Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are
still 4.8 m high, they are traveling at a speed of 8.0 m/s.
a) Calculate the Eg. [write here]
b) Calculate theEk [write here]
c) Calculate the Etotal. [write here)

Assume You Have A Person With A Mass Of 65 Kg Riding A Skateboard Down A Ramp. While They Arestill 4.8

Answers

Answer 1

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

Explanation:

The given parameters are;

The mass of the person, m = 65 kg

The height of the person, h = 4.8 m

The speed of the person, v = 8.0 m/s

a) The gravitational potential energy, [tex]E_g[/tex] = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j

Eg = 3,060.72 j

b) The kinetic energy, Ek = 1/2·m·v²

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j

Ek = 2,080 j

c) The constant total Mechanical Energy, Etotal = Eg + Ek

∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j

Etotal = 5,140.72 j.


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Answers

Answer: The employee must do 11.2308 Joules of work

Explanation:

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But  

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F = 294N

Also distance moved can be found using  the equation  

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Work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.

What is work done?

Work done is the force applied on a body to move it over a distance. Work done by a body can be given as,

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Here (F) is the magnitude of force and (d) is the distance traveled.

From the second law of motion, the force is product of mass time acceleration. Thus the above formula can be given as,

[tex]W=(ma)d[/tex]

For the gravitational acceleration, it can be written as,

[tex]W=(mg)d\\W=mgd[/tex]

The constant speed by which, the warehouse employee is pushing the desk across a floor is 0.50 m/s and the the final speed of the desk is 1 m/s.

Thus, the distance traveled by it can be find out using the third law of motion as,

[tex]v^2-u^2=2gd\\1^2-0.25^2=2\times9.8\times d\\d=0.0382\rm m[/tex]

As the mass of the desk is 30 kg and the distance moved is 0.382 meters. Thus, put the values in the above formula as,

[tex]W=30\times9.81\times0.0382\\W\cong11.3\rm J[/tex]

Thus the work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.

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Does Ganymede have phases?

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Answer:

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i need help asap !

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25%

125%

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Answer:

the answer is 100%!

your welcome

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Answer:

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Explanation:

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A marble was sent down a ramp into a solo cup. The first time the solo cup moved 20 cm. The second time the solo cup moved 24 cm. The third time the cup moved 16 cm. What is the average movement of the cup?​

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66yuvuvuvyftf5v7bictdtv7hivyftf5d5v7bibivydrd5gu ihibjbibibibibibibibibibibibibibibinonononononononompmpmpmpmpmpmpmpmpmpmpmpmpmpmpmpmpmpnininibibibuvuvuvuvycycyc6ctctcrxrxrzezea2ax4xtctcycyvyvyv7hibibinonobuvt

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Answer:

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Explanation:

From the question,

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make q' the subject of the equation

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The answer is deposition/A. Please mark brainliest.
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Answer:

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hi

mass is express  in Newtons.

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Answer:

they can have both ways because it turns out that they can go into different ways light waves are associated with constantly like her to certain ways or

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Answer:

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Help pweaseeee ill give u a brainlest

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Answer:

Mass of the larger object

Assume you have a person with a mass of 65 kg riding a skateboard down a ramp. While they are
still 4.8 m high, they are traveling at a speed of 8.0 m/s.
a) Calculate the Eg. [write here)
b) Calculate theEk [write here]
c) Calculate the Etotal. [write here]
d) If the ramp had a total height of 8.0 m, what would be their Eg, Ek, and Etotal at that height?

Answers

Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

d) Eg = 5,140.2 j

Ek = 0 j

Etotal = 5,140.2 j

Explanation:

The given parameters of the person riding the skateboard are;

The mass of the person, m = 65 kg

The height of the person (above ground level), h = 4.8 m

The speed at which the person is traveling, v = 8.0 m/s

a) The gravitational potential energy, Eg = m·g·h

Where;

m = The mass of the object at the given height = 65 kg

g = The acceleration due to gravity, g ≈ 9.81 m/s²

h = The height by which the object is elevated = 4.8 m

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 joules

The gravitational potential energy, Eg = 3,060.72 J

b) The kinetic energy, Ek, is given as follows;

Ek = 1/2·m·v²

Where;

v = The velocity of the object = 8.0 m/s

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 joules

The kinetic energy, Ek = 2,080 J

c) The total mechanical energy, Etotal = Eg + Ek

∴  Etotal = 3,060.72 j + 2,080 j = 5,140.72 J

The kinetic energy, Ek = 5,140.72 J

d) If the ramp had a total height of 8.0 m, we have;

At the 8.0 m height

Etotal = Eg(max), Ek = 0 j

With the given values, we get;

Eg(max) = 65 kg × 9.81 m/s² × 8 m = 5,101.2 joules = Etotal

Eg(max) = 5,101.2 j

Etotal = 5,101.2 j

Ek = 0 j

However, using only the values in the question with the assumption that all things being equal, we have;

Etotal = Constant = 5,140.72 j

Eg a the max height, 8.0 m = Eg(max) = Etotal = 5,140.2 j

Ek = 0 j

plz answer fast need your help plz plz plz​

Answers

Answer:

the vertical component of the force is 43.30 N.

Explanation:

Given;

angle of inclination of the force, θ = 60⁰

magnitude of the force, F = 50 N

The vertical component of the force is calculated as follows;

[tex]F_y = F \times sin(\theta}\\\\F_y = 50 N \times sin(60)\\\\F_y = 50 N \times \frac{\sqrt{3} }{2} \\\\F_y = 25\sqrt{3} \ N\\\\F_y = 43.30 \ N[/tex]

Therefore, the vertical component of the force is 43.30 N.

Which of the following explanations is correct about the wave that travels through the medium?
A. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
B. The vibration that produced the wave must have been perpendicular to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a transverse wave.
C. The vibration that produced the wave must have been parallel to the direction of motion of the resulting wave, because the figure shows that the resulting wave is a longitudinal wave.
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The correct answer is letter A
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