A student must determine the relationship between the inertial mass of an object, the net force exerted on the object, and the object’s acceleration. The student uses the following procedure. The object is known to have an inertial mass of 1.0kg .

Step 1: Place the object on a horizontal surface such that frictional forces can be considered to be negligible.

Step 2: Attach a force probe to the object.

Step 3: Hang a motion detector above the object so that the front of the motion detector is pointed toward the object and is perpendicular to the direction that the object can travel along the surface.

Step 4: Use the force probe to pull the object across the horizontal surface with a constant force as the force probe measures force exerted on the object. At the same time, use the motion detector to record the velocity of the object as a function of time.

Step 5: Repeat the experiment so that the object is pulled with a different constant force.

Can the student determine the relationship using this experimental procedure?

Answer choices:

A) Yes, because Newton’s second law of motion must be used to determine the acceleration of the object.

B) Yes, because the net force exerted on the object and its change in velocity per unit of time are measured.

C) No, because the motion detector should be oriented so that the object moves parallel to the line along which the front of the motion detector is aimed.

D) No, because knowing the net force exerted on the object and its change in velocity per unit of time is not sufficient to determine the relationship.

Answer:

No you didn't win the stuffed poodle

Explanation:

From the question we are told that

    The distance of the ramp to the hole is  d =  3 m \

     The angle of inclination is  [tex]\theta  =  10^o[/tex]

       The coefficient of static friction is [tex]\mu_s = 0.1[/tex]

     The coefficient of kinetic  friction is [tex]\mu_k = 0.08[/tex]

      The mass of the puck is  m  =  1 kg

     The velocity of the first slide  is  [tex]v_1  =  2.0 m/s[/tex]

Generally the kinetic energy at the bottom of the ramp  is equal the energy loss due to friction and this can be mathematically represented as

    [tex]\frac{1}{2} m *  v^  2 =  \mu_k * [m *  g] *  cos (theta )  *  d[/tex]

=>     [tex]\frac{1}{2}  *  v^  2 = 0.08 * 9.8 *  cos (10 )  *  3[/tex]

=>     [tex] v=  2.17 \  m/s [/tex]

Comparing the relative velocity obtained and the velocity of your first throw we can see that you didn't win the stuffed animal  

Answer:

can exchange energy with its surroundings through heat and work transfer. In other words, work and heat are the forms that energy can be transferred across the system boundary.

Answer:

Its speed remains the same but its velocity keeps chaging (in direction)

Explanation:

Answer:

The options are

A.on racetracks

B.in real-world conditions

C.in flooded environments

D.on closed courses

The answer is B. In real world conditions

The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin

how the cars perform based on real world conditions.

This will ensure they encounter the real and first hand experiences about the challenges and also the advantages associated with using this type of fuel.

Answer:

I'm in 10th grade

Explanation:

Answer:

The correct solution will be "271.95 N".

Explanation:

The given values are:

velocity  

v = 3.5 m/s

mass

m = 9.0 kg

r = 0.6 m

According to the question:

⇒ [tex]F_{branch}=F_{gravity}+F_{centrifugal}[/tex]

⇒             [tex]=mg+\frac{mv^2}{r}[/tex]

On substituting the values, we get

⇒             [tex]=9\times 9.8+\frac{9\times (3.5)^2}{0.6}[/tex]

⇒             [tex]=88.2+\frac{110.35}{0.6}[/tex]

⇒             [tex]=271.95 \ N[/tex]

Answer:

6000 joules

Explanation:

I jus learned dis

Answer:6000j

Explanation:

Hope that helps

Answer:

The observed wavelength is  [tex] \lambda = 700nm[/tex] (color -  Red)

Explanation:

From the question we are told that

   The wavelength of the emitter is  [tex]\lambda_ e  = 500 nm  =  500 *10^{-9} \  m[/tex]

  The redshift is  R  =  0.4  

     Generally red shift is mathematically represented as

    [tex]R =  \frac{ \lambda -  \lambda_e }{\lambda_e}[/tex]

=>  [tex]0.4  =  \frac{ \lambda -   500 *10^{-9} }{500 *10^{-9} }[/tex]

=>  [tex] \lambda - 500*10^{-9} = 200*10^{-9}  [/tex]

=>   [tex] \lambda = 700 *10^{-9}[/tex]

=>   [tex] \lambda = 700nm[/tex]

Answer:

Experimenter bias

Explanation:

If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of Experimenter bias.

Definitions of Experimenter bias

1) Research bias, also called experimenter bias, is a process where the scientists performing the research influence the results, in order to portray a certain outcome.

2) Observer bias (also called experimenter bias or research bias) is the tendency to see what we expect to see, or what we want to see. When a researcher studies a certain group, they usually come to an experiment with prior knowledge and subjective feelings about the group being studied.

Answer:

51.2Joules

Explanation:

Work done = Force × distance

Force = mg = 64.5×9.81

Force = 632.745N

Next is to get the distance using the equation of motion

v² = u²+2gS

1.26² = 0+2(9.81)S

1.5876 = 19.62S

S = 1.5876/19.62

S = 0.0809m

Get the work done:

Work done = F×S

Work done = 632.745×0.0809

Work done = 51.2Joules

Hence the net work done in Joules is 51.2Joules

The net work done required to stop a crate will be "51.2 Joules".

According to the question,

Mass, m = 64.5 kg

Speed, v = 1.26 m/s

Acceleration due to gravity, g = 9.8

We know,

The force, F = mg

By substituting the values,

                    = 64.5 × 9.8

                    = 632.745 N

By using Equation of motion,

→       v² = u² + 2gS

 (1.26)² = 0 + 2(9.81) S

1.5876 = 19.62 S

         S = [tex]\frac{1.5876}{19.62}[/tex]

            = 0.0809 m  

hence,

The work done (W) will be:

= F × S

= 632.745 × 0.0809

= 51.2 Joules

Thus the above response above is correct.

Find out more information about mass here:

https://brainly.com/question/25545050

Answer:

Injury to a vein increases the risk of forming a blood clot.

Explanation:

hoped this helped

Answer:

gjmoon = 19.6 m/s2

Explanation:

       [tex]F_{gE} = m* \frac{G*M_{E} }{R_{E} ^{2} } = m*g_{E}[/tex]

      [tex]F_{gjmoon} = m* \frac{G*M_{Jmoon} }{R_{Jmoon} ^{2} } = m*g_{jmoon} (1)[/tex]

       [tex]M_{Jmoon} = \frac{M_{E} }{2} (2)[/tex]  

      [tex]R_{Jmoon} = \frac{R_{E} }{2} (3)[/tex]

       [tex]F_{gjmoon} = m* \frac{G*M_{E} }{2*\frac{R_{E} ^{2}}{4} } = m*g_{jmoon} (1) = m* 2* \frac{G*M_{E} }{R_{E} ^{2}} = 2* m*g_{E}[/tex]

      ⇒  [tex]g_{jmoon} = 2* g_{E}[/tex]

       gjmoon = 19.6 m/s2 (in magnitude).

Answer:

also choose D and E i belive those are also correct

Answer:

v = 0.349 m/s

Explanation:

If you borrow your mom's car to drive 128 m to the store, but you go cruising  instead and drive a total distance of 1256 m in 3600s.

We need to find your speed during the  trip. It is equal to the total distance divided by time taken.

He has done cruising  instead and drive a total distance of 1256 m.

So,

[tex]v=\dfrac{d}{t}\\\\v=\dfrac{1256\ m}{3600\ s}\\\\v=0.349\ m/s[/tex]

So, the speed of the person during the trip is 0.349 m/s.

Answer:

Explanation:

What are simple machines?

Simple machines reduce effort or extend the ability to perform tasks beyond their abilities.

Why do we use simple machines?

Simple machines are used widely as they help humans and save time.

Simple Machine Examples:

Answer:

C

gravity and inertia

Explanation:

Answer:

c :)

Explanation:

Answer:

Acidity

Explanation:

A pH indicator measures how acidic or basic a substance is.

Hope this helped :)

Answer:

Equilibrium.

Explanation:

Streams compensate for changes in their systems by adjusting other factors in order to return to equilibrium because so as to maintain their watershed. When the surface runoff move downslope, it also cause a concentration in small areas and create small channels of streams. These channels normally allow the flow of water during rainfall.

Answer:

stop being an annoying child and appreciate everything your mother does for you because she cares for you

Explanation:

its the right thing to do

Be thankful for everything your mom does bc one day she wont be here any more! Love her while you can

Answer:

94.4

Explanation:

it is

Answer:

94.4 i took the test and got it right :)

hope that helps

Answer:

[tex]10.845\ \text{J}[/tex]

Explanation:

m = Mass of box = 0.6 kg

[tex]\theta[/tex] = Angle of incline = [tex]37^{\circ}[/tex]

[tex]\mu_k[/tex] = Coefficient of kinetic friction = 0.4

l = Distance the box travels = 2 m

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The potential energy in the spring is given by

[tex]U=mgl\sin\theta+mg\mu_k\cos\theta l\\\Rightarrow U=mgl(\sin\theta+\mu_k\cos\theta)\\\Rightarrow U=0.6\times 9.81\times 2\times(\sin37^{\circ}+0.4\times\cos37^{\circ})\\\Rightarrow U=10.845\ \text{J}[/tex]

The minimum elastic potential energy required is [tex]10.845\ \text{J}[/tex].

Answer:

A. g

Explanation:

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

m₁ = 70 lb

Answer:

The value  is  [tex]B =  0.0452 \  T [/tex]

Explanation:

From the question we are told that

   The number of turns is  N  =  1000

    The length is  L =  50 cm =  0.50 m  

    The radius is  r =  2.0 cm  =  0.02 m

     The current is I  =  18.0 A

Generally the magnetic field is mathematically represented as

         [tex]B = \mu_o  * \frac{N }{L}  *  I[/tex]

Here [tex]\mu_o[/tex] is the permeability of free space with value  

     [tex]\mu_o  =  4\pi * 10^{-7} N/A^2[/tex]

So

     [tex]B =  4\pi * 10^{-7}  *   \frac{1000}{0.50} *  18.0[/tex]

=>   [tex]B =  0.0452 \  T [/tex]

Answer:

option (i) is correct

Explanation:

as there is no air resistance, no force is acting on the object horizontally, but gravitational acceleration will obviously act, regardless of the air resistance... option (i) is correct

Answer:

1.152 miles

Explanation:

Given: central angle = 1 minute = [tex](\frac{1}{60}) ^{o}[/tex]

           radius of the earth = 3960 miles

The length of an arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r

where: [tex]\alpha[/tex] is the central angle, and r is the radius.

Thus,

Distance along the arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r

Distance along the arc = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 2 x [tex]\frac{22}{7}[/tex] x 3960

                                      = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 24891.4286

                                      = 1.1524

The required distance along an arc is 1.152 miles.