2. Which best describes magma?
A. Magma can form volcanoes
B. When lava is on Earth’s surface, it is called magma
C. Magma is a molten rock under Earth’s surface
D. Magma is a rock that forms mountains

Answers

Answer 1

Answer:

D tmtnttntntntmtndnndmtrjrrjrj

Answer 2
C is the correct answer!!!!!

Related Questions

If the light that has been reflected from the wall into the water is observed to be completely polarized, what angle does this beam make with the normal inside the water

Answers

The angle of incidence for a complete polarization of incident ray on water is 53.1⁰.

The given parameters;

refractive index of water, μ = 1.333

The angle of incidence for a complete polarization of incident ray on water is calculated by applying Brewster's law as shown below;

[tex]\mu = tan \ \theta[/tex]

where;

θ is the polarizing angle

The polarizing angle is calculated as;

[tex]\theta = tan^{-1}(1.333)\\\\\theta = 53.1^ 0[/tex]

Thus, the angle of incidence for a complete polarization of incident ray on water is 53.1⁰.

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How far from the front of the car will the CM be when two people sit in the front seat 2.80 m from the front of the car, and three people sit in the back seat 3.90 m from the front

Answers

The center mass of the car from the front for the given passengers is 3.46 m.

The given parameters;

distance of 2 people from the front of the car, d₁ = 2.8 mdistance of 3  people from the front of the car, d₂ =3.9 m

Assuming the mass of the passengers is the same, let their mass = m

Keeping the front seat as the reference point, the center mass is calculated as;

[tex]X_{cm} = \frac{ \ 2M(2.8m) \ + \ 3M(3.9m) }{2M + 3M} \\\\X_{cm} = \frac{17.3 Mm}{5M} \\\\X_{cm} = 3.46\ m[/tex]

Thus, the center mass of the car from the front for the given passengers is 3.46 m.

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Could you help me with this question please

Answers

Charge =

(current in Amperes) x (time in seconds)

1 Ampere means 1 Coulomb per second

240 Coulombs

90 Coulombs

150 Coulombs

Mrs. Jones invited her husband, Lester, on her weekly slide down the waxed hallway. Mr. Jones weighs 850. N and the coefficient of friction between his socks and the floor is 0.120. What is the magnitude of the force of friction the opposes his motion?

Answers

Explanation:

We know that [tex]f = \mu N,[/tex] where N is the normal force and [tex]\mu[/tex] is the coefficient of friction. In this case, Mr. Jones's weight is the normal force therefore, the frictional force on Mr. Jones is

[tex]f = (0.120)(850\:\text{N}) = 102\:\text{N}[/tex]

An object with a mass of 2 kg is moving with a velocity of 3 m/s when a 5 N net force
acts upon it. What will the object's velocity be if the force acts for 7 S?

Answers

By Newton's second law, the net force exerted on the object makes it undergo an acceleration a such that

(2 kg) a = 5 N

so that it is accelerated a = 2.5 m/s^2.

Since the object starts with velocity 3 m/s, after 7 s its acceleration will make it speed up to

3 m/s + (2.5 m/s^2) (7 s) = 20.5 m/s

50 POINTS HELP ME
How are the circulatory, respiratory, skeletal, muscular, and nervous systems put into use when a rabbit runs from danger?
Carbon dioxide is considered a waste product in animals. How do plants use carbon dioxide?
How do living things reproduce?
Why is it a good idea for carriers of disease genes to get tested before having children?
How do organisms interact?
What would happen if an organism at the bottom of a food chain died?
How are ecosystems different?
Why does burning fossil fuels create carbon dioxide?
How does Earth’s surface change?
How can people prevent damage from earthquakes?
What are Earth’s resources?
Why do you think most households and businesses get water from water companies?

Answers

Explanation:

Q1. Circulatory/respiratory systems: get blood with oxygen and food to leg muscles

Skeletal/muscular systems: make legs move

Nervous system: sense danger, coordinate leg movements

Hormones to change body activity's are sent out by the ___________

Endocrinesystem

Q2. Excess carbon dioxide and oxygen are excreted from the plant through the stomata in the leaves.

Q3. Reproduction is the process by which new living things are created. People, animals, plants, and even bacteria, reproduce. There are two methods by which living things reproduce--asexual or sexual. Asexual reproduction allows for a living thing to reproduce without another member of its species, while sexual reproduction requires genetic material from two different members of the species, usually but not always, a male and a female. There are a few rare species that have the ability to reproduce both sexually and asexually.

Sexual Reproduction

In sexual reproduction, species can be either anisogamous or isogamous. In anisogamous reproduction, there are two parents, generally male and female. In order to reproduce, both contribute a gamete, or reproductive cell containing a haploid, or single set of chromosomes, that will make up the offspring. Each gamete provides half of the offspring’s genetic material. Many animals, including humans, reproduce in this way. Males produce sperm, which fertilize a female’s ova, or egg, within her body during the process of sexual intercourse. The point at which the egg is fertilized is called conception. The union of the two gametes results in a new cell, called a zygote. This cell continuously divides, implanting itself into the female uterus, and developing into what becomes known first as an embryo, and later, as a fetus. It is nourished and grows in the uterus throughout what is referred to as a period of gestation. This length of time varies for different animals. When development is complete, the birth process allows the female parent to deliver the baby that has grown within her, so that it can begin to thrive and grow on its own. Humans can also fertilize eggs externally, through a process called in vitro fertilization. Some animals, particularly those that live in the water, fertilize eggs externally, by releasing sperm and egg into the water, where they join together and become fertilized. Birds and reptiles have their eggs fertilized internally, and then lay eggs, in which the new creature develops, and then is hatched. Flowering plants even reproduce sexually, through a process called pollination. However, depending on the plant, it may self-pollinate, or cross-pollinate.

Asexual Reproduction

In asexual reproduction, a living thing can reproduce without receiving any cells from another living thing. All chromosomes come from one parent causing the offspring to be similar or identical in genetic structure. Organisms that produce asexually include but are not limited to bacteria, molds, yeast and some plants. Methods of asexual reproduction include budding, in which a new organism is formed directly from a part of an organism, such as with plants. Fragmentation means a living thing is split into fragments, which grow to be clones of the original living thing. Molds and starfish are examples of organisms that reproduce through fragmentation. Binary fission occurs when a cell divides into two parts. These organisms may not be genetically identical. Bacteria reproduce in this way. Spore formation is another form of asexual reproduction. According tothe New World Encyclopedia, a spore is a reproductive structure that is adapted for dispersion and survival for extended periods of time in unfavorable conditions. Once conditions are favorable, the spore can develop into a new haploid organism using mitotic division

Q4. We cannot prevent natural earthquakes from occurring but we can significantly mitigate their effects by identifying hazards, building safer structures, and providing education on earthquake safety. By preparing for natural earthquakes we can also reduce the risk from human induced earthquakes.

hope it is helpful

Answer:

.

I did not mean to do this!

can I delete it?

Explanation:

A train leaving the station accelerates from a full stop at a rate of 0.250 meters per second squared for 45.0 seconds. How far does the train travel during this time?​

Answers

Answer:

[tex]\boxed {\boxed {\sf 253 \ meters}}[/tex]

Explanation:

We are asked to find the distance a train travels.

We are given the acceleration, initial velocity, and time. Therefore, we will use the following kinematic equation:

[tex]d=v_it+\frac{1}{2}at^2[/tex]

The train starts at a full stop or a velocity of 0 meters per second. It accelerates at a rate of 0.250 meters per second squared for 45.0 seconds.

[tex]v_i[/tex]= 0 m/s a= 0.250 m/s²t=45.0 s

Substitute the values into the formula.

[tex]d= (0 \ m/s)(45.0 \ s) + \frac{1}{2} (0.250 \ m/s^2)(45.0 \ s)^2[/tex]

Multiply the first two numbers. The units of seconds cancel.

[tex]d= 0 \ m + \frac{1}{2} (0.250 \ m/s^2)(45.0 \ s)^2[/tex]

Solve the exponent.

(45.0 s)² = 45.0 s *45.0 s = 2025 s²

[tex]d= 0 \ m +\frac{1}{2} (0.250 \ m/s^2)(2025 \ s^2)[/tex]

Multiply the numbers in parentheses. The units of seconds squared cancel.

[tex]d= 0 \ m +\frac{1}{2} (0.250 \ m/s^2 * 2025 \ s^2)[/tex]

[tex]d= 0 \ m +\frac{1}{2} (0.250 \ m * 2025 )[/tex]

[tex]d= 0 \ m + \frac{1}{2} (506.25 \ m)[/tex]

Multiply by 1/2 or divide by 2.

[tex]d=0 \ m + 253.125 \ m \\d= 253.125 \ m[/tex]

The original measurements of acceleration and time both have 3 significant figures, so our answer must have the same. For the number we found, that is the ones place. The 1 in the tenths place tells us to leave the 3.

[tex]d \approx 253 \ m[/tex]

The train travel approximately 253 meters.

A plane accelerates to a velocity of 240 m/s in 11 s by which time it had traveled 1,400 m down the runway what were it average and initial velocities

Answers

The average velocity is 127.27 m/s while the initial velocity is 14.55 m/s

According to Newton's law of motion:

s = [(v + u)/2]t

Where s is the distance moved = 1400 m, v is the final velocity = 240 m/s, u is the initial velocity, t is the time taken = 11 s, hence:

1400 = [(240 + u)/2)11

2800 = (240 + u)11

u + 240 = 254.55

u = 14.55 m/s

The average velocity = (v + u)/2 = (240 + 14.55)/2 = 127.27 m/s

Therefore the average velocity is 127.27 m/s while the initial velocity is 14.55 m/s

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A solid conductor with radius a is supported by insulating disks on the axis of a conducting tube with inner radius b and outer radius c . The central conductor and tube carry equal currents I in opposite directions. The currents are distributed uniformly over the cross sections of each conductor.

a. Derive an expression for the magnitude of the magnetic field at points outside the central, solid conductor but inside the tube
b. Derive an expression for the magnitude of the magnetic field at points outside the tube (r > c).

Answers

The answers to both are attached. Also hello to person in same class & same hw, physics 2 been a bummer but not too bad--just annoying in general.

Ampere's law allows us to find the results for the magnetic field at two distances from a system made up of two conductors:

     a) Magnetic field inside the system is:  [tex]b= \frac{\mu_o }{2\pi } \ \frac{I}{r}[/tex]  

     b) Magnetic field for the outside of the system is; b = 0

Ampere's Law.

Ampere's law states that the dot product of the magnetic field times a closed path is proportional to the current within the path.

          ∫ B. ds = μ₀ I

Where bold indicates vectors, B is the magnetic field, S the closed path, muo the vacuum permittivity and I the current

a) Ask the magnetic field inside the two conductors.

Let's fix a circular path within the system, see attached, in this case the current that stops inside the path is I.

The circle length is

        s = 2π r

        B 2π r = μ₀ I

        [tex]B = \frac{\mu_o}{2\pi } \ \frac{I}{r}[/tex]  

b) Ask the magnetic field on the outside of the two wires.

Let's use a circular path in the outer part of the system, see attached, in this case with indicate that the current is the two cables is of equal magnitude and in the opposite direction the net current is zero, consequently by Ampere's law

             B=0

In conclusion using Ampere's law we can find the magnetic field for the distances of a system formed by two conductors are:

     a) Magnetic field inside the systemis:    [tex]B = \frac{\mu_o}{2\pi } \ \frac{I}{r}[/tex]  

      b) Magnetic field outside of the system is; B = 0

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A ball is held at rest at the top of a hill. The ball is then released and starts rolling down the hill. At the bottom, it reaches level ground and keeps rolling along the ground. Consider the level ground at the bottom of the hill as zero height.

Select the type or types of energy the ball has at the top of the hill.
kinetic energy

gravitational potential energy

spring potential energy

rotational kinetic energy

electrostatic potential energy
Select the type or types of energy the ball has halfway down the hill.
kinetic energy

gravitational potential energy

spring potential energy

rotational kinetic energy

electrostatic potential energy
Select the type or types of energy the ball has on the level ground.
kinetic energy

gravitational potential energy

spring potential energy

rotational kinetic energy

electrostatic potential energy

Answers

The energies that the ball possess when it is in rest at the top of the hill is electrostatic  potential energy. When the ball at the level ground, it has gravitational potential energy and when it at the half way down hill , it possess rotational kinetic energy.

What is potential energy?

Potential energy of a body is generated by virtue of its position. When the object is placed at rest on the surface the gravitational field, the stored energy is called gravitational potential energy.

When the object starts to move it gains kinetic energy.  When the ball is at rest on the top of the hill it has the electrostatic potential energy. When starts to roll to the ground , then its potential energy converts to rotational kinetic energy.

When, the ball reaches the ground its kinetic energy again transforms to potential energy where the ball is falling down to the gravitational field and thus it possess gravitational potential energy.

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An oil droplet is levitated and held at rest in a region where the electric field is 1.4x104 N/C directed vertically downwards. If the droplet has 3 excess electrons attached, what is its mass

Answers

W = m g     weight of drop

W = q E

m = q E / g = = 3 e E / g

m = 3 * 1.6E-19 * 1.4E4 / 9.8 = 6.96E-16 kg

A 10 kg puck initially moving at 20 m/s has a perfectly inelastic collision with a 20 kg puck. a. Will the resulting velocity be greater than, less than, or equal to 10m/s

Answers

Answer:

Equal to

Explanation:

with a totally inelastic collision masses combine and velocity is the same.

p initial =p final

p=mv

10kg(20m/s)=20kg(v)

200kg m/s=20kg(v)

v=10m/s

The resulting velocity obtained is less than 10m/s.

We have the following information;

Mass of the first puck = 10 kg

velocity of the first puck = 20 m/s

Mass of the second puck = 20 kg

common velocity = ?

From the law of conservation of linear momentum;

[(10 kg  × 20 m/s) + (20 kg × 0 m/s)] = (10 kg + 20 kg) v

200 + 0 = 30v

v = 200/30

v = 6.67 m/s

Hence, the resulting velocity obtained is less than 10m/s.

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What determines the velocity of an object?
A. Its acceleration at a given point in time
B. Its displacement in a given period of time
C. Its weight in a given location
O D. Its mass at its final position
SUBMI

Answers

I think it’s A not 100% sure

The volume of a liquid is 36 mL and the mass is 4g. What is the density?

Answers

4/36=0.11111111111 g/cm^3 or 3.3019272488046mL

A ball hangs on a rope of 1.3 mm. The ball is pushed horizontally so that it has a speed of 1.3 m/sm/s. What angle does the rope make with the vertical when the ball's kinetic energy is halved

Answers

The angle the rope make with the vertical when the ball's kinetic energy is halved is 14.78°.

Let K = 1/2mv² be the balls initial kinetic energy when it is pushes horizontally. It rises to a height, h has potential energy U = mgh and has kinetic energy half of its initial kinetic energy. So, K' = 1/2K.

So, from the law of conservation of energy,

K = U + K'

K = U + 1/2K

K - 1/2K = U

K/2 = U

1/2(1/2mv²) = mgh

1/4mv² = mgh

1/4v² = gh

h = v²/4g

Since v = initial speed of ball = 1.3 m/s and g = acceleration due to gravity = 9.8 m/s².

Substituting the values of the variables into the equation, we have

h = v²/4g

h = (1.3 m/s)²/(4 × 9.8 m/s²)

h = 1.69 m²/s² ÷ 39.2 m/s²

h = 0.043 m.

Since the length of the rope l = 1.3 m and the distance of the ball from the pivot when it is h metres above its lowest point is L = l - h = 1.3 m - 0.043 m = 1.257 m.

So, the angle the rope makes with the vertical is Ф and cosФ = L/l

= 1.257/1.3

= 0.9669

Ф = cos⁻¹(0.9669)

Ф = 14.78°

So, the angle the rope make with the vertical when the ball's kinetic energy is halved is 14.78°.

Learn more about oscillatory motion here:

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How do organisms interact?

Answers

Answer:

Individual organisms live together in an ecosystem and depend on one another. ... Some organisms can make their own food, and other organisms have to get their food by eating other organisms. An organism that must obtain their nutrients by eating (consuming) other organisms is called a consumer, or a heterotroph.

Question 13 (2 points)
What is the centripetal acceleration of a jet making a turn with a radius of 0.50 km at a speed of 343 m/s?
Question 13 options:

686 m/s/s

0.7 m/s/s

235 m/s/s

235000 m/s/s
Question 14 (2 points)
Which force produces the largest torque?
Question 14 options:

20.0 N perpendicular to the center of rotation at a radius of 0.5 m

20.0 N perpendicular to the center of rotation at a radius of 1.0 m

10.0 N perpendicular to the center of rotation at a radius of 0.25 m

10.0 N perpendicular to the center of rotation at a radius of 1.5 m
Question 15 (2 points)
A tennis ball is hit across the court, raising up and coming back down. Which of the following statements is true about the tennis ball at the top of its path?
Question 15 options:

The horizontal velocity is zero.

The horizontal acceleration is zero.

The vertical acceleration is zero.

All the other statements are false.
Question 16 (2 points)
What is the name for the path a projectile takes?
Question 16 options:

hyperbolic path

trajectory

centripetal

linear path
Question 17 (2 points)
The centripetal force always points�
Question 17 options:

outside the circle

to the center of the circle

in the direction of the motion

tangential to the circle
Question 18 (2 points)
A plumber needs to increase the torque to unfasten a pipe. How can they do this?
Question 18 options:

Apply more force ONLY.

Get a longer wrench ONLY.

Apply more force AND get a longer wrench.

Neither more force nor a longer wrench will help.
Question 19 (2 points)
A T-shirt cannon needs to launch shirts as far as possible. What angle should the cannon be fired at?
Question 19 options:

Parallel to the ground

30 degrees over the ground

45 degrees over the ground

60 degrees over the ground
Question 20 (2 points)
What forces are acting on a projectile as it flies through the air?
Question 20 options:

gravity and normal

gravity and applied

gravity and tension

just gravity
Question 21 (2 points)


Two balls are thrown at the heights and velocities shown in the figure. Which ball will hit the floor first?

Question 21 options:

Ball A will hit the floor first.

Ball B will hit the floor first.

Both balls will hit the floor at the same time.

There is not enough information to answer the question.
Question 22 (2 points)


Two balls are thrown at the heights and velocities shown in the figure. Which ball travel farther to the right?

Question 22 options:

Ball A will go farther.

Ball B will go farther.

They will both hit the floor at the same place.

There is not enough information to answer the question.
Question 23 (2 points)
If the centripetal force suddenly stops, an object traveling in a circle will
Question 23 options:

continue traveling along the tangent line to the circular path.

continue traveling along the circular path.

stop moving.

continue traveling in some random direction.
Question 24 (2 points)
Which statement about a HORIZONTAL projectile is false?
Question 24 options:

The horizontal velocity is constant.

The horizontal acceleration is constant.

The vertical velocity is constant.

The vertical acceleration is constant.
Question 25 (2 points)


In the figure, a washer on a string (string not shown) moves in the circular path shown in red. Which arrow�best�describes the direction of the tangential velocity of the washer at that instant in time?

Question 25 options:

arrow A

arrow B

arrow C

arrow D

Answers

Bro just ask a simple question anyway 0.7 it’s a guess

Astronauts wear liquid cooled space suits to keep their body temperature moderate. One
group of students used the same technology to design this model of a sportsman's shirt
which transports cool fluid through pipes on it.

Based on the model, which of these conclusions is correct?
A. scientific technologies are independent of each other
B. scientific technologies are always tested on humans
C. space technology helps create products for specific use
D. all space technologies can be replicated for human benefit

Answers

Answer:

D. Because they are using space technology on a shirt so people can wear it on earth as well

potential energy questions

Answers

Answer:

Which of the following has kinetic energy?

A)  A book on a shelf

B)  A girl sprinting

C)  A stretched spring

Explanation:

PLEASE HELP!!!!
If multiple forces are acting on an object, which statement is always true? (1 point)
a. the acceleration will be directed in the direction of the gravitational force
b. a. the acceleration will be directed in the direction of the applied force
c. the acceleration will be directed in the direction of the net force
d. the acceleration will be directed in the direction of the normal force

Answers

Answer: C

Explanation:

The answer is choice C.

The sum of the vectors is the resultant vector, which is where the net force is directed.

An example would be if you had a ball rolling on a table and you bumped the ball perpendicular to its initial velocity, then the ball would move at a diagonal angle rather than move straight in the direction where you bumped it.

Acceleration is the change in velocity over time, so the acceleration vector tells us how the velocity's direction is changing.

Answer:

Explanation:

1.) If multiple forces are acting on an object, which statement is always true?

Answer: The acceleration will be directed in the direction of the net force.

2.) If a ball is accelerating down through the air with no horizontal motion, what must be true about the net forces acting on the ball?

Answer: The gravitational force is greater than the drag.

3.) A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?

Answer: 70 N

4.) Four friends push on the same block in different directions. Allie pushes on the block to the north with a force of 18 N. Bill pushes on the block to the east with a force of 14 N. Chris pushes on the block to south with a force of 23 N. Debra pushes on the block to the west with a force of 20 N. Assuming it does not move vertically, in which directions will the block move?

Answer: south and west

5.)  Two teams are playing tug of war. The tables show the members of each team and how much pulling force each team member applies to the rope.

If Team A pulls to the right and Team B pulls to the left, what is the total horizontal net force applied to the rope?

Answer: 20 N to the left

I hope this helps whoever needs it :))

A cylinder of radius 1.34 cm and a spherical shell of radius 6.97 cm are rolling without slipping along the same floor. The two objects have the same mass. If they are to have the same total kinetic energy, what should the ratio of the cylinder's angular speed wcyl to the spherical shell's angular speed wshl be?

Answers

Answer:

Explanation:

Moment of inertial of a UNIFORM cylinder is ½mR²

Moment of inertial of a spherical shell is ⅔mR²

Total kinetic energy is

KE = ½mv² + ½Iω²

KE = ½m(Rω)² + ½Iω²

KE = ½mR²ω² + ½Iω²

for the cylinder

KE = ½mR²ω₁² + ½(½mR²)ω₁²

KE = ¾m0.0134²ω₁²

for the sphere

KE = ½mR²ω₂² + ½(⅔mR²)ω₂²

KE = ⅚m0.0697²ω₂²

as the KE and mass are the same

¾m0.0134²ω₁² = ⅚m0.0697²ω₂²

¾0.0134²ω₁² = ⅚0.0697²ω₂²

ω₁²/ω₂² = ⅚0.0697²/¾0.0134²

ω₁/ω₂ = 0.0697√⅚ / 0.0134√¾

ω₁/ω₂ = 5.48285455...

avelocity of magnitude 40m/s is directed at an angle 40degree east of north draw a vector an paper to represent this velocity solution ​

Answers

Answer:

Explanation:

the horizontal and vertical component's of the velocity vector:

v_x=vcos\theta=40\ \dfrac{m}{s}\cdot cos40^{\circ}=30.6\ \dfrac{m}{s},v  

x

​  

=vcosθ=40  

s

m

​  

⋅cos40  

=30.6  

s

m

​  

,

v_y=vsin\theta=40\ \dfrac{m}{s}\cdot sin40^{\circ}=25.7\ \dfrac{m}{s}.v  

y

​  

=vsinθ=40  

s

m

​  

⋅sin40  

=25.7  

s

m

.

Let's draw the vector (here one division corresponds to 5 m\s ):

A ball is dropped from 8.5 meters above the ground. If it begins at rest, how long does it take to hit the ground?

Answers

Answer:

Explanation:

Givens

d = 8.5 meters

vi = 0

a = 9.81

t = ?

Formula

d = vi * t + 1/2 a t^2

Solution

8.5 = 0 + 1/2 9.81 * t^2       multiply both sides by 2

8.5 = 4.095 t^2                  Divide both sides by 4.095

8.5/4.095 = t^2

1.7329 = t^2                       Take the square root of both sides

t = 1.316

It takes 1.316 seconds to hit the ground.

Complete this concept map about types of waves.

Answers

Answer:

The answer is within the picture.

Explanation:

Un motociclist se deplseaza cu viteza de 54 km/h . In cat timp parcurge distanta de 18 km ?

Answers

Answer:

6767

Explanation:

The law of ellipse simple explanation

Answers

Kepler's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. ... The resulting shape will be an ellipse. An ellipse is a special curve in which the sum of the distances from every point on the curve to two other points is a constan

If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amperes·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field? A. 0.27 meters B. 2.8 meters C. 0.020 meters D. 3.7 meters

Answers

We know that EMF = L B v

Subbing in, we see that 0.88 = L (0.075) (4.2) => L = 0.88 / (0.075*4.2) = 2.794, which rounds to 2.8 m

Therefore, the correct answer is B

50 km/h east is an example of


velocity


acceleration


time


deceleration

Answers

velocity I hope so oh may

50 km/h east is an example of velocity.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time. Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.

Velocity is direction and magnitude and so 50 km/h east is an example of velocity.

50 km/h east is an example of velocity.

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Suppose you buy 50 L of gasoline at night when the temperature is 20oC. How much
gasoline will you have on a very hot afternoon when the temperature has raised at 39oC?
The coefficient of volume expansion of gasoline is 9.50 x 10-6/Co

Answers

The volume of gasoline you will have on a very hot afternoon when the temperature has raised to 39 °C is 50.009 L

How to determine the volume on a hot afternoon?

The following data were obtained from the question:

Initial volume of gasoline (L₁) = 50 LTemperature of gasoline at night (T₁) = 20 °C Temperature of gasoline on hot afternoon (T₂) = 39 °CCoefficient of volume expansion of gasoline (γ) = 9.50×10⁻⁶ /°C Volume of gasoline on hot afternoon (V₂) =?

V₂ = V₁[1 + γ(T₂ – T₁)]

= 50 × [1 + 9.50×10⁻⁶(39 – 20)]

=  50 × [1 + 9.50×10⁻⁶(19)]

=  50 × 1.0001805

= 50.009 L

Learn more about volume expansion:

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A helicopter flying horizontally at a height H with a speed v0needs to drop a supply capsule to a point P . Assume the capsule has zero relative velocity with respect to the helicopter when it was dropped. Neglect the effect of air resistance. (a) At what distance L away from point P should the heli- copter drop the capsule

Answers

L = V0 x t
L = V0 x (2H/g)^1/2
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