The art studio can offer a maximum of 8 painting classes and 5 pottery classes per week, while still meeting the time constraint and earning at least $1000 per week.
To find the maximum number of classes the art studio can offer per week, we need to set up an equation based on the time constraint.
Let's assume that the studio offers x painting classes and y pottery classes per week. Since each painting class is 1 hour long and each pottery class is 1.5 hours long, the total time spent on classes can be represented by the equation:
1x + 1.5y ≤ 40
This equation states that the total number of hours spent on painting classes (1x) plus the total number of hours spent on pottery classes (1.5y) must be less than or equal to 40 hours per week.
To find the minimum revenue the art studio can earn per week, we can set up another equation based on the cost of each class and the minimum revenue requirement.
Let's assume that each painting or pottery class costs $35. Then the total revenue earned per week can be represented by the equation:
35x + 35y ≥ 1000
This equation states that the total revenue earned from painting classes (35x) plus the total revenue earned from pottery classes (35y) must be greater than or equal to $1000 per week.
Now we have two equations:
1x + 1.5y ≤ 40
35x + 35y ≥ 1000
We can use these equations to find the maximum number of classes the art studio can offer per week.
To do this, we can graph the two equations on the same coordinate plane and find the point where they intersect.
When we do this, we get the point (x, y) = (8, 16/3).
This means that the art studio can offer a maximum of 8 painting classes and 16/3 (or approximately 5.33) pottery classes per week, while still meeting the time constraint and earning at least $1000 per week.
Note that since the studio can only offer one class at a time, they would need to round down the number of pottery classes to 5 in order to offer a whole number of classes per week.
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An experiment involving learning in animals requires placing white mice and rabbits into separate, controlled environments: environment I and environment II. The maximum amount of time available in environment I is 420 minutes, and the maximum amount of time available in environment II is 600 minutes. The white mice must spend 10 minutes in environment I and 25 minutes in environment II, and the rabbits must spend 12 minutes in environment I and 15 minutes in environment II. Find the maximum possible number of animals that can be used in the experiment and find the number of white mice and the number of rabbits that can be used.
We find that the maximum possible number of animals is 37, with 17 white mice and 20 rabbits.
Let's use the following variables:
x be the number of white mice
Let y be the number of rabbits
Based on the given information, we can create the following system of linear inequalities:
10x + 12y ≤ 420 (maximum time available in environment I)
25x + 15y ≤ 600 (maximum time available in environment II)
We also have the constraints that x and y must be non-negative integers.
To solve this problem, we can use a graphing approach. We can graph each inequality on the same coordinate plane and shade the region that satisfies all the constraints. The feasible region will be the region that is shaded.
However, since x and y must be integers, we need to find the corner points of the feasible region and test each one to see which one gives us the maximum value of x + y.
To find the corner points, we can solve each inequality for one variable and then substitute into the other inequality:
For the first inequality: 12y ≤ 420 - 10x, so y ≤ (420 - 10x)/12
For the second inequality: 15y ≤ 600 - 25x, so y ≤ (600 - 25x)/15
Since y must be a non-negative integer, we can use the floor function to round down to the nearest integer:
For the first inequality: y ≤ ⌊(420 - 10x)/12⌋
For the second inequality: y ≤ ⌊(600 - 25x)/15⌋
We can then plot these two expressions on the same graph and find the points where they intersect. We can then test each point to see if it satisfies all the constraints and if it gives us the maximum value of x + y.
After doing all the calculations, we find that the maximum possible number of animals is 37, with 17 white mice and 20 rabbits.
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A bracelet is now reduced to £420.this is 70% of the original price. what is the original price?
Answer:
.70p = £420, so p = £600
The original price of the bracelet is £600.
The original price of the bracelet was £600.
To find the original price of the bracelet, we need to use the information that the current price is 70% of the original price. We can use algebra to solve for the original price:
Let X be the original price of the bracelet.
70% of X is equal to £420.
We can write this as:
0.7X = £420
To solve for X, we can divide both sides of the equation by 0.7:
X = £420 ÷ 0.7
Evaluating the right-hand side gives us:
X = £600
Therefore, the original price of the bracelet was £600.
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please help i need this asap
All the value of angles are,
⇒ ∠a = 118°
⇒ ∠b = 62°
⇒ ∠q = 84°
⇒ ∠v = 84°
Given that;
Two parallel lines t₁ and t₂ are shown in image.
Here, we have;
Apply the definition of corresponding angles,
∠d = 180 - 62
∠d = 118°
Hence, By definition of vertically opposite angles,
⇒ ∠a = 118°
And,
∠b = 180 - 118°
∠b = 62°
Apply the definition of corresponding angles,
∠q = 180 - 96
∠q = 84°
Hence, By definition of vertically opposite angles,
⇒ ∠v = 84°
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Consider the geometric series 1 - x/3 - x^2/9 - x^3/27......
What is the common ratio of the series and for what values of x will the series converge? Determine the function f representing the sum of the series.
The function f representing the sum of the series for x in the interval (-3, 3). Hi! The given geometric series is 1 - x/3 - x^2/9 - x^3/27...
The common ratio of the series is obtained by dividing a term by its preceding term. Let's consider the first two terms:
(-x/3) / 1 = -x/3
Therefore, the common ratio (r) of the series is -x/3.
For a geometric series to converge, the absolute value of the common ratio must be less than 1, i.e., |r| < 1. In this case:
|-x/3| < 1
To find the values of x for which the series converges, we need to solve the inequality:
-1 < x/3 < 1
Multiplying all sides by 3, we get:
-3 < x < 3
So, the series converges for x in the interval (-3, 3).
Now, let's determine the function f representing the sum of the series. For a converging geometric series, the sum S can be calculated using the formula:
S = a / (1 - r)
where a is the first term and r is the common ratio. In this case, a = 1 and r = -x/3. Therefore:
f(x) = 1 / (1 - (-x/3))
f(x) = 1 / (1 + x/3)
This is the function f representing the sum of the series for x in the interval (-3, 3).
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What is the equation, in slope-intercept form, of the line that passes through
(0, 5) and has a slope of -1? (6 points)
Oy=-x-5
Oy=x+5
Oy=-x+5
Oy=x-5
Answer:
C) y = - x + 5---------------------------
The given point (0, 5) represents the y-intercept and we have a slope of -1.
It translates as:
m = - 1, b = 5 in the slope-intercept equation of y = mx + bBy substituting we get equation:
y = - x + 5This is option C.
If (arc)mEA=112* and m
If angle of arc EA is 112 degrees then value of arc IV is 36 degrees by outside angles theorem
Given that Arc EA measure is One hundred twelve degrees
By Outside Angles Theorem states that the measure of an angle formed by two secants, two tangents, or a secant and a tangent from a point outside the circle is half the difference of the measures of the intercepted arcs
(112-x)/2=38
112-x=38×2
112-x=76
112-76=x
36 degrees = angle IV or x
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A cement walkway is in the shape of a rectangular prism. The length is 10 feet, the width is three feet and the depth is 1.5 feet. How much cubic feet of cement will they need?
The volume of cement in cubic feet that will be needed is 45 cubic feet.
What is volume?Volume is the space occuppied by an object.
To calculate the volume of cement in cubic feet that will be needed, we use the formula below
Formula:
V = lwh....................... Equation 1Where:
V = Volume of the cement that is neededl = Length of the walkwayw = width of the walkwayh = depth of the walkwayFrom the question,
Given:
l = 10 feetw = 3 feeth = 1.5 feetSubstitute these values into equation 1
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Last question :) btw if u can’t tell the equation there is 6x+68
Answer:
The answer for x is 2
z is 100°
Step-by-step explanation:
80=6x+68
6x=80-68
6x=12
divide both sides by 6
6x/6=12/6
x=2
z=?(empty space)
?(empty space)=z
80+z+z+6x+68=360
Note:6x+68=80
80+80+2z=360
160+2z=360
2z=360-160
2z=200
divide both sides by 2
2z/2=200/2
z=100°
Shannon's net worth is $872. 17 and her liabilities are $15,997. If she pays off a credit card with a balance of $7,698, what is her new net worth?
Answer:
To calculate Shannon's new net worth after paying off her credit card, we need to subtract the credit card balance from her total liabilities, and then subtract the result from her net worth:
New liabilities = $15,997 - $7,698 = $8,299
New net worth = $872.17 - $8,299 = -$7,426.83
Based on these calculations, Shannon's new net worth would be -$7,426.83 after paying off her credit card. This indicates that her liabilities still exceed her assets, and she would need to continue working towards reducing her debt and increasing her net worth over time.
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17. What number is not part of the solution set to the
inequality below?
w - 10 < 16
A. 11
B. 15
C. 26
D. 27
Answer:
Step-by-step explanation:
To find the solution set to the inequality w - 10 < 16, we can solve for w by adding 10 to both sides of the inequality:
w - 10 + 10 < 16 + 10 w < 26
This means that any number less than 26 is part of the solution set to the inequality. So, out of the given options, the number that is not part of the solution set is D. 27 because it is greater than 26.
Sushi corporation bought a machine at the beginning of the year at a cost of $39,000. the estimated useful life was five years and the residual value was $4,000. required: complete a depreciation schedule for the straight-line method. prepare the journal entry to record year 2 depreciation.
Entry debits the Depreciation Expense account for $7,000 and credits the Accumulated Depreciation account for the same amount, reflecting the decrease in the value of the machine over time.
To calculate deprecation using the straight- line system, we need to abate the residual value from the original cost of the machine and also divide the result by the estimated useful life. Using the given values, we have
Cost of machine = $ 39,000
Residual value = $ 4,000
Depreciable cost = $ 35,000($ 39,000-$ 4,000)
Estimated useful life = 5 times
To calculate the periodic deprecation expenditure, we divide the depreciable cost by the estimated useful life
Periodic deprecation expenditure = $ 7,000($ 35,000 ÷ 5)
Depreciation Expense $7,000
Accumulated Depreciation $7,000
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The journal entry is as given in figure:
In ABC, the bisector of A divides BC into segment BD with a length of
28 units and segment DC with a length of 24 units. If AB -31. 5 units, what
could be the length of AC ?
To find the length of AC in triangle ABC, we will use the Angle Bisector Theorem and the given information:
In triangle ABC, the bisector of angle A divides BC into segments BD and DC, with lengths of 28 units and 24 units, respectively. Given that AB has a length of 31.5 units, we want to determine the possible length of AC.
Step 1: Apply the Angle Bisector Theorem, which states that the ratio of the lengths of the sides is equal to the ratio of the lengths of the segments created by the angle bisector. In this case, we have:
AB / AC = BD / DC
Step 2: Plug in the known values:
31.5 / AC = 28 / 24
Step 3: Simplify the ratio on the right side:
31.5 / AC = 7 / 6
Step 4: Cross-multiply to solve for AC:
6 * 31.5 = 7 * AC
Step 5: Calculate the result:
189 = 7 * AC
Step 6: Divide both sides by 7 to find AC:
AC = 189 / 7
Step 7: Calculate the value of AC:
AC = 27 units
So, the length of AC in triangle ABC could be 27 units.
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A sheet of dough has six identical circles cut from
it. Write an expression in factored form to represent the
approximate amount of dough that is remaining. Is
there enough dough for another circle
Approximate amount of dough that is remaining. Is (length - 2r)(width - 3r) - 6πr^2.
Without the size of the original sheet of dough or the size of the circles cut from it, it's not possible to give an exact expression. However, assuming that each circle has the same radius of 'r' and the original sheet of dough was a rectangle, we can write an expression in factored form for the remaining area of the dough:
Remaining area of dough = (Area of original rectangle) - 6(Area of circle)
= (length x width) - 6(πr^2)
= (length - 2r)(width - 3r) - 6πr^2
Whether there is enough dough for another circle would depend on the size of the circles and the original sheet of dough.
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Let f(x) = 2 sqrt(x)/8x^2 + 3x – 9
Evaluate f’(x) at x = 4.
The derivative of the function f(x) = 2 \sqrt(x) / (8x² + 3x - 9) evaluated at x = 4.
To find f'(x), we need to differentiate the given function f(x) using the power rule and the chain rule of differentiation.
First, we can rewrite the function f(x) as:
f(x) = 2x^{1/2} / (8x² + 3x - 9)
Next, we can differentiate f(x) with respect to x:
f'(x) = d/dx [2x^{1/2} / (8x² + 3x - 9)]
Using the quotient rule of differentiation, we have:
f'(x) = [ (8x² + 3x - 9) d/dx [2x^{1/2}] - 2x^{1/2} d/dx [8x² + 3x - 9] ] / (8x² + 3x - 9)²
Applying the power rule of differentiation, we have:
f'(x) = [ (8x² + 3x - 9)(1/2) - 2x{1/2}(16x + 3) ] / (8x² + 3x - 9)²
Now we can evaluate f'(x) at x = 4 by substituting x = 4 into the expression for f'(x):
f'(4) = [ (8(4)² + 3(4) - 9)(1/2) - 2(4)^(1/2)(16(4) + 3) ] / (8(4)² + 3(4) - 9)²
f'(4) = [ (128 + 12 - 9)(1/2) - 2(4)^(1/2)(67) ] / (128 + 12 - 9)^2
f'(4) = [ 131^(1/2) - 2(4)^(1/2)(67) ] / 12167
Therefore, f'(4) = [ 131^(1/2) - 134(2)^(1/2) ] / 12167.
This is the value of the derivative of f(x) at x = 4.
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Pleas help im stuck on this question and im too afraid to get it wrong
Step-by-step explanation:
g(x) is just f(x) shifted UP three units ...so
g(x) = f(x) +3
In Angle STU, the measure of U=90°, the measure of S=31°, and TU = 77 feet. Find the
length of US to the nearest tenth of a foot
If in Angle STU, the measure of U=90°, the measure of S=31°, and TU = 77 feet, then the length of US to the nearest tenth of a foot is approximately 39.4 feet.
In angle STU, we have a right triangle with U=90°, S=31°, and TU=77 feet. To find the length of US, we can use the sine function:
sin(S) = opposite side (US) / hypotenuse (TU)
sin(31°) = US / 77 feet
To find the length of US, multiply both sides by 77 feet:
US = 77 feet * sin(31°)
US ≈ 39.4 feet
Therefore, the length of US to the nearest tenth of a foot is approximately 39.4 feet.
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What is the meaning of a relative frequency of 0. 56
A relative frequency of 0.56 means that out of the total number of observations in a given sample or population, 56% of those observations belong to a particular category or have a certain characteristic.
In other words, it is the proportion or fraction of the observations that fall into that particular category or have that characteristic, relative to the total number of observations. For example, if we had a sample of 100 people and 56 of them had brown hair, then the relative frequency of brown hair would be 0.56 or 56%.
To calculate relative frequency, you divide the frequency of a specific event or category by the total number of observations. In this case, the specific event or category occurs 56% as often as the total events or categories observed.
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50 POINTS ASAP Polygon ABCD with vertices at A(−4, 6), B(−2, 2), C(4, −2), and D(4, 4) is dilated using a scale factor of five eighths to create polygon A′B′C′D′. If the dilation is centered at the origin, determine the vertices of polygon A′B′C′D′.
A′(5.8, −3), B′(1.6, −1.5), C′(−1.6, 3), D′(2.5, 3)
A′(−16, 24), B′(−8, 8), C′(16, −24), D′(16, 16)
A′(2.5, −3.75), B′(1.25, −1.25), C′(−2.5, 1.25), D′(−2.5, −2.5)
A′(−2.5, 3.75), B′(−1.25, 1.25), C′(2.5, −1.25), D′(2.5, 2.5)
Answer:
A′(−2.5, 3.75), B′(−1.25, 1.25), C′(2.5, −1.25), D′(2.5, 2.5)
Step-by-step explanation:
in the described situation you only need to multiply the coordinates by the scale factor (in our case the given 5/8)
A (-4, 6) turns into
A' (-4×5/8, 6×5/8) = A' (-2.4, 3.75)
and therefore we know already here that all the other answer options are wrong.
Shelby was in the next stall, and she needed 150 mL of a solution that was 30% glycerin. The two solutions available were 10% glycerin and 40% glycerin. How many milliliters of each should Shelby use?
Taking the data into consideration, Shelby should use 50 mL of the 10% glycerin solution and 100 mL of the 40% glycerin solution, as explained below.
How to find the amountsLet x be the amount of 10% glycerin solution and y be the amount of 40% glycerin solution that Shelby needs to use. We know that Shelby needs a total of 150 mL of the 30% glycerin solution, so we can write:
x + y = 150 (equation 1)
We also know that the concentration of glycerin in the 10% solution is 10%, and the concentration of glycerin in the 40% solution is 40%. So, the amount of glycerin in x mL of the 10% solution is 0.1x, and the amount of glycerin in y mL of the 40% solution is 0.4y. The total amount of glycerin in the 150 mL of 30% solution is 0.3(150) = 45 mL. So, we can write:
0.1x + 0.4y = 45 (equation 2)
We now have two equations with two variables. We can use substitution or elimination to solve for x and y. Here, we'll use elimination. Multiplying equation 1 by 0.1, we get:
0.1x + 0.1y = 15 (equation 3)
Subtracting equation 3 from equation 2, we get:
0.3y = 30
y = 100
Substituting y = 100 into equation 1, we get:
x + 100 = 150
x = 50
Therefore, Shelby needs to use 50 mL of the 10% glycerin solution and 100 mL of the 40% glycerin solution.
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What is the volume of the prism, measured in cubic inches
Answer:
360 cubes
Step-by-step explanation:
A student takes a measured volume of 3. 00 m hcl to prepare a 50. 0 ml sample of 1. 80 m hcl. What volume of 3. 00 m hcl did the student use to make the sample?.
The student used 30.0 mL of 3.00 M HCl to make the 50.0 mL sample of 1.80 M HCl.
To find the volume of 3.00 M HCl needed to make a 50.0 mL sample of 1.80 M HCl, we can use the equation:
M₁V₁ = M₂V₂
Where M₁ is the initial concentration, V₁ is the initial volume, M₂ is the final concentration, and V₂ is the final volume.
We are given M₁ = 3.00 M, M₂ = 1.80 M, and V₂ = 50.0 mL. We can rearrange the equation to solve for V₁:
V₁ = (M₂V₂) / M₁
V₁ = (1.80 M * 50.0 mL) / 3.00 M
V₁ = 30.0 mL
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As a candle burns, its wick gets smaller over time. When first purchased, the wick is 150 mm in length. After 50 minutes, the wick is only 110 mm in length. Find the slope you would use in a linear model of mm per minute. 3 points Construct an equation that models the length of the wick over this time period. Your answer should be in the proper form using correct letters and numbers with no spaces. 2 points Use your linear model to predict the how many minutes it would take to have 74 mm remaining. 3 points
It would take approximately 95 minutes for the wick to have 74 mm remaining.
1) Finding the slope (mm per minute):
The wick was initially 150 mm in length and reduced to 110 mm after 50 minutes. To find the slope, we use the formula:
Slope = (change in length) / (change in time)
Slope = (110 mm - 150 mm) / (50 minutes - 0 minutes)
Slope = (-40 mm) / (50 minutes)
Slope = -0.8 mm/minute
2) Constructing the linear equation:
We now have the slope (-0.8) and the initial length (150 mm) to create a linear equation:
Length (L) = initial length + slope × time (t)
L = 150 - 0.8t
3) Predicting the time to have 74 mm remaining:
To find the time, plug in 74 mm for the length (L) in the equation and solve for t:
74 = 150 - 0.8t
76 = 0.8t
t = 95 minutes
So, it would take approximately 95 minutes for the wick to have 74 mm remaining.
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In May, the cost for a child is not changed. The cost for an adult is reduced by p % to $22.10. (i) Calculate p.
The cost for an adult is reduced by approximately 26.33% to $22.10.
How to solveThe original cost for an adult ticket (X) = $30
The reduced cost for an adult ticket = $22.10
We need to find the percentage decrease (p) from the original cost to the reduced cost:
p = ((Original cost - Reduced cost) / Original cost) * 100
p = (($30 - $22.10) / $30) * 100
p = ($7.90 / $30) * 100
p ≈ 26.33 %
The fee for an adult has notably decreased by approximately 26.33%, now costing a mere $22.10.
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In May, the cost for a child is not changed. The cost for an adult is reduced by p % to $22.10. If the original cost of an adult ticket is $X, (i) calculate p, given that the original cost for an adult ticket is $30.
thank you !!!!!!!! (Choose ALL answers that are correct)
Answer:
a and b
Step-by-step explanation:
Given the center, a vertex, and one focus, find an equation for the hyperbola:
center: (-5, 2); vertex (-10, 2); one focus (-5-√29,2).
The equation of the hyperbola is -(x + 5)²/71 + (y - 2)² = -71
How to calculate the valueWe can also find the distance between the center and the given focus, which is the distance between (-5, 2) and (-5 - √29, 2):
d = |-5 - (-5 - √29)| = √29
Substituting in the known values, we get:
c² = a² + b²
(√29)² = (10)² + b²
29 = 100 + b²
b² = -71
(x - h)²/a² - (y - k)²/b² = 1
where (h, k) is the center of the hyperbola.
Substituting in the known values, we get:
(x + 5)²/100 - (y - 2)²/-71 = 1
Multiplying both sides by -71, we get:
-(x + 5)²/71 + (y - 2)²/1 = -71/1
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In 1680, Isaac Newton, scientist astronomen, and mathematician, used a comet visible from Earth to prove that some comers follow a parabolic path through space as they travell around the sun. This and other discoveries like it help scientists to predict past and future positions of comets.
Comets could be visible from Earth when they are most likely to fall down into earth
When solving the equation 6x² - 2x = -3 with the quadratic formula.
If a = 6, what are the values of b and c?
b =
C =
A/
3. let f be a differentiable function on an open interval i and assume that f has no local minima nor local maxima on i. prove that f is either increasing or decreasing on i.
Shown that if f has no local minima nor local maxima on i, then f is either increasing or decreasing on i.
Since f has no local minima nor local maxima on i, it means that for any point x in i, either f is increasing or decreasing in a small interval around x. In other words, either f'(x) > 0 or f'(x) < 0 for all x in i.
Now suppose there exist two points a and b in i such that a < b and f(a) < f(b). We want to show that f is increasing on i.
Consider the interval [a,b]. By the Mean Value Theorem, there exists a point c in (a,b) such that f'(c) = (f(b) - f(a))/(b - a). Since f(a) < f(b), we have (f(b) - f(a))/(b - a) > 0, which implies f'(c) > 0. Since f'(x) > 0 for all x in i, it follows that f is increasing on [a,c] and on [c,b]. Therefore, f is increasing on i.
A similar argument can be made if f(a) > f(b), which would imply that f is decreasing on i.
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Is the following data an example of a linear function?
Answer:
Yes
Step-by-step explanation:
Yes, because its graph represents a straight line
A punch recipe requires 2 cups of cranberry juice to make 3 gallons of punch. Using the same recipe, what is the amount of cranberry juice needed for 1 gallon of punch?
Answer:
To make 3 gallons of punch, you need 2 cups of cranberry juice.
We can set up a proportion to find out how much cranberry juice is needed for 1 gallon of punch:
2 cups / 3 gallons = x cups / 1 gallon
To solve for x, we can cross-multiply:
2 cups * 1 gallon = 3 gallons * x cups
2 cups = 3x
x = 2/3 cup
Therefore, you would need 2/3 cup of cranberry juice to make 1 gallon of punch using this recipe.