arrange the following electrons, represented by their quantum numbers, in increasing order of energy (lowest written first)

(1,0,0,-1/2); (3,1,1,1/2); (2,1,0,-1/2); (2,1,0,-1/2); (3,2,0,-1/2)

Answers

Answer 1

The electrons can be arranged in increasing order of energy as follows: (1,0,0,-1/2) < (2,1,0,-1/2) < (2,1,0,-1/2) < (3,1,1,1/2) < (3,2,0,-1/2).

The energy of an electron is determined by its principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m), and spin quantum number (s). The electrons can be arranged in increasing order of energy by comparing their quantum numbers.

Starting with the lowest energy electron, we have the electron with quantum numbers (1,0,0,-1/2). This electron has the lowest principal quantum number, indicating that it occupies the lowest energy level.

It also has an azimuthal quantum number of zero, which corresponds to the s subshell, and a negative spin quantum number, indicating that its spin is aligned opposite to the magnetic field.

Next, we have the two electrons with quantum numbers (2,1,0,-1/2). These electrons have the same principal quantum number, indicating that they occupy the same energy level.

They both have an azimuthal quantum number of one, which corresponds to the p subshell, and a negative spin quantum number.

Following these electrons, we have the electron with quantum numbers (3,1,1,1/2). This electron has a higher principal quantum number than the previous electrons, indicating that it occupies a higher energy level.

It has an azimuthal quantum number of one, which corresponds to the p subshell, and a positive spin quantum number.

Finally, we have the electron with quantum numbers (3,2,0,-1/2). This electron has the highest azimuthal quantum number of all the electrons, indicating that it occupies the d subshell. It also has a negative spin quantum number.

Therefore, the electrons can be arranged in increasing order of energy as follows: (1,0,0,-1/2) < (2,1,0,-1/2) < (2,1,0,-1/2) < (3,1,1,1/2) < (3,2,0,-1/2).

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Related Questions

How does the presence of coal in Antarctica support Wegener's continental drift hypothesis?

Answers

Answer:

Explanation:

Coal deposits have been found in Antarctica, particularly in the Transantarctic Mountains where they are interbedded in sedimentary rocks of the flat-lying Beacon Supergroup. The presence of coal in Antarctica supports Wegener's continental drift hypothesis because it suggests that Antarctica was once part of a larger landmass that had a warm climate suitable for the formation of coal. Coal is formed from ancient plant matter that has been compressed and heated over millions of years. The presence of coal in Antarctica suggests that the continent was once located closer to the equator and had a climate that supported lush vegetation.

A compound has the formula X2Fe(CN)6 ∙ 12H2O, where X is an unknown element.
If the compound is 45.34% water by mass, what is the identity of element X?

Answers

The identity of element X in the compound X2Fe(CN)6 · 12H2O is sodium (Na).

To find the identity of element X in the compound X2Fe(CN)6 · 12H2O, we can start by determining the molar mass of the compound.

The molar mass of X2Fe(CN)6 is:

2 × molar mass of X + molar mass of Fe + 6 × molar mass of C + 6 × molar mass of N

= 2 × atomic mass of X + atomic mass of Fe + 6 × 12.01 g/mol + 6 × 14.01 g/mol

= 2 × atomic mass of X + 55.85 g/mol + 432.72 g/mol + 84.06 g/mol

= 2 × atomic mass of X + 572.63 g/mol

The molar mass of 12H2O is:

12 × (atomic mass of H + atomic mass of O) = 12 × (1.01 g/mol + 16.00 g/mol) = 216.24 g/mol

The total molar mass of the compound is:

2 × atomic mass of X + 572.63 g/mol + 216.24 g/mol = 2 × atomic mass of X + 788.87 g/mol

Now we can use the given information that the compound is 45.34% water by mass. This means that the mass of water in the compound is 45.34% of the total mass of the compound, and the mass of the rest of the compound (X2Fe(CN)6) is 100% - 45.34% = 54.66% of the total mass of the compound.

Let's assume we have 100 g of the compound. Then the mass of water in the compound is:

45.34 g water = 0.4534 × 100 g compound

The mass of the rest of the compound (X2Fe(CN)6) is:

54.66 g rest of the compound = 0.5466 × 100 g compound

We can now use the mass of the rest of the compound (X2Fe(CN)6) to find the number of moles of the compound:

moles of X2Fe(CN)6 = (54.66 g) / (2 × atomic mass of X + 572.63 g/mol)

We can also use the mass of water to find the number of moles of water:

moles of H2O = (45.34 g) / 18.02 g/mol

Since the compound has 12 moles of water per mole of X2Fe(CN)6, we have:

moles of X2Fe(CN)6 = 1/12 × moles of H2O

We can now set these two expressions for moles of the compound equal to each other and solve for the atomic mass of X:

(54.66 g) / (2 × atomic mass of X + 572.63 g/mol) = 1/12 × (45.34 g) / 18.02 g/mol

Simplifying this equation and solving for the atomic mass of X gives:

atomic mass of X = 22.99 g/mol

The atomic mass of X is very close to the atomic mass of sodium (22.99 g/mol), so it is likely that X is sodium. Therefore, the identity of element X in the compound X2Fe(CN)6 · 12H2O is sodium (Na).

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Will we ever send humans to another planet? Most believe that if we were to travel to another planet, Mars would be the best option. Which of these would be a potential problem associated with travel to another planet?

Question 1 options:

we already know everything about Mars


no astronauts would ever volunteer for this mission


Mars has such a high gravity that it would crush humans and our spacecraft


the extended time for humans to be in space

Answers

A potential problem associated with travel to another planet is : the extended time for humans to be in space.

What is the potential problem associated with travel to another planet?

It is highly likely that humans will travel to another planet, and Mars is currently considered the most viable option for human exploration. However, there are many potential problems associated with this endeavor, and one of the major issues is the extended time that humans would need to spend in space.

Traveling to Mars would take several months, and once there, astronauts would need to spend significant amount of time on planet before returning to Earth. This means that they would be exposed to high levels of radiation and would need to find ways to survive in harsh and unforgiving environment.

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You have 20.7 grams of water at -25.34 °C. You want to warm it to 155.0 °C. Use the information below to calculate how much heat this will require.
Csolid = 2.09 J/(g·°C)
ΔHfus = 333 J/g
Cvapor = 2.03 J/(g·°C)
ΔHvap = 2260 J/g

Answers

Answer:

Cvapor = 2.03 J/(g·°C)heu

If the reaction A (aq) + B (aq) C(aq) has a Ka value equal to 4.26 x 10-6, what is the G value at 25 °C if the concentrations are as follows:

[A] = 1.50 M
[B] = 1.00 M
[C] = 5.00 x 10-5 M

Answers

The ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.

The relationship between ΔG and K is given by the following equation:

ΔG = -RTln(K)

where R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (25 °C = 298.15 K), and ln denotes the natural logarithm.

To calculate K, we need to use the equilibrium expression and the given concentrations:

[tex]K = [C]/([A][B])[/tex]

[tex]K = (5.00 * 10^{-5} M)/((1.50 M)(1.00 M))[/tex]

[tex]K = 3.33 x 10^{-5}[/tex]

Now we can substitute the values for R, T, and K into the equation for ΔG:

ΔG = -RTln(K)

ΔG = [tex]-(8.314 J/(mol.K))(298.15 K)ln(3.33 x 10^{-5})[/tex]

ΔG = -8.35 kJ/mol

Therefore, the ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.

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As the hour of her new job approached, Emma could feel her excitement blank

Answers

As the hour of her new job approached, Emma could feel her excitement peak.

What word can replace intensify ?

"Peak" is a synonym to "intensify" in this context because it means to reach the highest point or level of something. In the given passage, Emma's excitement is growing stronger and stronger as the time for her volunteer job approaches.

When her excitement "peaks," it means that it has reached the highest point of intensity, just like when something is intensified, it becomes stronger or more intense.

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What volume of oxygen gas can be collected
at 1.05 atm pressure and 44.0◦C when 42.5 g
of KClO3 decompose by heating, according to
the following equation?
2 KClO3(s) ∆
−−−−→
MnO2
2 KCl(s) + 3 O2(g)
Answer in units of L.
005 1.0 points

Answers

The volume of oxygen gas, O₂ collected at 1.05 atm pressure and 44.0 °C when 42.5 g of KClO₃ decomposed is 13.01 L

How do i determine the volume of oxygen gas collected?

We shall begin by obtaining the mole in 42.5 g of KClO₃. Details below:

Mass of KClO₃ = 42.5 g Molar mass of KClO₃ = 122.5 g/mol Mole of KClO₃ =?

Mole = mass / molar mass

Mole of CaC₂ = 42.5 / 122.5

Mole of CaC₂ = 0.35 mole

Next, we shall determine the mole of oxygen gas, O₂. produced. Details below:

2KClO₃ -> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produced 3 mole of O₂

Therefore,

0.35 mole of KClO₃ will decompose to produce = (0.35 × 3) / 2 = 0.525 mole O₂

Finally, we shall determine the volume of oxygen gas, O₂ collected. Details below:

Pressure (P) = 1.05 atmTemperature (T) = 44 °C = 44 + 273 = 317 KGas constant (R) = 0.0821 atm.L/mol KNumber of mole (n) = 0.525 moleVolume of gas (V) =?

PV = nRT

1.05 × V = 0.525 × 0.0821 × 317

Divide both sides by 1.05

V = (0.525 × 0.0821 × 317) / 1.05

Volume of oxygen gas = 13.01 L

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What is the chemical formula for the ionic compound barium iodide?

Answers

The chemical formula for the ionic compound barium iodide is [tex]BaI_2[/tex] .

Barium iodide is composed of one barium ion (Ba2+) and two iodide ions (I-), which together form a neutral compound. Barium iodide is a white crystalline solid with a high melting point and is soluble in water. It is commonly used in the manufacture of photographic paper and in the production of cathode ray tubes for televisions and computer monitors.

Barium iodide has a variety of other uses, including in medicine as a contrast agent for X-ray imaging and in the synthesis of organic compounds.

The compound has several different crystal structures, including hexagonal and cubic, and can be prepared by reacting barium carbonate with hydroiodic acid. Overall, barium iodide is an important and versatile compound with a range of practical applications.

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How many moles of solute are in 2 L of an 8.0 M solution?

Answers

Answer: 4 moles i think this is right im not sure

Explain why group 8 elements of the periodic table are referred to as group 0

Answers

Answer: They have eight outer electrons.

Explanation: They don't need any more electrons to be added to them and can't give out any electrons to other groups. They have a complete outer shell.

They used to be called group 8 because they have 8 electrons on their outer shell, but then they realised helium only has 2, so they renamed it to group 0. Also, they are called group 0 because they have zero reactivity, they cannot bond with other atoms.

The 500 cm³ of a pas enclosed in a container under a pressure of 580 mm of Hg. If the volume is reduced to 300 cm³ what will be the pressure then? ​

Answers

Answer:

The answer is 966.67 mm of Hg.

Explanation:

To solve this problem, we can use Boyle's Law which states that the pressure of a gas is inversely proportional to its volume when the temperature and the amount of gas are kept constant. The formula for Boyle's Law is:

P1V1 = P2V2

where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Using the given values:

P1 = 580 mmHg

V1 = 500 cm³

V2 = 300 cm³

We can solve for P2:

P1V1 = P2V2

580 mmHg x 500 cm³ = P2 x 300 cm³

290,000 mmHg·cm³ = P2 x 300 cm³

P2 = 290,000 mmHg·cm³ / 300 cm³

P2 = 966.67 mmHg (rounded to the nearest hundredth)

Therefore, the pressure when the volume is reduced to 300 cm³ is approximately 966.67 mmHg.

What amount of heat, in kJ, is required to vaporize 181.20 g of ethanol (C₂H₅OH)? (∆Hvap = 43.3 kJ/mol)

Answers

The amount of heat required to vaporize 181.20 g of ethanol would be 170.1 kJ.

Heat of vaporization

Using the formula:

Q = n ∆Hvap

where:

Q is the amount of heat required to vaporizen is the number of moles of the substance∆Hvap is the molar heat of vaporization.

Moles of 181.20 g of ethanol = 181.20 g / 46.07 g/mol = 3.933 mol

Substituting the values:

Q = 3.933 mol x 43.3 kJ/mol = 170.1 kJ

In other words, the amount of heat required to vaporize 181.20 g of ethanol is 170.1 kJ.

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2ch4 and c2h8 how are they different

Answers

Answer:

Explanation:

Both 2CH4 and C2H8 have the same number and kind of elements. But practically, 2CH4 will be existing but C2H8 cannot exist.

Haw many valance electrons in the following atoms.
O Na Sr

Answers

Answer:O has 6, Na has 1, and Sr has 2.

Explanation:

Complete combustion of a 0.0200 mol sample of a hydrocarbon, CxHy, gives 4.032 L of CO2 at STP and 3.602 g of H2O.
(a) What is the molecular formula of the hydrocarbon? (b) What is the empirical formula of the hydrocarbon?

Answers

The hydrocarbon's molecular structure is [tex]C_9H_20[/tex].The hydrocarbon's empirical formula is [tex]C_9[/tex]/4H5.

To solve this problem, we need to use stoichiometry to relate the amount of [tex]CO__2[/tex] and [tex]H_2O[/tex] produced to the amount of [tex]CxHy[/tex] burned.

(a) To find the molecular formula of the hydrocarbon, we need to first calculate the number of moles of [tex]CO__2[/tex] and [tex]H_2O[/tex] produced. From the ideal gas law, we know that 1 mole of gas at STP (standard temperature and pressure) occupies 22.4 L. Therefore, 4.032 L of [tex]CO__2[/tex] at STP corresponds to:

4.032 L / 22.4 L/mol = 0.180 mol [tex]CO__2[/tex]

Similarly, the mass of H2O produced corresponds to:
3.602 g / 18.02 g/mol = 0.200 mol [tex]H_2O[/tex]

Since the hydrocarbon undergoes complete combustion, it reacts with oxygen to form [tex]CO__2[/tex] and [tex]H_2O[/tex] according to the balanced chemical equation:

[tex]CxHy[/tex] + (x + (y/4))O2 → [tex]CO__2[/tex] + (y/2)[tex]H_2O[/tex]
where x and y are the coefficients of the balanced equation. We can use the stoichiometric ratios to set up two equations:

0.180 mol [tex]CO__2[/tex] = x mol [tex]CxHy[/tex] → x = 0.180 mol / 0.0200 mol = 9
0.200 mol [tex]H_2O[/tex] = (y/2) mol [tex]CxHy[/tex] → y = 0.400 mol / 0.0200 mol = 20

Therefore, the molecular formula of the hydrocarbon is [tex]C_9H_20[/tex].
(b) To find the empirical formula of the hydrocarbon, we need to divide the subscripts by their greatest common factor. In this case, both subscripts are divisible by 4, so we get:

[tex]C_9H_20[/tex] → C9/4H5
Therefore, the empirical formula of the hydrocarbon is C9/4H5.

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Dimensional analysis with shapes

Answers

The surface area of the rectangular prism is 0.034 square meters.

For a rectangular prism with length l, width w, and height h, the surface area is:

Surface area = 2lw + 2lh + 2wh

Substituting the given values, we get:

Surface area = 2(10 cm x 5 cm) + 2(10 cm x 8 cm) + 2(5 cm x 8 cm)

Surface area = 100 cm² + 160 cm² + 80 cm² = 340 cm²

We can use dimensional analysis. So the conversion factor is:

1 m² / 10,000 cm²

Multiplying the surface area by this conversion factor, we get:

Surface area = 340 cm² x (1 m² / 10,000 cm²)

Surface area = 0.034 m²

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--The complete Question is, What is the surface area of a rectangular prism that has a length of 10 cm, a width of 5 cm, and a height of 8 cm? Use dimensional analysis to convert the answer to square meters--

A 2.550×10−2 M glycerol solution (C3H8O3) in water is at 20.0 ∘C . The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.9 mL. The density of water at 20.0 ∘C is 0.9982 g/mL
a.) Calculate the molality of the glycerol solution
b.) Calculate the mole fraction of glycerol in this solution
c.) Calculate the concentration of the glycerol solution in percent by mass
d.) Calculate the concentration of the glycerol solution in parts per million by mass

Answers

The molality of the solution is 0.0256 m.

The mole fraction of glycerol is  0.00046

The percent by mass concentration of glycerol is 0.23%

The ppm concentration is 2300 ppm

What is the molality?

Molality is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent.

The formula for molality is:

molality = moles of solute / mass of solvent in kilograms

1) Density of water = mass/volume

Mass of water = Density * volume of water

Mass =[tex]0.9982 g/mL * 998.9 mL[/tex]

Mass =0.997 Kg of water

Number of moles of the glycerol =  [tex]2.550* 10^-2 M * 1 L[/tex]

= [tex]2.550*10^-2[/tex] moles

Molality of the solution = [tex]2.550*10^-2[/tex]  moles/0.997 Kg

= 0.0256 m

Number of moles of water = 998.9/18 g/mol

= 55.5 mole

Mole fraction of glycerol = [tex]2.550*10^-2[/tex] /[tex]2.550*10^-2[/tex]  + 55.5

= 0.00046

By percent by mass;

2.3/1001.2 * 100/1

= 0.23%

Mass of glycerol = 2.3 g

Volume of solution = 1 L

Thus we have concentration in ppm as;

[tex]2.3 * 10^3[/tex] mg/ 1 L =2300 ppm

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( + 0₂ (0₂ 1 Is the molecular mas of carbon is 12 and that of oxygen is 32, Calculate the mass of carbon dioxide formed when 24kg of carbon is burnt completely in oxygen and determine the heat thereby released in MJ if the complete combustion of 1kg of carbon releases 33.8MJ of heat​

Answers

The mass of carbon dioxide formed when 24 kg of carbon is burnt completely in oxygen is 88 kg, and the heat released is 811.2 MJ.

What is Molar Mass?

Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or formula unit of a compound. The molar mass is used in stoichiometry calculations to convert between mass and moles of a substance.

The balanced equation for the combustion of carbon is:

C + O₂ → CO₂

From the equation, we can see that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide. The molar mass of carbon dioxide is 12 + (2 × 16) = 44 g/mol.

First, let's find the number of moles of carbon in 24 kg:

n(C) = m/M = 24000 g / 12 g/mol = 2000 mol

Therefore, 2000 mol of CO₂ will be produced.

The mass of CO₂ produced can be calculated as:

m(CO₂) = n(CO₂) × M(CO₂) = 2000 mol × 44 g/mol = 88,000 g = 88 kg

Now, let's calculate the heat released during combustion:

Heat released = 33.8 MJ/kg × 24 kg = 811.2 MJ

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What is the minimum concentration of fluoride ions necessary to precipitate CaF2 from a 5.25 x 10-3 M solution of Ca(NO3)2? Ksp of CaF2 = 3.9 x 10-11

Answers

The minimum concentration of fluoride ions needed is 2.726 x 10⁻⁴ M.

How to solve

To find the minimum concentration of fluoride ions needed to precipitate CaF₂, we'll use the solubility product constant (Ksp) and the calcium ion concentration.

Ksp = [Ca²⁺][F⁻]²

Given: [Ca²⁺] = 5.25 x 10⁻³ M, Ksp = 3.9 x 10⁻¹¹

3.9 x 10⁻¹¹ = (5.25 x 10⁻³)[F⁻]²

Solve for [F⁻]:

[F⁻]² = (3.9 x 10⁻¹¹) / (5.25 x 10⁻³)

[F⁻]² = 7.4286 x 10⁻⁹

[F⁻] = 2.726 x 10⁻⁴ M

The minimum concentration of fluoride ions needed is 2.726 x 10⁻⁴ M.

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What mass (grams) of sodium sulfate would be formed by the complete reaction of 137.3 grams of sodium hydroxide?

NaOH + H2SO4 --> Na2SO4 + HOH

Answers

The mass of sodium sulfate [tex](Na_2SO_4)[/tex] formed by the complete reaction of 137.3 grams of sodium hydroxide [tex](NaOH)[/tex] is 486.74 grams.

The balanced chemical equation for the reaction between sodium hydroxide [tex](NaOH)[/tex] and sulfuric acid [tex](H_2SO_4)[/tex] is:

[tex]NaOH[/tex] + [tex](H_2SO_4)[/tex] → [tex]Na_2SO_4[/tex] + [tex]2H_2O[/tex]

From the balanced equation, we can see that 1 mole of [tex]NaOH[/tex] reacts with 1 mole of [tex](H_2SO_4)[/tex] to produce 1 mole of [tex]Na_2SO_4[/tex] and 2 moles of water [tex](H_2O).[/tex]

The molar mass of [tex]NaOH[/tex] is 40.00 g/mol, which means that 137.3 grams of [tex]NaOH[/tex] is equal to 137.3 g / 40.00 g/mol = 3.4325 moles of [tex]NaOH[/tex].

Since 1 mole of [tex]NaOH[/tex] reacts with 1 mole of [tex](H_2SO_4)[/tex] to produce 1 mole of [tex](Na_2SO_4)[/tex] , we can say that 3.4325 moles of [tex]NaOH[/tex] will react with 3.4325 moles of [tex]H_2SO_4[/tex] to produce 3.4325 moles of [tex]Na_2SO_4[/tex].

The molar mass of [tex](Na_2SO_4)[/tex] is 142.04 g/mol, which means that 1 mole of [tex](Na_2SO_4)[/tex] has a mass of 142.04 g.

Therefore, 3.4325 moles of [tex](Na_2SO_4)[/tex] has a mass of 3.4325 moles x 142.04 g/mol = 486.74 grams.

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Question 28
(1 mark)
Two other minerals can be seen in the photo:

galena, a dark grey mineral with the formula PbS

iron pyrite, a gold-coloured mineral with the formula FeS2

Compare their chemical formulas, by writing down one similarity and one difference between these two minerals.

Note: Pb = lead, Fe = iron, S = sulfur.




Question 29
(1 mark)
Wanting to create the beautiful golden colour of iron pyrite, FeS2, in the lab, a student mixes together black powdered iron (Fe) and yellow powdered sulfur (S). The result is a dull, yellowish grey powder. Propose why this attempt failed?




Question 30
(1 mark)
The student can vary the proportions of iron and sulfur by adding more of each powder to the mixture. Clarify why the same thing isn't true for the compound iron pyrite.

Answers

One similarity between the chemical formulas of galena and iron pyrite is that both minerals contain sulfur. One difference between the chemical formulas of galena and iron pyrite is that galena contains lead (Pb) while iron pyrite contains iron (Fe).

The reaction failed because it has a high activation energy.Pyrite is a compound while sulfur and iron are mere elements.

Compare the chemical structures of PbS and FeS2

PbS, sometimes referred to as galena, is made up of lead (Pb) and sulfur (S) atoms and has a straightforward structure. Each lead atom forms a tetrahedral link with four sulfur atoms, while each sulfur atom forms a covalent bond with two lead atoms.

Each sulfur atom forms an octahedral link with six iron atoms, while each iron atom forms a covalent bond with two sulfur atoms. FeS2's crystal structure is a cubic, tightly packed lattice.

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What is the family puzzle worksheet answer? Please make the pedigree and give me the answers

Answers

Interpreting Data:

Joshua's parents must be heterozygous carriers for cystic fibrosis (Nn).Bella's parents must be homozygous for the normal allele (NN).

How to analyze family pedigrees?

Predicting:

Joshua's brother has a 50% chance of being a carrier for cystic fibrosis (Nn) and a 50% chance of having the normal genotype (NN). This is because Joshua's parents are both carriers, so each of their children has a 50% chance of inheriting the recessive allele.

Communicating:

As a genetic counselor, information about many generations of a family is needed to draw conclusions about a hereditary condition because traits are passed down from generation to generation. By studying the family history, we can identify patterns of inheritance and determine the likelihood that a person has inherited a certain trait. This information can help us make informed decisions about genetic testing and treatment options.

Additionally, knowing the family history can help us determine the risk of passing on a genetic condition to future generations.

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Image transcribed and complete question:

Family Puzzle

Problem

A husband and wife want to understand the probability that their children might inherit cystic fibrosis. How can you use the information in the labeled Case Study to predict the probability?

Skills Focus

interpreting data, predicting

Materials

12 index cards

scissors marker

Procedure

1. Read the Case Study. In your notebook, draw a pedigree that shows all the family members. Use circles to represent the females, and squares to represent the males. Shade in the circles or squares representing the individuals who have cystic fibrosis.

2. You know that cystic fibrosis is controlled by a recessive allele. To help you figure out Joshua and Bella's family pattern, create a set of cards to represent the alleles. Cut each of six index cards into four smaller cards. On 12 of the small cards, write N to represent the dominant normal allele. On the other 12 small cards, write n for the recessive allele.

Case Study:

Joshua and Bella

• Joshua and Bella have a son named lan. lan has been diagnosed with cystic fibrosis.

⚫ Joshua and Bella are both healthy.

• Bella's parents are both healthy.

• Joshua's parents are both healthy. • Joshua's sister, Sara, has cystic fibrosis.

Analyze and Conclude

Write your answers in the spaces provided.

1. Interpreting Data What were the genotypes of Joshua's parents? What were the genotypes of Bella's parents?

2. Predicting Joshua also has a brother. What is the probability that he has cystic fibrosis? Explain.

3. Communicating Imagine that you are a genetic counselor. A couple asks why you need information about many generations of their families to draw conclusions about a hereditary condition. Write an explanation you can give to them.

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Review the pedigree that you just studied. What data suggest that the traits are not sex-linked? Explain.

If the reaction A (aq) + B (aq) C(aq) has a Ka value equal to 4.26 x 10-6, what is the G value at 25 °C if the concentrations are as follows:

[A] = 1.50 M
[B] = 1.00 M
[C] = 5.00 x 10-5 M

Answers

The Gibbs free energy change for the given reaction at 25°C and the given concentrations is -25.5 kJ/mol

The Gibbs free energy change (∆G) of a reaction can be calculated using the equation:

∆G = -RT ln(K)

Where R is the gas constant (8.314 J/molK), T is the temperature in Kelvin, and K is the equilibrium constant.

The equilibrium constant (K) can be calculated from the acid dissociation constant (Ka) as:

K = [C] ÷ ([A] × [B])

Substituting the given values, we get:

K = (5.00 x 10⁻⁵) ÷ (1.50 x 1.00) = 3.33 x 10⁻⁵

Therefore,

∆G = - (8.314 J/molK) × (298 K) × ln(3.33 x 10⁻⁵)

= 25.5 kJ/mol

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Calculate the energy difference (deltaE, in Joules) of an electron's transition from n = 6 to n = 1 in a hydrogen atom.

Answers

The energy difference of an electron's transition from n = 6 to n = 1 in a hydrogen atom is approximately -2.17 × 10⁻¹⁸ Joules.

To calculate the energy difference (deltaE) of an electron's transition from n = 6 to n = 1 in a hydrogen atom, we can use the following equation:

deltaE = -13.6 * (1/n_final^2 - 1/n_initial^2) eV
where n_initial is the initial energy level (6 in this case), n_final is the final energy level (1 in this case), and -13.6 eV is the ionization energy of hydrogen.

Converting eV to Joules, we get:
1 eV = 1.602 x 10^-19 J
Therefore, deltaE in Joules can be calculated as follows:
deltaE = -13.6 * (1/1^2 - 1/6^2) * 1.602 x 10^-19 J/eV
deltaE = -2.179 x 10^-18 J

Therefore, the energy difference (deltaE) of an electron's transition from n = 6 to n = 1 in a hydrogen atom is -2.179 x 10^-18 J.

To calculate the energy difference (ΔE) for an electron's transition from n = 6 to n = 1 in a hydrogen atom, you can use the following formula:
ΔE = -13.6 eV * (1/nf² - 1/ni²)

Where ΔE is the energy difference in electron volts (eV), nf is the final energy level (1 in this case), and ni is the initial energy level (6 in this case).
ΔE = -13.6 eV * (1/1² - 1/6²)
ΔE ≈ -13.56 eV

Now convert electron volts to Joules:
1 eV = 1.6 × 10⁻¹⁹ J
ΔE ≈ -13.56 eV * 1.6 × 10⁻¹⁹ J/eV
ΔE ≈ -2.17 × 10⁻¹⁸ J

So,  approximately -2.17 × 10⁻¹⁸ Joules is  the energy difference of an electron's transition from n = 6 to n = 1 in a hydrogen atom.

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* For all 3 trials find the moles of KHC8H4O4 using the grams of KHC8H4O4. Show all work!
* Use the mole ratio from question 1 to find the moles of NaOH used. Remember, in a 1:1 ratio if we use 1 mole of KHC8H4O4, then we use 1 mole of NaOH. Record the moles of NaOH used in each trial below.

Trial 1 ________________
Trial 2 ________________
Trial 3 ________________

Answers

At equivalence point, the reaction is seen to consume approximately 0.0024973 moles of KHP and then 0.0024973 moles of  NaOH

How to calculate the mole ratio?

The primary aim in this problem is to standardize a solution of the sodium hydroxide, NaOH, with the aid of potassium hydrogen phthalate, KHP.

The beginning point in this problem is the balanced chemical equation with respect to this neutralization reaction

KHP (aq] + NaOH(aq] → KNaP(aq] + H₂O(l]

The important thing that we are going to observe is that there is a ratio of 1:1 mole ratio between the two reactants. This suggests to us that the equivalence point can be attained by getting equal number of moles of  KHP and of NaOH to react with each other.

We will begin with 0.5100 g of KHP. To obtain the molar amount of acid utilized for the experiment, we will make use of its molar mass of 0.5100g⋅

molar mass of KHP

1 mole KHP 204.22g = 0.0024973 moles KHP

Thus, at equivalence point, the reaction is seen to consume approximately 0.0024973 moles of KHP and then 0.0024973 moles of  NaOH, due to the fact that it's what the  1:1 mole ratio suggests to us.

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Write the electronic configuration of all the metal ions in the d-blocks (3d series)​

Answers

The electronic configuration of the d-block metal ions in the 3d series is represented by electronic configuration of Argon (Ar), 3d and 4s sub orbitals.

What is the electronic configuration of all d block?

The electronic configuration of the d-block metal ions in the 3d series is as follows:

Scandium (Sc): [Ar] 3d¹ 4s²

Titanium (Ti): [Ar] 3d² 4s²

Vanadium (V): [Ar] 3d³ 4s²

Chromium (Cr): [Ar] 3d⁵ 4s¹

Manganese (Mn): [Ar] 3d⁵ 4s²

Iron (Fe): [Ar] 3d⁶ 4s²

Cobalt (Co): [Ar] 3d⁷ 4s²

Nickel (Ni): [Ar] 3d⁸ 4s²

Copper (Cu): [Ar] 3d¹⁰ 4s¹

Zinc (Zn): [Ar] 3d¹⁰ 4s²

Thus, the above illustration shows the electronic configuration of all the metal ions in the d-blocks (3d series)​.

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A sample of an ideal gas has a volume of 2.31 L
at 279 K
and 1.01 atm.
Calculate the pressure when the volume is 1.09 L
and the temperature is 308 K.

Answers

We can use the combined gas law to determine the pressure of the gas at the final state. The combined gas law relates the pressure, volume, and temperature of a gas:

(P1 x V1) / T1 = (P2 x V2) / T2

where P1, V1, and T1 are the pressure, volume, and temperature of the gas at the initial state, and P2, V2, and T2 are the pressure, volume, and temperature of the gas at the final state.

We are given the initial pressure (P1 = 1.01 atm), volume (V1 = 2.31 L), and temperature (T1 = 279 K) of the gas, and the final volume (V2 = 1.09 L), and temperature (T2 = 308 K) of the gas. We can solve for P2, the final pressure of the gas:

(P1 x V1) / T1 = (P2 x V2) / T2

P2 = (P1 x V1 x T2) / (V2 x T1)

P2 = (1.01 atm x 2.31 L x 308 K) / (1.09 L x 279 K)

P2 = 2.41 atm (rounded to three significant figures)

Therefore, the pressure of the gas when the volume is 1.09 L and the temperature is 308 K is approximately 2.41 atm.

A 0.4 kg piece of ice at -10 ∘C is dropped from a height h. Upon impact, 3.0 % of its kinetic energy is converted into heat energy. If the impact transforms all of the ice into water that has a final temperature of 0 ∘C , find h .

Answers

The height of fall of the ice is determined as 313.25 m.

What is the heat energy of the ice?

The total heat energy of the ice during the fall is calculated as follows;

Q = ml + mcΔT

where;

c is the specific heat of waterl is latent heat of fusionΔT is change in temperature

Q = 334000 x 0.4  +  0.4 x 4200 x (10)

Q = 150,400 J

The energy converted into potential energy is calculated as;

3%K.E = 150,400 J

0.03K.E = 150,400 J

K.E = 5,013,333.33 J

¹/₂mv² = 5,013,333.33 J

v = √(2 x 5,013,333.33)/(0.4)

v = 5,006.67 m/s

The height of fall is calculated as;

h = √2gh

h = √(2 x 5,006.67 x 9.8)

h = 313.25 m

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How does the frequency of a string affect its wavelength?

Answers

Answer:

as the frequency goes down, the speed goes down by the same factor, and so the wavelength doesn't change.

Explanation:

Answer: as the frequency goes down, the speed goes down by the same factor, and so the wavelength doesn't change.

Explanation:

a solution is made by mixing 100 ml of ethanol and 200 mL of water identified the solute of solvent of the solution and calculate the total volume of the solution​​

Answers

The solution has a total volume of 300 mL and is composed of 100 mL of ethanol (the solute) and 200 mL of water (the solvent).

Does a solution form when 50 mL of ethanol and 50 mL of water are combined?

Less than 100 ml will result from mixing 50 ml each of ethanol and water in an equal ratio. This happens because ethanol molecules, which are smaller than those of water, may fit inside big water molecules. As a result, the alcohol content in a 250 mL mix of water and alcohol is 60%.

The combined volumes of the ethanol and water make up the total volume of the solution, which is:

Total volume = 100 mL + 200 mL = 300 mL

Therefore, the solution is made up of 100 mL of ethanol (the solute) and 200 mL of water (the solvent), with a total volume of 300 mL.

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