After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. The rockets explode high in the air and the sound travels out uniformly in all directions. If the sound intensity is 1.67 10-6 W/m2 at a distance of 233 m from the explosion, at what distance from the explosion is the sound intensity half this value

Answer:

1.6 g

Explanation:

Use the formula: W =  m× g

       ∴ g =  W / m

Here, W = 128N

         m = 80 Kg

     ∴ g = 128 ÷ 80

           = 1.6 N (Ans)

Answer:

b. He is 8 years old

Explanation:

We will use Einstein's formula for time dilation, to calculate the age of Lee. Because Lee was traveling comparable to the speed of light, his age must be lesser than Leigh.

[tex]T = \frac{T_o}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]

where,

T₀ = Time on Earth = ?

T = Relative Time = 10 years

v = relativistic speed of Lee = 0.714 c

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]10\ years = \frac{T_o}{\sqrt{1-\frac{(0.714\ c)^2}{c^2} } } \\\\[/tex]

T₀ = 7 years

Hence, the age of Lee will be:

[tex]Lee's\ Age = 1\ year + 7\ years = 8\ years[/tex]

b. He is 8 years old

Answer:

Homogeneous mixtures

Explanation:

I think so because homogeneous means mixed mixtures

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

Answer: c is correct

Explanation: i did this

Answer:

A ray of light is incident from air on the surface of a block of clear ice (nice=1.31) at an angle of 45.0° with the normal. Part of the light is reflected and part is refracted. Find the angle between the reflected and refracted light.

Answer:

5. 60 Ω

6. 60 Ω

7. 10 Ω

8. 0.625 KΩ

Explanation:

5. Determination of the equivalent resistance.

Resistor 1 (R₁) = 10 Ω

Resistor 2 (R₂) = 20 Ω

Resistor 3 (R₃) = 30 Ω

Equivalent Resistance (R) =?

Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:

R = R₁ + R₂ + R₃

R = 10 + 20 + 30

R = 60 Ω

Thus, the equivalent resistance is 60 Ω

6. Determination of the equivalent resistance.

Resistor 1 (R₁) = 10 Ω

Resistor 2 (R₂) = 35 Ω

Resistor 3 (R₃) = 15 Ω

Equivalent Resistance (R) =?

Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:

R = R₁ + R₂ + R₃

R = 10 + 35 + 15

R = 60 Ω

Thus, the equivalent resistance is 60 Ω

7. Determination of the equivalent resistance.

Resistor 1 (R₁) = 6 Ω

Resistor 2 (R₂) = 4 Ω

Equivalent Resistance (R) =?

Since the resistors are arranged in series connection, the equivalent resistance can be obtained as follow:

R = R₁ + R₂

R = 6 + 4

R = 10 Ω

Thus, the equivalent resistance is 10 Ω

8. Determination of the equivalent resistance.

Resistor 1 (R₁) = 10 KΩ

Resistor 2 (R₂) = 2 KΩ

Resistor 3 (R₃) = 1 KΩ

Equivalent Resistance (R) =?

Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/2 + 1/1

Find the least common multiple (lcm) of 10, 2 and 1. The result is 10. Divide 10 by each of the denominator and multiply the result obtained by the numerator. This is illustrated below:

1/R = (1 + 5 + 10) / 10

1/R = 16/10

Invert

R = 10/16

R = 0.625 KΩ

Thus, the equivalent resistance is 0.625 KΩ.

Answer:

If you are at sea level, each square inch of your surface is subjected to a force of 14.6 pounds. The pressure increases about one atmosphere for every 10 meters of water depth. At a depth of 5,000 meters the pressure will be approximately 500 atmospheres or 500 times greater than the pressure at sea level.

Explanation:

At sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.

Pressure is defined as the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.

Pressure is the physical amount of force exerted on a particular area.

Pressure can be expressed as

Pressure = Force / area

There are three types  of pressure.

Thus, at sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.

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Answer:

Uzi

Explanation:

When somebody comes to me I don’t have any

Answer:

b

Explanation:

For given diverging lens(Concave) ; a) The distance of the image is -6 Cm, b) The image is virtual.

The lens that diverge incident parallel beam of light after refraction from the lens, is called diverging or concave lens.

Given data:

a)

        [tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\[/tex]

        [tex]\frac{1}{-10} = \frac{1}{v} - \frac{1}{-15}\\\frac{1}{-10} = \frac{1}{v} + \frac{1}{15}[/tex]

        [tex]\frac{1}{v} = \frac{1}{-10} -\frac{1}{15} \\\frac{1}{v} = \frac{-3-2}{30} \\[/tex]

         [tex]v = -6 Cm[/tex]

b) Magnification ,

m= ([tex]\frac{v}{u}[/tex])

on putting values,

[tex]m =(\frac{-6}{-15} )=\frac{2}{5} =0.4[/tex]

since m is positive it means the image is virtual

Hence a) distance of image is -6 Cm and b) the image is virtual.

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Answer:

Not all appliances run on energy. Some of them run on gas. Some both. It just depends on the age of the appliance, the make of the appliance, and the company who made it.

Answer:

T₂ = 16.83°C

Explanation:

Applying the law of conservation of energy principle here in this situation we get the following equation:

[tex]Energy\ Lost\ by\ Metal = Energy\ Gaine\ by\ Water\\m_{metal}C_{metal}(T_2-T_{1metal}) = m_{w}C_{w}(T_2-T_{1w})[/tex]

where,

T₂ = Final Temperature of Water = Final Temperature of Metal = ?

C_metal = Specififc Heat Capacity of the metal = 2.11 x 10² J/lg.°C

T_1metal = Initial Temperature of Metal = 225°C

m_metal = mass of metal = 1 x 10⁻²[tex](0.01\ kg)(211\ J/kg.^oC)(T_2-225^oC) = (0.09\ kg)(4184\ J/kg.^oC)(T_2-18^oC)\\2.11 T_2 - 474.75 = 376.56T_2 - 6778.08\\374.45T_2 = 6303.33\\[/tex] kg (exponent assumed due to missing info in question)

C_w = Specififc Heat Capacity of the water = 4184 J/lg.°C

T_1w = Initial Temperature of water = 18°C

m_w = mass of water = 0.09 kg

Therefore,

[tex](0.01\ kg)(211\ J/kg.^oC)(T_2-225^oC)=(0.09\ kg)(4184\ J/kg.^oC)(T_2-18^oC)\\\\2.11 - 474.75T_2 = 376.56 - 6778.08T_2\\[/tex]

T₂ = 16.83°C

Answer:

The force holding you down is gravity.

Explanation:

Gravity is a force between two objects with mass. It pulls things together. You have mass, and the Earth has mass, so gravity tries to pull you and the Earth together. The gravitational force is much bigger for more massive objects.

Answer:

Gravitational Force

Explanation:

Gravitational Force holding everything down

-TheUnknownScientist

Answer:

1) Van der rcf generator

2) the charge is distributed among all the hairs, as they all have the same potential,

the charges are of the same sign repel each other

Explanation:

1.) The object is a Van der rcf generator, which is loaded by friction,

The girl has no load

2) when the girl touches the sphere of the generator part of the electrons of this is transferred to the girl, when this charge reaches the hair, the charge is distributed among all the hairs, as they all have the same potential,

the charges are of the same sign repel each other

Answer:

10 N

Explanation:

Given that,

Force applied by a person = 25 N

Force of friction = 15 N

The net force acting on the box is given by :

F = Applied force - the force of friction

So,

F = 25 N - 15 N

F = 10 N

So, the required force is equal to 10 N.

Answer:

We can conclude by saying that in the beginning current will increase but after sometime, it becomes saturated.

Explanation:

Note: No information on change in number of electron generated.

Since there is a collision, the electrons emitted will not reach the collector at same time. As the voltage is increased, the the speed with which the electrons will reach the collector starts to increase. Due to this, electric current will first increases till all the emitted electrons reach the collector. Since we are not provided with the information that number of electrons generated are changing, after increasing voltage current will increase for some time and then reaches a saturated state.

We can conclude by saying that in the beginning current will increase but after sometime it becomes saturated.

Answer:

It is doubled

Explanation:

f2=2f1

x1=x2=x

W1=f1*x1=f1*x

W2=f2*x2=f2*x=2*(fi*x)=2*W1

Answer:

720N

Explanation:

180+(40×10)+140=720 remember we can only add with same units ;1kg=10N therefore 40 kg=(40×10)N=400N

The net force would be the summation of all the forces in addition to the weight force of the 40 kg weight, thus the net force of all the forces would come out to be 712.4 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

F = ma

As given in the problem we have to find the net force,

Let us assume the acceleration due to gravity would be 9.81 m/s².

The force generated by the 40-kilogram weight =40 ×9.81 Newtons.

The force generated by the 40-kilogram weight = 392.4 Newtons

Net force = 180 + 140 +392.4

                =712.4 Newtons

Thus, the net force of all the forces would come out to be 712.4 Newtons.

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Answer:

let say it will be positive

Answer:

a)    F = 18.375N, b) F = 24.5 N

Explanation:

This exercise can be solved using the translational equilibrium equations.

Let's start by fixing a reference system with the horizontal x axis and the vertical y axis, from the statement of the exercise I understand that the wall is vertical and the book is supported on it, therefore the applied force is in the direction towards the wall

a) In this part the force that does not allow the movement of the book is requested, therefore the static friction coefficient must be used (μ_s = 0.8)

X axis  

       F - N = 0

       N = F

Y axis

       fr - W = 0

       W = fr

where W is the weight of the book.

The friction force has the formula

       fr = μ_s N

we substitute

       mg = μ_s F

       F = [tex]\frac{mg}{\mu_s }[/tex]

let's calculate

       F = 1.5 9.8 / 0.8

       F = 18.375N

b) In this case the book is moving so the friction coefficient to use is kinetic (   μ_K = 0.6)

       F = [tex]\frac{mg}{\mu_K }[/tex]

we calculate

        F = 1.5 9.8 / 0.6

        F = 24.5 N

Answer: I like your profile picture

Explanation:

Answer:

[tex]d=5\ g/cm^3[/tex]

Explanation:

Given that,

Mass of the object, m = 100 grams

Volume of the object, V = 20 cm³

We need to find the density of the object. We know that, density is equal to mass per unit volume. So,

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{100\ g}{20\ cm^3}\\\\d=5\ g/cm^3[/tex]

So, the density of the object is equal to [tex]5\ g/cm^3[/tex].

Answer:fuafnshf dj en jz

Explanation:

Can. Nd I do j dj cdj an man Jaz jxn nah an b

Wonderful.

Look out below !

Was the FAA notified ?

Answer: [tex]278\ Hz[/tex]

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

[tex]\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m[/tex]

Condition for destructive interference is

[tex]\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}[/tex]

for second destructive interference; n=2

[tex]\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz[/tex]

Answer:

true  b, e

Explanation:

The expression that describes the diffraction of a grating is

         d sin θ = m λ

where d is the separation between the slits, m is the order of the spectrum

let's analyze the different answers

a) False. The size (height) of the slits does not influence the resolution, the number of them per unit of length influences, the greater the number, the smaller the distance (d) this they

b) True. The spectrum is resolved on a screen, in the form that each wavelength corresponds to a fixed distance from the central maximum, for a given order

c) False. The exit slit selects a given wavelength, but does not deflect the beam from its path

d) False. The slit lets in light, but does not measure its intensity

e) True. For a continuous spectrum, the wavelength variation that passes through a slit is proportional to its width. For a discrete spectrum the width of the slit does not affect the wavelength

Answer:

i dont know

Explanation:

do you mean to save the answer or to save your question