According to regulations, the legal limit for arsenic in drinking water is 0.05 ppm. If you test a sample of 100 grams of drinking water and find 0.0012 grams of arsenic, is this within the legal limit? Show your calculations.

Change in temperature of the Magnesium sample is calculated as 23.7°C.

Heat energy is a form of energy that is transferred between objects or systems due to temperature difference. It flows from hotter to cooler objects, and its amount is measured in joules.

As we know; Q = m c ΔT

Q is the amount of heat absorbed, m is mass of the object, c is specific heat, and ΔT is change in temperature.

ΔT = Q / (m * c)

ΔT = 1300 J / (54.2 * 1.023 )

ΔT = 23.7°C

Therefore, the change in temperature of the Magnesium sample is 23.7°C.

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Answer:

1.503 x 10^23

Explanation:

your question was how many atoms, so you have to multiply that number which is how many molecules by 8 atoms per molecule of sulphur. So you get 1.503 x 10^23 atoms in 8 grams of sulfur.

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Answer:

C. Nitrogen and Phosphorous.

Explanation:

Tagatose and Leloir pathways are two different metabolic pathways involved in the breakdown and utilization of dietary sugars, such as galactose.

The Tagatose pathway is a bacterial pathway that allows for the utilization of galactose, a monosaccharide similar to glucose, as an energy source.

In this pathway, galactose is converted into tagatose, another monosaccharide, by the enzyme galactose isomerase.

The tagatose is then broken down into dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate (G3P) through a series of reactions, which can enter the glycolysis pathway for further energy production.

The Leloir pathway, on the other hand, is a pathway found in animals and some microorganisms that also converts galactose into glucose-6-phosphate (G6P), a molecule that can enter the glycolysis pathway.

In the Leloir pathway, galactose is converted into galactose-1-phosphate by the enzyme galactokinase, and then into UDP-galactose by the enzyme galactose-1-phosphate uridylyltransferase. UDP-galactose is then converted into UDP-glucose by the enzyme UDP-galactose 4-epimerase.

Finally, UDP-glucose is converted into G6P by the enzyme phosphoglucomutase.

In summary, while both pathways involve the conversion of galactose into glucose derivatives, the Tagatose pathway involves the conversion of galactose into tagatose and then into DHAP and G3P, while the Leloir pathway involves the conversion of galactose into G6P through a series of intermediate steps.

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A cylinder of Krypton has contains 17 L of Ar at 22. 8 atm and 112 degrees celsisus. There are 0.824 moles of Ar in the cylinder.

The number of moles of Ar in the cylinder can be calculated using the ideal gas law equation: PV = nRT, where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

To use this equation, the given temperature of 112 degrees Celsius must be converted to Kelvin by adding 273.15 to get 385.15 K. The pressure of 22.8 atm and volume of 17 L are already in the correct units.

R can be found using the equation R = 0.0821 L atm/(mol K), and plugging in the values for P, V, n, R, and T gives: (22.8 atm)(17 L) = n(0.0821 L atm/(mol K))(385.15 K) n = 0.824 mol

The number of moles of Ar in the cylinder can be found using the ideal gas law equation, which requires the pressure, volume, temperature, and the gas constant. After converting the given temperature to Kelvin, the calculation yields 0.824 moles of Ar.

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The pressure of [tex]CO_2[/tex] gas in the canister at 20.00°C is 0.611 atm.

To determine the pressure of [tex]CO_2[/tex] gas in the canister, we can use the ideal gas law:

PV = nRT

First, we need to convert the volume of the canister from milliliters (mL) to liters (L):

500.0 mL = 0.5000 L

Next, we need to calculate the number of moles of [tex]CO_2[/tex] gas:

n = m/MW

where m is the mass of [tex]CO_2[/tex] gas and MW is the molar mass of [tex]CO_2[/tex] (44.01 g/mol).

n = 0.4650 g / 44.01 g/mol = 0.01057 mol

Now we can plug in the values and solve for the pressure:

P = nRT/V = (0.01057 mol)(0.0821 L·atm/mol·K)(293.15 K) / 0.5000 L = 0.611 atm

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Answer:2.18 g.

Explanation:To find the mass of sodium sulfate reacted, we use the balanced chemical equation to know that 1 mole of sodium sulfate reacts with 1 mole of barium sulfate. From the given mass of barium sulfate formed, we calculate the number of moles of barium sulfate. Since the stoichiometry of the reaction is 1:1, the number of moles of sodium sulfate reacted is the same as the number of moles of barium sulfate formed. We then use the molar mass of sodium sulfate to calculate the mass of sodium sulfate reacted. The final answer is 2.18 g.

Answer:

Reduction

Explanation:

when an atom or ion decreases in oxidation state

The process in which an atom or ion experiences a decrease in its oxidation state is called reduction.

Reduction is the opposite of oxidation, which is the process in which an atom or ion experiences an increase in its oxidation state. In a redox (reduction-oxidation) reaction, one species undergoes reduction while the other undergoes oxidation.

In the process of reduction, the species gains electrons, resulting in a decrease in its oxidation state. The reducing agent is the species that donates electrons, while the oxidizing agent is the species that accepts electrons.

Reduction reactions are important in many chemical and biological processes, including metabolism, photosynthesis, and corrosion. The study of redox reactions is important in understanding the behavior of chemicals in natural and industrial processes.

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The quantity of lithium iodide produced in the reaction was determined to be 7.8 moles.

The balanced chemical equation for the reaction between lithium carbonate (Li₂CO₃) and potassium iodide (KI) is:

2 Li₂CO₃ + 2 KI → 2 K₂CO₃ + 4 LiI

From the balanced equation, we can see that for every 2 moles of Li₂CO₃ reacted, 4 moles of LiI are produced.

Therefore, if we have 3.9 moles of K₂CO₃, we can calculate the moles of LiI produced as:

3.9 moles K₂CO₃ × (4 moles LiI / 2 moles Li₂CO₃) = 7.8 moles LiI

Therefore, 7.8 moles of lithium iodide were produced in the reaction.

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Answer:

when u stop at great speed in a vechial your body is in still in motion

Explanation:

About  739,982.4 Joules energy is required to raise the temperature of 100.0 grams of water from -269 degrees Celsius to 1500 degrees Celsius.

The formula for the change in heat is,

Q = mcΔT, the amount of energy required is Q, m is the mass of water, specific heat capacity of water is c, the change in temperature is ΔT,

ΔT = 1500°C - (-269°C)

ΔT = 1769°C

Next, we can look up the specific heat capacity of water, which is 4.184 J/g°C. Then, we can substitute the values into the formula,

Q = 100.0 g * 4.184 J/g°C * 1769°C

Q = 739,982.4 J

Therefore, it would require 739,982.4 Joules of energy to raise the temperature of 100.0 grams of water from -269 degrees Celsius to 1500 degrees Celsius.

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When we talk about a heating curve of water, we are referring to a graph that shows the temperature of water as it is heated.

The x-axis of the graph represents the amount of heat energy being added to the water, while the y-axis represents the temperature of the water.

The region of positive slope on the heating curve of water refers to the portion of the graph where the temperature of the water is increasing as more heat energy is added. This region starts at the melting point of ice (0°C) and extends all the way to the boiling point of water (100°C) at standard atmospheric pressure.

During this region, the heat energy being added to the water is being used to break the intermolecular bonds between the water molecules and increase their kinetic energy, resulting in an increase in temperature. As the temperature increases, the water transitions from a solid (ice) to a liquid, and finally to a gas (steam).

It is important to note that the slope of the heating curve during the region of positive slope is positive, which means that the temperature is increasing at a steady rate. This region is significant because it represents the phase changes of water, which have important implications for a variety of fields, including chemistry, physics, and engineering.

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The change in heat or enthalpy change in the reaction for photosynthesis to occur has + 2801 kJ of energy on the reactant side.

To show the energy necessary for the reaction to occur, the proper ΔH value should be added to the left side of the equation. As a result, the equation is:

6 CO₂ (g) + 6 H₂O (l) + 2801 kJ → C₆H₁₂O₆ (aq) + 6 O₂ (g)

it is true that the energy value is included as a reactant in the reaction, since it is required for the reaction to take place.

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There are 2.4 moles of C2O4^2- in the given sample

To determine the number of moles of C2O4 in the given sample, we need to use the balanced chemical equation of the reaction between MnO4 and C2O4. The equation is:

MnO4- + 5C2O4^2- + 8H+ → Mn2+ + 10CO2 + 4H2O

From the equation, we can see that 1 mole of MnO4- reacts with 5 moles of C2O4^2-. Therefore, if we have 0.48 moles of MnO4- at the endpoint, we can calculate the number of moles of C2O4^2- as follows:

0.48 moles MnO4- x (5 moles C2O4^2-/1 mole MnO4-) = 2.4 moles C2O4^2-

Therefore, there are 2.4 moles of C2O4^2- in the given sample.

It is important to note that moles are a unit of measurement used in chemistry to represent the amount of a substance, and it is equal to the mass of a substance in grams divided by its molar mass. In this case, we were able to determine the number of moles of C2O4^2- in the sample by using the stoichiometry of the balanced chemical equation.

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The hypothesis that a particular trait evolved by natural selection is indeed falsifiable. In fact, this is one of the foundational principles of the scientific method.

researchers must also consider alternative hypotheses and rule out alternative explanations before concluding that a trait evolved by natural selection.

The hypothesis that a particular trait evolved by natural selection is indeed falsifiable. In fact, this is one of the foundational principles of the scientific method.

To test whether a particular trait evolved by natural selection, researchers can design experiments or observational studies to investigate the trait's function and potential selective pressures. For example, they could manipulate the trait in question to see how it affects the organism's fitness, or compare the trait's frequency or variation across populations with different environmental conditions.

However, it's important to note that demonstrating that a trait evolved by natural selection does not necessarily mean that it is the only possible explanation for the trait's existence. Other evolutionary mechanisms such as genetic drift, gene flow, or mutation could also play a role in shaping the trait. Therefore, researchers must also consider alternative hypotheses and rule out alternative explanations before concluding that a trait evolved by natural selection.
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2NaOH + H₃PO₄ → Na₂HPO₄ + 2H2O is the balanced chemical equation for the reaction between 2 moles of NaOH and 1 mole of H3PO4.

It is clear from the balanced chemical equation that the reaction between 2 moles of NaOH and 1 mole of H₃PO₄ is an acid-base reaction, commonly referred to as a neutralization reaction.

In this reaction, phosphoric acid (H₃PO₄) acts as the acid and sodium hydroxide (NaOH) as the base. Na₂HPO₄ and H2O are created when the base (NaOH) and acid (H₃PO₄) react. Since all the reactants are completely consumed in the reaction and no excess of either reactant is left over, the stoichiometric balance of the number of moles of the acid and base is demonstrated by the balanced chemical equation.

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Answer:

12. Balanced chemical equation: Cu + Cl2 → CuCl2

Type of reaction: Combination or synthesis reaction

13. Balanced chemical equation: 2Ca(ClO3)2 → 2CaCl2 + 3O2

Type of reaction: Decomposition reaction

14. Balanced chemical equation: 2Li + 2H2O → 2LiOH + H2

Type of reaction: Single displacement or substitution reaction

Explanation:

Hope it helps^^

Answer: I believe it's A

Source: Trust me bro

One formula unit of ammonium dichromate, three ions would form upon dissociation in water.

When ammonium dichromate (NH₄)₂Cr₂O₇ dissociates in water, it breaks down into two ammonium ions (NH₄⁺) and one dichromate ion (Cr₂O₇²⁻). The dissociation is represented by the following chemical equation:

(NH₄)2Cr₂O₇ → 2NH₄⁺ + Cr₂O₇²⁻

Therefore, a total of three ions would be formed from the dissociation of ammonium dichromate in water. The two ammonium ions would have a positive charge, while the dichromate ion would have a negative charge.

These ions can interact with other ions in the solution and participate in various chemical reactions. The dissociation of ammonium dichromate is important in various industrial processes, as well as in chemical education for demonstrating chemical reactions and properties of ions.

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In this scenario, the limiting reactant is the ingredient that will run out first and limit the number of sandwiches that can be made.

Assuming that each sandwich requires two slices of bread, one serving of peanut butter, and one serving of jelly, we can see that we have enough bread and jelly to make a maximum of 1.5 sandwiches. However, since we only have one serving of peanut butter, we can only make one sandwich.

Therefore, the peanut butter is the limiting reactant. It is important to identify the limiting reactant in chemical reactions to determine the maximum amount of product that can be formed and to avoid wasting resources.

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The molarity of the solution diluted to the 1200.0 ml volume is found to be 0.220M.

The number of moles of H₂SO₄ in the original 22 mL solution can be calculated using the following formula,

moles of H₂SO₄ = Molarity × Volume (in liters)

22 mL = 22/1000 L

= 0.022 L

Substituting the given values, we get,

moles of H₂SO₄ = 12 M × 0.022 L

= 0.264 moles

The number of moles of H₂SO₄ will not change once the solution is diluted to a volume of 1200.0 mL since no H₂SO₄ is added or taken away. Consequently, the following formula can be used to determine the molarity of the diluted solution:

Molarity = moles of H₂SO₄ / Volume (in liters)

Again, we need to convert the volume to liters,

1200.0 mL = 1200.0/1000 L

= 1.200 L

Substituting the values, we get,

Molarity = 0.264 moles / 1.200 L

= 0.220 M

Therefore, the molarity of the diluted solution is 0.220 M.

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A brick with dimensions 1.00 m x 0.200 m x 0.500 m exerts different pressures on the floor when placed in different ways. The force exerted on the floor is 20.0 N.

To calculate the force exerted on the floor by the brick, we need to first calculate the area of the face of the brick that is in contact with the floor. The minimum pressure exerted by the brick on the floor is given as 100.0 Pa. Therefore, the force exerted on the floor by the brick can be calculated as:

Force = Pressure x Area

The area of the face of the brick in contact with the floor is given by 1.00 m x 0.200 m = 0.200 m². Therefore, the force exerted on the floor by the brick is:

Force = 100.0 Pa x 0.200 m² = 20.0 N

Since 20.0 N is not listed in the given options, it seems there may be an error or discrepancy in the provided answer choices.

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Answer: 17.49L

Explanation:

STP is 1atm and 273.15K

V=nRT/

V=(0.78)(0.0821)(273.15)/1

V= 17.49L

The three ions containing phosphorus are phosphate (PO₄³⁻), hydrogen phosphate (HPO₄²⁻), and dihydrogen phosphate (H₂PO₄⁻).

The pattern observed is that adding hydrogen atoms successively reduces the negative charge of the ion by one unit.


1. Observe the formulas of the three ions: PO₄³⁻, HPO₄²⁻, and H₂PO₄⁻.
2. Notice that hydrogen atoms are added successively: 0, 1, and 2.
3. Observe the charges of the ions: -3, -2, and -1.
4. Recognize the pattern: adding hydrogen atoms reduces the negative charge by one unit.

In other instances where hydrogen is added to polyatomic ions, a similar pattern occurs. The negative charge decreases as more hydrogen atoms are added. This pattern is consistent across various polyatomic ions containing hydrogen.

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When potassium carbonate is added to a solution containing two cations, the cation that forms a less soluble compound with carbonate will precipitate first.

This is because the less soluble compound will exceed its solubility product and form a solid precipitate. The solubility product is a constant that indicates the maximum amount of solute that can dissolve in a solution at a given temperature and pressure. In the case of the two cations, calcium ion (Ca2+) forms a more insoluble compound with carbonate ion (CO32-) than strontium ion (Sr2+). Therefore, calcium carbonate (CaCO3) will precipitate first, leaving strontium ion in solution.

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2.50 litres of a 10.0 M solution require the preparation of 25.0 moles of ethylene glycol.

Excellent antifreeze, anti-boil, and anti-corrosive qualities are produced when antifreeze and water are mixed in a 50/50 ratio. The proportion of conventional ethylene glycol to water in severely cold conditions can reach 70% antifreeze, 30% water. The maximum antifreeze to water ratio when using DEX-COOL® is 60/40.

moles = concentration (M) x volume (L)

Given that the desired concentration is 10.0 M and the volume needed is 2.50 L, the setup for calculating the total number of moles of ethylene glycol can be written as:

moles = 10.0 M x 2.50 L

moles = 25.0 mol

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The mass of CH2Cl2 that can be melted by applying 7.80 kJ of energy at the melting point can be calculated using the equation of q = m * c * ΔT, where q is the energy applied, m is the mass, c is the heat capacity, and ΔT is the difference between the final and initial temperatures. In this case, the mass can be calculated as m = q / (c * ΔT). Plugging in the given values yields a mass of 0.126 g, rounded to three significant figures.

Therefore, 7.80 kJ of energy can melt 0.126 g of solid CH2Cl2 at the melting point. The equation used for this calculation assumes that the heat capacity and melting point of CH2Cl2 remain constant throughout the process, and thus the calculated value is only an estimate.

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Answer:

Moving blood through your body

Explanation:

Thats the job of vascular system IE heart arteries and veins.