A trapezoid has an area of 134.33 square feet. One base is 16 feet long. The height measures 10.1 feet. What is the length of the other base?

Answer:

Step-by-step explanation:

The advantage of designing cars with crumple zones that collapse upon impact is that it helps to absorb the energy of a collision, which can reduce the amount of force that is transferred to the occupants of the vehicle. When a car collides with another object, the kinetic energy of the car is converted into other forms of energy, such as deformation of the car's structure and heat. By designing the car to crumple in certain areas upon impact, the energy of the collision can be dissipated over a longer period of time, reducing the peak force experienced by the occupants of the car. This can help to reduce the risk of injury or death in a collision. Additionally, the deformation of the car's structure can help to redirect the car's momentum, which can reduce the severity of the collision or prevent the car from spinning out of control. Overall, the use of crumple zones in car design is a significant safety improvement that can help to protect drivers and passengers in the event of a collision.

The total distance traveled by the airplane is 15.3 feet.

The Pythagorean theorem asserts that the square of the length of the hypotenuse in a right triangle equals the sum of the squares of the lengths of the two legs in a right triangle. This theorem is the basis for the distance formula. In the distance formula, the hypotenuse is the distance between the two points, and the two legs are the differences between the x- and y-coordinates of the two points. Any two locations in a two-dimensional coordinate system can have their distance between them calculated using the formula.

Let us suppose the starting point, that is, the point for jack as (0, 0).

Now, according to the given placements the position of the other students are:

Destiny: (0,2)

Barbara: (-9,2)

Now, using the distance formula we have:

The distance between Jack and Destiny is:

√[(0-0)² + (2-0)²] = √(4) = 2

The distance between Destiny and Barbara is:

√[(-9-0)² + (2-2)²] = √(81) = 9

The distance between Barbara and Jack is:

√[(0-(-9))² + (0-2)²] = √(85)

So the total distance traveled by the paper airplane is:

2 + 9 + √(85) ≈ 15.3 feet

Hence, the total distance traveled by the airplane is 15.3 feet.

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According to the histogram, a total of five participants had a heart rate between 120 and 130 bpm.

Review the histogram: Look at the histogram and locate the section that represents heart rates between 120 and 130 bpm.

Count the bars: Count the number of bars within that section.

Interpret the bars: Each bar represents one participant, so the total number of bars counted in the previous step represents the number of participants with heart rates between 120 and 130 bpm.

Identify the answer: The total number of bars counted is the answer to the question, which is five.

Therefore, according to the histogram, five participants had a heart rate between 120 and 130 bpm.

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The initial value is 20, the 1-unit growth/decay factor is 1.11, the 1-unit per cent change is 11%, and the function is g(x) = 20(1.11)^x, where x is the input.

Based on the given information, we can determine that the functions in this problem are exponential. To find the initial value, we can simply plug in 0 for the input of the function g(x) and solve for g(0) = 20.
To find the 1-unit growth/decay factor, we can subtract the output of the function at x=0 from the output of the function at x=1 and divide by the output at x=0. This gives us (g(1)-g(0))/g(0) = (22.2-20)/20 = 0.11.
To find the 1-unit percent change, we can multiply the 1-unit growth/decay factor by 100 to get 11%.
Using these calculations, we can write the function as g(x) = 20(1.11)^x. To find g(2) and g(3), we can simply plug in the respective values for x and round to 4 or more decimals.
g(2) = 20(1.11)^2 = 24.4421
g(3) = 20(1.11)^3 = 27.1213
Therefore, the initial value is 20, the 1-unit growth/decay factor is 1.11, the 1-unit percent change is 11%, and the function is g(x) = 20(1.11)^x, where x is the input.

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Answer:

57,310

Step-by-step explanation:

So you can either round up to 57,310 or round down to 57,300 and 57,309 is one away from 57,310 and 9 away from 57,300 so it’s closer to 57,310 therefore 57,310 is the answer

To round 57,309 to the nearest ten, we look at the ones place digit and round up if the digit is 5 or greater. In this case, since the ones place digit is 9, we round up the tens digit to 1.

To round 57,309 to the nearest ten, we look at the digit in the ones place, which is 9. Since 9 is greater than or equal to 5, we round up the tens digit to the next number. Therefore, 57,309 rounded to the nearest ten is 57,310.

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Answer:

5+(-9)=14

Step-by-step explanation:

Answer:

14 and 23

Step-by-step explanation:

To find two arithmetic means between 5 and 23, we need to first find the common difference between consecutive terms.

The common difference (d) between consecutive terms in an arithmetic sequence can be found using the formula:

d = (an - a1) / (n - 1)

where a1 is the first term, an is the last term, and n is the number of terms.

In this case, a1 = 5, an = 23, and n = 3 (since we want to find two means, there will be a total of 4 terms in the sequence). Plugging these values into the formula, we get:

d = (23 - 5) / (3 - 1) = 9

So the common difference between consecutive terms is 9. To find the first mean, we add the common difference to the first term:

First mean = 5 + 9 = 14

To find the second mean, we add the common difference to the first mean:

Second mean = 14 + 9 = 23

Therefore, the two arithmetic means between 5 and 23 are 14 and 23.

By squaring the deviations from the mean, we make them positive numbers, and the sum of the squared deviations will also be a positive number.

In mathematics and statistics, deviation refers to the difference between a value and a reference value or an expected value. More specifically, deviation is a measure of how far a set of numbers is spread out from their average value or the central point.

By squaring the deviations from the mean, we make them positive numbers, and the sum of the squared deviations will also be a positive number. This is because squaring any number makes it positive, regardless of whether the original number was positive or negative.

Additionally, squaring the deviations before summing them up allows us to give more weight to larger deviations from the mean. This is because squaring a larger deviation will result in a much larger value than squaring a smaller deviation, which helps to highlight the effect of outliers or extreme values in the data set.

The sum of the squared deviations is used in many statistical calculations, including calculating the variance and standard deviation of a data set, which are measures of the spread of the data.

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a) The Formula for A(t) is A(t) = 5000 [tex]e^{0.075t[/tex]

b) The differential equation is satisfied by A(t) is

dA/ dt = 375  [tex]e^{0.075t[/tex]

c) Amount after 2 year is $5, 809.

d) t= 4.48 years

We have,

R= 7.5%

P= $5000

a) The Formula for A(t) is

A(t) = P[tex]e^{rt[/tex]

Where P is Principal , t is time.

So, A(t) = 5000 [tex]e^{0.075t[/tex]

b) The differential equation is satisfied by A(t) is

dA/ dt = 375  [tex]e^{0.075t[/tex]

c) Amount after 2 year

A(2) = 5000 (2.71828[tex])^{0.15[/tex]

A(2) = 5000 x 1.1618

A(2)= $5, 809.

d) 7000 = 5000   [tex]e^{0.075t[/tex]

 [tex]e^{0.075t[/tex]= 1.4

Taking log on both side

0.075t log e= log 1.4

0.075t=   0.14612803567/0.4342944819

0.075t= 0.3364

t= 4.48 years

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Answer:

4

Step-by-step explanation:

80 divided by 4 is 20 then you take 20 and divide it by 5 to get 4 so in conclusion X = 4

A. Decimal squares and C. Base ten pieces would be the foremost reasonable manipulative materials for instructing decimal documentation to the hundredths put.

Decimal squares can offer assistance to understudies to visualize the relationship between tenths, hundredths, and thousandths, as each square can be separated into 10 little squares. Understudies can utilize squares to construct and compare decimal numbers to the hundredths put.

Base ten squares can too be utilized to speak to decimals to the hundredths put, with one level speaking to one entirety, one bar speaking to one-tenth, and one unit speaking to one-hundredth. Understudies can construct and compare decimal numbers utilizing the pieces, as well as utilize them to show operations with decimals.

The other manipulative materials recorded (Design pieces, Tangrams, Color Tiles, and Geoboards) are not particularly planned to speak to decimals and would likely not be as viable in instructing decimal documentation to the hundredths put. 

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Therefore, the solutions of the equation 15x⁴ + x³ - 52x² + 20x + 16 = 0 Reducible to Quadratic Equations are:

x₁ = (±2/√5

x₂ = (±2/√3)

x₃ = 0

x₄ = (±1/20)

To solve 15x⁴ + x³ - 52x² + 20x + 16 = 0 by Equations Reducible to Quadratic Equations, we can use the substitution method. Let's first substitute x² = y and rewrite the equation as:

15y² + y - 52y + 20√y + 16 = 0

Now, let's group the terms:

(15y² - 52y + 16) + (y + 20√y) = 0

Let's solve the first quadratic equation:

15y² - 52y + 16 = 0

We can factor this quadratic equation as:

(3y - 4)(5y - 4) = 0

So, the solutions are:

y₁ = 4/5 and y₂ = 4/3

Now, let's solve the second quadratic equation:

y + 20√y = 0

We can factor out y:

y(1 + 20√y) = 0

So, the solutions are:

y₃ = 0 and y₄ = (-1/20)² = 1/400

Now, let's substitute back y = x²:

x₁ = √(y₁) = ±√(4/5) = ±(2/√5)

x₂ = √(y₂) = ±√(4/3) = ±(2/√3)

x₃ = √(y₃) = 0

x₄ = √(y₄) = ±(1/20)

Therefore, the solutions of the equation 15x⁴ + x³ - 52x² + 20x + 16 = 0 are:

x₁ = (±2/√5)

x₂ = (±2/√3)

x₃ = 0

x₄ = (±1/20)

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The mean number of American adults who disapprove of the overall job that President Bush is doing, based on a sample size of 140, is approximately 93.8.

To calculate the mean, we need to first understand what it represents. The mean is a measure of central tendency, which represents the average value of a set of data. In this case, we want to find the average number of American adults who disapprove of President Bush's overall job.

Since we know that 67% of respondents disapproved of President Bush's overall job, we can assume that this percentage also applies to the entire population of American adults.

To find the mean number of American adults who disapprove, we can use the formula:

mean = total / sample size

In this case, the total number of American adults who disapprove can be calculated as:

total = sample size x percentage who disapprove

total = 140 x 0.67

total = 93.8

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The economic impact of fishing for nearly all great lakes states varies, but according to a report by the U.S. Fish and Wildlife Service, it falls within the range of $1 to $8 billion (in millions of dollars).

This impact includes the economic contributions of recreational fishing, commercial fishing, and related industries such as tourism and boat manufacturing. The exact amount varies from state to state and from year to year depending on factors such as weather, fish populations, and fishing regulations.

The Great Lakes region of the United States is home to some of the largest freshwater bodies in the world and boasts a rich variety of fish species. Fishing is an important economic activity in the region, contributing billions of dollars to the local and national economy. The economic impact of fishing in the Great Lakes region includes not only the direct revenue generated by commercial and recreational fishing, but also the indirect and induced effects of fishing-related industries such as tourism and boat manufacturing.

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It is not required to calculate the standard error of a sample mean or the standard error of an estimate in general.

False. The standard error is a measure of the variability of the sample mean and is calculated using the sample standard deviation and sample size, without necessarily requiring the calculation of the pooled variance.

The pooled variance, on the other hand, is a statistic used in hypothesis testing when comparing means from two independent samples, assuming that the two populations have equal variances. It is calculated by pooling the variances of the two samples, weighted by their degrees of freedom, and is used to calculate the standard error of the difference between the means.

While the pooled variance can be used to calculate the standard error of the difference between two means, it is not required to calculate the standard error of a sample mean or the standard error of an estimate in general.

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The mean slope of the function on the interval [-6, 10] is:

Mean slope is -62.

To find the mean slope of the function f(x) on the interval [-6, 10], we

need to calculate the total change in the function over that interval and

divide by the length of the interval:

Mean slope = (f(10) - f(-6)) / (10 - (-6))

We can simplify this by first finding the derivative of the function f(x):

[tex]f'(x) = 6x^2 - 18x - 108[/tex]

Then, we can use the mean value theorem to find the two values of c

where the instantaneous slope of the function equals the mean slope:

[tex]c1 = (-6 + \sqrt{(783)} ) / 3\\c2 = (-6 - \sqrt{ (783)} ) / 3[/tex]

Plugging these values into the derivative of f(x) gives the instantaneous

slope at each value of c:

f'(c1) = 165

f'(c2) = -33

Therefore, the mean slope of the function on the interval [-6, 10] is:

Mean slope = (f(10) - f(-6)) / (10 - (-6)) = (57 - 1015) / 16 = -62

And we can conclude that the mean slope of the function f(x) on the

interval [-6, 10] is equal to -62.

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Answer:

Step-by-step explanation:

Complementary Angles add up to 90°

90°-46°=44°

∠m = 44°

It is true that when conducting a t-test for two independent samples with a two-tailed example and α = 0.05, you divide the α by 2 (0.05/2 = 0.025) to find the critical t-scores that form the boundaries of the critical region. This is because you are considering both tails of the distribution.

True. When conducting a t test for two independent samples with a two-tailed example, we need to find the critical t-scores that form the boundaries of the critical region for α = 0.05. To do this, we divide the α value of 0.05 by 2 to get 0.0250, and then use this value to find the t-scores using a t-distribution table or calculator. This is necessary because we are looking at the possibility of a significant difference in either direction, hence the two-tailed example.

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Measures of m∠1 = 67.4°, m∠2 = 104.5°

What are the measures of angle?

When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.

Here, we have

The exterior angle 121.8° is the sum of the remote interior angles 17.3° and angle 2. Then ...

angle 2 = 121.8° -17.3° = 104.5° . . . . . . . matches the second choice

Angle 2 is the exterior angle of the top triangle. It, too, is the sum of the remote interior angles:

104.5° = angle 1 + 37.1°

angle 1 = 104.5° -37.1° = 67.4°

Hence, the measures of m∠1 = 67.4°, m∠2 = 104.5°.

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1. The dimensions of the printed area are approximately:

4.22 in (smaller value)

6.89 in (larger value).

2. An approximation for t, we can use it to find the point on the graph of f(x) that is closest to (x, y):

t = approximate solution from Newton's method

x-coordinate: t

y-coordinate: [tex]t^2 (21).[/tex]

Let the width of the printed area be x and the length of the printed area be y.

Then the total area of the page, including margins, is:

A = (x + 2)(y + 2)

The area of the printed portion is:

xy = 29

We want to minimize the total area, subject to the constraint that the printed area has an area of 29 square inches.

Using the constraint, we can solve for y in terms of x:

y = 29/x

Substituting this into the equation for A, we get:

A = (x + 2)(29/x + 2)

Expanding this expression, we get:

A = 29 + 2x + 58/x + 4

A = 2x + 58/x + 33.

To find the minimum value of A, we take the derivative with respect to x and set it equal to zero:

[tex]dA/dx = 2 - 58/x^2 = 0[/tex]

Solving for x, we get:

[tex]x = \sqrt{(58)}[/tex]

Substituting this back into the equation for y, we get:

[tex]y = 29/\sqrt{(58) }[/tex]

Therefore, the dimensions of the printed area are approximately:

4.22 in (smaller value)

6.89 in (larger value)

To find the point on the graph of the function [tex]f(x) = x^2 (21)[/tex]that is closest to the point (x, y), we can use the distance formula:

[tex]d = \sqrt{((x - t)^2 + (y - f(t))^2) }[/tex]

where t is the value of x that corresponds to the closest point on the graph, and[tex]f(t) = t^2 (21)[/tex]

We want to minimize d, so we take the derivative of d with respect to t and set it equal to zero:

[tex]dd/dt = (x - t) - 2t(21)(y - f(t)) = 0[/tex]

Expanding f(t), we get:

f(t) = 21t^2

Substituting this into the equation for dd/dt, we get:

[tex]dd/dt = (x - t) - 42ty + 42t^3 = 0[/tex]

Solving for t is difficult, but we can use an iterative numerical method, such as Newton's method, to approximate the solution.

We can start with an initial guess, [tex]t_0[/tex] , and use the iteration:

[tex]t_{n+1} = t_n - dd/dt(t_n) / d^2d/dt^2(t_n)[/tex]

where [tex]dd/dt(t_n)[/tex]  is the value of dd/dt at [tex]t_n[/tex], and [tex]d^2d/dt^2(t_n)[/tex] is the second derivative of d with respect to t evaluated at[tex]t_n.[/tex]

We can continue this iteration until the value of [tex]t_n[/tex] stops changing or until we reach a desired level of accuracy.

Once we have an approximation for t, we can use it to find the point on the graph of f(x) that is closest to (x, y):

t = approximate solution from Newton's method.

x-coordinate: t

y-coordinate: [tex]t^2 (21).[/tex]

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In conclusion, Ann's preferences are likely to be rational, weakly.

In order to determine if Ann's preferences have certain properties, we need to first understand what those properties mean in terms of preferences.

i. Rational:

Rationality is the property of preferences that requires them to be transitive. In other words, if Ann prefers A to B, and B to C, then she must prefer A to C. This is a reasonable assumption for any rational person making choices.

ii. Weakly Monotone:

Weak monotonicity is the property of preferences that requires them to be non-decreasing. In other words, if Ann prefers A to B, then she must prefer any combination of A and B where there is more of A and less of B. For example, if she prefers a bowl of Laksa with 1 chicken breast and 1 fish fillet to a bowl with 1 chicken breast and 1 tofu slice, then she should also prefer a bowl with 2 chicken breasts and 1 fish fillet to a bowl with 1 chicken breast and 1 fish fillet.

iii. Strongly Monotone:

Strong monotonicity is a stronger version of weak monotonicity that requires preferences to be strictly increasing. In other words, if Ann prefers A to B, then she must strictly prefer any combination of A and B where there is more of A and less of B. For example, if she prefers a bowl of Laksa with 1 chicken breast and 1 fish fillet to a bowl with 1 chicken breast and 1 tofu slice, then she must strictly prefer a bowl with 2 chicken breasts and 1 fish fillet to a bowl with 1 chicken breast and 1 fish fillet.

iv. Locally Non-satiated:

Local nonsatiation is the property of preferences that requires them to never be satisfied with any amount of a good. In other words, if Ann prefers A to B, then she must always prefer a little bit more of A to the same amount of B. This is a reasonable assumption for any person making choices, since there is always some amount of a good that would be preferred to the current amount.

a) Now let's consider each property in turn and determine whether Ann's preferences have that property or not.

i. Rational:

Ann's preferences are assumed to be rational, since rationality is a basic requirement for any preferences.

ii. Weakly Monotone:

Ann's preferences for a range of proteins, green vegetables, and noodles in her Laksa are likely to be weakly monotone, since it is reasonable to assume that if she prefers some amount of a good to another, she would prefer any combination of the two where there is more of the preferred good.

iii. Strongly Monotone:

Ann's preferences are not likely to be strongly monotone, since it is possible that she may have some preferences for specific combinations of goods that are not strictly increasing or decreasing. For example, she may prefer a bowl of Laksa with 1 chicken breast and 1 fish fillet to a bowl with 2 chicken breasts and no fish fillet.

iv. Locally Non-satiated:

Ann's preferences are likely to be locally non-satiated, since it is reasonable to assume that she would always prefer a little bit more of a good to the same amount of that good. For example, if she likes a bowl of Laksa with 1 chicken breast, 1 fish fillet, and 1 tofu slice, she would likely prefer a bowl with 1.1 chicken breasts, 1.1 fish fillets, and 1.1 tofu slices to the same bowl with 1 chicken breast, 1 fish fillet, and 1 tofu slice.

In conclusion, Ann's preferences are likely to be rational, weakly

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Answer:

60

Step-by-step explanation:

The answer of the given question based on the commutative property is ,  choice B: c + (a + b).

The commutative property is a fundamental property of some mathematical operations, which states that the order of the operands (inputs) can be changed without affecting the result. In other words, the commutative property means that the operation is independent of the order in which the operands are presented.

The commutative property of addition states that the order of the addends can be changed without changing the sum. In other words, a + b = b + a.

Using this property, we can rearrange the terms in the equation (a + b) + c = A to get:

c + (a + b) = A

This is the same as choice B: c + (a + b). Therefore, the choice that illustrates the commutative property for (a + b) + c is B.

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a) The probability of having at least one major fault in the next 2 km stretch on the highway is approximately 0.959.

b) The distribution of X, the distance between two successive major faults on the highway, is X ~ Exponential (mean=1/1.6). Therefore, the correct option is B.

a) To find the probability of having at least one major fault in the next 2 km stretch on the highway, we first need to find the probability of having zero major faults in that stretch. The number of major faults follows a Poisson distribution with mean λ = 1.6 for every 1 km.

Since we are looking at a 2 km stretch, the new mean is λ' = 2 * 1.6 = 3.2.

Using the Poisson probability mass function (PMF) formula:

P(X = k) = (e^(-λ) * λ^k) / k!

For zero major faults in the 2 km stretch (k = 0):

P(X = 0) = (e^(-3.2) * 3.2^0) / 0! = e^(-3.2)

Now, we want the probability of having at least one major fault, which is the complement of having zero faults:

P(X >= 1) = 1 - P(X = 0) = 1 - e^(-3.2)

Calculating this value:

P(X >= 1) ≈ 1 - 0.040762 = 0.959

So, the probability is approximately 0.959.

b) The distribution of X, the distance between two successive major faults on the highway, is described by an exponential distribution. In this case, the mean distance between major faults is the inverse of the rate (mean number of faults per km).

The rate is λ = 1.6 faults per km, so the mean distance between faults is 1/1.6 km.

Therefore, the correct answer is: B. X ~ Exponential(mean=1/1.6)

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Answer:

$0.78

Step-by-step explanation:

You divide the $7.80 by 10 to get the cost of one tulip.

Answer:

43rd term

Step-by-step explanation:

Given arithmetic sequence:

We can use the formula for the nth term of an arithmetic sequence to find which term the number 203 corresponds to in the given arithmetic sequence.

The formula for the nth term of an arithmetic sequence is:

[tex]\boxed{a_n = a_1 + (n-1)d}[/tex]

where:

For the given sequence, we know that the first term is a₁ = -7.

The common difference is d = 5, since each term is 5 more than the previous term.

Substitute these values into the formula to create an equation for the nth term:

[tex]\begin{aligned} \implies a_n &= -7 + (n-1)5\\&=-7+5n-5\\&=5n-12 \end{aligned}[/tex]

To find the position of number 203 in the sequence, substitute aₙ = 203 into the equation for the nth term and solve for n:

[tex]\begin{aligned} a_n &= 203\\ \implies5n-12&=203\\5n-12+12&=203+12\\5n&=215\\\dfrac{5n}{5}&=\dfrac{215}{5}\\n&=43 \end{aligned}[/tex]

Therefore, the number 203 corresponds to the 43rd term in the given arithmetic sequence.

The probability of selecting apple, a peach and a pear in that order is [tex]4.85%[/tex]%.

In this basket, we have 4 apples, 4 peaches, and 4 pears and will select three pieces of fruit without replacement.

The probability of selecting an apple first is 4/12.

The probability of selecting a peach second is 4/11.

The probability of selecting a pear third is 4/10.

P(Apple, Peach, & Pear) = (4/12) * (4/11) * (4/10)

P(Apple, Peach, & Pear) = 64/1320

P(Apple, Peach, & Pear) = 8/165

P(Apple, Peach, & Pear) = 0.04848484848

P(Apple, Peach, & Pear) = 4.85%

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The solution would be;

⇒ si sin(4x) cos(7x) dx = (1/2) [-cos(11x)/11 + cos(3x)/3] + C.

Now, For evaluate the indefinite integral of sin(4x) cos(7x) dx, we can use the trigonometric identity as;

⇒ sin(A)cos(B) = (1/2)[sin(A + B) + sin(A - B)]

Hence, Applying this identity as;

⇒ sin(4x) cos(7x) = (1/2)[sin(4x + 7x) + sin(4x - 7x)]

                          = (1/2)[sin(11x) + sin(-3x)]

                          = (1/2)[sin(11x) - sin(3x)]

Therefore, the indefinite integral of sin(4x) cos(7x) dx is given by:

∫ sin(4x) cos(7x) dx = (1/2) ∫ [sin(11x) - sin(3x)] dx

                             = (1/2) [-cos(11x)/11 + cos(3x)/3] + C

Hence, The solution would be;

⇒ si sin(4x) cos(7x) dx = (1/2) [-cos(11x)/11 + cos(3x)/3] + C.

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There are 182 buttons that have to be sold to make a profit of $500. And, the equation that represents the given situation is [tex]\$500 = \$2b + \$0.75b[/tex] or [tex]\$500 - \$0.75b = \$2b[/tex] . Therefore, options B and D are true.

Using the idea behind the equation that says,

A set of numerical variables and functions coupled via the use of operations like addition, subtraction, multiplication, and division make form an equation.

Given that,

For homecoming, the Booster Club at Martin Middle School is selling pride buttons.

And, The buttons cost $0.75 to make and will be sold for $2 each.

Let us assume that,

Number of buttons = b

Since we have to calculate the number of buttons to make a profit of $500.

Hence the equation can be written as,

[tex]\$500 = \$2b + \$0.75b[/tex]

Simplify the equation for b,

[tex]\$500 = \$2.75b[/tex]

Divide both sides by 2.75,

[tex]b = \dfrac{500}{2.75}[/tex]

[tex]b = 182[/tex]

Therefore, the correct option is B and D.

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