Ahoy starting from rest moves with a distance of 200m in 10 seconds...Find the magnitude of acceleration

Answers

Answer 1

Answer:

The magnitude of acceleration is 2m/s² .

Explanation:

First, you have to find the velocity as it starts to travel 200m in 10s. The formula of velocity is V = Distance/Time, then you have to substitute the values into the formula :

[tex]v = d \div t[/tex]

[tex]let \: d = 200 \\ let \: t = 10[/tex]

[tex]v = 200 \div 10[/tex]

[tex]v = 20m/s[/tex]

Next, you have to substitute the values into the acceleration formula, a = (v-u)/t where v represents final velocity, u is initial velocity and t is time taken :

[tex]a = \frac{v - u}{t} [/tex]

[tex]let \: v = 20 \\ let \: u = 0 \\ let \: t = 10[/tex]

[tex]a = \frac{20 - 0}{10} [/tex]

[tex]a = \frac{20}{10} [/tex]

[tex]a = 2m/ {s}^{2} [/tex]


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