A manufacturer of plumbing fixtures has developed a new type of washerless faucet. let rho-p(a randomly selected faucet of this type will develop a leak within 2 years under normal use). the manufacturer has decided to proceed with production unless it can be determined that p is too large; the borderline acceptable value of p is specified as 0.10. the manufacturer decides to subject n of these faucets to accelerated testing (approximating 2 years of normal use). with x = the number among the n faucets that leak before the test concludes, production will commence unless the observed x is too large. it is decided that if p = 0.10, the probability of not proceeding should be at most 0.10, whereas if rho = 0.30 the probability of proceeding should be at most 0.10. (assume the rejection region takes the form reject h if x2 c for some c. round your answers to three decimal places.)
1. what are the error probabilities for n10? p-value- can n- 10 be used?
a. it is not possible to use n = 10 because there is no value of x which results in a p-value
b. it is not possible to use n10 because it results in b(0.3)> 0.1
c. it is not possible to use n 10 because it results in b(0.3)<0.1 0.1.
d. it is possible to use n = 10 because both the p-value and β(0.3) are less than 0.1
e. it is possible to use 10 because both the p-value and b(0.3) are greater than 0.1
what are the error probabilities for n-20? p-value = β(0-3) = can n 20 be used?
a. it is not possible to use n = 20 because there is no value of x which results in a p-value
b. it is not possible to use n 20 because it results in b(0.3)0.1
c. it is not possible to use n 20 because it results in b(0.3) < 0.1
d. it is possible to use n 20 because both the p-value and b(0.3) are less than 0.1
e. it is possible to use n 20 because both the p-value and b(0.3) are greater than 0.1
2. what are the error probabilities for n-25? p-value . p(0.3) can n 25 be used?
a. it is not possible to use n-25 because there is no value of x which results in a p-value
b. it is not possible to use n 25 because it results in b(o.3) > 0.1
c. it is not possible to use n 25 because it results in b(0.3) < 0.1
d. it is possible to use n 25 because both the p-value and b(0.3) are less than 0.1
e. it is possible to use n 25 because both the p-value and b(0.3) are greater than 0.1 0.1.

Answers

Answer 1

It is not possible to use n = 10.

It is not possible to use n = 20.

It is possible to use n = 25.

1. The error probabilities for n = 10 are as follows:

- P-value: It is not possible to use n = 10 because there is no value of x which results in a p-value.
- Beta (0.3): B(0.3) > 0.1, which means the probability of failing to reject the null hypothesis (p = 0.1) when the true probability of a leak is actually 0.3 is too high.

Therefore, it is not possible to use n = 10.

2. The error probabilities for n = 20 are as follows:

- P-value: It is not possible to use n = 20 because it results in a beta error probability (B(0.3)) < 0.1, which means the probability of incorrectly rejecting the null hypothesis (p = 0.1) when the true probability of a leak is actually 0.3 is too low.
- Beta (0.3): B(0.3) > 0.1, which means the probability of failing to reject the null hypothesis (p = 0.1) when the true probability of a leak is actually 0.3 is too high.

Therefore, it is not possible to use n = 20.

3. The error probabilities for n = 25 are as follows:

- P-value: P(0.3) < 0.1, which means the probability of incorrectly rejecting the null hypothesis (p = 0.1) when the true probability of a leak is actually 0.3 is low enough to proceed with production.
- Beta (0.3): B(0.3) < 0.1, which means the probability of failing to reject the null hypothesis (p = 0.1) when the true probability of a leak is actually 0.3 is low enough to proceed with production.

Therefore, it is possible to use n = 25.

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Related Questions

Can someone please help! All I need is 19, 20, 21, 22, 23, 24! Thank you

Answers

Answer:

hope it helps! :)

Step-by-step explanation:

m < A = 61 bc 90+29=119

180-119=61

ED: 9y-22=5

9y=27

y=3

9(3)-22 =5

ED=5

3x-5=13

3x=18

x=6

[tex]BC^{2}[/tex]+25+=169

[tex]BC^{2}[/tex]=144

BC=12

m<DCE=29

y=3

I have tried doing this question for 20 minutes but I just can't get the answer, (add maths circular measure)
the answer is 17.2cm² supposedly​

Answers

Answer:

17.2 cm²

Step-by-step explanation:

Alr let me try

The angle is 1.2 you got it right. The rest is in the pics

Answer: A(shaded)=17.15 cm²

Step-by-step explanation:

What you did so far is correct.

Given:

r=5

s=6

Solve for Ф  angle:

s=[tex]\frac{part circle}{wholecircle} 2\pi r[/tex]         This way help you find the portion/percent you want

6=(Ф/360) (2[tex]\pi[/tex]5)       >solve for Ф  Divide by (2[tex]\pi[/tex]5) and multiply by 360

Ф=68.75

Solve for pie/sector

Now that you have the angle,  you can use the same concept for area

Area of sector = [tex]\frac{part circle}{wholecircle} \pi r^{2}[/tex]

Area of sector = [tex]\frac{68.75}{360} \pi 5^{2}[/tex]

Area of sector = 15.0 cm²

Now let find y so we can plug into area of triangle

use tan Ф = opposite/adjacent

tan 68.75 = y/5

y=5 * tan 68.75

y=12.86 cm

Area of triangle = 1/2 b h          b=y=12.86     h =5

Area of triangle = 1/2* 12.86*5

Area of triangle = 32.15 cm²

Now subtract area of sector from triangle

A(shaded)=A(triangle)-A(sector)

A(shaded)=32.15- 15.0

A(shaded)=17.15 cm²

okay ummm deleted question

Answers

Answer:

Sure, let me know if you have a new question or need any assistance!

At the Royal Dragon Chinese restaurant, a slip in the fortune cookies indicates a dollar amount that will be subtracted from your total bill. A bag of 10 fortune cookies is given to you from which you will select one. If six fortune cookies contain "1$ off," three contain "$3 off," and one contains "$8 off," determine the expectation of a selection.

Answers

Answer:

im sorry this makes absolutely no sense

Step-by-step explanation:

A bacteria population doubles every eight minutes if the population with one cell, how long will it take to grow to 2097152

Answers

The time that it will take the bacteria to grow to 2097152 is: 2 hours 48 minutes

How to solve Exponential functions?

An exponential function is defined as a Mathematical function in the form f(x) = [tex]a^{x}[/tex].

where:

“x” is a variable.

“a” is a constant which is called the base of the function and it should be greater than 0

However; the exponential function is:

1([tex]2^{x}[/tex]) = 2097152

log 2x  = log 2097152

x log 2 = log 2097152

x = log 2097152/log 2

x = 6.32162/0.3010

x = 21 times the population doubles

21(8) = 168 minutes = 2 hours 48 minutes

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Evaluate the integral by making an appropriate change of variables. Sle 9e2x + 2y da, where R is given by the inequality 2[x] + 2 y = 2

Answers

Using the change of variables u = x and v = x + y, we transform the given region R into a rectangle S, and evaluate the integral as 9 (e^6 - 2e^4 + e^2 - 1).

We need to find a change of variables that maps the region R onto a rectangle in the uv-plane. Let's make the following substitutions

u = x

v = x + y

Then, the region R is transformed into the rectangle S defined by 0 ≤ u ≤ 1 and 0 ≤ v ≤ 2.

To find the limits of integration in the new variables, we can solve the equations 2[x] + 2y = 2 for x and y in terms of u and v

2[x] + 2y = 2

2u + 2v - 2[x] = 2

[x] = u + v - 1

Since [x] is the greatest integer less than or equal to x, we have

u + v - 1 ≤ x < u + v

Also, since 0 ≤ y ≤ 1, we have

0 ≤ x + y - u ≤ 1

u ≤ x + y < u + 1

u - x ≤ y < 1 + u - x

Now we can evaluate the integral using the new variables

∫∫R 9e^(2x+2y) dA = ∫∫S 9e^(2u+2v) |J| dudv

where J is the Jacobian of the transformation, given by

|J| = det [[∂x/∂u, ∂x/∂v], [∂y/∂u, ∂y/∂v]]

= det [[1, 1], [-1, 1]]

= 2

Therefore, the integral becomes

∫∫S 9e^(2u+2v) |J| dudv = 2 ∫0^1 ∫0^2 9e^(2u+2v) dudv

= 2 ∫0^1 [9e^(2u+2v)/2]_0^2 dv

= 2 ∫0^1 (9/2)(e^(4+2v) - e^(2v)) dv

= 2 (9/2) [(e^6 - e^2)/2 - (e^4 - 1)/2]

= 9 (e^6 - 2e^4 + e^2 - 1)

Therefore, the value of the integral is 9 (e^6 - 2e^4 + e^2 - 1).

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A right rectangular prism has length 10 in. And width 8 in. The surface area of the prism is 376 in2. What equation can be used to find the height in inches?

Answers

The equation to find the height is 376 = 160 + 20h + 16h.

The height of the right rectangular prism is 6 inches.

We have,

Let's denote the height of the right rectangular prism as "h" inches.

The formula for the surface area of a right rectangular prism is:

Surface Area = 2lw + 2lh + 2wh

Given that the length (l) is 10 inches and the width (w) is 8 inches, and the surface area is 376 square inches, we can substitute these values into the formula:

376 = 2(10)(8) + 2(10)(h) + 2(8)(h)

Simplifying this equation:

376 = 160 + 20h + 16h

Combine like terms:

376 = 160 + 36h

Rearranging the equation to isolate "h":

36h = 376 - 160

36h = 216

Finally, divide both sides of the equation by 36 to solve for "h":

h = 216/36

h = 6

Therefore,

The height of the right rectangular prism is 6 inches.

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Simplify the following using appropriate properties :
(a) [1/2 x 1/4 ]+[1/2 x6]
(b) [1/5 x 2/15] - [1/5 x 2/15]

I need step by step explanation please will mark as brainliest if you give good explanation

Answers

Step-by-step explanation:

(a) [1/2 x 1/4] + [1/2 x 6]

First, we can simplify each term separately:

1/2 x 1/4 = 1/8

1/2 x 6 = 3

Now, we can add these two simplified terms:

1/8 + 3 = 3 1/8

Therefore, [1/2 x 1/4] + [1/2 x 6] simplifies to 3 1/8.

(b) [1/5 x 2/15] - [1/5 x 2/15]

Both terms are the same, so when we subtract them, the result will be zero:

[1/5 x 2/15] - [1/5 x 2/15] = 0

Therefore, [1/5 x 2/15] - [1/5 x 2/15] simplifies to 0.

Find the divergence of vector fields at all points where they are defined.
div ( (2x^2 - sin(x2)) i + 5] - (sin(X2)) k)

Answers

The divergence of the given vector field at all points where it's defined is div [tex]F = 4x - 2x × cos(x^2).[/tex]

To find the divergence of the given vector field at all points where it's defined, we will use the following terms:

divergence, vector field, and partial derivatives.

The given vector field is[tex]F = (2x^2 - sin(x^2)) i + 5j - sin(x^2) k.[/tex]

To find the divergence of F (div F), we need to take the partial derivatives of each component with respect to their

respective variables and then sum them up. So, div [tex]F = (∂(2x^2 - sin(x^2))/∂x) + (∂5/∂y) + (∂(-sin(x^2))/∂z)[/tex].

Find the partial derivative of the first component with respect to x:

[tex]∂(2x^2 - sin(x^2))/∂x = 4x - 2x × cos(x^2)[/tex] (applying chain rule).

Find the partial derivative of the second component with respect to y:

∂5/∂y = 0 (since 5 is a constant).

Find the partial derivative of the third component with respect to z:

[tex]∂(-sin(x^2))/∂z = 0[/tex] (since there is no z variable in the component).

Sum up the partial derivatives:

[tex]div F = (4x - 2x × cos(x^2)) + 0 + 0 = 4x - 2x × cos(x^2).[/tex]

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People were asked if they were considering changing what they eat.29% of the people asked said yes.of these, 23% said they were considering becoming vegetarian.what percentage of the people asked said they were considering becoming vegetarian?

Answers

Answer:

66.7%

Step-by-step explanation:

Let people asked bye x.

Then, people considering to change = 29% of x

People considering to become vegetarians = 23% of (29% of x)

                                                                          = 23/100 * 29x/100

                                                                          = 667x/10000

Percentage of people considering to become vegetarians = 667x/10

                                                                                                  = 66.7%

Can somebody help me really quickly please

Answers

Answer: 77

Step-by-step explanation:

Bigger Rectangle = LW  = 5x5 =25 There are 2 of those. =50

middl rectangle = LW = 5x3=15

triangles= 1/2 b h = 1/2 (3)(4) = 6 but therere are 2 so =12

Add up all shapes=50+15+12=77

If a side of a square is doubled and an adjacent side is diminished by 3, a rectangle is formed whose area is numerically greater than the area of the square by twice the original side of the square. Find the dimensions of the original square

Answers

The dimensions of the original square is 8 by 8.

Let x be the original side length of the square. The area of the square is x². When one side is doubled and the adjacent side is diminished by 3, the rectangle's dimensions become 2x and (x-3). The area of the rectangle is (2x)(x-3) = 2x² - 6x.

According to the problem, the area of the rectangle is greater than the area of the square by twice the original side of the square, which is 2x. So we can set up the equation:

2x² - 6x = x² + 2x

Now, solve for x:

2x² - x² = 6x + 2x
x² = 8x
x = 8

So the dimensions of the original square are 8 by 8.

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Which of theses is a rectangle pentagon, trapezoid, square, rhombus

Answers

Among the given options, the square is a rectangle.

To determine which of these is a rectangle, we will consider the properties of a rectangle and compare them with the properties of a pentagon, trapezoid, square, and rhombus.

A rectangle is a quadrilateral with four right angles and opposite sides equal in length.

1. Pentagon: A pentagon has five sides and cannot be a rectangle since a rectangle must have four sides.


2. Trapezoid: A trapezoid has one pair of parallel sides, but it does not have four right angles, so it cannot be a rectangle.


3. Square: A square has four equal sides and four right angles, making it a special type of rectangle. Therefore, a square is a rectangle.


4. Rhombus: A rhombus has four equal sides but does not necessarily have four right angles, so it is not a rectangle.

In conclusion, among the given options, the square is a rectangle.

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PLEASE HELP WILL MARK BRANLIEST !!!

Answers

If password begin with capital letter followed by lower case letter, and end with symbol , then the number of unique passwords which can be created using letters and symbols are 47525504.

The password must have 6 characters and the first character must be a capital letter, so, we have 26 choices for the first character.

For the second character, we have 26 choices for a lower-case letter.

For the third, fourth, and fifth characters, we can choose from any of the 26 letters (upper or lower case).

For the last character, we have 4 choices for the symbol

So, total number of unique passwords that can be created is:

⇒ 26 × 26 × 26 × 26 × 26 × 4 = 26⁵ × 4 = 47525504.

Therefore, there are 47525504 unique passwords that can be created using these letters and symbols.

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what are the values of m and n, and what does the plotted graph look like?

Answers

The values of m and n are

m = 0 and n = 3.125

The graph is attached

How to find the values of m and n

The values of m and n are solved using the relationship between miles and kilometers. This type of relationship is a linear proportional relationship. Linear relationship implies the graph will be a straight line graph.

This relationship is that 1 mile equals 0.625 km hence the linear equation is

y = 0.625x

when x = 0, we have that

y = 0.625 * 0

y = 0

when x = 5, we have that

y = 0.625 * 5

y = 3.125

Where x is kilometers and y is miles

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D is the centroid of PQR PA= equals 17 BD equals nine and DQ equals 14 find each missing measure

Answers

The centroid of the triangle is D and the measures of sides are solved

Given data ,

Let the triangle be represented as ΔPQR

Now , the centroid of the triangle is D

where the measure of PA = 17 units

The measure of BD = 9 units

And , the measure of side DQ = 14 units

Now , centroid of a triangle is formed when three medians of a triangle intersect

And , from the properties of centroid of triangle , we get

PA = AR

DR = DQ

AD = BD

On simplifying , we get

The measure of side AR = 17 units

PR = PA + AR = 34 units

The measure of side DR = 14 units

BR = BD + DR = 23 units

The measure of side AD = 9 units

AQ = AD + DQ = 23 units

Hence , the centroid is solved

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10. Determine the line of regression and use it to find the best predicted new mileage rating of a ( point) four-wheel-drive vehicle given that the old rating is 19 mi/gal old 6 27 1 33 28 24 8 22 20 29 21 New 15 24 15 29 25 22 6 20 826 19 Oy 0.808 0.863x; 18.1 mi/gal Oy = 0.863 + 0.808x; 16.2 mi/gal oy 0.863 + 0.808x; 22.4 mi/gal y-0.808+ 0.863x; 17.2 mi/gal

Answers

The line of regression equation for the mileage rating of a ( point) four wheel drive vehicle is [tex]\hat y = 16.111 + 0.365x,[/tex] and the best predicted new mileage rating of a ( point) four-wheel drive vehicle when x = 19 mi/gal, is equals to the 23.046 mi/gal. So, option(b) is right one.

A linear regression line has an equation of the form [tex]\hat y = a + bx,[/tex]

where x is the independent variable and y is the dependent variable. The slope of the line is b, and a is the estimated intercept (the value of y when x = 0). We have a table form data of old and new rating of four-wheel-drive vehicles. We have to determine the line of regression. Now, we have to calculate the value of 'a' and 'b'. Let the old and new mileage rating of four-wheel-drive vehicles be represented by vaiables 'x' and 'y'. Using the following formulas, [tex]b =\frac{ S_{xy}}{S_{xx}}[/tex] where, [tex]S_{xx} = \sum x² - \frac{ (\sum x)² }{n} [/tex]

[tex]S_{xy} = \sum xy - \frac{ (\sum y \sum x) }{n}[/tex][tex]a = \bar y - b \bar x,[/tex]

where , [tex]\bar x = \frac{\sum x }{n}[/tex]

[tex]\bar y = \frac{\sum y }{n}[/tex]

Here, n = 11, [tex]\sum x[/tex] = 235

[tex]\sum xy[/tex] = 263, [tex]\sum x²[/tex] = 5733, [tex]\sum xy[/tex] = 5879, so

[tex]S_{xx}[/tex] = 5733 - (235)²/11

= 5733 - 5020.454 = 712.546

[tex]S_{xy}[/tex] = 5879 - (235×263)/11

= 260.364

Now, b = 260.364/712.546 = 0.365

a = (263/11) - 0.365 ( 235/11)

= 23.909 - 7.798

= 16.111

So, regression line equation is

[tex]\hat y = 16.111 + 0.365x,[/tex]

The best predicted value of y, when x = 19 mi/gal, [tex]\hat y = 19× 0.365 + 16.111[/tex]

=23.046 mi/gal

Hence, the best predicted value is

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Complete question:

10. Determine the line of regression and use it to find the best predicted new mileage rating of a ( point) four-wheel-drive vehicle given that the old rating is 19 mi/gal

old 6 27 17 33 28 24 8 22 20 29 21

New 15 24 15 29 25 22 6 20 82 6 19

a) y cap = 0.863 + 0.808x; 16.2 mi/gal

b) y cap = 16.111 + 0.365x; 23.04 mi/gal

c) y cap =0.808+ 0.863x; 17.2 mi/gal

d) y cap = 0.808 0.863x; 18.1 mi/gal

Which term can be put in the blank to make the statement below true?
3,000,000=30________________
A. Thousands
B.Ten-Thousands
C.Hundred-Thousands
D.Millions

Answers

The correct answer is D. Millions.

If we add "millions" to the blank, the statement becomes "3,000,000 = 30 millions," which is a true statement.

Determine the specified confidence interval. An organization advocating for healthcare reform has estimated the average cost of providing healthcare for a senior citizen receiving Medicare to be about $13,000 per year. The article also stated that, with 90% confidence, the margin or error for the estimate is $1,000. Determine the resulting 90% confidence interval for the average cost for healthcare of a senior citizen receiving Medicare

Answers

the resulting 90% confidence interval for the average cost for healthcare of a senior citizen receiving Medicare  is [$12,000, $14,000].

The estimated average cost of providing healthcare for a senior citizen receiving Medicare is $13,000 per year, and the margin of error for this estimate is $1,000 with a 90% confidence level.

To find the confidence interval, we need to add and subtract the margin of error from the estimated mean.

Lower Limit = Estimated Mean - Margin of Error

Lower Limit = 13,000 - 1,000

Lower Limit = 12,000

Upper Limit = Estimated Mean + Margin of Error

Upper Limit = 13,000 + 1,000

Upper Limit = 14,000

Therefore, the resulting 90% confidence interval for the average cost for healthcare of a senior citizen receiving Medicare is [$12,000, $14,000]. This means we are 90% confident that the true mean cost of providing healthcare for a senior citizen receiving Medicare is between $12,000 and $14,000 per year.

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PART 2:
The regular price, in dollars, the gym charges can be represented by the equation y=15x+20
B.How much money, in dollars, does justin save the first month by joining the gym at the discounted price rather than at the regular price?

Answers

The amount of money Justin saves in the first month would be 5 times the value of x, where x represents the number of months of gym membership, based on the discounted price provided.

What is the linear equation?

A linear equation is an equation in mathematics that represents a relationship between two variables that is a straight line when graphed on a coordinate plane. It is an equation of the form:

y = mx + b

To calculate the amount of money Justin saves in the first month by joining the gym at the discounted price rather than the regular price, we need to know the discounted price.

The equation given is y = 15x + 20, where y represents the regular price in dollars and x represents the number of months of gym membership. However, we need to know the discounted price, which is not provided in the given information.

Once we have the discounted price, we can substitute it into the equation and calculate the savings. For example, if the discounted price is y = 10x + 20, then we can calculate the savings by subtracting the discounted price from the regular price:

Savings = Regular price - Discounted price

= (15x + 20) - (10x + 20)

= 15x - 10x

= 5x

Hence, the amount of money Justin saves in the first month would be 5 times the value of x, where x represents the number of months of gym membership, based on the discounted price provided.

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f(x,y) = x2 + y² + xy {(x, y) : x2 + y2 < 1}
"Find the maxima and minima, and where they are reached, of the
following function. Find the locals and absolutes. Identify the
critical points inside the disk if any."

Answers

The given function f(x,y) = x^2 + y^2 + xy has a maximum value of 3/4 at (x,y) = (1/2,1/2) and a minimum value of -1/4 at (x,y) = (-1/2,1/2) inside the disk x^2 + y^2 < 1. There are no critical points inside the disk.

To find the critical points, we need to take partial derivatives of the function with respect to x and y and solve the resulting equations simultaneously.

fx = 2x + y = 0

fy = 2y + x = 0

Solving these equations, we get the critical point at (x,y) = (-1/2,-1/2) outside the disk. Hence, we do not consider it further.

Next, we need to find the boundary points of the disk, which is the circle x^2 + y^2 = 1. We can parameterize this circle as x = cos(t) and y = sin(t), where t ranges from 0 to 2π.

Substituting these values in the given function, we get:

f(cos(t), sin(t)) = cos^2(t) + sin^2(t) + cos(t)sin(t)

= 1/2 + 1/2sin(2t)

Now, we need to find the maximum and minimum values of this function. Since sin(2t) ranges from -1 to 1, the maximum value of the function is 3/4 when sin(2t) = 1, i.e., when t = π/4 or 5π/4. At these points, x = cos(π/4) = 1/2 and y = sin(π/4) = 1/2.

Similarly, the minimum value of the function is -1/4 when sin(2t) = -1, i.e., when t = 3π/4 or 7π/4. At these points, x = cos(3π/4) = -1/2 and y = sin(3π/4) = 1/2.

Therefore, the function has a maximum value of 3/4 at (x,y) = (1/2,1/2) and a minimum value of -1/4 at (x,y) = (-1/2,1/2) inside the disk x^2 + y^2 < 1. There are no critical points inside the disk.

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Stan's Car Rental charges $35 per day plus $0. 25 per mile. Denise wants to rent one of Stan's cars, keeping the total

cost of the rental to no more than $55. What is the greatest number of miles Denise can drive the

car to stay within her budget?

O A) 75 miles

O B) 80 miles

O c) 90 miles

OD) 100 miles

Answers

Denise can drive at most 80 miles to stay within her budget of $55.

Let's assume that Denise drives x miles during the rental period. Then the total cost of the rental will be:

Total cost = $35 (flat rate for the day) + $0.25 per mile x (number of miles driven)

We want to find the greatest number of miles that Denise can drive and still stay within her budget of $55, so we can set up an inequality as follows:

Total cost ≤ $55

$35 + $0.25x ≤ $55

Subtracting $35 from both sides

$0.25x ≤ $20

Dividing both sides by $0.25

x ≤ 80

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A regular pentagonal prism has an edge length 9 m, and height 13 m. Identify the volume of the prism to the nearest tenth

Answers

The volume of the regular pentagonal prism with an edge length of 9 m and a height of 13 m is approximately 1811.6 m³ to the nearest tenth.

To find the volume of a regular pentagonal prism with an edge length of 9 m and a height of 13 m, follow these steps:

Step 1: Find the apothem (a) of the base pentagon. Use the formula a = s / (2 * tan(180/n)), where s is the edge length and n is the number of sides (5 for a pentagon).

a = 9 / (2 * tan(180/5))
a ≈ 6.1803 m

Step 2: Calculate the area (A) of the base pentagon. Use the formula A = (1/2) * n * s * a.

A = (1/2) * 5 * 9 * 6.1803
A ≈ 139.3541 m²

Step 3: Determine the volume (V) of the pentagonal prism. Use the formula V = A * h, where h is the height.

V = 139.3541 * 13
V ≈ 1811.6033 m³

So, the volume of the regular pentagonal prism with an edge length of 9 m and a height of 13 m is approximately 1811.6 m³ to the nearest tenth.

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A telephone pole has a wire attached to its top that is anchored to the ground. the distance from the bottom of the pole to the anchor point is
69 feet less than the height of the pole. if the wire is to be
6 feet longer than the height of the pole, what is the height of the pole?

Answers

A telephone pole has a wire attached to its top that is anchored to the ground then conclude the height of the pole is approximately 51.53 feet.

Let h be the height of the pole. The equation h = (h - 69) + 6 represents the given information. Solving it gives h = 75.

Let's denote the height of the pole as "h". Then, according to the problem, the distance from the bottom of the pole to the anchor point is 69 feet less than the height of the pole, which means it is h - 69. Additionally, the wire is to be 6 feet longer than the height of the pole, so its length is h + 6.

Now we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (in this case, the wire) is equal to the sum of the squares of the lengths of the other two sides (in this case, the height of the pole and the distance from the bottom of the pole to the anchor point). So we have:

(h - 69)^2 + h^2 = (h + 6)^2

Expanding and simplifying, we get:

h^2 - 138h + 4761 + h^2 = h^2 + 12h + 36

Rearranging and simplifying, we get:

h^2 - 75h - 1602 = 0

We can solve for h using the quadratic formula:

h = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 1, b = -75, and c = -1602.

Plugging in these values, we get:

h = (75 ± sqrt(75^2 - 4(1)(-1602))) / 2(1)

h ≈ 51.53 or h ≈ -31.53

Since the height of the pole cannot be negative, we can ignore the negative solution and conclude that the height of the pole is approximately 51.53 feet.

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Shelby multiplies 7,358.9 by a power of 10 and gets the product
73.589. select all possible factors.

(a) 1/100 "fraction"

(b) 1/10 "fraction"

(c) 1

(d) 0.1

(e) 0.01

(f) 0.001

Answers

(a) 1/100 (or 0.01)

(e) 0.01

This factor represents dividing the number by 100.

When Shelby multiplies 7,358.9 by a power of 10 and gets the product 73.589, we can determine the factor by comparing the two numbers.

7,358.9 → 73.589

We can see that the decimal point has moved two places to the left. Therefore, the factor is the one that will shift the decimal point two places to the left. Among the given options, the factor that does this is:

(a) 1/100 (or 0.01)

(e) 0.01

This factor represents dividing the number by 100. The other options (b, c, d, and f) do not represent the correct division by powers of 10 in this case.

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A manufacturer makes aluminum cups with a volume of 10 cubic centimetres cach, in the form of right circular cylinders open at the top. Find the dimensions that would require the least amount of material.

Answers

The dimensions that require the least amount of material are r = (10/π)^(1/3) cm for the radius and h = (10/π)^(1/3) cm for the height.

To minimize the amount of material used for making aluminum cups with a volume of 10 cubic centimeters, you will need to optimize the dimensions of the right circular cylinders.

Given the volume (V) is 10 cm³, the formula for the volume of a right circular cylinder is V = πr²h, where r is the radius and h is the height.

10 = πr²h

To minimize the material used, we want to minimize the surface area (SA) of the open cylinder, which is given by the formula SA = 2πrh + πr² (the first term represents the lateral surface and the second term the base).

Using the volume formula, we can find a relationship between r and h:

h = 10 / (πr²)

Now substitute this expression for h in the surface area formula:

SA(r) = 2πr(10 / (πr²)) + πr²
SA(r) = 20/r + πr²

To find the minimum surface area, differentiate SA(r) with respect to r and set the result equal to zero:

d(SA)/dr = -20/r² + 2πr

Now solve for r:

0 = -20/r² + 2πr
20/r² = 2πr
r³ = 10/π

Now take the cube root of both sides:

r = (10/π)^(1/3)

To find the height, substitute this value of r back into the expression for h:

h = 10 / (π((10/π)^(1/3))²)
h = (10/π)^(1/3)

The dimensions that require the least amount of material are r = (10/π)^(1/3) cm for the radius and h = (10/π)^(1/3) cm for the height.

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A store has `80` pumpkins for sale. Here are the values of the quartiles. About how many of the `80` pumpkins would you expect to weigh less than `15.5` pounds

Answers

This is just a rough estimate, and the actual number of pumpkins that weigh less than 15.5 pounds could be slightly higher or lower.

What is the median?

The median is a measure of central tendency that represents the middle value in a dataset when the values are arranged in order of magnitude.

Assuming that the quartiles divide the pumpkins' weights into four equal parts, we can use the value of the second quartile (Q2) to estimate the median weight of the pumpkins. Since there are 80 pumpkins, Q2 would be the average of the 40th and 41st heaviest pumpkins.

We don't know the exact values of the quartiles, but we can make some reasonable assumptions. For example, if we assume that the first quartile (Q1) is around 12 pounds and the third quartile (Q3) is around 20 pounds, then we can estimate the median weight as follows:

Median = (Q2) = (Q1 + Q3)/2 = (12 + 20)/2 = 16 pounds

Based on this estimate, we can expect that roughly half of the 80 pumpkins (i.e., 40 pumpkins) weigh less than 16 pounds. Therefore, we might expect that slightly fewer than 40 pumpkins would weigh less than 15.5 pounds.

However, this is just a rough estimate, and the actual number of pumpkins that weigh less than 15.5 pounds could be slightly higher or lower depending on the distribution of the pumpkin weights.

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Pythagorean Theorem answer quick please

Answers

Answer:

3.9

Step-by-step explanation:

pythagorean theorem states:

[tex]a^{2} +b^{2} =c^{2}[/tex]

We know that a is the height of the triangle, 2.

We also know that b is the base of the triangle, 3.

So, solve for c:

2²+3²=c²

simplify

4+9=c²

15=c²

take the square root of both sides

c=3.9

So, the spider and the fly are 3.9 ft apart from each other

Hope this helps :)

Answer:

3.6 feet

Step-by-step explanation:

The Pythagorean theorem states that a^2+b^2=c^2, where c is the hypotenuse, or longest side of the triangle opposite to the right angle, and a and b are the two legs of the triangle (the other two sides.)

In the question, sides a and b are given as 2ft and 3ft long. Plugging 2 and 3 into the equation, we will get that 2^2+3^2=c^2. 2 x 2 = 4 and 3 x 3 = 9, so 4 + 9 = c^2, or, c^2 = 13.

However, this is still c^2, not c, so we must take the square root of both sides. This is because the equation is now essentially saying that c x c = 13, so if we find a number that when multiplied by itself equals 13, that number will be c. to do this, we must take the square root of 13. This will give us an irrational number- approximately 3.605551275. The question asks to round it to the nearest tenth though, so this will simply become 3.6.

In the context of this question, it means that the spider and the fly are 3.6ft apart.

Which correctly describes how to graph the equation shown below?
y=1/4x
Start with a point at (1, 4). Then go up 1 and 4 to the right.
Start with a point at (1, 4). Then go up 4 and 1 to the right.
Start with a point at (0, 0). Then go up 4 and 1 to the right.
Start with a point at (0, 0). Then go up 1 and 4 to the right.

Answers

The statement which correctly describes how to graph the equation shown above include the following: Start with a point at (0, 0). Then go up 1 and 4 to the right.

What is a translation?

In Mathematics, the translation a geometric figure or graph to the right simply means adding a digit to the value on the x-coordinate of the pre-image while the translation a geometric figure or graph upward simply means adding a digit to the value on the y-coordinate (y-axis) of the pre-image.

In Mathematics and Geometry, the translation a geometric figure upward simply means adding a digit to the value on the positive y-coordinate (y-axis) of the pre-image;

g(x) = f(x) + N

g(x) = y = 1/4(x)

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Garden plots in the Portland Community Garden are rectangles limited to 45 square meters. Christopher and his friends want a plot that has a width of 7.5 meters. What length will give a plot that has the maximum area allowed?

Answers

The length that will give a plot with the maximum area allowed is 6 meters.

To find the length that will give a plot with the maximum area, we need to use the formula for the area of a rectangle, which is A = lw, where A is the area, l is the length, and w is the width. In this case, we are given that the area is 45 square meters, and the width is 7.5 meters.

Substituting these values into the formula, we get:

45 = l(7.5)

To solve for l, we divide both sides by 7.5:

l = 45/7.5

Simplifying, we get:

l = 6

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