An uncharged parallel-plate capacitor is connected through an open switch to a battery of voltage VV. The switch is closed and the capacitor is allowed to charge. As the capacitor is charged, energy is transferred to it from the battery. When the capacitor is fully charged, the energy stored in the capacitor is U1U1 . The energy stored in the capacitor when the stored charge is q02q02 is

Answer:

D, the acceleration  of A is twice that of b.

Explanation: in four seconds b got to ten, in two seconds a got to 20. Going  10m/s faster in half the time is going twice the acceleration

Answer: Force and Direction

Explanation:

To calculate potential energy, use the formula

[tex]ep \: = mgh[/tex]

Where m is mass in kg, g is gravitational field strength in m s^-2 and h is height in metres.

So in this case, calculate

2kg × 9.8m/s × 40m

and you should find your answer.

Answer:

C. Amplitude

Explanation: Amplitude is the maximum displacement from the equilibrium of a wave. Basically the height.   

Answer:

The potential between the plates will decrease.

Explanation:

An insulator is usually placed between the parallel plates and is also called a dielectric because it makes the amount of charge a capacitor can accommodate to increase at a particular potential difference.

Furthermore, the dielectric effect will make the electric field of the charged capacitor which is not connected to a source of supply to decrease.

Now, when the battery is removed, the charge Q remains constant and Capacity C will increase.

Formula for the potential difference is here;

V = Q/C

Since the numerator Q is constant and the denominator C increases, it means the potential difference V will decrease

Answer:

[tex]x = t[/tex]

[tex]y = \frac{1}{3}t[/tex]

[tex]z =t[/tex]

Explanation:

Given

[tex]r(t) = f(t)i + g(t)j + h(t)k[/tex] at [tex]t = 0[/tex]

Point: [tex](f(t0), g(t0), h(t0))[/tex]

[tex]r(t) = ln\ t_i + \frac{t-1}{t+2}j + t\ ln\ tk[/tex], [tex]t0 = 1[/tex] -- Missing Information

Required

Determine the parametric equations

[tex]r(t) = ln\ ti + \frac{t-1}{t+2}j + t\ ln\ tk[/tex]

Differentiate with respect to t

[tex]r'(t) = \frac{1}{t}i +\frac{3}{(t+2)^2}j + (ln\ t + 1)k[/tex]

Let t = 1 (i.e [tex]t0 = 1[/tex])

[tex]r'(1) = \frac{1}{1}i +\frac{3}{(1+2)^2}j + (ln\ 1 + 1)k[/tex]

[tex]r'(1) = i +\frac{3}{3^2}j + (0 + 1)k[/tex]

[tex]r'(1) = i +\frac{3}{9}j + (1)k[/tex]

[tex]r'(1) = i +\frac{1}{3}j + (1)k[/tex]

[tex]r'(1) = i +\frac{1}{3}j + k[/tex]

To solve for x, y and z, we make use of:

[tex]r(t) = f(t)i + g(t)j + h(t)k[/tex]

This implies that:

[tex]r'(1)t = xi + yj + zk[/tex]

So, we have:

[tex]xi + yj + zk = (i +\frac{1}{3}j + k)t[/tex]

[tex]xi + yj + zk = it +\frac{1}{3}jt + kt[/tex]

By comparison:

[tex]xi = it[/tex]

Divide by i

[tex]x = t[/tex]

[tex]yj = \frac{1}{3}jt[/tex]

Divide by j

[tex]y = \frac{1}{3}t[/tex]

[tex]zk = kt[/tex]

Divide by k

[tex]z = t[/tex]

Hence, the parametric equations are:

[tex]x = t[/tex]

[tex]y = \frac{1}{3}t[/tex]

[tex]z =t[/tex]

Answer:

1. a vector field is an assignment of a vector to each point in a subset of space.

2. The direct answer is that it happens through Newton’s second law. If an object is in a potential field that is different at different points in space, then the object will experience a force in the direction in which the potential energy decreases. Newton’s second law says that a force causes a change in motion, which changes the kinetic energy.

3. According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.

4. Ions are charged atoms that form when an atom donates or accepts one or more negatively charged electrons. Cations (ions with a positive charge) are attracted to anions (ions with a negative charge). This attraction is called an ionic bond.

5. Magnetic Field

Hope it Helps!!!!

Answer:

false

Explanation:

Answer:

Five examples of locomotor movements are:

Hopping

Galloping

Walking

Running

Skipping

Explanation:

I hope it helps ❤❤

Answer:

Explanation:

During an energy transfer, the collision loss for an electron can be determined by using the formula:

[tex]Q = \dfrac{4mME }{(m+M)^2}[/tex]

However; from the total stopping power & power loss of the electron;

[tex]\dfrac{radiational \ energy \ loss}{colisional \ energy \ loss } = \dfrac{ZE}{800}[/tex]

where;

Z = atomic no. for lead = 82

E = 1.9 MeV

∴

radiational energy loss = collisional energy loss  [tex]=\dfrac{82 \times 1.9}{800}[/tex]

= 0.19475

b)

Normally, the traditional lead shielding in its pure shape contains high brittleness. However, the functionality of this carbon group chemical element is useful for protection because it has an excessive density.

Initially, the conventional lead protection however reduces the mild clarity at the same moment as plexiglass is useful for light transmittance and readability.

Moreover, the traditional lead with its high density and thickness reduces observation features, in the meantime, the plexiglass is a whole lot higher than the stated.

Finally, plexiglass contains a high dimensional balance with an excessive dielectric constant.

Answer:

This is something for biology, it shouldnt be in the physics subject

Explanation:

AnswerHM???

Explanation:

I dONT KNOW

Answer:

Option A

Explanation:

Answer:

equal and opposite

Explanation:

..........

Answer:

8. organelle

Explanation:

9. Epithelial tissue

am i correct?

Answer:

12.5 m/s

Explanation:

Excuse my scribbles!

I had to work backwards using the inelastic collision formula for this problem.

Step 1: Substitute in the values provided in the problem

2.5=(8*0)+(?*?)/(8+?)

Step 2: Subtract block 1's mass from the combined mass to determine block 2's mass

10-8=2     Block 2's mass is 2.

2.5=(8*0)+(2*x)/(8+2)    

Now simplify.

2.5=(2*x)/(8+2)

2.5=2x/10

Step 3: Multiply both sides by the reciprocal

(5)2.5=2x/10(5)

12.5=x

Answer is checked in the attached images!

Answer:

A. pushing a car that isn't moving

Answer:

467 volts

Explanation:

Vs/Vp = Ns/Np

Vs = Ns/Np × Vp

Vs = 350/150 × 200 = 7/3 × 200

Vs = 467 volts

Answer:

Explanation:

for vertical movement , time to reach the top = time to reach the hand = 2.5 s

v = u - gt

At the top , v = 0 , time t = 2.5 s

0 = u - g x 2.5

u = 2.5 x 9.8 = 24.5 m /s

velocity of throw = 24.5 m /s

So , when it passes the hand on its way down , it will have velocity equal to 24.5 m /s and it will accelerate downwards . Let its velocity down by 22 m be v

v² = u² + 2 g s

= 24.5² + 2 x 9.8 x 22

= 600.25 + 431.2

= 1031.45

v = 32.11 m /s .

Complete question is;

A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The worker holds the rope at the same height as the connection point between the rope and weight. The distance from the connection point to the ceiling is 40 ft. Suppose the worker stands directly next to the weight (i.e., a total rope length of 80 ft) and begins to walk away at a constant rate of 3 ft/s. How fast is the weight rising when the worker has walked:

A) 10 feet

B) 30 feet

Answer:

A) 0.728 ft/s

B) 1.8 ft/s

Explanation:

Let the the position of the worker in ft be denoted by s.

Since he begins to walk away at a constant rate of 3 ft/s, then;

ds/dt = 3 ft/s

Now, the rope will form a triangle, with width "s" and the height 40. Since distance from the connection point to the ceiling = 40 ft

Using pythagoras theorem, we can find the length of the rope on this side of the pulley.

Hence, the length of rope on this side of the pulley = √(s² + 40²)

Meanwhile, on the other side the length will be;

(80) - √(s² + 40²)

Also, height of the weight will be;

h = 40 - ((80) - √(s² + 80²))

h = √(s² + 80²) - 40

Differentiating this, we have;

dh/dt = (ds/dt) × (s/√(s² + 40²))

From earlier, we saw that ds/dt = 3 ft/s

Thus;

dh/dt = 3s/√(s² + 40²)

A) when he has walked 10 ft, it means that s = 10. Thus;

dh/dt = (3 × 10)/√(10² + 40²)

dh/dt = 0.728 ft/s

B) when he has walked 30 ft, it means that s = 30. Thus;

dh/dt = (30 × 3)/√(30² + 40²)

dh/dt = 1.8 ft/s

Answer:

hopefully alex quackity hahhaa

Explanation:

i hope this was free points and not an actual thing

Answer:

cool, cool for alex .....

Answer:

2.5 m/s^2

Explanation:

First, convert 90 km/hr into m/s:

90/3.6 = 25 m/s

vf = final velocity = 25 m/s

vi = initial velocity = 0 m/s

t = time = 10 seconds

a = acceleration, unknown

Then, find a using the following equation:

(vf - vi)/t = a

(25 m/s)/10 s = 2.5 m/s^2

a = 2.5 m/s^2

Hope this helps!! :)

Answer:

B.

Explanation:

Answer:

An atom has a number of stable orbits in which an electron can reside without the emission of radiant energy. ... Each orbit corresponds, to a certain energy level.

Explanation:

Hope it is helpful....

Answer:

KE = 60.91875 J

Explanation:

First, convert the mass of the ball into kg, since we want the answer in J (SI system):

150 g = 0.15 kg

then use the kinetic energy formula

[tex]KE=\frac{1}{2} m*v^{2} \\KE=\frac{1}{2} (0.15)*(28.5)^{2}\\KE=60.91875 J[/tex]

Answer: When the car speed triples, momentum also triples but Kinetic energy increases 9 times or by 9 fold.

Explanation:

The momentum of a car (an object) is

p= mv

where

m is =the mass of the object( in this case car)

v is its= velocity

While the kinetic energy is is given by the formulae

K=1/2mv²

To determine how momentum and kinetic energy of the  car changes when the speed of the object triples, We have that the new velocity,

v¹= 3v

So that  the momentum  change becomes

p¹=mv¹=m (3v)= 3mv

mv=p

therefore p¹= 3p

we can see that the momentum also triples.

And the kinetic energy change  becomes

K¹=1/2m(v¹)²= 1/2m (3v)²

= 1/2m9v²= 1/2 x m x 9 x v²=9 x1/2mv²

1/2mv²=K

K¹= Kinetic energy = 9k

but Kinetic energy increases 9 times

Solution :

Given that :

The energy of the protons, K.E. = 1.10 keV

                                                    [tex]$= 1.10 \times 10^3 \ eV $[/tex]

The current produced by the generator is I = 5 mA

                                                                        [tex]$= 5 \times 10^{-3} \ A$[/tex]

Now [tex]$1 \ eV = 1.6 \times 10^{-19 }\ J$[/tex]

Mass of the proton, m = [tex]$1.67 \times 10^_{-27} $[/tex] kg

Charge of the proton, [tex]$q_p = 1.6 \times 10^{-19} \ C$[/tex]

a). Therefore using the formula for K.E. we can find out the velocity of the proton.

[tex]$K.E. =\frac{1}{2}mv^2$[/tex]

[tex]$v=\sqrt{\frac{2K.E.}{m}}$[/tex]

[tex]$v=\sqrt{\frac{2\times 10^3 \times 1.6 \times 10^{-19}}{1.67 \times 10^{-27}}}$[/tex]

  [tex]$= 4.38 \times 10^5 \ m/s$[/tex]

b). We know that the current is :

 [tex]$I=\frac{\Delta Q}{\Delta t}$[/tex]

Therefore, the total charge in one second is given by :

[tex]$\Delta Q = I \times \Delta t$[/tex]

     [tex]$= 5 \times 10^{-3} \times 1$[/tex]

    [tex]$= 5 \times 10^{-3}\ C$[/tex]

So, the number of protons in this charge is given by :

[tex]$n = \frac{\Delta Q}{q_p}$[/tex]

  [tex]$=\frac{5 \times 10^{-3} }{1.6 \times 10^{-19}}$[/tex]

  [tex]$= 3.13 \times 10^{16}$[/tex] protons

Answer:

All answer are explained below in the explanation section.

Explanation:

1. The pressure varies proportionally with the change in temperature. It can also be observed in our daily lives.

As for example, a pressure cooker uses the same principal to cook food faster. With the increasing temperature, the pressure inside the cooker increases.

Thus after a while, the excess pressure inside is released through the top nozzle. The data shown below supports that pressure and temperature varies linearly.

2. Hand drawn plot is attached in the attachment please refer to the attachment for the hand drawn plot.

Tire pressure at temperature 18.6 degree C is ~ 35 psi.

Temperature at air pressure of 37 psi is ~26.1 degree C

3. a.) Necessary values are included in the stat box. It is attached in the attachment please refer to the attachment.

3. b) The equation becomes: Pressure = 0.176 x temperature + 32.32

3. c) It is already done in part a of this question.

4. The value of the slope estimated from the linear fit is 0.176 +/- 0.094.

5. % Error = [tex]\frac{Actual - Experiment}{Actual} x 100[/tex]

Plugging in the values, we get:

Actual = 0.145, Experimental = 0.176. Thus, percentage error is given by:

% Error = 21.33%

6. a.) Visual estimation of tire pressure at t = 18.6 degree C is ~ 35 psi

6.  b.) Estimation of pressure from the best fit line is given by 35.6 psi, which is consistent with the eye estimation value.

6. c.) The eye estimation and the estimation from the line fit are quite comparable. The discrepancy of +/-0.5 psi is within the percentage error calculated in 5.

7.  a.) Visual estimation of temperature of the air for a tire-pressure of 37 psi is ~ 26 degree C.

7.  b.) Estimation of temperature from best fit value of line is = 26.64 degree C

7 c) The values from eye estimation and evaluated from the fit are quite consistent within a random fluctuation of +/- 0.64 degree C.