solving for a1, we get:

a1 = 15

Now we can use the formula for the **sum** of an arithmetic series to find the sum of terms 8 to 30:

S = (n/2)(a1 + an)

S = (23/2)(15 + (-43))

S = -826

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Given two events E and F with Pr(E) = 0. 4, Pr(F) = 0. 5, and Pr(EnF) = 0. 3, a) Pr(E|F) = b) Pr(F|E) = c) Are E and F independent? (Enter YES or NO)

Given two **events** E and F with Pr(E) = 0. 4, Pr(F) = 0. 5, and Pr(EnF) = 0. 3 then:

a) Pr(E|F) = 0.6

b) Pr(F|E) = 0.75

c) NO, E and F are not independent.

a) To find Pr(E|F), we use the **formula**: Pr(E|F) = Pr(EnF)/Pr(F). Substituting the given values, we get Pr(E|F) = 0.3/0.5 = 0.6.

b) Similarly, to find Pr(F|E), we use the formula: Pr(F|E) = Pr(EnF)/Pr(E). Substituting the given values, we get Pr(F|E) = 0.3/0.4 = 0.75.

c) We can check for **independence** by seeing if Pr(E) = Pr(E|F) or Pr(F) = Pr(F|E). However, since Pr(E) ≠ Pr(E|F) and Pr(F) ≠ Pr(F|E), we can conclude that E and F are not independent.

In other words, the occurrence of one event affects the probability of the other event occurring. Specifically, the fact that Pr(EnF) ≠ Pr(E)Pr(F) indicates that the events are dependent.

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Mohal is a waiter at a restaurant. Each day he works, Mohal will make a guaranteed wage of $25, however the additional amount that Mohal earns from tips depends on the number of tables he waits on that day. From past experience, Mohal noticed that he will get about $15 in tips for each table he waits on. How much would Mohal expect to earn in a day on which he waits on 16 tables? How much would Mohal expect to make in a day when waiting on

�

t tables?

**Answer:**

If Mohal waits on 16 tables, he can expect to earn $25 wages + ($15 tips x 16 tables) = $265 in a day.

If Mohal waits on 1 table, he can expect to earn $25 wages + ($15 tips x 1 table) = $40 in a day.

What is the explicit equation for the nth term of the arithmetic sequence 6.3, 3.6, 0.9, –1.8, –4.5, …? an = 6.3 – 2.7n an = 6.3 – 2.7(n – 1) an = 6.3 + 2.7n an = 6.3 + 2.7(n + 1)

The **explicit** **equation** for the nth term of the arithmetic sequence is an = 9 - 2.7n.

**What is the implicit equation?**

An implicit equation is an equation in which the variables are **not** **explicitly expressed** in terms of each other. In other words, the equation does not give a direct formula for one of the variables in terms of the other(s), but rather relates the variables through some function or equation.

**What is the explicit equation?**

An explicit equation is an equation in which one variable is expressed **directly** in terms of the other(s). In other words, the equation gives a formula for one of the variables in terms of the other(s).

**According to the given information:**

the first term of the sequence is a1 = 6.3, and the common difference between consecutive terms is d = -2.7 (since we subtract 2.7 from each term to get to the next term). Therefore, the explicit equation for the nth term of the sequence is:

an = 6.3 + (n - 1)(-2.7)

Simplifying this expression, we get:

an = 6.3 - 2.7n + 2.7

an = 9 - 2.7n

So the correct equation for the nth term of the arithmetic sequence 6.3, 3.6, 0.9, -1.8, -4.5, ... is:

an = 9 - 2.7n

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Lesley needs to spend at least $15 at the grocery store to use a coupon. She buys 1 container of tomatoes and needs to buy some potatoes. One container of tomatoes costs $2. 75 and one pound of potatoes costs $2. 45. How may pounds of potatoes, p, does Lesley need to buy to use the coupon? write your answer using an inequality symbol

**Answer: 5**

**2.75+(2.45x5) = 15**

Each year Wenford Hospital records how long patients wait to be treated in the Accident

and Emergency department.

In 2015 patients waited 11% less time than in 2014.

In 2015 the average time patients waited was 68 minutes.

(a) Work out the average time patients waited in 2014.

Give your answer to the nearest minute.

The** average time** patients waited in 2014 was approximately 76 minutes, calculated by dividing the 2015 waiting time by 0.89 as patients waited 11% less time in 2015.

Let's call the average time patients waited in 2014 as per **Wenford Hospital records** "x" (in minutes). According to the problem statement, patients waited 11% less time in 2015 compared to 2014, so,

0.89x = 68

Solving for x,

x = 68 / 0.89

x ≈ 76.4

Therefore, the average time **patients** waited in 2014 was approximately 76 **minutes** (rounded to the nearest minute).

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Write an expression for the sequence of operations described below.

Subtract three from the product of seven and eight

Type x if you want to use a multiplication sign. Type / if you want to use a division sign. Do not simplify any part of the expression.

An expression for the sequence of **operations** described "Subtract three from the **product** of seven and eight." is (7 × 8) - 3.

In order to evaluate and solve this **expression**, we would have to apply the PEMDAS rule, where mathematical **operations** within the parenthesis (grouping symbols) are first of all evaluated, followed by exponent, and then multiplication or division from the left side of the equation to the right. Lastly, the mathematical **operations** of addition or **subtraction** would be performed from left to right.

Based on the information provided, we have the following mathematical **expression**:

Expression: (7 × 8) - 3

56 - 3

53

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The charge for a mission to the zoo is $3.25 for each adult and $1.50 for each student. on a day when 400 people paid to visit the zoo, the receipts totaled 1,237. find the number of adult tickets purchased that day

The **number** of adult tickets purchased that day was **36** if the charge is $3.25 for each adult and $1.50 for each student and 400 people paid $1237

Let the number of adults be x

the number of students be y

Total **people** = 400

x + y = 400

Total **receipts** = $1,237

**Cost** of an adult ticket = $3.25

Cost of a student ticket = $1.50

Cost of x adults tickets = 3.25x

Cost of y student tickets = 1.50y

3.25x + 1.50y = 1237

Multiply the first **equation** by 1.50

1.50x + 1.50y = 600

**Subtract** the second and above equation

1.75x = 637

x = 364

364 + y = 400

y = 36

Thus, the number of adult tickets purchased is **36**.

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exercise 4.11. on the first 300 pages of a book, you notice that there are, on average, 6 typos per page. what is the probability that there will be at least 4 typos on page 301? state clearly the assumptions you are making.

**The probability** that there will be at least 4 typos on page 301 is 0.847

To solve this problem, we need to make some assumptions. Let's assume that the number of typos on each page follows a **Poisson distribution** with a mean of 6 typos per page, and that the number of typos on one page is independent of the number of typos on any other page.

Under these assumptions, we can use the Poisson distribution to calculate the probability of observing a certain **number of typos** on a given page.

Let X be the number of typos on page 301. Then X follows a Poisson distribution with a mean of 6 typos per page. The probability of observing** at least 4 **typos on page 301 can be calculated as follows

P(X ≥ 4) = 1 - P(X < 4)

= 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

Using the **Poisson distribution formula**, we can calculate the probabilities of each of these events

P(X = k) = (e^-λ × λ^k) / k!

where λ = 6 and k is the number of typos. Thus,

P(X = 0) = (e^-6 × 6^0) / 0! = e^-6 ≈ 0.0025

P(X = 1) = (e^-6 × 6^1) / 1! = 6e^-6 ≈ 0.015

P(X = 2) = (e^-6 × 6^2) / 2! = 18e^-6 ≈ 0.045

P(X = 3) = (e^-6 × 6^3) / 3! = 36e^-6 ≈ 0.091

Plugging these values into the** equation **above, we get

P(X ≥ 4) = 1 - (e^-6 + 6e^-6 + 18e^-6 + 36e^-6)

≈ 0.847

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What is the length of the segment indicated by the question mark

Check the picture below.

[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2 \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{6.6+x}\\ a=\stackrel{adjacent}{6.6}\\ o=\stackrel{opposite}{8.8} \end{cases} \\\\\\ (6.6+x)^2= (6.6)^2 + (8.8)^2\implies (6.6+x)^2=121\implies (6.6+x)^2=11^2 \\\\\\ 6.6+x=11\implies x=4.4[/tex]

Question 3 Part C (3 points): Tami has two jobs and can work at most 20 hours each week. She works as a server and makes $6 per hour. She also tutors and makes $12 per hour. She needs to earn at least $150 a week. Review the included image and choose the graph that represents the system of linear inequalities.

The **expression **of linear inequalities that represents **Tami's **earnings is as follows: 6x + 12y ≥ 150.

A **linear **inequality is a mathematical expression that involves a linear function and a relational operator such as <, >, ≤, ≥, or ≠ and it can be used to compare two expressions or values. It defines a range of values that satisfy inequality.

For the scenario painted above, we see that Tani is meant to earn a **minimum of $150 **Thus, the greater than or equal to symbol ≥ should be used for the expression. $6 per hour and $12 per hour are also well represented in the equation.

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Find the distance between

the points (4, -3) and (-2, 1)

on the coordinate plane.

Ay

O

X

**Answer:no image**

**Step-by-step explanation:**

A rectangular living room measures 6 by 12 feet. At $36 per square yard, how much will it cost to carpet the room?

First, we need to determine the area of the living room in square feet, which can be calculated by multiplying the length by the width:

Area = length x width = 6 feet x 12 feet = 72 square feet

Since carpet is usually priced by the square yard, we need to convert the area from square feet to square yards. There are 9 square feet in 1 square yard, so:

Area in square yards = 72 square feet / 9 = 8 square yards

Now, we can calculate the total cost of carpeting the living room by multiplying the area in square yards by the price per square yard:

Cost = area in square yards x price per square yard = 8 square yards x $36 per square yard = $288

Therefore, it would cost $288 to carpet the living room.

Area = length x width = 6 feet x 12 feet = 72 square feet

Since carpet is usually priced by the square yard, we need to convert the area from square feet to square yards. There are 9 square feet in 1 square yard, so:

Area in square yards = 72 square feet / 9 = 8 square yards

Now, we can calculate the total cost of carpeting the living room by multiplying the area in square yards by the price per square yard:

Cost = area in square yards x price per square yard = 8 square yards x $36 per square yard = $288

Therefore, it would cost $288 to carpet the living room.

**Answer:**

It will cost **$288** to **carpet** the **living room** at **$36** **per square yard**.

**Step-by-step explanation:**

**First**, we need to **convert** the **room** **dimensions** to **square yards**, since the **carpet** **price** is given in **square yards**.

The **area** of the **living room** is:

[tex]\sf:\implies 6\: ft \times 12\: ft = 72\: ft^2[/tex]

To **convert** this to **square** **yards**, we **divide** by **9** (since there are 9 square feet in a square yard):

[tex]\sf:\implies \dfrac{72\: ft^2}{9} = 8\: yards^2[/tex]

So the **living room** is **8 square yards** in **area**.

To **find** the **cost** of **carpeting** the **room**, we **multiply** the **area** by the **cost** **per square yard**:

[tex]\sf:\implies 8\: yards^2 \times \$36/square\: yard = \boxed{\bold{\:\:\$288\:\:}}\:\:\:\green{\checkmark}[/tex]

**Therefore**, it will cost **$288** to **carpet** the **living** **room** at **$36 per square yard**.

Consider the concentration, C, (in mg/liter) of a drug in the blood as a function of the amount of drug given, x, and the time since injection, t For 0 <= x <= 5 and t >= 0 hours, we have C = f(x,t) = 26te^-(5-x) f (3,5) = _____

Using the given **function**, we can plug in x=3 and t=5 to find the concentration of the drug in the blood:

C = f(x,t) = 26te^-(5-x)

C = f(3,5) = 26(5)e^-(5-3)

C = f(3,5) = 130e^-2

Using a calculator, we can simplify this to:

C = f(3,5) ≈ 32.22 mg/liter

Therefore, the **concentration **of the drug in the blood 3 hours after injection with a dosage of 5 mg is approximately 32.22 mg/liter.

Hi! To find the concentration C at f(3,5), you'll need to plug in the values for x and t into the given function f(x,t) = 26te^-(5-x).

So, f(3,5) = 26(5)e^-(5-3) = 130e^(-2).

Now, calculate the **exponential value**: e^(-2) ≈ 0.1353.

Finally, multiply this value by 130: 130 * 0.1353 ≈ 17.589.

Thus, f(3,5) = 17.589 mg/liter (rounded to 3 decimal places).

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(4,7);y=3x+6

Write an equation passing through the point and parallel to the given line.

The **Equation **of the line which is parallel to the **line **"y = 3x + 6", and also passes through (4,7) is "y = 3x - 5".

In order to find an equation of a line which passes through **point **(4,7) and is parallel to line "y = 3x + 6", we use the fact that parallel lines have the same slope.

The given line ""y = 3x + 6" has a **slope **of 3,

So, the "**parallel**-line" we want to find must also have a slope of 3.

Now, by using the "**point-slope**" form of the equation of a line, which is : y - y₁ = m(x - x₁),

where m is slope and (x₁, y₁) is a point on the line,

So, we substitute "m = 3" and (x₁, y₁) = (4,7) to get:

⇒ y - 7 = 3(x - 4),

⇒ y - 7 = 3x - 12,

⇒ y = 3x - 5

Therefore, the equation of the required **line **is y = 3x - 5.

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BRAIN-COMPATIBLE

Directions: Arrange the sentences in the box to form a problem. Then solve each problem.

Write your answer in your activity notebook.

1. If she leaves home at 6:00 in the morning

What time will she arrive?

Zaira goes to her grandmother's house

She cycles 30 km at a steady speed of 10 km

Problem

Solution

2. I had an average speed of 55 kph for 2 hours in the afternoon

What was the total distance covered by the bus

A bus had an average speed of 65 kph for 1. 5 hours in the morning.

Problem:

Solution:

3 What was the average speed of the train?

The distance between the two stations is 14 km

A train left Station X at 9:00 a. M. And arrived station Y ay 9:30 a. M.

The correct **arrangement **of problem is explained below and their solution are as follows:

(1) Zaira will arrive at her grandmother's house at 9:00 am.

(2) The total **distance **covered by bus is 207.5 km.

(3) The average-speed of the train was 28 km/h.

Part (1) : The **Problem **is : Zaira goes to her grandmother's house. If she leaves home at 6:00 in the morning, she cycles 30 km at a steady speed of 10 km. What time will she arrive?

Solution:

Zaira cycles at a steady speed of 10 km, she will cover the distance of 30 km in 30/10 = 3 hours.

So, she will arrive at her **grandmother's **house at 6:00 + 3:00 = 9:00 am.

Part (2) : Problem : A bus had an average speed of 65 kph for 1.5 hours in the morning. It had average speed of 55 kph for 2 hours in afternoon. What was total distance covered by bus?

Solution:

The distance covered by the bus in the morning can be calculated as:

Distance = Speed × Time = 65 kph × 1.5 hours = 97.5 km,

The distance covered in the afternoon can be calculated as:

Distance = Speed × Time = 55 kph × 2 hours = 110 km

So, **total-distance** covered by bus is = 97.5 km + 110 km = 207.5 km.

Part (3) : Problem : A train left **Station **X at 9:00 a.m. and arrived station Y at 9:30 a.m. The distance between the two stations is 14 km. What was average speed of train?

Solution:

The time taken by the train to cover the distance of 14 km can be calculated as:

Time = Arrival Time - Departure Time = 9:30 am - 9:00 am = 0.5 hours

The average speed of the train = Distance/Time = 14 km/0.5 hours = 28 km/h;

Therefore, the average **speed **of the train was 28 km/h.

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The given question is incomplete, the complete question is

Directions: Arrange the sentences in the box to form a problem. Then solve each problem.

(1) If she leaves home at 6:00 in the morning

What time will she arrive?

Zaira goes to her grandmother's house

She cycles 30 km at a steady speed of 10 km

(2) I had an average speed of 55 kph for 2 hours in the afternoon

What was the total distance covered by the bus

A bus had an average speed of 65 kph for 1. 5 hours in the morning.

(3) What was the average speed of the train?

The distance between the two stations is 14 km

A train left Station X at 9:00 a.m. and arrived station Y at 9:30 a.m.

a research methods professor creates a computer tutor to help students understand confounding and obscuring variables. before the second exam in the class, volunteers are randomly assigned to either interact with the computer tutor on the materials or to play angry birds on the computer for an equivalent time (30 minutes). although the students in the tutor group do significantly better on the exam the following day, many of the practice questions from the tutor are exactly the same as those on the exam. what is the main threat to concluding that the tutor was effective?

The main threat to concluding that the tutor was effective in helping **students** understand confounding and obscuring **variables** is the issue of 'practice effects'.

Practice effects occur when exposure to specific materials or questions during a study can artificially inflate performance on subsequent measures, such as an exam.

In this case, if the practice **questions** from the tutor were exactly the same as those on the exam.

Then the **students** who interacted with the tutor may have had an advantage on the exam .

Due to familiarity with the questions rather than a true understanding of the material.

The use of the same practice questions in the tutor and on the exam .

It represents a potential confounding variable that could affect the interpretation of the results.

It is possible that the tutor may have been effective.

But it is also possible that the practice effect of the repeated questions contributed to the observed improvement in performance.

Future research could use different practice questions in the tutor and on the exam.

Use a different exam altogether to assess performance.

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A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 19. 1 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 18. 1, 21. 1, 22. 1, 23. 1, 21. 1, 27. 1, and 27. 1 pounds. If α = 0. 200, what is the critical value? The population standard deviation is unknown

Since the population standard deviation is unknown, we use a t-distribution to find the critical value. The degrees of freedom for the t-distribution is n-1, where n is the sample size. In this case, n = 7, so the degrees of freedom is 7-1 = 6. The critical value for a t-distribution with 6 degrees of freedom and a significance level of α = 0.200 (two-tailed) can be found using a t-table or calculator. The critical value is approximately **±1.94**.

69x 10x 6969x 8008x696969696969

I'm still not entirely clear on the question, but assuming you are asking for the product (or multiplication) of these numbers, here's how you can solve it:

69 x 10 x 6969 x 8008 x 696969696969 = 1.841394e+22

In standard notation, this number is 18,413,940,000,000,000,000, which is a very large number.

Note: The "e+22" notation in the answer represents "times 10 to the power of 22," which means we move the decimal point 22 places to the right.

69 x 10 x 6969 x 8008 x 696969696969 = 1.841394e+22

In standard notation, this number is 18,413,940,000,000,000,000, which is a very large number.

Note: The "e+22" notation in the answer represents "times 10 to the power of 22," which means we move the decimal point 22 places to the right.

Graph the equation shown below by transforming the given graph of the parent function. 2^3x

The **graph **of the **exponential function **[tex]y = 2^{3x}[/tex] is given as follows:

An exponential function has the **definition **presented as follows:

[tex]y = ab^x[/tex]

In which the **parameters **are given as follows:

The **function **in this problem is given as follows:

[tex]y = 2^{3x}[/tex]

Hence the **parameter **values are:

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