answer pls urgent pls​

From a flying plane a body should dropped in advance to hit the target,Why? ... The body should be dropped in advance as when the body is dropped it has the velocity of the plane. So, in air the body moves forward which we have to take into consideration in order to hit the target.

Answer:

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Explanation:

hope it will helps u

Answer: 5cm

Explanation:

Answer:

Th average force impact is [tex]F = 168.298 \ N[/tex]

Explanation:

From the question we are told that  

   The mass of the golf ball is  [tex]m_g = 26.7 \ g = 0.0267 \ kg[/tex]

    The angle made is [tex]\theta = 33.6 ^o[/tex]

    The range of the golf ball  is [tex]R = 190 \ m[/tex]

     The duration of contact is [tex]\Delta t = 7.13 \ ms = 7.13 *10^{-3} \ s[/tex]

Generally the range of the golf ball is mathematically represented as

       [tex]R = \frac{v^2 sin2(\theta)}{g}[/tex]

Here v  is the velocity with which the golf club propelled it with, making  v the subject

       [tex]v = \sqrt{\frac{R * g}{sin 2 (\theta)} }[/tex]

=>     [tex]v = \sqrt{\frac{190 * 9.8}{sin 2 (33.6)} }[/tex]

=>     [tex]v = 44.94 \ m/s[/tex]

Generally the change in momentum of the golf ball is mathematically represented as

      [tex]\Delta p = m * (v - u )[/tex]

here u  is the initial  velocity of the ball before being stroked and the value is 0 m/s

       [tex]\Delta p = 0.0267 * ( 44.94 - 0 )[/tex]

=>    [tex]\Delta p = 1.19996 \ kg \cdot m/s[/tex]

Generally the  average force of impact is mathematically represented as      

         [tex]F = \frac{\Delta p }{\Delta t}[/tex]

=>        [tex]F = \frac{1.19996 }{7.13 *10^{-3}}[/tex]

=>        [tex]F = 168.298 \ N[/tex]

Answer:

–1652 N. The negative sign indicate that the force is in opposite direction to car.

Explanation:

The following data were obtained from the question:

Mass (m) of car = 1400 kg

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Force (F) applied on the car =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Acceleration (a) =?

a = (v – u) /t

a = (12 – 25) /11

a = –13/11

a = –1.18 m/s²

Finally, we shall determine the force on the car as follow:

Acceleration (a) = –1.18 m/s²

Mass (m) of car = 1400 kg

Force (F) applied on the car =?

F = ma

F = 1400 × –1.18

F = –1652 N

Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.

Answer:

D- Z, X, Y, W

Explanation:

Correct on edge

Answer:

C

Explanation:

There's a reason newton's 3rd law is called action-reaction :D

A - 1st law/inertia

B - 2nd law/f=ma

Newton's third law of motion states that for each action there is an equal and opposite reaction or force. Thus, the correct option is C.

Newton's third law of motion states that for every action or force applied in nature there is an equal and opposite reaction or force.

According to Newton's third law of Motion, if an object A exerts a force on the object B, then the object B must exert a force which is of equal magnitude and opposite direction back on the object A. This law represents symmetry in nature with the forces which are always occur in pairs, and one body cannot exert a force which is on another object without experiencing a force itself.

Therefore, the correct option is C.

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Answer:

A for sure

Explanation:

I feel like I'm in a city

Answer:

0.03 cm

Explanation: If the scale is 500:1, you have to divide 500 by 15 to get 0.03. You do not multiply 500 times 15 because the cells are smaller than the scale representation so you divide.

Answer:

4.356e-6 Newtons

Explanation:

Using the equation for the force of gravity F=[tex]\frac{Gm_1m_2}{r^2}[/tex]. The two masses are m1=800kg and m2=1000 kg. The value of G, the gravitational constant =6.67e-11. The problem states the distance between the center of masses of the two cars is 3.5 meters(r). Plugging in what we have from the problem, you will get 4.346e-6 newtons. This makes sense as gravity in itself is a weak force requiring extremely massive objects to result in a noticeable force.

Answer:

is used to display images

Explanation:

Explanation:

Momentum is conserved when there is no net external force.  So momentum is conserved in the direction parallel to the incline.

p₀ = p

m v cos θ = (m + M) vₓ

vₓ = m v cos θ / (m + M)

After the collision, energy is conserved.

PE = KE

(m+M) gh = ½ (m+M) vₓ²

gh = ½ vₓ²

h = vₓ² / (2g)

d sin θ = [m v cos θ / (m + M)]² / (2g)

d = [m v cos θ / (m + M)]² / (2g sin θ)

Answer:

b

Explanation:

i took the test

Earth’s landmasses were first recognized as the continents we know today

135 million years ago.

Landmass is defines as a large area of land. It can also be referred to as the

continents we have today. There are seven types of earth landmasses and

they are

They were first discovered around 135 million years ago by the early

dwellers of the earth.

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Answer:

B is correct

Explanation:

Maximum Kinetic energy= Work done.

Now, Work done=mgh=mg(L−Lcosθ)=mgL(1−cosθ)

Option B is thus correct.

Answer:

because of glass' higher refractive index

Explanation:

air and vacuum have a lower refractive index and are optically lighter, so light travels faster.

whereas glass has a higher optical density, so light travels slower

The discovery of fossils remains of Cynognathus at both South America And Africa suggests that these continents used to be connected and later moved apart.

According to continental drift theory:

"All of the continents were once together as a single continent named Pangaea, which was surrounded by a Mega Ocean known as Panthalassa."

The continental drift theory was first proposed by Abraham Ortelius in 1596, and Alfred Wegener developed it in 1912.

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The cart comes to rest from 1.3 m/s in a matter of 0.30 s, so it undergoes an acceleration a of

a = (0 - 1.3 m/s) / (0.30 s)

a ≈ -4.33 m/s²

This acceleration is applied by a force of -65 N, i.e. a force of 65 N that opposes the cart's motion downhill. So the cart has a mass m such that

-65 N = m (-4.33 m/s²)

m = 15 kg

Answer:

Bernoulli's theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquidor gas), the compressibility and viscosity (internal friction) of which are negligible and the flow of which is steady, or laminar.

Three properties of an ideal fluid that obey Bernoulli’s principle are :

1) incompressible

2) subjected to conservative forces

3) non - viscous

Bernoulli's principle  states that as the speed of moving fluid increases , the pressure within fluid decreases or it states that   if the fluid flows horizontally so that no change in gravitational potential energy occurs, then a decrease in fluid pressure is associated with an increase in fluid velocity.

As we know that Bernoulli's principle is only valid for ideal fluids which have following properties :

1) Should be incompressible

2) subjected to conservative forces

3) It should be non - viscous which means there is no internal friction in the flow .

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Answer:

You have learnt how objects move. You also know that a moving object like a ball rolling on the ground slows down. Sometimes it may change its direction of motion. It is also possible that the ball may slow down and also change its direction. what makes an object to slow down or go faster, or change its direction of motion?

Let us recall some of our everyday experiences. What do you do to make a football move? What do you do to make a moving ball move faster? How does a goalkeeper stop a ball? How do fielders stop a ball hit by a batsman? A hockey player changes the direction of the moving ball with a flick of the stick. In all these situations the ball is either made to move faster or slower or its direction of motion is changed.

Explanation:

Answer:

The temperature and gravity both affects the density

Answer:

a) F₃ = 108.71 N ,    θ = 218.68º    b)  m = 0.8487 kg

Explanation:

a) To solve this problem we will use Newton's second law, in the first part the accuracy is zero

          ∑ F = 0

X axis

          F₁ₓ + F₂ₓ + F₃ₓ = 0

          F₃ₓ = - F₁ₓ -F₂ₓ

Y axis

         [tex]F_{1y}[/tex] + F_{2y} + F_{3y} = 0

         F3y = -F_{1y} -F_{2y}

Let's use trigonometry to find the components of the applied forces

         cos 70 = F₁ₓ / F₁                 F₁ₓ = F₁ cos 70

         sin 70 = F_{1y} / F₁             F_{1y} = F₁ sin 70

         cos 20 = F₂ₓ / F2               F₂ₓ = F₂ cos 70

         sin 20 = F_{2y} / F₂           F_{2y} = F₂ sin 70

         F₁ₓ = 45 cos 70 = 15.39 N

         F_{1y} = 45 sin 70 = 42.29 N

         F₂ₓ = 75 cos 20 = 70.48 N

         F_{2y} = 75 sin 20 = 25.65 N

let's calculate

        F₃ₓ = -15.39 - 70.48

        F₃ₓ = -85.87 N

        F_{3y} = -42.29 - 25.65

        F_{3y} = -67.94 N

this is the force that must be applied to keep the system in equilibrium, we can give this value in the form of module and angle

         F₃ = √ (F₃ₓ² + F_{3y}²)

         F₃ = √ (85.87²  +67.94²)

         F₃ = 108.71 N

         tan θ = F₃ = [tex]F_{3y}[/tex] / F₃ₓ

         θ = tan⁻¹ (67.94 / 84.87)

         θ = 38.68º

Since the two values ​​are negative, this angle is in the third quadrant, therefore the measuring angle n counterclockwise from the positive side of the x-axis is

        θ = 180 + 38.68

        θ = 218.68º

b) It is not clear, but we must suppose that the person exerts this force F3 in the direction of movement, bone at an angle θ= 39.68º, in this case Newton's equation for the x axis remains

         F₁ₓ + F₂ₓ + F₃ₓ = m a

         m = (F₁ₓ + F₂ₓ + F₃ₓ) / a

let's calculate

          m = (15.39 + 7048 + 85.87) / 200

          m = 0.8487 kg

Answer:

0.399 rev/s

Explanation:

Given that,

The diameter of a tornado, d = 74 m

Radius, r = 37 m

Linear velocity, v = 335 km/h = 93.05 m/s

We need to find the angular velocity in revolutions per second. Let it is [tex]\omega[/tex]. The relation between angular velocity and linear velocity is as follows :

[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{93.0556}{37}\\\\\omega=2.51\ rad/s[/tex]

or

[tex]\omega=\dfrac{2.51}{2\pi}\\\\\omega=0.399\ rev/s[/tex]

So, the angular velocity of the blade is 0.399 rev/s.

a higher energy than an electron near the nucleus

In an electron cloud, an electron that is farther away from the nucleus has a higher energy than an electron near the nucleus. Thus, the correct option is C.

An electron cloud is the region which is surrounding an atomic nucleus in which there is a very high probability of an electron being located in an atom. The probability of finding an electron is greater than the more dense regions of the electron cloud in the atom.

One way in which the elements differ from each other is the structure of the electron cloud in each of the element's atoms in an electron cloud and the electrons which is farther from the nucleus has a higher energy than an electron near the nucleus of the atom.

Therefore, the correct option is C.

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Answer:

gas

Explanation:

it is gas because the particles are floating up none of the above would be floating up.

Answer:

Solid

Explanation:

A: Solid- Solids have the particles tightly packed. They have a definite shape and volume

B: Liquid- Liquids have particles not to tightly packed but kind of loose. They have an indefinite shape but a definite volume

C: Gas- Gas has particles freely all around. Indefinite shape and volume

D: Plasma- Plasma is different and should be explained with an example; think of lighting....

Since the image shows tightly packed particles, it is clear the answer is a solid.

Answer:

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Explanation:

The torque applied will be the average of the 3 torque calculated.

Torque = 12.01 Nm

Torque of a couple is the product of a force and its perpendicular distance to the direction of the force. Torque is synonymous to moment.

From the question, the given radius is 0.53m. The perpendicular distance for each torque will be 2 x 0.53 = 1.06 m

We will calculate for each torque

T1 = F1d

T1 = 8 x 1.06 = 8.48 Nm

T2 = F2d

T2 = 15 x 1.06 = 15.9 Nm

T3 = F3d

T3 = 11 x 1.06 = 11.66 Nm

The torque applied will be the average of the 3 torque calculated. That is,

Torque = (8.48 + 15.9 + 11.66)/3

Torque = 36.04 /3

Torque = 12.01 Nm

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Answer:

(a) V₂ = 1.86 m/s

(b) Q = 5.1 x 10⁻⁴ m³/s

Explanation:

(a)

The formula derived for Venturi tube is as follows:

P₁ - P₂ = (ρ/2)(V₂² - V₁²)

where,

P₁ - P₂ = Difference in Pressure of Inlet and Outlet = 1.2 KPa = 1200 Pa

ρ = Density of Gasoline = 7.4 x 10² kg/m³

V₂ = Exit Velocity = ?

V₁ = Inlet Velocity

Therefore,

1200 Pa = [(7.4 x 10²kg/m³)/2](V₂² - V₁²)

V₂² - V₁² = (1200 Pa)/(3.7 x 10² kg/m³)

V₂² - V₁² = 3.24 m²/s²   ------------------- equation (1)

Now, we will use continuity equation:

A₁V₁ = A₂V₂

where,

A₁ = Inlet Area = πd₁²/4 = π(0.0374 m)²/4 = 1.098 x 10⁻³ m²

A₂ = Exit Area = πd₂²/4 = π(0.0187 m)²/4 = 2.746 x 10⁻⁴ m²

Therefore,

(1.098 x 10⁻³ m²)V₁ = (2.746 x 10⁻⁴ m²)V₂

V₁ = (2.746 x 10⁻⁴ m²)V₂/(1.098 x 10⁻³ m²)

V₁ = 0.25 V₂  

using this value in equation (1):

V₂² - (0.25 V₂)² = 3.24 m²/s²

0.9375 V₂² = 3.24 m²/s²

V₂² = (3.24 m²/s²)/0.9375

V₂ = √(3.456 m²/s²)

V₂ = 1.86 m/s

(b)

For fluid flow rate we use the following equation:

Flow Rate = Q = A₂V₂ = (2.746 x 10⁻⁴ m²)(1.86 m/s)

Q = 5.1 x 10⁻⁴ m³/s

The formula for finding variables in a  Venturi tube is shown below:

P₁ - P₂ = (ρ/2)(V₂² - V₁²)

where, P₁ - P₂ is difference in pressure of Inlet and outlet, ρ = density, V₂ = exit velocity and V₁ is inlet velocity

P₁ - P₂ = 1.2 KPa = 1200 Pa

ρ = 7.4 x 10² kg/m³

V₂ = Exit Velocity = ?

V₁ = Inlet Velocity

We then substitute the variables into this equation.

P₁ - P₂ = (ρ/2)(V₂² - V₁²)

1200 Pa = [(7.4 x 10²kg/m³)/2](V₂² - V₁²)

V₂² - V₁² = (1200 Pa)/(3.7 x 10² kg/m³)

V₂² - V₁² = 3.24 m²/s²  ------ equation (1)

The  continuity equation A₁V₁ = A₂V₂ is then used

where,A₁ = Inlet area = πd₁²/4 = π(0.0374 m)²/4 = 1.098 x 10⁻³ m²

A₂ = Exit Area = πd₂²/4 = π(0.0187 m)²/4 = 2.746 x 10⁻⁴ m²

(1.098 x 10⁻³ m²)V₁ = (2.746 x 10⁻⁴ m²)V₂

V₁ = (2.746 x 10⁻⁴ m²)V₂/(1.098 x 10⁻³ m²)

V₁ = 0.25 V₂  

We then substitute the value into equation 1

V₂² - (0.25 V₂)² = 3.24 m²/s²

0.9375 V₂² = 3.24 m²/s²

V₂² = (3.24 m²/s²)/0.9375

V₂ = √(3.456 m²/s²)

V₂ = 1.86 m/s

This can be calculated using the formula

Flow Rate = Q = A₂V₂

                  = (2.746 x 10⁻⁴ m²)(1.86 m/s)

                 = 5.1 x 10⁻⁴ m³/s

Answer:

C

Explanation:

The most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.

It has negative consequences on the muscle, and it is also known as "microtrauma," which occurs as a result of muscle contraction and is a normal part of the muscle repair and growth process. Here, the fibers in the muscle are damaged, and in response, the body initiates a repair process. This leads to muscle growth and increased strength and is helpful for muscle repair.

Hence, the most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.

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Answer:

1.25

Explanation:

acceleration = velocity÷time

Answer:

Its acceleration is 1.25 meters/second2

Explanation:

The car's average acceleration would be 1.25m/s^2 or 1.25meters/second/second. That looks to be the fourth one you've listed.