Assume that a normal curve is a good model for this data set. If 10,000 more observations were collected, what percentage of the observations would be greater than 98.02? In other words, what percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis?

A) 5.9%
B) 2.96%
C) 2.5%
D) 0.0%

Answer:

OC. Fe³+

Explanation:

Greater reduction potential (bigger positive E value) means that things wants to get electrons. For this, you have to look at the chart that I have attached. Since, Fe3+ has highest E value out of other options, it will likely be reduced.

The species which is most likely to get reduced is Fe³⁺.

Reduction is the process of the addition of electrons and loss of oxygen atoms. It is part of redox reactions.

Redox reactions are the type of reactions in which oxidation and reduction simultaneously take place. Oxidation is the addition of oxygen atoms. Reduction is the removal of oxygen atoms.

Redox reaction can be represented as:

PbO (s) + H₂ (g) → Pb(s) + H₂O (l)

In the above reaction, PbO is getting reduced and H₂ is getting oxidized.

Fe³⁺ is most likely to get reduced because the more positive the value of reduction potential, the more will be its tendency to get reduced.

In the given four species, the value of the reduction potential of Fe³⁺ is the highest.

Values of the reduction potential of four species are:

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The pH can be obtained directly from the concentration using the formula below pH = - log [H⁺]  Hence, pH of a 8.4x10⁻⁶ M H⁺ solution is 5.08.

A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

Taking the negative logarithm of the concentration of hydronium ions that are in the solution:

pH = - log [H⁺]

     = - log [8.4x10⁻⁶ ]

     =  5.08

Hence, pH of a 8.4x10⁻⁶ M H⁺ solution is 5.08.

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Explanation:

I) carbon dioxide

ii) nitrogen dioxide

iii) nitric acid

iv) sulphric acid

v) Potassium dichromate

vi) hexacyanoferrate (III) ion( not sure)

To determine the percentage yield, do the following:

Stoichiometry simply defined the relationships of the various quantities as they react in a chemical reaction

Scientist are mostly inquisitive and as such may want to determine the percentage yield of a reaction even before carrying it out.

To determine the percentage for a given reaction, we must set up the following:

From the above, we can conclude that option A gives the right steps if we must successfully determine the percentage yield of a reaction.

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Answer:

A

Explanation:

Edge 2022

Answer:

6 moles

Explanation:

From the equation you can see that twice as many HCL moles are used as H2 produced

2 x 3 = 6 moles  of HCL required

Answer:

Hint for Naming XeCl4

We have two non-metals so this is a molecular (sometimes called covalent) compound.

Answer:

T₂ = 39.4 °K

Explanation:

Because you are only dealing with volume and temperature, you can use Charles' Law to find the missing value. The formula looks like this:

V₁ / T₁ = V₂ / T₂

In this formula, "V₁" and T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You have been given values for all of the variables except for "T₂". Therefore, by plugging these values into the formula, you can simplify to find the answer.

V₁ = 350 mL                     T₁ = 45 °K

V₂ = 400 mL                     T₂ = ?

V₁ / T₁ = V₂ / T₂                                        <----- Charles' Law formula

(350 mL)(45 °K) = (400 mL)T₂                <----- Insert values into variables

15750 = (400 mL)T₂                                <----- Multiply left side

39.4 = T₂                                                 <----- Divide both sides by 400

Answer:

The two that are true are, "this represents a pure compound in two different states" and "it represents a mixture a solid and a gas".

Explanation:

This two are concluded only from the picture and the use of uniform colors throughout the picture (Showing the same element).

The nucleus of the atom is the heaviest part of the atom.

When the ratio of neutrons to protons is too high, the nucleus becomes unstable and Beta emission has to take place.

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Answer: a = 2 ; f = 5 ; b = 2 ; g = 2 ; c = 2 ; h = 2 ; d = 4 ; i = 5 ; e = 3 ; j = 7

Explanation: Some rules to follow while calculating sig figs is

1. If a number like 4500 is present, only two sig figs are counted, but none of the zeros are, but if 4500. has a decimal point present, then you should count all the numbers available.

2. If a number like .0005 is present, only count 5 as a sig fig, however if the number is .00050, count the 0 after the 5 in this example (this would then have two sig figs.

Answer:

95.45 moles

Explanation:

CO2 has mole weight  12 + 2 *16 = 44 gm/mole

4200 gm / 44 gm/mole = 95.45 moles

The ⁴⁰₁₈X is the symbol for ⁴⁰₁₈Ar - atom and it has 18 protons, 18 electrons, and 22 neutrons.

Mass number is the sum of the numbers of protons and neutrons present in the nucleus of an atom.

In the given element,  ⁴⁰₁₈X,  Subscript 18 is the number of proton and is also equal to the number of electron. While supercript 40 is the atomic mass.

The number of neutrons is given by subtracting the proton number from the mass number.

Therefore,

Number of Neutron = Mass Number - Atomic Number

                                 = 40 - 18

                                 = 22 Neutrons

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Oven cleaners typically contain a layer of sodium hydroxide, which converts the greases and oils on the oven walls into soap, which can then be cleaned away more easily.

A chamber used for baking, heating, or drying.

Self-cleaning ovens emit dangerous fumes into the air with an unpleasant burning smell. Self-cleaning ovens reach high temperatures and produce fumes from the cooking of food particles. These fumes circulate with the air and can affect the home substances.

Spray-on oven cleaner ovens contain a layer (sodium hydroxide), which converts the greases of the oven walls into soap, which can then be cleaned away more easily.

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Answer: .75 M

Explanation:

Answer:

8.33 atm

Explanation:

Xe is   5  out of (4+5)   or   5 / 9 ths of the gas present

  5/9  * 15 atm = 8.33 atm

Answer:

can you post a photo? to help y with the question

Explanation:

If data from a clinical trial contains personal information about a study participant, De-identification process should be used to separate identifying information from health information. Thus, Option (A) is correct

De-identification is a process of detecting identifiers (e.g., personal names and social security numbers) that directly or indirectly point to a person (or entity) and deleting those identifiers from the data.

De-identification and anonymization are strategies that are used to remove patient identifiers in electronic health record (EHR) data.

Hence, De-identification process should be used to separate identifying information from health information. Thus, Option (A) is correct.

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Answer: B and E are True

Explanation:

Because Fe has a higher oxidation potential than H2, H+ can oxidize it.

[tex]$\begin{array}{llllll}\mathrm{Fe} & \rightarrow & \mathrm{Fe}^{2+} & +2 \mathrm{e}- & \mathrm{E}^{0}=0.44 \mathrm{~V} \\ \mathrm{H} & \rightarrow & \mathrm{H}^{+} & + & \mathrm{e}^{-} & \mathrm{E}^{0}=0 \mathrm{~V}\end{array}$[/tex]

Ni can reduce Br2 because the reduction potential of Ni is more than Br2.

[tex]\mathrm{Ni}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni}^{-} \quad \mathrm{E}^{0}=-0.25 \mathrm{~V}\\2 \mathrm{Br}^{-} \quad \rightarrow \mathrm{Br}_{2}+2 \mathrm{e}^{-} \quad \mathrm{E}^{0}=-1.087 \mathrm{~V}$[/tex]

Answer:

Work is the use of force to move an object. It is directly related to both the force applied to the object and the distance the object moves. Work can be calculated with this equation: Work = Force x Distance.

:)

Answer:

In ionic bond one element should be metal and next should be non metal. in covalent both element should be met Alice. if there valence electron is less than 4 than it is metal or more than 4 it is non metal.

For all three questions, we will use the fact that

1) For 175 mL of solution at 0.203 M, this means that:

Considering the hydrochloric acid solution, if we have 0.035523 mol, then:

2) If there is 20.3 mL = 0.0203 L, then:

This means that the molarity of the diluted solution is:

3) If we need 1.50 L of 0.700 M solution, then:

Considering the 9.36 M acid solution, from which we need 1.05 mol of perchloric acid from,

Aluminum can be oxidized by [tex]Li^{+}[/tex] and [tex]Ca^{2+}[/tex]

Some of the metal corrodes (or oxidizes) and forms the corresponding metal oxide on the surface as a result of a chemical reaction between the metal surface and the oxygen in the air. The corrosion products that occur in some metals, like steel, are highly apparent and loose.

According to reactivity series (The array of metals in the descending order of their reactivities is referred to as the metals' reactivity series. It is sometimes referred to as the metals in the activity series.)

Lithium and calcium ions are more reactive than aluminum ion and they are less electronegative.

Since silver and tin are more electronegative than aluminum so, they cannot oxidize aluminum.

∴ [tex]Li^{+}[/tex] and [tex]Ca^{+2}[/tex] ions can oxidize aluminum.

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Answer:

pH = 4.6  

Explanation:

pH is the negative of the log of the hydrogen ion concentration

- log { 2.52 x 10^-5)   = ~ 4.6

Answer:

chuma ya ndoshi.............

Explanation:

.

kwenda ukalale .............

Answer:

The si unit used to measure weight is kilogram /kg

A chemical equilibrium when the amounts of reactants or products no longer change.

Explanation:

Chemical equilibrium is a dynamic process, meaning the rate of formation of products by the forward reaction is equal to the rate at which the products re-form reactants by the reverse reaction.

The complete table is inserted.

A table is given,

Formulas used:

pH=  -log(H⁺)

pOH=  -log(OH⁻)

pH+ pOH=14

Calculations:

For A: (H⁺)=2×10⁻⁸M

Using the pH formula:

pH=  -log(H⁺)=-log(2×10⁻⁸)=7.69

pOH=14 - 7.69=6.3

Calculating OH concentration,

pOH=  -log(OH⁻)

6.3= -log(OH⁻)

(OH⁻)=5.011×10⁻⁷M

Hence, the nature of A is basic.

Similarily,

For B,

(OH⁻)=1×10⁻⁷

Using the pH formula:

pOH=  -log(OH⁻)= -log(1×10⁻⁷)=7

pH=14-7=7

Calculating H concentration,

pH=  -log(H⁺)

7= -log(H⁺)

(H⁺)=1×10⁻⁷M

Hence, the nature of B is neutral.

Similarily,

For C,

pH=12.3

Using the pH formula:

pOH=14-12.3=1.7

Calculating H concentration,

pH=  -log(H⁺)

12.3= -log(H⁺)

(H⁺)=5.011×10⁻¹³M

Calculating OH concentration,

pOH=  -log(OH⁻)

1.7= -log(OH⁻)

(OH⁻)=1.99×10⁻²M

Hence, the nature of C is Basic.

Similarily,

For D,

pOH=6.8

Using the pH formula:

pH=14-6.8=7.2

Calculating H concentration,

pH=  -log(H⁺)

7.2= -log(H⁺)

(H⁺)=6.309×10⁻⁸M

Calculating OH concentration,

pOH=  -log(OH⁻)

6.8= -log(OH⁻)

(OH⁻)=1.58×10⁻⁷M

Hence, the nature of D is basic.

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Assuming pressure is held constant,

[tex]\frac{8}{3}=\frac{V_{2}}{4}\\\\V_{2}=4\left(\frac{8}{3} \right) \approx \boxed{10.7 \text{ L}}[/tex]