[tex]{\underline{\green{\textsf{\textbf{ Answer : }}}}}[/tex]
➡ 0.96 pounds in a minute.
Which of the following is a practical example of gravity acting on an object.
A.) A leaf falls from a tree and floats to the ground.
B.) A diver jumps off a diving board and splashes into a pool below.
C.) A car speeds up as a traffic light turns green.
D.) Rain falls from the sky.
a ball of mass 0.5 kg is at point with initial speed 4 m/s at height 10. what is the total energy
Answer:
The total energy is 53 Joule
Explanation:
Mechanical Energy
The mechanical energy of an object of mass m, speed v, and at a height h is:
[tex]\displaystyle E = m.g.h+\frac{mv^2}{2}[/tex]
The ball has a mass of m=0.5 Kg, a speed v = 4 m/s, and at a height of h=10 m. Thus the total energy is:
[tex]\displaystyle E = 0.5\cdot 9.8\cdot 10+\frac{0.5\cdot 4^2}{2}[/tex]
E = 49 J + 4 J = 53 J
The total energy is 53 Joule
What does a switch in an electrical circuit do?
O A. It concentrates negative charges on one side of the circuit when it
is open.
B. It concentrates negative charges on one side of the circuit when it
is closed.
C. It allows electrons to flow from one part of the circuit to another
when it is open.
D. It allows electrons to flow from one part of the circuit to another
when it is closed.
Answer:
It allows electrons to flow from one part of the circuit to another
when it is closed.
Explanation:
hope this helps <3 !!
Answer: D
Explanation:
WHICH OF THE FOLLOWING IS
you need to attach a picture so I can answer it
Draw the resultant of each set of vectors. Indicate if you used the parallelogram or head-to-tail method.
Answer:
Explanation:
See attached file.
In a hot summer day, a spherical air bubble that has a volume of 1.20 cm3 is released at temperature 17.0 °C by a scuba diver 25.0 m below the surface of ocean. Calculate the radius of the spherical bubble when it reaches the surface at temperature 30 °C? Assume that the number of air molecules in the bubble remain the same (rhosalt water = 1.027 g/cm3 ).
Answer:
The radius of the bubble when it reaches the surface at 30 ºC is 1.015 centimeters.
Explanation:
Let suppose that air bubble behaves as ideal gas, whose equation of state is:
[tex]P\cdot V = n\cdot R_{u}\cdot T[/tex] (Eq. 1)
Where:
[tex]P[/tex] - Pressure of the bubble, measured in kilopascals.
[tex]V[/tex] - Volume of the bubble, measured in cubic meters.
[tex]n[/tex] - Molar amount of the bubble, measured in kilomoles.
[tex]T[/tex] - Temperature, measured in Kelvin.
[tex]R_{u}[/tex] - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.
Then, we eliminate the molar amount and the ideal gas constant by constructing the following relationship:
[tex]\frac{P_{A}\cdot V_{A}}{T_{A}} = \frac{P_{B}\cdot V_{B}}{T_{B}}[/tex] (Eq. 2)
Where:
[tex]P_{A}[/tex], [tex]P_{B}[/tex] - Pressure of the bubble at bottom and surface, measured in kilopascals.
[tex]V_{A}[/tex], [tex]V_{B}[/tex] - Volume of the bubble at bottom and surface, measured in cubic meters.
[tex]T_{A}[/tex], [tex]T_{B}[/tex] - Temperature of the bubble at bottom and surface, measured in Kelvin.
The pressure experimented by the bubble at bottom and surface are, respectively:
[tex]P_{A} = 101.325\,kPa+\left(1027\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{kg}{m^{3}} \right)\cdot (25\,m)\cdot \left(\frac{1}{1000}\,\frac{kPa}{Pa} \right)[/tex]
[tex]P_{A} = 353.120\,kPa[/tex]
[tex]P_{B} = 101.325\,kPa[/tex]
If we know that [tex]P_{A} = 353.120\,kPa[/tex], [tex]P_{B} = 101.325\,kPa[/tex], [tex]V_{A} = 1.20\times 10^{-6}\,m^{3}[/tex], [tex]T_{A} = 290.15\,K[/tex] and [tex]T_{B} = 303.15\,K[/tex], then the volume of the bubble at surface is:
[tex]\frac{(353.120\,kPa)\cdot (1.20\times 10^{-6}\,m^{3})}{290.15\,K} = \frac{(101.325\,kPa)\cdot V_{B}}{303.15\,K}[/tex]
[tex]1.460\times 10^{-6} = 0.334\cdot V_{B}[/tex]
[tex]V_{B} = 4.372\times 10^{-6}\,m^{3}[/tex]
[tex]V_{B} = 4.372\,cm^{3}[/tex]
And the volume of the air bubble is determined by this formula:
[tex]V_{B} = \frac{4\pi\cdot R^{3}}{3}[/tex] (Eq. 3)
Where [tex]R[/tex] is the radius of the air bubble, measured in centimeters.
If we know that [tex]V_{B} = 4.372\,cm^{3}[/tex], then the radius of the air bubble is:
[tex]4.372 = \frac{4\pi\cdot R^{3}}{3}[/tex]
[tex]R^{3} = 1.044[/tex]
[tex]R \approx 1.015\,cm[/tex]
The radius of the bubble when it reaches the surface at 30 ºC is 1.015 centimeters.
5) A forklift raises a box 1.2 m doing 7,000 J of work on it. What is the mass of the box?
Answer:
The answer is 5833.3 kgExplanation:
To find the mass of the box we use the formula
[tex]m = \frac{w}{d} \\ [/tex]
w is the workdone
d is the distance
From the question we have
[tex]m = \frac{7000}{1.2} \\ = 5833.3333...[/tex]
We have the final answer as
5833.3 kgHope this helps you
A 3.0 kg object moving 8.0 m/s in the positive x-direction has a one-dimensional elastic collision with an object of mass, M, initially at rest. After the collision the object of unknown mass has a velocity of 6.0 m/s in the positive x direction. What is M
Answer:
1kgExplanation:
According to law of conservation of momentum
m1u1+ m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are their initial velocities
v is their common velocity
Given
m1 = 3kg
m2 = M
u1 = 8m/s
u2 = 0m/s (object at rest)
v = 6.0m/s
Substitute and get M
3(8) + M(0) = (3+M)6
24 = 18+6M
24-18 = 6M
6 = 6M
M = 1kg
Hence the mass M is 1kg
Someone help me please I got it wrong idk why please help
Answer:
not enough avidence is the correct answer
A shell traveling with speed, v0 , exactly horizontally and due north explodes into two equal mass fragments. It is observed that just after the explosion one fragment is traveling vertically up with speed v0 . What is the velocity of the other fragment? Hint: Velocity has both magnitude and direction.
Answer:
yeah
Explanation:
yeah yeah yeah yeah
answer pls urgent pls
Answer:
[tex]\huge\boxed{\sf Hen's \ Egg}[/tex]
Explanation:
Seen with an unaided eye means that is visible to the naked eye.
So,
Hen's Egg can be seen with an unaided eye.
However, Red Blood Cells (RBCs) and Sperm cells need a microscope for them to be seen!
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807answer please urgent
Answer:
Explanation:
Potassium is the correct answer
Answer:
[tex]\huge\boxed{Potassium}[/tex]
Explanation:
Group I elements are called alkali metals and are soft but highly reactive (because they have only 1 electron in their outermost shell). Potassium is of Group I (Alkali metal) and is thus soft and highly reactive.
Magnesium and Calcium both are of Group II (Alkaline Earth Metals).
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807answer please urgent
Answer:
equal and unlike charges
Explanation:
Answer:
[tex]\huge\boxed{\sf Equal \ and \ unlike \ charges}[/tex]
Explanation:
When two bodies are rubs against each other, Charges of equal magnitude are induced in them. However, they are of equal magnitude but the charges are opposite and unlike.
For Example:
If we rub an iron rod with a cotton cloth, a positive charge will be induced in the iron rod and a negative charge will be induced in the cotton cloth. Note that the charges will be of equal magnitude.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
Let me know if you have any q's regarding this!
~AnonymousHelper1807How many energy levels does hydrogen have?
What becomes V if we use 2 resistors of 4W in parallel?
A. 2.66 V
B. 6 V
C. 12 V
D. 24 V
Explanation:
The question is incomplete. To get the voltage V across the resistors, we need to total current flowing in the circuit.
Let the current I = 6 A
According to ohms law, V = IRt
V is the total voltage
I is the total current
Rr is the total effective resistance
Since the 2 4ohms resistors are connected in parallel;
1/Rt = 1/4 + 1/4
1/Rt = 2/4
Cross multiply
2Rt = 4
Rt = 4/2
Rt = 2 ohms
Get the voltage V.
V = IRt
V = 6(2)
V = 12V
Hence the required voltage will be 12V
Note that the value of the current used was assumed. The same calculation can be employed for any value of the current
A 35 degree piece of metal is put into a container of 70 degree water.
Which of these things will happen to the temperature of on of the
objects.
O The temperature of the metal will decrease
O The temperature of the water will increase
O The temperature of the metal will increase
O The temperature of the water will stay the same
Answer:
The temp. of the metal will decrease
Explanation:
Hope this helps!
Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2 as F1 = 45 N 70degree And F2 = 75 N , 20 Degree (a) Find the magnitude and direction of the force that third person should exert to stop this cart. You can ignore the effects of friction. (b) If the third person exerts the force found in part (a), the cart accelerates at 200 m/S2 in the (+) x-direction. What is the weight of the cart
Answer:
I had to search the Figure on Google to solve this question.
a) The magnitude of the force F₃ is:
[tex] F_{3} = 87.47 N [/tex]
And the direction of F₃:
[tex] \alpha = 79.04 ^{\circ} [/tex] (with respect to the y-direction, in the third quadrant)
b) P = 4.22 N
Explanation:
I had to search the Figure on Google to solve this question.
a) We can find the force of the third person as follows:
[tex] \Sigma F_{x} = F_{1x} + F_{2x} + F_{3x} = 0 [/tex]
[tex] \Sigma F_{y} = F_{1y} - F_{2y} + F_{3y} = 0 [/tex]
So, in x-direction we have:
[tex] \Sigma F_{x} = 45 N*cos(70) + 75 N*cos(20) + F_{3x} = 0 [/tex]
[tex] F_{3x} = -85.87 N [/tex]
In y-direction we have:
[tex] \Sigma F_{y} = 45 N*sin(70) - 75 N*sin(20) + F_{3y} = 0 [/tex]
[tex] F_{3y} = -16.63 N [/tex]
The magnitude of the force F₃ is:
[tex] F_{3} = \sqrt{F_{3x}^{2} + F_{3y}^{2}} = \sqrt{(-85.87 N)^{2} + (-16.63 N)^{2}} = 87.47 N [/tex]
To find the direction of F₃ we need to calculate its angle with respect to the y-direction (in the third quadrant):
[tex] tan(\alpha) = \frac{|F_{3x}|}{|F_{3y}|} = \frac{85.87 N}{16.63 N} [/tex]
[tex] \alpha = 79.04 ^{\circ} [/tex]
b) If the third person exerts the force found in part (a) the car will stop, so the only way for the cart to accelerate at 200 m/s² is that the third person does not exert the force found in a.
To find the weight of the cart when it accelerates at 200 m/s², we need to consider: F₃ = 0.
First, we need to find the cart's mass. Since the car is moving in the x-direction we have:
[tex] \Sigma F_{x} = F_{1x} + F_{2x} = ma [/tex]
[tex] 45 N*cos(70) + 75 N*cos(20) = m*200 m/s^{2} [/tex]
[tex] m = \frac{45 N*cos(70) + 75 N*cos(20)}{200 m/s^{2}} = 0.43 kg [/tex]
Now, the weight of the cart is:
[tex] P = mg = 0.43 kg*9.81 m/s^{2} = 4.22 N [/tex]
I hope it helps you!
If a car is able to accelerate a 500kg truck at 50m/s^2 what is the force applied by the engine on the car? Please show work
Answer:
The answer is 25,000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 500 × 50
We have the final answer as
25,000 NHope this helps you
Answer:
Force applied by the engine on the car = 25 kN
Explanation:
Mass (m) = 500 kg
Acceleration (a) = 50 m/s²
The force (F) is equated to the product of the mass times the acceleration.
[tex] \boxed{ \bf{F = ma}}[/tex]
By substituting values, we get:
[tex] \longrightarrow [/tex] F = 500 × 50
[tex] \longrightarrow [/tex] F = 25000 N
[tex] \longrightarrow [/tex] F = 25 kN
Zookeepers carry a stretcher that holds a sleeping lion. The total mass of the stretcher and lion is 175 kg. The lion's forward acceleration is 2 m/s2. What is the force necessary to produce this acceleration?
Answer:
350 N
Explanation:
Newton's second law:
∑F = ma
∑F = (175 kg) (2 m/s²)
∑F = 350 N
Diana is exploring caves on her field trip. She enters a cave and shouts out aloud. She immediately hears the echo of her own voice. What is the most likely reason for the echo?
Answer:
the cave walls reflect sound waves
Explanation:
i did the study island
Add these measurements, using significant digit rules:
44.2+0.123=
Answer:
the answer is 44.323 hope this is usefil
Let’s say you have a cart of some mass and when pushed with 10N of force, the cart accelerates at 5.0 m/s/s. If you were to push the same cart with a 20N force:
a. The acceleration would increase
b. The acceleration would decrease
c. The acceleration would remain the same
Answer:
a. The acceleration would increase.
Explanation:
because we know that
F=ma
m= mass and a= acceleration
so Mass is same for the cart in any situation that's why only acceleration could increase.
Answer:
A
Explanation:
because when the cart is pushed at 10N it at 5.0 the when u increase the N it will keep on increasing...
What unit is used to measure energy when calculating specific heat capacity? Give the abbreviation, not the full name.
The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).
What unit is used to measure energy?The specific heat capacity should be determined in joules per kilogram degree-celsius ( J k g − 1 ∘ C − 1 ).
It is to be supplied for the substance with respect to mass and it increased the temperature.
Hence, The unit that should be used to measure energy when calculating specific heat capacity is Energy is in Joules ( J ).
Learn more about unit here: https://brainly.com/question/16660726
The unit used to measure energy when calculating specific heat capacity is the joule (J).
The joule (J), a unit used to quantify energy, is used to calculate specific heat capacity. In the International System of Units (SI), the joule serves as the default unit of energy.
It is described as the quantity of energy that is delivered when one newton of force is exerted across a one-meter distance.
Thus, the quantity of heat energy needed to increase the temperature of a particular substance by a specific amount is measured as specific heat capacity. J/kg°C, or joules per kilogramme per degree Celsius, is the unit of measurement.
For more details regarding specific heat, visit:
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What would happen if one of the four-stroke combustion cycle parts never worked?
Answer:
An internal-combustion engine goes through four strokes: intake, compression, combustion (power), and exhaust. As the piston moves during each stroke, it turns the crankshaft.
Answer:
The engine will not work causing no movement in the wheels .
Explanation:
Remember the four stroke combustion cycle powers the wheels and if one of these parts do not work, then the car will not move .
is power a vector quantity
Answer:
Power is a scalar quantity and has a unit,a magnitude(a numerical value) but no direction.
Explanation:
What kind of motion do you see when using scissors
Answer:
When we are using scissors, our hand makes an open and close motion.
Explanation:
When scientists make models of dynamic physical events, they will normally choose to have values that may change as time progresses. What are these values called?
boundary conditions
initial conditions
outputs
gravity
Answer:
1. Initial conditions
2. The speed of a character at the moment of contact
3. The hardness of the sidewalk where the mug landed
4. The location where potential energy is zero
5. Aerodynamic properties
Explanation:
100%
The values that may change over time in a model are called initial conditions.
Scientists use models to represent actual conditions. A model is always a representation of real life situations and are very useful for explanatory and predictive purposes.
When scientists make models of dynamic physical events, they will normally choose to have values that may change as time progresses. These values are called initial conditions.
Learn more: https://brainly.com/question/8646601
Suppose that 5 J of work is needed to stretch a spring from its natural length of 36 cm to a length of 45 cm.
Required:
a. How much work is needed to stretch the spring from 38 cm to 43 cm? (Round your answer to two decimal places.) J
b. How far beyond its natural length will a force of 45 N keep the spring stretched? (Round your answer one decimal place.
Answer:
2.78J
3.64cm
Explanation:
Natural length is 36 and stretches to 45. 5 J of work is needed
5 = 1/2k(0.45-0.36)²
5 = 1/2k(0.09)²
5 = 0.0081k/2
10 = 0.0081k
K = 1234.568
X1 = 0.38-0.36 = 0.02
X2 = 0.43-0.36 = 0.07
Work done
W = 1/2k(x2²-x1²)
W = 1/2(1234.568)(0.007²-0.02²)
W = 1234.568(0.0049-0.0004)/2
W = 2.78j
F = 45N
F = kx
X = f/k
= 45/1234.568
= 0.0364
= 3.64cm
The answer to A is 2.78j
The answer to b is 3.64cm
How many electrons are in the third energy level?
2
8
18
20
Answer:
B)8
Explanation:
In the first energy level you can have, at most, 2. Every energy level after that wants to have 8 electrons. Valence electrons I believe.
Hope this helps, have a nice day! (^-^)
What is the strongest bones in our body?
Answer:
the femur, or thigh bone
Answer:
The femur bone is the longest and strongest bone in the body.
Explanation:
