Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the machine?

Answers

Answer 1

Answer:

80 Percent

Explanation:

E=energy output/energy input×100

E=8000/10000×100

E=0.8×100

E=80 percent.

Mark brianliest if my answer suit your question

Answer 2

If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.

What is Work?

Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.

Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.

As per the data provided in the question,

Total input energy = 10,000 J

Total output energy = 8,000 J

Then, the efficiency (η) of the machine will be,

η = (output energy/input energy) × 100

η = 8000/10000 × 100

η = 80%.

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Related Questions

Please give me concept to solve this.

Answers

Answer:

The difference in tension,  between adjacent sections of the pull cable at the given conditions is 17.701 kN

Explanation:

We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation

[tex]F_{car}[/tex] = Upward tension force,  [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable

The parameters given are;

Mass of car, m = 2750 kg

Angle of inclination of taut cables, θ = 35°

The upward acceleration of the car, a = 0.81 m/s²

Given that the weight is acting vertically downwards, we have;

Component of the weight of the car along the taut cable = m × g × sin(θ)

∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N

We therefore have;

[tex]F_{car}[/tex] =  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N

[tex]F_{car}[/tex]  = m × a = 2750 × 0.81 =  [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66

∴  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N

Hence the difference in tension,  [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.

a linear function has the same y-intercept as x + 4y equals 16 and it's graph contains the point (4,5). Find the slope of the linear function. ​

Answers

Answer:  [tex]\bold{\text{Slope (m)}=\dfrac{1}{4}}[/tex]

Explanation:

A linear equation is of the form: y = mx + b   where

m is the slopeb is the y-intercept (where it crosses the y-axis)

x + 4y = 16

     4y = -x + 16

       [tex]y = -\dfrac{1}{4}x+\dfrac{16}{4}[/tex]

       [tex]y=-\dfrac{1}{4}x+4[/tex]

The y-intercept (b) = 4

Next, find the slope given point (4, 5) and b = 4

[tex]y=mx+b\\\\5=m(4)+4\\\\1=4m\\\\\dfrac{1}{4}=m\\\\\\\\\large\boxed{Slope (m)=\dfrac{1}{4}}[/tex]

8. Simple machines make a job easier to perform by
a. decreasing the amount of work
b. decreasing the amount of friction
c. decreasing the amount of force and/or changing the direction of force
d. only lower the amount of force

Answers

Answer:

C

Explanation:

a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg​

Answers

Answer:

-7500 N

Explanation:

v₀ = 108 km/h = 30 m/s

v = 0 m/s

t = 4 s

a = Δv / Δt

a = (0 m/s − 30 m/s) / 4 s

a = -7.5 m/s²

F = ma

F = (1000 kg) (-7.5 m/s²)

F = -7500 N

Answer:-7500

Explanation v₀ = 108 km/h = 30 m/s

v = 0 m/s

t = 4 s

a = Δv / Δt

a = (0 m/s − 30 m/s) / 4 s

a = -7.5 m/s²

F = ma

F = (1000 kg) (-7.5 m/s²)

F = -7500 N

Explain two applications of resonance

PLEASEEEE HELP ME! ​

Answers

Answer:

in physics, resonance is a phenomenon in which a vibrating system or external force drives another system to oscillate with greater amplitude at specific frequencies. example a familiar example is a playground swing, which acts as a pendulum.

hope this helped!

An object with more mass has more kinetic energy than an object with less
mass, if both objects are moving
OA) at the same speed
OB) in the same direction
OC) in opposite directions​

Answers

Explanation:

The kinetic energy of an object is given in terms of its mass and object as :

[tex]K=\dfrac{1}{2}mv^2[/tex]

An object with more mass has more kinetic energy. An object with less  mass, if both objects are moving at the same speed, in opposite directions, will have less kinetic energy. The square of v will give positive number.

When heat is converted into another form of energy, the total amount of energy is constant. Which law best illustrates this statement?
A.
the first law of thermodynamics
B.
the second law of thermodynamics
C.
the third law of thermodynamics
D.
none of the above

Answers

Answer:

A

Explanation:

This is the first law of thermodynamics and it's called the law of conservation of energy

Answer : A


explanation :



can there be shadows at night outside?

Answers

Answer:

To see a shadow there most be light provided, even if it's night and there are lights, we can still see the shadow but if there is no light, we can't.

Hope it helped (:

Answer: yes of course, but there should be some light to make or see shadows.

The atomic number of a nucleus decreases during which nuclear reactions?

A. Nuclear fission and alpha decay
B. Nuclear fusion and beta decay (positron emission)
C. Nuclear fission and beta decay (electron emission)
D. Nuclear fusion and alpha decay

Answers

The atomic number of a nucleus decreases during:

A. Nuclear fission and alpha decay

What happens in alpha decay?

Alpha decay is an atomic rot process where a shaky core changes to one more component by shooting out a molecule made out of 2 protons and 2 neutrons. This catapulted molecule is known as an alpha molecule and is just a helium core.

It changes or 'rots' into an alternate nuclear core, with a mass number that is decreased by four and a nuclear number that is diminished by two.

Thus, option A is correct.

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PLEASE HELP. Really important

Answers

Explanation:

2) C would need the least effort, because the longer the effort distance, the least the effort applied.

what is light rays ?​

Answers

Answer:

A light ray is a line (straight or curved) that is perpendicular to the light's wavefronts

Explanation:

Have a great day.

plzzzzzzz help me quick

Answers

Explanation:

in the first thing we are allowing bacteria to grow

in the second one we are killing it

A lonely child is swinging on a rusty old swing set, as seen in the image provided. If friction does 145 J of work slowing the swing, what is the maximum speed she can reach?

Answers

Answer:

2.331

Explanation:

It just the change of Energy from potential (PE) to kinetic (KE)

PE on A = PE on B + KE on B + friction works (Wf)

mg(ha) = mg(hb) + ½mv² + Wf

35 * 9.8 * 1.5 = 35 * 9.8 * 0.8 + ½ * 35 * v² + 145

514.5 = 274.4 + 17.5v² + 145

514.5 - 274.4 - 145 = 17.5v²

17v² = 95.1

v² = 5.434

v =√5.434 = 2.331 m/s

An escalator is used to move 25 passengers every minute from the first floor of a department store to the second. The second floor is located 5.30 meters above the first floor. The average passenger's mass is 60 kg. Determine the power requirement of the escalator in order to move this number of passengers in this amount of time.
Please help me quickly!

Answers

Answer:

1298.5watt

Explanation:

Power is defined as the rate at which work is done

Expressed mathematically as;

P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered

Hence for 1 person the power consumption is ;

Note weight =mass× acceleration of free fall due to gravity,g

g is known as 9.8m/S2

Time taken is 1min which is 60 sec

60 ×9.8 × 5.3/60 = 51.94 watt

Hence for 25 persons we have

25 × 51.94 =1298.5watt

1.3kilo watt( kilo is 1000)

The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

The Work Done is calculated as:

Force (F) = 60 × 9.8

Distance (d) = 5.30 meters

Work (W) = F × d

Work (W) = (60 × 9.8) × 5.30

Work (W) = 3,080.4 joules

The Power is calculated as:

Time (t) = 1 minute

Power (P) = Work / Tim (t)

Power (P) = 3,080.4 / 60

Power (P) = 51.34 watts

Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

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What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??

Answers

Answer:

F = 37.5 N

Explanation:

It is given that,

Mass of the object is 5 kg

Acceleration of the object is 7.5 m/s²

We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,

F = m

[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]

So, the force acting on the object is 37.5 N.    

Explain how series circuits use current and voltage and Explain how parallel circuits use current and voltage

Answers

'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''

Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is
132 m high. How many seconds does it take the ball to fall to the ground?

Answers

Answer:

t = 5.19 s

Explanation:

We have,

Height of the cliff is 132 m

It is required to find the time taken by the ball to fall to the ground. Let t is the time taken. So, using equation of kinematics as :

[tex]y=ut+\dfrac{1}{2}gt^2\\\\\text{since}\ u=0\\\\y=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y}{g}}\\\\t=\sqrt{\dfrac{2\times 132}{9.8}}\\\\t=5.19\ s[/tex]

So, it will take 5.19 seconds to fall to the ground.

what is the defination of temperature ​

Answers

Answer:

Temperature is a physical property of matter that quantitatively expresses hot and cold

Explanation:

Answer:

Temperature is the degree of hotness or coldness in a body

Explanation:

it is measured by the Average kinetic energy of the body. It is independent of the mass,it's measured in °C(Celsius),K(kelvin),°F(Fahrenheit)


A train starts from its station and it
velocity reaches 200m/s in 5
seconds. What is its acceleration?

a. 400m/s
b. 40m/s2
c. 4.5m/s2
d. Initial velocity is missing​

Answers

Answer:

b. 40m/s2

Explanation:

Acceleration is calculated by dividing velocity over time. Therefore 200m/s by 5s equals 40m/s2

Answer:

B

Explanation:

v = vo + at

200 = 0 + a*5

200 = 5a

a = 200/5 = 40 m/s²

initial velocity (vo) is 0 because it says it start from station

Help needed plz . Answer what you can. Thanx

Answers

Answer:

both a and b have same pressure

Benda setinggi 3 cm diletakkan pada jarak 10 cm di depan cermin cekung yang berjari-jari


kelengkungan 10 cm. Tentukan:


 Jarak bayangan


 Perbesaran bayangan


 Sifat bayangan

Answers

Answer:

a) Shadow distance

10 cm in front of the mirror.

b) Zoom in the shadow

The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.

c) The nature of the shadow

The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.

Explanation:

English Translation

Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:

a) Shadow distance

b) Zoom in the shadow

c) The nature of the shadow

Solution

The mirror equation is given as

(1/f) = (1/v) + (1/u)

f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm

v = image distance = ?

u = object distance = 10 cm

We can then calculate the shadow' s distance from the mirror thus

(1/5) = (1/v) + (1/10)

(1/v) = 0.2 - 0.1 = 0.1

v = (1/0.1) = 10 cm

b) Zoom in the shadow

Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.

c) The nature of the shadow

Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.

Hope this Helps!!!

Is there a link between number of bulbs and current drawn from the power pack?

Answers

Answer:

Yes, there a link between number of bulbs and current drawn from the power pack.

Explanation:

In an Electrical circuit, we have resistors present in that circuit. These resistors can be connected in two ways.

a) Series connection

b) Parallel connection

There is a link or a relationship between number of bulbs and the current drawn from the power pack. This is because the number of bulbs is equivalent to or equal to the number of resistors.

Hence,

a) In a series connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) decreases.

b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.

Un movil pasa por el punto A en direccion hacia B (350cm más adelante) y, luego, sigue hasta el punto C. Sabiendo que pasa por B a las 11:42:38 y por C a las 11:43:16, completando un tiempo total de recorrido de 3min 47s, calule la distancia entre B y C y a la hora a la que paso por el punto A.

Answers

Explanation:

PRIMERO HACES EL RECUENTO DEL TIEMPO Y LO CONVIERTES EN

SEGUNDOS Y ENTONCES

t = 227 s      [tex]t_{AB}[/tex] = 227 S - 38 s = 189 s

[tex]t_{BC}[/tex] = 38 s

LUEGO USANDO LA ECUACIÓN DE GALILEO GALILEI SSUPONIENDO

QUE EL MOVIL VIAJA A VELOCIDAD CONSTANTE

v = 3.50 m/189 s = 0.0185 m/s

PARA LA DISTANCIA NTRE B Y C

[tex]x_{BC}[/tex] = 0.0185 m/S( 38 s) = 0.703 m

LA HORA EN QUE EL MOVIL PASA POR A ES

11:43:15 - 38 s - 189 s = 11:39:29

Please explain it’s in the photo

Answers

Answer:

Since air resistance actually stops vehicles and goes in a vector opposite to the direction of the vehicle and slows it down. Vehicles would want to make vehicles aerodynamic. Many cars bump into air molecules therefore making air resistance. Aerodynamic cars will lesser the allowance of bumping into said molecules. Thats why cars like to cut down on air resistance

Air resistance is friction.  

-- Friction steals kinetic energy.

-- A car gets kinetic energy by burning gasoline, and uses the kinetic energy to get where it needs to go.  

-- If anything steals the car's kinetic energy, then the car has to burn more gasoline to get where it needs to go.

-- Gasoline costs money.

-- Anything that steals a car's kinetic energy costs you more money to operate the car.

(Another thing that takes kinetic energy away from the car is the car's brakes. The driver uses the brakes when he WANTS to slow down or stop, so it's not stealing, but it still costs kinetic energy and money.)

if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?

Answers

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

Answer is 9 V you use Ohm’s Law to solve the problem

When salt is added to the water what happens to the surface?

Answers

Answer:

it increases the surface tension of the water

Calcula el trabajo que realiza la fuerza de fregamiento sobre un cuerpo de 13kg que es desplaza una distáncia de 46 m si el coeficiente de fregamiento entre las superficies es de 0,45

Answers

Answer:

Los datos que tienes son:

m = 13 kg

d = 46 m

∪ = 0,45

g = 9,8 m/s²

Fr = ? 

w = ? 

Lo primero que haremos que calcular Fr

Fr = ∪mg

Fr = (0,45) (13 kg) (9,8 m/s²)

Fr = 57,33 N

Calculamos el trabajo realizado.

w = Fd

w = (57,33 N) (46 m)

w = 2637,18 Joules

Respuesta.

El trabajo realizado es 2637,18 Joules

Explanation:

A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.

Answers

Answer:

Yes, in case of uniform velocity

Explanation:

This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.

Since, acceleration is defined as the rate of change of velocity.

Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.

a = ΔV/t = 0/t

a = 0 m/s²

So, the acceleration of the body is 0 m/s², but it has a uniform velocity

Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.

Which statements best describe X-rays?

Answers

Answer:x rays are electromagnetic waves.

x rays are transverse waves

x rays travel at the speed of light

Explanation:

For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 24N acts on a certain object, the acceleration of the object is 3m/s^2. If the acceleration of the object becomes 10m/s^2, what is the force

Answers

Answer:

80 N

Explanation:

From the question,

F = ma .......................... Equation 1

Where F = Force, m = mass of the object, a = acceleration of the object.

make m the subject of the equation

m = F/a.................... Equation 2

Given: F = 24 N, a = 3 m/s²

Substitute into equation 2

m = 24/3

m = 8 kg.

If the acceleration of the object becomes 10 m/s²,

Substitute into equation 1

F = 10(8)

F = 80 N.

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