A rectangle has an area of 96cm2 it's length is 4cm longer than it's width. Calculate the length and width.

Answer:

After 121 passes, there will be 11 cups facing up

Step-by-step explanation:

Given that:

Peter initially  lines up 121 cups facing down in a straight line from left to right and consecutively labels them from 1 to 121.

We can have an inequality ; i.e 1 ≤ n ≤  121; if n represents the divisor including n itself for which n  = odd number. Thus at the end of this claim, the cup will be facing up.

On the ith pass, he flips over cups i, 2i, 3i, 4i,.... (By "flip," we mean changing the cup from face down to face up or vice versa.)

For each divisor on the ith pass of n;

[tex]i \ th \ pass \ = \ n \ \to \ p |n[/tex]  since we are dealing with possibility of having an odds number:

Thus; [tex]p =i[/tex] and [tex]i^2 = n[/tex]  where ; n = perfect square.

Thus ; we will realize that between 1 to 121 ; there exist 11 perfect squares. Therefore; as a result of that ; 11 cups will definitely be facing up after 121 passes

Answer:

3.75 feet

Step-by-step explanation:

The length of the frame is 3 times the width.

Let the width be x.

The length will be 3x.

Kyle uses 10 feet of wood to make the frame. This means that the perimeter is 10 feet.

The perimeter of a rectangle is:

P = 2(L + W)

=> 10 = 2(3x + x)

=> 10/2 = 4x

5 = 4x

=> x = 5/4 = 1.25 feet

The width is 1.25 feet. The length is therefore:

1.25 * 3 = 3.75 feet

Answer:C

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

Source: Dude trust me

Answer:

[tex]7x+1+6x+101=180\\13x=78\\x=6[/tex]

Answer:

  14

Step-by-step explanation:

There are 7 elements in each set, and no elements are shared. The number of elements in the union of the sets is then ...

  n(A∪B) = 7+7 = 14

Answer:

x = 15, AOB = 15, BOC = 165

Step-by-step explanation:

Assume that this is a straight line

2x - 15 + 11x = 180

Combine like terms

13x - 15 = 180

Add 15 on both sides

13x = 195

Divide 13 on both sides

x = 15

Substitute x for 15 in both equations

2(15) - 15 = 15

11(15) = 165

(For checking purposes, 165 + 15 = 180)

Answer:

You can do this two ways

1. Divide 170 into 4 parts and multiply by 3.

170/4=42.5

42.5 x 3 = 127.5 so 127.5 is the answer

2. 3/4=0.75

170 x 0.75 = 127.5

or 170/1 x 3/4 = 510/4 = 127 1/2

127 1/2 = 127.5 because 1 divided by 2 is 0.5__127 + 0.5 = 127.5

Hope this helps

Step-by-step explanation:

Answer:

1096750 impressions

Step-by-step explanation:

Given that :

Mean = 850,000

Standard deviation = 150,000

If we assume that X should be the numbers of impressions created;

Then ;

[tex]X \approx N (\mu , \sigma^2)[/tex]

Now ; representing x as the value for the number of impression needed ; Then ;

[tex]P(X>x) = 0.95[/tex]

[tex]P(\dfrac{X- \mu}{\sigma} > \dfrac{x -850000}{150000}) = 0.95[/tex]

[tex]P(Z> \dfrac{ x -850000}{150000}) = 0.95[/tex]

From normal tables:

[tex]P(Z >1.645) = 0.95[/tex]

[tex]\dfrac{x - 850000}{150000} =1.645[/tex]

(x- 850000) = 1.645(150000)

x - 850000 = 246750

x = 246750 + 850000

x = 1096750 impressions

Answer: Thr amount spent to manufacture each radio.

Step-by-step explanation: I put two and two together...lol...plz brainlest.

Answer:

The amount spent to manufacture each radio.

Step-by-step explanation:

125 is the start up cost and each radio costs 5.25 to make.

Answer:

Option(B) is the correct answer to the given question.

Step by Step Explanation

We know that

[tex]A\ =\ P \ *(\ 1+\ \frac{r}{n} \ ) ^{nt}[/tex]

Here A=amount

r=15.98%=0.1598

n=365

t=1

Putting these values into the equation

[tex]A\ =\ P \ *(\ 1+\ \frac{0.1598}{365} \ ) ^{365}[/tex]

[tex]A\ =\ P \ *(\ 1+\ 0.000437) ^\ { 365}[/tex]

[tex]A\ =\ P \ *(\ 1.000437 ) ^{365}[/tex]

[tex]A\ =1.17288 P[/tex]

Now we find the interest

I=[tex]1.17288P\ -P\\=\ 0.17288P\\\ ~ 0.1720P[/tex]

Therefore effective interest rate of the last year can be determined by

[tex]\frac{0.1720P}{P}[/tex]

=0.1720 *100

=17.20%

Answer:

17.32%

Step-by-step explanation:

Answer:

  (0, 3/2)

Step-by-step explanation:

The equation can be put in the form ...

  x^2 = 4py

where p = 3/2.

In this form, the focus is distance "p" from the vertex in the direction the parabola opens.

The vertex is at (0, 0); the parabola opens upward. So, the focus is 3/2 units above the vertex, at ...

  focus = (0, 3/2) . . . . . matches choice A

Complete question is:

Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

Answer:

Probability = 0.0277

Step-by-step explanation:

We are given;

Mean: μ = 32

Standard deviation;σ = 7

Random sample number; n = 34

To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.

Thus;

z = (29.7 - 32)/(7/√34)

Thus, z = -2.3/1.200490096

z = -1.9159

From the standard z table and confirming with z-calculator, the probability is 0.0277

Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the proportion of "X: gloves fitness, categorized: Fit poorly and Fit well" is the same for two populations of interest, "male firefighters" and "female firefighters"

To do this you have to conduct a Chi-Square test of Homogeneity.

In the null hypothesis you have to state that the proportion of the  categories of the variable are the same for all the populations of interest.

Be

M: the firefighter is male

F: the firefighter is female

Y: represents the category that the gloves "fit poorly"

W: represents the category that the gloves "fit well"

The null hypothesis will be:

H₀: P(Y|M)=P(Y|F)=P(Y)

P(W|M)=P(W|F)=P(W)

H₁: At least one of the statements in the null hypothesis is false.

α: 0.01

To calculate the statistic under the null hypothesis you have to calculate the expected frequencies first:

[tex]E_{ij}= O_{.j}*\frac{O_{i.}}{n}[/tex]

O.j= total of the j-column

Oi.= total of the i-row

n= total of observations

[tex]E_{11}= 547*\frac{152}{586} = 141.88[/tex]

[tex]E_{12}=39*\frac{152}{586}= 10.12[/tex]

[tex]E_{21}= 547*\frac{434}{586} = 405.12[/tex]

[tex]E_{22}= 39*\frac{434}{586} = 28.88[/tex]

[tex]X^2= sum \frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~~X^2_{(r-1)(c-1)}[/tex]

r= number of rows (in this case 2)

c=number of columns (in this case 2)

[tex]X^2_{H_0}= \frac{(132-141.88)^2}{141.88} +\frac{(20-10.12)^2}{10.12} +\frac{(415-405.12)^2}{405.12} +\frac{(19-28.88)^2}{28.88} = 13.95[/tex]

Using the critical value approach, you have to remember that this test is always one-tailed to the right, meaning that you'll have only one critical value from which the rejection region is defined:

[tex]X^2_{(r-1)(c-1);1-\alpha }= X^2_{1;0.99}= 6.635[/tex]

The decision rule is then:

If [tex]X^2_{H_0}[/tex] ≥ 6.635, reject the null hypothesis.

If [tex]X^2_{H_0}[/tex] < 6.635, do not reject the null hypothesis.

The calculated value is greater than the critical value, the decision is to reject the null hypothesis.

So at a 1% level you can conclude that this test is significant. This means that the proportions of gloves fitness, categorized in "Fit poorly" and "Fit well" are different for the male and female firefighters populations.

I hope this helps!

Answer:

The Chi - Square Test Statistics is  13.98

p-value = 0.0002

CONCLUSION: Since the p-value is less than the level of significance ; (i.e p-value < ∝) we reject the null hypothesis and accept the alternative hypothesis.

Thus; there is a difference in the population proportion of glove fitness for the two genders.

Step-by-step explanation:

From the information given ; the structure of the table can be well represented as follows;

Observed data                  Males                    Females             Total

Gloves fit poorly                132                         20                       152

Gloves fit well                    415                         19                        434

Total                                   547                        39                       586

Expected data                  Males                   Females              Total

Gloves fit poorly

Gloves fit well

Total

The objective of this question is to  use the chi-square test to determine if there is a difference in the population proportion of glove fitness for the two genders.

We call represent the hypothesis as follows:

The null hypothesis: [tex]H_o:[/tex] states that there is no difference  in the population proportion of glove fitness for the two genders.

The alternative hypothesis: [tex]H_a[/tex] states that there is difference  in the population proportion of glove fitness for the two genders.

The expected frequency of a particular cell can be calculated by multiplying the sum of the rows and columns together, then dividing it by the Total sum

For row 1 column 1 (gloves fit poorly (male) ; we have:

[tex]= \dfrac{547*152}{586} =141.884\\[/tex]

For row 2 column 1 (gloves fit well(male) ; we have:

[tex]= \dfrac{547*434}{586} =405.116[/tex]

For row 1 column 2 (gloves fit poorly (female)) ; we have:

[tex]= \dfrac{39*152}{586} =10.116[/tex]

For row 2 column 2 ( gloves fit well ( female ) ; we have:

[tex]= \dfrac{39*434}{586} =28.884[/tex]

Thus; we can have the complete table to now be:

Observed data                  Males                    Females             Total

Gloves fit poorly                132                         20                       152

Gloves fit well                    415                         19                        434

Total                                   547                        39                       586

Expected data                  Males                   Females              Total

Gloves fit poorly                141.884                 10.116                  152

Gloves fit well                    405.116                28.884                 434

Total                                    547                        39                     586

The Chi - Square Test Statistics can be calculated via the formula:

[tex]X^2 = \dfrac{\sum (f_o-f_e)^2}{f_e}[/tex]

where;

[tex]f_o[/tex] = observed data frequency

[tex]f_e[/tex] = expected data frequency

∴

The Chi - Square Test Statistics is as follows:

[tex]=\dfrac{(131-141.884)^2}{141.884} + \dfrac{(20-10.116)^2}{10.116}+ \dfrac{(415-405.116)^2}{405.116}+ \dfrac{(39-28.884)^2}{28.884}[/tex]

= 0.68+9.6+0.2+3.5

= 13.98

We are given the level of significance ∝  to be = 0.01

numbers of rows = 2; number of column = 2

Thus; the degree of freedom = (2-1)(2-1) = 1×1 = 1

Using the Excel Function : [ = CHISQ.DIST.RT²(X²,df)]

p-value = 0.0002

CONCLUSION: Since the p-value is less than the level of significance ; (i.e p-value < ∝) we reject the null hypothesis and accept the alternative hypothesis.

Thus; there is a difference in the population proportion of glove fitness for the two genders.

Answer:

[tex]h=\sqrt{1.44}\\h = 1.2[/tex]

Step-by-step explanation:

Base of the triangle on the left = 0.5

Use pythagorean theorem

[tex]a^{2} + b^{2} = c^{2}[/tex]

Substitute

[tex]0.5^{2} + b^{2} = 1.3^{2}[/tex]

[tex]b^{2} = 1.3^2 - 0.5^2[/tex]

[tex]b^2 = 1.44[/tex]

[tex]b = \sqrt{1.44} \\[/tex]

[tex]b = 1.2[/tex]

in this case b is the height

so

[tex]h=\sqrt{1.44}\\h = 1.2[/tex]

Answer:

The correct option is (d).

Step-by-step explanation:

The complete question is:

The random variable x represents the number of computers that families have along with the corresponding probabilities. Use the probability distribution table below to find the mean and standard deviation for the random variable x.

    x :    0          1          2           3         4

p (x) : 0.49     0.05    0.32     0.07    0.07

(a) The mean is 1.39 The standard deviation is 0.80

(b) The mean is 1.39 The standard deviation is 0.64

(c)The mean is 1.18 The standard deviation is 0.64

(d) The mean is 1.18 The standard deviation is 1.30

Solution:

The formula to compute the mean is:

[tex]\text{Mean}=\sum x\cdot p(x)[/tex]

Compute the mean as follows:

[tex]\text{Mean}=\sum x\cdot p(x)[/tex]

         [tex]=(0\times 0.49)+(1\times 0.05)+(2\times 0.32)+(3\times 0.07)+(4\times 0.07)\\\\=0+0.05+0.64+0.21+0.28\\\\=1.18[/tex]

The mean of the random variable x is 1.18.

The formula to compute variance is:

[tex]\text{Variance}=E(X^{2})-[E(X)]^{2}[/tex]

Compute the value of E (X²) as follows:

[tex]E(X^{2})=\sum x^{2}\cdot p(x)[/tex]

          [tex]=(0^{2}\times 0.49)+(1^{2}\times 0.05)+(2^{2}\times 0.32)+(3^{2}\times 0.07)+(4^{2}\times 0.07)\\\\=0+0.05+1.28+0.63+1.12\\\\=3.08[/tex]

Compute the variance as follows:

[tex]\text{Variance}=E(X^{2})-[E(X)]^{2}[/tex]

             [tex]=3.08-(1.18)^{2}\\\\=1.6876[/tex]

Then the standard deviation is:

[tex]\text{Standard deviation}=\sqrt{\text{Variance}}[/tex]

                              [tex]=\sqrt{1.6876}\\\\=1.2990766\\\\\approx 1.30[/tex]

Thus, the mean and standard deviation for the random variable x are 1.18 and 1.30 respectively.

The correct option is (d).

Answer:

B: It takes too much time

Step-by-step explanation:

Once the points have been calculated and then graphed, the solutions to y = 0 can be found. Look for y = 0 and the solutions are -5 and -1. But that takes a lot of time. There must be an easier way, and fortunately, there is.

Answer:  24 square units

Explanation: The diagonals are 4+4 = 8 and 3+3 = 6 units long. Multiply the diagonals to get 8*6 = 48. Then divide this in half to get 48/2 = 24.

An alternative is to find the area of one smallest triangle, and then multiply that by 4 to get the total area of the rhombus. You should find the area of one smallest triangle to be 0.5*base*height = 0.5*4*3 = 6, which quadruples to 24.

Answer:

11

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Since the diagonals of a parallelogram bisect each other, the two halves must be equal. Therefore:

[tex]15-x=2x \\\\15=3x \\\\x=5[/tex]

Hope this helps!

Answer:

[tex]x=5[/tex]

Step-by-step explanation:

CE = EB since E is the midpoint of CB (proven by AD intersecting it).

If CE=EB, then:

[tex]2x=15-x\\[/tex]

Add [tex]x[/tex] to both sides

[tex]3x=15\\[/tex]

Divide both sides by 3

[tex]x=5[/tex]

Answer:

2,808

Step-by-step explanation:

since 117 = d then we would just plug that into the equation of s = 24d and get s = 24(117), after that you would just solve.

Answer:

53

Step-by-step explanation:

Answer:

The answer is 0

Step-by-step explanation:

Answer:

The correct answer will be "0.400 gm".

Step-by-step explanation:

The give values are:

Needs of hospital, N = 0.100 gm

Time, t = 10 days

Minimum amount of Xenon, N₀ = ?

As we know,

⇒  [tex]N(t)=N_{0} \ e^{-\lambda t}[/tex]

∴  Decay constant, λ = [tex]\frac{ln2}{t_{1/2}}[/tex]

                                λ = [tex]\frac{ln2}{5}[/tex]

On putting values, we get

⇒  [tex]0.100=N_{0} \ e^{-\frac{ln2}{5}}\times 10[/tex]

⇒  [tex]0.1=N_{0} \ e^{-2ln2} = N_{0} \ e^{-ln4}[/tex]

⇒  [tex]0.1=N_{0} \ e^{ln\frac{1}{4}}[/tex]

⇒  [tex]0.1=\frac{N_{0}}{4}[/tex]

⇒  [tex]N_{0}=0.1\times 4[/tex]

⇒  [tex]MX_{e}=0.400 \ gm[/tex]

Answer:

  (0, ∞)

Step-by-step explanation:

A good place to start is by visualizing what the graph looks like on a number line.

For x > 0, it is an open circle at x=0, and shading to the right extending to infinity.

__

So, the left end of the interval is 0, but 0 is not included in the interval.

The right end of the interval is infinity, but there is no such number, so "infinity" is not included in the interval.

"Not included" means you use round brackets ( ) for the corresponding end of the interval. ("Included" would mean you use square brackets [ ].)

So, the interval 0 < x < ∞ is written in interval notation as ...

  (0, ∞)

Answer:

126 in²

Dude just trust me

"we dont gaf abt no bii, we dont giveeaf abt no bii and if i was you i wouldnt kiss her on the lips"

Answer:

[tex]\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}[/tex]

And simplifying we got:

[tex] a^3 b^2 a b^3[/tex]

[tex] a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5[/tex]

Step-by-step explanation:

We want to simplify the following expression:

[tex] \frac{a^3 b^2}{a^{-1} b^{-3}}[/tex]

And we can rewrite this expression using this property for any number a:

[tex] a^{-1}= \frac{1}{a}[/tex]

And using this property we have:

[tex]\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}[/tex]

And simplifying we got:

[tex] a^3 b^2 a b^3[/tex]

[tex] a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5[/tex]

Answer:

The probability of spinning a 3 out of the 6 options is 1/6.

Answer: 1/6

Step-by-step explanation:

Im assuming the p stands for probability. There is a total of 6 slices, the 3rd slice takes up 1/6th of the circle

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

A.

The function will follow multinomial distribution:

[tex]f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})[/tex]

Substitute the values and make a table.

TABLE IN ATTACHMENT

B.

We calculate marginal distribution by:

[tex]P (X=x)=[/tex] ∑ [tex]P(X=x,Y=y)[/tex]

[tex]fx(x)[/tex] can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

The mathematic expectation E is the sum of product of each possibility with its probabiity.

[tex]E(X)=[/tex]∑ [tex]xP(X=x)[/tex]

Find E(X):

[tex]E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)[/tex]

[tex]E(X)=0.06[/tex]

Condition probability states:

[tex]P(A|B)=\frac{P(A,B)}{P(B)}[/tex]

It can also be written as:

[tex]f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}[/tex]

Where [tex]f_x(1)\\[/tex] = 0.057624

Calculate the quotient:

[tex]Y|_{x=1}[/tex] = 0 ,  [tex]f_{Y|_X=1[/tex] = 0.862245

[tex]Y|_{x=1}[/tex] = 1 ,  [tex]f_{Y|_X=1[/tex] = 0.132653

[tex]Y|_{x=1}[/tex] = 2 ,  [tex]f_{Y|_X=1[/tex] = 0.000510

[tex]Y|_{x=1}[/tex] = 3 ,  [tex]f_{Y|_X=1[/tex] = 0

Find the dependency:

[tex]f_{XY}(y)=f_X(x)f_Y(y)[/tex]

We found that

[tex]f_{Y|_X=1[/tex] = 0.862245

Calculate [tex]f_Y(1)[/tex] from summing the column from the table

[tex]f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141[/tex]

Which are not equal.

Conclusion:

X and Y are NOT Independent