Answer:
Distance = 420 km
Explanation:
Speed = Distance/ Time
Where speed = 70 km/hr and time = 6 hours
Distance = Speed × Time
D = 70 km/hr × 6 hrs
D = 420 km
Answer:
GIVEN DATA :
TIME TAKEN=t=6h
SPEED OF THE TRAIN=v=70km/h
TO FIND:
DISTANCE COVERED=d=?
SOLUTION:
AS WE KNOW THAT
SPEED=DISTANCE COVERED / TIME TAKEN
SPEED × TIME TAKEN = DISTANCE COVERED
70km/h×6h=distance covered
distance covered=420km
Calcula el trabajo que realiza la fuerza de fregamiento sobre un cuerpo de 13kg que es desplaza una distáncia de 46 m si el coeficiente de fregamiento entre las superficies es de 0,45
Answer:
Los datos que tienes son:
m = 13 kg
d = 46 m
∪ = 0,45
g = 9,8 m/s²
Fr = ?
w = ?
Lo primero que haremos que calcular Fr
Fr = ∪mg
Fr = (0,45) (13 kg) (9,8 m/s²)
Fr = 57,33 N
Calculamos el trabajo realizado.
w = Fd
w = (57,33 N) (46 m)
w = 2637,18 Joules
Respuesta.
El trabajo realizado es 2637,18 Joules
Explanation:
Explain how series circuits use current and voltage and Explain how parallel circuits use current and voltage
'''In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. Components connected in parallel are connected along multiple paths so that the current can split up; the same voltage is applied to each component.''
Standing on top of a building, Bob tosses a baseball straight up with an initial speed of 15 m/s. It takes 4.0 s for the ball to hit the ground. What is the vertical distance of the building? (g = -9.8 m/s²)
Answer:
48.26 m
Explanation:
time to goes up (till stop for a while in the air - maximum height)
vt = vo + a t
0 = 15 + g . t
0 = 15 + (-9.8) . t
9.8t = 15
t = 1.531 s
so the time left to goes down is
4.0 - 1.531 = 2.469 s
height from the top of building can find it by using
vo =√(2gh)
15 = √(2)(9.8).h
15² = 19.6h
h = 225/19.6 = 11.48 m
so the distance of maximum height to the ground is
t = √(2H/g)
2.469 = √(2H/9.8)
2.469² = 2H/9.8
6.096 = 2H/9.8
2H = 6.096 x 9.8 = 59.74 m
so the vertical distance of the building (or the building height's is)
H - h = 59.74 - 11.48 = 48.26 m
Un movil pasa por el punto A en direccion hacia B (350cm más adelante) y, luego, sigue hasta el punto C. Sabiendo que pasa por B a las 11:42:38 y por C a las 11:43:16, completando un tiempo total de recorrido de 3min 47s, calule la distancia entre B y C y a la hora a la que paso por el punto A.
Explanation:
PRIMERO HACES EL RECUENTO DEL TIEMPO Y LO CONVIERTES EN
SEGUNDOS Y ENTONCES
t = 227 s [tex]t_{AB}[/tex] = 227 S - 38 s = 189 s
[tex]t_{BC}[/tex] = 38 s
LUEGO USANDO LA ECUACIÓN DE GALILEO GALILEI SSUPONIENDO
QUE EL MOVIL VIAJA A VELOCIDAD CONSTANTE
v = 3.50 m/189 s = 0.0185 m/s
PARA LA DISTANCIA NTRE B Y C
[tex]x_{BC}[/tex] = 0.0185 m/S( 38 s) = 0.703 m
LA HORA EN QUE EL MOVIL PASA POR A ES
11:43:15 - 38 s - 189 s = 11:39:29
Please give me concept to solve this.
Answer:
The difference in tension, between adjacent sections of the pull cable at the given conditions is 17.701 kN
Explanation:
We take the cars as moving upwards such that the resultant pulling force on the car, F, along the cable is given by the relation
[tex]F_{car}[/tex] = Upward tension force, [tex]Tension_{(upwards)}[/tex] - Downward tension force, [tex]Tension_{(downwards)}[/tex] - Component of the weight of the car along the taut cable
The parameters given are;
Mass of car, m = 2750 kg
Angle of inclination of taut cables, θ = 35°
The upward acceleration of the car, a = 0.81 m/s²
Given that the weight is acting vertically downwards, we have;
Component of the weight of the car along the taut cable = m × g × sin(θ)
∴ Component of the weight of the car along the taut cable = 2750 × 9.81 × sin (35°) = 15473.66 N
We therefore have;
[tex]F_{car}[/tex] = [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] - 15473.66 N
[tex]F_{car}[/tex] = m × a = 2750 × 0.81 = [tex]T_{upwards}[/tex] - [tex]T_{downwards}[/tex] - 15473.66
∴ [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] = 2750 × 0.81 + 15473.66 = 17701.16 N
Hence the difference in tension, [tex]Tension_{(upwards)}[/tex] - [tex]Tension_{(downwards)}[/tex] between adjacent sections of the pull cable if the cars are at the maximum permissible mass and are being accelerated up the incline = 17701.16 N or 17.701 kN.
If a 5kg ball is rolling to the left and has a momentum of -25kg*m/s what is the velocity (not just speed) of the ball
Answer:
The velocity of the ball is 5 m/s to the left.
Explanation:
-25kg*m/s divided by 5 kg gives
speed of -5 m/s
The velocity of the ball is 5 m/s to the left.
write the different between the fall of a parachute on earth and its fall on the moon?on what condition does a body have free fall?
Answer:
Shown from explanation
Explanation:
You have heard that expression what ever goes up must come down that's usually used to mean when you throw an object up, it comes down on its accord. This is due to a force on the earth that occurs in nature known as gravity.
So when an object falls under this influence it's said to fall freely.
Note not all heavenly bodies have gravitational pull, from experience by scientists who went to the moon they found out whatever goes up keeps flying endlessly so in that case an external force is needed to keep objects in the moon on ground level.
Hence the parachute falls on earth freely without an external force but on the moon it must fall with an external force inputed on the parachute system.
This means in the earth we have free fall but in the moon no such thing exist. So a body falls freely when there is gravity.
a linear function has the same y-intercept as x + 4y equals 16 and it's graph contains the point (4,5). Find the slope of the linear function.
Answer: [tex]\bold{\text{Slope (m)}=\dfrac{1}{4}}[/tex]
Explanation:
A linear equation is of the form: y = mx + b where
m is the slopeb is the y-intercept (where it crosses the y-axis)x + 4y = 16
4y = -x + 16
[tex]y = -\dfrac{1}{4}x+\dfrac{16}{4}[/tex]
[tex]y=-\dfrac{1}{4}x+4[/tex]
The y-intercept (b) = 4
Next, find the slope given point (4, 5) and b = 4
[tex]y=mx+b\\\\5=m(4)+4\\\\1=4m\\\\\dfrac{1}{4}=m\\\\\\\\\large\boxed{Slope (m)=\dfrac{1}{4}}[/tex]
A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.
Answer:
Yes, in case of uniform velocity
Explanation:
This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.
Since, acceleration is defined as the rate of change of velocity.
Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.
a = ΔV/t = 0/t
a = 0 m/s²
So, the acceleration of the body is 0 m/s², but it has a uniform velocity
Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.
8. Simple machines make a job easier to perform by
a. decreasing the amount of work
b. decreasing the amount of friction
c. decreasing the amount of force and/or changing the direction of force
d. only lower the amount of force
Answer:
C
Explanation:
For a moving object, the force acting on the object varies directly with the objects acceleration. When a force of 24N acts on a certain object, the acceleration of the object is 3m/s^2. If the acceleration of the object becomes 10m/s^2, what is the force
Answer:
80 N
Explanation:
From the question,
F = ma .......................... Equation 1
Where F = Force, m = mass of the object, a = acceleration of the object.
make m the subject of the equation
m = F/a.................... Equation 2
Given: F = 24 N, a = 3 m/s²
Substitute into equation 2
m = 24/3
m = 8 kg.
If the acceleration of the object becomes 10 m/s²,
Substitute into equation 1
F = 10(8)
F = 80 N.
A train starts from its station and it
velocity reaches 200m/s in 5
seconds. What is its acceleration?
a. 400m/s
b. 40m/s2
c. 4.5m/s2
d. Initial velocity is missing
Answer:
b. 40m/s2
Explanation:
Acceleration is calculated by dividing velocity over time. Therefore 200m/s by 5s equals 40m/s2
Answer:
B
Explanation:
v = vo + at
200 = 0 + a*5
200 = 5a
a = 200/5 = 40 m/s²
initial velocity (vo) is 0 because it says it start from station
A remote controlled plane accelerates to a velocity of 21.0 m/s while covering a distance of 87.4 m in 6.11 s. What was the plane's initial velocity?
Answer:
7.61 m/s
Explanation:
Given:
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
71.6
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
Is there a link between number of bulbs and current drawn from the power pack?
Answer:
Yes, there a link between number of bulbs and current drawn from the power pack.
Explanation:
In an Electrical circuit, we have resistors present in that circuit. These resistors can be connected in two ways.
a) Series connection
b) Parallel connection
There is a link or a relationship between number of bulbs and the current drawn from the power pack. This is because the number of bulbs is equivalent to or equal to the number of resistors.
Hence,
a) In a series connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) decreases.
b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.
a motorcar is moving with a velocity of 108 km / h and it takes 4s to stop after the brakes are applied calculate the force exerted by the brakes on the motorcar if it's mass along with the passengers is 1000 kg
Answer:
-7500 N
Explanation:
v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
Answer:-7500
Explanation v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
What is the force experienced when a 5.0 kg mass is accelerated at 7.5 m/s??
Answer:
F = 37.5 N
Explanation:
It is given that,
Mass of the object is 5 kg
Acceleration of the object is 7.5 m/s²
We need to find the force experienced by the object. The force is given by the product of mass and acceleration of an object. So,
F = m
[tex]F=5\times 7.5\\\\F=37.5\ N[/tex]
So, the force acting on the object is 37.5 N.
PLEASE HELP. Really important
Explanation:
2) C would need the least effort, because the longer the effort distance, the least the effort applied.
Please explain it’s in the photo
Answer:
Since air resistance actually stops vehicles and goes in a vector opposite to the direction of the vehicle and slows it down. Vehicles would want to make vehicles aerodynamic. Many cars bump into air molecules therefore making air resistance. Aerodynamic cars will lesser the allowance of bumping into said molecules. Thats why cars like to cut down on air resistance
Air resistance is friction.
-- Friction steals kinetic energy.
-- A car gets kinetic energy by burning gasoline, and uses the kinetic energy to get where it needs to go.
-- If anything steals the car's kinetic energy, then the car has to burn more gasoline to get where it needs to go.
-- Gasoline costs money.
-- Anything that steals a car's kinetic energy costs you more money to operate the car.
(Another thing that takes kinetic energy away from the car is the car's brakes. The driver uses the brakes when he WANTS to slow down or stop, so it's not stealing, but it still costs kinetic energy and money.)
Which statements best describe X-rays?
Answer:x rays are electromagnetic waves.
x rays are transverse waves
x rays travel at the speed of light
Explanation:
A lonely child is swinging on a rusty old swing set, as seen in the image provided. If friction does 145 J of work slowing the swing, what is the maximum speed she can reach?
Answer:
2.331
Explanation:
It just the change of Energy from potential (PE) to kinetic (KE)
PE on A = PE on B + KE on B + friction works (Wf)
mg(ha) = mg(hb) + ½mv² + Wf
35 * 9.8 * 1.5 = 35 * 9.8 * 0.8 + ½ * 35 * v² + 145
514.5 = 274.4 + 17.5v² + 145
514.5 - 274.4 - 145 = 17.5v²
17v² = 95.1
v² = 5.434
v =√5.434 = 2.331 m/s
Benda setinggi 3 cm diletakkan pada jarak 10 cm di depan cermin cekung yang berjari-jari
kelengkungan 10 cm. Tentukan:
Jarak bayangan
Perbesaran bayangan
Sifat bayangan
Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!
An escalator is used to move 25 passengers every minute from the first floor of a department store to the second. The second floor is located 5.30 meters above the first floor. The average passenger's mass is 60 kg. Determine the power requirement of the escalator in order to move this number of passengers in this amount of time.
Please help me quickly!
Answer:
1298.5watt
Explanation:
Power is defined as the rate at which work is done
Expressed mathematically as;
P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered
Hence for 1 person the power consumption is ;
Note weight =mass× acceleration of free fall due to gravity,g
g is known as 9.8m/S2
Time taken is 1min which is 60 sec
60 ×9.8 × 5.3/60 = 51.94 watt
Hence for 25 persons we have
25 × 51.94 =1298.5watt
1.3kilo watt( kilo is 1000)
The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.
The Work Done is calculated as:
Force (F) = 60 × 9.8
Distance (d) = 5.30 meters
Work (W) = F × d
Work (W) = (60 × 9.8) × 5.30
Work (W) = 3,080.4 joules
The Power is calculated as:
Time (t) = 1 minute
Power (P) = Work / Tim (t)
Power (P) = 3,080.4 / 60
Power (P) = 51.34 watts
Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.
To know more about the work done and power:
https://brainly.com/question/29369495
#SPJ4
Which of these would not improve accuracy?
A)Taking a bigger sample size
B)Using a bigger range of the independent variable
C)Using measuring instruments that can read to a greater number of decimal places
D)Remove anomalies
Ed biked home from school in 400 seconds. His home is located 2000 m south of the school. What was his velocity?
[tex]answer = 5 \: \: metre \: per \: second\\ distance = 2000 \: m \\ time = 400 \: seconds \\ velocity = \: \frac{distance \:t ravelled}{time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2000}{400} \\ \: \: \: \: \: \: \: \: \: = 5 \: metre \: per \: second \\ hope \: it \: helps[/tex]
Help needed plz . Answer what you can. Thanx
Answer:
both a and b have same pressure
What are some advantages
and disadvantages to using
superconductors as electric
transmission lines
Answer:
Insulators show very high resistance to electricity. Conductors like copper show some resistance. Another class of materials show no resistance at all when cooled to very low temperatures, cooler than the coolest deep freezer. Called superconductors, they were discovered in 1911.
Explanation: i looked it up
Mass is the amount of what
Answer:
Mass is the amount of matter in a substance.
Explanation:
The basic SI unit for mass is the kilogram (kg).
can there be shadows at night outside?
Answer:
To see a shadow there most be light provided, even if it's night and there are lights, we can still see the shadow but if there is no light, we can't.
Hope it helped (:
Answer: yes of course, but there should be some light to make or see shadows.
When salt is added to the water what happens to the surface?
Answer:
it increases the surface tension of the water
An object with more mass has more kinetic energy than an object with less
mass, if both objects are moving
OA) at the same speed
OB) in the same direction
OC) in opposite directions
Explanation:
The kinetic energy of an object is given in terms of its mass and object as :
[tex]K=\dfrac{1}{2}mv^2[/tex]
An object with more mass has more kinetic energy. An object with less mass, if both objects are moving at the same speed, in opposite directions, will have less kinetic energy. The square of v will give positive number.
