A study was conducted to determine how bacteria cells multiply over time in a controlled environment. In the study, the bacteria cells were counted once every hour for a total of 6 hours. which one is indepedent variable and dependent varible?

Answer:  see boxed answers below

Step-by-step explanation:

(i) multiply the exponent to the coefficient then subtract 1 from the exponent.

[tex]y=\dfrac{3}{5x^3}+3x^4+2x^2-20\\\\\\\text{rewrite it as follows}: y=\dfrac{3}{5}x^{-3}+3x^4+2x^2-20x^0\\\\\\y'=(-3)\dfrac{3}{5}x^{-3-1}+(4)3x^{4-1}+(2)2x^{2-1}-(0)20x^{0-1}\\\\\\y'=-\dfrac{9}{5}x^{-4}+12x^3+4x^1-0\\\\\\y'=\large\boxed{-\dfrac{9}{5x^{4}}+12x^3+4x}[/tex]

(ii) Use the division formula:    [tex]y = \dfrac{a}{b}\rightarrow \quad y'=\dfrac{ab'-a'b}{b^2}[/tex]

[tex]a=5x^3+1\qquad \qquad a'=15x^2\\b=3x^5+4x^2\qquad \quad b'=15x^4+8x\\\\\\y'=\dfrac{(15x^2)(3x^5+4x^2)-(5x^3+1)(15x^4+8x)}{(3x^5+4x^2)^2}\\\\\\.\quad =\dfrac{45x^7+60x^4-75x^7-55x^4-8x}{(3x^5+4x^2)^2}\\\\\\.\quad =\large\boxed{\dfrac{-35x^7+5x^4-8x}{(3x^5+4x^2)^2}}[/tex]

Answer:

The probability that the number of free throws he makes exceeds 80 is approximately 0.50

Step-by-step explanation:

According to the given data we have the following:

P(Make a Throw) = 0.80%

n=100

Binomial distribution:

mean:   np = 0.80*100= 80

hence, standard deviation=√np(1-p)=√80*0.20=4

Therefore, to calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:

P(X>80)= 1- P(X<80)

You could calculate this value via a normal distributionapproximation:

P(Z<(80-80)/4)=1-P(Z<0)=1-50=0.50

The probability that the number of free throws he makes exceeds 80 is approximately 0.50

The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.

Given that,

A college basketball player makes 80% of his free throws.

Over the course of the season, he will attempt 100 free throws.

Assuming free throw attempts are independent.

We have to determine,

The probability that the number of free throws he makes exceeds 80 is.

According to the question,

P(Make a Throw) = 80% = 0.80

number of free throws n = 100

Binomial distribution:

Mean: [tex]n \times p = 0.80 \times 100 = 80[/tex]

Then, The standard deviation is determined by using the formula;

[tex]= \sqrt{np(1-p)} \\\\=\sqrt{80\times (1-0.80)}\\\\= \sqrt{80 \times 0.20 } \\\\= \sqrt{16} \\\\= 4[/tex]

Therefore,

To calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:

[tex]P(X>80)= 1- P(X<80)[/tex]

To calculate this value via a normal distribution approximation:

[tex]P(Z<\dfrac{80-80}{4})=1-P(Z<0)=1-0.50=0.5000[/tex]

Hence, The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.

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Answer: axiom

Step-by-step explanation:

Answer: [tex]\frac{21}{4}[/tex]

Step-by-step explanation:

Multiply each side by 2 to get rid of the fraction on the right side. That basically gets rid of the 1/2 and the 2.

Youre now stuck with 2x + y = 21. They gave us y which is 2x. 2x + 2x = 4x

You now have 4x = 21

Divide each side by 4 to get x = 21/4

Answer:

D

Step-by-step explanation:

When there is an negative sign inside in a radical, then we remove that and put out of the radical classifying as "i". Then, reduce 63 into smallest form and we can write it as 9 and 7. 9 is a perfect square of 3 so we put it outside and the answer is D.

Answer:

c of what im sure about

Step-by-step explanation:

Answer:

Option 2

Step-by-step explanation:

Because the slope is -0.09 the answer is the second option. A negative slope means a decrease.

Answer:

Option C is correct

Step-by-step explanation:

Given: vertex of this parabola is at (-2,-3)

To find: coefficient of the squared expression in the parabola’s equation if the x-value is -1, the y-value is -5

Solution:

The equation of parabola is of the form [tex]y=a(x-h)^2+k[/tex]

Here, a is the coefficient of the squared expression in the parabola’s equation.

Put [tex](h,k)=(-2,-3)\,,\,(x,y)=(-1,-5)[/tex]

[tex]-5=a(-1+2)^2-3\\-5+3=a(1)^2\\-2=a\\a=-2[/tex]

So, the coefficient of the squared expression in the parabola’s equation is [tex]-2[/tex]

Answer:

n = 3 or n = 4

Step-by-step explanation:

Let the unknown number be n.  

Then:

n² = 7n - 12

In standard quadratic form, we have:

n² - 7n + 12 = 0

In factored form, we have:

(n - 3)(n - 4) = 0, and so

n = 3 and n = 4

Answer:

AOB = 73

BOC = 107

Step-by-step explanation:

So make an equation.

9x + 27 = 180

9x = 153

x = 17

AOB = 73

BOC = 107

By completing the square the function will be, g(x)=4(x-2)²-9

The standard form of the quadratic equation will be ax²+bx+c=0.

Equate the given equation with standard form of equation and determine the values of a, b, and c.

a=4

b=-16

c=7

For completing the square, add and subtract [tex]\frac{b^2}{4a}=\frac{(-16)^2}{4\times4}=16[/tex] in the given equation.

g(x)=4x²-16x+16-16+7

g(x)=(4x²-16x+16)-9

g(x)=4(x²-4x+4)-9

The term x²-4x+4 is equivalent to (x-2)².

g(x)=4(x-2)²-9

So, the given function is same as g(x)=4(x-2)²-9.

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Answer:

Step-by-step explanation:

5

Answer:

2/3

Step-by-step explanation:

[tex]\dfrac{12}{18}= \\\\\\\dfrac{6\times 2}{6\times 3}= \\\\\\\dfrac{2}{3}[/tex]

Hope this helps!

Answer:

[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

[tex]\frac{12}{18}=\frac{x}{3}[/tex]

[tex]18x=12 \times 3[/tex]

[tex]18x=36[/tex]

[tex]\frac{18x}{18y} =\frac{36}{18}[/tex]

[tex]x=2[/tex]

[tex]=\frac{2}{3}[/tex]

The answer would be -3 13/81 (simplified)

Answer:

Is there any options if so just repost with the options and i will answer it

Step-by-step explanation:

Answer:  A

Step-by-step explanation:

To multiply matrices, multiply each term in Row 1 of the first matrix with each term in Column 1 of the second matrix and then find their sum.  Repeat for Row1×Column2, Row2×Column1, and Row2×Column2.

[tex]\left[\begin{array}{ccc}1&4&-1\\3&2&2\end{array}\right] \times \left[\begin{array}{cc}2&-1\\0&3\\5&2\end{array}\right] \\\\\\=\left[\begin{array}{ccc}1(2)+4(0)-1(5)&1(-1)+4(3)-1(2)\\3(2)+2(0)+2(5)&3(-1)+2(3)+2(2)\end{array}\right] \\\\\\=\left[\begin{array}{cc}-3&9\\16&7\end{array}\right][/tex]

Answer:

Step-by-step explanation:

Hello,

qop(2)=q(p(2))

p(2) = 4+3=7

[tex]q(7) = \sqrt{7+2}=\sqrt{9}=3[/tex]

so

qop(2)=3

and poq(2)=p(q(2))

[tex]q(2)=\sqrt{2+2} = \sqrt{4}=2[/tex]

p(2) = 7

so poq(2)=7

thanks

The answer is "[tex]\bold{(q \circ p)(2)= 3}\ and \ \bold{(p \circ q)(2)=7}[/tex]" and the further explanation can be defined as follows;

Given:

[tex]\to \bold{p(x)=x^2+3}\\\\\to \bold{q(x)=\sqrt{x+2}}[/tex]

Find:

[tex]\bold{(q \circ p)(2)=?}\\\\\bold{(p \circ q)(2)=?}[/tex]

Solve the value for [tex]\bold{(q \circ p)(2)}\\\\[/tex]:

[tex]\to \bold{(q \circ p)(2)= q \circ p(2) =q(p(2))}\\\\[/tex]

[tex]\therefore\\\\ \to \bold{p(2)=2^2+3= 4+3=7}\\\\\ \because \\\\ \to \bold{q(p(2))=\sqrt{7+2}=\sqrt{9}=3}[/tex]

Solve the value for [tex]\bold{(p \circ q)(2)}\\\\[/tex]:

[tex]\to \bold{(p \circ q)(2)= p \circ q(2)= p (q(2))}\\\\[/tex]

[tex]\therefore\\\\ \to \bold{q(2)=\sqrt{2+2}=\sqrt{4}=2}\\\\\ \because \\\\ \to \bold{p(q(2))=2^2+3= 4+3=7}[/tex]

Therefore the final answer of "[tex]\bold{(q \circ p)(2)= 3}\ and \ \bold{(p \circ q)(2)=7}[/tex]"

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Answer:

By the Chebyshev Theorem, at least 75% of commuters in Boston has a commute time within 2 standard deviations of the mean

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

What minimum percentage of commuters in Boston has a commute time within 2 standard deviations of the mean

By the Chebyshev Theorem, at least 75% of commuters in Boston has a commute time within 2 standard deviations of the mean

95% of commuters in Boston has a commute time within 2 standard deviations of the mean

Empirical rule states that for a normal distribution, 68% of the values are within one standard deviation from the mean, 95% of the values are within two standard deviation from the mean and 99.7% of the values are within three standard deviation from the mean.

Hence, 95% of commuters in Boston has a commute time within 2 standard deviations of the mean

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Complete Question:

The Giant Machinery has the current capital structure of 65% equity and 35% debt. Its net income in the current year is $250 000. The company is planning to launch a project that will requires an investment of $175 000 next year. Currently the share of Giant machinery is $25/share. Required: a. How much dividend Giant Machinery can pay its shareholders this year and what is dividend payout ratio of the company. Assume the Residual Dividend Payout Policy applies? b. If the company is paying a dividend of $2.50/share and tomorrow the stock will go ex-dividend. Calculate the ex-dividend price tomorrow morning. Assuming the tax on dividend is 15%? c. Little Equipment for Hire is a subsidiary in the Giant Machinery and currently under the liquidation plan due to the severe contraction of operation due to corona virus. The company plans to pay total dividend of $2.5 million now and $ 7.5 million one year from now as a liquidating dividend. The required rate of return for shareholders is 12%. Calculate the current value of the firm’s equity in total and per share if the firm has 1.5 million shares outstanding?

Answer:

a) Total dividend for the current year = $136,250

Dividend Payout Ratio = 0.545

b) Ex-dividend price = $22.875

c) Total current value = $9,196,428.57

Current value per share = $6.13

Step-by-step explanation:

a) Equity = 65%

Debt = 35%

Net Income for year 0 = $250,000

proposed Investment for year 1= $175,000

Current price = $25/share

Tax on dividend = 15%

Total dividend for year 0 = 250000 - (65% of 175000)

Total dividend for year 0= 250000 - 113750

Total dividend for the current year = $136,250

Dividend Payout Ratio = total dividends/ total earning

Dividend Payout Ratio = 136250/250000

Dividend Payout Ratio = 0.545

b) Dividend = $2.5/ share

Ex-dividend price = current price - Dividend * (1-tax on dividend)

Substituting the appropriate values:

Ex-dividend price = 25 - 2.5 * (1-15%)

Ex-dividend price = 25 - 2.125

Ex-dividend price = $22.875

c) Current value of the firm = Dividend paid in year 0 + (Dividend to be paid in year 1/discount rate)

Dividend paid in year 0 = $2,500,000

Dividend to be paid in year 1 = $7,500,000

Discount rate = 12%

Total current value = 2,500,000 + (7,500,000 / 1.12)

Total current value = $9,196,428.57

Numbe of shares = 1,500,000

Current value per share = Total current value / number of shares

Current value per share = 9,196,428.57/1,500,000

Current value per share = $6.13

Answer:

Step-by-step explanation:

mabey its c

The equation which is equivalent to [tex]2^{\frac{2}{3} }[/tex] will be equal to [tex]\sqrt[4]{2^3}[/tex]. Hence, option C is correct.

The four basic mathematical operations are the addition, subtraction, multiplication, and division of two or even more integers.

Among them is the examination of integers, particularly the order of actions, which is crucial for all other mathematical topics, including algebra, data organization, and geometry.

As per the given information in the question,

[tex]2^{\frac{2}{3} }[/tex] = 1.68

Now, let's check the options,

A.

[tex](2^{\frac{1}{4} } )^{\frac{1}{2} }[/tex] = 1.09 ≠ 1.68, hence this is incorrect.

B.

[tex]2\frac{1}{4}*2\frac{1}{2}[/tex] = 9/4 × 5/2 = 5.625 ≠ 1.68, hence, this is incorrect.

C.

[tex]\sqrt[4]{2^3}[/tex] = 1.68 = 1.68, hence, this is correct.

D.

√8 = 2.82 ≠ 1.68, hence, this is incorrect.

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Answer:

[tex]\sqrt{17}[/tex] or ≈4.12

Step-by-step explanation:

Use the distance formula

d= √(x₂ - x₁) ² + (y₂-y₁) ²

d= √(4-0)² + (1-0)²

d= √16 + 1

d= √17

Answer:

6781632 ft ^ 3

Step-by-step explanation:

The first thing is to know the formula for the volume of a pyramid:

V = 1/3 * Ab * h

That is, it is one third of the product between the area of the base and the height.

The base area would be:

Ab = l ^ 2

the side equals 156 ft, replacing:

Ab = 156 ^ 2

Ab = 24336 ft ^ 2

now, replacing in the volume formula:

V = 1/3 * 24336 * 836

V = 6781632

Which means that the volume of the pyramid is 6781632 ft ^ 3

Answer:

The highest you could reach with this ladder is 30 feet or 9.14 meters.

Answer:

15.2 lbs

Step-by-step explanation:

Make a ratio: 150 : 24 = 95 : x

[tex]\frac{75}{12}=\frac{95}{x}[/tex]

75x = 1140

x = 15.2

Answer:

2 real solutions

Step-by-step explanation:

Answer:

y = x - 2

Step-by-step explanation:

y = x + b

3 = 5 + b

y = x - 2

We can use the slope intercept form of a line.

y = mx+b where m is the slope and b is the y intercept

y = 1x +b

Substitute the point into the equation

3 = 1*5+b

3 = 5+b

Subtract 5 from each side

3-5 = 5+b-5

-2 =b

y = x-2

Answer:

C

Step-by-step explanation:

I explained in my last answer but someone deleted it

Answer:

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]

Step-by-step explanation:

Given that:

A tank contains 180 liters of fluid in which 50 grams dissolved inside.

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

The salt pumped out[tex]= \dfrac{6 L}{180 L} = \dfrac{1}{30}[/tex] of initial amount added salt

At (t = 0) = 50

To determine the number A (t)

[tex]\dfrac{dA}{dt}=Rate_{in} - Rate _{out}[/tex]

[tex]A' = 6 - \dfrac{1}{30}A[/tex]

[tex]A' + \dfrac{1}{30}A = 6[/tex]

Integrating factor  [tex]y = e^{\int\limits pdt[/tex]

[tex]y = e^{\int\limits \dfrac{1}{30}dt}[/tex]

[tex]y = e^{\dfrac{t}{30}}[/tex]

[tex](e^{ \frac{t}{30}}A)' =4 e ^{\dfrac{t}{30}}+c[/tex]

Taking integral on the both sides;

[tex]Ae ^{\dfrac{t}{30}}= 6 * 30 e^{\dfrac{t}{30}} + c[/tex]

[tex]A = 180+ ce^ {-\dfrac{t}{30}}[/tex]

At  A(t = 0) = 50

50 = 180  + C            (assuming C = [tex]ce ^{-\dfrac{t}{30}}[/tex])

C = 50 - 180

C = 130

[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]