Answer:
a) V₀ₓ = 8.66 m/s
b) V₀y = 5 m/s
c) Magnitude of velocity vector = 10 m/s
Explanation:
a)
The magnitude of the horizontal component of launch velocity can easily be given by the following formula:
V₀ₓ = V₀ Cos θ
where,
V₀ₓ = horizontal component of velocity = ?
V₀ = Launch Velocity = 10 m/s
θ = Launch Angle of the ball with the horizontal = 30°
Therefore,
V₀ₓ = (10 m/s)(Cos 30°)
V₀ₓ = 8.66 m/s
b)
The magnitude of the vertical component of launch velocity can easily be given by the following formula:
V₀y = V₀ Sin θ
where,
V₀y = vertical component of velocity = ?
V₀ = Launch Velocity = 10 m/s
θ = Launch Angle of the ball with the horizontal = 30°
Therefore,
V₀y = (10 m/s)(Sin 30°)
V₀y = 5 m/s
c)
The magnitude of the velocity vector will be equal to the resultant velocity or net velocity, which is 10 m/s.
Magnitude of Velocity Vector = 10 m/s
When did Pangaea begin to break apart?
Answer:
Hey!
Well according to scientific data and analysis, it started to break up about 175 - 200 million years ago!!
Explanation:
HOPE THIS HELPS!!
Answer:
250 million (:
Explanation:
Can someone explain what ice jacking is and how it can cause structures to fail?
Answer: Rock slope failures can occur due to the presence of water; ice jacking occurs when water between joint or fissure surfaces freezes and expands. This type of failure is progressive, resulting in incremental weakening over time, often requiring several cycles before failure. Ice jacking is one form of rock erosion.
Please explain how you got the answer :(
Answer:
36.5 kJ
Explanation:
Energy by machine = energy to machine × efficiency
E = 52.1 kJ × 0.70
E = 36.5 kJ
1. Calculate the total binding energy of 12
6 C.
Answer in units of MeV.
2. Calculate the average binding energy per nucleon of 24
12Mg.
Answer in units of MeV/nucleon.
3. Calculate the average binding energy per nucleon of 85
37Rb.
Answer in units of MeV/nucleon.
4. Find the binding energy per nucleon of 238
92U.
Answer in units of MeV/nucleon.
5. Calculate the total binding energy of 20
10Ne.
Answer in units of MeV.
6. Calculate the total binding energy of 40
20Ca.
Answer in units of MeV.
Answer:
1. B = 79.12 MeV
2. B = -4.39 MeV/nucleon
3. B = 2.40 MeV/nucleon
4. B = 7.48 MeV/nucleon
5. B = -18.72 MeV
6. B = 225.23 MeV
Explanation:
The binding energy can be calculated using the followng equation:
[tex] B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} [/tex]
Where:
Z: is the number of protons
[tex]m_{p}[/tex]: is the proton's mass = 1.00730 u
N: is the number of neutrons
[tex]m_{n}[/tex]: is the neutron's mass = 1.00869 u
M: is the mass of the nucleus
1. The total binding energy of [tex]^{12}_{6}C[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV [/tex]
2. The average binding energy per nucleon of [tex]^{24}_{12}Mg[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
Where: A = Z + N
[tex] B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon [/tex]
3. The average binding energy per nucleon of [tex]^{85}_{37}Rb[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
[tex] B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon [/tex]
4. The binding energy per nucleon of [tex]^{238}_{92}U[/tex] is:
[tex] B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon [/tex]
5. The total binding energy of [tex]^{20}_{10}Ne[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV [/tex]
6. The total binding energy of [tex]^{40}_{20}Ca[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV [/tex]
I hope it helps you!
A 2kg object is dropped from a height 10m.Calculate the speed of the object after it has fallen 5m, assuming there is no resistance. g= 10 N/kg
Answer:
10m/s
Explanation:
[tex]d=v_ot+\dfrac{1}{2}at^2[/tex]
Since there is no initial velocity as the object is dropped, you can write the following equation:
[tex]5=\dfrac{1}{2}(10)t^2 \\\\1=t^2 \\\\t=1[/tex]
Now that you know how long the fall took, you can use another physics equation to find the velocity at that point.
[tex]v_f=v_o+at[/tex]
Since there once again is no initial velocity, you can rewrite this as:
[tex]v_f=at=(10)(1)=10m/s[/tex]
Hope this helps!
The kinetic energy the object has at any point during the fall is exactly the potential energy it lost by falling to that height.
Potential energy = (mass) · (gravity) · (height)
Change of potential energy = (mass) · (gravity) · (change of height)
Change of potential energy = (2 kg) · (10 m/s ) · (-5 m)
Change of potential energy = 100 Joules
Kinetic energy = (1/2) · (mass) · (speed²)
Kinetic energy = (1 kg) · (speed² )
100 J = (1 kg) · (speed²)
Speed² = (100 J) / (1 kg)
Speed² = (100 kg-m²/s²) / (1 kg)
Speed² = (100 m²/s²)
Speed = 10 m/s
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Answer:
The net displacement is
[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]
[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]
Explanation:
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Given data
A = 15 m
B = 25 m
Angle between the vectors A and B is θ = 30°
The net displacement is
[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]
[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]
What are some potential sources of error in the
experiment that is described in the article?
Answer: experimental design
the accuracy of data-collecting devices
human error
bias in selecting samples
incorrect data analysis
incorrect treatment of the control group
Explanation:
Instrumental, environmental, procedural, and human errors are frequent causes. Depending on how they affect the outcomes, each of these errors can either be random or systematic.
What are Experimental Error?The discrepancy between a measured value and its true value is known as experimental error. In other words, the error or inaccuracies are what prevent us from perceiving a measurement that is 100 percent accurate.
Every measurement has some degree of experimental error, which is fairly common. Due to the widespread belief that some degree of error is inherent to the scientific method, it is not typically seen as a "mistake" in the classic sense.
However, scientists can reduce error and obtain results that are more accurate by embracing and comprehending the ways that experimental error can affect any scientific operation.
The potential sources of error in experiment are Instrumental, environmental, procedural, and human errors.
Learn more about Experimental Error here:
https://brainly.com/question/17038045
#SPJ6
Which musical instruments produce lower pitches
Answer:
bigger instruments make lower pitches
Explanation:
bass drums and other large instruments have low sounds because they're so big. the smaller the instrument is, the higher pitch it's going to have
Answer:
It is mostly the Bass instruments because they use mouthpieces while the wind instrument use reeds and make a higher pitched sounds
Explanation:
Band
A squeeze bottle squeezes when pressed. It regains its shape when pressed .It regains its shape when the pressure from your hand is withdrawn. What may happen if the squeeze bottle is pressed to take the sauce out and then immediately corked tightly? Will it regain its shape? If not, Why?
Answer: It will not regain its shape, because when it is corked it can not replace the volume of material that you just take out of it.
Explanation:
When you squeeze the bottle, you are changing the volume of the bottle, in this process, you are "expelling" the material inside the bottle.
When you stop squeezing, there is a change in pressure, and the bottle "absorbs" air, until the pressure is equilibrated, and in this process, the bottle returns to the original shape.
Now, if you take the sauce out of the bottle and immediately cored it, then you removed the material inside of the bottle and did not let the bottle to "refill" the empty space with air, so it can not regain its shape.
can someone put these in the right order please
A student drops two metallic objects into a 120 g steel container holding) 150 g of water at 25°C. One object is a 253 g cube of copper that is initially at 85°C, and the other is a chunk of aluminum that is initially at 5°C. To the surprise of the student, the water reaches a final temperature of 25°C, its initial temperature. What is the mass of the aluminum chunk? (please add an explanation)
Answer: 0.326kg
Explanation:
Given the following :
Mass of copper (Mc) = 253g
Initial temperature of copper (t1) = 85°C
Mass of aluminium(Ma)=?
Initial temperature of aluminum(t1) = 5°C
Specific heat capacity of aluminum(Ca) = 900
Specific heat capacity of copper (Cc) = 387
Final temperature(t2) = 5°C
Q = mc(t2 - t1)
Ma × Ca × (t2 - t1)a = Mc × Cc × (t2 - t1)c
Ma × 900 × (25 - 5) = 0.253 × 387 × (25 - 85)
Ma × 900 × 20 = 0.253 × 387 × 60
Ma × 18000 = 5874.66
Ma = 5874.66 / 18000
Ma = 0.32637
Ma = 0.326kg
The mass of the aluminum chunk dropped into the water is 325.5 g.
The given parameters;
mass of the steel, = 120 gmass of water = 150 ginitial temperature of water = 25 °Cmass of copper = 253 ginitial temperature of the copper = 85 °Cinitial temperature of the aluminum = 5 °Cfinal temperature of water = 25 °CSpecific heat capacity of aluminum = 0.9 J/gC Specific heat capacity of copper = 0.386 J/gCApply the principle of conservation of energy, the heat gained by the aluminum is equal to heat lost by the copper;
[tex]M_a C_a (t- t_a) = M_c C_c (t_c - t)\\\\M_a\times 0.9 \times (25-5) = 253 \times 0.386 \times (85-25)\\\\18 M_a = 5859.48\\\\M_a = \frac{5859.48}{18} \\\\M_a = 325 .5 \ g[/tex]
Thus, the mass of the aluminum chunk dropped into the water is 325.5 g.
Learn more here: https://brainly.com/question/20709851
What would Genaris and her classmates most likely do to
test this idea?
its
Explanation:
they would formulate a new hypothesis with the same dependent variable but a different independent variable as a virginal hypothesis .
What is the wavelength of a 1.28 x 10^17 Hz wave?
Answer:
The wavelength of the wave is 2.34 nm.
Explanation:
It is required to find the wavelength of a [tex]1.28\times 10^{17}\ Hz[/tex] wave. A wave moves with a speed of light. Speed of a wave is given in terms of wavelength and frequency. So,
[tex]v=f\lambda[/tex]
[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1.28\times 10^{17}}\\\\\lambda=2.34\times 10^{-9}\ m\\\\\text{or}\\\\\lambda=2.34\ nm[/tex]
So, the wavelength of the wave is 2.34 nm.
The wavelength of the wave is 2.34 × 10⁻⁹ meters.
Given the data in the question;
Frequency; [tex]f = 1.28*10^{17}Hz[/tex]Wavelength; [tex]\lambda =\ ?[/tex]
To determine the wavelength of the wave, we use the expression for the relations between wavelength, frequency and speed of light.
[tex]\lambda = \frac{c}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and c is speed of light ( [tex]3*10^8m/s[/tex] )
We substitute our values into the equation
[tex]\lambda = \frac{3*10^8m/s}{1.28*10^{17}Hz} \\\\\lambda = \frac{3*10^8m/s}{1.28*10^{17}s^{-1}} \\\\\lambda = 2.34 * 10^{-9}m[/tex]
Therefore, the wavelength of the wave is 2.34 × 10⁻⁹ meters.
Learn more: https://brainly.com/question/10674607
Who is prime minister of india
His name is
Narendra Modi
Answer:
Hey!
*its kinda the wrong topic but ill answer anyway!!!*
The Prime Minister of India is...
Narendra ModiExplanation:
HOPE THIS HELPS!!
If there are a boys pulling a rubber
with the same amount of force what will happen?
Answer:
The rubber will expand to its maximum and then tear in the middle.
Explanation:
Answer:
Hey!
Well if they continue to pull the rubber band, it would eventually rip apart right in the middle as the force could not be contained by the elastic fibres and had reached its maximum extension!
Explanation:
HOPE THIS HELPS!!
How many meters is in 32 km
Answer:
32000 m
Explanation:
1000m in 1 km, so 32000m in 32 km.
Answer:
32000m
Explanation:
1km=1000m
so 32 kn is equals to 32000m
Please LOTS OF POINTS. WILL MARK BRAINLIEST
Calculate the Resulting movement using the formula:
Perpendicular distance x Force
1]F1*D1=F2*D2
10N×2m=5N*3m
20N=15Nm
The seesaw will turn anti clock wise.
2]
F1*D1=F2*D2
3N*4m=2N*6m
12Nm=12Nm
It will neither rotate toward anti clock wise nor clock wise
What is the magnitude of impulse of a 2.7 gram ping pong ball initially moving at 15 m/s, if hit by a ping pong paddle and then moves the opposite direction at 14/ms
Answer:
impulse = 0.0783 kg.m/s
Explanation:
The impulse is the product of the force and an interval of time. This can be represented in terms of the mass of the body and the change in the velocity of the body in such a time:
[tex]F\Delta t=m\Delta v[/tex] [tex]=|m(v_f-v_i)|[/tex]
m: mass of the body = 2.7gm = 0.0027 kg
vf: final velocity = -14m/s
vi: initial velocity = 15m/s
vf is negative because the direction of the ball is opposite to the initial direction:
[tex]|m(v_f-v_i)|=|(0.0027kg)(-14m/s-15m/s)|=0.0783\frac{kg.m}{s}[/tex]
hence, the impulse of the ping pong ball is 0.0783 kg.m/s
Which is an example of transforming potential energy to kinetic energy? Select two options
changing thermal energy to electrical energy
changing chemical energy to thermal energy
changing nuclear energy to radiant energy
changing radiant energy to electrical energy
changing mechanical energy to chemical energ
Answer :
.changing chemical energy to thermal energy
.changing nuclear energy to radiant energy
Explanation :
Hope it helps you mate ))Answer:
.changing chemical energy to thermal energy
.changing nuclear energy to radiant energy
Explanation:
The mass of an object is 50 kg. If its weight is 600N on a certain planet. Calculate the
gravitational field strength of the planet.,
Answer: The answer is 700kg
Explanation:
The gravitational force between two students sitting beside each other on Earth is
Answer:
Fgrav. = GM1×M2/R2
Explanation:
Gravitational force is mostly related
to planetary bodies by Newton's law of gravitation which states that the gravitional force is proportional to the product of the mass of the object and inversely proportional to the square of the distance between them.
Hence in this case the Gravitational force,
Fgrav. = GM1×M2/R2
M1 and M2 are the mass of the two students and R is their distance apart
G is a constant known as gravitational constant.6.67408 × 10-11 m3/kgs2
In the equation for elastic potential energy below, what is represented by the symbol k? Ee = ½ × k × e²
Answer:
K is the spring/elastic constant measured in Newton per metre square (N/m²)
Explanation:
E = ½Ke²
In the equation above,
E is the energy in Joules (J)
K is the elastic/spring constant in Newton per metre square (N/m²)
e is the extension in metre (m)
Answer:
In the equation Ee = ½ × k × e², "k" = spring constant
Explanation:
how many chromosomes will an elephant's sperm have ?
A 4.0 kg block is initially at rest on a frictionless, horizontal surface. The block is moved 8.0 m by the application of a constant 10.0 N horizontal force. If the block slides into a fixed horizontal spring and comes to rest when the spring is compressed a distance of x=0.25m. Determine the spring constant of the fixed horizontal spring. Show all formula with substitutions and units.
Answer:
k = 2560 N/m
Explanation:
To find the spring constant, you take into account that all the kinetic energy of the block becomes elastic potential energy in the spring, when the block compressed totally the spring:
[tex]K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]
m: mass of the block = 4.0kg
v: velocity of the block just before it hits the spring
x: compression of the spring = 0.25m
k: spring constant = ?
You solve the previous equation for k:
[tex]k=\frac{mv^2}{x^2}[/tex] (1)
Then, you have to calculate the velocity v of the block. First, you calculate the acceleration of the block by using the second Newton law:
[tex]F=ma[/tex]
F: force over the block = 10.0N
a: acceleration
[tex]a=\frac{F}{m}=\frac{10.0N}{4.0kg}=2.5\frac{m}{s^2}[/tex]
With this value of a you can calculate the final velocity after teh block has traveled a distance of 8.0m:
[tex]v^2=v_o^2+2ad[/tex]
vo: initial velocity = 0m/s
d: distance = 8.0m
[tex]v=\sqrt{2ad}=\sqrt{2(2.5m/s^2)(8.0m)}=6.32\frac{m}{s}[/tex]
Now, you can calculate the spring constant by using the equation (1):
[tex]k=\frac{mv^2}{x^2}=\frac{(4.0kg)(6.32m/s)^2}{(0.25m)^2}=2560\frac{N}{m}[/tex]
hence, the spring constant is 2560 N/m
Salt is dissolved in a flask of tap water . Distilling the mixture causes the salt to separate from the water. Which type of energy is required to begin the distilling process
energy is the ability to___or___ matter
Energy is defined in science as the ability to move matter or change matter in some other way.
QUICK WILL MARK BRAINLIEST
As light shines from air to water, the index of refraction is 1.02 and the angle of
incidence is 38.0 °. What is the light's angle of refraction?
29.8°
32.5°
37.1°
39.8°
Answer:
37.1°
Explanation:
A student with a mass of 66.0 kg climbs a staircase in 44.0 s. If the distance between the base and the top of the staircase is 14.0 m, how much power will the student deliver by climbing the stairs
[tex]power = 205.8 \: watt \\ solution \\ mass = 66 \: kg \\ time = 44 \: sec \\ distance = 14 \\ now \\ power = \frac{w}{t} \\ \: \: \: \: \: \: \: \: = \frac{f \times d}{t} \\ \: \: \: \: \: = \frac{m \times g \times d}{t} \\ \: \: \: \: \: \: = \frac{66 \times 9.8 \times 14}{44} \\ \: \: \: \: = \frac{9055.2}{44} \\ \: \: \: \: \: = 205.8 \: watt \\ hope \: it \: helps[/tex]
When a rocket accelerates through space is there work done?
Calculate the weight of an object on earth surface having 600km from surface of earth?
Your question seems to contradict itself. You said "on Earth surface" and then you said "600 km from surface of the Earth" ... both in the same sentence.
I'll assume that the object is actually 600 km from surface of the Earth, because that makes the question (and the answer) more interesting.
We know that the weight of any object is (mass) x (gravity). Those are the two numbers we need in order to calculate the object's weight. Mysteriously, you haven't told us either one. We'll call the object's mass ' M ' (clever, eh ?), and we'll calculate the value of gravity up there where the object is located.
We now that the acceleration of gravity is inversely proportional to the square of the distance between the centers of two objects. When an object is on the Earth's surface, it's 6,371 km from Earth's center, and the acceleration of gravity there is 9.8 m/s².
The object in the question is 600 km farther from Earth's center, so the acceleration of gravity there is
(9.8 m/s²) · (6371 / 6971)² = 8.2 m/s².
So the object's weight is (8.2 M) Newtons.
This is about 84% of its weight on Earth's surface.
(Notice that the astronauts aboard the International Space Station are NOT "weightless". The strength of gravity up there where they are is around 84% of what it is down on the ground. The question of why they float, and why their muscles waste away, is a topic for another Brainly question.)
