An astronomer wants to observe a cloud of dust in a relatively close part of the Galaxy. Unfortunately, this dust cloud is not located in the direction of a crowded region of stars. What instrument would be the most help in finding this cloud. Group of answer choices a visible-light telescope (like the Keck) with a camera or CCD detector a spectroscope that can search for the line radiation from highly ionized atoms an x-ray telescope in orbit around the Earth a sensitive infra-red telescope in orbit around the Earth

Answers

Answer 1

The instrument that would be the most help in finding this cloud is D. a sensitive infra-red telescope in orbit around the Earth.

What is an astronomer?

It should be noted that an astronomer is a scientist who focuses on the study of the Earth.

In this case, the instrument that would be the most help in finding this cloud is a sensitive infra-red telescope in orbit around the Earth.

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Related Questions

NEED ANSWER ASAP!!!! Tony pulls a luggage cart at an angle of 30° to the horizontal. The luggage cart has a mass of 35 kg, and he pulls with a force of 75 N.

a. What is the normal force on the luggage cart?

b. What force would Tony need to apply at a 30° angle to pull the luggage cart completely off the ground?

c. How does your answer in part (b) change as the angle increases?

Answers

a)The normal force on the luggage cart will be 305.85 N

b)The force would Tony needs to apply at a 30° angle to pull the luggage cart willl be 375 N.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration. Mathematically aion in the different components and balancing the equation gets.Components in the x-direction.

Given data;

The angle of pulling with horizontal. =  30°

Mass of luggage cart=35 kg

Pulling force= 75 N

The force in the y-direction;

N+Fsin30° = mg

N+75 sin 30° = 35 × 9.81

N=305.85 N

The force would Tony need to apply at a 30° angle to pull the luggage cart completely off the ground;

N-mg=Fsin30

Fsin30=75 sin 30

Fsin30=375 N

Hence the normal force on the luggage cart and force would Tony need to apply at a 30° angle to pull the luggage cart willl be 305.85 N and 375 N.

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Please, please help i will give 50 points to someone who will help me get this correct!!!!!

Answers

can you write the question because i cant see it

Answer the following questions clearly and thoughtfully.
1. If you were governor of your state...

A. What are two things you would do to protect wetlands? (2 points)

B. What are three important things wetlands can do that make them worth
protecting? (3 points)

I need help

Answers

A) Formulate policies to protect wetlands and ensure that the policies are enforced.

B) Wetlands hold important biodiversity. They are a source of foods, medicines, and raw materials. They help with stabilizing the climate.

Wetlands

As a governor of my state, the two most important steps to protect wetlands include:

Formulate relevant policies through consultation with different stakeholdersEnsure that the policies are enforced.

Wetlands are homes to many important plant, animal, and microbe species. Some of these species serve as foods, raw materials, and medicines for humans and their livestock.Wetlands help sequestrate carbon dioxide and as such, help with the regulation of climate.

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To protect the wetlands, I will ensure a strict enforcement of all existing state laws on the conservation of wetlands.

What are wetlands?

The wetlands are those areas that consists of marshes and swamps. They are of great important to the ecosystem and biodiversity.

a) The two things that I will do to protect wetlands are;

I will ensure that the areas that drain into the wetlands are kept clean from contaminants such as pesticides and other chemicals.I will ensure a strict enforcement of all existing state laws on the conservation of wetlands.

b) Wetlands are very important because;

They are very important in erosion controlThey help to preserve biodiversityThey are important components of the biogeochemical cycles of water, nitrogen and sulfur.

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Questions: 1. A table of weight 500N has four legs covering a total area of 0.5m². Calculate the pressure applied by the table on the ground

2. A man with a mass of 50kg, is standing on the ground. His two feet cover an area of 0.01m². calculate the pressure exerted by his two feet

3. An elephant has a weight of 40000N and her feet cover a total area of 0.5m². A woman weighs 600N and area of her heels in contact with the ground is 0.0075m². Who exerts the greatest pressure on the ground?

Answers

Answer:

shown below

Explanation:

1) P = F/A

P = 500 / 0.5

P = 1000N/m²

2) W = mg

W = 50 x 9.8

W = 490

P = F/A

P = 490 / 0.01

P = 49000N/m²

3) P = F/A

For E:

P = 40000 / 0.5

P = 80000N/m²

For W:

P = 600 / 0.0075

P = 80000N/m²

They're exerting the same amount of pressure on the ground

Which of the following describes an action-reaction pair?
A. You push on a wall, and the wall pushes back on you.
O B. You sit on a chair, and the chair is pulled down by gravity.
O C. A cup pushes down on a table, and the table pushes down on the
ground.
D. The Moon's gravity pulls on Earth, and your gravity pulls on the
Moon.

Answers

Answer:

A) only the wall is involved for both forces (action-reaction)

Siobhan wants to measure the mass of the bag of flour.what should she do?

Answers

Answer:

Weight it in beam balance or any other weight mesuring device

True or false? the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

Answers

True, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

What is electric field?

Electric field is the region of space at which electric force is felt.

E = kq/r²

where;

r is the distance of the charge

at infinite plane, r → ∞, and E = 0

Thus, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

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A football is kicked with an initial velocity of 10 m/s at an angle of 25°. If it hits the ground 1.5s later, how many meters does it travel?

Answers

Answer:

i am pretty sure its 15 m

Explanation:

10 m/s

1.5 seconds

25 angle


10m/1.5s

10x1.5=15

An uncharged spherical conductor hangs by an insulating thread. You bring a negatively charged rod near
from the left side. The net charge on the hanging conductor’s left side is (choose one):

a. Positive

b. Negative

c. Neutral

Answers

Answer:

Positive

This type of charging is called charging by induction

In this the uncharged body gets the opposite type of charge.

when a negatively charged rod is bring near uncharged spherical conductor it attracts positive charge and repels negative charges

so In left side all positive charges appears and in right side all negetive

Types of methods of charging

Charging by contact charging by rubbing charging by induction.

red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because ____.

Answers

Red dwarf stars evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.

What are red dwarf stars?

Red dwarf stars are the smallest and coolest kind of stars on the main sequence.

Red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.

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a balloon of total mass 2200 kg hovers stationary at a height of several meters above the ground. a mass of 200 kg is released from rest from the balloon.calculate the acceleration of the balloon as it starts to rise.

Answers

Answer:

1 m/s²

Explanation:

added in the picture

A point located on the second hand of a large clock has a radial acceleration of 0. 1cm/s2. How far is the point from the axis of rotation of the second hand?

Answers

The distance of the point from the axis of rotation of the second hand is 9.1 m.

Radius of the clock

The point from the axis of rotation of the second hand is the radius of the rotation of the clock.

a = v²/r

v² = ar

v = √ar

V = 2πr/T

√ar = 2πr/T

ar = 4π²r²/T²

a = 4π²r/T²

r = aT²/4π²

r = (0.1 x 60²)/(4π²)

r = 9.1 m

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You are on a boat in a fog and know there are cliffs ahead of you somewhere, but you cannot see them. you use your fog horn to send out a blast of sound (assume the temperature of the air is 20 oc) and the time it takes for the sound to return to you is 20.0 s. how far away are the cliffs (in metric units)

Answers

The distance of the cliff from where you are is determined as 3,430 m.

Distance of the cliff

Apply the formula for echo.

v = 2d/t

where;

v is speed of sound at 20 ⁰C = 343 m/sd is distance = ?t is time = 20 s

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

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You pushes a 25kg box with 40 N of force, but the friction on the crate is 15 N. What is the net
force?

Answers

Answer:

25 N  in the direction of your push

Explanation:

The friction force acts against your pushing force....it reduces the net amount of force you are exerting

Net force =  40 - 15 = 25 N  

A train is traveling west at a velocity of 25 m/s. Another train is traveling east directly toward the west-bound train at a velocity of 15 m/s. The west-bound train blows its whistle with a frequency of 600 Hz when the two trains are 1000 m apart and then blows its whistle again 10 seconds later. For passengers on the east-bound train, how will the perceived frequency of the first whistle compare with the perceived frequency of the second whistle

Answers

(a) The frequency observed by the passenger on the east-bound train when they are 1000 m apart is 675.5 Hz.

(b) After 10 seconds, the frequency observed by the passenger on the east-bound train will be greater than the frequency observed when they are 1000 m apart.

Observed frequency

The frequency observed by the passenger on east-bound train is calculated by applying Doppler shift formula.

[tex]f = f_0(\frac{v \pm v_0}{v\pm v_s} )[/tex]

where;

f is observed frequencyf₀ is original frequency or source frequencyv is speed of soundv₀ is speed of observer (positive when moving towards source)vs is source frequency (negative when moving towards observer)

when the two trains are 1000 m apart

[tex]f = 600(\frac{343 +15}{343-25} )\\\\f = 675.5 \ Hz[/tex]

The frequency observed by the passenger increases with decrease in distance between the two trains.

Thus, after 10 seconds, the frequency observed by the passenger on the east-bound train will be greater than the frequency observed when they are 1000 m apart.

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Which would most likely cause a decrease in the rate of energy production in a fusion nuclear reactor? a drop in the temperature in the reactor an increase in the number of neutrons in the reactor an increase in the amount of nuclear fuel used in the reactor a drop in the number of reactions that involve the splitting of nuclei

Answers

A drop in temperature would most likely result in a decline in the rate of energy production in a fusion nuclear reactor.

What is nuclear power?

The utilization of nuclear reactions to generate energy is known as nuclear power.

Nuclear power facilities produce the great bulk of the electricity generated by nuclear fission of uranium and plutonium.

The environment should be hot enough for the deuterium and tritium ions' kinetic energies to be sufficient to break through the Coulomb barrier and fuse together.

Therefore, a decrease in temperature would most likely cause a decrease in the rate of energy production in a fusion nuclear reactor.

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A football is kicked with an initial velocity of 10 m/s at an angle of 25 degrees. If it hits the ground 1.5s later, how many meters does it travel?

Answers

The distance travelled by the ball, given the data is 7.82 m

Data obtained from the questionInitial velocity (u) = 10 m/sAngle of projection (θ) = 25 degrees Time of flight (T) = 1.5 sAcceleration due to gravity (g) = 9.8 m/s²Range (R) = ?

How to determine the range

The range (i.e distance) travelled by the ball can be obtained as illustrated below:

R = u²Sine(2θ) / g

R = 10² × Sine (2×25) / 9.8

R = 10² × Sine 50 / 9.8

R = 7.82 m

Thus, the distance travelled by the ball is 7.82 m

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Two skaters, a man and a woman, are standing on ice. Neglect any friction between the skate blades and the ice. The mass of the man is 89 kg, and the mass of the woman is 59 kg. The woman pushes on the man with a force of 46 N due east. Determine the acceleration (magnitude and direction) of (a) the man and (b) the woman

Answers

Answer:

Acceleration of this man: approximately [tex]0.52\; {\rm m\cdot s^{-1}}[/tex] due east.

Accelerate of this woman: approximately [tex]0.78\; {\rm m \cdot s^{-1}}[/tex] due west.

Explanation:

The question implies that the net force on the man is [tex]F = 46\; {\rm N}[/tex] due east. The mass of the man is [tex]m = 89 \; {\rm kg}[/tex]. The acceleration of the man would be:

[tex]\begin{aligned} a &= \frac{F}{m} \\ &= \frac{46\; {\rm N}}{89\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{due east})}{} \\ &\approx 0.52\; {\rm m\cdot s^{-2}} && (\text{due east})\end{aligned}[/tex].

In other words, the acceleration of this man would be approximately [tex]0.52\; {\rm m \cdot s^{-2}}[/tex] due east (same direction as the net force.)

By Newton's Laws of Motion, for every force there is a reaction force that is equal in magnitude but opposite in direction.

The woman in this question is applying a due east [tex]46\; {\rm N}[/tex] force on the man. Thus, this woman would experience a reaction force of the same magnitude ([tex]46\; {\rm N}\![/tex]) and opposite direction (due west) from the man. Under assumptions of the question, the net force on the woman would be [tex]\! 46\; {\rm N}[/tex] due west.

The acceleration of this [tex]m = 59\; {\rm kg}[/tex] woman would be:

[tex]\begin{aligned} a &= \frac{F}{m} \\ &= \frac{46\; {\rm N}}{59\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{due west})}{} \\ &\approx 0.78\; {\rm m\cdot s^{-2}} && (\text{due west})\end{aligned}[/tex].

What is nuclear power

Answers

Answer:

D. All of the statements describe nuclear power

What is NUCLEAR POWER?

➡️ is the use of nuclear reactions to produce electricity.

➡️ it can be obtained from nuclear fission, nuclear decay and nuclear fusion reactions.

Hope it helps

briefly describe how the micrometre screw gauge is used​

Answers

Answer:

the micrometre screw gauge is used​ for making precise linear measurements (e.g to measure diameter of a wire)

What are the characteristics of the image formed by the object?

Answers

Answer:

The image is formed by a convex lens with the object at 2F.

Image will be of same size as the objectImage will be real and upside down.

Sample Response: The image created by the object is located on 2F behind the lens, real, inverted, and the same size as the actual object. 

Explanation: EDGE.

Can anyone please answer this cq..

Answers

Hqisgshsjsvg udyfudueuduutuufududuydd

Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm.

Answers

The ray diagram for the given object consists of 2 cm height of object, 4 cm object distance and 3 cm focal length.

Image formed by a diverging lens

Diverging lens is called a concave lens. The working of the lens is dependent on the refraction of the light rays as they pass through the lens.

Image formed by a diverging lens is always virtual, erect and diminished; smaller than the object and is located on the same side of the lens as the object.

The ray diagram for the given object is presented in the image in the diagram.

Object height = 2 cmFocal length = 3 cmObject distance = 4 cm

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the range of diameters and luminosities displayed by elliptical galaxies is ____.

Answers

The range of diameters and luminosities displayed by elliptical galaxies is 3000 to 700,000 light years and Mv-23 down to Mv- -16 mag respectively

What are elliptical galaxies?

Elliptical galaxies are type of galaxies with a smooth ellipsoidal shape.

They are the most abundant galaxies in the universe.

Their diameter ranges from 3, 000 to 700, 000 light years.

Their luminosity ranges from Mv-23 down to Mv- -16 mag

Therefore, the range of diameters and luminosities displayed by elliptical galaxies is 3000 to 700,000 light years and Mv-23 down to Mv- -16 mag respectively.

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The average distance from Earth to the Moon is 384,000 km. How many days would it take, traveling at 800 km/h (the typical speed of a jet), to reach the Moon

Answers

Answer:

20 days, 480 hours

A spring with constant 185 N/m is compressed 1.38 m with a mass of 0.53 kg. How fast is it going 2.5 m above the ground?

Answers

The velocity 2.5 m above the ground will be 49.07 m/sec.

What is spring force?

The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;

F = kx

The formula for force is;

F=ma

Equating both the equation;

ma = kx

a=kx/m

a=( 185 N/m × 1.38 m) / 0.53

a  = 481.6 m/s²

The speed is found by Newton's third equation of motion;

v²=u²+2as

v²=0+2as

v²=2 × 481.6 m/s² × 2.5 m

v = 49.07 m/sec

Hence the velocity 2.5 m above the ground will be 49.07 m/sec.

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Perform the following mathematical operation and report answer to the correct number of significant figures 143.6 divided by 21.2

Answers

The answer to the correct number of significant figures is 6.774.

What is quotient?

When a number(big) divided smaller number, the answer obtained greater than zero is called a quotient.

Divide 143.6 ÷ 21.2

143.6/21.2 = 1436/212

                  =6.77358

The quotient is rounded to three significant figures after decimal

143.6 ÷ 21.2 = 6.774

Thus, the answer to the correct number of significant figures is 6.774

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a traffic light at an intersection is hanging from two wires of equal length making angles of 10 degrees below the horitzontal. The traffic light weights 2500 N. What are the tensions in the wires

Answers

The tensions in the wires at the given angle of inclination is determined as 434.1 N.

Tension on the wire

The tension in the wires is calculated as follows;

T = Wsinθ

where;

T is tension in each wireW is weight of the traffic light

T = 2500 x sin(10)

T = 434.1 N

Thus, the tensions in the wires at the given angle of inclination is determined as 434.1 N.

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ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. In working this problem, assume the value of "g" to be 9.8 m/s2 with two (2) significant digits unless otherwise stated. Calculate the increase in potential energy of a 60.0-kg man who climbs a ladder 10.0 meters high.
5880
600
58,800

Answers

The increase in potential energy of a 60.0-kg man who climbs a ladder 10.0 meters high is 5,880 J.

Increase in the potential energy of the man

The increase in the potential energy of the man is calculated as follows;

P.E = mgh

where;

m is mass of the manh is height attained by the mang is acceleration due to gravity

P.E = 60 x 9.8 x 10

P.E = 5,880 J

Thus, the increase in potential energy of a 60.0-kg man who climbs a ladder 10.0 meters high is 5,880 J.

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What would be the effect of adding a proton to a nucleus?
A. It would increase the strong nuclear force and increase the
electrostatic force.
B. It would decrease the strong nuclear force and decrease the
electrostatic force.
C. It would increase the strong nuclear force and decrease the
electrostatic force.
D. It would decrease the strong nuclear force and increase the
electrostatic force.

Answers

Answer:

A

Explanation:

The electrostatic force and strong nuclear force are opposite forces. The electrostatic force causes the repulsion beteween the positively charged protons in the nucleus but the strong force keeps the nucleus glued together but overcoming the electrostatic force. They would both increase upon the addition of a proton or radioactivity will result.

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