An 8.20 kg object is pulled along a horizontal surface by a force of 22.0 N. If its acceleration is 1.1 m/s2, what is the coefficient of friction between the two surfaces?

Answers

Answer 1

Answer:

0.5

Explanation:

In this picture,

An 8.20 Kg Object Is Pulled Along A Horizontal Surface By A Force Of 22.0 N. If Its Acceleration Is 1.1

Related Questions

gravitational potential is the energy due to an object's:
a. motion
b. spring stretch or compression
c. position in a gravity field
d. chemical bonds.​

Answers

position in a gravitation field (c)

Answer:

The answer is C. position in a gravity field

In which direction does the magnetic field in the center of the coil point?

A. Left
B. Down
C. Right
D. Up

Answers

I believe that it most likely would be C,

The direction of the magnetic field in the center of the coil point towards the up. So, the correct option is D.

What is right-hand grip rule ?

Right-hand grip rule states that, if you are holding a current carrying conductor with your right hand, such that the curled fingers point towards the direction of current flowing through the conductor, then the thumb will point towards the direction of the magnetic field.

Here,

From the current carrying conductor given,

The current is flowing through the conductor in a direction from left to right or it can be said as, the current is flowing in a clockwise direction.

So, we can apply the right-hand grip rule in this conductor.

According to the right-hand grip rule, stretch the thumb of the right hand and point it towards the direction of flow of current in the conductor. Then the remaining curled fingers will be pointed upwards in the conductor.

Hence,

The direction of the magnetic field in the center of the coil point towards the up.

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determine the total voltage in the circuit below the ammeter is reading 4 A

Answers

Answer:

6 V.

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 3 Ω

Resistor 2 (R₂) = 3 Ω

Equivalent Resistance (R) =?

Since the two resistor are in parallel connection, the equivalent resistance can be obtained as:

R = (R₁ × R₂) / (R₁ + R₂)

R = (3 × 3) / (3 + 3)

R = 9/6

R = 1.5 Ω

Finally, we shall determine the total voltage in the circuit. This can be obtained as follow:

Current (I) = 4 A

Equivalent Resistance (R) = 1.5 Ω

Total voltage (V) =?

V = IR

V = 4 × 1.5

V = 6 V

Thus, the total voltage in the circuit is 6 V

Proton traveling across a capacitor A proton enters with a velocity v between the plates of a capacitor as shown in the figure. What is the direction of the magnetic field needed so that the proton continues its trajectory, undeflected? Explain each step of your reasoning.

Answers

Answer:

Please see the direction of force in the attachment

Explanation:

As the particle enters the capacitor, it experiences electric. In order to move in the same direction as the electron was moving before entering the capacitor, the force due to the electric field of capacitor must be balanced by the magnetic field.

The direction of particle is shown in the attachment.

As we know,

Force = q (v *B)

the ice and steam point on a thermometer are found to be 96ml apart. what temperature is recorded when the length of mercury thread is 33.6ml above the ice point

Answers

Answer:

33.6 / 96   is the fraction of the temperature between ice and freezing

33.6 / 96 = .35

So C = .35 * 100 = 35 deg C  where the ice point would be 0 deg C

You can convert C to F

F = 9 / 5 * C + 32 = 9/5 * 35 + 32 = 95 deg F

What is the mass of a jet that accelerates at 4 m/s2 after a 4,000 N force from the engines?

Answers

Answer:

1000kg

Explanation:

F=MA

Rearrange the formula: M=F/A

plug in values for F (force), and A (acceleration).

M=4000/4

M=1000kg

i think.

not sure tho.

The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.

What is Newton's second law of motion?

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.

Rearranging the formula to solve for mass, we get:

m = F / a

Substituting the given values, we get:

[tex]m = 4000 N / 4 m/s^2[/tex]

m = 1000 kg

Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.

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Give the relationship between the number of valence electrons in an atom's
valence electron shell and the position of the element on the Periodic Table​

Answers

Answer:

they're reactions

Explanation:

The relationship between the valence electrons and position is: the number of valence electrons determines the position

What is valence electron?

This is the number of electrons in the outermost shell of an atom.

NOTE: The outermost shell is called valence shell

Position in Periodic table

This is where an element is located in the periodic table

Relationship between valence electrons and position

The position of an element in the periodic table is determined by the number of valence electrons.

For example

Sodium, Na (atomic number of 11) has the following electronic configuration

1st shell = 2 electrons2nd shell = 8 electrons 3rd (valence) shell = 1 electron

Since the valence electron is 1, thus, sodium is located in group 1 of the periodic table.

Thus, we can see that the position of an element in the periodic table is related to the valence electron(s) in the atomic shell of the element.

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A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 5.80 ft from the mirror on the left wall and 13.7 ft from the mirror on the right wall.

Answers

Answer:

Explanation:

When the person stands 5.80 ft from the mirror of the wall.

a) The first image is found by multiplying the distance of the left mirror to the person.

i.e.

2 × 5.80 = 11.6 ft

b) The second image is deduced by the addition of the distance of the first image with the distance created by the right mirror.

i.e.

(2 × 13.7 ) + 11.6

= 39 ft

c) The third image is acquired by the addition of the image presented by the left mirror and the image presented by the right mirror.

(2 × 5.80) + 39

= 50.6 ft

As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.01 mm apart and position your screen 3.09 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 639 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe

Answers

Answer:

[tex]0.00195\ \text{m}[/tex]

[tex]0.00293\ \text{m}[/tex]

Explanation:

m = Order = 1

D = Distance between screen and slit = 3.09 m

d = Slit distance = 1.01 mm

[tex]\lambda[/tex] = Wavelength = 639 nm

Distance from the first bright fringe from the central bright fringe is given by

[tex]y=\dfrac{m\lambda D}{d}\\\Rightarrow y=\dfrac{1\times 639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00195\ \text{m}[/tex]

Distance from the first bright fringe from the central bright fringe is [tex]0.00195\ \text{m}[/tex]

Distance from the second dark fringe from the central bright fringe is given by

[tex]y=(m+\dfrac{1}{2})\dfrac{\lambda D}{d}\\\Rightarrow y=(1+\dfrac{1}{2})\dfrac{639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00293\ \text{m}[/tex]

Distance from the second dark fringe from the central bright fringe is [tex]0.00293\ \text{m}[/tex].

if the root mean square speed of a gas particle is 200 m/s at a temperature of 400k, at what approximate temperature will urms when kelvin temperature equals 350 m/s

Answers

Answer:

The correct solution is "1230 K".

Explanation:

The given values are:

[tex](V_{rms})_1= 200 \ m/sec[/tex]

[tex](V_{rms})_2= 350 \ m/sec[/tex]

[tex]T_1=400 \ K[/tex]

As we know,

⇒  [tex]V_{rms} \propto \sqrt{T}[/tex]

or,

⇒  [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]

On substituting the values, we get

⇒  [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]

⇒   [tex]T_2=1230 \ K[/tex]

Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalories does it release? (1 cal = 4.184 J) (Round off answer to 2 decimal place)​

Answers

Answer: 9.42

Explanation: yes

An object has a mass of 50 kg on Earth. What would be the mass of that object in the Moon

Answers

It would be 50 kg.

Mass doesn't change.

Weight can.

Determine the activity of the sample of cerium when the sample was 80 seconds old

Answers

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1 kg block slides down a frictionless inclined plane that makes an angle of 300 with respect to the ground. The total length of the plane is 2 m, but midway down it collides with a second block, weighing 0.5 kg. The two blocks stick together and travel as one unit the rest of the way down the ramp. What is the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane

Answers

Answer:

the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J

Explanation:

Given that the data in the question;

angle of inclination with respect to the ground [tex]\theta[/tex] = 30°

length of plane d = 2m

m₁ = 1 kg

m₂ = 0.5 kg

now, velocity of the first block at midpoint;

[tex]\frac{1}{2}[/tex]mv² = mgsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]

[tex]\frac{1}{2}[/tex]v² = gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex]

v² = gsin[tex]\theta[/tex]d

v = √( gsin[tex]\theta[/tex]d)

g is 9.8 m/s

so we substitute

v = √( 9.8 × sin30° × 2)

v = √( 19.6 )

v =  3.13 m/s

Now, velocity just after collision of the blocks will be;

(m₁ + m₂)v₂ = m₁v

v₂ = m₁v / (m₁ + m₂)

we substitute

v₂ = (1 × 3.13) / (1 + 0.5)

v₂ = 3.13 / 1.5

v₂ = 2.0866 m/s

now, final kinetic energy will be;

[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + Initial Kinetic energy

[tex]KE_f[/tex] = (m₁ + m₂)gsin[tex]\theta[/tex][tex]\frac{d}{2}[/tex] + [tex]\frac{1}{2}[/tex]mv₂²

we substitute

[tex]KE_f[/tex] = [(1 + 0.5)9.8 × sin30 × [tex]\frac{2}{2}[/tex]] + [[tex]\frac{1}{2}[/tex] × 1.5 × 2.0866 ]

[tex]KE_f[/tex] = 7.35 + 3.2654

[tex]KE_f[/tex] = 10.62 J

Therefore, the kinetic energy of the combined 1.5 kg block when it reaches the bottom of the plane is 10.62 J

From fastest to slowest, which of the following lists describes the speed at which sound tends to travel in different materials?
A. Gases, solids, liquids
B. Gases, liquids, solids
C. Solids, liquids, gases
D. Solids, gases, liquids

Answers

Answer:

C. Solids,Liquids, Gases

HELP PLEASEE

when a person receives an electric shock from wires , is he most affected by a spark, corona, arc or humus solution?​

Answers

Answer:

Usually an eletric shock. You can be left with numbness and MAYBE problems with your eyes.

Explanation:

In the nitrogen cycle, plants take in nitrates and convert them into

Answers

It is then converted into a ammonia.

the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67​

Answers

Answer:

[tex]\theta_c = 36.78^o[/tex]

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]

[tex]\theta_c = 36.78^o[/tex]

A car on a roller coaster loaded with passengers has a mass of 2.0 x 10^3 kg. At the lowest point of the the track, the radius of curvature is 24 m and the roller coaster car has a tangential speed of 17 m/s

Answers

We have that the  is mathematically given as

Fn=36000N

Force

Question Parameters:

mass of 2.0 x 10^3 kg

the radius of curvature is 24 m and

the roller coaster car has a tangential speed of 17 m/s

Generally the equation for the Force   is mathematically given as

F=ma

Fn-fg=mv^2/r

Fn=m(v^2/r+g)

Therefore

Fn=2000(12^2/18+9.8)

Fn=36000N

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Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have the frequency 440 Hz and the note E should be at 659 Hz. The tuner can determine this by listening to the beats between the third harmonic of the A and the second harmonic of the E. A tuner first tunes the A string very precisely by matching it to a 440 Hz tuning fork. She then strikes the A and E strings simultaneously and listens for beats between the harmonics. What beat frequency indicates that the E string is properly tuned

Answers

Answer:

The beat frequency = 2.0 Hz

Explanation:

From the given information

The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.

i.e.

[tex]f_{3A} = 3f_A[/tex]

where;

[tex]f_A =[/tex] note A fundamental freq.

replacing 440 Hz for [tex]f_A[/tex]

[tex]f_{#a} = 3 (440 \ Hz)[/tex]

[tex]f_{3A} = 1320 Hz[/tex]

However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.

i.e.

[tex]f_{2E} = 2f_E[/tex]

[tex]f_E =[/tex]  note E fundamental freq.

replacing 659 Hz for [tex]f_E[/tex]

[tex]f_{2E} = 2(659)[/tex]

[tex]f_{2E} = 1318 \ Hz[/tex]

Finally, the beat frequency when the E string is properly tuned is:

[tex]\Delta f = f_{3A}-f_{2E}[/tex]

[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]

[tex]\Delta f = 2.0 \ Hz[/tex]

Thus, the beat frequency = 2.0 Hz

Assertion: In electrical circuits the connecting wires are usually made of thick copper wires. Reason: Thicker wires offer higher resistance and the wires are made of copper as the electrical conductivity of copper is low

a)Both A and R are true and R is the correct explanation of A.b)Both A and R are true, and R is not the correct explanation of A.c)A is true, but R is false. d)A is false, but R is true. e)Both A and R are false.

Answers

There actually three assertions here: one in A and two more in B.

All three assertions, as well as the reasoning described in this mess, are all False.

The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.

A 1.50x103-kilogram car is traveling east at 30 meters per second.
The brakes are applied and the car is brought to rest in 9.00 seconds.
A. Calculate the magnitude of the total impulse applied to the car to
bring it to rest. [Show all work, including the equation and
substitution with units.]
B. State the direction of the impulse applied to the car. [East or
West?]


PLEASE HELP!!!!

Answers

Answer:

[tex]39000\ \text{kg m/s}[/tex]

West

Explanation:

m = Mass of car = [tex]1.3\times 10^{3}\ \text{kg}[/tex]

t = Time = 9 seconds

u = Initial velocity = 30 m/s

v = Final velocity = 0

Impulse is given by

[tex]J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}[/tex]

The magnitude of the total impulse applied to the car to bring it to rest is [tex]39000\ \text{kg m/s}[/tex].

The direction is towards west as the sign is negative.

What is meant by the terms critical mass and supercritical?

Answers

Answer:

Critical mass is the minimum mass of fissionable material required to sustain a nuclear fission reaction, and a supercritical mass, which will provide more than enough neutrons to sustain a fission reaction at the time of detonation.

Explanation:

Why are objects that fall near Earth's surface rarely in free fall?
O Gravity does not act on objects near Earth's surface.
O Air exerts forces on falling objects near Earth's surface.
O The objects do not reach terminal velocity.
O The objects can be pushed upward by gravity.​

Answers

Answer:

Air exerts forces on falling objects near earth's surface

Explanation:

Falling objects are typically subject to air resistance which prevents the force of gravity on the object

A ball is rolling down a hill. Wich action would slow the ball down?

Answers

friction.............................

Families attempting to rebound from crises are advised to discontinue family rituals and leisure activities, as they may regenerate negative family stress and threaten resilience.

A. False
B. True

Answers

The answer is B. Yes I know it’s correct .

The weight of an object is the force pulling the object:

a. upward
b. to the side.
c. in all directions
d. downward

Answers

D pulling because of gravity

Philosophy: The Big Picture Unit 8

Would an existentialist argue that the study of philosophy was a good use of a life?

A. Yes, if society valued the results of the study.
B. Yes, but only if the individual found it meaningful.
C. No, a life should be spent minimizing the role of anxiety.
D. No, there is no way that philosophy could create a meaningful life.

Answers

the answer to this would be C

As you know a cube with each side 4 m in length has a volume of 64m3. Each side of the cube is now doubled in length. What is the ration if the new volume to the old volume

Answers

Answer:

The ratio of the new volume to the old volume is 8 to 1.

Explanation:

Let's first list what we know:

A cube has sides with lengths of 4 mThe volume of the cube is 64 [tex]m^3[/tex]The new cube has sides double the length of the old cube

Since the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.

The equation for the volume of a cube is [tex]V = s^3[/tex], where "V" is the volume and "s" is the lengths of the sides.

Now, let's solve for the volume of the new cube:

[tex]V = s^3[/tex]

[tex]V = 8^3[/tex]

[tex]V = 512[/tex]

The volume of the new cube is 512 [tex]m^3[/tex].

The ratio of the new volume to the old volume is 512 : 64.

Let's simplify the ratio:

512 : 64

8 : 1

The ratio of the new volume to the old volume is 8 to 1.

P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)

Calculate the work done to push a 200-N object 5-meters

Answers

1000 joules
jskskmxk dnd
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