AKAJAXOSPAPXODAOAPA HELP

Answer:

He used 6 bananas at .50 which cost $3.00

12 oranges at .75 which cost $9.00 and

3 papayas at $1.25 which cost $3.75

Step-by-step explanation:

We can set up a system of equations using the information given.

b for banana, r for orange, p for papaya

b + r + p = 21. Also given r = 2b So substitute to simplify for calculating two unknowns:

b + 2b + p = 21 The number of items.

50b + 75(2b) +125p = 1575 The cost.

I multiplied everything by 100 to eliminate the decimals.

To solve by substituion, rewrite the first equation to get a value for p in terms of b

p = 21 - 3b

Substitute this value in the second equation and solve for b.

50b + 150b + 125(21–3b) = 1575

200b +2625 –375b = 1575 Subtract 2625 from both sides and combine the like terms:

–175b = 1575 –2625

–175b = –1050. Divide both sides by –175

b = 6

Substitute in the original equation to find the amount of each fruit:

b + r + p = 21

b = 6 bananas

r = 2b. 2(6) = 12 oranges. I used r so as not to mix up o with 0.

6 + 12 + p = 21

p = 21 –18

p = 3 papayas

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