A village water tank contained some water. The villagers used 10300 litre of the water in the day. A pump supplied 12,700 of the water in the tank. There was 16500 litre of water left in the tank in the end. How much water was there in the tank at first?​

Step-by-step explanation:

(8+(-2)-4)

=8-2-4

=2

(3-5)

=-2

Answer:

c

Step-by-step explanation:

you would do

m = money overall

(m*1.08) +3000= you would do that twelve times

Answer:

Step-by-step explanation:

Understanding the problem:

x -----> number of munchkins

y -----> number of yema

Devise a plan:

x + y ≥ 10

3x + 2y ≥ 50

Carry out:

y ≥ -x + 10 ------------(I)

3x + 2y  ≥ 50

       2y ≥ -3x + 50

        y ≥ [tex]\frac{-3}{2}+\frac{50}{2}[/tex]

       [tex]y \geq \frac{-3}{2}x + 25[/tex]

Answer:

Understanding the problem:

x -----> number of munchkins

y -----> number of yema

Devise a plan:

x + y ≥ 10

3x + 2y ≥ 50

Carry out:

y ≥ -x + 10 ------------(I)

Answer:

She can put fill 2 “2/5 pound bags” and will have 1/5 pounds of raisins remaining.

Step-by-step explanation:

First we change the 2/5 into common denominators by multiplying by 2 and we go from 2/5–>4/10. Now that we have this we can see how many times 4 goes into 9 which is 2 so we know that she can fill 2 “2/5 pound bags.” But 4/10x2=8/10 and since we have 9/10 pounds of raisins we subtract 8/10 from 9/10 to get a difference of 1/10. So we have 1/10 pounds of raisins remaining and she can fill 2 full bags of “2/5 pound bags.”

First one: 7

Second one: 22

Third one: 137

Hope this helps.

Answer:

(4-9)+2=5

Step-by-step explanation:

hope it's it's right

Step-by-step explanation:

For A

The name of two similar triangles is ABC and CED.

For b

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

Here

< BAC = < CED ( given)

<ACB = < ECD ( vertically opposite angles)

Answer: No, it is equal.

Step-by-step explanation:

No, small ....... otherwise your question is wrong......

=>4320/1000=4.32

////////////??????????

=>(,)-------(.).......4(.)32/4(,)32

Which is this?

Answer:

4x-y+3

Step-by-step explanation:

When we are given two points and asked to find the equation of the line, we must find the slope first. After that, it is the same three steps: substitute, distribute, solve for y. You should now be able to write the equation of a line in: point-slope form, slope-intercept form, or standard form

Answer:

3

Step-by-step explanation:

Answer:   it is 1.25

hope i helped

Answer:

1.25

Step-by-step explanation:

yeah

Answer:

90°grados es la respuesta

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the derivatives.

Hence, here

y = 6x^2 -4x +17

so, dy/dx = d(6x^2-4x+17)/dx

===> hence, dy/dx = 12x -4 ( used formula d(x^n) /dx = nx^n-1 )

======> dy/dx = 12x-4

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given value:

[tex]\to f_X (x) \ \ xe^{-x} \ , \ x>0[/tex]

For point a:

Moment generating function of X=?

Using formula:

[tex]\to M(t) =E(e^{tx})= \int^{\infty}_{-\infty} \ e^{tx} f(x) \ dx[/tex]

[tex]M(t) = \int^{\infty}_{-\infty} \ e^{tx}xe^{-x} \ dx = \int^{\infty}_{0} \ xe^{(t-1)x} \ dx[/tex]

integrating the values by parts:

[tex]u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\[/tex]  

        [tex]= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\[/tex]

Therefore, the moment value generating by the function is [tex]=\frac{1}{(t-1)^2}[/tex]

In point b:

[tex]E(X^n)=?[/tex]

Using formula: [tex]E(X^n)= M^{n}_{X}(0)[/tex]

form point (a):

[tex]\to M_{X}(t)=\frac{1}{(t-1)^2}[/tex]

Differentiating the value with respect of t

[tex]M'_{X}(t)=\frac{-2}{(t-1)^3}[/tex]

when [tex]t=0[/tex]

[tex]M'_{X}(0)=\frac{-2}{(0-1)^3}= \frac{-2}{(-1)^3}= \frac{-2}{-1}=2\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M'''_{X}(t)=\frac{(-2)(-3)(-4)}{(t-1)^5}\\\\M''_{X}(0)=\frac{(-2)(-3)(-4)}{(0-1)^5}= \frac{24}{(-1)^5}= \frac{24}{-1}=-24\\\\\therefore \\\\M^{K}_{X} (t)=\frac{(-2)(-3)(-4).....(k+1)}{(t-1)^{k+2}}\\\\[/tex]

[tex]M^{K}_{X} (0)=\frac{(-2)(-3)(-4).....(k+1)}{(-1)^{k+2}}\\\\\therefore\\\\E(X^n) = \frac{(-2)(-3)(-4).....(n+1)}{(-1)^{n+2}}\\\\[/tex]

Answer:

To calculate this you just have to calculate a rule of three with both gas tanks, so if the dad´s car holds 12 gallons of gas, and the mom´s car holds 50% more that means 150% of in the rule of three: So the total amount of gallons that the mom´s car tank can hold is 18 gallons.

Answer:

[tex] A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]

Step-by-step explanation:

[tex] A_{sector} = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ A_{sector} = \frac{144 \degree}{360 \degree} \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 0.4 \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 80.384 \\ \\ A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]

Answer:

Perpendicular lines are lines that cross perfectly to create a 90 degree angle! Kinda like a big cross. with a right angle in the center area

Step-by-step explanation:

Answer:

yes they are perpendicular to eachother because when both the lines cross it makes a right angle 90 degrees making it perpendicular

Step-by-step explanation:

It is located in quadrant 4 hope this helps

yup if I'm not mistaken it's supposed to be iv

Answer: 12 adult tickets where sold

Step-by-step explanation:

Answer:

[tex]P(x=3) = 0.1318[/tex]

Step-by-step explanation:

The question illustrates a binomial distribution and the given parameters are:

Given

[tex]n = 6[/tex] -- sample size

[tex]p = 0.75[/tex] --- probability of success

[tex]r = 3[/tex] --- half of the participant

Using the binomial probability formula, we have:

[tex]P_x = ^nC_xp^x(1-p)^{n-x}[/tex]

For x = 3, the probability is:

[tex]P(x=3) = ^6C_3*0.75^3 * (1-0.75)^{6-3}[/tex]

[tex]P(x=3) = 20*0.75^3 * 0.25^3[/tex]

[tex]P(x=3) = 0.1318[/tex]

Step-by-step explanation:

Answer:25.1

Step-by-step explanation:

Answer:

47.065

Step-by-step explanation:

The formula for area of a circle is A = πr^2

Since the diameter is double the radius, divide 3 in half to get 1.5.

Then plug your numbers into the equation and remember to start with exponents.

3.14 x 1.5^2  or  3.14 x (1.5 x 1.5)

Answer:

7.07 cm

Step-by-step explanation:

Area of a circle = πr²

{diameter = 3 cm ; radius = 3/2 = 1.5 cm}

πr²

= 3.14 x (1.5)²

=3.14 x 2.25

= 7.07 cm (approx)

Answer:

0.3²+3

=3.27

Step-by-step explanation:

please mark me as brainliest

the answer would be,

[tex]u > \frac{3x}{7} - \frac{9x - 7i}{21} [/tex]

sorry. if wrong.

but hope it helps anyways.

Answer:

11

Step-by-step explanation: