According to the following reaction, what amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follows: Al2S3 = 150.17 g/mol, H2O = 18.02 g/mol.

Answer:

This water has a level acceptable, 0.1359ppm and 135.9ppb.

Explanation:

1.40g of Cl⁻ are:

1.40g Cl⁻ × (1000mg / 1g) = 1400mg Cl⁻

In 1.03x10⁴L:

1400mg / 1.03x10⁴L = 0.1359mg/L.

As the upper limit of Cl⁻ in water is 250mg/L, this water has a level acceptable

ppm are the ratio between mg of solute and liters of solution, that means the tank contains 0.1359mg/L = 0.1359ppm

ppb, parts per billion are 1000 times ppm, thus, parts per billion of the storage tank are:

0.1359ppm × 1000 = 135.9ppb

Answer:

1177.88g of C3H8

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Next we shall determine the number of mole of C3H8 required to produce 80.3 moles of CO2. This is illustrated below:

From the balanced equation above,

1 mole of C3H8 reacted to produce 3 moles of CO2.

Therefore, Xmol of C3H8 will react to produce 80.3 moles of CO2 i.e

Xmol of C3H8 = 80.3/3

Xmol of C3H8 = 26.77 moles

Finally, we shall convert 26.77 moles of C3H8 to grams.

Molar mass of C3H8 = (3x12) + (8x1) = 44g/mol

Mole of C3H8 = 26.77 moles

Mass of C3H8 =..?

Mass = mole x molar mass

Mass of C3H8 = 26.77 x 44

Mass of C3H8 = 1177.88g

Therefore, 1177.88g of C3H8 are needed for the reaction

Answer:

A substance that increases H3O+ concentration when it is dissolved in water.

Explanation:

Note that H3O+ and H+ are used quite interchangeably in chemistry.

An acid makes the H+ content higher, thereby decreasing the pH.

Answer:

a

A substance that increases H3O+ concentration when it is dissolved in water.

Explanation:

Answer:

Option C

The specific heat is the heat capacity for one mole of a substance.

Explanation:

The incorrect statement is  The specific heat is the heat capacity for one mole of a substance.

This is because the specific heat capacity is the amount of heat required to raise the temperature of 1 gramme of a substance by 1 degree Celcius.

Note that the unit in question here for the specific heat capacity of the substance is in grammes.

The definition given in the options is actually for the molar heat capacity of the substance, not the specific heat capacity.

Answer: 1.8 micrograms, 1.8 milligrams, 1.8 grams, 1.8 kilograms

Explanation:

Answer:

A. the law of constant composition

Explanation:

The molecules in the container would have the same composition because they would have traded around atoms until an equilibrium was reached with every molecule having 1 Hydrogen and 1 Chlorine.

Answer:

Explanation:

Step 1: NaCl(s) → Na(s) + 1/2 Cl2(g)  ΔHf   (ionization energy) in this step energy is required to change the phase of the compound

Step 2: Na(s) + 1/2 Cl2(g) → Na(g) + 1/2 Cl2(g)  ΔHa  (elements needed to be in gaseous state for born-haber cycle so metal changes from solid to gas state by changing the enthalpy.

Step 3: Na(g) + 1/2 Cl2(g) → Na(g) + Cl (g)  1/2ΔHd  

Step 4: Na(g) + Cl(g) → Na⁺(g) + Cl⁻(g)  IE+EA  ( in this step both ionization energy and electron affinity was involved because in metal (Na) electron is added which needs the energy and this energy draw from the step 3 and Chlorine require releasing electron to be in ionic state so when electron leaves the orbit energy releases.

Step 5: final step is Hess Law which is the combination of all the steps which step 4 again go back to step 5 and this cycle continues by repeating same steps    Na⁺(g) + Cl⁻(g)→NaCl(s)

at this step heat of formation is calculated

Heat of formation= atomization energy+ dissociation energy+ sum of ionization energies + sum of electron affinity + lattice energy.

2:  if we look at the electron configuration of the nitrogen it has 5 electrons in its outermost shell which indicates it can make 5 bonds 4 bonds and 1 lone pair usually and Oxygen has 6 electrons in its outermost shell. So nitrate ion have the total number of 24 electrons including the 1 electron which shows on the compound.

So when they make nitrate ion NO₃⁻¹ it shows that nitrate has 3 resonance structures. Nitrogen's three sigma bonds are attached to oxygen and fourth one make 1 pie bond which can rotate, delocalized and change its position anytime from one Oxygen atom to other oxygen atom.

Answer:

A. The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combines in the same proportion by mass.

B. The law of conservation of mass states that during ordinary chemical reactions, matter can neither be created or destroyed.

Note: The full question is as follows;

A researcher placed 25.0 g of silver chloride, AgCl, in sunlight and allowed the substance to decompose completely to form silver, Ag, with the release of chlorine gas, Cl2. The gas was collected in a container during the decomposition. The researcher determined that the mass of the silver formed was 18.8 g, and the mass of the chlorine gas formed was 6.2 g. The equation for the reaction is:

2AgCl ----> 2Ag + Cl2

a. State the law of definite proportions. Then use the researcher's data to confirm the law of definite proportions. Show your calculations.

b. State the law of conservation of matter. Then use the researcher's data to confirm the conservation of matter. Show your calculations.

Explanation:

A. Mass of silver obtained from AgCl = 18.8g.

Percentage mass of silver in the chloride = (18.8/25.0) * 100 = 75.2 %

Mass of chlorine obtained from AgCl = 6.2

Percentage mass of chlorine = (6.2/25) * 100 = 24.8 %

In one mole of AgCl with a molar mass of 143.3 g/mol; mass of silver = 107.8, mass of Cl = 35.5

Percentage mass of Ag = (107.8/143.3) * 100 = 75.2%

Percentage mass of Cl = (35.5/143.3) * 100 = 24.8%

Since the percentages by mass of Ag and AgCl obtained from the sample is the same to that obtained from a mole of AgCl, the law of definite proportions which states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass is verified.

B. Mass of reactant; AgCl sample = 25.0

Mass of products; At = 18.8 g; Cl = 6.2 g

Sum of products masses = 18.8 + 6.2 = 25.0 g

Therefore mass of reactant = mass of products.

This is in accordance with the law of conservation of mass which states that during ordinary chemical reactions, matter is neither created nor destroyed.

The correct answer is B. An observation

Explanation:

An observation is defined as a statement or conclusion you made after observing or measuring a phenomenon, this includes statements based on precise instruments. For example, if you conclude a plant grows 2 inches every month by measuring the plant during this time, this is classified as an observation. The conclusion of the student is also an observation because he concludes this after analyzing the volume of the water in the cylinder through the lines in the graduated cylinder, considering the water is just in the middle of 100 mL and 200 mL which indicates there are 150 mL of water.

Answer:

B. An observation

Explanation:

Hello,

Given the illustration, such statements is considered as an observation, since it came up from something the student realized with his/her own eyes, as in the volumetric cylinder the level of the liquid reached 150 mL of water. Predictions are not observed but assumed, theories are stated when experimentation is already deeply studied and hypothesis are assumptions before experimenting.

Regards.

Answer:

The mass is 1.4701 grams and the moles is 0.01.

Explanation:

Based on the given question, the volume of the solution is 100 ml or 0.1 L and the molarity of the solution is 0.100 M. The moles of the solute (in the given case calcium chloride dihydride (CaCl2. H2O) can be determined by using the formula,  

Molarity = moles of solute/volume of solution in liters

Now putting the values we get,  

0.100 = moles of solute/0.1000

Moles of solute = 0.100 * 0.1000

= 0.01 moles

The mass of CaCl2.2H2O can be determined by using the formula,  

Moles = mass/molar mass

The molar mass of CaCl2.2H2O is 147.01 gram per mole. Now putting the values we get,  

0.01 = mass / 147.01

Mass = 147.01 * 0.01

= 1.4701 grams.  

The mass should be considered as the 1.4701 grams and the moles should be 0.01.

Since we know that

Molarity = moles of solute/volume of solution in liters

So,

0.100 = moles of solute/0.1000

Moles of solute = 0.100 * 0.1000

= 0.01 moles

Now The mass should be

Moles = mass/molar mass

0.01 = mass / 147.01

Mass = 147.01 * 0.01

= 1.4701 grams.  

hence, The mass should be considered as the 1.4701 grams and the moles should be 0.01.

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Answer:

a) ortho-para isomers predominates

b) 3-nitrobenzoic acid ( meta isomer predominates)

c) 3-bromo nitrobenzene ( meta isomer predominates)

d) the ortho- para isomers predominates

Explanation:

a) Toluene contains -CH3 which is an ortho- para- director hence the major product of the sulphonation of toluene should be the ortho- para isomers.

b) The major product of the nitration of benzoic acid is 3-nitrobenzoic acid. This is an electrophilic substitution in which the meta isomer predominates.

c) The meta isomer predominates giving 3-bromo nitrobenzene as the major product.

d) The isopropyl group is an ortho- para director hence the ortho- para isomers predominates .

Answer:

Explanation:

An artifact is found in a desert cave. The anthropologists who found this artifact would like to know its age. They find that the present activity of the artifact is 9.25 decays/s and that the mass of carbon in the artifact is 0.100 kg. To find the age of the artifact, they will need to use the following constants:

r=1.2

The activity of carbon 14 is

[tex]A=A_0e^{\lambda t}[/tex]

where,

[tex]A_0[/tex] is the initial activity of the compound

Solve for t

[tex]-\lambda t=In\frac{A}{A_0}[/tex]

[tex]t=-\frac{1}{\lambda} In(\frac{A}{A_0} )[/tex]

[tex]=-\frac{1}{\lambda} In(\frac{A}{\lambda r(\frac{m_c}{m_a} )} )[/tex]

since,

[tex]A_0=\lambda r(\frac{m_c}{m_a} )[/tex]

[tex]=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )[/tex]

Now, the age of the artifact is

[tex]=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )[/tex]

[tex]=-\frac{1}{1.21\times 10^{-4}} In(\frac{(9.25)(2.32\times 10^{-26}}{1.21\times 10^{-4}(\frac{1}{3.15569\times10^7} )(1.2\times 10^{-12})(0.100)}} )\\\\=6303.4 \ years[/tex]

to two significant figure = 6300 years

Answer:

6-metyl-2-heptyne

Explanation:

C-C-C-C-C-C-C hept

   2

C-C≡C-C-C-C-C  2-heptyne

                   C

                    | 6

C-C≡C-C-C-C-C

6-metyl-2-heptyne

The IUPAC name for the above structure is 6 methyl, hept-2-yne.

IUPAC stands for international Union of pure and applied chemistry. It is the body in charge of naming organic chemical compounds.

The naming is is based on a molecule's longest chain of carbons connected by single/double/triple bonds, whether in a continuous chain or in a ring etc.

According to this question, a structure is given. The following applies;

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#SPJ6

Answer:

see explanation below

Explanation:

In the first case, we have a reaction where we have the 3-chloro-3-methylpentane reacting with t-butoxide. The t-butoxide is a very voluminous base, so the strength of substracting a hydrogen atom is reduced. Therefore, the reaction taking place here will be an E2 but instead of substracting the hydrogen from the carbons 2 or 4, it will substract it from the methyl group, cause it has less steric hindrance there and the reaction will go faster.

In the second case, the sodium ethoxide is a strong base, so it will rapidly substract an atom of hydrogen from carbon 2 or 4 to form the (Z) - 3 - methyl - 2- pentene and the substitution product.

Look picture for mechanism and products.

Answer:

The half-life of the material is 2 years

Explanation:

Given;

initial count rate = 2000 decays/minute

final count rate =  500 counts/min

decay time = Four hours

To determine the half life of the material; we create a simple decay table that matches the decay time and count rates.

time (years)                     count rate

0                                    2000 decays/minute

2                                     1000 decays/minute

4                                     500 decays/minute

Half life is the time intervals = 2 years

Also using a formula;

[tex]N = \frac{N_o}{(t/2)^2} \\\\N_o-is \ the \ initial \ count\ rate\\\\N-is \ the \ final \ count\ rate\\\\t/_2 - is \ the\ half\ life \\\\N = \frac{N_o}{(t/2)^2} \\\\500 = \frac{2000}{(t/2)^2}\\\\(t/_2)^2 = \frac{2000}{500} \\\\(t/_2)^2 = 4\\\\t/_2 = \sqrt{4} \\\\t/_2 = 2 \ years[/tex]

Therefore, the half-life of the material is 2 years

Answer:

The master mix contains the following reagents: dNTPs, DNA Polymerase, PCR buffer and MgCl2.

Explanation:

The DNA templates are the gene fragments to amplify by PCR, thereby they have to be added separately in each tube. Moreover, the primer pairs are specific for each gene, thereby they have to be added separately in each tube.  

Deoxynucleotide triphosphates (dNTPs) are the building blocks of the DNA molecules: dGTP, dATP, TTP, and dCTP.

The PCR buffer provides a suitable medium for the activity of the DNA polymerase, often it contains Tris-Hcl and KCl.

MgCl2 is a cofactor for the activity of the DNA Polymerase.

The DNA Polymerase is an enzyme that amplifies DNA by adding nucleotides to the 3' end.

Answer:

Enzyme is carbonic anhydrase

Substrate is [tex]CO_2[/tex]

Turnover number is [tex]10^{7}[/tex]

Explanation:

An enzyme is used by a living organism as a catalyst to perform a specific biochemical reaction.

A substrate is a molecule upon which an enzyme acts.

Turnover number refers to the number of substrate molecules transformed by a single enzyme molecule per minute. Here, the enzyme is the rate-limiting factor.

Here,

Enzyme is carbonic anhydrase

Substrate is [tex]CO_2[/tex]

Turnover number is [tex]10^{7}[/tex]

Answer:

The type of reaction is Polymerization

Answer:

combustion?

Explanation:

Yo, like what is that question.

Answer:

c

Explanation:

chemicals can be found in every part of our lives

Answer:

they would repel

Explanation:

unlike charges attract while like ones repel.

Answer:

2 - Butyne

Explanation:

The name of the molecule with a carbon atoms arranged in a straight chain with a triple bond between the second and third carbons is 2 - Butyne.

2- Butyne is an alkyne with structural formula given below. Some of the properties of Butyne include it is a produced artificially, it is volatile and colorless in nature.

Hence, the given molecules described is 2 - Butyne.

Answer:

ammonia

Explanation:

Answer:

slump. weathering, and creep

Explanation:

Freezing and thawing cycle in geology is the process in which water gets in between soil space or rock cracks, freeze in a cold season, and then melt in a warmer season, exerting a force on the soil or rock around it. This force is due to the expansion and contraction of water when it changes from ice to liquid water.

The three geological processes slump, weathering and creep all depend on thawing and freezing cycle among other factors.

Answer:

It is slump, weathering and creep

Explanation:

Took the test on edg

Answer:

u

uric acid is a useful diagnostic tool as screening for most of purine metabolic disorders. The importance of uric acid measurement in plasma and urine with respect of metabolic disorders is highlighted. Not only gout and renal stones are indications to send blood to the laboratory for uric acid examination

Answer:

E) 1.85 M

Explanation:

M(C12H22O11) = 342.3 g/mol

22.5 g * 1mol/342.3 g = 0.0657 mol

35.5 mL = 0.0355 L

Molarity = mol solute/L solution = 0.0657 mol/0.0355L =1.85 mol/L = 1.85 M

The molarity of the aqueous solution is 1.85 M. The correct option is E) 1.85 M

From the question,

We are to determine the molarity (that is, concentration) of the given sucrose solution

First, we will determine the number of moles present in the given mass of sucrose

Mass of sucrose = 22.5 g

Using the formula

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of sucrose = 342.2965 g/mol

∴ Number of moles of sucrose present = [tex]\frac{22.5}{342.2965}[/tex]

Number of moles of sucrose present = 0.0657325 moles

Now, for the molarity (concentration) of the sucrose solution

From the formula

Number of moles = Concentration × Volume

Then,

[tex]Concentration = \frac{Number\ of\ moles}{Volume}[/tex]

From the question,

Volume = 35.5 mL = 0.0355 L

∴ [tex]Concentration = \frac{0.0657325}{0.0355}[/tex]

Concentration = 1.85 M

Hence, the molarity of the aqueous solution is 1.85 M. The correct option is E) 1.85 M

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Answer:

1. density = 0.89 g/cm3

2. Yes is possible to identify the liquid

3. ethanolamine

Explanation:

Data:

mass = 682 g

volume = 0.767 L = 767 mL or cm3

1.

To calculate the density of the liquid it is necessary to know that the density formula is:

[tex]density=\frac{mass(g)}{volume(cm^{3}) }[/tex]

The data obtained is replaced in the formula:

[tex]density=\frac{682g)}{767(cm^{3}) }=0.89\frac{g}{cm^{3} }[/tex]

2.

With the given data it is possible to identify the liquid, this because the density value is a basic property of each liquid.

3.

It is possible to determine what liquid it is, since when comparing the value obtained with those reported in the collection of Material Safety Data Sheets (MSOS), the value that agrees is that of ethanolamine.

Answer:

Oxygen is the limiting reactant.

Explanation:

Based on the reaction:

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

1 mole of sucrose reacts with 12 moles of oxygen to produce 12 moles of CO₂ and 11 moles of H₂O.

10.0g of sucrose (Molar mass: 342.3g /mol) are:

10.0g C₁₂H₂₂O₁₁ × (1mole / 342.3g) = 0.0292 moles of C₁₂H₂₂O₁₁

And moles of 10.0g of oxygen (Molar mass: 32g/mol) are:

10.0g O₂ × (1mole / 32g) = 0.3125 moles of O₂

For a complete reaction of 0.0292 moles of C₁₂H₂₂O₁₁ you need (knowing 12 moles of oxygen react per mole of sucrose):

0.0292 moles of C₁₂H₂₂O₁₁ × (12 moles O₂ / 1 mole C₁₂H₂₂O₁₁) = 0.3504 moles of O₂

As you have just 0.3125 moles of O₂, oxygen is the limiting reactant.

Explanation:

Mitochondria (sing. mitochondria) are organelles, or parts of the eukaryote cell. They are in the cytoplasm, not the nucleus. They make the most cell supply of adenosine triphosphate (ATP), a molecule that cells use as an energy source. ... This means that mitochondria are known as '' the powerhouse of the cell'' or ''cell strength".

Good Luck, and have a great day..

Answer:

not 100% but i think its 1.57x10^20

Explanation:

5.25x10^-4g / 2.016g

2.60x10^-4 x 6.022x10^23= 1.56x10^20 molecules

Answer:

Explanation:

70% (vol/vol) means

cotnaimns 70 %(vol/vol) 70 ml of isoprapnol is there in 100 ml of Rubbing sold alcohol.

if it is 200 ml then obvouly it has the 70*2 =140 ml of isoproanol  required.

Alcohol is an organic compound that when rubbed on the skin it evaporates quickly leaving a cool effect on the skin. The reason why it evaporates is because it has loosely bound molecules and a low boiling temperature.

The volume of pure isopropanol required to produce a 200-ml bottle of rubbing alcohol is 140 ml

From the question:

Alcohol sold contains 70%(vol/vol). This means 70 ml of the solute of isopropanol can be found in 100 ml of solution.

Hence:

100ml of solution = 70ml of isopropanol

200ml of solution = ?

Cross Multiply

200 ml x 70 ml / 100 ml

= 140 ml

Therefore, the volume of pure isopropanol required to produce a 200-ml bottle of rubbing alcohol is 140 ml

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