Answer:
Explanation:
Solution
In physics, a period is a measurement of time. The answer must be either B or C. It is a direct measurement of time, not its reciprocal. So the answer is B. A and D is a measurement of the actual cycle that it takes before the motion begins to repeat itself.
Answer
B
A metallic spoon is placed in a hot cup of coffee. If the coffee gives away 190 calories to the spoon to cool down by 0.75°C, what is the mass of the coffee? (Assume that ccoffee = 1.0 cal/gC°.)
Taking into account the definition of calorimetry, the mass of the coffee is 253.33 g.
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.c is the specific heat sudstance.ΔT is the temperature variation.Mass of coffeeIn this case, you know:
Q= 190 caloriesc= 1 [tex]\frac{cal}{gC}[/tex]m= ?ΔT= 0.75 CReplacing in the equation that allows to calculate heat exchanges is:
190 cal = 1 [tex]\frac{cal}{gC}[/tex]× m× 0.75 C
Solving:
m= 190 cal÷ (1 [tex]\frac{cal}{gC}[/tex]× 0.75 C)
m=253.33 g
Finally, the mass of the coffee is 253.33 g.
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A periodic wave has a wavelength of 0,50 m and a speed of 20 m/s, What is the wave frequency?
Answer:
u=speed, w=wavelenght, f=frequency
It's known that u=w*f => f=u/w
u=20m/s ==> f=20/0,5 => f=40 Hz
w=0,50m
Explanation:
Identify the law, write the equation and calculate the answer to the problem below.
An incident light ray strikes water at an angle of 45 degrees. The index of refraction of air is 1.0003, and the index of refraction of water is 1.33. What is the angle of refraction rounded to the nearest whole number?
Find refractive index first
[tex]\\ \rm\Rrightarrow \mu=\dfrac{c}{v}[/tex]
[tex]\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}[/tex]
[tex]\\ \rm\Rrightarrow \mu =0.75[/tex]
Now
[tex]\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr[/tex]
[tex]\\ \rm\Rrightarrow sinr=0.94[/tex]
[tex]\\ \rm\Rrightarrow r=sin^{-1}(0.94)[/tex]
[tex]\\ \rm\Rrightarrow r=70^{\circ}[/tex]
There are several ways to model a compound one type of model is shown what is the chemical formula for the molecule modeled
what is the radius of the 5th orbital in hydrogen?
Answer: 1.32 x 10^-9 m
Explanation:
The formula for the radius of nth orbital is:
[tex]r_{n}=\frac{n^{2}}{Z} \times 0.528 \text { Angstorms }[/tex]
For hydrogen, Z= 1, so we have:
[tex]$$\begin{aligned}r_{n} &=5^{2} \times 0.528 \text { Angstorm } \\&=13.2 \text { Angstorms } \\&=13.2 \times 10^{-10} \mathrm{~m} \\&=1.32 \times 10^{-9} \mathrm{~m}\end{aligned}$$[/tex]
Answer: 1.32*10^-9
Explanation: I had the same question and here's what I got:
rn = n2(r1)
n = 5
r = 5.29*10^-11
rn = n^2(r1)
= 5^2(5.29*10^-11)
r = 1.32*10^-9
If the atmospheric pressure is 15 lb/in, what is the corresponding downward force on the top of a horizontal square area 5 inches on each side ?
The corresponding downward force on the top of a horizontal square is 375 lb.in
What is pressure?The pressure is the amount of force applied per unit area. It is represented as
Pressure p = Force/Area
If the atmospheric pressure is 15 lb/in and area 5 inches on each side is
A = 5² = 25 in²
The force applied is
15 lb/in = F /25 in²
F = 375 lb.in
Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in
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an object is 27.0 cm from a concave mirror of focal length 15.0 cm. find the image distance.
The distance of the Image will be -33.75 cm
A concave mirror has an inward-curving reflecting surface that faces away from the light source. Unlike convex mirrors, a concave mirror's image forms a variety of images based on the object's proximity to the mirror.
Given that, an object placed 27 cm from a concave mirror having the focal length of 15 cm
We have to find distance of the Image
Using Mirror Formula:
1/f = 1/v + 1/u
Where,
f = focal length
v = Image distance from the mirror
u = object distance from the mirror (concave)
Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.
1/(-15) = 1/v + 1/(-27)
1/(-15) = 1/v - (1/27)
1/v = -0.029
v = -33.75 cm
Therefore the distance of the Image will be -33.75 cm
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An upward force is applied to a 6.0–kilogram box. This force displaces the box upward by 10.00 meters. What is the work done by the force on the box?
Answer:
588J
Explanation:
Work done = Fd
=wh=mgh
=6×9.8×10
=558J
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule. What force will result in stretching the spring 10.0 centimeters?
The force result in stretching the spring 10.0 centimeters is 2.5N.
What is Hooke's law?If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.
F = kx
where k is the proportionality constant called the spring constant or force constant.
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.
Let the spring constant be very low 0.04N/m
The force applied is
F = 10 cm / 0.04
F = 0.1 m / 0.04
F = 2.5 N
Thus, the force result in stretching the spring 10cm is 2.5 N.
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Answer: 2.5 newtons
source- trust me bro
In the following word completion task: carrot, peas, corn, b_____, most people would answer “beans” (instead of “beetle” for example) even though there were no instructions on how to do this task. The psychological reason we made the assumption that the blank word was related to the previous words is due to
Answer:
Explanation:
Wow, I said 'beets'..... I must be weird.
Any Acellus folk figure out the answer to this one??? I CANNOT for the life of me.
What is the angular velocity of the minute hand of a clock?
[?] rad/s
Hint: It travels clockwise and takes 60 minutes to make one revolution.
(not 1.25, 1.7, 1800, 30, 60, 0.1047)
Answer:
-0.10472[tex]\frac{rad}{s}[/tex]
Explanation:
Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.
The formula for period is:
[tex]T = \dfrac{2\pi}{\omega}[/tex]
Solve for [tex]\omega\\[/tex] and you get:
[tex]\omega=\dfrac{2\pi}{T}[/tex]
The period is 60 seconds so make that division and you're left with -0.10472[tex]\frac{rad}{s}[/tex] or -0.10[tex]\frac{rad}{s}[/tex] if significant figures apply (negative because the rotation is clockwise).
Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope at a constant speed, as shown in the Figure. The coefficient of kinetic friction between the sled and snow is 0.100.
a) How much work, in joules, is done by friction as the sled moved 28 m along the hill?
b) How much work, in joules, is done by the rope on the sled this distance?
c) What is the work, in joules done by the gravitational force on the sled?
d) What is the net work done on the sled, in joules?
a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.
b.21,835 J work, in joules, is done by the rope on the sled this distance.
c. 23,170 J the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.
What is friction work?
The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement
a. How much work is done by friction as the sled moves 28m along the hill?
ans. We use the formula:
friction work = -µ.mg.dcosθ
= -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60
= -1337.3 J
-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.
b. How much work is done by the rope on the sled in this distance?
We use the formula:
Rope work = -m.g.d(sinθ - µcosθ)
rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)
= 26,754 (0.816)
= 21,835 J
21,835 J work, in joules, is done by the rope on the sled this distance.
c. What is the work done by the gravitational force on the sled?
By using the formula:
Gravity work = mgdsinθ
= 97.5 kg * 9.8 m/s² * 28 m * sin 60
= 23,170 J
23,170 J the work, in joules done by the gravitational force on the sled .
D. What is the total work done?
By adding all the values
work done = -1337.3 + 21,835 + 23,170
= 43,670 J
The net work done on the sled, in joules is 43,670 J.
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A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period of the motion
Answer:
Explanation:
The amplitude is extraneous information for this question.
Period (T) is simply a measure of time (how long it takes to complete a full cycle).
The frequency (f), is the reciprocal (how many cycles it can complete per unit of time).
The frequency reported is 12Hz. Hz is a unit meaning "cycles per second"
Thus 12cycles = 1second.
To find the number of seconds per cycle, simply create the other unit fraction and simplify:
[tex]T=\frac{1second}{12cycles}\\T=0.8\bar{3}\frac{seconds}{cycle}\\[/tex]
[tex]T=0.83seconds[/tex]
What does Charles Darwin’s theory of natural selection state about traits?
A.
Traits that increase the survival rate of a population are rarely passed on to future generations since they can affect reproduction.
B.
Traits that prevent people from reproducing are passed on to future generations to ensure their survival.
C.
Traits that make it more likely for a species to survive or reproduce become less common in a population over time.
D.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations.
Charles Darwin's theory of natural selection states that features that offer survival or reproductive advantage are more likely to be handed down to subsequent generations.
What are traits?A trait is a distinctive pattern of behavior or conscious motivation that may be evaluated by peers or oneself.
Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations is Charles Darwin’s theory of natural selection state traits.
Hence option D is correct.
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Answer: option d
Explanation:
A spoon inserted in a half-filled cup of water appears crooked because as light travels into a substance with a lower index of refraction, it... Select one: a. does not bend. b. bends away from the normal. c. bends toward the normal. d. is reflected.
Explanation:
The light is bent away from the normal
use ideas of electromagnetic induction to explain how the input voltage is transformed into an output voltage
With the help of a transformer input voltage is transformed into an output voltage
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Hence with the help of a transformer input voltage is transformed into an output voltage.
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Gravity will have a greater effect on an object with?
A model rocket with a mass of 5 kg has a downward thrust of 100 newtons. Assuming there are no other forces acting on the rocket, what is the rocket’s acceleration upward?
a. 20 m/s2
b. 100 m/s2
c. 5 m/s2
d. 105 m/s2
Answer:
A
Explanation:
F = m * a
100 = 5 * a
a = 100/5 = 20 m/s^2
The position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively. Find the unit vector along r(t)
The unit vector along r(t) will be 3t–4t^2+2
A vector is a quantity with direction and magnitude that is especially useful for locating one location in space in relation to another. A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields weight are a few examples of vectors in nature.
Given the the position of particle as a function of particle of time is given by: r(t)=3tî–4t^2j+2k. Where î & j are unit vector along the x-axis and y-axis respectively.
We have to find the unit vector along r(t)
To find the unit vector along r(t) we have to put the value of (i,j,k) = (1,1,1) in r(t)
So,
r(t) = 3tî–4t^2j+2k
r(t) = 3t(1)–4t^2(1)+2(1)
r(t) = 3t–4t^2+2
Therefore the unit vector along r(t) will be 3t–4t^2+2
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Proofread the following text and correct the 3 subject-verb disagreements.
Astronomers are telling people to be especially watchful this evening, as a rare event could be making a very special appearance. The release of energised particles from the sun , coupled with particularly helpful overnight conditions , are predicted to make the "Northern Lights" visible much further south than normal.
Interviewed earlier today, Derwent University's Professor Andrew Higgins said, 'Everybody are talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'
He added: 'The forecasts given out by the weather office enables us to know when the skies will be clear. Either 11pm or 3am will be best, and I'll be over the moon if we get some good photos.'
(a) From the first sentence, particularly goes with condition.
(b) From the second sentence, everybody goes with is.
(c) From the third sentence, forecasts goes with enable.
What is subject verb agreement?In subject- verb agreement, if a subject is singular, its verb must also be singular and if a subject is plural, its verb must also be plural.
From the first sentence, the correct subject-verb agreement is;
The release of energised particles from the sun , coupled with particularly helpful overnight condition, are predicted to make the "Northern Lights" visible much further south than normal.
From the second sentence, the correct subject-verb agreement is;
'Everybody is talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'
From the third sentence, the correct subject-verb agreement is;
'The forecasts given out by the weather office enable us to know when the skies will be clear.
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During a diversity management session, a manager suggests that stereotypes are a necessary part of working with others. “I have to make assumptions about what’s in the other person’s head, and stereotypes help me do that,” she explains. “It’s better to rely on stereotypes than to enter a working relationship with someone from another culture without any idea of what they believe in!” Discuss the merits of and problems with the manager’s statement.
The merits of and problems with the manager’s statement are explained below.
What is stereo typing in organizations?Extension of the social identity of the individual in groups such as working in company or studying in college is called as the stereotyping in organizations.
Merits of Stereotypes in organizations:
It relies on categorical thinkingHelps understand outside world easily'unique characteristics are difficult to recall every time.groups are identified easilyhelps filling the gaps while talking of some new culture.helps enhancing self perception and social identity.Demerits of Stereotypes:
difficulty in understanding behavior of other individual in organizations.an individual may be sometimes under or over estimated.discourages social group while entering a profession.discriminatory behavior.not helps in describing with their talent.Thus, the merits and demerits of stereotypes in organizations are explained above.
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a generator uses loops of area 0.239 m^2, rotating 373 rad/s in a 0.0639 t magnetic field. how many loops must the coil have to generate a maximum emf of 2500 v?
The loops must the coil have to generate a maximum emf of 2500 will be 439.
What is the faraday law of electromagnetic induction?According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the flow of amount of current.
Given data;
Area,A = 0.239 m²
Angular velocity,ω=373 rad/sec
Magnetic field,B=0.0639 T
Maximum emf,E= 2500V
The formula for the maximum induced voltage is;
E{max} = N × B × A × ω
2500 = N × 0.639 × 0.0239 × 373
N = 438.66
N = 439 \ turns
Hence, loops must the coil have to generate a maximum emf of 2500 will be 439.
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Answer: 11392.99
Explanation: I had the same problem and here are the steps:
Values:
N (Number of loops) = 2000
A (area) = 0.239
ω (angular velocity) = 373
B (magnitude) = 0.0639
ε = NABω
= (2000)(0.239)(373)(0.0639)
ε = 11392.99 (FINAL ANSWER)
the 3kg object in figure is released from rest at height of on a curved frictionless ramp. at the foot of the ramp is a spring of force constant 400N/m. the object slides down the ramp and into the spring,compressing it a distance x before coming momentarily to rest.
a) find x
b) describe the motion of the object (if any) after the block momentarily comes to rest?
(a) The compression of the spring is 7.4 cm.
(b) When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
Compression of the spring [ x ]
The compression of the spring is calculated by applying Hooke's law as follows;
F = kx
x = F/k
x = (mg)/k
x = (3 x 9.8)/400
x = 0.074 m
x = 7.4 cm
When the object comes to rest its potential energy from the given height will be converted into elastic potential energy of the spring.
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Question 12 of 25
Two identical satellites circle the Earth in orbits. The distance between the
Earth and satellite B is twice the distance between the Earth and satellite A.
What is the relationship between the gravitational force acting on satellite A
(FA) and the force on B (FB)?
Earth
OA. FB = FA
OB. Cannot be determined
OC. FB< FA
OD. Fa> FA
Satellite A
Satellite B
Answer:
F = G M m / R^2 gravitational force on satellite of mass m
Fma / Fmb = (ma / Ra^2) \ (mb / Rb^2) = (ma / mb) * (Rb / Ra)^2
Fma / Fmb = 1 * 4 = 4
The force on A is 4 times the force on B
The velocity of the water jet discharging from the orifice can be obtained from v=\12ih, where h = 2 m is the depth of the orifice from the water surface. Determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits from surface.
(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.
(b) The horizontal distance x where it hits from surface is 3.94 m.
Time for the water to reach the surface
The time of the water to reach the surface is calculated as follows;
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
where;
t is time of motionh is height of the orificet = √( (2 x 2)/(9.8) )
t = 0.63 s
Horizontal distanceThe horizontal distance is calculated as follows;
X = vt
where;
v is the velocity of the water = √2ghX = (√2gh)t
X = (√2 x 9.8 x 2) x 0.63
X = 3.94 m
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The pressure of a gas (relative to vacuum) inside a rigid container at 0 °C is:
A) The same as at 25 °C.
B) Not zero, but somewhat less than it would be at 25 °C.
C) zero
The pressure of a gas inside a rigid container at 0 °C will not be zero, but will somewhat be less than it would be at 25 °C.
Temperature and pressure of gasesAccording to Charle's law of gases, the pressure of a gas is directly proportional to its temperature. This is based on the condition that the volume of the gas does not change.
Thus, for a gas inside a rigid container, the pressure at 0 °C may not be zero. However, the pressure will be less than it would be if the temperature were to be 25 °C.
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3. Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius
R₂. The two planets are a distance of L apart, measured from surface to
surface. An object is launched with some initial speed from the surface of
Planet 1 directly towards Planet 2. For this problem, assume that Planets
1 and 2 are stationary. (20 points)
(a) At what initial speed must the object be launched so that it reaches
the surface of Planet 2 with zero speed?
(b) Derive an inequality between M₁ and M₂ that represents when (a)
can occur.
(c) Show that, using your result in (b), if R₁ = R₂, then M₁ must be
greater than M₂.
(a) The initial speed must the object be launched so that it reaches
the surface of Planet 2 with zero speed is √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]
(b) An inequality between M₁ and M₂ that represents when (a)
can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0
(c) if R₁ = R₂, then M₁ must be greater than M₂ is proved.
What is gravity?The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.
The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.
F = GMm/R²
Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.
If v is the launch velocity, then initial total energy will be
T.E = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)
The final total energy will be
T.E =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)
From energy conservation principle, we get
1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)
v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]
(b) an inequality between M₁ and M₂ so that object reaches the surface of Planet 2 with zero speed is
[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0
{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0
Thus, this is an inequality between M₁ and M₂.
(c) If R₁ = R₂, then
{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0
M₁(R+L) + M₂R - M₁R -M₂(R+L) / R (R+L) ≥ 0
M₁(R+L) + M₂R - M₁R -M₂(R+L) ≥ 0
M₁L - M₂L ≥ 0
M₁ ≥ M₂
M₁ must be greater than M₂.
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Most of the bending of light in the eye is done at the air-cornea interface. By what angle (θcornea) is the beam of light shown in Figure deviated as it passes from air to the cornea if the incident angle is θi = 23.6°? The refractive index of air is nair = 1.00, the refractive index of the cornea is ncornea = 1.38. Explain why θcornea< θi?
The angle (θcornea) when light passes from air to cornea is 16.86°
What is Snell's law?It states that the ratio of sine of angle of incidence and angle of refraction is equal to the refractive index of second medium to the first medium.
sini/sinr =n₂ / n₁
Most of the bending of light in the eye is done at the air-cornea interface. The beam of light deviated as it passes from air to the cornea if the incident angle is θi = 23.6°.
Given the angle of incidence i = 23.6°, refractive index of air n₁ =1, refractive index of cornea n₂ = 1.38, then the angle of refraction at cornea is
sinr = sini x (n₁/n₂)
Plug the values, we get
sinr = sin23.6 x (1/1.38)
sinr = 16.86°
The angle of refraction is less than angle of incidence due to refraction.
Thus, the angle (θcornea) when light passes from air to cornea is 16.86°
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Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
The force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N
What is gravity?The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.
Given, a 1 kg box located at a point 1.3 × 10⁷ m from the center of Earth. The Earth has the acceleration due to gravity, g = 9.81 m/s².
Force of gravity F = GMm/R²
where G = gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg² and R is the distance between two masses.
The Mass of Earth M= 5.98 × 10²⁴ kg
Substituting the values, we get
F = (6.67 x 10⁻¹¹ N.m²/kg² x 1kg x 5.98 × 10²⁴ kg)/ ( 1.3 × 10⁷ m)²
F = 2.36 N
Therefore, the force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N
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A boat moves with a velocity of 15m/s, N in a river which flows with a velocity of 8.0m/s, Calculate the boat’s resultant velocity with respect to North
The boat’s resultant velocity with respect to North is determined as 17 m/s.
Resultant velocity of the boatThe boat’s resultant velocity with respect to North is calculated as follows;
R² = Va² + Vb²
where;
R is resultant velocityVa is velocity of boatVb is velocity of riverR = √(Va² + Vb²)
R = √(15² + 8²)
R = 17 m/s
Thus, the boat’s resultant velocity with respect to North is determined as 17 m/s.
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