Are any of the forces acting on the freezer
unbalanced?

Answer:

A statement about you

Explanation:

Answer:

Personification is when you give an animal or object qualities or abilities that only a human can have. This creative literary tool adds interest and fun to poems or stories. Personification is what writers use to bring non-human things to life. It helps us better understand the writer's message.

Explanation:

Answer:

2.22m/s to the left

Explanation:

Given parameters:

Initial position = +125m

Final position  = -75m

Motion time  = 90s

Unknown:

Velocity of the steel ball  = ?

Solution:

The velocity of the steel ball is given as the displacement divided by the time;

   Velocity  = [tex]\frac{displacement}{time}[/tex]

The net displacement of the ball  = 125- (-75) = 200m to the left

Input the parameters and solve for the velocity;

     Velocity  = [tex]\frac{200}{90}[/tex]   = 2.22m/s to the left

Explanation:

According to newton's second law of motion.

[tex]\sum Fx = ma\\\\\sum Fx = 1061 - 915\\\\\sum Fx = 146N[/tex]

m is the mas of the sky diver = 93.4kg

a is the acceleration of the skydiver

From the formula above;

[tex]a = \frac{\sum Fx}{m}\\ \\a = \frac{146}{93.4}\\\\a = 1.563m/s^2[/tex]

Hence the acceleration of the sky diver is 1.563m/s²

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

Answer:

slower speeds = larger and faster steering wheel movements

faster speeds = small and slow steering wheel movements

Explanation:

When driving at slower speeds you need to use larger and faster steering wheel movements. This is because at slow speeds the car does not have enough momentum to make certain maneuvers with small steering wheel movements in a given amount of time, therefore making large and faster steering wheel movements gives the car enough time with the momentum it has to make the desired maneuver. At faster speeds only small and slow steering wheel movements are needed and while cause the car to quickly change to the desired direction due to the increased momentum of the car.

Answer:

The spring constant is 3.44x10⁶ kg/s².

Explanation:

We cand find the spring constant by conservation of energy:

[tex] E_{i} = E_{f} [/tex]

[tex] mgh = \frac{1}{2}kx^{2} [/tex]   (1)

Where:

m is the mass =  41700 kg

g is the gravity = 9.81 m/s²

h is the height = 2.65 m

x is the distance of spring compression = 79.4 cm

k is the spring constant =?

Solving equation (1) for k:

[tex]k = \frac{2mgh}{x^{2}} = \frac{2*41700 kg*9.81 m/s^{2}*2.65 m}{(0.794 m)^{2}} = 3.44 \cdot 10^{6} kg/s^{2}[/tex]              

Therefore, the spring constant is 3.44x10⁶ kg/s².

I hope it helps you!

Answer:

A) T1 = 269.63 K

T2 = 192.59 K

B) W = -320 KJ

Explanation:

We are given;

Initial volume: V1 = 7 m³

Final Volume; V2 = 5 m³

Constant Pressure; P = 160 KPa

Mass; m = 2 kg

To find the initial and final temperatures, we will use the ideal gas formula;

T = PV/mR

Where R is gas constant of helium = R = 2.0769 kPa.m/kg

Thus;

Initial temperature; T1 = (160 × 7)/(2 × 2.0769) = 269.63 K

Final temperature; T2 = (160 × 5)/(2 × 2.0769) = 192.59 K

B) world one is given by the formula;

W = P(V2 - V1)

W = 160(5 - 7)

W = -320 KJ

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

[tex]M_{before} = M_{after}[/tex]

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

[tex](m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})[/tex]

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

Answer:

A. 1.4 m/s to the left

Explanation:

Answer:

The correct answer is (a)

Explanation:

A spring scale measures the weight of an object not the mass because according to hooke's law the extension of a spring is directly proportional to the load or force attached/applied to it. The force of gravity acting on the mass of any substance as it goes up actually reduces and increases as it comes down.

If F = ma, as a increases, F will also increase and vice versa

Where F = force

m = mass

a = acceleration (due to gravity in this case)

From the above explanation, it can be deduced that the scale will read more than mg as it gets to the ground because of an increase in the force of gravity (which also increases a) as it approaches the ground.

Answer:

K.E of the Astronaut is greater

Explanation:

Mathematically;

K.E = 1/2 * m * v^2

For the truck, the kinetic energy will be

1/2 * 21,000 * 130^2 = 177,450,000 J

while for the astronaut, his K.E will be

1/2 * 84 * 28,000^2 = 3.2928 * 10^10

This shows that the K.E of the astronaut is greater

Answer:

Displacement is 5√2 miles

Explanation:

From south, Scott travelled 2 miles north and then 5 miles west then he came back south by 7 miles.

I've attached a diagram to indicate Scott's path travelled

Now, displacement is a vector quantity that tells us the overall change in position by Scott i.e distance from his initial position to his current final position while distance is a scalar quantity and tells us how much ground Scott covered in his motion over the entire trip.

Now, from the attached image, the displacement is denoted by "d".

d can be found from pythagoras theorem.

Thus;

d² = 5² + 5²

d = √50

d = 5√2 miles

Explanation:

Given two capacitors 7.0 µF and 5.0 µF connected in series, let s calculate the effective capacitance.

[tex]\frac{1}{C_T} = \frac{1}{7.0} +\frac{1}{5.0}\\ \frac{1}{C_T} = \frac{5+7}{35} \\C_T = \frac{35}{12}\\ C_T = 2.9166\mu F[/tex]

Given

V = 5.0kV = 5000Volts

To get the total charge in the circuit, we will use the formula:

[tex]Q = C_TV\\Q = 2.9166\times 10^{-6} \times 5000\\Q = 0.014583 C\\Q = 1.4583 \times 10^{-2}C[/tex]

Since the same charge flows in a series connected capacitors, the charge on them in mC is 14.583mC

For the voltage across 7.0 µF:

[tex]V = \frac{Q}{C}\\V = \frac{0.014583}{0.000007} \\V = 2,083.28V[/tex]

Voltage across the 7.0 µF is 2,083.28V

The voltage across the  5.0 µF:

V = 5000 - 2,083.28

V = 2,916.72Volts

Voltage across the  5.0 µF is 2,916.72V

Answer:

The charge on the first capacitor is 14.59 mC

The voltage across the first capacitor is 2084 V

The charge on the second capacitor is 14.59 mC

The voltage across the second capacitor is 2918 V

Explanation:

Given;

first capacitor, C₁ = 7.0 µF

second capacitor, C₂ = 5.0 µF

potential difference, V = 5000 V

The equivalent capacitance is given by;

[tex]\frac{1}{C_{eq}}= \frac{1}{C_1} +\frac{1}{C_2}\\\\\frac{1}{C_{eq}}= \frac{C_1 + C_2}{C_1C_2}\\\\C_{eq} = \frac{C_1C_2}{C_1 +C_2}\\\\ C_{eq} = \frac{(7*10^{-6})(5*10^{-6})}{(7*10^{-6} \ +\ 5*10^{-6})}\\\\C_{eq} = 2.917*10^{-6} \ F[/tex]

The charge on the first capacitor is given by;

[tex]Q_1 = C_{eq} V\\\\Q_1 = 2.917*10^{-6} *5000\\\\Q_1 = 0.01459 \ C\\\\Q_1 = 14.59 \ mC[/tex]

The voltage across the first capacitor is given by;

[tex]V_1 = \frac{Q_1}{C_1} \\\\V_1 = \frac{0.01459}{7*10^{-6}}\\\\ V_1 = 2084.286 \ V[/tex]

V₁ = 2084 V

The charge on the second capacitor is given by;

[tex]Q_2 = C_{eq} V\\\\Q_2 = 2.917*10^{-6} *5000\\\\Q_2 = 0.01459 \ C\\\\Q_2 = 14.59 \ mC[/tex]

The voltage across the second capacitor is given by;

[tex]V_2 = \frac{Q_2}{C_2}\\\\ V_2 = \frac{0.01459}{5*10^{-6}}\\\\V_2 = 2918 \ V[/tex]

Answer:

T = D/S

Explanation:

Given the formula for calculating the average speed of an object as:

average speed = Distance/Time

Let average speed = S

Distance = D

Time = T

Substitute

S = D/T

Make T the subject of the formula:

From S = D/T

Cross multiply

ST = D

Divide both sides by S

ST/S = D/S

T = D/S

Hence the expression for he time T after rearrangement is T = D/S

Answer: B. The gravitational field strength of Planet X is Wx/m.

Explanation:

Weight is a force, and as we know by the second Newton's law:

F = m*a

Force equals mass times acceleration.

Then if the weight is:

Wx, and the mass is m, we have the equation:

Wx = m*a

Where in this case, a is the gravitational field strength.

Then, isolating a in that equation we get:

Wx/m = a

Then the correct option is:

B. The gravitational field strength of Planet X is Wx/m.

Answer:

a) The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.

b) The force of repulsion between two people is [tex]13.851\times 10^{6}[/tex] newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.

Explanation:

a) From Second Newton's Law, we form this equation of equilibrium:

[tex]\Sigma F = F_{E}-W = 0[/tex] (Eq. 1)

Where:

[tex]F_{E}[/tex] - Electrostatic force exerted on human, measured in Newton.

[tex]W[/tex] - Weight of the human, measured in Newton.

If we consider that human can be represented as a particle and make use of definitions of electric field and weight, the previous equation is expanded and electric charge is cleared afterwards:

[tex]q\cdot E-m\cdot g = 0[/tex]

[tex]q = \frac{m\cdot g}{E}[/tex] (Eq. 2)

[tex]E[/tex] - Electric field, measured in Newtons per Coloumb.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravity acceleration, measured in meters per square second.

[tex]q[/tex] - Electric charge, measured in Coulomb.

As electric field of the Earth is directed in toward the center of the planet, that is, in the same direction of gravity, electric field must be a negative value. If we know that [tex]m = 60\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]E = -150\,\frac{N}{C}[/tex], the charge that a 60-kg human must have to overcome weight is:

[tex]q = \frac{(60\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{-150\,\frac{N}{C} }[/tex]

[tex]q = -3.923\,C[/tex]

The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.

b) The electric force of repulsion between two people with the same charge calculated in part (a) is determined by Coulomb's Law, whose definition we proceed to use:

[tex]F = \kappa \cdot \frac{q^{2}}{r^{2}}[/tex] (Eq. 3)

Where:

[tex]\kappa[/tex] - Electrostatic constant, measured in Newton-square meter per square Coulomb.

[tex]q[/tex] - Electric charge, measured in Coulomb.

[tex]r[/tex] - Distance between two people, measured in meters.

If we know that [tex]\kappa = 9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q = -3.923\,C[/tex] and [tex]r = 100\,m[/tex], then the force of repulsion between two people is:

[tex]F = \left(9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right)\cdot \left[\frac{(-3.923\,C)^{2}}{(100\,m)^{2}} \right][/tex]

[tex]F = 13.851\times 10^{6}\,N[/tex]

The force of repulsion between two people is [tex]13.851\times 10^{6}[/tex] newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.

Answer:

yeah

Explanation:

Geology. a basic law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it.

Answer:

Found this answer off of google, "Geology. a basic law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it."

Hope this helps, have a great day and stay safe!

Also Happy Halloween! :) :D :3

Answer:

Blood is moved away from the brain

Explanation:

Took the test

Answer:

hello your question is incomplete attached below is missing part of the question

answer:

1 )  Magnetic field due to long current carrying wire : [tex]B = \frac{U_{0} I}{2\pi d}[/tex]

Therefore the net magnetic field due the both wires ; B = B[tex]_{1}[/tex] + B[tex]_{2}[/tex] . when we adjust the current I[tex]_{1}[/tex] = I[tex]_{2}[/tex] then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

[tex]F = \frac{U_{0}I_{1}I_{2} }{2\pi d }[/tex]

Explanation:

1 )  Magnetic field due to long current carrying wire : [tex]B = \frac{U_{0} I}{2\pi d}[/tex]

Therefore the net magnetic field due the both wires ; B = B[tex]_{1}[/tex] + B[tex]_{2}[/tex] . when we adjust the current I[tex]_{1}[/tex] = I[tex]_{2}[/tex] then the Netfield (B ) = zero

2) The distance between the field lines are not equally spaced and this is because the separation between field lines increases with the increase in the distance between the wires

3) Increase in current through the wire will lead to increase in force and this can be explained via this equation

[tex]F = \frac{U_{0}I_{1}I_{2} }{2\pi d }[/tex]

Answer: I only know that the skater riding down the ramp increeses it's kinetic energy.

Explanation:

Answer:

III) [tex]d_{1}+ d_{2}=d_{t}[/tex]

Explanation:

I) coordinate (0,5) is the head for [tex]d_{1}[/tex] I will put the tail coordinate as (0,0) but it could be any other number in the x just not in the 5  with the the y being any other value.

II) coordinate (5,5) is the head for [tex]d_{2}[/tex] the tail needs to be in the head of [tex]d_{1}[/tex] being (0,5)

III) coordinates for [tex]d_{t}[/tex] is connecting the tail from [tex]d_{1}[/tex] and the head of [tex]d_{2}[/tex] making it (0,0)[tex](tail)[/tex] and (0,5)[tex](head)[/tex] and is written as [tex]d_{1}+ d_{2}=d_{t}[/tex]

(i) using coordinate grid notation to represent d₁, d₁ = 5y

(ii) using coordinate grid notation  to represent d₂, d₂ = 5x + 5y

(ii) The sum of d₁ and d₂ is written as 5x + 10y

In order to show the horizontal direction of a vector, we will place x after the magnitude of the vector.

Also, to show the vertical direction of a vector, we will place a y after the magnitude of the vector.

(i) Using coordinate grid to represent d₁ = (0, 5)

[tex]d_1 = 0(x) + 5(y)\\\\d_1 = 5y[/tex]

(ii) Using coordinate grid to represent d₂ = (5, 5)

[tex]d_2 = 5x + 5y[/tex]

(iii) The total vector is written as;

[tex]d_1 + d_2 = 5y + (5x + 5y)\\\\d_1 + d_2 = 5y + 5x + 5y\\\\d_1 + d_2 = 5x + 10y[/tex]

Learn more here: https://brainly.com/question/17212749

Answer:

2, 3, 4, 1

Explanation:

geosphere, hydrosphere, biosphere, and atmosphere

Answer:

Lithosphere hydrosphere biosphere atmosphere

Explanation:

So yea mark me brainliest

Answer:

Answer and steps in the pic

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) = [tex]\frac{g}{7}[/tex]

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T = [tex]\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2[/tex]

T = [tex]4mx^2 + 2my^2 -2mxy[/tex]  

also the general potential energy can be expressed as

U = [tex]-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant[/tex]

The Lagrangian of the problem can now be setup as

[tex]L =4mx^2 +2my^2 -2mxy +2mgy + constant[/tex]

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange  equation = [tex]4x-y =0\\-2y+x +g = 0[/tex]

solving the equations simultaneously

x ( acceleration of mass 4m ) = [tex]\frac{g}{7}[/tex]

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

This question involves the concept of semi-projectile motion. It can be solved using the equations of motion in the horizontal and the vertical motion.

The bullet drops "2.76 m" by the time it reaches the target.

First, we will analyze the horizontal motion. We assume no air resistance, so the horizontal motion will be uniform. Hence, using the equation of uniform motion here to find the total time to reach the target:

[tex]s = vt\\\\t = \frac{s}{v}[/tex]

where,

s = distance = 75 m

v = velocity = 100 m/s

t = time = ?

Therefore,

[tex]t = \frac{75\ m}{100\ m/s}[/tex]

t = 0.75 s

Now, we will analyze the vertical motion of the bullet. We will use the second equation of motion in the vertical direction to find the height dropped by the bullet.

[tex]h = v_it+\frac{1}{2}gt^2[/tex]

where,  

h = height dropped = ?  

vi = initial vertical speed = 0 m/s

t = time interval = 0.75 s  

g = acceleration due to gravity = 9.81 m/s²

therefore,

[tex]h = (0\ m/s)(0.75\ s)+\frac{1}{2}(9.81\ m/s^2)(0.75\ s)^2[/tex]

h = 2.76 m

Learn more about equations of motion here:  

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

Answer:

a. resin and turpentine

Explanation:

The chemicals that diverged from trees are resin and turpentine.

Resin are produced by special cells in trees, most times we see them when a tree is damaged or cut. They are usually derived from pines and firs.

Turpentine is obtained by distilling resin.

 Turpentine has an antiseptic property that has different uses. They are used as cleansing agents and for producing sanitary materials.

Answer:

The acceleration is [tex] a =  17.083 \ m/s^2 [/tex]

Explanation:

From the question we are told that

   The force is [tex]F =  41 \  N[/tex]

     The mass of the object is [tex]m  =  2.4 \  kg[/tex]

Generally the force is mathematically represented as

        [tex]F  =  m*  a[/tex]

=>      [tex] 41  = 2.4*  a[/tex]

=>      [tex] a =  17.083 \ m/s^2 [/tex]