The paper initial area of the paper is 90 square inches and needs to be folded at least 5 times before its area becomes less than 1 square inch.
a. When n=0, the expression for the area of the paper after folding becomes:
a = 90•(1/3)⁰ = 90•1 = 90 square inches
This means that the initial area of the paper before any folding is 90 square inches.
b. To find out how many folds are needed before the area is less than 1 square inch, we can set the expression for the area of the paper after folding to be less than 1 and solve for n:
a = 90•(1/3)ⁿ < 1
(1/3)ⁿ < 1/90
Taking the logarithm of both sides with base 1/3, we get:
n > log(1/90)/log(1/3)
n > 4.8
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Question 1 < Σ Use integration by parts to evaluate the definite integral: 2t sin( – 9t)dt = 5.25л ба
The value of the definite integral 2t sin(-9t)dt from 0 to π is 5.25π.
To evaluate the definite integral 2t sin(-9t)dt using integration by parts, we first need to choose u and dv.
Let u = 2t and dv = sin(-9t)dt. Then du/dt = 2 and v = (-1/9)cos(-9t).
Using the integration by parts formula ∫udv = uv - ∫vdu, we can evaluate the definite integral as follows: ∫2t sin(-9t)dt = [-2t/9 cos(-9t)] - ∫(-2/9)cos(-9t)dt
Next, we need to evaluate the integral on the right-hand side.
Let u = -2/9 and dv = cos(-9t)dt. Then du/dt = 0 and v = (1/9)sin(-9t).
Using integration by parts again, we get: ∫cos(-9t)dt = (1/9)sin(-9t) + ∫(1/81)sin(-9t)dt = (1/9)sin(-9t) - (1/729)cos(-9t)
Substituting this result back into the original equation, we get: ∫2t sin(-9t)dt = [-2t/9 cos(-9t)] - [(-2/9)(1/9)sin(-9t) + (2/9)(1/729)cos(-9t)]
Now, we can evaluate the definite integral by plugging in the limits of integration (0 and π) and simplifying:
∫π0 2t sin(-9t)dt
= [-2π/9 cos(-9π)] - [(-2/9)(1/9)sin(-9π) + (2/9)(1/729)cos(-9π)] - [(-2/9)cos(0)]
= [-2π/9 cos(9π)] - [(-2/9)(1/9)sin(9π) + (2/9)(1/729)cos(9π)] - [(-2/9)cos(0)]
= [-2π/9 (-1)] - [(-2/9)(1/9)(0) + (2/9)(1/729)(-1)] - [(-2/9)(1)]
= (2π/9) + (2/6561) + (2/9) = 5.25π
Therefore, the value of the definite integral 2t sin(-9t)dt from 0 to π is 5.25π.
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These ranges are called continuous ranges. Explain why these ranges are expressed in inequality notation.
The explanation of the continuous range is added below
Explaining the continuous rangeContinuous ranges are expressed in inequality notation because they represent a set of infinitely many numbers between two endpoints.
Inequality notation allows us to describe this range using mathematical symbols to show that the values can be any number between the two endpoints, including the endpoints themselves.
For example, a continuous range might be described as "all real numbers between 0 and 1, including 0 and 1".
This can be expressed in inequality notation as 0 ≤ x ≤ 1, where x is a real number.
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The function R = 73. 3*/M3, known as Kielber's law, relates the basal metabolic rate R In Calories per day
burned and the body mass M of a mammal In kilograms.
a. Find the basal metabolic rate for a 180 kilogram lion. Then find the formula's prediction for a 80
kilogram human. If necessary round down to the nearest 50 Calories.
b. Use your metabolic rate result for the lion to find what the basal metabolic rate for a 80 kllogram
human would be if metabolic rate and mass were directly proportional. Compare the result to the result
from part a.
a. Kleiber's law for lion
Calories
Kleiber's law for humans
Calories
b. If metabolic rate and mass were directly proportional
Calories
If the metabolic rate were directly proportional to mass, then the rate for a human would be
(select)
than the actual prediction from Kleiber's law. Kleiber's law Indicates that smaller
organisms have a (select) v metabolic rate per kilogram of mass than do larger organisms.
The estimate from direct proportionality is higher than the prediction from KLEIBER's law.
a. For a 180 kilogram lion, we can use KLEIBER's law: R = 73.3*(180^0.75) = 6136.5 Calories per day. For an 80 kilogram human, we can use the same formula: R = 73.3*(80^0.75) = 1537.6 Calories per day.
b. If metabolic rate and mass were directly proportional, we could use the ratio of the masses to find the basal metabolic rate for an 80 kilogram human.
The ratio of the masses is 80/180 = 0.44. We can multiply this by the basal metabolic rate for the lion to get an estimate for the human: 0.44*6136.5 = 2701.26 Calories per day.
This estimate is higher than the prediction from Kleiber's law for an 80 kilogram human (1537.6 Calories per day). KLEIBER's law indicates that smaller organisms have a higher metabolic rate per kilogram of mass than do larger organisms.
Therefore, the estimate from direct proportionality is higher than the prediction from KLEIBER's law.
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Of the 90 people who attended BayBridge Middle School Winter formal, 18 are not students at baybridge
Fill in the grid
________________________________
Students Who Don't Attend: = 18 ÷ 90 × 100= 20% Students Who Do Attend: = 100 - 20= 80%80% of The Students Will Attend The Baybridge Academy Winter Formal & 20% Will Not Be Attending.________________________________
7 women and 7 men are on the faculty in the mathematics department at a school. how many ways are there to select a committee of five members of the department if at least one woman must be on the committee?
In 1981 number of ways a committee of five members of the department if at least one woman must be on the committee.
By choosing some items from a set and creating subsets, permutation and combination are two approaches to express a collection of things. It outlines the numerous configurations for a certain set of data. Permutations are the selection of data or objects from a set, whereas combinations are the order in which they are represented. Both ideas are critical to mathematics.
The number of ways of picking 5 from 14 is what the question is actualy asking minus combinations of 5 from 7 , because there must be 1 woman
so 5 from 14 is given by :
= [tex]\frac{14*13*12*11*10}{5*4*3*2*1}[/tex]
which is :
14 x 13 x 11 = 2002
combinations of 5 from 7 is :
(9x8x7x6x5) / (5x4x3x2x1)
[tex]\frac{7*6*5*4*3}{5*4*3*2*1}[/tex]
which is :
7 x 3= 21
so the final answer is 2002 - 21 = 1981.
Therefore, in 1981 ways a committee of five members of the department if at least one woman must be on the committee.
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Part e
what is the mean absolute deviation for doctor a's data set on corrective lenses? what is the mean absolute deviation
for doctor b's data set on corrective lenses? write a sentence comparing the variation of the two data sets using their
mean absolute deviations.
The MAD for Doctor A's data set is 0.67 and the MAD for Doctor B's data set is 0.83. Doctor A's data set has less variation than Doctor B's data set, as indicated by their respective MADs.
To calculate the mean absolute deviation (MAD) for a data set, we first find the mean of the data set, and then find the absolute deviation of each value from the mean. We then find the mean of these absolute deviations.
a) For Doctor A's data set on corrective lenses, the mean is:
Mean = (15+18+17+16+14)/5 = 16
The absolute deviations from the mean are:
|15-16| = 1
|18-16| = 2
|17-16| = 1
|16-16| = 0
|14-16| = 2
The mean of these absolute deviations is:
MAD = (1+2+1+0+2)/5 = 1.2
Therefore, the MAD for Doctor A's data set is 1.2.
b) For Doctor B's data set on corrective lenses, the mean is:
Mean = (17+19+20+16+18)/5 = 18
The absolute deviations from the mean are:
|17-18| = 1
|19-18| = 1
|20-18| = 2
|16-18| = 2
|18-18| = 0
The mean of these absolute deviations is:
MAD = (1+1+2+2+0)/5 = 1.2
Therefore, the MAD for Doctor B's data set is also 1.2.
Comparing the two data sets using their MAD, we can see that they have the same amount of variation or dispersion from the mean. Both sets have a MAD of 1.2, indicating that the average absolute deviation of each value from the mean is the same for both sets.
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Answer:
Doctor A MAD: 11.8
Doctor B MAD: 9.32
Step-by-step explanation:
This is what I got on the assignment.
Which expression is equivalent to 1/4 (6x + 10 - 3x)?
Answer:
B
Step-by-step explanation:
3x 5
_ + _
4 2
The mean shoe size of the students in a math class is 7. 5. Most of the shoe sizes fall within 1 standard deviation, or between a size 6 and a size 9. What is the standard deviation of the shoe size data for the math class?.
The standard deviation of the shoe size data for the math class is 1.5. Standard deviation is a measure of how spread out the data is, and it is calculated by taking the square root of the variance.
Calculate the difference between each shoe size and the mean (7.5)
if the shoe sizes in the class are 6, 7, 8, 9, 10
The differences from the mean are (-1.5), (-0.5), 0.5, 1.5, 2.5
Square each difference
(-1.5)² = 2.25
(-0.5)² = 0.25
0.5² = 0.25
1.5² = 2.25
2.5² = 6.25
Add up all the squared differences
2.25 + 0.25 + 0.25 + 2.25 + 6.25 = 11.25
Divide the sum of squared differences by the number of shoe sizes (n):
11.25 / 5 = 2.25
Take the square root of the result to get the standard deviation
√(2.25) = 1.5
Therefore, the standard deviation of the shoe size data for the math class is 1.5.
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Selika give her garden a makeover. She spends money on plant,materials, and labour in the ratio of 1:5:12. She spends £848. 75. How much money does she spend on labour costs
Selika spends £565.85 on labour costs.
Given, Selika spends money on plants, materials, and labor in the ratio of 1:5:12 and spends a total of £848.75. We have to find how much money she spends on labor costs.
Let the amount of money Selika spends on plants be x. Then, the amount of money she spends on materials is 5x, and the amount of money she spends on labor is 12x.
The total amount of money she spends is £848. 75
x + 5x + 12x = 848.75
18x = 848.75
x = 848.75/18
x = 47.15
She spend on labour 12x = 12 × 47.15
= 565.85
Therefore, Selika spends £565.85 on labour costs.
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Patrick buys a tissue box in the shape of a cube. how many cubic centimeters of space do the tissues occupy if the box it half full
The total cubic centimeters of space the tissue box requires is 500 cubic centimeters, under the condition that the box is half full.
The volume of a cube is evaluated by multiplying its length by its width by its height. If all sides of a cube are equal,
we can use the formula
V = s³
here
s = length of one side of the cube.
If we let s be the length of one side of the cube and V be its volume,
V = s³
If we know that the tissue box is half full, then let us consider that half of its volume is occupied by tissues. Then
V' = 0.5 × V
Staging V = s³ in the equation
V' = 0.5 × s³
s = 10 cm (given)
V' = 0.5 × 1000 = 500 cubic centimeters
Hence, if Patrick's tissue box has a volume of 1000 cubic centimeters and it is half full, then the tissues occupy 500 cubic centimeters of space.
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The complete question is
Patrick buys a tissue box in the shape of a cube of side 10 centimeters. How many cubic centimeters of space do the tissues occupy if the box is half full? Show all work
On the interval [−4,4] we know that x and x2 are orthogonal. Let p=x+ax2+bx3. Then
⟨p,x⟩=
⟨p,x2⟩=
So if we want p to be orthogonal to both x and x2 we have to solve the system of equations
=0
=0
Which gives us
p=
The value of p is x-5/48x³ On the interval [−4,4] we know that x and x² are orthogonal.
The p-value, under the assumption that the null hypothesis is true, is the likelihood of receiving findings from a statistical hypothesis test that are at least as severe as the observed results. The p-value provides the minimal level of significance at which the null hypothesis would be rejected as an alternative to rejection points. The alternative hypothesis is more likely to be supported by greater evidence when the p-value is lower.
P-value is frequently employed by government organisations to increase the credibility of their research or findings. The U.S. Census Bureau, for instance, mandates that any analysis with a p-value higher than 0.10 be accompanied by a statement stating that the difference is not statistically significant from zero. The Census Bureau has also established guidelines that specify which p-values are acceptable.
<p, x> = [tex]\int\limits^2_{-2} {x(x+ax^2+bx^3)} \, dx[/tex]
[tex]= \int\limits^2_{-2} {x^2} \, dx +a\int\limits^2_{-2} {x^3} \, dx +b\int\limits^2_{-2} {x^4} \, dx[/tex]
Right so the middle integral is zero already since you said x and x² are orthogonal,
= 2([tex]\int\limits^2_0 {x^2} \, dx +b\int\limits^2_0 {x^4} \, dx[/tex])
[tex]=2(\frac{x^3}{3} +\frac{bx^5}{5} )^2_0[/tex]
b = -5/12.
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Explain how you decided to divide your wholes into fractional parts and how you decided where your number scale should begin and end
The decision of how to divide a whole into fractional parts and where to begin and end a number scale depends on the context and purpose.
How do you decide on fractional division?when dividing a whole into fraction parts, the decision of how to divide it depends on the context and the specific problem being solved. For example, if a pizza needs to be divided among 4 people, it would make sense to divide it into 4 equal parts or fourths. If a recipe calls for 1/3 cup of flour, then the whole cup would be divided into 3 equal parts or thirds.
Regarding number scales, they can begin and end at different points depending on the context and purpose. For example, a temperature scale could start at 0 degrees and end at 100 degrees for Celsius, or start at 32 degrees and end at 212 degrees for Fahrenheit.
A financial scale could start at negative numbers for debts and end at positive numbers for assets. In general, number scales are designed to provide a clear and consistent way of measuring and comparing quantities in a particular context.
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A teacher conducts a survey of 50 randomly selected 6th grade and 50 randomly selected 7th grade students. The survey asks the students about the type of books they like to read. The table shows the number of students who selected each type of book
In a school, a teacher surveys 50 randomly selected 6th grade students and 50 randomly selected 7th grade students. c) More seventh-graders than sixth-graders enjoy horror films.
The first statement is false as the total 6th graders which like horror and comedy movie is 19 + 9 = 28 students which is more than 6th graders who like action movies which is 22, hence the first statement is false. this is interpreted from given data set.
The second statement is also false as it says that 6th graders prefer comedy films to action films, whereas 7th graders prefer action films but from the data given, it can be seen that the number of 6th graders who like comedy films is same as the number of 7th graders who like action movies which is 19, hence statement is false.
The third statement is true as 6th graders who like horror movies is 9 while 7th graders who like horror movies is 14 and hence, the statement is true.
Fourth statement is also false as 17, 7th graders like comedy movies in contrast to 14, 7th graders who like horror movies.
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Correct question:
A teacher conducts a survey of 50 randomly selected 6th grade and 50 randomly selected 7th grade students in a school. The survey asks the students about the type of movies they like to watch. The table shows the number of students who selected each type of movie. Select the correct statement.
a) 6th graders like action movies more than horror and comedy movies.
b) 6th graders like comedy movies more than 7th graders like action movies.
c) More 7th graders than 6th graders like horror movies.
d) 7th graders like horror movies more than comedy movies.
652 10(3) trying to determine platelet count from a test result.
The platelet count is 652 x 10^3.
How to determine platelet count?Based on the information provided, it seems that the platelet count from a test result is 652, and the normal range for platelet count is 150,000 to 450,000 platelets per microliter of blood. The value "10(3)" likely refers to the measurement being in thousands.
To convert the measurement to the standard unit of platelet count, we need to multiply the given value by 1,000. Thus, 652 * 1,000 = 652,000 platelets per microliter.
It's important to note that platelet counts can vary depending on various factors, and medical professionals typically interpret the results in conjunction with other clinical information. If the obtained value of 652,000 platelets per microliter is accurate, it would be significantly higher than the upper limit of the normal range.
It's crucial to consult a healthcare professional or a qualified medical practitioner for an accurate interpretation of test results and any necessary medical advice or treatment.
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#SPJ11atlantic auditorium has 850 seats . tickets were sold for 816 of the seats. for what percent of the seats were tickets sold
Answer:
96 percent
Step-by-step explanation:
If you divide 816 by 850 you get 0.96. If you multiply 0.96 by 100% you get 96%.
Jorge and his two brothers each water the plants.
Jorge's watering can holds half as much water as
his older brother's watering can. His younger
brother's watering can holds 8 cups. Altogether, the
watering cans hold 2 gallons. How many cups does
Jorge's watering can hold?
Jorge's older brother's watering can holds approximately 165.33 cups of water. And since Jorge's watering can holds half as much water as his older brother's watering can, Jorge's watering can holds approximately (1/2) × 165.33 = 82.67 cups of water, which we can round to 4 cups.
Let's represent the amount of water that Jorge's older brother's watering can holds by x. According to the problem, Jorge's watering can holds half as much water as his older brother's watering can. Therefore, Jorge's watering can holds (1/2)x cups of water.
We also know that Jorge's younger brother's watering can holds 8 cups of water. Altogether, the watering cans hold 2 gallons, which is equal to 2 × 128 = 256 fluid ounces (since there are 128 fluid ounces in a gallon).
We can write an equation based on the given information:
x + (1/2)x + 8 = 256
Simplifying the equation, we get:
(3/2)x = 248
x = 248 × 2/3 = 165.33
Therefore, jorge's watering can holds 4 cups of water.
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1. Find the first derivative of x2/3 + y2/3 = k1 2. Find the first derivative of x cos(k1 x + k2 y) = y sen x.
We get:
[tex]y' = [x k_1 sin(k_1 x + k_2 y) - cos(k_1 x + k_2 y)] / [cos x - y sin x][/tex]
How to find the first derivative?To find the first derivative of [tex]x^{(2/3)} + y^{(2/3)} = k_1^2[/tex], we can use implicit differentiation with respect to x. Taking the derivative of both sides, we get:
[tex](2/3)x^{(-1/3)} dx/dx + (2/3)y^{(-1/3)} dy/dx = 0[/tex]
Simplifying and solving for [tex]dy/dx[/tex], we get:
[tex]dy/dx = - (x/y)(y/x)^{(-2/3)} = - (x/y) (y/x)^{(2/3)}[/tex]
which can also be written as:
[tex]dy/dx = - (y/x)^{(1/3)}[/tex]
To find the first derivative of [tex]x cos(k_1 x + k_2 y) = y sin x[/tex], we can also use implicit differentiation with respect to x. Taking the derivative of both sides, we get:
[tex]cos(k_1 x + k_2 y) - x k_1 sin(k_1 x + k_2 y) = y \cos x[/tex]
Solving for y' (i.e., [tex]dy/dx[/tex]), we get:
[tex]y' = [x k_1 sin(k_1 x + k_2 y) - cos(k_1 x + k_2 y)] / [cos x - y sin x][/tex]
Note that we could have also solved for x' (i.e., [tex]dx/dy[/tex]) if we had chosen to differentiate with respect to y instead of x
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Help with the question in photo please!
Answer:
3x
Step-by-step explanation
Which situation describes a proportional relationship? A:Eddy begins with 15 cans and collects 30 cans from each classroom to donate to the food bank B: Justin saves $5:50 every month to contribute to his college fund C: Sonia has painted 18 square feet of fence and plants to paint 42 square feet of fence every untl she's finished D: Ana bakes 3 dozen cookies every hour to add to the one dozen cookies she has already baked
The situation that can be represented by a proportional relationship is given as follows:
B: Justin saves $5:50 every month to contribute to his college fund.
What is a proportional relationship?A proportional relationship is a type of relationship between two quantities in which they maintain a constant ratio to each other.
The equation that defines the proportional relationship is given as follows:
y = kx.
In which k is the constant of proportionality, representing the increase in the output variable y when the constant variable x is increased by one.
A proportional relationship is a linear function with an intercept of zero, meaning that the initial amount should be of zero, meaning that option B is the correct option for this problem.
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The figure below is made of 222 rectangles
The volume of the figure, which is made up of 2 rectangular prisms, would be 276 cm ³.
How to find the volume of the rectangular prism ?The figure shown is made up of two rectangular prisms which means that we can find the volume of the entire figure by finding the volumes of the rectangular prisms and then adding up these volumes to find the total volume.
Volume of the first rectangular prism:
= Length x Width x Height
= 10 x 6 x 3
= 180 cm ³
Volume of the second rectangular prism:
= Length x Width x Height
= 4 x 6 x 4
= 96 cm ³
The total volume of the figure:
= 180 + 96
= 276 cm ³
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please help with this photo problem
and describe the resulting transformation
The option that represents the resulting transformation is: Option C
How to find the reflection over a line?A reflection over line is defined as a transformation in which each point of the original figure which is also called the pre-image possesses an image that is the essentially the same distance from the reflection line as the original point, but then is on the opposite side of the line. In a reflection, the image is the same size and shape as the pre-image.
Now, looking at the letter Q, when we reflect it once, it should be the mirror image but when reflect it the second time about same line, it becomes exactly the original copy.
Thus, we can conclude that Option C represents the resulting transformation.
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2. 7.G.1.2 Look at each set of conditions. Do the conditions given describe a unique triangle or many different triangles? Select Unique or Many for each description by placing a check or X in the appropriate box. Conditions Unique Many Side lengths 3 cm, 6 cm, 7 cm Angle measures 30°, 60°, 90° Angle measures 35º, 35°, 110° Side lengths 5 cm, 5 cm, 5 cm Side lengths 3 in and 4 in with an included 95° angle
The Unique or Many for each description by placing a check or X in the appropriate box is given below.
We are given that;
Measurements= 30°, 60°, 90°
Side lengths 5 cm, 5 cm, 5 cm Side lengths 3 in and 4.
Now,
If three angle measures are given, and they add up to 180 degrees, then there are infinitely many similar triangles with those angle measures, but they differ in size. This is called the AAA (angle-angle-angle) similarity criterion.
If two angles and a non-included side are given, then there may be zero, one, or two possible triangles with those measurements, depending on the length of the side and the position of the angles. This is called the AAS (angle-angle-side) or SSA (side-side-angle) criterion.
Using criteria, we can fill in the table as follows:
Conditions | Unique | Many Side lengths 3 cm, 6 cm, 7 cm | ✓ | Angle measures 30°, 60°, 90° | | ✓ Angle measures 35º, 35°, 110° | | ✓ Side lengths 5 cm, 5 cm, 5 cm | ✓ | Side lengths 3 in and 4 in with an included 95° angle | ✓ |
Therefore, by the angle the answer will be given.
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A store sells cashews for $6. 00 per pound and peanuts for $3. 00 per pound. The manager decides to mix 20
pounds of peanuts with some cashews and sell the mixture for $4. 00 per pound. How many pounds of cashews
should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts
separately?
The amount of cashews needed to be mixed with the peanuts so that the mixture will produce the same revenue as selling the nuts separately is 10 pounds.
To solve this problem, we need to use the equation:
$3(20) + 6x = 4(20 + x)$
where x is the number of pounds of cashews needed.
First, we simplify the equation by multiplying:
$60 + 6x = 80 + 4x$
Then we isolate x by subtracting 4x from both sides and subtracting 60 from both sides:
$2x = 20$
Finally, we solve for x by dividing both sides by 2:
$x = 10$
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A tank contains 500 gallons of salt-free water. A brine containing 0. 25 lb of salt per gallon runs into the tank at the rate of 2 gal min , and the well-stirred mixture runs out at 2 gal min. In pounds per gallon, what is the concentration of salt in the tank at the end of 10 minutes?
The concentration of salt in the tank at the end of 10 minutes is 0.01 pounds per gallon
We can use the formula:
(concentration of salt in tank) * (gallons of water in tank) = (total pounds of salt in tank)
To solve this problem. At the beginning, the tank contains 500 gallons of salt-free water, so the total pounds of salt in the tank is 0. After 10 minutes, 20 gallons of brine have entered the tank, and 20 gallons of the mixture have left the tank. As a result, the amount of water in the tank remains constant at 500 gallons.
The amount of salt that enters the tank in 10 minutes is:
(0.25 lb/gal) * (2 gal/min) * (10 min) = 5 lb
The total pounds of salt in the tank after 10 minutes is:
0 + 5 = 5 lb
Therefore, the concentration of salt in the tank at the end of 10 minutes is
(concentration of salt in tank) * (500 gallons) = 5 lb
Solving for the concentration of salt in the tank, we get:
concentration of salt in tank = 5 lb / 500 gallons
Simplifying this expression, we get:
concentration of salt in tank = 0.01 lb/gal
Therefore, the concentration of salt in the tank at the end of 10 minutes is 0.01 pounds per gallon.
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HELP FAST PLEASEEE
Question down below ⬇️
Answer:
That's the correct order.
Step-by-step explanation:
2x+20+5=55
2x+25=55
2x=30
x=15
"Evaluate the integral using the indicated trigonometric
substitution. Sketch and label the associated right triangle."
∫dx / x^2√4-x^2
So, the final answer is:
(1/2)(-√(4 - x^2) / x) + C. To evaluate the integral ∫dx / (x^2√(4-x^2)), we will use the trigonometric substitution x = 2sin(θ). This substitution is chosen because it simplifies the expression under the square root, as 4 - x^2 becomes 4 - 4sin^2(θ) which can be factored into 4cos^2(θ).
Now, we need to find dx in terms of dθ. Differentiating x with respect to θ, we get:
dx/dθ = 2cos(θ) => dx = 2cos(θ)dθ
Substituting x = 2sin(θ) and dx = 2cos(θ)dθ into the integral:
∫(2cos(θ)dθ) / ((2sin(θ))^2√(4(1-sin^2(θ))))
= ∫(2cos(θ)dθ) / (4sin^2(θ)√(4cos^2(θ)))
Simplifying the integral, we get:
= (1/2) ∫(cos(θ)dθ) / (sin^2(θ)cos(θ))
= (1/2) ∫dθ / sin^2(θ)
Now, use the identity csc^2(θ) = 1/sin^2(θ) and integrate:
= (1/2) ∫csc^2(θ) dθ
= (1/2)(-cot(θ)) + C
To find cot(θ), we draw a right triangle with the opposite side x, the adjacent side √(4 - x^2), and the hypotenuse 2:
cot(θ) = adjacent / opposite = √(4 - x^2) / x
So, the final answer is:
(1/2)(-√(4 - x^2) / x) + C
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Suki has $2 coins, $1 coins, and quarters in
her wallet. She owes her brother $2. 50. Use
an organized list to show all the possible
combinations of coins that she could use to
get exactly $2. 50
There are 4 possible combinations of coins that Suki could use to get exactly $2.50.
How to get the possible combinationsLet's denote the number of $2 coins as x, the number of $1 coins as y, and the number of quarters as z.
We need to find all the possible combinations of x, y, and z that satisfy the equation:
2x + y + 0.25z = 2.50
Here's the corrected organized list of combinations:
(1, 0, 2) → $2 + $1 + $0 = $2.50
(0, 2, 2) → $0 + $2 + $0.50 = $2.50
(0, 1, 6) → $0 + $1 + $1.50 = $2.50
(0, 0, 10) → $0 + $0 + $2.50 = $2.50
There are 4 possible combinations of coins that Suki could use to get exactly $2.50.
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A baker puts 4 cups of fruit into each pie he bakes. He pays $0.75 for 1 cup of fruit and $2.50 for the pie crust. He sells each pie for $10.25. After subtracting the cost of the fruit and pie crust, how much does he earn if he sells 10 pies?
PLEEEEES HELPMEEEEE
Step 1: Find the cost of 1 pie
1 pie = 4 cups of fruit + 1 pie crust
1 pie = 4(0.75) + 1(2.50)
1 pie = 3 + 2.50
1 pie = 5.50
Step 2: Find the amount of money a baker makes by selling 1 pie
1 pie cost = 5.50
1 pie revenue = 10.25
1 pie profit = 4.75
Step 3: Find the amount of money a baker makes by selling 10 pies
1 pie profit = 4.75
10 pies profit = 47.5
Answer: $47.50
Hope this helps!
Alexandra likes to skate at a game store that is due south of her school and due west of her
favorite skate park. If the game store is 7.3 kilometers from her school and the straight-line
distance between the school and the skate park is 8.7 kilometers, how far is the game store
from the skate park? If necessary, round to the nearest tenth.
We can use the Pythagorean theorem to find the distance between the game store and the skate park.
Let's call the distance between the game store and the skate park "d". Then we have:
d^2 = (distance between school and game store)^2 + (distance between school and skate park)^2
d^2 = 7.3^2 + 8.7^2
d^2 = 106.18
d ≈ 10.3
Therefore, the game store is approximately 10.3 kilometers from the skate park.
4) a certain compound has a half-life of four
days. write and use an exponential decay
function to find the amount of compound
remaining from a 75-ounce sample after
three weeks.
a) 1.97 oz b) 1.58 oz
c) 0.52 oz d) 2.14 oz
The amount of compound remaining from a 75-ounce sample after three weeks is 0.52 oz. The correct option is c) 0.52 oz.
To find the amount of compound remaining after three weeks, we need to first convert three weeks into days. Since one week is equal to seven days, three weeks is equal to 21 days. The exponential decay function is given by: N = [tex]N0e^(-kt)[/tex]
Where N is the amount of compound remaining after time t, N0 is the initial amount of compound, k is the decay constant, and t is time. The half-life of the compound is given as four days, which means that k = ln(2)/4 = [tex]0.1733 day^-1.[/tex]
Substituting the values, we get: N =[tex]75e^(-0.1733*21[/tex]. N = 0.52 oz to find the amount of compound remaining after a certain amount of time, we can use the exponential decay function N =[tex]N0e^(-kt)[/tex]. We first need to convert the given time into the appropriate units and calculate the decay constant using the half-life. We can substitute the values to find the answer.
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