The value of the test statistic z is approximately -2.12. The Option D is correct.
What is the value of the test statistic z?To test the hypothesis that the mean wrist breadth of men is equal to 9 cm, we will use a one-sample z-test.
The null hypothesis is: H0: µ = 9 cm
The alternative hypothesis is: Ha: µ ≠ 9 cm
We are given a sample of n = 72 men with a sample mean of x = 8.91 cm and a population standard deviation = 0.36 cm.
The test statistic for a one-sample z-test is given by: z = (x - µ) / (o / sqrt(n))
Substituting the given values, we get:
= (8.91 - 9) / (0.36 / sqrt(72))
z = -2.119
At a significance level of a = 0.01, the critical values for a two-tailed test are ±2.576.
Since our test statistic (-2.119) falls outside of this range, we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the mean wrist breadth of men is not equal to 9 cm.
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What is true about the constant of variation for an inverse variation relationship?
Answer:
it is the product of the independent and dependent variables
Step-by-step explanation:
I took a quiz and got that answer right
The constant of variation for an inverse variation relationship is always a fixed value.
What is a characteristic of the constant of variation in an inverse variation relationship?Inverse variation is a relationship between two variables where an increase in one variable results in a decrease in the other variable, while a decrease in one variable results in an increase in the other variable.
Mathematically, this relationship is expressed as y = k/x, where k is the constant of variation.
The constant of variation represents the ratio of the two variables in the inverse variation relationship. It is a fixed value because it remains the same regardless of the values of the variables.
For example, if y varies inversely with x, and y = 4 when x = 2, then the constant of variation is k = xy = 4(2) = 8. This means that y will always be equal to 8/x in this inverse variation relationship.
Therefore, the constant of variation for an inverse variation relationship is always a fixed value, and it represents the ratio between the two variables in the relationship.
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Determine o valor das letras para que a sequencia 4,8,a,18 seja inversamente proporcional a sequencia 54,b,24,c
Answer:
Step-by-step explanation:
The values of the letters are: a = k / (648b), b = k / (1296c), c = k / (1296b) and 24c = k / (576a).
To determine the value of the letters in the given sequences, we need to first recall the formula for inverse proportionality, which states that the product of the terms in one sequence is equal to the constant value of the product of the terms in the other sequence. Mathematically, we can represent this as:
4 x 8 x a x 18 = k = 54 x b x 24 x c
Here, k is the constant of proportionality. To find the value of the letters, we can solve for them algebraically. First, we can simplify the equation by dividing both sides by 4 x 18 x 24:
a = k / (4 x 8 x 18 x 24 / 54 x b x c)
a = k / (6b c)
Next, we can substitute the given values of the sequence into the equation and simplify:
a = k / (6b c) = k / (648b)
Multiplying both sides by 648b, we get:
648b a = k
Similarly, we can solve for the values of the other letters as follows:
b = k / (54 x 24 x c) = k / (1296c)
24c = k / (4 x 8 x a x 18) = k / (576a)
c = k / (54 x b x 24) = k / (1296b)
Therefore, the values of the letters are:
a = k / (648b)
b = k / (1296c)
c = k / (1296b)
24c = k / (576a)
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Choose the correct answer.
Find the quadratic equation given the points (6,0), (-1,0), and (7,4).
h(x) = 1/2(x + 1)(x − 6)
h(x) = 2(x+6)(x − 1)
h(x) = 2(x + 1)(x - 6)
h(x):1/2(x+6) (x - 1)
The quadratic equation given the points (6,0), (-1,0), and (7,4).
The correct answer is h(x) = 1/2(x + 1)(x - 6).
To find the quadratic equation given the points (6,0), (-1,0), and (7,4), we can use the general form of a quadratic equation, which is [tex]h(x) = ax^2 + bx + c.[/tex]
First, let's substitute the coordinates of the given points into the equation to create a system of equations:
For the point (6,0):
[tex]0 = a(6)^2 + b(6) + c ---- (1)[/tex]
For the point (-1,0):
[tex]0 = a(-1)^2 + b(-1) + c ---- (2)[/tex]
For the point (7,4):
[tex]4 = a(7)^2 + b(7) + c ---- (3)[/tex]
We now have a system of three equations with three unknowns (a, b, c). We can solve this system to find the values of a, b, and c.
Solving the system of equations (1), (2), and (3), we find:
a = 1/2
b = -3/2
c = 0
Thus, the quadratic equation that satisfies the given points is:
h(x) = 1/2(x + 1)(x - 6).
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I need help its asking me to find the absolute value of the difference of the theoretical and experimental probabilities.
To find the absolute value of the difference between theoretical and experimental probabilities, you need to follow these steps:
1. Calculate the theoretical probability: This is the probability of an event occurring based on the total number of possible outcomes. It can be found by dividing the number of successful outcomes by the total number of possible outcomes.
2. Calculate the experimental probability: This is the probability of an event occurring based on actual experiments or trials. It can be found by dividing the number of successful outcomes by the total number of trials conducted.
3. Find the difference: Subtract the experimental probability from the theoretical probability.
4. Take the absolute value: The absolute value is the non-negative value of a number, disregarding its sign. To find the absolute value of the difference, simply remove the negative sign if the result is negative.
By following these steps, you'll find the absolute value of the difference between theoretical and experimental probabilities, which is an important measure to assess the accuracy of experiments and predictions.
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A researcher found that 66% of a sample of 14 infants had completed the hepatitis b vaccine series. can we conclude on the basis of these data that, in the sampled population, more than 60% have completed the series? use α = 0.01.
To determine if we can conclude that more than 60% of the sampled population have completed the Hepatitis B vaccine series, we need to perform a hypothesis test.
Our null hypothesis (H0) is that the proportion of infants who completed the vaccine series is equal to or less than 60%, while our alternative hypothesis (Ha) is that the proportion is greater than 60%.
We can use a one-sample proportion test to test this hypothesis. The test statistic is calculated as follows:
z = (p - P) / sqrt(P(1-P)/n)
where p is the sample proportion (0.66), P is the hypothesized proportion under the null hypothesis (0.6), and n is the sample size (14).
Plugging in the values, we get:
z = (0.66 - 0.6) / sqrt(0.6(1-0.6)/14) = 0.67
Using a significance level of α = 0.01, our critical value for a one-tailed test is 2.33 (from a z-table). Since our test statistic (0.67) is less than the critical value (2.33), we fail to reject the null hypothesis.
Therefore, we cannot conclude that more than 60% of the sampled population have completed the hepatitis b vaccine series based on these data.
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The highest BASE drop zone in the world is the Kjerag in Norway, where BASE jumpers make an almost straight down plunge at a height of 3,228 feet. The function
represents the time t (in seconds) that it takes a BASE jumper to fall d feet. How far will a BASE jumper fall in 4. 5 seconds?
feet
A BASE jumper will fall 324 feet in 4.5 seconds.
What are velocity ?
velocity is a unit of measurement for the Distance an object travels in a
the predetermined period of time. Here is a word equation that illustrates the connection between space, speed, and time: velocity is calculated by dividing the total Distance traveled by the journey time.
We can use the given function to find out how far a BASE jumper will fall in 4.5 seconds:
d = 16t²
where d is the distance (in feet) and t is the time (in seconds).
Substitute t = 4.5 into the formula:
d = 16(4.5)²
d = 324
Therefore, a BASE jumper will fall 324 feet in 4.5 seconds.
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i need this answer in by 6:00.. i have tutoring at that time
Answer:
80
Step-by-step explanation:
v=bxh
v=10x8
v=80
A computer company wants to determine the proportion of defective computer chips from a day’s production. A quality control specialist takes a random sample of 100 chips from the day’s production and determines that there were 12 defective chips. He wants to construct a 90% confidence interval for the true proportion of defective chips from the day’s production. Are the conditions for inference met?
Yes, the conditions for inference are met.
No, the 10% condition is not met.
No, the randomness condition is not met.
No, the Large Counts Condition is not met
The conditions for inference are indeed met. The correct option is:
Yes, the conditions for inference are met.
The conditions for inference are met when conducting a confidence interval for a proportion if the following conditions are satisfied:
Random Sample: The sample should be a simple random sample or a random sample from a well-defined sampling frame. This ensures that the sample is representative of the population of interest.
Large Counts Condition: The sample size should be large enough so that both the number of successes (defective chips) and failures (non-defective chips) in the sample are at least 10. This ensures that the sampling distribution of the proportion is approximately normal.
Independence: The individual observations in the sample should be independent of each other.
In this scenario, the quality control specialist took a random sample of 100 chips from the day's production, which satisfies the random sample condition.
Now, let's check the Large Counts Condition.
The quality control specialist found 12 defective chips in the sample. To satisfy the Large Counts Condition, both the number of defective chips and the number of non-defective chips should be at least 10.
In this case, the number of defective chips is 12, and the number of non-defective chips is 100 - 12 = 88.
Both numbers are greater than 10, so the Large Counts Condition is met.
Since both the random sample condition and the Large Counts Condition are met, the conditions for inference are indeed met. Therefore, the answer is:
Yes, the conditions for inference are met.
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The tops of two vertical poles of heights 20 m and 15 m joined by a taut wire 12 m long. What is the angle of slope of the wire?
The angle of the tops of two vertical poles of heights 20 m and 15 m joined by a taut wire 12 m long slope of the wire = 24.6 °
Height of the 1st vertical pole = 20m
Height of the second vertical pole = 15m
Difference of their height = 5 m
Length of the taut wire = 12m
Using trigonometry ratio of sin we get
Perpendicular = 5 m
Hypotenuse = 12 m
Sin A = Perpendicular/ hypotenuse
Sin A = 5/12
A = [tex]sin^{-1} (5/12)[/tex]
A = 24.6 °
The angle of slope of the wire = 24.6°
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Solve the write an equation of the line that passes through a pair of points a. y=x+3 b. y=x-3 c. y=-x+2 d. y=-x-2
The equation of the line passing through the points (0,-2) and (2,0) is y = x - 2.
What is equation?An equation is a mathematical statement that shows that two expressions are equal. It typically consists of variables, constants, and mathematical operations, such as addition, subtraction, multiplication, and division, and can be represented using symbols and/or words. Equations are used to solve problems in mathematics, science, engineering, and other fields.
In the given question,
We can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.
First, we need to find the slope of the line passing through the points (0,-2) and (2,0):
slope = (change in y)/(change in x)
slope = (0 - (-2))/(2 - 0)
slope = 2/2
slope = 1
Now that we have the slope, we can use one of the given equations and substitute the coordinates of one of the points to find the y-intercept:
y = mx + b
-2 = 1(0) + b
b = -2
So the equation of the line passing through the points (0,-2) and (2,0) is y = x - 2.
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Please help me this and can you write answer in box!!!!!
Use the gradient to find the directional derivative of the function at P in the direction of PQ. . f(x, y) = 3x2 - y2 + 4, = P(3, 1), Q(2, 4)
The directional derivative of the function f(x, y) = 3x^2 - y^2 + 4 at P(3, 1) in the direction of PQ is -24/sqrt(10).
To find the directional derivative of the function f(x, y) = 3x^2 - y^2 + 4 at point P(3, 1) in the direction of PQ, follow these steps:
Step 1: Compute the gradient of the function. The gradient of f(x, y) is given by the partial derivatives with respect to x and y: ∇f(x, y) = (df/dx, df/dy) = (6x, -2y)
Step 2: Calculate the gradient at point P(3, 1). ∇f(3, 1) = (6(3), -2(1)) = (18, -2)
Step 3: Calculate the unit vector in the direction of PQ. First, find the difference vector PQ = Q - P = (2-3, 4-1) = (-1, 3). Next, find the magnitude of PQ: |PQ| = sqrt((-1)^2 + (3)^2) = sqrt(10). Then, calculate the unit vector uPQ = PQ / |PQ| = (-1/sqrt(10), 3/sqrt(10)).
Step 4: Compute the directional derivative of f at P in the direction of PQ. The directional derivative, D_uPQ f(P), is given by the dot product of the gradient at P and the unit vector uPQ: D_uPQ f(P) = ∇f(P) • uPQ = (18, -2) • (-1/sqrt(10), 3/sqrt(10)) = 18(-1/sqrt(10)) - 2(3/sqrt(10)) = -18/sqrt(10) - 6/sqrt(10) = -24/sqrt(10)
So the directional derivative of the function f(x, y) = 3x^2 - y^2 + 4 at P(3, 1) in the direction of PQ is -24/sqrt(10).
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Next Problem (1 point) Suppose f"(x) = -(sin(x)), f'(0) = 0, and f(0) = -3. - Find f(1/4). f(1/4) = 1
f(1/4) is approximately equal to -2.9974. The problem states that f"(x) = -(sin(x)), which means that the second derivative of the function f(x) is equal to the negative of the sine of x. We are also given that f'(0) = 0 and f(0) = -3.
To find f(1/4), we need to use the information given to us and apply the process of integration. We know that the first derivative of f(x) is f'(x), so we need to integrate f"(x) to find f'(x). Integrating the negative sine function will give us the cosine function, so:
f'(x) = -cos(x) + C
Where C is a constant of integration. To find the value of C, we use the fact that f'(0) = 0:
0 = -cos(0) + C
C = 1
So now we have:
f'(x) = -cos(x) + 1
Next, we integrate f'(x) to find f(x):
f(x) = -sin(x) + x + D
Where D is another constant of integration. We can find the value of D by using the fact that f(0) = -3:
-3 = -sin(0) + 0 + D
D = -3
So finally, we have:
f(x) = -sin(x) + x - 3
Now we can find f(1/4):
f(1/4) = -sin(1/4) + (1/4) - 3
f(1/4) = -0.2474 + 0.25 - 3
f(1/4) = -2.9974
Therefore, f(1/4) is approximately equal to -2.9974.
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Mrs. Hinojosa had 75 feet of ribbon. If each of the 18 students in her
class gets an equal length of ribbon, how long will each piece be?
Write your answer in 3 ways:
a. using only feet
b. using a whole number of feet and a whole number of inches
c. using only inches
Using division operation with unit conversions, the length of ribbon that each of the 18 students in Mrs. Hinojosa's class gets is as follows:
a) 4.2 feet.
b) 4 feet and 2 inches
c) 50 inches.
What is division operation?Division and multiplication operations are used in unit conversions.
Unit conversions involve converting measurements from hours to minutes or seconds, centimeters to meters and miles, etc.
The total quantity of ribbon Mrs. Hinojosa had = 75 feet
1 foot = 12 inches
75 feet = 900 inches (75 x 12)
The number of students in the class = 18
The length of ribbon received by each student = 4.167 feet (75 ÷ 18)
The length of ribbon received by each student ≈ 4 feet and 2 inches
The length of ribbon received by each student in inches only = 50 inches (900 ÷ 18)
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Mrs. Thomas has two rolls of garden edging that are each 96 inches long.
She wants to make two new flower beds in her back yard. Each flower bed
will be bordered by one roll of the edging. One flower bed will be in the
shape of a quadrilateral. The other will be in the shape of a triangle.
Mrs. Thomas decides to make a scale drawing of each flower bed using a
scale of 1 centimeter = 5 inches. What will be the total length of each roll
of edging in her scale drawings?
The total length of each roll of edging in Mrs. Thomas's scale drawings will be 19.2 cm.
How to find the total length ?To find the total length of each roll of edging in her scale drawings, we need to convert the length from inches to centimeters using the given scale.
To convert the length to centimeters:
( Length in cm ) / ( Length in inches ) = ( 1 cm ) / ( 5 inches )
x / 96 inches = 1 cm / 5 inches
x 5 inches = 96 inches x 1 cm
5x = 96 cm
x = 96 cm / 5
x = 19.2 cm
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Examples of geometric transformations can be found throughout the real world. Think about some places where you might use or se transformations. Give at least three examples for each type of transformation. Make use of the Internet, books, magazines, newspapers, and everyday life experiences to come up with your examples.
Geometric transformations can be found in everyday life, such as moving furniture (translation), opening a door (rotation), using mirrors (reflection), zooming in and out of maps (scaling), skewing images in Photoshop (shearing), and stretching a rubber band (stretching).
Here are some examples of different types of transformations and their applications:
Translation:
Moving furniture in a room
Moving a vehicle on a map
Shifting a picture on a wall
Rotation:
Swinging a pendulum
Turning a key in a lock
Opening a door
Reflection:
Mirrors reflecting images
Water reflections of a landscape
Reflective surfaces on cars and buildings
Scaling:
Enlarging or reducing a picture on a screen
Adjusting the size of a printout
Shearing:
Skewing an image in Photoshop
Tilting a picture frame on a wall
Slanting the roof of a building for better drainage
Stretching:
Stretching a rubber band
Stretching a balloon before inflating it
Stretching a canvas for painting
These are just a few examples of the many ways geometric transformations are used in our everyday lives. By understanding these concepts, we can appreciate the beauty and functionality of the world around us.
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The Integral ∫55dx/√86x - x^2 can converges to
The integral ∫(5/5)dx/√[86(x^2 - x^2)] converges to 5 since the denominator becomes 0 at x=0, which is not in the interval of integration [5,5].
We can start by simplifying the integrand
∫(5/5)dx/√[86(x^2 - x^2)]
Using the identity a^2 - b^2 = (a + b)(a - b), we can rewrite the denominator as
√[86(x^2 - x^2)] = √[86(x + x)(x - x)] = √[86] * √[x + x] * √[x - x] = √[86] * √[2x] * √[0] = 0
Therefore, the integrand is undefined when x = 0. Since the interval of integration is [5,5], which does not include 0, the integral is well-defined and converges to 5.
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Select the correct answer. Harriet is cultivating a strain of bacteria in a petri dish. Currently, she has 10^3 bacteria in the dish. The bacteria divide every two hours such that the number of bacteria has doubled by the end of every second hour. How many bacteria will Harriet have in the dish at the end of 6 hours?
A. 10^24
B. 10^3 TIMES 6
C. 20^3
D. 10^3 TIMES 8
10³ times 8 bacteria will Harriet have in the dish at the end of 6 hours, if she has 10³ bacteria now and they double every 2 hours, option D.
Starting with the initial number of bacteria: 10³
Since the bacteria double every 2 hours, after 2 hours, there will be 10³ × 2 bacteria.
After another 2 hours (total of 4 hours), the bacteria will double again: (10³ × 2) × 2 = 1³ × 2²
After the final 2 hours (total of 6 hours), the bacteria will double once more: (10³ × 2²) × 2 = 10³ × 2³
So, at the end of 6 hours, Harriet will have 10³ × 2³ bacteria in the dish. The correct answer is D. 10³ times 8.
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Which ordered pair could be the y intercept of a function?
Answer:
C) (0,1)
Step-by-step explanation:
What is a y-intercept?
A y-intercept is a value when x=0, so up and down the y-axis of a graph.
Given this, we can see that x must be equal to 0 to have a y-intercept number.
The first option, (1,1), is located in the first quadrant, making this incorrect.
The second option, (1,0) is when y=0, so the point would be on the x-axis, making this also incorrect.
The third option, (0,1), is when x=0, meaning that the point would be on the y-axis, making this the correct option.
Hope this helps! :)
In a certain game you have to guess the number that your opponent writes down on a sheet of paper. you get five guesses. after each guess, your opponent has to tell you if your number is too high or too low. each guess is considered ____ the last guess.
After each guess, your opponent has to tell you if your number is too high or too low. each guess is considered fifth attempt the last guess.
Let's dive deeper into the game and understand it from a mathematical perspective. You are given five chances to guess the number your opponent has written down. In each turn, you can guess a number, and your opponent will tell you if the number you guessed is too high or too low. This information is crucial because it helps you to narrow down the possibilities of what the actual number could be.
Now, let's consider the game in mathematical terms. Suppose the number your opponent has written down is called "X." Your goal is to guess X in five attempts. Let's call these attempts "A1, A2, A3, A4, and A5." After each attempt, your opponent will give you a clue that the number you guessed is either too high or too low. Based on this feedback, you can eliminate some possibilities of what the number X could be.
As you can see, with each guess, you are narrowing down the possibilities of what the number X could be. The game is all about using logical reasoning and deduction to guess the number X correctly in five attempts. If you guess the number correctly before your fifth attempt, you win the game.
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This question please
Box of candy contains 0. 6 of a pound of caramels 3. 6 pounds of coconut What percent the contents of the box, by weight consists of caramels?
The contents of the box, by weight, consists of 14.29 percent caramels.
We need to find the percentage of caramels in the box, given the weights of caramels and coconut candies.
Step 1: Determine the total weight of the candies in the box.
The box contains 0.6 pounds of caramels and 3.6 pounds of coconut candies. Add these two weights together:
Total weight = 0.6 (caramels) + 3.6 (coconut)
Total weight = 4.2 pounds
Step 2: Calculate the percentage of caramels in the box.
To find the percentage, divide the weight of caramels by the total weight of the box and then multiply by 100:
Percentage of caramels = (Weight of caramels / Total weight) x 100
Percentage of caramels = (0.6 / 4.2) x 100
Step 3: Solve the equation.
Percentage of caramels = (0.6 / 4.2) x 100 ≈ 14.29%
So, approximately 14.29% of the contents of the box, by weight, consists of caramels.
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what is the length of the hypotenuse of the triangle when x=2? round your answer to the nearest tenth
Answer:
17.1
Step-by-step explanation:
A) Eight percent (8%) of all college graduates hired by companies stay with the same company for more than five years. (i) What is the probability, rounded to four decimal places, that in a random sample of 15 such college graduates hired recently by companies, exactly 2 would stay with the same company for more than five years?(4 marks)
(ii) What is the probability, rounded to four decimal places, that in a random sample of 15 such college graduates hired recently by companies, more than 3 would stay with the same company for more than five years? (5 marks)
(iii) If 24 college graduates were hired by companies, how many are expected to stay with the same company for more than five years. (2 marks)
(iv) Describe the shape of this distribution. Justify your answer using the relevant statistics
The probability that exactly 2 out of 15 college graduates stay with the same company 0.0246, the probability that more than 3 out of 15 college graduates stay with the same company is 0.0567, 2 college graduates would stay in the company and the shape of the binomial distribution is approximately normal
(i) To find the probability that exactly 2 out of 15 college graduates stay with the same company for more than five years, we use the binomial probability formula:
P(X = 2) = (15 choose 2) * (0.08)^2 * (0.92)^13
= 105 * 0.0064 * 0.3369
≈ 0.0246
So the probability, rounded to four decimal places, is 0.0246.
(ii) To find the probability that more than 3 out of 15 college graduates stay with the same company for more than five years, we can use the complement rule and find the probability of 3 or fewer staying with the same company, and then subtract that from 1:
P(X > 3) = 1 - P(X ≤ 3)
= 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)]
= 1 - [(15 choose 0) * (0.08)^0 * (0.92)^15 + (15 choose 1) * (0.08)^1 * (0.92)^14 + (15 choose 2) * (0.08)^2 * (0.92)^13 + (15 choose 3) * (0.08)^3 * (0.92)^12]
≈ 0.0567
So the probability, rounded to four decimal places, is 0.0567.
(iii) If 8% of all college graduates hired by companies stay with the same company for more than five years, then we would expect 0.08 * 24 = 1.92 college graduates to stay with the same company for more than five years. Since we cannot have a fractional number of college graduates, we would expect 2 college graduates to stay with the same company for more than five years.
(iv) The distribution of the number of college graduates staying with the same company for more than five years follows a binomial distribution. This is because each college graduate either stays with the same company for more than five years or they do not, and the probability of success (staying with the same company for more than five years) is constant for all college graduates.
The shape of the binomial distribution is approximately normal, provided that both np and n(1-p) are greater than or equal to 10, where n is the sample size and p is the probability of success. In this case, np = 15 * 0.08 = 1.2 and n(1-p) = 15 * 0.92 = 13.8, which are both greater than or equal to 10, so we can assume that the distribution is approximately normal.
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The mean test score of 12 students is 42. A student joins the class and the mean becomes 43. Find the test score of the student who joined the class
The test score of the student who joined the class is 55.
To find the test score of the student who joined the class, we can use the formula for calculating the mean:
Mean = (Sum of all values) / (Number of values)
We know that the mean test score of the original 12 students was 42. This means that the sum of their test scores was:
Sum of scores = Mean x Number of students = 42 x 12 = 504
Now, when the new student joins the class, the mean test score becomes 43. This means that the sum of all 13 students' test scores is:
Sum of scores = Mean x Number of students = 43 x 13 = 559
We can subtract the sum of the original 12 students' test scores from the sum of all 13 students' test scores to find the test score of the student who joined the class:
Test score of new student = Sum of all scores - Sum of original scores
Test score of new student = 559 - 504
Test score of new student = 55
Therefore, the test score of the student who joined the class is 55.
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1. If the probability that a light bulb is defective is 0.1, what is the probability that...
a. exactly 3 out of 7 bulbs are defective.
b. exactly 2 out of 5 bulbs are defective.
c. 4 or 5 out of 10 bulbs are defective.
1
d. no bulbs out of 10 are defective.
e. one or more bulbs out of 10 are defective.
Answer:
a. 5.74%.
b. 7.29%
c. 20.18%
d. 34.87%
e. 65.13%
Step-by-step explanation:
a. This problem can be solved using the binomial distribution formula: P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where n is the sample size, k is the number of successes, p is the probability of success, and (n choose k) is the binomial coefficient.
For this problem, n=7, p=0.1, and we want to find P(X=3). Therefore, we have:
P(X=3) = (7 choose 3) * 0.1^3 * (0.9)^4 = 0.0574, or 5.74%.
b. We have n=5, p=0.1, and we want to find P(X=2). Therefore, we have:
P(X=2) = (5 choose 2) * 0.1^2 * (0.9)^3 = 0.0729, or 7.29%.
c. To find the probability that 4 or 5 out of 10 bulbs are defective, we can use the binomial distribution to find the probabilities of each outcome separately and add them together. We have n=10 and p=0.1.
P(4 out of 10 are defective) = (10 choose 4) * 0.1^4 * (0.9)^6 = 0.1937, or 19.37%.
P(5 out of 10 are defective) = (10 choose 5) * 0.1^5 * (0.9)^5 = 0.0081, or 0.81%.
P(4 or 5 out of 10 are defective) = P(4 out of 10 are defective) + P(5 out of 10 are defective) = 0.1937 + 0.0081 = 0.2018, or 20.18%.
d. To find the probability that no bulbs out of 10 are defective, we can use the binomial distribution with n=10 and p=0.1, and find P(X=0). Therefore, we have:
P(X=0) = (10 choose 0) * 0.1^0 * (0.9)^10 = 0.3487, or 34.87%.
e. To find the probability that one or more bulbs out of 10 are defective, we can use the complement rule and subtract the probability of no bulbs being defective from 1. Therefore, we have:
P(one or more bulbs out of 10 are defective) = 1 - P(X=0) = 1 - 0.3487 = 0.6513, or 65.13%.
How might the graph be redrawn to emphasize the difference between the cost per doctor visit for each of the three plans? The scale on the y-axis could be changed to 0–100. The scale on the y-axis could be changed to 25–40. The interval of the y-axis could be changed to count by 5s. The interval of the y-axis could be changed to count by 20s.
To emphasize the difference between the cost per doctor visit for each of the three plans, you can change the scale on the y-axis to either 0–100 or 25–40 and adjust the interval of the y-axis to count by 5s.
To emphasize the difference, you can consider the following adjustments to the graph:
1. Change the scale on the y-axis to 0–100. This adjustment will give a wider range for the costs, making it easier to see the differences between the three plans.
2. Alternatively, change the scale on the y-axis to 25–40. This change will focus more on the specific cost range that the three plans fall into, magnifying the differences between them.
3. Change the interval of the y-axis to count by 5s. This alteration will increase the number of increments on the y-axis, giving a more detailed view of the cost differences between the plans.
4. On the other hand, changing the interval of the y-axis to count by 20s might not be the best option. It will decrease the increments on y-axis and make it harder to visualize the cost differences between the plans.
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A shipping container is in the shape of a right rectangular prism with a length of 7 feet, a width of 14 feet, and a height of 13. 5 feet. The container is completely filled with contents that weigh, on average, 0. 66 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?
The weight of the contents in the container is approximately 873 pounds.
A shipping container is in the shape of a right rectangular prism with a length of 7 feet, a width of 14 feet, and a height of 13.5 feet.
To find the volume of the container, we multiply the dimensions: 7 ft × 14 ft × 13.5 ft = 1,323 cubic feet. The container is completely filled with contents that weigh, on average, 0.66 pound per cubic foot.
To find the weight of the contents in the container, we multiply the volume by the average weight: 1,323 ft³ × 0.66 lb/ft³ ≈ 873.18 pounds.
Rounded to the nearest pound, the weight of the contents in the container is approximately 873 pounds.
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Find the finance charge for a 7000 two year loan with a 6.75 APR
The finance charge for a $7000 two year loan with a 6.75% APR is $945.
What is the finance charge for a 7000 two year loan with a 6.75 APR?To determine the finance charge for a $7000 two year loan with a 6.75% APR, we need to use the following formula:
Finance charge = (Amount borrowed × Annual percentage rate) × Time period
Given that, the amount borrowed is $7000, the annual percentage rate (APR) is 6.75%, and the time period is two years.
First, we need to convert the APR to a decimal by dividing it by 100:
APR = 6.75%
APR = 6.75/100
APR = 0.0675
Now we can plug in the values into the formula:
Finance charge = (Amount borrowed × Annual percentage rate) × Time period
Finance charge = ( $7000 × 0.0675) x 2
Finance charge = $945
Therefore, the finance charge is $945.
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Darren made a display board in the shape of a trapezoid.
Part A
The height of the trapezoid is half the length of the shorter base, and the longer base is twice the length
of the shorter base.
4 yd
2 yd
2 yd
b
What are the lengths of the height and the longer base? Enter your answers in the boxes.
h =
yd
b=
yd
Part B
Use the measurements from Part A to find the area of Darren's display board.
o 8 yd?
12 yd?
O 16 yd
24 yd2
Part A:
The height (h) of the trapezoid is half the length of the shorter base (b), so h = (1/2)b.
The longer base is twice the length of the shorter base, so the longer base is 2b.
Given: 4 yd + 2 yd + 2 yd + b = 8 yd (since the sum of all sides of the trapezoid is equal to the perimeter of the display board)
Solving for b, we get:
b = 2 yd
Substituting this value in the equation for h, we get:
h = (1/2)(2 yd) = 1 yd
Therefore, the length of the height is 1 yd and the length of the longer base is 4 yd.
Part B:
The formula for the area of a trapezoid is A = (1/2)(h)(b1 + b2), where h is the height and b1 and b2 are the lengths of the two bases.
Using the values from Part A, we have:
A = (1/2)(1 yd)(2 yd + 4 yd)
A = (1/2)(1 yd)(6 yd)
A = 3 yd^2
Therefore, the area of Darren's display board is 3 yd^2.
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how to find vertex form when you have the parabola
Answer:
Step-by-step explanation: The vertex is the point at the bottom if the parabola opens up and at the top if it opens at the bottom.
Use the definition of the laplace transform to show that if f(x) = 0 then
[tex]l[f(x)] = 0[/tex]
show that f(x)= 1 then
[tex]l[f(x)] = \frac{1}{s} [/tex]
show that f(x)= x then
[tex]l[f(x)] = \frac{1}{ {s}^{2} } [/tex]
show that f(x)= e^ax then
[tex]l[f(x)] = \frac{1}{s - a} [/tex]
provide the steps by using the definition and evaluating the integral.
Answer:
Step-by-step explanation:
the Laplace transform of the function f(x) = e^(ax) is 1/(a-s).
The definition of the Laplace transform of a function f(t) is given by:
L{f(t)} = F(s) = ∫_0^∞ e^(-st) f(t) dt
where s is a complex number.
If f(x) = 0, then we have:
L{f(x)} = L{0} = ∫_0^∞ e^(-st) 0 dt = 0
Therefore, the Laplace transform of the zero function is zero.
If f(x) = 1, then we have:
L{f(x)} = L{1} = ∫_0^∞ e^(-st) dt
Using integration by parts, we get:
L{1} = ∫_0^∞ e^(-st) dt = [-e^(-st)/s]_0^∞ = [0 - (-1/s)] = 1/s
Therefore, the Laplace transform of the constant function 1 is 1/s.
If f(x) = x, then we have:
L{f(x)} = L{x} = ∫_0^∞ e^(-st) x dt
Using integration by parts again, we get:
L{x} = ∫_0^∞ e^(-st) x dt = [(-e^(-st) x)/s]_0^∞ + (1/s) ∫_0^∞ e^(-st) dt
Since e^(-st) x approaches zero as t approaches infinity, the first term evaluates to zero. We can then simplify the second term using the result from part 2:
L{x} = (1/s) ∫_0^∞ e^(-st) dt = 1/s * (1/s) = 1/s^2
Therefore, the Laplace transform of the function f(x) = x is 1/s^2.
If f(x) = e^(ax), then we have:
L{f(x)} = L{e^(ax)} = ∫_0^∞ e^(-st) e^(ax) dt
Simplifying the integrand, we get:
L{e^(ax)} = ∫_0^∞ e^((a-s)t) dt
We can evaluate this integral using the formula:
∫_0^∞ e^(-bx) dx = 1/b
Setting b = a - s, we get:
L{e^(ax)} = ∫_0^∞ e^((a-s)t) dt = 1/(a-s)
Therefore, the Laplace transform of the function f(x) = e^(ax) is 1/(a-s).
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