A particle moves along the x-axis so that its position at time t>0 is given by


X(t) = (t^2 - 9)/(3t^2 + 8)


A) show that the velocity of the particle at time this given by v(t) = 70t/(3t^2 + 8)^2


B) is the particle moving toward the origin or away from the originator time t = 2? Give a reason for your answer.


C) The acceleration of the particle is given by £(t). Write an expression for £(t), and find the value of £(2).


D) What position does the particle approach as t approaches infinity?

Answer:

43.96 cm

Step-by-step explanation:

Given

Radius ( r ) = 7 cm

To find : Circumference of Circle

Formula

Circumference of Circle = 2πr

Note

The Value of π = 3.14

Circumference of Circle

= 2πr

= 2 × 3.14 × 7

= 43.96 cm

Answer:

Not Rounded: 43.9822971503

Rounded: 44

Step-by-step explanation:

r= radius

2[tex]\pi[/tex]r

2[tex]\pi[/tex](7)

= 43.9822971503

Answer:

(8/√2)^2 = 64/2 = 32 square inches

The height of the trapezoid is 9 yards. Therefore, the correct answer is option b. 9 yd.

To find the height of the trapezoid with the given area and base lengths, we will use the formula for the area of a trapezoid:

Area = (1/2) * (base1 + base2) * height

Here, the area is given as 126 square yards, base1 is 17 yards, and base2 is 11 yards. We need to find the height.

1. Substitute the given values into the formula:

126 = (1/2) * (17 + 11) * height

2. Simplify the equation:

126 = (1/2) * 28 * height

3. To isolate the height, divide both sides by (1/2) * 28:

height = 126 / ((1/2) * 28)

4. Calculate the result:

height = 126 / 14

height = 9

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Step-by-step explanation:

First start with the graph of    y = | x|

  then shift it RIGHT one unit

         | x -1 |

  then shift it DOWN one unit

  y=   |x-1| -1

The equation of demand of candle sticks can be modeled by

y = 14 - 0.02x while the revenue function will be xy = 14x - 0.02x².

Here we are given the information that

200 candles are sold for $10 and,

250 candles are sold for $9

Let the Price be y while the Quantity sold be x

Hence, by one unit decrease in price P, the quantity sold is increased by 50 units.

Here the slope of the function will be

(10 - 9)/(200 - 250)

= - 1/50

= - 0,02

Now we will use the formula of the equation of a straight line

(y - y₁) = m(x - x₁)

where, m is the slope and x₁ , y₁ are some point on line

Hence we get

(y - 10) = -0.02(x - 200)

or, y - 10 = -0.02x + 4

or, y = 14 - 0.02x

The revenue function will be xy = 14x - 0.02x²

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Correct Question

A candlemaker prices one set of scented candles at $10 and sells an average of 200 sets each week. he finds that when he reduces the price by $1, he then sells 50 more candle sets each week. a function can be used to model the relationship between the candlemaker's weekly revenue, r(x), after one-dollar decrease in price. this situation can be modeled by the equation y =

Answer: 720

Step-by-step explanation: 1800 x 40%

Answer:

720 math books

Step-by-step explanation:

1800×40%= 720

there are 720 math books

a) The graph of the given lines is as attached

b) The area of the enclosed triangle is: 8 square units

The general form of expression of linear equations in slope intercept form is expressed as:

y = mx + c

where:

m is slope

c is y-intercept

We are given the equations as:

y = x + 5

y = 5

x = 4

The graph of these three linear equations is as shown in the attached file

2) The area of the given triangle enclosed by the three lines is gotten from the formula:

A = ¹/₂ * b * h

where:

A is area

b is base

h is height

Thus:

A = ¹/₂ * 4 * 4

A = 8 square units

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The overall limit is undefined as the the second limit is undefined

The given limit is of the indeterminate form 0/0 and hence we can apply l'Hôpital's Rule to evaluate it.

Applying l'Hôpital's Rule, we get:

lim sin(3x) / (3x) = lim [cos(3x) * 3] / 3 = cos(3x)

Now, we need to evaluate lim (3x)/(1 - cos(x)) as x approaches 0.

Again, this limit is of the indeterminate form 0/0, so we can apply l'Hôpital's Rule once again:

lim (3x)/(1 - cos(x)) = lim (3)/(sin(x)) = 3/0 (which is undefined)

Since the second limit is undefined, the overall limit is also undefined.

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The surface area of the triangular prism is 3152 square cm if the  base of the prism is an isosceles triangle.

What exactly is a triangular prism?

When a prism has three rectangular sides and two triangular bases, the prism is said to be triangular. It's a pentahedron. A right triangular prism has two faces and three rectangular sides. Bases refers to the triangle faces, whereas laterals refers to the rectangular sides.

We have a triangular prism, is showing in the picture:

Here  a = 25

b = 25

c = 14

h = 44

The surface area of the triangular prism is given by

  A = ah + bh + ch + 1/2√-a⁴ + 2(ab)² + 2(ac)² + -b⁴ + 2(bc)² - c⁴

  Plug all the values in the formula we get:

A = 3152 square cm

Thus, the surface area of the triangular prism is 3152 square cm if the  base of the prism is an isosceles triangle.

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This expression is not a polynomial, and it doesn't have a type or degree.

The expression zx^3/9-x^3 can be simplified as:

zx^3/(9-x^3)

This expression is not a polynomial because it contains a variable (x) in the denominator, which makes it a rational expression.

A polynomial is an expression of one or more terms involving only constants and variables raised to positive integer powers, with no variables in the denominators.

Therefore, this expression is not a polynomial, and it doesn't have a type or degree.

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The value of m is 11, and the divisibility test states that n is divisible by 11 if and only if the alternating sum of its two-digit chunks is divisible by 11.

Let's consider the given divisibility test proposed by Lizzie. The process involves breaking a positive integer, n, into two-digit chunks and finding the alternating sum of these chunks. The alternating sum is obtained by adding the first number, subtracting the second, adding the third, and so on.

To find the value of m that makes this a divisibility test, we need to analyze the properties of this test. Let's assume that n is divisible by m.

When n is divisible by m, each two-digit chunk in n will also be divisible by m. This means that the alternating sum of these chunks will also be by m since adding or subtracting multiples of m will not change its divisibility.

Conversely, if the alternating sum of the two-digit chunks is divisible by m, it implies that each chunk is divisible by m. Therefore, if the chunks are divisible by m, the original number n will also be divisible by m.

Hence, this process indeed serves as a divisibility test for m, where n is divisible by m if and only if the result of the alternating sum of the two-digit chunks is divisible by m.

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The constant 1.2 in the function represents the rate of change of the quantity per year.

Specifically, it represents the factor by which the quantity grows or decays over a year.

Since 1.2 is greater than 1, the function describes an exponential growth, where the quantity is multiplied by 1.2 each year.

For example, after one year, the quantity is multiplied by 1.2, after two years it is multiplied by 1.2 squared, and so on.

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The area of the first triangle is 0 square feet.

To find the area of the first triangle with the given side lengths of 1 ft, 3 ft, and 4 ft, you can use Heron's formula.

Calculate the semi-perimeter (s) of the triangle:
s = (a + b + c) / 2
where a, b, and c are the side lengths of the triangle.
s = (1 + 3 + 4) / 2 = 8 / 2 = 4 ft

Apply Heron's formula to find the area (A) of the triangle:
A = √(s * (s - a) * (s - b) * (s - c))
A = √(4 * (4 - 1) * (4 - 3) * (4 - 4))
A = √(4 * 3 * 1 * 0)
A = √0 = 0

The area of the first triangle is 0 square feet. This means that the given side lengths do not form a valid triangle, as two sides' lengths (1 ft and 3 ft) do not add up to be greater than the length of the third side (4 ft).

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The probability is approximately 45.4% (rounded to the nearest tenth of a percent).

To find the probability that a randomly selected point within the circle falls in the white area, we need to find the area of the white region and divide it by the total area of the circle.

The total area of the circle is:

A = πr² = π(4 cm)² = 16π cm²

The area of the white region can be found by subtracting the area of the two semicircles from the area of the circle:

White area = A - 2(1/2π(2.5 cm)²) = 16π - 2(4.375π) = 7.25π cm²

So, the probability that a randomly selected point within the circle falls in the white area is:

P(white area) = (white area)/(total area) = (7.25π)/(16π) ≈ 45.4%

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The maximum area of the quadrilateral is achieved when it is a square with a side length of 50cm, resulting in an area of 2500cm².

This is because a square has equal sides and equal angles,

resulting in the most efficient use of the perimeter to enclose the maximum area.

To see why, consider a rectangle with a perimeter of 200cm.

If the rectangle is long and thin, with one side much longer than the others,

then it will have a smaller area than a square with the same perimeter.

This is because the longer sides of the rectangle will be less effective at enclosing area than the shorter sides.

Hence, The maximum area of a quadrilateral with a minimum perimeter of 200cm is achieved when the quadrilateral is a square.

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discount amount= CP-Disount percentage

or,480=CP-25/100

or480×100+25 =CP

48025 is the original price of shirt

If you let z be a random variable with a standard normal distribution, the indicated probability is 0.0793. So, the probability P(z ≥ 1.41) = 0.0793

To find the probability P(z ≥ 1.41) for a standard normal distribution, you can use a Z-table or calculator to find the area to the right of z = 1.41.

Using a Z-table or calculator, you will find the value of P(z ≥ 1.41) is approximately 0.0793. So, the probability P(z ≥ 1.41) = 0.0793. Remember to round your answer to four decimal places.

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Answer:

1024

Step-by-step explanation:

I hope everything I wrote is clear, I really need to sharpen my pencil oof

The probability of a randomly selected tire from this sample having a lifespan greater than 45,000 miles is approximately 0.0639 or 6.39%.

We can use the central limit theorem to approximate the distribution of the sample mean.

In this case, the population mean is 44,000 miles and the population standard deviation is 7,650 miles. We are taking a sample of 120 tires, so the standard deviation of the sample mean is:

σ/√n = 7,650/√120 = 698.68

To find the probability that the sample mean will be longer than 45,000 miles, we need to standardize the sample mean using the formula:

z = (x - μ) / (σ / √n)

where x is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values, we get:

z = (45,000 - 44,000) / (7,650 / √120) = 1.527

We can then look up the probability corresponding to a z-score of 1.527 in a standard normal distribution table or using a calculator. The probability of a randomly selected tire from this sample having a lifespan greater than 45,000 miles is approximately 0.0639 or 6.39%.

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The equation that can be used to compute the number of pieces of jewellery is ($120 + $15q)/q = $20 .

Average cost is total cost divided by the quantity of jewellery sold.

Average cost = total cost / quantity

Total cost is the sum of fixed cost and variable cost.

Total cost = fixed cost + variable cost

The fixed cost is the cost of renting the stall. The variable cost is the cost of the materials.

Total cost = $120 + ($15 x q)

T = $120 + $15q

Average cost = ($120 + $15q)/q = $20

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Answer: To find the vertex of the graph of the equation Y=3x^2+6x+1, we can use the formula:

x = -b/2a

where a = 3 and b = 6, which are the coefficients of the x^2 and x terms, respectively.

x = -6/(2 x 3) = -1

Substituting x = -1 into the equation, we get:

Y = 3(-1)^2 + 6(-1) + 1 = -2

Therefore, the vertex of the graph is (-1, -2), so the answer is A. (-1,-2).

Step-by-step explanation:

Answer:

x=81

Step-by-step explanation:

Rewrite log_3 (x)=4 in exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then log_b(x)=y is equivalent to b^y=x.

Rewrite the equation as x=3^4

Raise 3 to the power of 4 

x=81

0 J. When the child carries the box at a constant speed, the net force on the box is zero because there is no acceleration. Therefore, the work done by the child on the box is zero. So, the correct option is 0 J.

To determine the amount of work done by the child while walking across the floor at a constant speed, we need to consider the following terms: work, force, and displacement.

Work is the amount of energy transferred when a force is applied over a certain distance. It is calculated as:

Work = Force x Distance x cos(θ)

where Force is the applied force, Distance is the displacement, and θ is the angle between the force and displacement vectors.

When the child carries the box with a constant speed across the room, the force applied is equal to the gravitational force acting on the box (i.e., the weight of the box). However, since the force and displacement are in different directions (the force is acting vertically, while the displacement is horizontal), the angle between the force and displacement is 90 degrees.

Now, we know that cos(90°) = 0. Thus,

Work = Force x Distance x cos(90°) = Force x Distance x 0 = 0 J

So, the work done by the child on the box while walking across the floor at constant speed is 0 J.

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Answer:

It's fascinating to observe how the volume of different shapes can vary based on their measurements. For instance, a cylinder with a height of 6 centimeters and radius r1 has a volume of 302 cubic centimeters. Do you require further assistance?

As for the new set of instructions, please consider the following statements:

6. Sometimes true. The period of the function is determined by the formula T= 2π/b, where b is the coefficient of x in the argument of the sine function. In this case, b = π/5, so T= 10.

7. Always true. The maximum height of the object is equal to the amplitude of the function plus the vertical shift, which is 55 centimeters.

8. Sometimes true. The minimum height of the function occurs when the sine function has a value of -1, which happens at x= h-5. So, if h= 0, then x= -5, which means the statement is sometimes true depending on the value of h.

9. Always true. The midline of the function is determined by the vertical shift, which is 55 in this case.

10. Always true. The amplitude of the function is given by A= |b|, where b is the coefficient of x in the argument of the sine function. In this case, A= 42π/5, which simplifies to 84.

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Unfortunately, this integral doesn't have a simple closed-form solution. However, you can use numerical methods or software like Wolfram Alpha or a graphing calculator to approximate the value of the integral.

We have:

y = t and ds = sqrt(9t^4 + 1) dt

So, the line integral becomes:

∫C y^3 ds = ∫0^5 (t^3)(sqrt(9t^4 + 1)) dt

Using the substitution u = 9t^4 + 1, we get du/dt = 36t^3, which means dt = du/36t^3. Also, when t = 0, u = 1 and when t = 5, u = 1126.

Substituting these values and simplifying, we get:

∫C y^3 ds = (1/36) ∫1^1126 (u-1/4)(1/2) du
= (1/72) [(u-1)^2 u^(1/2)]_1^1126
= (1/72) [(1125)^2 (1126^(1/2)) - (1)^2 (1^(1/2))]

= 3555.89 (approx)

Therefore, the line integral is approximately equal to 3555.89.
To evaluate the line integral along the curve C with the given parameterization x = t^3 and y = t for 0 ≤ t ≤ 5, we need to find the integral of y^3ds. First, we need to find the derivative of the parameterization with respect to t:

dx/dt = 3t^2
dy/dt = 1

Now, we can find the differential arc length ds, which is given by the formula:

ds = √((dx/dt)^2 + (dy/dt)^2) dt

ds = √((3t^2)^2 + (1)^2) dt
ds = √(9t^4 + 1) dt

Next, substitute the parameterization of y in terms of t (y = t) into the integral:

∫(y^3 ds) = ∫(t^3 √(9t^4 + 1)) dt, with limits 0 to 5.

Now, evaluate the integral:

∫(t^3 √(9t^4 + 1)) dt from 0 to 5.

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a. The data provided enough evidence at a = 0.05 level that the true mean pH of water from this source differs from 7

b. A 95% confidence interval for the true mean pH level of the water is (6.21, 6.59) means  about 95% of those intervals would contain the true mean pH level.

c. The estimated mean pH level of seven is not included in the interval in section (b). This is consistent with the result of the test in part (a), which also rejects the null hypothesis that the true mean pH level is 7.

(a) To test whether the true mean pH of water from this source differs from 7, we can perform a one-sample t-test. The null hypothesis is that the true mean pH is equal to 7, and the alternative hypothesis is that the true mean pH is not equal to 7.

The test statistic can be calculated as follows:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

t = (6.4 - 7) / (0.5 / sqrt(30))

t = -3.07

Using a t-table with 29 degrees of freedom at a significance level of 0.05 (two-tailed test), the critical t-value is ±2.045. Since the calculated t-value (-3.07) is outside of the critical t-value range, we can reject the null hypothesis and conclude that there is enough evidence at a = 0.05 level to suggest that the true mean pH of water from this source differs from 7.

(b) A 95% confidence interval for the true mean pH level of the water is (6.21, 6.59). This means that if we were to take many random samples of size 30 from this water source, and construct a 95% confidence interval for each sample mean pH level, then about 95% of those intervals would contain the true mean pH level.

(c) The interval in part (b) does not include the hypothesized mean pH level of 7. This is consistent with the result of the test in part (a), which also rejects the null hypothesis that the true mean pH level is 7.

The confidence interval provides additional information by giving a range of plausible values for the true mean pH level, and we can see that all of the values in this range are below 7, indicating that the water is indeed slightly acidic.

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The dimensions of the larger space would be roughly 300 x 350 x 461 feet multiplied by the scaling factor of 3.01. This gives dimensions of approximately 903 x 1053 x 1388 feet.

To determine the appropriate dimensions of a space that can accommodate 200,000 people, we can use the concept of similarity.

We know that the smaller event had a crowd of 22,000 people and the area was roughly a right triangle with side lengths of 300, 350, and 461 feet. We can use the ratio of the number of people to the area to find the scaling factor.

The area of the triangle is (1/2) x 300 x 350 = 52,500 square feet.
The ratio of people to area is 22,000/52,500 = 0.42 people per square foot.

To accommodate 200,000 people, we need an area of 200,000/0.42 = 476,190.5 square feet.

Assuming we maintain the same shape and proportions, we can use the area of the triangle as a guide to find the dimensions of the larger space. Let x be the scaling factor. Then:

(1/2) x (300x) x (350x) = 476,190.5
52,500x² = 476,190.5
x² = 9.05
x = 3.01

In summary, we can use the ratio of people to area to determine the appropriate dimensions of a space that can accommodate 200,000 people. By maintaining the same shape and proportions of a smaller event, we can find the scaling factor needed to determine the dimensions of the larger space.

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The population increased by a percentage of 5%.

The population of Sanibel, Florida in 2016 can be determined using the given population model P = 6191 * 1.05^t, where t represents the number of years since 2016. To find the population in 2016, we set t to 0 since there are 0 years since 2016.

Step 1: Set t to 0 in the equation:
P = 6191 * 1.05^0

Step 2: Calculate the population P:
P = 6191 * 1
P = 6191

So, the population in Sanibel, Florida in 2016 was 6,191.

Regarding the percent population increase each year, the given model uses an exponential growth formula with a constant factor of 1.05. The factor (1.05) represents a 5% increase in the population each year.

In summary, the population in Sanibel, Florida in 2016 was 6,191, and the population increases by 5% each year. This exponential growth model demonstrates how the population continues to grow at a steady rate, contributing to the overall population increase in the area.

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The given integral is ∫₁₀ (10/(x-2)) dx.

The given integral is divergent and the answer is "oo".

To see why the integral is divergent, we can use the following limit comparison test:

∫₁₀ (10/(x-2)) dx ~ ∫₁₀ (1/x) dx, as x → 2.

The symbol "~" means "is asymptotic to". We can use this comparison because as x approaches 2 from the right, the function 10/(x-2) approaches positive infinity.

Now, we know that the integral ∫₁₀ (1/x) dx diverges because the improper integral of 1/x from 1 to infinity diverges. Therefore, by the limit comparison test, the original integral is also divergent.

Hence, the given integral ∫₁₀ (10/(x-2)) dx is divergent, and the answer is "oo".

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