A student dissolves 10.2 g of sodium hydroxide (NaOH) in 250. g of water in a well-insulated open cup. He then observes the temperature of the water rise from 21.0 °C to 32.7 °C over the course of 3.7 minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: NAOH(s) → Na" (aq) + OH (aq) You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to 3 significant digits. do Note for advanced students: Its possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction. O exothermic Is this reaction exothermic, endothermic, or neither? O endothermic O neither If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in this case. kJ Calculate the reaction enthalpy AH per mole of NaOH. mol

Answer:

Simple sugars are a type of carbohydrate.

Explanation:

Carbohydrates are one of the three basic macronutrients — the other two being protein and fat. Simple sugars are found naturally in fruits and milk, or they can be produced commercially and added to foods to sweeten, prevent spoilage, or improve structure and texture.

Answer:

a: Nn or XN

b: Nn or Xn

c: 75%

d: 50%

Explanation:

Answer:

51.03g/mol is the molar mass of X

Explanation:

Based on the reaction:

2XI₃ + 3Cl₂X → 2XCl₃ + 3I₂

Where 2 moles of XI₃ reacts to produce 2 moles of XCl₃ -The ratio of reaction is 1:1-

To solve this question we must find the mass of X per mole (This is the atomic mass of X).

As the moles of both compounds are the same:

1.196g / 0.436g = Molar mass XI₃ / molar mass XCl₃ (1)

Also:

Molar mass XI₃ = Molar mass X + 380.71g/mol

Molar mass XCl₃ = Molar mass X + 106.36g/mol

Replacing in (1):

2.7431 = (Molar mass X + 380.71g/mol) / (Molar mass X + 106.36g/mol)

2.7431 Molar mass X + 291.76g/mol = Molar mass X + 380.71g/mol

1.7431 Molar mass X = 88.95g/mol

Molar mass X = 51.03g/mol

Answer:

C)The same bond in a different molecule has a different energy. For example, O-H in water versus ethanol has different energies.

Explanation:

This is true going by the the statement about the bond energies and the bonding being different among the various elements. In the example given which is between ethanol and water, the bonds which exist among the elements is stronger in water than in ethanol. That is why, ethanol is easily combustible than water.

Answer:

The same bond in a different molecule has a different energy. For example, O-H in water versus ethanol has different energies.

Explanation:

Answer:

55.025g of N2O

Explanation:

2 NH3 + 2 O2 → N2O + 3 H2O

moles of O2 = 80.0/32 = 2.5 moles O2

moles of N2O = 2.5 moles O2 * 1 mole N2O

= 1.25 moles N2O

moles = mass/Molar mass

mass = moles * Molar mass = 1.25 x 44.02 = 55.025 g

Answer:the answer is a c and e

Explanation:

Answer:

The composition of the objects because not all the planets have been explored

Answer:

Decomposition.

Explanation:

Decomposition Reactions T hose reactions in which a single substance (reactant) splits up into two or more simpler substances (products) are known as decomposition reactions. These reactions are carried out by supplying energy in form of heat, electricity or light which breaks that substance into simpler substances

Answer:

1. x=-2

2. x=65/27

3. x=37/3

Explanation:

Isolate x

1. Divide by 5: 2x+15=11

2x=11-15

x=-2

2. Distribute: 54x+36=166

54x=166-36

x=130/54

Simplify by dividing by 2: x=65/27

3. Distribute: 24x+60=356

24x=356-60

x=296/24

Simplify by dividing by 8: x=37/3

Answer:

Molecular formula: S4K8O16  empirical formula: SK2O4

Explanation:

First we find the moles of each by first finding grams (using the percent) and then using stoichiometry to convert into moles:

Sulfur: 696 *.18 = 125.28grams S* [tex]\frac{1 mole S}{32.065 g S} = 3.907 moles S[/tex]

Potassium: 696 *.4487 = 312.2952 *[tex]\frac{1 mole K}{39.08 g K}[/tex]= 7.99117 mole K

Oxygen: 696 * .367 = 255.432 * [tex]\frac{1 mol O}{16g O}[/tex] = 15.9654 mole O

Then we divide each value by the atom with the smallest number of moles to find the mole ratio:

3.907/3.907= 1

7.99117 mole K/ 3.907= 2.043

15.9654 mole O/ 3.907= 4.08

The empirical formula is SK2O4

To find the molecular formula, we divide the mass given (696) by the mass of the empirical formula (174.22) to get 4. We then divide each atom by 4.

Molecular formula: S4K8O16

Answer:

0.093 M

Explanation:

First, we assume that the density of household hydrogen peroxide is 1 g/mL. We also assume that there's no reaction between hydrogen peroxide and sodium carbonate, if there were, in the end all hydrogen peroxide would be consumed.

Now we calculate how many grams of H₂O₂ were added, using the given volume, concentration and density:

We convert grams to moles:

0.45 g H₂O₂ ÷ 34 g/mol = 0.013 mol H₂O₂

Now we divide the number of moles by the final volume, to calculate the molarity of H₂O₂:

Based on the given concentration of the original hydrogen peroxide solution, the molarity of the hydrogen peroxide (in mol/L) of the final solution is 0.093 M.

Assuming that the density of household hydrogen peroxide is 1 g/mL and that no reaction occurs between hydrogen peroxide and sodium carbonate.

The mass in grams of H₂O₂ added is first determined using the given volume, concentration and density:

mass = 15 mL *  1 g/mL * 3g/100g  = 0.45 g H₂O₂

Moles of H₂O₂ is determined as follows:

molar mass of H₂O₂ = 34 g/mol

moles of H₂O₂ = 0.45 g H₂O₂ / 34 g/mol

moles of H₂O₂ = 0.013 mol H₂O₂

molarity of H₂O₂ is then calculated as follows:

final volume = 15 mL + 120 mL + 5 mL = 140 mL

final volume = 140 mL / 1000 = 0.140 L

molarity = 0.013 mol H₂O₂ / 0.140 L

molarity of H₂O₂ = 0.093 M

Therefore, the molarity of the hydrogen peroxide (in mol/L) of the final solution is 0.093 M.

Learn more about molarity at: https://brainly.com/question/17138838

Answer:

V2= 1.03L

Explanation:

Start off with what you are given.

V^1: 1.00L

T^1: 23°C

V^2?

T^2: 33°C

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V^1/T^1 = V^2/T^2

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

(23+273 = 296)     (33+273 = 306)

Multiply crisscross

1.00/296= V^2/306

296V^2 = 306

Dividing both sides by 296 to isolate V2, we get

306/296 = 1.0337837837837837837837837837838

V2= 1.03L

Answer:

487638640,7819

dndndnndndbxbdbdbdbdb

Answer:

Explanation:

From the information given:

The Chemical equation is:

[tex]SO_2Cl_{2(g)} \iff SO_{2(g)} + Cl_{2(g)}\\[/tex]

since 43.6% of the initial concentration remains at equilibrium

Then; the amount of [tex]SO_2Cl_2[/tex] that is being reacted is:

= 0.543 × (100 -43.6)%

= 0.306 M

The ICE table can be computed as follows:

           [tex]SO_2Cl_2[/tex]               ⇔           [tex]SO_{2(g)[/tex]           +             [tex]Cl_{2(g)[/tex]

I            0.543                                    0                           0

C          0.306                                 +0.306                     0.306

E           0.237                                  0.306                      0.306

[tex]K_c = \dfrac{[SO_2] [Cl_{2}]}{[SO_2Cl_2]}[/tex]

[tex]K_c = \dfrac{0.306 \times 0.306}{0.237}[/tex]

[tex]K_c = 0.995[/tex]

Thus; the concentration at equilibrium for the species are:

[tex]SO_2Cl_2[/tex]  = 0.237 M

[tex]SO_{(2g)[/tex] = 0.306 M

[tex]Cl_{2(g)[/tex] = 0.306 M

Answer:

C,A,B,D

Explanation:

That's the correct order, hope this helps

Answer:

I would be if I do it your no learning anything but I would but I don't have insta yet

Explanation:

sorry

Answer:

k

Explanation:

Answer:

The solution is 10^-2 or 0.01M in HCl.

Explanation:

meaning of pH is "power of hydrogen".

what is the molar concentration of a HCl solution with pH=2?

Let say pH=2

[H+]=10^-2M

HCL is a strong acid that dissociates completely:

[H+]=[HCL]

Therefore solution is 10^-2 or 0.01M in HCL.

Answer:

B

Explanation:

you can tell by looking at the image lol the wires have to be connected

(brainliest please? c:)

( although its fine if not im just glad to have helped )

Answer:

The answer is B

Explanation:

Answer:

3.955*10^48

Explanation:

1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48

Answer:

Bohr's model of the hydrogen atom is based on three postulates:

1) An electron moves around the nucleus in a circular orbit,

2) An electron's angular momentum in the orbit is quantised,

3) The change in an electron's energy as it makes a quantum jump from one orbit to another is always accompanied by the emission or absorption of a photon. Bohr's model is semi-classical because it combines the classical concept of electron orbit (postulate 1) with the new concept of quantisation ( postulates 2 and ).

Carbon-14 is a radioisotope of carbon that decays following first-order kinetics. There are four values of interest in this problem: the "normal" (or original) amount of carbon-14 for a jawbone ([tex]\mathrm{N_0}[/tex]), the actual amount of carbon-14 in a jawbone ([tex]\mathrm{N}[/tex]), the half-life of carbon-14 ([tex]\mathrm{t_{1/2}}[/tex]), and the actual time elapsed ([tex]\mathrm{t}[/tex]) from the original time. There is an equation that ties all these values in together,

[tex]N= N_0 e^{-kt}[/tex]

where k is the rate constant, which, for first-order decay, is related to the half-life by

[tex]k = \dfrac{\ln 2}{ t_{1/2} }.[/tex]

What you want to find here is the time elapsed (t). So, you can substitute the latter equation for k into the k in the former equation to get

[tex]N= N_0 e^{\frac{-\ln 2 \;t}{t_{1/2}}.[/tex]

Rearranging to solve for t, the equation becomes

[tex]t = \left(\dfrac{\ln \dfrac{N_0}{N}}{\ln 2} \right) t_{1/2}.[/tex]

You are given all three of the values necessary to solve for t: The normal amount of carbon-14 is 200 mg; the actual amount of carbon-14 in the sample is 50 mg; and the half-life of carbon-14 is 5730 years. Plugging them into the above equation, we get

[tex]t = \left(\dfrac{\ln \dfrac{200 \text{ mg}}{50 \text{ mg}}}{\ln 2} \right) \left(5730 \text{ years} \right) = 11460 \text{ years}.[/tex]

So the jawbone found is 11460 years old (or 11000 if accounting for sig figs).

Answer:

all letter cannot be created or destroyed just transformed

Answer:

There are 6 atoms of oxygen in 2Ca(NO3)2

Answer:

48.27g Na

Explanation:

To start we need to balance the equation. The trick is to make sure both sides have equal amounts of each atom:

2Na + Cl2 --> 2NaCl

Now we can use sociometry

We have 75 g of Cl2, and for every 1 mole of Cl2, there are 70.9 grams:

[tex]75g Cl2 * \frac{1mole Cl2}{70.9g Cl2}= 1.05 mole Cl2[/tex]

Now we have moles of Cl2. To get to grams of Na, we need to first use mole to mole ratio:

[tex]1.05mole Cl2 *\frac{2 mole Na}{1 mole Cl2} =2.1 mole Na[/tex]

 From here we convert moles of Na into grams of Na

[tex]2.1mol Na*\frac{22.99g Na}{1 mole Na} = 48.27g Na[/tex]

It's usually easier to just make one singular equation with all of these smaller equations.

[tex]75gNa*\frac{1molCl2}{70.9gCl2} *\frac{2mol Na}{1 mol Cl2} *\frac{22.99g Na}{1 mol Na}=48.27 gNa[/tex]

The trick to sociometry is making sure your units cancel out until you only have the unit you want. If there are moles of Na in the numerator, there needs to be moles of Na in the denominator. If there are grams of Cl2 in the numerator, there needs to be grams of Cl2 in the denominator and so one and so on

Answer:

44 g NaCI

Explanation:

The problem provides you with the molarity and volume of the target solution, so your first step here will be to use this information to figure out how many moles of sodium chloride.

Answer: [tex]3Mg(s)+2SnCl_3(aq)\rightarrow 3MgCl_2(aq)+2Sn(s)[/tex]

Explanation:

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

A more reactive element is one which can easily lose or gain electrons as compared to the other element.

As Magnesium is more reactive than tin, it can easily displace tin from its salt solution [tex](SnCl_3)[/tex] and form magnesium chloride and tin in elemental form.

The balanced chemical equation is:

[tex]3Mg(s)+2SnCl_3(aq)\rightarrow 3MgCl_2(aq)+2Sn(s)[/tex]

Answer: a. 3.36 L

b. 33.2 g

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

[tex]\text{Number of moles of} Fe_2O_3=\frac{16.0g}{159.69g/mol}=0.1mole[/tex]

[tex]3O_2(g)+4Fe(s)\rightarrow 2Fe_2O_3(s)[/tex]

a. 2 moles of [tex]Fe_2O_3[/tex] are produced by = [tex]3\times 22.4L=67.2L[/tex] of [tex]O_2[/tex]

Thus 0.1 moles of  [tex]Fe_2O_3[tex] are produced by =[tex]\frac{67.2}{2}\times 0.1=3.36L[/tex] of [tex]O_2[/tex]

b. [tex]3\times 22.4L=67.2L[/tex] of [tex]O_2[/tex] react with = [tex]4\times 55.8=223.2g[/tex] of iron

Thus 10.0 L of [tex]O_2[/tex] react with = [tex]\frac{223.2}{67.2}\times 10=33.2g[/tex] of iron