the concentration of sulfate ion when the precipitation of barium sulfate begins is 1.07×10^-8 M.
To determine the formula of the substance that precipitates first, we need to determine which combination of ions will form an insoluble compound first. We can do this by considering the solubility rules for common ionic compounds.
Calcium acetate dissociates into Ca2+ and CH3COO- ions in solution, while barium nitrate dissociates into Ba2+ and NO3- ions. Ammonium sulfate, when added to the solution, will dissociate into NH4+ and SO42- ions.
The possible combinations of ions that can form insoluble compounds are:
- Ca2+ and SO42- form CaSO4, which is insoluble
- Ba2+ and SO42- form BaSO4, which is insoluble
According to the solubility rules, calcium sulfate (CaSO4) is slightly soluble in water, while barium sulfate (BaSO4) is insoluble. Therefore, the substance that precipitates first is barium sulfate (BaSO4).
To determine the concentration of sulfate ion when the precipitation first begins, we need to calculate the product of the concentrations of barium ion and sulfate ion, and compare it to the solubility product constant (Ksp) for barium sulfate.
The balanced chemical equation for the precipitation reaction is:
Ba(NO3)2 + (NH4)2SO4 → BaSO4↓ + 2NH4NO3
The Ksp expression for barium sulfate is:
Ksp = [Ba2+][SO42-]
At the point when precipitation begins, the barium and sulfate ion concentrations will be equal to each other, so we can use the concentration of barium ion to calculate the concentration of sulfate ion:
[Ba2+] = 1.03×10^-2 M
Ksp for barium sulfate is 1.1×10^-10 at 25°C.
Therefore, we can calculate the concentration of sulfate ion:
Ksp = [Ba2+][SO42-]
1.1×10^-10 = (1.03×10^-2 M)([SO42-])
[SO42-] = 1.07×10^-8 M
Therefore, the concentration of sulfate ion when the precipitation of barium sulfate begins is 1.07×10^-8 M.
Visit to know more about precipitation:-
https://brainly.com/question/14330965
#SPJ11
When solutions of two ionic compounds are combined and a solid forms, the process is called:.
The process described in the question is known as a precipitation reaction.
In a precipitation reaction, two aqueous solutions of ionic compounds are mixed together to form a solid compound called a precipitate. This occurs because the ions in the two solutions react with each other to form an insoluble product, which separates from the solution as a solid.
Precipitation reactions are commonly used in analytical chemistry to determine the presence or absence of certain ions in a solution. The reaction is usually identified by observing a change in the appearance of the solution, such as the formation of a cloudy or milky precipitate.
The chemical equation for a precipitation reaction can be written as:
[tex]AB(aq) + CD(aq) → AD(s) + CB(aq)[/tex]
where A, B, C, and D are ions, and (aq) and (s) denote aqueous and solid states, respectively.
Overall, precipitation reactions play an important role in chemical analysis and in the formation of minerals and other solids in natural processes.
To know more about precipitation reaction refer to-
https://brainly.com/question/29762381
#SPJ11
If a piece of metal at 150 *C is placed in a beaker with 50 ml water at 60*C.
a. What is likely to happen to the temperature of the water in the beaker?.
b. What is likely to happen to change with the metal?.
a) The temperature of the water in the beaker is likely to increase as heat flows from the metal to the water until they reach thermal equilibrium.
b) The metal will likely lose heat to the water until it reaches thermal equilibrium with the water.
a) The temperature of the water in the beaker is likely to increase due to the transfer of heat from the metal to the water. This process is known as conduction, and it occurs because heat always flows from hotter objects to cooler objects. The metal, being at a higher temperature than the water, will transfer heat to the water until both reach a state of thermal equilibrium.
b) The amount of heat lost by the metal will depend on its mass, specific heat capacity, and initial temperature. The metal may also undergo physical changes due to the change in temperature, such as contraction or expansion. The type of metal and its properties will influence how much it changes in response to the temperature change.
To learn more about temperature follow the link:
https://brainly.com/question/31273735
#SPJ4
How many grams of chlorine would exert a pressure of 610 torr in a 3. 26-liter container at standard temperature? 4. 25gCL
3.86 grams of chlorine would exert a pressure of 610 torr in a 3.26-liter container at standard temperature.
To calculate the number of grams of chlorine required to exert a pressure of 610 torr in a 3.26-liter container at standard temperature, we need to use the ideal gas law equation: PV = nRT.
Where,
P = pressure = 610 torr
V = volume = 3.26 L
n = number of moles
R = gas constant = 0.0821 Latm/(molK) (standard value)
T = temperature = 273 K (standard temperature)
n = PV ÷ RT
Substituting the given values, we get:
n = (610 torr × 3.26 L) ÷ (0.0821 Latm/(molK) × 273 K)
n = 0.109 mol
Now, to convert moles to grams, we need to use the molar mass of chlorine, which is 35.45 g/mol.
Thus, number of grams of chlorine required is:
0.109 mol × 35.45 g/mol = 3.86 g
To learn more about chlorine follow the link:
https://brainly.com/question/7585012
#SPJ4
What volume of a 4.5 m hcl solution do you need to dilute and prepare a 65 l of a 0.050 m solution of hcl? (2 s.f)
0.72 L (or 720 mL) of the 4.5 M HCl solution is required to prepare a 65 L solution of 0.050 M HCl.
We need to dilute a concentrated 4.5 M HCl solution. We can use the dilution equation to calculate the volume of the concentrated solution required:
[tex]M_1V_1 = M_2V_2[/tex]
where M1 is the concentration of the concentrated solution, V1 is the volume of the concentrated solution required, M2 is the concentration of the diluted solution, and V2 is the final volume of the diluted solution.
In this case, we want to prepare a 65 L solution of 0.050 M HCl from a 4.5 M HCl solution. Therefore:
[tex]M_1[/tex] = 4.5 M
[tex]V_2[/tex] = 65 L
[tex]M_2[/tex] = 0.050 M
Solving for V1:
[tex]V_1 = (M_2 * V_2) / M_1 \\V_1 = (0.050 M * 65 L) / 4.5 M \\V_1 = 0.72 L[/tex]
To know more about HCl solution, here
brainly.com/question/31019516
#SPJ4
You want to completely boil 500g of water that is at 15°C. How much energy is needed to accomplish this?
The amount of energy required to boil water depends on the initial temperature of the water, the mass of the water, and the heat of vaporization of water.
The heat of vaporization of water is 40.7 kJ/mol or 2.26 kJ/g.
To completely boil 500g of water that is at 15°C, we need to first heat the water to its boiling point (100°C), and then provide the energy required for the phase change from liquid to gas.
The amount of energy required to heat the water from 15°C to 100°C can be calculated using the specific heat capacity of water, which is 4.184 J/g°C:
Q1 = m * c * ΔT
Q1 = 500g * 4.184 J/g°C * (100°C - 15°C)
Q1 = 191,020 J
The amount of energy required for the phase change from liquid to gas can be calculated as follows:
Q2 = m * Hv
Q2 = 500g * 2.26 kJ/g
Q2 = 1,130 kJ
Therefore, the total amount of energy required to completely boil 500g of water that is at 15°C is:
Qtotal = Q1 + Q2
Qtotal = 191,020 J + 1,130 kJ
Qtotal = 1,321,020 J
So, it would require 1,321,020 joules of energy to completely boil 500g of water that is at 15°C.
To know more about energy refer here
https://brainly.com/question/1932868#
#SPJ11
How do i calculate the percent yield based on the theoretical yield and the actual yield
When conducting chemical reactions, it is important to determine how efficient the reaction was. The percent yield is a measure of the efficiency of a chemical reaction.
It is calculated by comparing the actual yield obtained from the experiment to the theoretical yield that would be obtained if the reaction went to completion. The percent yield is expressed as a percentage.
To calculate the percent yield, the first step is to determine the theoretical yield of the reaction. The theoretical yield is the maximum amount of product that can be obtained from the reactants. This can be calculated using stoichiometry and the balanced chemical equation for the reaction.
Once the theoretical yield has been calculated, the next step is to determine the actual yield obtained from the experiment. This is the amount of product that is actually obtained from the reaction. The actual yield can be measured experimentally or estimated using calculations.
Finally, the percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100. This calculation shows the percentage of the theoretical yield that was obtained in the experiment.
For example, if the theoretical yield is 10 grams and the actual yield obtained is 8 grams, the percent yield would be calculated as:
Percent yield = (8/10) x 100 = 80%
In this case, the experiment yielded 80% of the maximum amount of product that could have been obtained if the reaction went to completion.
Overall, the percent yield is an important measure of the efficiency of a chemical reaction. By comparing the actual yield to the theoretical yield, chemists can determine the effectiveness of their experimental techniques and make improvements for future experiments.
To know more about chemical reaction, visit:
https://brainly.com/question/29039149#
#SPJ11
During a synthesis reaction, 3. 2 grams of magnesium reacted with 12. 0 grams of oxygen. What is the maximum amount of magnesium oxide that can be produce during the reaction
The maximum amount of magnesium oxide that can be produced during the synthesis reaction between 3.2 grams of magnesium and 12.0 grams of oxygen is 14.4 grams.
This is because the amount of product produced in a synthesis reaction is limited by the amount of the reactant with the lowest mass. In this case, the reactant with the lowest mass is the 3.2 grams of magnesium, so the maximum amount of magnesium oxide that can be produced is 3.2 grams of magnesium multiplied by the mole ratio of magnesium oxide to magnesium, which is 1:1, resulting in 3.2 grams of magnesium oxide.
Therefore, the maximum amount of magnesium oxide that can be produced during the reaction is 14.4 grams (3.2 grams of magnesium multiplied by 4.5 grams of oxygen, which is the mole ratio for magnesium oxide to oxygen).
This is due to the Law of Conservation of Mass, which states that mass is neither created nor destroyed during a chemical reaction, only rearranged.
Know more about Synthesis reaction here
https://brainly.com/question/16987748#
#SPJ11
Which statements correctly describe the strength of an acid or base? Select all that apply.
The greater the hydroxide ion concentration, the stronger the base.
The greater the hydronium ion concentration, the stronger the base.
The greater the hydroxide ion concentration, the stronger the acid.
The greater the hydronium ion concentration, the stronger the acid.
The statements that correctly describe the strength of an acid or base are:
The greater the hydroxide ion concentration, the stronger the base.The greater the hydronium ion concentration, the stronger the acid.What is an acid?An acid is a chemical that donates hydrogen ions, whose addition to an existing solution results in increased acidity.
According to the conventional definition of acids, they are compounds which discharge positively charged hydrogen ions when mixed with water. Acids have a sour flavor and possess pH levels below 7.
Learn more about base at
https://brainly.com/question/9624014
#SPJ1
How much heat is evolved when 27.5 g of ammonia gas condenses to a liquid at its boiling point?
ahcond = -23.3 kj/mol
The heat evolved when 27.5 g of ammonia gas condenses to a liquid at its boiling point is -37.8 kJ.
First, we need to calculate the amount of heat required for the ammonia gas to condense. The heat of vaporization of ammonia is 23.4 kJ/mol. The molar mass of ammonia is 17.03 g/mol, so we have:
23.4 kJ/mol x (27.5 g / 17.03 g/mol) = 37.8 kJ
This means that 37.8 kJ of heat is required for 27.5 g of ammonia gas to condense. However, since the question asks for the heat evolved, we need to reverse the sign of the answer.
Thus, the amount of heat released as 27.5 grams of gaseous ammonia undergoes condensation at its boiling point is equal to -37.8 kJ.
To know more about boiling point, refer here:
https://brainly.com/question/32031404#
#SPJ11
the molar solubility of lead phosphate in a 0.202 m sodium phosphate solution is_______m.
the molar solubility of lead phosphate in a 0.202 M sodium phosphate solution is approximately 1.27 × 10^-7 M.
To calculate the molar solubility of lead phosphate in a sodium phosphate solution, we need to use the solubility product constant (Ksp) of lead phosphate and the common ion effect of sodium phosphate.
The balanced equation for the dissolution of lead phosphate (Pb3(PO4)2) is:
Pb3(PO4)2(s) ⇌ 3Pb2+(aq) + 2PO42-(aq)
The Ksp expression for lead phosphate is:
Ksp = [Pb2+]^3[PO42-]^2
The balanced equation for the dissociation of sodium phosphate (Na3PO4) is:
Na3PO4(s) ⇌ 3Na+(aq) + PO42-(aq)
In a 0.202 M sodium phosphate solution, the concentration of the PO42- ion is [PO42-] = 3 × 0.202 M = 0.606 M, due to the dissociation of sodium phosphate.
To calculate the molar solubility of lead phosphate, we can assume that x mol/L of Pb3(PO4)2 dissolves and forms 3x mol/L of Pb2+ and 2x mol/L of PO42-. Using the Ksp expression and the common ion effect, we can write:
Ksp = [Pb2+]^3[PO42-]^2
Ksp = (3x)^3(2x)^2 = 108x^5
Since the concentration of PO42- is 0.606 M, the concentration of Pb2+ is also 3x = 3(0.202 M - x). Substituting this into the Ksp expression gives:
Ksp = (3x)^3(2x)^2 = 108x^5
4.8 × 10^-27 = (3(0.202 - x))^3(2x)^2
Solving for x, we get:
x = 1.27 × 10^-7 M
Therefore, the molar solubility of lead phosphate in a 0.202 M sodium phosphate solution is approximately 1.27 × 10^-7 M.
Visit to know more about molar solubility:-
https://brainly.com/question/28202068
#SPJ11
How many grams of CaCO3 are produced when 98. 2 grams of CaO are reacted with an excess of Co2 according to the equation provided? CaO+CO2-->CaCO3
175.16 grams of[tex]CaCO3[/tex]will be produced when 98.2 grams of [tex]CaO[/tex] are reacted with an excess of [tex]CO2[/tex].
The balanced chemical equation for the reaction between[tex]CaO and CO2[/tex]is:
[tex]CaO + CO2 → CaCO3[/tex]
According to the equation, one mole of[tex]CaO[/tex] reacts with one mole of [tex]CO2[/tex]to produce one mole of [tex]CaCO3[/tex].
The molar mass of [tex]CaO[/tex]is 56.08 g/mol, and the molar mass of [tex]CO2[/tex] is 44.01 g/mol. Therefore, the number of moles of [tex]CaO[/tex] present in 98.2 g can be calculated as:
moles of [tex]CaO[/tex] = mass / molar mass = 98.2 g / 56.08 g/mol = 1.75 mol
Since the reaction is with an excess of [tex]CO2[/tex], all the [tex]CaO[/tex]will react. Therefore, the number of moles of CaCO3 produced will be the same as the number of moles of [tex]CaO[/tex] used, which is 1.75 mol.
The molar mass of [tex]CaCO3[/tex]is 100.09 g/mol. Therefore, the mass of [tex]CaCO3[/tex] produced can be calculated as:
mass of [tex]CaCO3[/tex] = moles of [tex]CaCO3[/tex] × molar mass = 1.75 mol × 100.09 g/mol = 175.16 g
To know more about balanced chemical equation refer to-
https://brainly.com/question/28294176
#SPJ11
Help what’s the answer?
The number of moles in 1.16 × 10³g of Fe₂O₃ is 7.26 moles.
How to calculate number of moles?The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
no of moles = mass ÷ molar mass
According to this question, 1.16 × 10³ grams of iron (II) oxide is given. The molar mass of this compound is 159.69 g/mol.
no of moles in Fe₂O₃ = 1160g ÷ 159.69g/mol = 7.26 moles.
Learn more about no. of moles at: https://brainly.com/question/26416088
#SPJ1
A chemical reaction produced 125mL of CO2. What was the mass of the gas produced?
Answer:
0.25g
Explanation:
Dimensional analysis.
Assuming the reaction is taking place at standard temperature and pressure (STP, 1 atm at 298.15K or 25 C), 1 mol of gas occupies 22.4L.
We are given the volume of the gas, with this we are able to find its number of moles.
125mL = 0.125L
[tex]0.125 L * \frac{1 mol}{22.4 L}[/tex]
= 0.0056mol
With the number of moles we can simply multiply by the molecules molar mass.
CO2 = 12.011 g/mol+ 2*15.999 g/mol
CO2 = 44.009g / mol
[tex]44.009 \frac{g CO2}{mol} * 0.0056mol CO2\\\\=0.25 g CO2[/tex]
Which sentence best paraphrases this information about river otters?
Otters are really good slide builders.
Crayfish and small amphibians are eaten by otters.
Outstanding among these characteristics is the otter's habit of building slides.
Otters are talented at constructing slides. These help them move through their environment with ease as they hunt for small sea life to eat.
D) The sentence that best paraphrases the information about river otters is: "Otters are talented at constructing slides. These help them move through their environment with ease as they hunt for small sea life to eat."
River otters aresemi-aquatic mammals that are generally set up in gutters, aqueducts, and other aqueducts. One of the most outstanding characteristics of these creatures is their habit of erecting slides. Otters make slides by creating a path of slush or snow on a steep pitch leading to the water.
This helps them to move through their terrain with ease and quest for small ocean life, similar as crayfish and small amphibians, which are their primary sources of food. Otters are known for their sportful nature and can frequently be seen sliding down their constructed slides constantly, putatively just for the fun of it. still, these slides serve a practical purpose as well. By erecting their own slides, otters can avoid rocky or else dangerous areas of the swash bank and safely pierce the water.
Learn more about river otters at
https://brainly.com/question/29218263
#SPJ1
1) write the formula of the conjugate acid:
HCO2-
2) write the formula of the conjugate base:
C6H5NH2
3) write the formula of the conjugate acid of the brønsted-lowry base:
HCO3-
4) write the formula of the conjugate acid of the brønsted-lowry base:
C6H5NH2
5) write the acidic equilibrium equation for HC2H3O2
6) write the basic equilibrium equation for C6H5NH2
7) write the basic equilibrium equation for NH3
In the field of chemistry, the term "conjugate" is used to describe pairs of molecules or ions that are connected through the transfer of a proton, which is represented as H⁺. Conjugate acids and bases, specifically, are pairs of molecules or ions that vary by the presence or absence of one proton.
These equilibrium equations represent the transfer of a proton between a weak acid or base and water, resulting in the formation of its conjugate acid or base.
Answer of the given questions are as follows :
1. The formula of the conjugate acid: HCO₂H
2. The formula of the conjugate base: C₆HNH₃⁺
3. The formula of the conjugate acid of the brønsted-lowry base: H₂CO₃
4. The formula of the conjugate acid of the brønsted-lowry base:
C₆H₅NH₃⁺
5. The acidic equilibrium equation for HC₂H₃O₂: HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O²⁻
6. The basic equilibrium equation for C₆H₅NH₂
C₆H₅NH₂ + H₂O ⇌ C₆H₅NH₃⁺ + OH⁻
7. The basic equilibrium equation for NH₃
NH₃ + H₂O ⇌ NH₄⁺ + OH⁻
To know more about the conjugate refer here :
https://brainly.com/question/29870475#
#SPJ11
1. Draw the structure of diiodine monoselenide and
a. Write the formula
b. Determine the molecular geometry
C. Calculate the formal charge of EACH element. (SHOW ALL WORK)
Diiodine monoselenide is an inorganic compound with the chemical formula I2Se. It is a dark red solid that is sparingly soluble in water. The structure of diiodine monoselenide consists of a linear Se-I-I unit, with the selenium atom in the middle and the two iodine atoms on either side. This arrangement gives the compound a linear, V-shaped structure.
Diiodine monoselenide is an important compound in the field of materials science, as it exhibits some interesting properties. For example, it can be used as a precursor for the synthesis of various selenium-containing compounds, including organoselenium compounds, which are used in catalysis and medicine.
Additionally, diiodine monoselenide has been studied as a potential material for use in electronic devices, due to its semiconducting properties. In conclusion, diiodine monoselenide is an important inorganic compound that exhibits some interesting structural and material properties.
Its linear, V-shaped structure is due to the arrangement of the selenium and iodine atoms in a linear Se-I-I unit. This compound is used in the synthesis of various selenium-containing compounds and has potential applications in the field of electronics.
To know more about monoselenide refer here
https://brainly.com/question/19960546#
#SPJ11
At what volume will 22.4l of oz (p) at 303k and 1.2atm have the same number of molecules as neon gas at 303k and 12 atm?
When the volume of neon gas is 2.07 L, 22.4 L of ounce (p) at 303 K and 1.2 atm will have the same number of molecules as neon gas at 303 K and 12 atm.
To solve this problem, we can use the ideal gas law equation:
PV = [tex]nRT[/tex], where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
First, we need to find the number of moles of neon gas at 303K and 12 atm. We can use the equation PV = [tex]nRT[/tex] and rearrange it to solve for n: n = PV/RT. Plugging in the values, we get:
[tex]n = (12 atm)(22.4 L)/(0.0821 L*atm/mol*K)(303 K)[/tex]
n = 12.04 mol
So, neon gas at 303K and 12 atm has 12.04 moles.
Now, we need to find the volume of oz (p) at 303K and 1.2 atm that has the same number of molecules. We can use the equation n = N/NA, where N is the number of molecules and NA is Avogadro's number (6.022 x 10^23). Rearranging the equation to solve for V, we get:
V = [tex]nRT[/tex]/P
[tex]V = (12.04 mol)(0.0821 L*atm/mol*K)(303 K)/(1.2 atm)[/tex]
V = 249.5 L
Therefore, at 303K and 1.2 atm, 22.4 L of oz (p) has the same number of molecules as neon gas at 303K and 12 atm when the volume is 249.5 L.
To solve this problem, we'll use the Ideal Gas Law equation, PV=[tex]nRT[/tex], where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
First, let's find the number of moles of the given gas, oz (p):
P1 = 1.2 atm
V1 = 22.4 L
T1 = 303 K
R = 0.0821 L atm/mol K (Ideal Gas Constant)
1.2 atm * 22.4 L = n * 0.0821 L atm/mol K * 303 K
n = (1.2 * 22.4) / (0.0821 * 303) = 1 mol
Now, let's find the volume (V2) of neon gas at the given conditions:
P2 = 12 atm
T2 = 303 K
n2 = 1 mol (since we want the same number of molecules)
12 atm * V2 = 1 mol * 0.0821 L atm/mol K * 303 K
V2 = (1 * 0.0821 * 303) / 12 = 2.07 L
Thus, 22.4 L of oz (p) at 303 K and 1.2 atm will have the same number of molecules as neon gas at 303 K and 12 atm when the volume of neon gas is 2.07 L.
For more question on volume
https://brainly.com/question/29796637
#SPJ11
chemistry help please!
6. The mass (in grams) present is 9.72×10⁸ grams
7. The number of atoms is 8.50×10²⁴ atoms
8. The mass (in grams) present is 3.73×10¹⁰ grams
6. How do i determine the mass ?First, we shall determine the mole of LiNO₃. Details below:
6.022×10²³ atoms = 1 mole of LiNO₃
Therefore,
8.48×10³⁰ atoms = 8.48×10³⁰ / 6.022×10²³
8.48×10³⁰ atoms = 1.41×10⁷ moles of LiNO₃
Finally, we shall determine the mass of LiNO₃. Details below:
Mole of LiNO₃ = 1.41×10⁷ molesMolar mass of LiNO₃ = 68.95 g/molMass of LiNO₃ = ?Mass = Mole × molar mass
Mass of LiNO₃ = 1.41×10⁷ × 68.95
Mass of LiNO₃ = 9.72×10⁸ grams
7. How do i determine the number of atoms?First, we shall determine the mole in 2105 g of (NH₄)₃PO₃. Details below:
Mass of (NH₄)₃PO₃ = 2105 grams Molar mass of (NH₄)₃PO₃ = 149.09 g/mol Mole of (NH₄)₃PO₃ =?Mole = mass / molar mass
Mole of (NH₄)₃PO₃ = 2105 / 149.09
Mole of (NH₄)₃PO₃ = 14.12 moles
Finally, we shall determine the number of atoms. Details below:
From Avogadro's hypothesis,
1 mole of (NH₄)₃PO₃ = 6.022×10²³ atoms
Therefore,
14.12 moles of (NH₄)₃PO₃ = 14.12 × 6.022×10²³
14.12 moles of (NH₄)₃PO₃ = 8.50×10²⁴ atoms
Thus, the number of atoms is 8.50×10²⁴ atoms
8. How do i determine the mass?First, we shall determine the mole of (NH₄)₂SO₄. Details below:
6.022×10²³ atoms = 1 mole of (NH₄)₂SO₄
Therefore,
1.7×10³² atoms = 1.7×10³² / 6.022×10²³
1.7×10³² atoms = 2.82×10⁸ moles of (NH₄)₂SO₄
Finally, we shall determine the mass of (NH₄)₂SO₄. Details below:
Mole of (NH₄)₂SO₄ = 2.82×10⁸ molesMolar mass of (NH₄)₂SO₄ = 132.14 g/molMass of (NH₄)₂SO₄ = ?Mass = Mole × molar mass
Mass of (NH₄)₂SO₄ = 2.82×10⁸ × 132.14
Mass of (NH₄)₂SO₄ = 3.73×10¹⁰ grams
Learn more about number of atoms:
brainly.com/question/15488332
#SPJ1
NH3 + H2O = NH4+ + OH-
If an acid is defined as an H+ donor, what is the acid in the reverse reaction
In the reverse reaction NH4+ + OH- = NH3 + H2O, the acid is OH-. This is because OH- accepts a proton (H+) from NH4+, forming H2O.
In this reaction, OH- acts as a base, accepting the proton and becoming neutral water. When a base accepts a proton, it is called a Brønsted-Lowry acid, as it acts as an acid in the reverse reaction. This is because acids and bases are defined in terms of their behavior in reactions, rather than their chemical composition.
Acids are substances that donate protons (H+) in chemical reactions, while bases are substances that accept protons. When NH3 accepts a proton from H2O, it forms NH4+ and OH-, with NH3 acting as a base and H2O acting as an acid.
However, in the reverse reaction, OH- accepts a proton from NH4+, making it the acid and NH3 the base. Understanding these concepts is important in understanding acid-base chemistry, which has many practical applications in fields such as medicine, industry, and environmental science.
To know more about reverse reaction, visit:
https://brainly.com/question/16614705#
#SPJ11
Help me I will give you
A reaction that occurs when 23 grams of iron (II) chloride
reacts with sodium phosphate forming iron (II) phosphate and sodium chloride. What is the limiting reagent? How much sodium chloride can be formed?
3FeCl2 + 2Na3PO4-Fe3 (PO4)2 +6NaClâ
To convert moles of sodium chloride to grams, we multiply by its molar mass of 58.44 g/mol. Therefore, the amount of sodium chloride produced is 0.363 mol x 58.44 g/mol = 21.2 grams.
To determine the limiting reagent in this reaction, we need to calculate the moles of both reactants. From the given information, we know that the mass of iron (II) chloride is 23 grams, and its molar mass is 126.75 g/mol.
Therefore, the number of moles of iron (II) chloride is 23 g/126.75 g/mol = 0.1815 mol.
Next, we calculate the number of moles of sodium phosphate. Since there are two molecules of sodium phosphate for every three molecules of iron (II) chloride, we need to multiply the moles of iron (II) chloride by the ratio of the coefficients. Therefore, the number of moles of sodium phosphate is (0.1815 mol x 2/3) = 0.121 mol.
Since there are fewer moles of sodium phosphate than iron (II) chloride, sodium phosphate is the limiting reagent. This means that all of the sodium phosphate will be used up in the reaction, and any remaining iron (II) chloride will be left over.
To calculate the amount of sodium chloride produced, we need to use the stoichiometric coefficients from the balanced equation.
For every 2 moles of sodium phosphate used, 6 moles of sodium chloride are produced. Therefore, since we have 0.121 mol of sodium phosphate, we can produce (0.121 mol x 6/2) = 0.363 mol of sodium chloride.
Finally, to convert moles of sodium chloride to grams, we multiply by its molar mass of 58.44 g/mol. Therefore, the amount of sodium chloride produced is 0.363 mol x 58.44 g/mol = 21.2 grams.
To know more about molar mass refer here: https://brainly.com/question/7585012#
#SPJ11
What is volume? a. How close particles are stuck together b. The amount of space occupied by matter c. The amount of particles in any given object d. The weight of an object Please select the best answer from the choices provided
The best answer to the question "What is volume?" is b. The amount of space occupied by matter. Volume is a physical property of matter that refers to the amount of space that an object or substance takes up. It is often measured in cubic units such as cubic meters, cubic feet, or cubic centimeters.
It is important to note that volume is not the same as mass or weight, as it refers to the amount of space that matter occupies rather than the amount of matter itself. In summary, volume is the amount of space occupied by matter and is an important concept in the study of physics and chemistry.
to know more about Volume refer here
https://brainly.com/question/23409099#
#SPJ11
What is the molarity of a solution containing 72. 0 g of NaOH in 356 mL of solution?
The molarity of the solution is 5.06 M
To find the molarity of a solution, we use the formula:
Molarity = moles of solute / liters of solution
First, we need to find the moles of[tex]NaOH[/tex]in the solution:
moles of [tex]NaOH[/tex] = mass / molar mass
The molar mass of [tex]NaOH[/tex] is 40.00 g/mol (sodium = 22.99 g/mol, oxygen = 15.99 g/mol, hydrogen = 1.01 g/mol).
moles of[tex]NaOH[/tex] = 72.0 g / 40.00 g/mol = 1.80 mol
Next, we need to convert the volume of solution from milliliters to liters:
356 mL = 0.356 L
Now we can calculate the molarity of the solution:
Molarity = 1.80 mol / 0.356 L = 5.06 M
Therefore, the molarity of the solution is 5.06 M
To know more about molarity refer to-
https://brainly.com/question/8732513
#SPJ11
How do paleontologists determine the placement of a fossil for display? Explain how diagnostic structure is used for the accurate placement of a fossil
Paleontologists use a variety of methods to determine the placement of a fossil for display. One important factor is the diagnostic structure of the fossil, which refers to unique features that help to identify the species and its evolutionary relationships. For example, if a fossil has a particular shape or pattern on its shell, this could indicate a specific genus or species.
To accurately place a fossil for display, paleontologists will carefully examine its diagnostic structures and compare them to other specimens in their collection or in published research. They may also consult with experts in the field or use advanced imaging techniques to better understand the fossil's characteristics.
Once the paleontologists have identified the species and determined its placement, they can design a display that showcases the fossil in a way that is both educational and visually appealing. This may involve creating a custom mount or exhibit case, selecting appropriate lighting and text labels, and considering the context in which the fossil was found.
Overall, the accurate placement of a fossil for display is crucial for conveying its scientific significance to the public and helping people to better understand the history of life on Earth. By using diagnostic structure as a key tool in this process, paleontologists can ensure that the fossils are correctly identified and presented in a way that is both informative and engaging.
To know more about Paleontologists refer here
https://brainly.com/question/11805817#
#SPJ11
Complete the following reaction
a. HN03 + KOH -->. +.
b. HCl + LiOH -->. +.
c. H2S + NaOH -->. +
a. HNO3 + KOH --> KNO3 + H2O
b. HCl + LiOH --> LiCl + H2O
c. H2S + 2NaOH --> Na2S + 2H2O
To know more about KNO3 refer here
https://brainly.com/question/27118748#
#SPJ11
3 Zn + 2 H3PO4 → 3 H2 + Zn3(PO4)2
How many grams of Zn are needed in order to produce 0. 15 g of H2?
4.85 grams of Zn are needed to produce 0.15 grams of H2.
The balanced chemical equation for the reaction between zinc and phosphoric acid is:
[tex]3 Zn + 2 H_3PO_4[/tex] → [tex]3 H_2 + Zn_3(PO4)2[/tex]
Step 1: Calculate the number of moles of [tex]H_2[/tex] produced
We can use the molar mass of hydrogen gas ([tex]H_2[/tex]) to calculate the number of moles produced:
n([tex]H_2[/tex]) = mass of [tex]H_2[/tex] / molar mass of [tex]H_2[/tex]
n([tex]H_2[/tex]) = 0.15 g / 2.016 g/mol = 0.0743 mol
Step 2: Calculate mass [tex]Z_2[/tex] needed
We can use the molar mass of zinc to convert moles of Zn to grams of Zn:
mass of Zn = n(Zn) x molar mass of Zn
mass of Zn = 0.0743 mol x 65.38 g/mol
mass of Zn = 4.85 g
To know more about molar mass , here
brainly.com/question/22997914
#SPJ4
How many grams of magnesium can be heated to raise the temperature 45 C and absorb 843 J of energy
Explanation:
You will need the specific heat of Mg which I found to be 1.02 J / (g C)
m * 45 C * 1.02 J . (g C) = 843
m = 843 / (45* 1.02) = 18.4 g of Magnesium
Which gas, Cl2 (g) or COCl2(g) , will deviate most from the ideal gas law at low temperature?
Justify your choice
COCl2(g) will deviate most from the ideal gas law at low temperature. The other name for COCl2(g) is Phosgene. This is because COCl2(g) is a larger molecule with stronger intermolecular forces than Cl2(g). At low temperatures, these intermolecular forces become significant and cause the molecules to be closer together, resulting in a smaller molar volume than predicted by the ideal gas law.
Additionally, COCl2(g) is a polar molecule, which also contributes to the deviation from the ideal gas law as the polar interactions between molecules become stronger at low temperatures. Thus COCl2(g) will be the one deviating from the ideal gas law at low temperature.
Learn more: brainly.com/question/1946554
#SPJ11
Iron (III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 1. 67x10^23 atoms of Fe reacts completely with oxygen?
Approximately 88.67 grams of [tex]Fe_2O_3[/tex] are formed when [tex]1.67*10^{23}[/tex] atoms of Fe react completely with oxygen.
The balanced chemical equation for reaction between iron and oxygen to form iron (III) oxide can be written as:
4 Fe + 3 O2 → 2 [tex]Fe_2O_3[/tex]
To find the number of moles [tex]Fe_2O_3[/tex] formed when [tex]1.67*10^{23[/tex] atoms of Fe react, we first need to convert the given number of atoms of Fe to moles:
1.67x[tex]10^{23}[/tex] atoms of Fe × (1 mol/6.022 x [tex]10^{23}[/tex] atoms) = 0.2777 mol of Fe
The number of moles of [tex]Fe_2O_3[/tex] formed :
0.2777 mol of Fe × (1 mol of [tex]Fe_2O_3[/tex]/0.5 mol of Fe) = 0.5554 mol of[tex]Fe_2O_3[/tex]
We can calculate the mass of [tex]Fe_2O_3[/tex] :
0.5554 mol of [tex]Fe_2O_3[/tex] × 159.69 g/mol = 88.67 g of [tex]Fe_2O_3[/tex]
To know more about iron (III) oxide, here
brainly.com/question/19392610
#SPJ4
How many moles of aluminium chloride, ALCL3 form when 142 g CL2 reacts with plenty of aluminium?
When 142 g Cl₂ combines with lots of aluminium, 1.33 moles of AlCl₃ are formed.
To determine the number of moles of AlCl₃ formed when 142 g Cl₂ reacts with plenty of aluminum, we first need to write a balanced chemical equation for the reaction:
2 Al + 3 Cl₂ → 2 AlCl₃
From the balanced equation, we can see that 3 moles of Cl₂ react with 2 moles of Al to form 2 moles of AlCl₃.
Next, we need to calculate the number of moles of Cl₂ present in 142 g:
n(Cl₂) = m/M
n(Cl₂) = 142 g / 70.9 g/mol
n(Cl₂) = 2.00 moles
Since the reaction consumes 3 moles of Cl₂ for every 2 moles of AlCl₃ formed, we can determine the number of moles of AlCl₃ formed as:
n(AlCl₃) = (2/3) x n(Cl₂)
n(AlCl₃) = (2/3) x 2.00 moles
n(AlCl₃) = 1.33 moles
Therefore, 1.33 moles of AlCl₃ form when 142 g Cl₂ reacts with plenty of aluminum.
To know more about the Aluminium, here
https://brainly.com/question/16088530
#SPJ1
Calculate the standard free-energy changes for the following reactions at 25°c: (a) h2(g) + br2(l) → 2hbr(g)
The standard free-energy change for the reaction H₂(g) + Br₂(l) → 2HBr(g) at 25°C can be calculated using the equation ΔG° = ΔH° - TΔS°, where ΔH° is the standard enthalpy change, T is the temperature, and ΔS° is the standard entropy change.
To calculate the standard free-energy change for the reaction H₂(g) + Br₂(l) → 2HBr(g) at 25°C, you need to use the equation: ΔG° = ΔH° - TΔS°. Follow these steps:
1. Determine the standard enthalpy change (ΔH°) for the reaction.
2. Determine the standard entropy change (ΔS°) for the reaction.
3. Calculate ΔG° using the equation and the given temperature (25°C = 298.15 K).
To know more about standard free-energy click on below link:
https://brainly.com/question/6556762#
#SPJ11
