a motorcyclist riding North along a straight road at 50 km per hour observes that the wind appeared to have a velocity of 50 km per hour from the direction North 60 degrees West what is the velocity of the wind.​

Answer:

300.25

Step-by-step explanation:

The mass of 1 packet of low fat vegetable soup is 70.5g, the mass of 50 packets is 300.25g(70.5x50).

The mass of 50 low-fat vegetable soups has a mass equal to 300.25 g.

Given : The mass of 1 packet of low-fat vegetable soup is 70.5g

To find: The mass of 50 such packets

Concept: In mathematics, a product is the result of multiplication, or an expression that identifies factors to be multiplied. For example, 30 is the product of 6 and 5

The mass of 50 such packets is 70.5x50 i.e., mass of 1 pkt* number of packets given which is given to be 70.5 and 50 respectively

= 300.25 g.

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Answer:

Step-by-step explanation:

Please give me Brainliest!

Answer:

ok the first point there is (-4;-3)

the second point is(0;-6)

The rise and run that would give us a similar right triangle on the same given line is: B. a rise of 8 and a run of 6.

The rise/run of any two points on the same line are have the same slope value.

Given the coordinates:

The rise of triangle ABC = change in y = 4 units

The run of triangle ABC = change in x = 3 units

Rise/run = 4/3

Therefore, a rise of 8 and a run of  6 would give us: 8/6 = 4/3.

This will give us a triangle similar to triangle ABC.

Therefore, the answer is: B. a rise of 8 and a run of 6.

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Answer:

14.285714285714 %

Step-by-step explanation:

suppose the weekly payment is of x dollars

Then

Previous payment : $(x/40) per hour

New payment : $(x/35) per hour

Then

The percentage increase in the hourly rate of pay is :

[tex]=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100[/tex]

[tex]=\frac{\frac{5x}{1400} }{\frac{x}{40} } \times100[/tex]

[tex]=\frac{5x}{1400} \times \frac{40}{x} \times100[/tex]

[tex]=\frac{200}{1400} \times100[/tex]

[tex]=\frac{1}{7} \times100[/tex]

[tex]=14.285714285714[/tex]

The value of x will be 50°. Then the correct option is D.

It is a polygon with four sides. The total interior angle is 360 degrees. A parallelogram's opposite sides are parallel and equal.

Then the sum of the adjacent angle of the parallelogram is 180 degrees.

Then the value of x that makes ABCD a parallelogram will be

The one angle is x+60°.

Then the another angle will be 70°.

Then we have

x + 60° + 70° = 180°

       x + 130° = 180°

                  x = 50°

Then the correct option is D.

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Answer: B. 4x-2y=2

Step-by-step explanation:

We will work this out one by one. Plug in the x and y values of the solution to the equations and you will see which one is true or false.

A. [tex]2(1)+y(1)=2\\2+1\neq 2[/tex]     B. [tex]4(1)-2(1)=2\\4-2=2[/tex]

C. [tex]2(1)-2(1)=2\\2-2\neq 2[/tex]     D. [tex]x(1)+y(1)=4\\1+1\neq 4[/tex]

With this information, we see that B is the correct answer.

I hope this helped!! Pls mark brainliest!! :))

Answer :C)It is nonlinear because the increase in the “Total Houses Built” compared to the increase in the “Months Passed” does not show a constant rate of change.

:) hope you have a great day!

Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P at; D: 105°

From the given image, If we connect points C of the blue quadrilateral to point C' of the rotated quadrilateral using the center of rotation P, then we will notice that ∠CPC' will be greater than 90°.

Now, the rotation is counterclockwise and it therefore means that the angle of rotation is will be positive and since ∠CPC' is greater than 90°, then we can say that the only correct option is Option D which is 105°

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By using trigonometric identities we can solve the trigonometric equation Sin (5x-28) = cos (3x - 50) for x.

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

The question is incomplete.

The complete question is:

Solve for X given that sin(5X - 28)° = cos(3X - 50)°.​

We have given:

sin(5X - 28)° = cos(3X - 50)°.

[tex]\rm \sin \left(5x-28\right)=\sin \left(\dfrac{\pi }{2}-\left(3x-50\right)\right)[/tex]

[tex]\rm \left5x-28\right= \left\dfrac{\pi }{2}-\left(3x-50\right)\right[/tex]

[tex]\rm x=\dfrac{4\pi n+156+\pi }{16}[/tex]     (n = 0, 1, 2, ...)

[tex]\rm x=\dfrac{\pi +4\pi n-44}{4}[/tex]

Thus, by using trigonometric identities we can solve the trigonometric equation Sin (5x-28) = cos (3x - 50) for x.

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[tex]\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \dfrac{\sqrt{a}}{\sqrt{b}}=\sqrt{\dfrac{a}{b }},\:\quad \:a\ge 0,\:b\ge 0[/tex]

[tex]\dfrac{\sqrt{6}}{\sqrt{27}}=\sqrt{\dfrac{6}{27}}[/tex]

[tex]=\sqrt{\dfrac{6}{27}}[/tex]

[tex]\mathrm{ Cancel \ \ \dfrac{6}{27} \ \ \ ; \ \ \dfrac{2}{9} }[/tex]

[tex]=\sqrt{\dfrac{2}{9}}[/tex]

[tex]\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b }},\:\quad \:a\ge 0,\:b\ge 0[/tex]

[tex]=\sqrt{\dfrac{2}{9}}[/tex]

[tex]\sqrt{9}=3[/tex]

[tex]=\dfrac{\sqrt{2}}{3} \ \ === > \ \ \ Answer[/tex]

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:

x = 59/12

Step-by-step explanation:

4x + 1/3 = 20

4x = 20 - 1/3

12x/3 = 60/3 - 1/3

12x = 60 - 1

12x = 59

x = 59/12

Check:

4*59/12 + 1/3 = 20

236/12 + 4/12 = 20

240/12 = 20

So there is a possibility I read it wrong, or you typed it wrong. but from what I see, there are NO right triangles.

Step-by-step explanation:

a right triangle has a 90 degree angle. none of these have one.

Answer:

“The slope is Negative three-fourths, and the y-intercept is 3.”

Step-by-step explanation:

the graph passes through the points (0 , 3) and (4 , 0)

Then

The slope is :

[tex]=\frac{0-3}{4-0}[/tex]

[tex]=-\frac{3}{4}[/tex]

Since , the graph passes through (0 , 3)

THen the y-intercept is 3.

Answer:

The formula for the volume of a cone is V=1/3hπr².

Answer:

30

Step-by-step explanation:

Answer: D, $116

Step-by-step explanation:

A = 100(1 + 0.03)^5

A = 100(1.03)^5

A = 100(1.1593)

A = 115.92

Hope this helped!

#1

Correct version

[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]

[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]

[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]

#2

[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]

[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]

[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]

Answer:

x1 = 4 y x2= 2

Step-by-step explanation:

escuchame

x2 - 5x -6 = 0

(4)^2 - 5(2) - 6 = 0

16 - 10 - 6 = 0

6 - 6 = 0

de nade :)

Answer:

The place value of 3 is tens

the 3 is in the value of tens

Answer:

Domain is all x-values and range is all y values. See all of the x values and y values that are touching the graph. Also, when there is a circle/ hole, use parenthesis for the interval notation.  Hope it helps!

The set A satisfying the given inequality is A = (-[tex]\infty[/tex], -10].

Following are some facts which are true for an inequality relation:

[tex]\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)[/tex]

Since y ∈ B, -2 ≤ y ≤ 7. So,

[tex]\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\; y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.[/tex]

The set {-x | inequality (1) holds ∀ y ∈ B} is [10, [tex]\infty[/tex]) i.e.

10 ≤ -x ≤ [tex]\infty[/tex].

Multiplying -1 throughout gives

-10 ≥ x ≥ -[tex]\infty[/tex].

x, thus, lies in the range A = (-[tex]\mathbf{\infty}[/tex], -10}.

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Disclaimer: The question was incomplete. Please find the full content below.

Find the set A such that for x ∈ A

[tex]\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y[/tex]

∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.

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1) Either [tex]\ell \parallel p[/tex] or [tex]\ell[/tex] ∦ [tex]p[/tex] (only two possibilities)

2) Assume [tex]\ell \parallel p[/tex] (one of two possibilities)

3) [tex]\angle 1 \cong \angle 2[/tex] (if two parallel lines are cut by a transversal, the corresponding angles are congruent)

4) But [tex]\angle 1[/tex] is not congruent to [tex]\angle 2[/tex] (given)

5) So [tex]\ell[/tex] ∦ [tex]p[/tex] (only other possibility)

The equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]

Which expression is equivalent to [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

The expression is given as:

[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

Apply the exponent law of indices

[tex](\frac{x^{-9}y^5}{x^{-4}y})^{2}[/tex]

Next, we apply the common base law of indices

[tex](x^{4 -9}y^{5-1})^2[/tex]

Evaluate the difference

[tex](x^{-5}y^4)^2[/tex]

Remove bracket

[tex]x^{-10}y^8[/tex]

Hence, the equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]

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Answer:

y^8/x^10

Step-by-step explanation:

The guy above me is right but just forgot to distribute the negative out of x. :)

Answer:

A key turning point in American politics was the election of 1980. It indicated the new electoral power of the suburbs. The success that Reagan had as a conservative would initiate a group of parties because liberals and conservatives would either leave politics or change party affiliations through the 1980s and 1990s. The research shows this caused the 1980 election to be recalled as one of America's best historical events.

Step-by-step explanation:

The League of Women Voters is pleased to welcome President Jimmy Carter, the Democratic Party's candidate for re-election to the Presidency, and Governor Ronald Reagan of California, the Republican Party's candidate for the Presidency. The candidates will debate questions on domestic, economic, foreign policy, and national security issues.

In the debate between sitting president Jimmy Carter and Republican challenger Ronald Reagan, Reagan's arguments and explanations best match the available evidence. Carter claims his policies had reduced the inflation rate by 10% in less than a year and points to the 9 million jobs he had provided to reduce unemployment rates. Reagan refutes this by mentioning that while Carter may have decreased the inflation rate from the beginning of the year, the inflation rate increased from 4.4% at the start of his presidency to almost 12% now. A graph provided by Ed Genuity proves this to be true, therefore current evidence supports Reagan's claim.

In the final week of the 1980 presidential campaign between Democratic President Jimmy Carter and Republican nominee Ronald Reagan, the two candidates held their only debate. And then, during the debate, Reagan posed what has become one of the most important campaign questions of all time: “Are you better off today than you were four years ago?” Carter’s answer was a resounding “NO,” and in the final, crucial days of the campaign, his numbers tanked.

On Election Day, Reagan won a huge popular vote and electoral victory. The “better off” question has been with us ever since. Its simple common sense makes it a great way to think about elections. And yet the answers are rarely simple.

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Answer:

i think it is 102

Step-by-step explanation:

first u solve the equation to find

then substitute and solve for at a tb

next just add them to find

Answer:

now we have to follow up with the formula n² - n¹

which is 7-1= 6

n³-n²

which is 13-7=6

so therefore the nth term=6

Answer:

$20 × 14 days = $280

&30 × 3 = $90

&280 + $90 = $370

Answer:

For car she owes=

$20 x 14 = $280

For tank she owes=

$30 x 3 = $90

Therfore in total she owes,

$280 + $90 = $370

An asset loses value over time as a result of use, damage, or obsolescence.

An asset loses value over time as a result of use, damage, or obsolescence. Depreciation is the measurement for this decline.

The depreciation method that does not initially use the residual value in depreciation calculations is the depreciating balance.

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Anne will walk a distance of 7 km, and she takes 2 hours to walk that distance.

The total distance is 18.5 km.

She travels 10km by train and 1.5km by bus, for a total of 11.5km.

The distance that she walks is given by:

18.5km - 11.5km = 7km

So she walks for a distance of 7 km, at a speed of 3.5km per hour.

Remember the relation:

distance = time*speed

That can be rewritten to:

time = distance/speed.

Then the time that she walks is given by:

T = (7 km)/(3.5 km/hour) = 2 hours

She walks for 2 hours.

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