A red laser with a wavelength of 630 nm and a blue laser with a wavelength of 450 nm emit laser beams with the same light power. How do their rates of photon emission compare

Answers

Answer 1

Answer:

Evaluate the following numerical expressions.

6 + 3 • 4 =

18

(6 + 3) ÷ (4 – 5) =

Explanation:

Evaluate the following numerical expressions.

6 + 3 • 4 =

18

(6 + 3) ÷ (4 – 5) =


Related Questions

A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in figure A, she rotates about her center of mass at a rate of 6.27 rad/s. Her moment of inertia about this axis is 17.9 kg⋅m2. A short time later, the aerialist is in the straight position, as shown in figure B. If the moment of inertia about her center of mass in this position is now 33.1 kg⋅m2, what is her rotational speed in revolutions per minute (rpm)?

Answers

The rotational speed of the trapeze artist is 32.372 revolutions per second.

In this question we should apply the principle of angular momentum conservation to determine the final angular speed of the trapeze artist, since there are no external forces acting on the trapeze artist:

[tex]I_{A}\cdot \omega_{A} = I_{B}\cdot \omega_{B}[/tex] (1)

Where:

[tex]I_{A}[/tex], [tex]I_{B}[/tex] - Initial and final moments of the trapeze artist, in kilograms-square meter.

[tex]\omega_{A}[/tex], [tex]\omega_{B}[/tex] - Initial and final angular speeds, in radians per second.

If we know that [tex]I_{A} = 17.9\,kg\cdot m^{2}[/tex], [tex]I_{B} = 33.1\,kg\cdot m^{2}[/tex] and [tex]\omega_{A} = 6.27\,\frac{rad}{s}[/tex], then the final angular speed is:

[tex]\omega_{B} = \frac{I_{A}}{I_{B}}\times \omega_{A}[/tex]

[tex]\omega_{B} = \frac{17.9\,kg\cdot m^{3}}{33.1\,kg\cdot m^{2}}\times 6.27\,\frac{rad}{s}[/tex]

[tex]\omega_{B} = 3.390\,\frac{rad}{s}[/tex] ([tex]32.372\,rpm[/tex])

The rotational speed of the trapeze artist is 32.372 revolutions per second.

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A constant force of 8.0 N is exerted for 4.0 s on a 16-kg object initially at rest. The change in speed of this object will be:

Answers

The change in speed of this object is 3m/s

According to Newton's second law;

F = ma

F = mv/t

Given the following parameters

Force F = 8.0N

mass m = 16kg

time t = 4.0s

Required

speed v

Substitute the given parameters into the formula

v = Ft/m

v = 8 * 6/16

v = 48/16

v = 3m/s

Hence the change in speed of this object is 3m/s

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What are last two commandments? Please write them down.

Answers

[tex]⇒[/tex]

The Second Commandment refers to: The second of the Ten Commandments, which is: "Thou shalt have no other gods before me. Thou shalt not make unto thee any graven image" under the Talmudic division of the third-century Jewish Talmud.

Answer:

Thou shalt love the Lord thy God with all thy heart, and with all thy soul, and with all thy mind. This is the first and great commandment. And the second is like unto it, Thou shalt love thy neighbor as myself.

Explanation:

In the circuit, the capacitor is fully charged when switch is closed. Calculate the time needed for the potential energy stored by the circuit to be equally distributed between the capacitor and inductor. The capacitance is =20.0 mF and inductance is =45.0 H .

Answers

We have that for the Question "In the circuit, the capacitor is fully charged when switch is closed. Calculate the time needed for the potential energy stored by the circuit to be equally distributed between the capacitor and inductor. The capacitance is =20.0 mF and inductance is =45.0 H ." it can be said that the time required is

[tex]T=0.745s[/tex]

From the question we are told

In the circuit, the capacitor is fully charged when switch is closed. Calculate the time needed for the potential energy stored by the circuit to be equally distributed between the capacitor and inductor. The capacitance is =20.0 mF and inductance is =45.0 H .

Generally the equation for the Time   is mathematically given as

[tex]T=\sqrt{LC}*\frac{\pi}{4}[/tex]

[tex]T=\sqrt{20*10^{-3}*45}*\frac{\pi}{4}[/tex]

[tex]T=0.745s[/tex]

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A person walks 32∘ north of west for 94m and 35∘ east of south for 122m. What is the magnitude of his displacement?

Answers

Answer:

n

Explanation:

What is the gravitational potential energy of a circus performer with a mass of 50 kg walking on a tightrope 10 m above the ground

Answers

Answer:

5000 J

Explanation:

GPE = mgh

50*10*10

= 5000 J

The gravitational potential energy of the circus performer walking on the tightrope above the ground is 4900J.

Given the data in the question;

Mass of circus performer; [tex]m = 50kg[/tex]Distance from ground level; [tex]h = 10m[/tex]Gravitational potential energy; [tex]U = ?[/tex]

Gravitational Potential Energy

Gravitational potential energy is simply the potential energy an object possesses relative to another object due to gravity.

It is expressed as;

[tex]U = mgh[/tex]

Where m is mass, h is height or distance from the other massive object and g is the gravitational field ( [tex]g = 9.8m/s^2[/tex] )

To determine the gravitational potential energy of  circus performer, we substitute our values into the expression above.

[tex]U = mgh\\\\U = 50kg\ *\ 9.8m/s^2\ *\ 10m\\\\U = 4900kgm^2/s^2\\\\U = 4900J[/tex]

Therefore, the gravitational potential energy of the circus performer walking on the tightrope above the ground is 4900J.

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A 100-g block slides back and forth on a frictionless surface between two springs, as shown in Fig. 7.18. The left-hand spring has k = 110 N/m and its maximum compression is 21 cm.The right-hand spring has
k = 240 N/m. Find (a) the maximum compression of the right-hand spring and (b) the speed of the block as it moves between the springs.

Answers

(a) Energy is conserved at every point in the block's motion, so the potential energy P stored in the first spring at its maximum compression is the same as is stored in the second spring.

The total work performed on the block by the first spring is

W = -1/2 (110 N/m) (0.21 m²) = -2.4255 J

The work performed by the second spring is the same, so

W = -1/2 (240 N/m) x²

Solve for x :

x² = -2W/(240 N/m) = 0.0202125 m²

x ≈ 0.14 m = 14 cm

(b) By the work-energy theorem, the total work performed by either spring on the block as the spring is compressed is equal to the change in the block's kinetic energy. The restoring force of the spring is the only force involved. At maximum compression, the block has zero velocity, while its kinetic energy and hence speed is maximum just as it comes into contact with either spring.

W = 0 - K

W = -1/2 (0.10 kg) v²

v² = -2W/(0.10 kg) = 48.51 m²/s²

v ≈ 7.0 m/s

The LANDSAT C Earth resources satellite has a nearly circular orbit with an eccentricity of 0.00132. At perigee the satellite is at an altitude (measured from the earth's surface) of 417km. a) Calculate its altitude at apogee. b) Calculate its period. c) Calculate the velocity at perigee.

Answers

We have that for the Question it can be said that

altitude at apogee = [tex]434.96km[/tex]period = [tex]5585.41s[/tex]velocity at perigee = [tex]7.67km/s[/tex]

From the question we are told

The LANDSAT C Earth resources satellite has a nearly circular orbit with an eccentricity of 0.00132. At perigee the satellite is at an altitude (measured from the earth's surface) of 417km.

Generally the equation for perigee radius is mathematically given as

[tex]r_p = R_E+Z_P\\\\=6378+417\\\\=6795km[/tex]

the equation for orbit is

[tex]r_p = \frac{h^2}{u}*\frac{1}{1+e}\\\\6795 = \frac{h^2}{398600}*\frac{1}{1+0.00132}\\\\h = 52077.5km^2/s[/tex]

the equation for velocity at perigee is mathematically given as

[tex]V_p = \frac{h}{r_p}\\\\= \frac{52077.5}{67.95}\\\\=7.67km/s[/tex]

the equation for Apagee radius is mathematically given as

[tex]r_a = \frac{h^2}{u} * \frac{1}{1-e}\\\\= \frac{52077.5^2}{398600} * \frac{1}{1-0.00132}\\\\= 6812.97km[/tex]

the equation for altitude at Apagee is mathematically given as

[tex]Z_a = r_a - R_E\\\\=6812.97-6378\\\\=434.96km[/tex]

the equation for period

[tex]Period T = \frac{2\pi}{u^2} * (\frac{h}{\sqrt1-e^2})^3\\\\= \frac{2\pi}{398600^2} * (\frac{52077.5}{\sqrt1-0.00132^2})^3\\\\= 5585.41s[/tex]

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He drives 150 meters in 18 seconds. Assuming constant speed, what is his speed in meters per second?

Answers

Answer:

Explanation:

Givens

d = 150 meters

t  = 18 seconds

r (rate) = ?

Formula

r = d/t

Solution

r = 150/18

r = 8.33 m/s

Select all of the following that are involved in translation:

amino acids
tRNA
mRNA
ribonucleotides
deoxyribonucleotides
RNA Polymerase

Answers

Answer:

Amino Acids

tRNA

mRNA

ribonucleotides

Explanation:

Amino Acids

- During translation, an mRNA sequence is read using the genetic code, which is a set of rules that defines how an mRNA sequence is to be translated into the 20-letter code of amino acids, which are the building blocks of proteins.

tRNA

- At the beginning of translation, the ribosome and a tRNA attach to the mRNA. The tRNA is located in the ribosome's first docking site. This tRNA's anticodon is complementary to the mRNA's initiation codon, where translation starts. The tRNA carries the amino acid that corresponds to that codon. ransfer ribonucleic acid (tRNA) is a type of RNA molecule that helps decode a messenger RNA (mRNA) sequence into a protein. tRNAs function at specific sites in the ribosome during translation, which is a process that synthesizes a protein from an mRNA molecule.

mRNA

- Translation is the process by which a protein is synthesized from the information contained in a molecule of messenger RNA (mRNA). ... Then a transfer RNA (tRNA) molecule carrying the amino acid methionine binds to what is called the start codon of the mRNA sequence.

ribonucleotides

- During transcription, a ribonucleotide complementary to the DNA template strand is added to the growing RNA strand and a covalent phosphodiester bond is formed by dehydration synthesis between the new nucleotide and the last one added.

If a block is sitting in a shelf 5 foot high and the same size block is sitting on the shelf above it at 6 feet high. Which has more potential energy? Explain your reasoning.

Answers

Answer:

Explanation:

Assuming that not only is the size of the two blocks the same but the MASS is also the same, then the higher block will have more potential energy.

Potential energy is equal to the amount of work required against gravity to position a mass

Work is a force times a distance. PE = W = Fd

As each block has the same mass, they each create the same force which would be their weight mg

PE = W = Fd = mgd

so potential energy is directly proportional to the height of each block

the lower block has potential energy PE = Fd = mg(5)

while the upper block has potential energy PE = mg(6)

above a reference frame origin, possibly the floor.

It is possible that the higher block has less potential energy then the lower block if only the size is considered. If the higher block is a one foot cube of ice at 57.2 lbs and the lower block is a one foot cube of copper at 559 lbs then the lower mass would have much more potential energy because of its much greater mass.

559(5) = 2795 ft•lb of potential energy

57.2(6) = 343.2 ft•lb of potential energy

How much force is required to swing a 3 kg mass in a circle with a radius of 1.5 m at a speed of 5 m/s?

Answers

The force that is required to swing the mass is 50 Newton.

Given the following data:

Mass = 3 kgRadius = 1.5 metersSpeed = 5 m/s

To find the amount of force that is required to swing the mass, we would use centripetal force formula:

Mathematically, centripetal force is given by the formula:

[tex]F_c = \frac{mv^2}{r}[/tex]

Where:

m is the mass.v is the speed.r is the radius.

Substituting the parameters into the formula, we have;

[tex]F_c = \frac{3 \times 5^2}{1.5}\\\\F_c = \frac{3 \times 25}{1.5}\\\\F_c = \frac{75}{1.5}\\\\F_c = 50[/tex]

Centripetal force = 50 Newton

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car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. The car has
_______________ energy.

Answers

Answer:896000 J

Explanation: K.E = 1/2*m*v^2

Answer:

The car has Kinetic energy. 896000 Joules

Explanation:

Kinetic energy formula: 1/2 (mass)(speed)^2

First you multiply 1120 by 1/2 and get 560

Then you take the square root of 40 ([tex]40x^{2}[/tex]) and get 1600

Finally to get the answer multiply 560 by 1600 and your final answer should be 896000 Joules

during the spin cycle of a washing machine the cloth stick to the outer wall of the barrel as it spins at a speed of 65 m per second. the radius of the barrel is 0.35 m. what is the magnitude and direction of centripetal acceleration of the clothes which are located on the wall of the barrel​

Answers

Hi there!

Centripetal acceleration can be written as:

[tex]a_c = \frac{v^2}{r}[/tex]

v = tangential velocity (m/s)

r = radius (m)

Plug in the given values:

[tex]a_c = \frac{65^2}{0.35} = \boxed{12071.43 \text{ m}/s^2}}}[/tex]

The centripetal acceleration vector ALWAYS points towards the CENTER POINT of the barrel.

An object of mass is used to provide tension in a 6.0 ‑m‑long string that has a mass of 0.252 kg, as shown. A standing wave that has a wavelength equal to 1.5 m is produced by a source that vibrates at 24 Hz.

Answers

The tension on the string at the given length and mass is 54.43 N.

The given parameters:

length of the string, L = 6.0 mmass of the string, m = 0.252 kgwavelength, λ = 1.5 mfrequency of the source, F = 24 Hz

The speed of the wave is calculated as follows;

[tex]v= f\lambda\\\\v = 24 \times 1.5\\\\v = 36 \ m/s[/tex]

The tension on the string is calculated as follows;

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v = \sqrt{\frac{T}{M/l} } \\\\v = \sqrt{\frac{Tl}{M} } \\\\v^2 = \frac{Tl}{M} \\\\T = \frac{v^2 M}{l} \\\\T = \frac{(36)^2 \times 0.252}{6} \\\\T = 54.43 \ N[/tex]

Thus, the tension on the string at the given length and mass is 54.43 N.

"Your question is not complete is seems to be missing the following information;"

An object of mass is used to provide tension in a 6.0 ‑m‑long string that has a mass of 0.252 kg, as shown. A standing wave that has a wavelength equal to 1.5 m is produced by a source that vibrates at 24 Hz. Determine the tension on the string.

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Một xe có khối lượng 20000kg chuyển động dần đều dưới tác dụng của lực 600N,vận tốc ban đầu của xe bằng 15m/s.hỏi :
a,gia tốc của xe
b,sau bao lâu xe dừng lại
c,đoạn đường xe đã chạy được kể từ lúc hàm cho đến khi dừng hẳn.

Answers

Answer:

please vote and heart please and follow me because I have no followers yet

what is the magnitude of its velocity just before it strikes the ground, if the bottle was thrown straight out horizontally from the tower with a speed of 11.8 m/s?

Answers

There's not enough given information to find the answer.

The horizontal velocity has no effect on anything that happens vertically. To find the object's vertical speed when it hits the ground, we need to know what height it was dropped from, and that's not given in the question.

Since the bottle is falling vertically, the vertical displacement s is the height of the tower from which it was thrown.

If a bottle is thrown horizontally from a tower, its initial vertical velocity is 0 m/s since there is no vertical component to its initial velocity. The only force acting on the bottle in the vertical direction is gravity, which causes it to accelerate downward at a rate of approximately 9.81 m/s² (assuming Earth's gravity).

Since the initial vertical velocity is 0 m/s and the acceleration is 9.81 m/s², you can use the following kinematic equation to find the magnitude of its velocity just before it strikes the ground:

v2=u2+2as

Where:

v is the final vertical velocity (which we're trying to find)

u is the initial vertical velocity (0 m/s)

a is the acceleration due to gravity (-9.81 m/s², negative because it's acting downward)

s is the vertical displacement (which is the height of the tower)

Since the bottle is falling vertically, the vertical displacement

s is the height of the tower from which it was thrown.

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The weight of the atmosphere above 1 m- of
Earth's surface is about 100.000 Ņ. Density, of
course, becomes less with altitudd- But suppose
the density of air were a constant 1.2 kg/m?

Answers

Answer:

1.09 kg.m

Explanation:

no need

A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 when the ball is at its lowest point (θ = 0).
a) What is the gravitational potential energy, in joules, of the ball before it is released?
b) What will be the speed of the ball, in meters per second, when it reaches the bottom?

Answers

Explanation:

a) The height of the ball h with respect to the reference line is

[tex]h = L - L\cos{31°} = L(1 - \cos{31°})[/tex]

so its initial gravitational potential energy [tex]U_0[/tex] is

[tex]U = mgh = mgL(1 - \cos{31°})[/tex]

[tex]\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})[/tex]

[tex]\:\:\:\:\:=0.23\:\text{J}[/tex]

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

[tex]\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U[/tex]

We know that the initial kinetic energy [tex]K_0,[/tex] as well as its final gravitational potential energy [tex]U[/tex] are zero so we can write the conservation law as

[tex]mgL(1 - \cos{31°}) = \frac{1}{2}mv^2[/tex]

Note that the mass gets cancelled out and then we solve for the velocity v as

[tex]v = \sqrt{2gL(1 - \cos{31°})}[/tex]

[tex]\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}[/tex]

[tex]\:\:\:\:\:= 1.3\:\text{m/s}[/tex]

Answer:

a. 0.23J

b. 1.35 m/s

Explanation:

a. U = mgh where where m = mass of the object, g = acceleration due to gravity, and h = height

h = L - Lcos(θ) where L = length of the rope, and θ = angle with respect to vertical.

Therefore, U = mg(L - Lcos(θ))

U = 0.25 * 9.8 (0.65m - 0.65cos(31° ))

U = 0.2275 ≈ 0.23J

The gravitational potential energy of the ball before it is released = 0.23J

b. To determine the velocity of the object at the bottom of its motion, all of the energy has gone from gravitational potential into kinetic since at the bottom, the problem says that U = 0. The kinetic energy of an object is given by the following equation:  

[tex]K.E=\frac{I}{2}*mv^{2}[/tex]

where m = mass of the object and v = velocity of the object. Since we know that all of the energy was transferred into kinetic energy at the bottom, we can conclude that:

[tex]0.2275=\frac{1}{2} *0.25*v^{2}[/tex]

[tex]v^{2}=\frac{2*0.2275}{0.25}[/tex]

[tex]v^{2}=1.82[/tex]

[tex]v=\sqrt{1.82}=1.3491\\[/tex] ≈ [tex]1.35m/s[/tex]

Therefore, the speed of the ball when it reaches the bottom = 1.35m/s

 

A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant

Answers

516.154 megawatts of heat are exhausted to the river that cools the plant.

By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ([tex]Q_{out}[/tex]), in megawatts:

[tex]Q_{out} = Q_{in} - W[/tex]

[tex]Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W[/tex](1)

Where:

[tex]\eta[/tex] - Efficiency.[tex]W[/tex] - Electric power, in megawatts.

If we know that [tex]\eta = 0.39[/tex] and [tex]W = 330\,MW[/tex], then the energy rate exhausted to the river is:

[tex]Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)[/tex]

[tex]Q_{out} = 516.154\,MW[/tex]

516.154 megawatts of heat are exhausted to the river that cools the plant.

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Sin is the ____________________________ of the law. 1 John 3:4.

Answers

Answer:

transgression

Explanation:

A slender rod of length 80.0 cm and 0.600 kg has its center of gravity at its geometrical center. But its density is not uniform; it increases by the same amount from the center of the rod out to either end. You want to determine the moment of inertia Icm of the rod for an axis perpendicular to the rod at its center, but you don't know its density as a function of distance along the rod, so you can't use an integration method to calculate Icm. Therefore, you make the following measurements: You suspend the rod about an axis that is a distance d (measured in meters) above the center of the rod and measure the period T (measured in seconds) for small-amplitude oscillations about the axis. You repeat this for several values of d. When you plot your data as T2−4π2d/g versus 1/d, the data lie close to a straight line that has slope 0.470 m⋅s2. What is the value of Icm for the rod?

Answers

Answer:

Icm = 0.0701 kgm^2

Explanation:

The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route.

Answers

The given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.

During a pick-stage cart, the first bad you load into the vehicle is always placed on the bottom, while subsequent bags are arranged on top of the first bag, all inside the vehicle.

At any point on your route, any bad you tend to open becomes the last bag you load into the vehicle because the first bag is far below the bottom.

Thus, we can conclude that the given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.

"Your question is not complete, it seems to be missing the following information";

The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route. False/True

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Why do heavier objects roll down slopes faster than lighter objects? (Assuming they are the same shape)

Answers

Answer:

because of the friction against the object

Explanation:

9) How many valence electrons does this atom have?
A.2
B. 3
C.8
D. 13

Answers

Answer:

I think it's 2

Explanation:

Within each column, or group, of the table, all the elements have the same number of valence electrons. This explains why all the elements in the same group have very similar chemical properties. For elements in groups 1–2 and 13–18, the number of valence electrons is easy to tell directly from the periodic table.

If you're under stress what is the best way to recharge and calm the brain

Answers

Answer:

Take slow, deep breaths. Or try other breathing exercises for relaxation. ...

Soak in a warm bath.

Listen to soothing music.

Practice mindful meditation. The goal of mindful meditation is to focus your attention on things that are happening right now in the present moment. ...

Write. ...

Use guided imagery.

Take deep breaths and close your eyes

9. Two spheres, one of mass 4.0 x 107 kg and the other of mass 8.0 x 107 kg are separated by a
distance of 400.0 m. The force of gravity between them is
a) 1.3 N b) 530 N c) 1.8 x 104 N
d) 5.1 x 1021 N
e) 5.3 x 1022 N

Answers

Hi there!

We can use the gravitational force equation:

[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

Where:

G = Gravitational Constant

m₁ = mass of one sphere (kg)

m₂ = mass of the other sphere (kg)

r = distance between the spheres (m)

Plug in the given values into the equation:

[tex]F_g = \frac{(6.67*10^{-11})(4.0*10^7)(8.0*10^7)}{400^2} = \boxed{1.334 N}[/tex]

Thus, the correct answer is A.

When converted to a household measurement, 9 kilograms is approximately equal to a) 9000 grams. b) 9000 ounces. 19.8 ounces. d) 19.8 pounds.

Answers

Answer:

9000 grams which is also very close to 19.8 pounds

so answers a) and d) are correct

Explanation:

9 kg(1000 gm/kg) = 9000 gms

9 kg(2.205 lb/kg) = 19.845 lb

I guess it rather depends on whose household you are in. One in the US would probably use 19.8 lb while one in Canada might use 9000 gm.

Thermal is to heat as ___ is to water.
drain
waste
dilute
absorb

Answers

The answer is Absorb I’m pretty sure.

Answer:Thermal is to heat as absorb  is to water.

Explanation:

Water is able to absorb heat - without increasing much in temperature - better than many substances. This is because for water to increase in temperature, water molecules must be made to move faster within the water; this requires breaking hydrogen bonds, and the breaking of hydrogen bonds absorbs heat.

please mark me as brainliest.Thank you so much

The Israelites grumbled 11 times against God. True or False?

Answers

Answer:

This is not a question about physics.

Anyway. Eleven times seems underrated.

Answer:

True

Explanation:

Because they didn't always appreciate the work of God

Other Questions
Estimate the volume of the following geometric figure belowAnswer it properly if not you will be reported Explain fully why each of the strategies you suggest in (c)( i) above is likely to be successful Which point will going to be in y=-4+6 PLSS HELP NEED THIS TODAYRecall what you have learned about analyzing informational texts to write an analysis of Perfectly Imperfect by Donna Bozzone. Use the following prompts to guide your response:1.Write a paragraph in which you analyze the text structure of the informational text. Identify the text structure. Explain how you identified it. Tell how the authors choice of structure helped you as a reader.2.Write a paragraph in which you analyze the authors purpose and point of view. Explain how you determined the authors point of view. Tell how thinking about the authors purpose and point of view helped you understand the topic.3.Write a paragraph in which you analyze how the author distinguished their position from other positions. Explain what you learned from thinking about the different positions. Give examples from the texts. pls help me wich one is it ANSWER ASAP NO FILES OR LINKS (LAST ONE) (maybe) Did the people agree or disagree with adams A 76-kg water skier is being pulled by a nylon (Young's modulus 3.7 x 109 N/m2) tow rope that is attached to a boat. The unstretched length of the rope is 19 m and its cross-section area is 1.6 x 10-5 m2. As the skier moves, a resistive force (due to the water) of magnitude 140 N acts on her; this force is directed opposite to her motion. What is the change in length of the rope when the skier has an acceleration whose magnitude is 0.61 m/s2? Most mutations occurring in an organismGroup of answer choicesare harmful or neutral.cause multiple effects.are beneficial.are deadly. Before traveling to different countries, you may be vaccinated against diseases that you may not normally encounter in your home country. a. Trueb. False what the answer to this equation?9n - 14 =5n + 58 Solve the simultaneous equations5x + 6y = 372x + 3y = 4 what is the main similarity between life in 1750 and today What physical attributes are needed for success in basketball? A) minimal levels of leg strengthB) high levels of aerobic fitness C) high levels of body fat what radio station plays christmas music right now HELP!!!!!!!!!!!!!!! i need it today, if i do not get it submitted today i will be kicked out of the course!!!!!!!!!!!!!!!!!What set of transformations is performed on ABCD to form A'B'C'D'?A. A 90-degree counterclockwise rotation about the origin followed by a translation 1 unit to the leftB. A translation 1 unit to the left followed by a 90-degree counterclockwise rotation about the originC. A 270-degree counterclockwise rotation about the origin followed by a translation 1 unit to the leftD. A translation 1 unit to the left followed by a 270-degree counterclockwise rotation about the origin PLS HELP. Essay. How do you think the first cell came into existence? Write one paragraph stating your opinion. It must be a creative idea on how you might think it came to exist. Please dont steal points with a wrong answer. Its literally all i have. Syyshshdhehqvswwpwurxwittau What did the Townshend Acts of 1767 declare? That independence was the only way for the colonists to earn their freedom. That the colonists would pay taxes. That the colonies were under the control of the English government. That the colonists needed to move back to England.. Consider the following scenario. The police believe you have stolen items and hidden them in your house. They decide to raid your house to see if any of the stolen items are there. What right could you invoke to protect yourself from this raid?A. the Ninth Amendment B. the First Amendment C. the Third Amendment D. the Fourth Amendment