Answer:=
1 7/18
Step-by-step explanation:
Turn the improper fraction into a mixed fraction.
Two students, A and B, are working independently on homework (not necessarily for the same class). Student A takes X = Exp(1) hours to finish his or her homework, while B takes Y = Exp(2) hours. (a) Find the CDF of X/Y , the ratio of their problem-solving times. (b) Find the probability that A finishes his or her homework before B does.
Answer:
a) The CDF of X/Y is calculated as:
[tex]F_{z} (\zeta) = \frac{\zeta}{\zeta + 2}[/tex] for [tex]0 < \zeta < \infty[/tex]
[tex]F_{z} (\zeta) = 0[/tex] for [tex]\zeta \leq 0[/tex]
Note: Z = X/Y
b) Probability that A finishes before B = 1/3
Step-by-step explanation:
For clarity and easiness of expression, this solution is handwritten and attached as a file. Check the complete solution in the attached file.
Antonio burns 75 calories for every 15 minutes
Answer is 5 calories/min
75 divided by 15 is 5
Answer:five cal per min.15 in five groups equals ''75''
A magazine asks its readers to complete a survey on their favorite music and tv celebrities. Classify this sample
Answer:
All the elements in the sample share a common characteristic. All of them read the magazine, so we may have a biased sample. And we also have the bias of the fact that only the volunteers will respond to this survey, so this is a biased sample.
This type of sample is usually called convenience sampling, where the elements in the sample are the most readily available (and what is most readily available for a magazine than its own readers?)
Then the type of sample is a convenience sample and a biased sample.
When estimating a job to bid, a contractor’s estimator first determines the actual cost of labor using the function L(h) = 28.75h, where h is the number of estimated hours it will take to complete the job. Next, the estimator adds the labor burden, which accounts for taxes and insurance, using the function B(L) = 1.78L. Finally, the estimator calculates the selling price, including the markup for overhead and profit, using the function M(B) = 1.43B. Which composite function can be used to find the selling price for the labor portion of a bid based on the estimated number of hours?
Answer:
M(h) = 73.18025h
Step-by-step explanation:
The composite function is ...
M(B(L(h))) = M(B(28.75h)) = M(1.78(28.75h)) = M(51.175h)
= 1.43(51.175h) = 73.18025h
The composite function is ...
M(h) = M(B(L(h))) = 73.18025h
Answer:
a
Step-by-step explanation:
(a) Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the power series expansion of the given function.
(b) Based on the information given in the section on algebraic properties of power series, for which values of x can you guarantee that the new series converges.
(If you have a CAS, you can easily find several more nonzero terms in the power series expansions of the functions.)
(e^x)/(cos(x))
Answer:
a) [tex]\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}[/tex]
b) See Below for proper explanation
Step-by-step explanation:
a) The objective here is to Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the power series expansion of the given function.
The function is [tex]e^x + 3 \ cos \ x[/tex]
The expansion is of [tex]e^x[/tex] is [tex]e^x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ...[/tex]
The expansion of cos x is [tex]cos \ x = 1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...[/tex]
Therefore; [tex]e^x + 3 \ cos \ x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ... 3[1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...][/tex]
[tex]e^x + 3 \ cos \ x = 4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} + \dfrac{x^3}{3!}+ ...[/tex]
Thus, the first three terms of the above series are:
[tex]\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}[/tex]
b)
The series for [tex]e^x + 3 \ cos \ x[/tex] is [tex]\sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!} + 3 \sum \limits^{\infty}_{x=0} ( -1 )^x \dfrac{x^{2x}}{(2n)!}[/tex]
let consider the series; [tex]\sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!}[/tex]
[tex]|\frac{a_x+1}{a_x}| = | \frac{x^{n+1}}{(n+1)!} * \frac{n!}{x^x}| = |\frac{x}{(n+1)}| \to 0 \ as \ n \to \infty[/tex]
Thus it converges for all value of x
Let also consider the series [tex]\sum \limits^{\infty}_{x=0}(-1)^x\dfrac{x^{2n}}{(2n)!}[/tex]
It also converges for all values of x
Suppose you would like to save P9000 invested at 8% compounded quarterly for 5 years and 6 months. (Note: Round off your answer to the nearest hundredth) (a) How much would the value of her savings at the end of the term? Answer (b) How much is the interest earned by your savings? Answer
Answer:
a) 13913
b) 4913.82
Step-by-step explanation:
The compound interest formula is given by:
[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]
Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.
In this question:
Investment of 9000, so [tex]P = 9000[/tex]
Interest rate of 8%, so [tex]r = 0.08[/tex]
Compounded quarterly, so [tex]n = 4[/tex]
5 years and 6 months, that is, 5 years and half, so [tex]t = 5.5[/tex]
(a) How much would the value of her savings at the end of the term?
[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]
[tex]A(5.5) = 9000(1 + \frac{0.08}{4})^{4*5.5} = 13913.82[/tex]
(b) How much is the interest earned by your savings?
The amount subtracted by the principal. So
13913.82 - 9000 = 4913.82
Michelle purchased a sofa that was on sale for $125 off. The original price of the sofa was $515. What was the sale price of the sofa?
Answer:
We know that:
The original price was $515
and
It was $125 off
so we need to find the price of the sofa after the discount.
$515 - $125 = $390
The sale price of the sofa after the discount was $390
hope This helps and pls mark me brainliest if it did :)
For problems 3 and 4, find the missing side of the triangle. Leave answers in simplest radical form.
Answer: 3. 4[tex]\sqrt{13}[/tex] 4. [tex]\sqrt{225}[/tex]
Step-by-step explanation:
8^2 + 12^3 = c^2
64 + 144 = c^2
208 = c^2
√208
[tex]4\sqrt{13}[/tex]
The final answer is the square root of 208
8^2 + b^2 = 17^2
64 + b^2 = 289
-64 64
b^2 = 225
[tex]\sqrt{225}[/tex]
A 500.0 g piece of aluminum at 100° C is placed in 300ml of water. While in the water, the
aluminum then cools to 30°C. Calculate the amount of heat lost by the aluminum. The
specific heat of water is 4.18 J/g °C and the specific heat of aluminum is 0.90 J/g °C
Answer:
The amount of heat lost by the aluminum is 31,500 J
Step-by-step explanation:
Given;
mass of aluminum, m = 500 g
initial temperature of the aluminum, θ₁ = 100° C
final temperature of the aluminum, θ₂ = 30°C
specific heat capacity of water, C = 4.18 J/g °C
specific heat capacity of aluminum , C = 0.90 J/g
Heat lost by the aluminum is equal to heat gained by the water.
The amount of heat lost by the aluminum, is calculated as;
Q = MCΔθ
Q = 500 x 0.9 (100 - 30)
Q = 500 x 0.9 x 70
Q = 31,500 J
Therefore, the amount of heat lost by the aluminum is 31,500 J
Akmal, Bakri and Cadin share their mother medical expenses which cost RM4200. Cadin pays RM2100 while akmal pays three quarters of Bakri amount. Find the ratio of the expenses shared by Akmal to Bakri to Cadin
Answer:
The ratio of the expenses shared by Akmal to Bakri to Cadin is 7 : 4 : 3
Step-by-step explanation:
The 3 of them shares their mother medical expenses which cost RM4200 . There mother medical expenses is RM4200 in total. Cadin pays RM2100 which is half of their mother medical expenses. Then Akmal pays three quarters of Bakri amount.
Let
The amount Bakri pays = a
Akmal pays = 3/4 of a
Akmal pays = 3/4a
Therefore,
a + 3a/4 = 2100
4a + 3a/ 4 = 2100
7a/4 = 2100
cross multiply
7a = 8400
divide both sides by 7
a = 8400/7
a = 1200
Therefore,
Bakri pays =RM 1200
Akmal pays = 3/4 × 1200 =RM 900
The ratio of the expenses shared by AKmal to Bakri to Cadin is expressed as 2100 : 1200 : 900. Divide through by 300
7 : 4 : 3
1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and
the sum of the ages of all 3 is 147 years, what is the age difference between oldest the
youngest?
Answer:
37 years difference.
Step-by-step explanation:
K = Kissi
k = Age of Kissi
E = Esinam
e = Age of Esinam
L = Lariba
l = Age of Lariba
k + e + l = 147
K : E
3 : 5 → (×3) → 12 : 15
E : L
3 : 5 → (×5) → 15 : 25
K : E : L
12 : 15 : 25
12 + 15 + 25 = 52
147/52 = 2.8269...
K is the young since out of the three part ratio, 12 is the smallest and likewise, L is the oldest.
k = 12 × 2.8269... = 33.923... → 34 y/o
e = 15 × 2.8269... = 42.40... → 42 y/o
l = 25 × 2.8269... = 70.673... → 71 y/o
∴ The difference between the youngest and oldest is:
71 - 34 = 37
y=5•(0)
Which graph represents the function
?
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard deviation 7.6 mm.(a)What is the probability that defect length is at most 20 mm
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 28, \sigma = 7.6[/tex]
What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 28}{7.6}[/tex]
[tex]Z = -1.05[/tex]
[tex]Z = -1.05[/tex] has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
I want to buy a car for $1150.00. I earn $5.25 per hour. How many hours must work to buy the car if all my earnings go for this purchase?
Answer
About 219-220
Step-by-step explanation:
Answer: $219.047619
Step-by-step explanation: 1150.00 ÷ 5.25 = 219.047619
The product of two integers
is 270. If one of the integers
is-18, find the other.
Step-by-step explanation:
To find it we will simply divide 270 by - 18
270 ÷ - 18 = - 15
Answer:
- 15
Step-by-step explanation:
ab=270
-18b=270
b=270/(-18)
b= - 15
The lines shown below are parallel if the green line has a slope of 8 what is the slope of the redline?
Answer:
Option D
Step-by-step explanation:
If these lines are parallel, they should have the same slope. How so? Well slope is the change in axis, y / x more specifically. If the lines are parallel they should change at a similar rate so that they don't intersect, and hence are, by definition, ║;
[tex]Green Line's Slope = Red Line's Slope,\\8 = Red Line's Slope,\\Red Line's Slope = 8 units\\\\Solution - Option D[/tex]
Hope that helps!
A cell phone company is offering 2 different monthly plans. Each plan charges a monthly fee plus an additional cost per minute. Plan A: $ 40 fee plus $0.45 per minute Plan B: $70 fee plus $0.35 per minute a) Write an equation to represent the cost of Plan A b) Write an equation to represent the cost of Plan B c) Which plan would be least expensive for a total of 100 minutes?
*Please Show Work*
Answer:
Plan A would be the least expensive
Step-by-step explanation:
Plan A= $0.45x100= 45, 45+40=$85
Plan B= $0.35x100= 35, 35+70= %105
(Each plan is for 100 minutes)
Suppose you buy a CD for $500 that earns 3% APR and is compounded quarterly. The CD matures in 3 years. Assume that if funds are withdrawn before the CD matures, the early withdrawal fee is 3 months' interest. What is the early withdrawal fee on this account?
Answer:
$3.75
Step-by-step explanation:
I = Prt
I = $500·0.03·(3/12) = $3.75
The early-withdrawal fee is $3.75 for the first quarter.
_____
Each quarter after that, the principal amount will be larger, so the interest penalty will be larger. The fee would be the amount of interest that would be credited at the end of the next quarter, or at the end of the quarter currently in progress.
find five rational numbers between ? explain please
Answer:
1.5, 6, 24.7, 384, 404.4, 1,980Step-by-step explanation:
Rational numbers are the result of dividing two integers. Intergers cannot be fractions. So 1.5 is rational but 3/2 is not.
Five rational numbers: 1.5, 6, 24.7, 384, 404.4, 1,980
I'm always happy to help :)
lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2:131F2:131 white squash, 3434 yellow squash, and 1010 green squash. Are these data consistent with a 12:3:112:3:1 dominant epistatic model of genetic inheritance( white being dominant)? The null hypothesis for the chi‑square goodness‑of‑fit test is
Here is the full question:
When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.
Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?
The null hypothesis for the chi-square goodness-of-fit test is
Answer:
The null hypothesis for the chi-square goodness-of-fit test is :
[tex]\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16} }[/tex]
Step-by-step explanation:
The objective of this question is to state the null hypothesis for the chi-square goodness-of-fit test.
Given that:
There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1
The total number of these color traits associated with this model = 12 + 3 + 1 = 16
Thus ;
The null hypothesis for the chi-square goodness-of-fit test is :
[tex]\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16} }[/tex]
A sports physician conducts an observational study to learn the average amount of time that 3,000 swimmers in the town can hold their breath underwater. He uses 150 sampling of 60 people. The average of the means of all the samplings is 72.7, and the standard deviation is 0.92. This is a histogram of the sampling distribution of the sample mean
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
A sports physician conducts an observational study to learn the average amount of time that 3,000 swimmers in the town can hold their breath underwater. He uses 150 sampling of 60 people. The average of the means of all the samplings is 72.7, and the standard deviation is 0.92. This is a histogram of the sampling distribution of the sample mean. Based on this data, with a 95% confidence interval the researchers can determine that the actual average amount of time the entire population can hold their breath under water is?
Given Information:
sample mean time = 72.7
sample standard deviation = 0.92
Sampling size = n = 150
Confidence level = 95%
Required Information:
95% confidence interval = ?
Answer:
[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 72.7 \pm 0.14836\\\\\text {confidence interval} = 72.7 - 0.14836, \: 72.7 + 0.14836\\\\\text {confidence interval} = (72.552, \: 72.848)\\\\[/tex]
Step-by-step explanation:
The confidence interval is given by
[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\[/tex]
Where [tex]\bar{x}[/tex] is the sample mean time and Margin of error is given by
[tex]$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\[/tex]
Where n is the sampling size, s is the sample standard deviation, and [tex]t_{\alpha/2}[/tex] is the t-score corresponding to 95% confidence level.
The t-score corresponding to 95% confidence level is
Significance level = 1 - 0.95 = 0.05/2 = 0.025
Degree of freedom = n - 1 = 150 - 1 = 149
From the t-table at α = 0.025 and DoF = 149
t-score = 1.975
[tex]MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 1.975\cdot \frac{0.92}{\sqrt{150} } \\\\MoE = 1.96\cdot 0.07512\\\\MoE = 0.14836\\\\[/tex]
So the required 95% confidence interval is
[tex]\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 72.7 \pm 0.14836\\\\\text {confidence interval} = 72.7 - 0.14836, \: 72.7 + 0.14836\\\\\text {confidence interval} = (72.552, \: 72.848)\\\\[/tex]
Therefore, we are 95% confident that actual average amount of time the entire population can hold their breath under water is within the range of (72.552, 72.848)
Help asap giving branlist!!!
Answer:
Option 2
Step-by-step explanation:
The question states "the width of the rectangle is 4 less than half the length." Since we are looking for the value of w, w will be equal to the expression we create. We start with half the length and than subtract 4 from it. This is because it says 4 less than half the length, not half of 4-length or another variation. In many of these problems the best way to solve them is by working backwards.
Answer:
Option 2
Step-by-step explanation:
Translating these words into math, we get w = 1/2l - 4 which is Option 2.
What’s 148+383-163=?
Answer:
368
Step-by-step explanation:
An urban economist is curious if the distribution in where Oregon residents live is different today than it was in 1990. She observes that today there are approximately 3,109 thousand residents in NW Oregon, 902 thousand residents in SW Oregon, 244 thousand in Central Oregon, and 102 thousand in Eastern Oregon. She knows that in 1990 the breakdown was as follows:
72.7% NW Oregon, 20.7% SW Oregon, 4.8% Central Oregon, and 2.8% Eastern Oregon.
Can she conclude that the distribution in residence is different today at a 0.05 level of significance?
a) Yes, because the p-value = .0009.
b) No, because the p-value = .0009.
c) Yes, because the p-value = .0172.
d) No, because the p-value = .0172.
Answer:
c) Yes, because the p-value = 0.0172
Step-by-step explanation:
The following table is obtained:
Categories Observed(fo) Expected (fe) (fo-fe)²/fe
NW Oregon 3109 4357*0.727=3167.539 1.082
SW Oregon 902 4357*0.207=901.899 0
Central Oregon 244 4357*0.048=209.136 5.812
Eastern Oregon 102 4357*0.028=121.996 3.277
Sum = 4357 4357 10.171
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
H0:p1=0.727,p2=0.207,p3=0.048,p4=0.028
Ha: Some of the population proportions differ from the values stated in the null hypothesis
This corresponds to a Chi-Square test for Goodness of Fit.
(2) Rejection Region
Based on the information provided, the significance level is α=0.05, the number of degrees of freedom is df=4−1=3, so then the rejection region for this test is R={χ2:χ2>7.815}.
(3) Test Statistics
The Chi-Squared statistic is computed as follows:
[tex]X^2=\sum^n_{i=1}\frac{(O_i-E_i)^2}{y} \\\\= 1.082+0+5.812 +3.277 = 10.171[/tex]
(4) Decision about the null hypothesis
Since it is observed that
[tex]X^2 = 10.171 > X_c^2 = 7.815[/tex]
it is then concluded that the null hypothesis is rejected.
(5) Conclusion
It is concluded that the null hypothesis H_o is rejected. Therefore, there is enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the α=0.05 significance level.
–12 + 3b – 1 = –5 – b
Answer:
2
Step-by-step explanation:
-13+3b=-5-b
4b=8
b=2
Written as a simplified polynomial in standard form, what is the result when
(x + 1)2 is subtracted from 7x2 - 4x + 6?
Answer:
The resultant polynomial is: [tex]6x^2-6x+5[/tex]
Step-by-step explanation:
We need to subtract [tex](x+1)^{2}[/tex] from [tex]7x^2-4x+6[/tex]
so, we start by performing the multiplication involved in the perfect square of the binomial [tex](x+1)[/tex], and obtain its expression in separate terms that can be combined:
[tex](x+1)^{2}=(x+1)\,(x+1)=x^2+x+x+1=x^2+2x+1[/tex]
Now we can subtract this trinomial from [tex]7x^2-4x+6[/tex], and combining like terms to get the resultant polynomial expression:
[tex]7x^2-4x+6-(x^2+2x+1)=7x^2-4x+6-x^2-2x-1=7x^2-x^2-4x-2x+6-1=6x^2-6x+5[/tex]
Then the resultant polynomial is: [tex]6x^2-6x+5[/tex]
Solve for x
A) -8
B) 3.5
C) 8
D) 26
Answer:
C) 8
Step-by-step explanation:
By remote interior angle property of a triangle.
[tex] 19x - 3 = 94° + 7x - 1\\\\
19x - 7x = 94 + 3 - 1\\\\
12 x = 96\\\\
x = \frac{96}{12}\\\\
\huge \orange{\boxed {x = 8}} [/tex]
write down the exact value of
a. cos 30 degrees
b. sin45 degrees
c. tan 30 degrees
Answer:
.86602 a
.707106 b
.577355 c
Step-by-step explanation:
entered itno calculator
Los dueños de un restaurante cultivan sus propios
tomates, hierbas aromáticas, acelgas y otros vegetales
que utilizan en la preparación de sus comidas. Para el
riego de sus plantas, han construido un reservorio, cuya
capacidad es de 6,25 m3. Si al cabo de unos días han
utilizado los 2/3 de esta cantidad, ¿cuántos metros
cúbicos de agua todavía quedan en el reservorio y a
cuántos litros equivale?
(Considera 1 m3 = 1000 L).
Answer:
Quedan 2.083 m^3 de agua en el reservorio.
Equivalen a 2083 litros.
Step-by-step explanation:
Los dueños del restaurante tienen un reservorio de agua cuyo volumen es de 6.25 m^3.
Si han utilizado 2/3 del reservorio, esto implica que aún quedan en el reservorio una tercera parte del volumen original (1/3).
Entonces, la cantidad de metros cúbicos (m^3) de agua que quedan en el reservorio se puede calcular como:
[tex]V=(1/3)\cdot V_0=(1/3)\cdot6.25\,m^3=2.083\,m^3[/tex]
Este valor equivale a un volumen en litros de:
[tex]V=2.083\,m^3\cdot \dfrac{1,000\,l}{1m^3}=2,083\,l[/tex]
describe the slope of the graph from 1 sec to 5.3 sec ( is the slope positive, negative, zero or non existent)
Answer:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
Where x for this case represent the time and y the height waist off ground.
We have one point that can be extracted from the graph on this case:
[tex] x_1 = 1, y_1= 3[/tex]
Bout for the other point we have:
[tex] x_2 = 5.3 , y_2 = 9.6[/tex]
Is important to notice that 9.6 is an estimation since we don't have the scale to identify the real value. so then if we replace we got:
[tex] m =\frac{9.6-3}{5.3-1}= 1.535[/tex]
And for this case we can conclude that this slope is positive and around 1.5 and 1.6. And that means if we increase the time in one unit then the height off waist off ground would increae about 1.5 to 1.6 ft
Step-by-step explanation:
In order to calculate the slope we need to use the following formula:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
Where x for this case represent the time and y the height waist off ground.
We have one point that can be extracted from the graph on this case:
[tex] x_1 = 1, y_1= 3[/tex]
Bout for the other point we have:
[tex] x_2 = 5.3 , y_2 = 9.6[/tex]
Is important to notice that 9.6 is an estimation since we don't have the scale to identify the real value. so then if we replace we got:
[tex] m =\frac{9.6-3}{5.3-1}= 1.535[/tex]
And for this case we can conclude that this slope is positive and around 1.5 and 1.6. And that means if we increase the time in one unit then the height off waist off ground would increae about 1.5 to 1.6 ft