Analyzing Ideas A friend claims to have built a
motor by attaching a shaft to the core of a galva-
nometer and removing the spring. Can this motor
rotate through a full rotation? Explain your answer.

Answer:

B

Explanation:

this is because the neutrons do not have a charge, the things that have charge in an atom are electrons and protons.

and in the nucleus of an atom, there are protons and neutrons so you can see that A is not the answer

if you see the periodic table, you will know that the number of electrons and protons are equal, so the charges cancel each other out, hence the charge of an atom will be neutral

let me give you a tip which I got from my teacher, never write there is no charge in the atom, this suggests that there is no protons or electrons.

instead, write, the it is neutral

hope it helps if not please report it so that someone else gets to try it out

Answer:

800J

Explanation:

Given data

Force= 100N

Distance moved= 8m

The expression for the work done is

WD= Force* distance

substitute

WD= 100*8

WD= 800Joules

Hence the work done is 800J

Answer:

Mass is a base unit, acceleration is a derived unit calculated as a function of length and time which are both base units. Any unit definition that is a function of more basic units is considered a derived unit.

Answer:

Acceleration of one cyclist=[tex]2.67m/s^2[/tex]

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration, [tex]a=\frac{v-u}{t}[/tex]

Using the formula

[tex]a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2[/tex]

Acceleration of one cyclist=[tex]2.67m/s^2[/tex]

Acceleration of another cyclist, a'=[tex]\frac{30-0}{8}m/s^2[/tex]

Acceleration of another cyclist, a'=[tex]3.75m/s^2[/tex]

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.

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Answer:

all of the above are correct

Explanation:

hope it helps you

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Answer: B) Frequency

Explanation:

Answer:

Acceleration = 1.85m/s²

Explanation:

Given the following data;

Final velocity = 300km/h to m/s = 300*1000/3600 = 83.33m/s

Time = 45 seconds

Since the plane started from rest, initial velocity is equal to 0m/s.

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Where,

a is acceleration measured in [tex]ms^{-2}[/tex]

v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]

t is time measured in seconds.

Substituting into the equation, we have;

Acceleration = (83.33 - 0)/45

Acceleration = 83.33/45

Acceleration = 1.85m/s²

Therefore, the acceleration of the plane is 1.85m/s².

Answer:

a)   y = y₀ - 4.9, v = -9.8 m / s, b)  y =y₀ - 19.6,  v = - 19 m / s

c)  y =y₀ - 44.1, v = - 29.4 m / s

Explanation:

To solve this exercise let us use the kinematic relations

          y =y₀ + v₀ t - ½ g t²

          v = v₀ - g t

They indicate that the body is released therefore the initial velocity is zero v₀ = 0

          y = y₀ - ½ g t²

          v = - gt

a) the position and velocity for t = 1s

         y = y₀ - ½ 9.8 12

         y = y₀ - 4.9

         v = - 9.8 1

         v = -9.8 m / s

the negative sign indicates that the velocity is directed downwards

b) t = 2 s

         y =y₀ - ½ 9.8 2 2

         y =y₀ - 19.6

         v = - 9.8 2

         v = - 19 m / s

c) t = 3 s

        y = y₀ - ½ 9.8 3 2

        y =y₀ - 44.1

        v = - 9.8 3

        v = - 29.4 m / s

Answer:

Explanation:

We shall find first the distance where electric field is E/4 .

Let the charge be Q and distance be d where electric field is E . From the coulomb's Law

E = k Q / d²

Let distance be d₁ where field is E/4

E/4 = kQ / d₁²

Dividing the two equation

4 = d₁² / d²

d₁ = 2d

We shall have to find Potential at d₁ which is equal to 2 d .

Potential at d₁

V = k Q / 2d

= kQ d / 2d²

= E d / 2 . where d is distance of the point where field is E .

Answer:

Protists are called plant-like, fungus-like and animal-like because they share some of the characteristics of plants, fungi and animals, even though they belong in a different category: the kingdom Protista.

Explanation:

Answer:

14.76

Explanation:

If you put it in the calculator it would show

Answer:

1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km

2) Mia's average speed is 6.00 km/hour

Peter's average speed is 8.48 km/hour

4) Mia's average velocity = Peter's average velocity = 6.00 km/hour

Explanation:

The given information from the diagram are;

The distance Peter jogs from school to the flower shop = 2.00 km

The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.

The distance Mia walks from school directly to the Coffee shop = 3.00 km

The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour

1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km

The distance Mia travels from school to the Coffee shop = 3.00 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km

2) [tex]Average \ speed = \dfrac{Total \ distance \ traveled}{Total \ time \ taken \ in \ the \ journey}[/tex]

[tex]Therefore, \ Mia's \ average \ speed = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour[/tex]

Mia's average speed = 6.00 km/hour

[tex]Peter's \ average \ speed = \dfrac{4.24 \ km}{0.5 \ hour}= 8.48 \ km/hour[/tex]

Peter's average speed = 8.48 km/hour

4) [tex]Average \ velocicty = \dfrac{Displacement }{Time \ taken}[/tex]

The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter

The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour

[tex]Therefore, \ Mia's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour[/tex]

Mia's average velocity = 6.00 km/hour

[tex]Peter's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour[/tex]

Therefore, Peter's average velocity is also = 6.00 km/hour

Answer: car at the top of a hill

Explanation:

// s - displacement, t - time, v - velocity

Known:

s = 542 meters;

v = 10m/s

Unknown:

t - ?

Formula:

t = s / v

Solution:

t = 542 / 10 = 54,2 (s)

Answer:

54,2 s

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Answer: Warm water from the ocean is needed to develop typhoon

Pls Rate this as Brilliant Answer thank you :) keep on learning

Typhoons form when strong winds blow into warm areas of the ocean. These winds pick up moisture and rise, bringing colder air with them. This creates pressure, causing the winds to move quickly. The winds revolve or spin around a central point known as an eye.

A typhoon is a mature tropical cyclone that forms in the Northern Hemisphere between 180° and 100°E. The Northwestern Pacific Basin is the most active tropical cyclone basin on Earth, accounting for nearly one-third of the world's annual tropical cyclones.

The Philippines is just above the equator and faces the western Pacific, with little else to absorb storm energy before it reaches land. Storms are fueled by warm, tropical waters, which produce approximately 20 typhoons per year.

Hurricanes and typhoons can wreak havoc on coastlines and hundreds of miles inland. They can generate winds of up to 155 mph, as well as tornadoes and microbursts.

Thus, Typhoons form when strong winds blow into warm areas of the ocean.

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Answer:

4P + 502 → 2P205

Explanation:

Hence the above equation is balanced.

Explanation:

[tex] \underline{ \underline{ \large{ \text{Given \: chemical \: equation}}}} : [/tex]

Here , Multiply P2O5 by 2 and O2 by 5 to equalize oxygen :

[tex] \tt{P+ 5O_{2} \: \: ➞\: \: 2P_{2} \:O_{5}}[/tex]

Now , To equalize P atoms , Multiply P by 4

[tex] \boxed{ \large{\tt{ 4P + 5O _{2} \: ➞ \: \: \: \: 2P_{2} \: O_{5}}}}[/tex]

Here , On the left side we have 4P and On the right side ,we have 4P. Again , On the left side , we have 10 O and On the right side , we have 10 O. And yippie , we got the balanced chemical equation !!!

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Answer:

Metaphase II

Explanation:

Metaphase II is the division of two daughter cells and is when sister chromatids line up in the middle of the cell.  This is what appears to be happening in the image.  Additionally, you can see that the chromosomes have already crossed over.  

Metaphase I only involves 1 cell, not 2 daughter cells.

Telophase II and Cytokinesis are when the cell splits.  Also, Telophase II would result in 4 daughter cells, not just 2.  

Answer:B

Explanation:

Resistance  =  (voltage) divided by (current)

                                              =  (120 V)  /  (0.5 Amp)

                                              =          240 ohms .

The Earth, Sun, and Moon systems create several patterns, including the day and night cycle, seasons, lunar phases, tides, and solar and lunar eclipses. These patterns have been studied and understood by scientists for centuries and have played an important role in shaping our understanding of the universe and our place in it. Understanding these patterns is essential in comprehending the workings of the universe and the impact they have on our planet.

The Earth, Sun, and Moon systems create several patterns, including:

Day and Night cycle: The rotation of the Earth on its axis causes the alternating cycle of day and night as different parts of the planet face towards or away from the Sun.

Seasons: The tilt of the Earth's axis (23.5 degrees) causes the seasons to change as different parts of the planet receive varying amounts of sunlight throughout the year.

Lunar Phases: The Moon orbits the Earth, causing it to appear to change shape in the sky as different amounts of sunlight reflect off its surface.

Tides: The gravitational pull of the Moon and the Sun on the Earth's oceans creates a regular cycle of high and low tides.

Solar and Lunar Eclipses: The alignment of the Earth, Sun, and Moon can cause a shadow to be cast on one celestial body by another, resulting in either a solar or lunar eclipse.

These patterns have been studied and understood by scientists for centuries and have played an important role in shaping our understanding of the universe and our place in it.

Therefore, The day and night cycle, seasons, lunar phases, tides, and solar and lunar eclipses are just a few of the patterns that the Earth, Sun, and Moon systems produce. Scientists have been analyzing and studying these patterns for centuries, and they have had a significant impact on how we view the cosmos and our place in it. Knowing these patterns is crucial to understanding how the cosmos functions and how they affect our world.

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Answer:

Radiation therapy uses high-energy particles or waves, such as x-rays, gamma rays, electron beams, or protons, to destroy or damage cancer cells.Hope that helps

Answer: Galileo's laws of Motion determined that the natural state of an object is rest or uniform motion, objects always have a velocity, sometimes that velocity has a magnitude of zero rest. objects resist change in motion, which is called inertia.

Explanation:

Galileo failed to formulate equations to describe this type of motion because he was unable to prove this motion by direct or obvious means.

Galileo introduced two different propositions to describe motion of an object, which includes;

Galileo considered to define uniform acceleration as change in speed over equal change in distance or change in velocity over equal change in time of motion.

Galileo chose the later definition, "uniform acceleration as the change in velocity over equal change in time of motion".

Galileo failed to formulate equations to describe this type of motion because he was unable to prove this motion by direct or obvious means.

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Answer:

Explanation:

25.0 m/s

Answer:

Explanation:

Given the following data;

Mass = 2kg

Energy = 50J

Height = 10m

To find the speed

Kinetic energy can be defined as the energy possessed by a body due to its motion.

K.E = ½mv²

Substituting into the equation, we have;

50 = ½*2*v²

V² = 50

Taking the square root of both sides, we have;

V = 7.07m/s

Answer:

4,0kg it is stopped!!!!!

The momentum of the object with a mass of 3 kg and when the object is stopped is zero. There is no momentum taking place.

Momentum is equal to the product of the mass and velocity of the object. Momentum is a vector quantity as it has both magnitude and direction. The unit of momentum is kg.m/s².  Momentum represents the mass of the moving body.

Momentum is represented as the letter p. p = m×v, where m is the mass of the body and v is the velocity of the object. Momentum is directly proportional to the velocity. The velocity of the object is defined as the rate of change of displacement per unit time.

From the given,

mass of the object = 3 kg

the velocity of the object = 0 (when the body is stopped v=0)

the momentum, p = m×v

p = 3×0

   = 0

The linear momentum of the object is zero.

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Explanation:

this is the answer for your question further if you have any doubts

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Answer:

[tex]20.61\times 10^{5}Nm^{-2}[/tex]

Explanation:

We are given that

h=20 cm=0.20m

1m=100 cm

Density of water=[tex]\rho=1.0\times 10^3 kg/m^3[/tex]

We have to find the pressure experienced by driver at that depth.

Atmospheric pressure, P0=101 kPa

Pressure experience by driver

[tex]P=\rho hg+P_0[/tex]

Where [tex]g=9.8[/tex]

[tex]P=1.0\times 10^3\times 0.20\times 9.8+101[/tex]

[tex]P=2061KPa[/tex]

1 KPa=[tex]1000Nm^{-2}[/tex]

[tex]P=2061\times 1000=2061000N/m^2[/tex]

[tex]P=20.61\times 10^{5}Nm^{-2}[/tex]

Answer:

1) Sucrose C₁₂H₂₂O₁₁

Common name; Sugar

Types of Compound ; Covalent Compound

Melting point; No melting point, it decomposes when heated

Electrical conductivity; Does not conduct electricity when dissolved in water

Solubility in water; Soluble in water

2) C₉H₈O₄ (Acetyl Salicylic acid)

Common name; Aspirin

Types of Compound ; Covalent Compound

Melting point; High

Electrical conductivity; Does not conduct electricity when dissolved in water

Solubility in water; Slightly soluble in water

3) NaCl (Sodium Chloride)

Common name; Salt

Types of Compound ; Ionic Compound

Melting point; High

Electrical conductivity; Conducts electricity when dissolved in water

Solubility in water; Soluble in water

4) C₅H₈NO₄Na (Monosodium Glutamate (MSG)

Common name; Vetsin

Types of Compound ; Ionic Compound

Melting point; High

Electrical conductivity; Conducts electricity when dissolved in water

Solubility in water; Soluble in water

5) C₈H₁₈ (Octane)

Common name; Common gasoline

Types of Compound ; Covalent Compound

Melting point; Low

Electrical conductivity; Does not conducts electricity and insoluble in water

Solubility in water; Relatively insoluble in water

Explanation: