The rate of production of the final product is 0.3 t/h, and the composition of the final product is approximately 12.5% alcohol and 12% water, with no inert material present.
In an ethanol plant, the distillation process separates alcohol from corn. With a feed rate of 2.0 tons per hour, the bottoms waste contains 85% of the feed, while the final product is obtained from condensing and cooling the vapor.
To determine the rate of production of the final product and its composition, we need to calculate the mass flow rate of the final product and the composition of the final product.
Given:
Feed rate = 2.0 t/h
Composition of feed:
Alcohol: 15%
Water: 82%
Inert material: (100% - 15% - 82%) = 3%
Bottoms composition:
Water: 94%
Inert material: 3.5%
Alcohol: 2.5%
To calculate the rate of production of the final product, we need to subtract the mass of bottoms produced from the feed rate:
Rate of production of the final product = Feed rate - Mass of bottoms
Mass of bottoms = Feed rate × Bottoms composition = 2.0 t/h × 85% = 1.7 t/h
Rate of production of the final product = 2.0 t/h - 1.7 t/h = 0.3 t/h
Therefore, the rate of production of the final product is 0.3 tons per hour.
To calculate the composition of the final product, we need to consider the remaining components after removing the bottoms:
Composition of final product:
Alcohol: 15% - 2.5% = 12.5%
Water: 82% - 94% = 12%
Inert material: 3% - 3.5% = -0.5% (Assuming a negative value means there is no inert material remaining)
Therefore, the composition of the final product is approximately:
Alcohol: 12.5%
Water: 12%
No inert material
Please note that the negative value for the inert material indicates that there is no inert material present in the final product.
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1. From the chemicals listed on your lab handout, write down the weak acid (with its pKa) and its conjugate base that would create a buffer that best fits your protein. Would you expect for your buffer to have more acid or more base?
My assigned protein is Xylanase and has an optimum pH of 5. 5.
2. Buffers are used to the inhibit the change of pH upon the addition of strong acids and bases. If you were to add 0. 1 M HCl to your buffer, would you expect the pH to change? If so, would the pH increase or decrease? What would happen if 0. 1M NaOH were to be added instead?
3. Keeping your buffer composition from question 1 in mind, would you expect to use a larger volume of HCl or NaOH to change the pH of the buffer solution by one unit? Explain
1. Based on the information provided, a weak acid with a pKa close to the ideal pH of 5.5 would be the best buffer for Xylanase. Acetic acid (CH3COOH) can be utilised as the weak acid component of the buffer since it has a pKa of 4.76, which is close to the ideal pH.
Acetate ion (CH3COO-), its conjugate base, can also be utilised as a buffering agent. Since Xylanase prefers an acidic pH (below 7), we would anticipate the buffer to contain more acid than base.
2. The pH of the buffer would drop if 0.1 M HCl was introduced because the weak acid would arise when the H+ ions from the HCl react with the conjugate base in the buffer.
Instead, if 0.1 M NaOH was added, the pH would rise as the weak acid in the buffer reacts with the NaOH's OH- ions to form the conjugate base. The capacity of the buffer and the quantity of HCl or NaOH injected, however, would determine how much the pH changed.
3. It would take more HCl to raise the pH by one unit in the buffer in question 1 since it contains a weak acid and its conjugate base. This is due to the fact that the conjugate acid might be created when the weak acid component of the buffer reacts with extra H+ ions to limit significant pH shifts.
On the other hand, if NaOH were to be added to the buffer, the buffer's acid component would be consumed, causing a greater pH change.
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Explain what sedimentation equilibrium is and how it is related to chemical equilibrium.
Answer:
Sedimentation equilibrium in a suspension of different particles, such as molecules, exists when the rate of transport of each material in any one direction due to sedimentation equals the rate of transport in the opposite direction due to diffusion.
a 90.-ml sample of juice was titrated with the i2(aq) solution described above using a buret. the initial reading of the buret was 0.24 ml. when the endpoint was reached, the reading on the buret was 33.08 ml. how many mg of vitamin c were in the juice sample?
The juice sample contains 28,920 mg of vitamin C.
The amount of iodine used in the reaction can be calculated as:
I2 used = (final buret reading - initial buret reading) * 0.005 M
I2 used = (33.08 ml - 0.24 ml) * 0.005 M = 0.16392 moles
Since 1 mole of vitamin C reacts with 1 mole of iodine, the amount of vitamin C in the juice can be calculated as:
Vitamin C = I2 used * (1 mol of vitamin C / 1 mol of I2) * (176.12 g/mol)
Vitamin C = 0.16392 * (1 / 1) * (176.12 g/mol) = 28.92 g
Converting to milligrams:
Vitamin C = 28.92 g * 1000 mg/g = 28,920 mg
Therefore, the juice sample contains 28,920 mg of vitamin C.
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how many atp molecules are produced by metabolism of an acetyl coa molecule?12 ATP molecules13 ATP molecules14 ATP molecules15 ATP molecules
The metabolism of an acetyl CoA molecule produces a total of 12 ATP molecules through the process of cellular respiration.
The metabolism of one acetyl molecule through the Krebs cycle can produce 1 ATP molecule through substrate-level phosphorylation. In addition, the oxidation of NADH and FADH2 produced during the Krebs cycle can generate more ATP through oxidative phosphorylation in the electron transport chain.
However, the exact amount of ATP generated through oxidative phosphorylation depends on various factors, such as the efficiency of the electron transport chain and the availability of oxygen. Overall, the complete metabolism of one molecule of acetyl CoA can generate up to 10 ATP molecules through oxidative phosphorylation.
This occurs through the citric acid cycle and the electron transport chain, which are both part of the metabolic pathway that converts energy from glucose into usable ATP molecules.
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If earth had no atmosphere, its longwave radiation emission would be lost quickly to space making the planet approximately 33 K cooler. Calculate the rate of radiation emitted E and the wavelength of maximum radiation emission for earth at 255 K.
The Earth is emitting the most longwave radiation at a wavelength of approximately 11.4 micrometers.
Longwave radiation emission, also known as infrared radiation, is the process by which the Earth releases heat into space. This radiation is absorbed by greenhouse gases in the atmosphere, which then trap the heat and prevent it from escaping back into space.
If the Earth had no atmosphere, this longwave radiation emission would be lost quickly to space, resulting in a much cooler planet.
To calculate the rate of radiation emitted (E) by the Earth at a temperature of 255 K, we can use the Stefan-Boltzmann Law, which states that E = σT⁴, where σ is the Stefan-Boltzmann constant (5.67 x 10⁻⁸ W/m²K⁴) and T is the temperature in Kelvin. Plugging in the values, we get:
E = 5.67 x 10⁻⁸ x (255)⁴
E = 3.8 x 10⁸ W/m²
This means that the Earth is emitting 3.8 x 10⁸ watts of longwave radiation per square meter at a temperature of 255 K.
The wavelength of maximum radiation emission can be determined using Wien's Law, which states that the wavelength of maximum emission (λmax) is equal to the constant of proportionality (b) divided by the temperature in Kelvin. The value of b is approximately equal to 2.898 x 10⁻³ mK.
Plugging in the values, we get:
λmax = b/T
λmax = 2.898 x 10⁻³ / 255
λmax = 1.14 x 10⁻⁵ meters
This means that the Earth is emitting the most longwave radiation at a wavelength of approximately 11.4 micrometers.
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Select the correct answer.
where are globular clusters usually found?
oa. disk
ob. nucleus
oc. interstellar space
od. halo
Globular clusters are usually found in the halo of a galaxy. The answer is d.
Globular clusters are dense, spherical collections of stars that orbit a galactic center. They are typically composed of tens of thousands to hundreds of thousands of stars and are some of the oldest known objects in the universe.
Globular clusters are usually found in the halo of a galaxy, which is the outermost region of a galaxy that surrounds the disk.
This is because they are thought to have formed early in the history of the galaxy, when the halo was still being formed.
In contrast, stars in the disk of a galaxy are typically younger and more spread out, with less dense collections of stars. The nucleus of a galaxy is the central region, which usually contains a supermassive black hole and dense concentrations of stars.
Therefore, the correct answer is d. halo.
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0. 18 g of a
divalent metal was completely dissolved in 250 cc of acid
solution containing 4. 9 g H2SO4 per liter. 50 cc of the
residual acid solution required 20 cc of N/10 alkali for
complete neutralization. Calculate the atomic weight of
metal.
39.
Ans: 36
0.18 g of a divalent metal was completely dissolved in 250 cc of acid solution containing 4. 9 g H₂SO₄ per liter. 50 cc of the residual acid solution required 20 cc of N/10 alkali for complete neutralization. The atomic weight of metal is 45 g/mol.
First, we need to determine the moles of H₂SO₄ present in 250 cc of the acid solution:
4.9 g/L = 0.0049 g/cc
0.0049 g/cc x 250 cc = 1.225 g of H₂SO₄
Next, we can calculate the number of moles of H₂SO₄ that were neutralized by the alkali solution:
20 cc of N/10 NaOH = 0.002 mol NaOH
Since the reaction is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
then 1 mol of H₂SO₄ reacts with 2 mol of NaOH, therefore 0.004 mol of H₂SO₄ reacted with 0.002 mol of NaOH.
So, the remaining number of moles of H₂SO₄ is:
0.004 mol - 0.002 mol = 0.002 mol
Now we can calculate the moles of metal present in the solution:
0.18 g / atomic weight = moles of metal
We can use the remaining H₂SO₄ to find the number of moles of metal:
1 mol of H₂SO₄ reacts with 1 mol of metal, so the number of moles of metal is equal to the number of moles of H₂SO₄ remaining:
0.002 mol H₂SO₄ = 0.002 mol metal
Now we can solve for the atomic weight:
0.18 g / 0.002 mol = 90 g/mol
Since the metal is divalent, we need to divide by 2 to get the atomic weight:
90 g/mol / 2 = 45 g/mol
Therefore, the atomic weight of the metal is 45 g/mol.
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The hydrolysis of acetyl phosphate has ΔG = −42 kJ mol−1 under typical biological conditions. If the phosphorylation of acetic acid were to be coupled to the hydrolysis of ATP, what is the minimum number of ATP molecules that would need to be involved?
The hydrolysis of one ATP molecule has ΔG = -30.5 kJ mol⁻¹. Therefore, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate, with ΔG = -42 kJ mol⁻¹, is 2 ATP molecules.
The phosphorylation of acetic acid involves the transfer of a phosphate group from ATP to acetic acid, forming acetyl phosphate and ADP. The reaction can be represented as follows:
Acetic acid + ATP → Acetyl phosphate + ADPThe hydrolysis of acetyl phosphate involves the addition of a water molecule, which breaks the phosphoanhydride bond and releases the energy stored in the phosphate bond. The reaction can be represented as follows:
Acetyl phosphate + H₂O → Acetic acid + PiThe ΔG value of the hydrolysis of acetyl phosphate is -42 kJ mol⁻¹. Since the phosphorylation of acetic acid requires one ATP molecule, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate is calculated as follows:
ΔG = ΔG1 + ΔG2-42 kJ mol⁻¹ = -30.5 kJ mol⁻¹ + ΔG2ΔG2 = -42 kJ mol⁻¹ + 30.5 kJ mol⁻¹ΔG2 = -11.5 kJ mol⁻¹Since the hydrolysis of one ATP molecule has ΔG = -30.5 kJ mol⁻¹, the minimum number of ATP molecules required to drive the hydrolysis of acetyl phosphate is 2.
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You are asked to make a 1. 5 L solution of. 35 M HCl by diluting concentrated 16. 0 M HCI. What
volume of acid would be needed to make the dilution?
To make a 1.5 L solution of 0.35 M HCl using 16.0 M HCl, you will need 32.81 mL of concentrated acid.
1. Use the dilution formula: M1V1 = M2V2
2. M1 is the initial concentration (16.0 M), V1 is the volume of concentrated acid needed, M2 is the final concentration (0.35 M), and V2 is the final volume (1.5 L).
3. Plug in the values: (16.0 M)(V1) = (0.35 M)(1.5 L)
4. Solve for V1: V1 = (0.35 M)(1.5 L) / 16.0 M
5. V1 = 0.0328125 L, which is equal to 32.81 mL.
6. So, 32.81 mL of concentrated 16.0 M HCl is needed to make the 1.5 L solution of 0.35 M HCl.
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which are true of the greenhouse effect? multiple select question. all energy from the sun is absorbed by atmospheric gases. some sunlight is absorbed and some is reflected by the atmosphere. some infrared energy is absorbed by gases such as carbon dioxide (co2), water vapor (h2o), and methane (ch4). it changes sunlight and transforms it into carbon dioxide. some light is absorbed by the land and oceans, which radiate infrared energy back into the atmosphere.
The true statements regarding the greenhouse effect are:
Some sunlight is absorbed and some is reflected by the atmosphere.Some infrared energy is absorbed by gases such as carbon dioxide (CO2), water vapor (H2O), and methane (CH4).Some light is absorbed by the land and oceans, which radiate infrared energy back into the atmosphere. Options B, C and E are correct.The greenhouse effect is a natural process that occurs when certain gases in the atmosphere, known as greenhouse gases, trap heat from the sun and prevent it from escaping back into space. This helps to keep the Earth's surface warm enough to support life. However, human activities, such as burning fossil fuels, have increased the concentration of greenhouse gases in the atmosphere, which has led to an enhanced greenhouse effect and global warming.
In the greenhouse effect, not all energy from the sun is absorbed by atmospheric gases. Rather, some of it is reflected back into space by the atmosphere. Additionally, the greenhouse effect does not change sunlight into carbon dioxide; rather, it is the burning of fossil fuels and other human activities that release carbon dioxide into the atmosphere. Options B, C and E are correct.
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3. A certain nut crunch cereal contains 11. 0 grams of sugar (sucrose, C12H22011) per
serving size of 60. 0 grams. How many servings of this cereal must be eaten to consume
0. 0350 moles of sugar?
The number of servings of cereal needed to consume 0.0350 moles of sugar is approximately 0.834 servings.
1. Calculate the molar mass of sucrose (C₁₂H₂₂O₁₁): (12x12) + (1x22) + (16x11) = 144 + 22 + 176 = 342 g/mol.
2. Convert grams of sugar per serving to moles: 11.0 g/serving * (1 mol/342 g) ≈ 0.0322 moles/serving.
3. Divide the desired moles of sugar by moles/serving: 0.0350 moles / 0.0322 moles/serving ≈ 0.834 servings.
So, to consume 0.0350 moles of sugar, you need to eat approximately 0.834 servings of this cereal.
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A sample of graphite with a mass of 15.0 grams drops from an initial temperature of 22°C to a
final temperature of 12°C. Calculate how much heat was transferred, and state whether it was
gained or lost based on the sign of your answer.
Answer:
106.5 J, and it was lost.
Explanation:
To calculate the amount of heat transferred, we can use the following formula:
Q = m * c * ΔT
where Q is the amount of heat transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
For graphite, the specific heat capacity is approximately 0.71 J/g°C.
So we have:
Q = 15.0 g * 0.71 J/g°C * (-10°C)
Q = -106.5 J
The negative sign of the answer indicates that the graphite lost heat, since its temperature decreased. Therefore, the heat was transferred from the graphite to its surroundings.
So the amount of heat transferred from the graphite was 106.5 J, and it was lost.
Explain why the following carboxylic acids cannot be prepared by a malonic ester synthesis. Part A A line-angle formula shows a ring with six vertices and alternating single and double bonds. A CH2COH group, with an O atom double-bonded to the second (from left to right) carbon atom, is attached to one of the ring vertices. A line-angle formula shows a ring with six vertices and alternating single and double bonds. A CH2COH group, with an O atom double-bonded to the second (from left to right) carbon atom, is attached to one of the ring vertices. An SN2 reaction cannot be done on benzyl bromide. An SN2 reaction cannot be done on bromobenzene. An SN2 reaction cannot be done on dibromobenzene. The bromide required for the synthesis is unstable
The first two carboxylic acids described contain a benzene ring, which is not susceptible to the malonic ester synthesis.
The malonic ester synthesis requires a compound with a methyl group adjacent to both carboxylate groups, and a benzene ring does not fulfill this requirement. The last two carboxylic acids described cannot be prepared by the malonic ester synthesis because an SN₂ reaction cannot be performed on compounds with bulky substituents or with two or more halogen atoms attached to the same carbon atom.
The synthesis requires the use of an alkyl halide that can undergo an SN₂ reaction with sodium ethoxide, but benzyl bromide, bromobenzene, and dibromobenzene are not suitable for this type of reaction. Additionally, the bromide required for the synthesis is unstable, which further complicates the reaction.
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4 points
A solution consists of 2. 50 moles of NaCl dissolved in
100. Grams of H20 at 25°C. Compared to the boiling
point and freezing point of 100. Grams of H20 at
standard pressure, the solution at standard pressure
has
A) a lower boiling point and a higher freezing point
B) a higher boiling point and a lower freezing point
C) a higher boiling point and a higher freezing point
D) a lower boiling point and a lower freezing point
A solution consists of 2.50 moles of NaCl dissolved in 100 grams of H₂0 at 25°C. Compared to the boiling point and freezing point of 100 grams of H₂0 at standard pressure, the solution at standard pressure has a lower boiling point and a higher freezing point. The correct option is A.
When a solute, such as NaCl, is dissolved in a solvent, such as water, the boiling point of the solution is raised and the freezing point is lowered. This phenomenon is known as boiling point elevation and freezing point depression.
The extent of the change in boiling point and freezing point depends on the concentration of the solute in the solution. In this case, the solution consists of 2.50 moles of NaCl dissolved in 100 grams of H₂O. This concentration of NaCl will cause the solution to have a lower boiling point and a higher freezing point compared to pure water.
The reason is that the NaCl molecules dissociate into ions when dissolved in water, which increases the number of particles in the solution and lowers the vapor pressure, making it more difficult for the solution to boil. Additionally, the presence of the solute disrupts the formation of crystal lattice structures in the solvent, causing a decrease in the freezing point. Hence, option A is correct.
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Two other minerals can be seen in the photo:
galena, a dark grey mineral with the formula PbS
iron pyrite, a gold-coloured mineral with the formula FeS2
Compare their chemical formulas, by writing down one similarity and one difference between these two minerals.
Note: Pb = lead, Fe = iron, S = sulfur.
Galena and Pyrite are mineral ores.
Ore is a deposit of one or more precious minerals in the Earth's crust.
Galena is lead ore with formula PbS while pyrite is iron ore having formula FeS₂. In Other words, Galena is sulfide of lead and pyrite is sulfide of iron.
Both Galena and Pyrite are sulfide ores with different specific gravities.
Pyrite shows magnetic property on heating which galena is nonmagnetic component and doesn’t bear any magnetic properties.
Both are semi conductors but they are used for different purpose.
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A 17. 98-g piece of iron absorbs 2056. 5 joules of heat energy, and its temperature changes from 25°C to 200°C. Calculate the specific heat capacity of iron
The specific heat capacity of iron is 0.449 J/g°C.
The quantity of heat energy needed to raise the temperature of one gram of a substance by one degree Celsius is the substance's specific heat capacity.
The specific heat capacity of iron can be calculated using the formula:
q = mcΔT
where q is the heat energy absorbed by the iron, m is the mass of the iron, c is the specific heat capacity of iron, and ΔT is the change in temperature of the iron.
Substituting the given values:
2056.5 J = (17.98 g) × c × (200°C - 25°C)
2056.5 J = (17.98 g) × c × (175°C)
Solving for c:
c = 0.449 J/g°C
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Sketchpad
a chemist dilutes 2.0 l of a 1.5 m solution with water until the final volume is 6.0 l. what is
the new molarity of the solution?
show your work
The new molarity of the solution after dilution is 0.5 M.
To solve this problem, we can use the formula:
[tex]M_2 = M_1V_1 / V_2[/tex]
where [tex]M_1[/tex] and [tex]V_1[/tex] are the initial molarity and volume of the solution, and [tex]M_2[/tex] and [tex]V_2[/tex] are the final molarity and volume of the diluted solution.
In this case, we have:
[tex]M_1[/tex] = 1.5 M
[tex]V_1[/tex] = 2.0 L
[tex]V_2[/tex] = 6.0 L
We want to find the final molarity, [tex]M_2[/tex].
Using the formula, we can solve for [tex]M_2[/tex]:
[tex]M_2 = M_1V_1 / V_2[/tex]
Substituting the given values, we get:
[tex]M_2[/tex] = (1.5 M) × (2.0 L) / (6.0 L) = 0.5 M
Therefore, the new molarity of the solution is 0.5 M.
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Create the Equation: How many grams of Aluminum Chloride would be made from 42. 7 L of Chlorine gas at STP reacting with 50. 0 g of Aluminum? *
SOMEONE PLEASE HELP ME WITH THIS ONE ASAP
The reaction of 42.7 L of chlorine gas at STP with 50.0 g of aluminum produces 150.5 g of aluminum chloride.
The balanced chemical equation for the reaction between aluminum and chlorine gas is:
2Al + 3Cl₂ -> 2AlCl₃
To use this equation to calculate the grams of aluminum chloride produced, we need to convert the given volume of chlorine gas to moles using the ideal gas law:
n = PV/RT
At STP, the pressure (P) and temperature (T) are 1 atm and 273 K, respectively. The volume (V) is given as 42.7 L. The gas constant (R) is 0.08206 L atm K⁻¹ mol⁻¹ Plugging these values in, we get:
n = (1 atm * 42.7 L) / (0.08206 L atm K⁻¹ mol⁻¹ * 273 K) = 1.694 mol
Since the stoichiometry of the balanced equation is 2:3 (2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride), we need to calculate how many moles of aluminum are needed to react with 1.694 moles of chlorine gas:
2 mol Al / 3 mol Cl₂ * 1.694 mol Cl₂ = 1.129 mol Al
Finally, we can use the molar mass of aluminum chloride (133.34 g/mol) to calculate the grams of product:
1.129 mol AlCl₃ * 133.34 g/mol = 150.5 g AlCl₃
Therefore, 150.5 g of aluminum chloride would be produced from 42.7 L of chlorine gas at STP reacting with 50.0 g of aluminum.
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Substances can be the same if one has more of the same type of repeating group of atoms
Yes, substances can be the same if one has more of the same type of repeating group of atoms.
For example, polymers are made up of repeating units of the same monomer, and the number of monomers can vary, resulting in different sizes of polymers but still the same substance. Another example is isotopes, which are elements with the same number of protons but varying numbers of neutrons.
They have the same chemical properties and can form the same compounds despite having different atomic masses. Thus, substances can be identical in terms of their chemical properties even if they have different physical properties due to variations in the number of repeating groups of atoms or isotopes.
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If the final pressure in a container is 6. 10 atm and the volume changes from 2. 5 L to 3. 7 L, what is the original pressure?
Your answer:
9. 028 atm
1. 51 atm
0. 66 atm
4. 12 atm
The original pressure in the container was 9.028 atm.
To solve this problem, we need to use the combined gas law equation, which relates the pressure, volume, and temperature of a gas. The equation is P1V1/T1 = P2V2/T2, where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.
We are not given the temperature, so we can assume that it is constant.
First, we can rearrange the equation to solve for P1:
P1 = (P2V2/T2) * T1/V1
Substituting the given values, we get:
P1 = (6.10 atm * 3.7 L) / (2.5 L * T2) * T1
Since the temperature is constant, we can cancel it out, and the equation becomes:
P1 = (6.10 atm * 3.7 L) / (2.5 L)
Simplifying, we get:
P1 = 9.028 atm
Therefore, the original pressure in the container was 9.028 atm.
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If the pressure of a 7. 2 liter sample of gas changes from 735 torr to 800 torr and the temperature remains
constant, what is the new volume of the gas? (6. 62 L)
Answer:
you equate the question 800×7.2 divide the answer by 735.And you'll get 7.84litre then covert to 0.0m³ if the question says so to get 0.00784
How do you calculate the concentration of obtained solution with 2 solutions having the same concentration but different volume?
^
50.0cm³ of 0.0250 mol/dm³ nitric acid was mixed with 40.0 cm³ of 0.0250 mol dm/³ sulfuric acid.
Using an experimentally determined value (1. 8×10−10) of Ksp, determine the value for the reaction quotient 'Q' if Ag2CrO4 will precipitate when 5. 00 mL of 0. 0040 M AgNO3 are added to 4. 00 mL of 0. 0024 M K2CrO4
The solubility product constant (Ksp) for Ag2CrO4 is given by the following equation:
Ag2CrO4(s) ⇌ 2Ag+(aq) + CrO4^(2-)(aq)
The expression for Ksp is:
Ksp = [Ag+]^2[CrO4^(2-)]
where [Ag+] and [CrO4^(2-)] are the concentrations of the silver ion and chromate ion in the equilibrium mixture, respectively.
To determine the value of Q, the reaction quotient, we need to determine the concentrations of Ag+ and CrO4^(2-) in the mixture of 5.00 mL of 0.0040 M AgNO3 and 4.00 mL of 0.0024 M K2CrO4. To do this, we need to make some assumptions:
1. The volumes of the two solutions are additive, so the total volume is 9.00 mL.
2. The AgNO3 and K2CrO4 solutions react completely to form Ag2CrO4.
First, we need to determine the moles of Ag+ and CrO4^(2-) in each solution:
For the AgNO3 solution:
moles of Ag+ = (0.0040 M) x (0.00500 L) = 2.0 x 10^-5 mol
For the K2CrO4 solution:
moles of CrO4^(2-) = (0.0024 M) x (0.00400 L) = 9.6 x 10^-6 mol
Since the AgNO3 and K2CrO4 react in a 1:1 ratio to form Ag2CrO4, the limiting reactant is K2CrO4. Therefore, all of the CrO4^(2-) is used up in the reaction, and the concentration of CrO4^(2-) in the equilibrium mixture is zero.
The concentration of Ag+ in the equilibrium mixture is:
[Ag+] = moles of Ag+ / total volume of mixture
[Ag+] = (2.0 x 10^-5 mol) / (9.00 x 10^-6 L)
[Ag+] = 2.22 M
Now, we can calculate the value of Q:
Q = [Ag+]^2[CrO4^(2-)] = (2.22 M)^2(0 M) = 0
Since Q is equal to zero and Ksp is greater than zero (1.8 x 10^-10), the reaction is not at equilibrium and Ag2CrO4 will precipitate from the solution.
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ASAP. Magnetic field lines cannot be observed using a compass or iron filings.
True or false
Answer:
false
Explanation:
magnetic field lines can be accurately observed using *iron filling*
C₂H5OH +202 → 2CO2 + 3H₂O + 1367 kJ
What is the ratio between ethanol
and energy of the reaction?
? mole C₂H5OH
kJ
Fill in the green blank.
The ratio between ethanol and energy in this reaction is 1 mole of C₂H5OH which is 1367 kJ.
What is the ratio of a chemical equation?A mole ratio is described as the ratio between the amounts in moles of any two compounds involved in a balanced chemical reaction.
The balanced chemical equation should be able to provide a comparison of the ratios of the molecules necessary to complete the reaction.
In the molar ratio method, a property of a solution is plotted against the molar ratio of the two reactants, the concentration of one being kept constant.
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Answer:
Explanation:
its 1:-1367 you got it right but you need to put the - sign :)
How many grams of CaCl2 would be required to produce a. 750 M solution with a 855 ml volume?
8.32 grams of CaCl2 are required to produce 750 ml of a 0.100 M CaCl2 solution.
The number of moles of solute that can dissolve in 1 L of a solution is known as molarity or molar concentration.
Volume of solution (in litres) / Number of solutes (in moles), or
C = n / V
According to the question,
V = 750 ml and C = 0.100 M
Let's convert millilitres to litres for this.
We know 1 L = 1000 ml
Consequently, 750 ml equals (750/1000) L, or 0.75 L.
So, V = 0.75 L
We know that C = n / V
So, n = C x V
n = 0.100 x 0.75 = 0.075
The solute contains n moles in total.
CaCl2 thus has a mole count of 0.075 moles.
In 750 ml of solution, this demonstrates that there are 0.075 moles of CaCl2.
We must know the molar mass of CaCl2 in order to calculate the mass of CaCl2 in grams.
To do this, we must use the periodic table to determine the atomic masses of each atom.
CaCl2 consists of 1 Ca and 2 Cl atoms.
Atomic mass of Ca is 40.08 g and that of Cl is 35.45, so 2 x 35.45 = 70.90 g.
We obtain the mass of CaCl2 in grams by averaging these measurements.
Hence, mass of CaCl2 = 40.08 + 70.90 = 110.98 g
Thus, 110.98 g equals 1 mole of CaCl2.
Therefore, 0.075 moles of CaCl2 will weigh 8.3235 g, which is rounded to 8.32 g, or 0.075 x 110.98 g.
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The complete question is
How many grams of calcium chloride will be needed to make 750 mL of a 0.100 M CaCl2 solution?
Walking at a brisk pace burns off about 280 cal/h. how long would you have to walk to burn off the calories obtained from eating a cheeseburger that contained 25 g of protein, 25 g of fat, and 31 g of carbohydrates? [hint: one gram of protein or one gram of carbohydrate typically releases about 4 calg, while fat releases 9 cal/g. ] hours
You would need to walk at a brisk pace for about 1 hour and 40 minutes to burn off the calories obtained from eating the cheeseburger.
25 g of protein and 31 g of carbohydrates release 4 cal/g, which equals 240 calories. 25 g of fat release 9 cal/g, which equals 225 calories. So, the total calories in the cheeseburger are 465.
Now, to burn off 465 calories at a rate of 280 cal/h, we need to divide 465 by 280, which equals 1.66 hours or approximately 1 hour and 40 minutes.
In summary, to burn off the calories obtained from a cheeseburger containing 25 g of protein, 25 g of fat, and 31 g of carbohydrates, you would need to walk at a brisk pace for about 1 hour and 40 minutes.
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The valencies of metals X,Y and Z are 1,2 and 3 respectively. What are the formulae of their:. A)hydroxides? b)sulphates? c) carbonates? d) hydrogen carbonates? e)nitrates? f)phosphates?
The formulae of the hydroxides are: X(OH), Y(OH)₂, and Z(OH)₃.
The formulae of the sulphates are: XSO₄, YSO₄, and Z(SO₄)₂.
The formulae of the carbonates are: XCO₃, YCO₃, and Z(CO₃)₂.
The formulae of the hydrogen carbonates are: X(HCO₃), Y(HCO₃)₂, and Z(HCO₃)₃.
The formulae of the nitrates are: X(NO₃), Y(NO₃)₂, and Z(NO₃)₃.
The formulae of the phosphates are: X(PO₄), Y(PO₄)₂, and Z(PO₄)₃.
The valency of a metal tells us how many electrons it can lose or gain in order to form an ion. Using the valencies of metals X, Y, and Z, we can determine the formulae of their compounds with different anions. In each case, we use the appropriate valency of the metal and the valency of the anion to balance the charges of the compound.
For example, in the case of hydroxides, the valency of metal X is 1, which means it can combine with one hydroxide ion (OH⁻) to form a neutral compound, X(OH). Similarly, for metal Y with valency 2, it requires two hydroxide ions to form a neutral compound, Y(OH)₂.
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Help what’s the answer?
The mass of the zinc hydroxide that we need for the reaction is about 21.8 g.
What is the equation of reaction?The equation of a reaction is a chemical equation that represents the chemical change that occurs during a chemical reaction. It is typically written in the form:
Reactants → Products
where the reactants are the starting materials and the products are the substances that are formed as a result of the reaction.
The equation of the reaction is;
Zn(OH)2 + H2SO4 → ZnSO4 + 2H2O
Number of moles of H2SO4 = 21.1 g/98 g/mol
= 0.22 moles
If the reaction is 1:1,
Mass of the Zn(OH)2 required = 0.22 moles * 99 g/mol
= 21.8 g
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When solutions of lead(II) nitrate and potassium carbonate are mixed, a precipitate of lead(II) carbonate forms. Pb(NO3)2 + K2CO3 --> 2KNO3 + PbCO3 (Note: Give all answer with 3 sigfigs).
What is the molarity of the potassium carbonate solution if 50. 2 mL are required to react with 64. 4 mL of 2. 56 M lead(II) nitrate?
The molarity of the potassium carbonate solution is 3.29 M, rounded to three significant figures.
From the balanced chemical equation, we can see that the reaction between lead(II) nitrate and potassium carbonate has a 1:1 stoichiometry. This means that the number of moles of lead(II) nitrate and potassium carbonate that react must be equal.
First, we need to calculate the number of moles of lead(II) nitrate present in the 64.4 mL of 2.56 M solution:
moles of [tex]Pb(NO3)2[/tex] = Molarity x Volume (in L)
moles of [tex]Pb(NO3)2[/tex] = 2.56 M x 0.0644 L
moles of [tex]Pb(NO3)2[/tex] = 0.165 M
Since the stoichiometry of the reaction is 1:1, the number of moles of potassium carbonate must also be 0.165 moles. We can use this information to calculate the molarity of the potassium carbonate solution:
moles of [tex]K2CO3[/tex] = Molarity x Volume (in L)
0.165 mol = Molarity x 0.0502 L
Molarity = 0.165 mol / 0.0502 L
Molarity = 3.29 M
Therefore, the molarity of the potassium carbonate solution is 3.29 M, rounded to three significant figures.
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