A meter stick is hung from the ceiling with a string attached to the center. A 3.0 kg mass is hung from the 0.10 m line on the meter stick. Where should a 5.0 kg mass be hung to balance the meter stick.

In an electromagnetic wave, the electric and magnetic fields are oriented such that they are 'perpendicular to one another and perpendicular to the direction of wave propagation' (option d).

An electromagnetic wave is a type of wave that consists of oscillating electric and magnetic fields, which are perpendicular to one another and to the direction of wave propagation. The electric field is oriented in one plane, while the magnetic field is oriented in a plane perpendicular to the electric field. These fields work together to create an electromagnetic wave that can travel through space at the speed of light.

In conclusion, the electric and magnetic fields in an electromagnetic wave are oriented perpendicular to one another and perpendicular to the direction of wave propagation. This unique orientation allows electromagnetic waves to carry energy and information over long distances, and it is the basis for many important technologies, including radio and television broadcasting, cellular communication, and satellite communications.

Option d is the answer.

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We can solve for various parameters such as current, voltage, resistance, and power, and optimize the performance of the circuit.

Starting with the equation for power:

P = IV

We can rearrange this equation to solve for either I or V, depending on what we need:

I = P/V

V = P/I

Now, let's look at the equation for resistance:

R = V/I

We can rearrange this equation to solve for either V or I:

V = IR

I = V/R

So the two equations that can be derived from P = IV and R = V/I are:

I = P/V

V = P/I

and

V = IR

I = V/R

These equations are fundamental to understanding the behavior of electric circuits and are used in circuit analysis and design. By manipulating these equations, we can solve for various parameters such as current, voltage, resistance, and power, and optimize the performance of the circuit.

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If the mass of a simple pendulum is divided by four while its length is doubled, the period will:4.E) increase by a factor of 1.4.

A simple pendulum would continue oscillating in an ideal condition with no friction. We do not, however, live in such a world. When a pendulum is transformed into heat, it loses energy and hence stops oscillating. Even in the absence of air friction, the friction with the point around which the pendulum spins causes the system to lose kinetic energy and finally come to a halt.

The period of a pendulum is determined only by the length of the string, not by the mass of the ball. The period of two pendulas with different masses but the same length will be the same.

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"It is zero at both points." is true of the electric field at these points. The correct option is A.

In a hollow metal sphere, under electrostatic conditions, the electric field inside the sphere is zero everywhere. This is because any electric field that exists inside the sphere will cause the free electrons in the metal to move until the electric field is zero. Therefore, at point C, which is the center of the sphere, the electric field is zero. Similarly, at any point P within the sphere, the electric field is also zero since it is inside a conductor under electrostatic conditions.

Option (B) is incorrect because the electric field is zero at point P inside the sphere, and not directed inward.

Option (C) is incorrect because the electric field is zero at point P inside the sphere, and not directed outward.

Option (D) is incorrect because the electric field is zero at point C, the center of the sphere, under electrostatic conditions.

Option (E) is incorrect because, as mentioned above, the electric field inside a hollow metal sphere under electrostatic conditions is zero everywhere.

Therefore, The correct option is (A) It is zero at both points.

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If we widen the slit in a diffraction experiment, the pattern becomes narrower and the intensity of the light decreases.In a diffraction experiment, a pattern of light and dark bands is formed due to the interference of light waves.

The pattern depends on the width of the slit through which the light passes. This is because, as the slit becomes wider, the angle of diffraction becomes smaller, resulting in a narrower pattern. The intensity of the light also decreases because more light is passing through the wider slit, which means that the light is more spread out and less concentrated.

It is important to note that the width of the slit is not the only factor that affects the diffraction pattern. The distance between the slit and the screen, as well as the distance between the individual slits (in the case of multiple slits), also play a role in determining the pattern.

In summary, widening the slit in a diffraction experiment will result in a narrower pattern and a decrease in the intensity of the light.

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Weak nuclear force, electric force, nuclear force, and gravitational force are the four fundamental forces of nature. The weak and strong forces are dominant only at the level of subatomic particles and are only effective across extremely small distances. amongst Electric force allows you to close a door by pushing on it.

Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion define how it affects the target body and how it does so. One of the many forces that affect things is the electric force.

For instance, moving a box results in a force being applied to it because the negatively charged electrons in the hand pushing it repel the similarly negatively charged electrons in the box's atoms.

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The event horizon is considered as a boundary near a black hole where light or any kind of radiation can not pass through. Or in simple words, it is a boundary of a black hole where a light can not escape due to very high gravitational force.

Singularity lies at the center of the black hole whose space is extremely small but mass is extreme. In singularity, the density and gravity is so huge that it becomes almost infinite and no physics law in applicable there.

It would only take around 20 seconds to reach the singularity once you crossed the event horizon.

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the amount of incoming radiation to earth compare to the amount of outgoing radiation is the amount of incoming radiation must be greater than the amount of outgoing radiation. Hence correct option is A.

Energy that emanates from a source and moves through space at the speed of light is referred to as radiation. This energy has wave-like qualities and is accompanied by an electric field and a magnetic field. The term "electromagnetic waves" can also be used to describe radiation.

The sun is sending radiation which contains all types of radiation, ultraviolet radiation, visible radiation and IR radiation. whatever we feel heat in sun light is called as IR radiation.

Outgoing radiation is nothing but reflected radiation from the surface of the earth, most of the radiation is absorbed by the earth surface and a small amount of radiation is reflected by the sea.

Hence option A is correct.

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The average person's vertical jump on the Moon would be 0.65 m.

The gravitational acceleration near the surface of the Moon is 1.62 m/s2, which is about one sixth the gravitational acceleration on Earth.

As a result, an average person's vertical jump on the Moon would be less than on Earth.

To calculate the vertical jump on the Moon, we need to use the formula h = 1/2 x g x t2.

This equation is used to calculate the height h (in meters) that an object will reach when thrown into the air, given the gravitational acceleration g (in m/s2) and the time t (in seconds) it takes to reach the peak of the jump.

Since the gravitational acceleration on the Moon is 1.62 m/s2, and the time taken to reach the peak of the jump is the same (assume 0.5 s), then h = 0.5 x 1.62 x (0.5)2, which is 0.65 m.

Therefore, an average person's vertical jump on the Moon would be 0.65 m.

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The conversion between linear velocity and angular velocity is an essential concept in physics, particularly in the study of rotational motion.

In rotational motion, an object rotates around an axis, and its motion is described in terms of angular velocity. Linear velocity, on the other hand, refers to the speed of an object moving along a straight line.

To convert linear velocity to angular velocity, you can use the formula ω = v / r, where ω represents the angular velocity, v represents the linear velocity, and r represents the radius.

This formula states that the angular velocity is equal to the linear velocity divided by the radius of rotation. The radius is the distance between the axis of rotation and the point at which the linear velocity is measured.

Conversely, to convert angular velocity to linear velocity, you can use the formula v = rω, where v represents the linear velocity, ω represents the angular velocity, and r represents the radius.

This formula states that the linear velocity is equal to the product of the radius and the angular velocity.

The formulas are crucial in various fields of physics, including engineering, mechanics, and astronomy, as they enable scientists and engineers to determine the relationship between linear velocity and angular velocity.

By applying these formulas, they can calculate the rotational speed of objects, such as gears and wheels, and design machines that operate efficiently and safely.

In conclusion, understanding the conversion between linear velocity and angular velocity is essential in physics and related fields.

The formulas ω = v / r and v = rω provide a simple yet powerful method for converting between these two types of velocity, enabling researchers and engineers to study and design rotational motion with accuracy and precision.

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The energy from the two waves that are canceling at a dark fringe is still present in the system, but it is being redirected or dispersed in other directions.

When considering a dark fringe in an interference pattern, it is important to remember that this is a result of destructive interference between the two waves from the two slits. This means that the peaks of one wave are arriving at the same point as the troughs of the other wave, resulting in a cancellation of the wave amplitudes.

However, just because there is no visible light energy at this point does not mean that energy is not present. In fact, the energy from the two waves is still arriving at this point, but it is simply being redirected elsewhere. This redirection of energy can occur in a few different ways.

One possibility is that the energy is being reflected back towards the source, essentially reversing the path of the waves. Another possibility is that the energy is being dispersed in other directions, either through diffraction or scattering.



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False. The total energy of a closed, isolated system is always constant because energy cannot be created or destroyed, only converted between different forms, according to the conservation of energy principle.

The total energy of a closed, isolated system is always constant, according to the law of conservation of energy. This fundamental law of physics states that energy cannot be created or destroyed, only transformed from one form to another. In a closed, isolated system, no energy can enter or leave the system, so the total energy of the system remains constant over time. This means that the sum of all forms of energy in the system, including kinetic energy, potential energy, and internal energy, remains constant. This law has been confirmed by numerous experiments and is one of the most well-established principles in physics. Therefore, the statement "The total energy of a closed, isolated system is NEVER constant" is false.

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The time it takes for a star to rise again after it has crossed the meridian is approximately 23 hours and 56 minutes

which is the length of a sidereal day (the time it takes for the Earth to complete one rotation relative to the fixed stars).

Therefore, if Sirius rises at exactly 7:36 PM on one night, it will rise approximately 4 minutes later on the following night, at around 7:40 PM.

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A rapid change of a magnetic field induces an 'electric field of the same magnitude' (option a).

This phenomenon is known as electromagnetic induction and was first discovered by Michael Faraday in 1831. It occurs when there is a change in the magnetic flux, which is the measure of the strength and direction of the magnetic field passing through a given surface. When this change occurs, an electric field is induced in the conductor, according to Faraday's law of induction. The magnitude of the induced electric field is directly proportional to the rate of change of the magnetic field.

In summary, a rapid change of a magnetic field induces an electric field of the same magnitude. This is due to the phenomenon of electromagnetic induction, which occurs when there is a change in the magnetic flux passing through a conductor. The induced electric field is directly proportional to the rate of change of the magnetic field.

Option a is answer.

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When two large, flat, parallel, conducting plates are 0.04 m apart, The lower plate is at a potential of 2 V with respect to ground. The upper plate is at a potential of 10 V with respect to ground. Point P is located 0.01 m above the lower plate. electric potential at point P is 2 V. Hence option E is correct.

In this problem,

two parallel plates are separated by a distance 0.04m (4cm),

two plates are at 2 V and 10 V, means that there is 8V of potential difference between plates which are 4 cm apart. this means that there is 2V/cm of potential difference exist between two plates because of constant electric field.

Hence there is potential difference of 2V/cm, hence for 0.01m (1cm) there exist 2 V of potential difference.

Hence option E is correct.

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Yes, the critical angle exists for both cases where light is incident from air to glass and from glass to air. The critical angle is the angle of incidence at which the refracted angle becomes 90 degrees.

To calculate the critical angle, we can use Snell's law which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the refractive indices of the two mediums.

For the case of light incident from air to glass, we have:

sin(critical angle) = n2/n1 = 1/1.5 = 0.6667

Taking the inverse sine of 0.6667 gives us the critical angle:
critical angle = sin^-1(0.6667) = 42.48 degrees

For the case of light incident from glass to air, we have:
sin(critical angle) = n2/n1 = 1.5/1 = 1.5

Again, taking the inverse sine of 1.5 gives us the critical angle:
critical angle = sin^-1(1.5) = 90 degrees

This means that any angle of incidence greater than 90 degrees will result in total internal reflection.

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The angular acceleration values into the equation: [tex]a = (0^2 - 20\times0^2) / (2 \times 2.51) = -312.3 rad/s^2[/tex]

The angular acceleration of the tire can be determined using the equation:

[tex]a = (v^2 - u^2) / (2 \times s)[/tex]

where

The radius of the tire can be determined from its diameter:

[tex]r = d / 2 = 0.800 m / 2 = 0.400 m[/tex]

Therefore, the circumference of the tire is:

[tex]s = 2 \times \pi \times r = 2 \times \pi \times 0.400 m = 2.51 m[/tex]

Now, we can substitute the values into the equation:

[tex]a = (0^2 - 20\times0^2) / (2 \times 2.51) = -312.3 rad/s^2[/tex]

The negative sign indicates that the angular acceleration is in the opposite direction of the tire's initial motion, as the tire is coming to a stop.

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The range of sound levels between the threshold of hearing and the threshold of feeling at a frequency of 500 Hz is 120 decibels.

The threshold of hearing and the threshold of feeling are sound levels that define the lower and upper limits of human hearing, respectively. At a frequency of 500 Hz, the range of sound levels between the threshold of hearing and the threshold of feeling can be calculated as follows:

The threshold of hearing at 500 Hz is typically defined as a sound level of 0 dB, which represents the minimum sound level that a healthy human ear can perceive.

The threshold of feeling at 500 Hz is typically defined as a sound level of 120 dB or higher, which represents the sound level that is felt as vibration or pressure in the body rather than heard as sound.

Therefore, the range of sound levels between the threshold of hearing and the threshold of feeling at a frequency of 500 Hz is:

                   120 dB - 0 dB = 120 dB

In other words, the range of sound levels between the threshold of hearing and the threshold of feeling at 500 Hz is 120 dB, which is a very wide range of sound levels.

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The two media. Any angle of incidence greater than this will result in total internal reflection of the light ray.

Critical angle is a term used in optics to describe the angle of incidence of a light ray that results in the refracted ray being at an angle of 90 degrees to the surface normal. This means that any angle of incidence greater than the critical angle will result in total internal reflection of the light ray.

The critical angle can be calculated using Snell's law, which relates the angles of incidence and refraction of a light ray as it passes through a boundary between two media with different refractive indices. Snell's law states that:

n1 sinθ1 = n2 sinθ2

where n1 and n2 are the refractive indices of the two media, θ1 is the angle of incidence, and θ2 is the angle of refraction.

To find the critical angle, we set θ2 to 90 degrees (since this is the angle at which total internal reflection occurs), and solve for θ1:

n1 sinθc = n2 sin90

Since sin90 = 1, we can simplify this to:

n1 sinθc = n2

Then, we solve for θc:

θc = sin^-1(n2/n1)

This gives us the critical angle for the boundary between the two media. Any angle of incidence greater than this will result in total internal reflection of the light ray.

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The mirror copy of the cup measures about 22.49 cm in height.

To determine the height of the cup's mirror image, we can use the mirror equation:
1/f = 1/d_o + 1/d_i
where f is the focal length, d_o is the object distance (the distance from the mirror to the object), and d_i is the image distance (the distance from the mirror to the image).
Plugging in the given values, we get:
1/29.0 = 1/79.1 + 1/d_i
Solving for d_i, we get:
d_i = 22.5 cm
Now we can use the magnification equation:
m = -d_i/d_o
where m is the magnification.
Plugging in the given values, we get:
m = -22.5/13.0
m = -1.73
This means that the image is inverted and 1.73 times larger than the object. So the height of the cup's mirror image would be:
h_i = 1.73 x 13.0 cm
h_i = 22.49 cm (rounded to 100th place)

Therefore, the height of the cup's mirror image is approximately 22.49 cm.

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Approximately 7.32 pounds, this person would lose wieght if the loss were essentially all from body fat.

A person consuming 2,500 kcal/day and expending 3,500 kcal/day experiences a daily caloric deficit of 1,000 kcal (3,500 - 2,500 = 1,000). Over a month, this deficit accumulates to 30,000 kcal (1,000 x 30 days). Since body fat has an energy content of about 4,100 kcal per pound, we can calculate the weight loss by dividing the total caloric deficit by the energy content of body fat.

Weight loss = Total caloric deficit / Energy content of body fat
Weight loss = 30,000 kcal / 4,100 kcal/pound
Weight loss ≈ 7.32 pounds

In a month's time, this person would lose approximately 7.32 pounds if the loss were essentially all from body fat. It's important to note that weight loss may vary depending on individual factors, and maintaining a healthy, balanced diet alongside regular exercise is crucial for overall well-being.

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The point P, where the potential is zero is at a distance d/4 to the right of Q and 3d/4 to the left of 3Q.

Let the point be P at a distance x from Q and (d - x) from -3Q.

The potential at P due to the charge Q,

V₁ = kQ/x

where, k = 1/4[tex]\pi[/tex]ε₀

The potential at P due to -3Q,

V₂ = k(-3Q)/(d - x)

So, for the total potential at P to be zero,

V = V₁ + V₂ = 0

(kQ/x) + [-k(3Q)/(d - x)] = 0

kQ/x = 3kQ/(d - x)

(d - x)/x = 3

4x = d

Therefore, x = d/4.

d - x = d- d/4 = 3d/4

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The frequency of the system is the reciprocal of the period, so if the period increases by a factor of √2, the frequency will decrease by the same factor.

The period of a spring-mass system is given by the equation:

[tex]T = 2π√(m/k)[/tex]

where T is the period, m is the mass, and k is the spring constant.

If we double the spring constant (k), keeping the amplitude and mass constant, the period of the system will change. To see how it changes, we can use the above equation:

[tex]T = 2π√(m/k)[/tex]

If we double the spring constant (k), the square root of (m/k) will be halved, since the denominator (k) is doubled. Therefore, the period (T) of the system will be:

[tex]T' = 2π√(m/2k) = √2 (2π√(m/k)) = √2 T[/tex]

So the period of the system will increase by a factor of √2 (approximately 1.414).

Therefore, the frequency of the system will decrease by a factor of √2.

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To find the force required to lift the automobile using the hydraulic lift, we can use Pascal's Law. Pascal's Law states that the pressure in a fluid is transmitted uniformly throughout the fluid. In this case, the pressure applied to the small piston will be equal to the pressure on the large piston.

Pressure = Force / Area

Let F1 be the force applied to the small piston with area A1, and F2 be the force on the large piston with area A2.

F1 / A1 = F2 / A2

Given the mass of the automobile (m) is 1500 kg, we can find the force due to gravity (weight) acting on it:

Weight (F2) = m * g (where g = 9.81 m/s^2, the acceleration due to gravity)
F2 = 1500 kg * 9.81 m/s^2 = 14715 N

Now, we can plug the values for F2, A1, and A2 into the equation and solve for F1:

F1 / 0.4 m^2 = 14715 N / 15 m^2
F1 = (0.4 m^2 * 14715 N) / 15 m^2
F1 ≈ 392.4 N

Therefore, a force of approximately 392.4 N must be applied to the small piston to raise the automobile.

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The acceleration of the rocket is 25.5 m/s^2.

To find the acceleration of the rocket, we can use Newton's second law of motion which states that force (F) is equal to mass (m) times acceleration (a). Therefore, we can calculate the acceleration of the rocket as follows:

F = ma

Given values:
F = 790 N
m = 30.9 kg

Now, rearrange the equation to solve for acceleration (a):
a = F / m

Where F is the upward force or thrust created by the rocket's engine, m is the mass of the rocket and a is the acceleration.

Given that the mass of the rocket is 30.9 kg and the upward force created by the engine is 790 N, we can plug in these values into the formula and solve for acceleration:

790 N = 30.9 kg x a

a = 790 N / 30.9 kg

a = 25.5 m/s^2

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The car is travel approximately 33.554 miles in 1 hour at a constant speed of 15 m/s.

It must translate the speed from metres per second to miles per hour in order to figure out how many miles the car covers in an hour.

Let's first translate the car's speed from metres per second to miles per hour:

1 mile = 1609.34 meters (approximately)

1 hour = 3600 seconds

Consequently, this is the conversion factor for metres per second to miles per hour,

(1 meter/second) × (3600 seconds/1 hour) × (1 mile/1609.34 meters)

Now, let's put in the given speed of 15 m/s into the conversion factor:

15 m/s × (3600 seconds/1 hour) × (1 mile/1609.34 meters)

Miles per hour remains after the metres unit cancels out,

15 × 3600 / 1609.34 miles/hour

Calculating the above expression, can get:

33.554 miles/hour (rounded to three decimal places)

Therefore, the car would travel approximately 33.554 miles in 1 hour at a constant speed of 15 m/s.

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The image of Source 2 will be closer to her eye than the image of Source 1 when the person is looking at the images in the mirror.

To answer your question, let's go through the steps to understand the situation and the terms involved.

1. Two point sources of light, Source 1 and Source 2, are placed in front of a flat mirror. Source 2 is closer to the mirror and Source 1 is further away.

2. A person is observing the images of the two sources in the mirror.

Now, let's analyze the situation to determine which image is closer to the person's eye.

In a flat mirror, the distance between an object and its image is the same as the distance between the object and the mirror. This means that the image of Source 2 will be at the same distance from the mirror as Source 2, and the image of Source 1 will be at the same distance from the mirror as Source 1.

Since Source 2 is closer to the mirror, its image will also be closer to the mirror than the image of Source 1. Therefore, when the person is looking at the images in the mirror, the image of Source 2 will be closer to her eye than the image of Source 1.

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The time it takes for a cloud droplet to reach the ground depends on its size and the distance it falls.

Assuming the air is still, the typical terminal velocity of a cloud droplet is about 5 meters per second. Therefore, to fall 1000 meters, it would take approximately 200 seconds (1000 meters / 5 meters per second = 200 seconds).

However, it is unlikely that a cloud droplet would reach the ground because as it falls, it will encounter other air molecules, including water vapor. The air molecules will collide with the droplet, causing it to slow down and eventually reach a state of equilibrium, known as the terminal velocity. For a typical cloud droplet, the terminal velocity is about 5 meters per second, which is not enough to overcome the upward motion of air currents in the atmosphere. Therefore, most cloud droplets evaporate or collide and merge with other droplets to form larger droplets or raindrops, which then fall to the ground.

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a. The initial velocity is v0 = 20.0 m/s

b. The total distance traveled by the particle Δx = 8,500.0 m

c. The average acceleration is aav = 2.5 m/s²

d. The instantaneous acceleration a of the particle is a = 7.5 m/s²

a. The initial velocity v0 is given as 20.0 m/s.

b. To calculate the total distance traveled by the particle, we need to integrate the velocity function with respect to time. Doing so, we get Δx = 0.5at² + v0t, where a is the constant acceleration of the particle. Substituting the given values, we get Δx = 8,500.0 m.

c. The average acceleration aav of the particle over the first 20.0 seconds can be calculated as aav = (v - v0)/t, where v is the final velocity of the particle after 20.0 seconds. Using the equation v = v0 + at, we get v = 70.0 m/s. Substituting the values, we get aav = 2.5 m/s².

d. The instantaneous acceleration a of the particle at t=45.0s can be calculated using the same equation v = v0 + at. Differentiating both sides of the equation with respect to time, we get a = dv/dt = d/dt (v0 + at) = a. Substituting the given values, we get a = 7.5 m/s².

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The final charge on each sphere is the same as follows:

Since the two spheres are in contact, they will share charges until they reach the same potential.

Let's assume that the initial charge on the left sphere is Q and the initial charge on the right sphere is q. After they are brought into contact, the total charge is conserved, so we have:

Q + q = (Q + q)/2 + (Q + q)/2

Simplifying this equation, we get:

Q + q = 2(Q + q)/2

Q + q = Q + q

This tells us that the final charge on each sphere is the same, which is half of the sum of their initial charges. Therefore:

Final charge on left sphere = Q/2

Final charge on right sphere = q/2

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