Answer:
f = c / y where y is the wavelength lambda
y = 3.00E8 / 5.17E14/s = 5.80E-7 m = 580 millimicrons - visible yellow
To calculate the wavelength of the radiation, you can use the formula that relates the speed of light (c) to the frequency (f) and wavelength (λ) of electromagnetic waves: λ = c / f.
Where:
λ = Wavelength
c = Speed of light (approximately 3.00 x 10^8 m/s)
f = Frequency
Given that the frequency (f) is 5.17 x 10^14 s^-1, you can plug in the values and calculate the wavelength:
λ = (3.00 x 10^8 m/s) / (5.17 x 10^14 s^-1)
λ ≈ 5.80 x 10^-7 meters
So, the wavelength of the radiation is approximately 5.80 x 10^-7 meters, which is in the range of the visible light spectrum (typically measured in nanometers).
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F = kx
k = ?
Select one:
a. F/x
b .x/F
c. F + x
d. F − x
Answer:
[tex]F = kx \\ k = \frac{F }{x} [/tex]
so the answer is a
car accelerates at a rate of 4.00 m/s?. How long will it take the car to speed up from 20 m/s to 50 m/s?
The distance that will take the car to speed yup from 20m/s to 50m/s is 262.5 meters
The first step is to write out the parameters given in the question are
acceleration= 4
initial velocity= 20
final velocity= 50
The distance can be calculated as follows
V²= U² + 2as
50²= 20² + 2(4)(s)
2500= 400= 8s
2500-400= 8s
2100= 8s
s= 2100/8
s= 262.5 meters
Hence the distance is 262.5 meters
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From the definition of acceleration, the time it will take the car to speed up is 7.5 seconds
Given that a car accelerates at a rate of 4.00 m/s^2. To calculate how long it will take the car to speed up from 20 m/s to 50 m/s, let us first mark out the needful parameters.
Acceleration a = 4 m/[tex]s^{2}[/tex]
Initial velocity U = 20 m/s
Final Velocity V = 50 m/s
Time t = ?
From the definition of acceleration, acceleration is the rate of change of velocity. That is,
a = (V - U)/ t
Substitute all the parameters into the formula above.
4 = ( 50 - 20) / t
Cross multiply
4t = 30
Make t the subject of formula
t = 30/4
t = 7.5 t
Therefore, the time it will take the car to speed up is 7.5 seconds
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If 8.90 kg of ice at -5.00°C is added to 12.0 kg of water at 15°C, compute the final temperature.
(in deg C)
How much ice remains, if any? (in Kg)
Answer:
6.93 kg
Explanation:
m1 = 8.90 kg
T1 = -5°C
m2 = 12 kg
T2 = 15°C
constant needed:
c (ice) = 2100 J/kg °C
c (water) = 4200 J/kg °C
L (Latent Heat) = 336 000 J/kg
Black Principle
Q (release) = Q (absorbs)
Q (release) max = m2 c(water) ∆T2
Q (release) max = 12 x 4200 x (15-0)
Q (release) max = 756 000 J
Q (absorbs) = m1 c(ice) ∆T1 + m1 L
Q (absorbs) = 8.9 x 2100 x (0-(-5)) + 8.9 x 336 000
Q (absorbs) = 93 450 + 2 990 400 = 3 083 850 J
since Q (absorbs) is much much bigger than Q (release), only a few litlle ice melting. So we need to see how much ice melting and how many left.
Q (release) - Q (absorbs) ice -5°C to ice 0°C = 756000 - 93450 = 662550
mass of melting Ice
Q (absorbs) melting ice = m(melting) L
662 550 = m(melting x 336 000
m (melting) = 662 500/336 000
m (melting) = 1.977 kg
so the ice remains is 8.90 - 1.97 = 6.93 kg
A steam pipe is covered with 1.50-cm thick insulating material of thermal conductivity of 0.200 cal/cm · °C · s. How much energy is lost every second when the steam is at 195°C and the surrounding air is at 20.0°C? The pipe has a circumference of 800 cm and a length of 40.0 m. Neglect losses through the ends of the pipe.
This question involves the concepts of Fourier's law of heat conduction and heat loss per unit time.
The heat energy loss per second is "3.12 x 10⁸ W".
Applying Fourier's Law of Heat Conduction here, we get:
[tex]Q = -kA\frac{\Delta T}{\Delta x}[/tex]
where,
Q = heat energy loss per unit time = ?
k = thermal conductivity = 0.2 cal/cm.°C.s [tex](\frac{4.184\ J}{1\ cal})(\frac{100\ cm}{1\ m})[/tex] = 83.68 J/m.°C.s
A = Surface area = (circumference)(length) = (8 m)(40 m) = 320 m²
ΔT = difference in temperature = 20°C - 195°C = -175°C
Δx =thickness of insulation = 1.5 cm = 0.015 m
Therefore,
[tex]Q = -(83.68\ J/m.^oC.s)(320\ m^2)(\frac{-175\ ^oC}{0.015\ m})\\\\[/tex]
Q = 3.12 x 10⁸ W = 312 MW
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The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where section 1 ends and section 2 begins. A block of M is placed at different locations on the incline. The coefficients of kinetic and static friction between the block and each section are shown in the table below.
If the block is at rest on section 1 of the incline, what is the magnitude of the force of static friction exerted on the block by the incline?
The static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex].
The given parameters;
mass of the block, = Mcoefficient of static friction in section 1, = [tex]\mu_s_1[/tex]angle of inclination of the plane, = θThe normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
[tex]F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta[/tex]
Thus, the static friction exerted on the block by the incline is [tex]\mu _ s _1 Mgcos \ \theta[/tex]
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If an astronaut was on a planet 9*10^10 meters away, how long would it take a radio signal (in seconds) to travel from them to Earth? (Be sure to give your answer to two decimal places)
The time taken a radio signal to travel form the given distance to Earth is [tex]2.65 \times 10^8 \ s[/tex].
The given parameters;
distance between the astronaut and Earth, d = 9 x 10¹⁰ mThe time taken a radio signal to travel form the given distance to Earth is calculated by using Echo formula as shown below;
[tex]2d = v \times t\\\\t = \frac{2d}{v}[/tex]
where;
v is the speed of sound sound in air = 340 m/st is the time taken for the signal to be heard (to and fro)The time taken for the signal to travel in a single forward motion is calculated as;
[tex]t = \frac{1}{2} \times \frac{2d}{v} = \frac{d}{v} \\\\t = \frac{9\times 10^{10}}{340} \\\\t = 2.65 \times 10^8 \ s[/tex]
Thus, the time taken a radio signal to travel form the given distance to Earth is [tex]2.65 \times 10^8 \ s[/tex].
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Hello, I wanted an answer from a mathematician. The number 1.04 is closer to the number 1, 2, 1.25 or 1.5.
Answer:
Explanation:
Of the 4 numbers given, the answer is 1 or A
If you take the absolute value of abs(1 - 1.04) you get 0.04.
(2 - 1.04) = 0.96
1.25 - 1.04 = .21
1.5 - 1.04 = 0.46
The last three are all larger than 0.04
Note: absolute value means the positive difference between 2 numbers (even though it is negative). If it is negative, absolute value makes it positive.
Find the maximum possible coefficient of performance for a heat pump used to heat a house in a northerly climate in winter
Answer:
[tex]COP_{Heating}[/tex][tex]= \frac{T_{H}}{T_{H}-T_{C} }[/tex]
The temperature must be in Kelvin: [tex]degrees Celsius+273.15=K[/tex].
Explanation:
COP is similar to efficiency: [tex]\frac{what you get}{what you pay}[/tex] = [tex]\frac{energy from hot reservoir}{work needed for energy transfer}[/tex]
The maximum possible coefficient of performance (COP) for a heat pump is equal to 7.32.
What is the coefficient of performance of a heat pump?The coefficient of performance can be described as the relationship between the power (kW) that is supplied to the compressor and the power (kW) that is drawn out of the heat pump as cooling or heat.
The coefficient of performance of a heat pump or air conditioning system is a ratio of useful heating or cooling provided to work or energy required. The COP usually exceeds 1, it pumps extra heat from a heat source to where the heat is needed.
Assume that the temperature of the hot reservoir is [tex]T_H[/tex] and the temperature of the cold reservoir is [tex]T_c[/tex].
The temperature of the hot reservoir, T[tex]_H[/tex] = 20° C = 20 + 273 = 293 K
The temperature of cold reservoir, [tex]T_C[/tex] = -20°C = 273 -20 = 253 K
The equation of the maximum possible coefficient of performance for a heat pump is as follows:
[tex]COP_{max}= \frac{T_H}{T_H-T_c}[/tex]
[tex]COP_{max } = \frac{293}{293-253}[/tex]
COP = 7.32
Therefore, the maximum possible coefficient of performance for a heat pump is 7.32.
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Your question is incomplete, most probably the complete question was,
Find the maximum possible coefficient of performance for a heat pump used to heat a house in a northerly climate in winter. The inside is kept at 20°C and the outside is -20°C.
Compare and contrast the different parts of the Electromagnetic Spectrum. Evaluate the usefulness of each part and decide which part is most useful, or most important, to you and society as a whole. You must provide two reliable sources to back up your opinion. Recall that reliable sources include scientific sites or publications, education sites or publications, and government sites or publications.
Answer:
Think in your Mind
Explanation:
if you do you will have a better understanding of what you're doing
you could study you could ask a parent or guardian
or maybe stop looking up answer and expect other people breaking thier heads doing this
Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s. A girl pushes a 21 kg lawn mower as shown in the figure
a)If F = 32 N and θ = 45 ∘ what is the acceleration of the mower? Ignore friction.
b)What is the normal force exerted on the mower by the lawn?
Newton's second law allows us to find the result for the acceleration of the mower is:
a = 0.8 m / s²
Newton's second law says that the net force is proportional to the mass and the acceleration of the bodies.
∑ F = m a
where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the bodies.
A free-body diagram is a schematic where the forces are drawn if the details of the bodies, see attached.
Let's write Newton's equation.
x-axis
Fₓ = ma
y-axis
N - F_y - w = 0
Let's use trigonometry to find the components of the force.
Cos 45 = [tex]\frac{F_x}{F}[/tex]
sin 45 = [tex]\frac{F_y}{F}[/tex]
Fₓ = F cos 45
F_y = F sin 45
Let's substitute.
F cos 45 = m a
a = [tex]\frac{F \ cos45}{m}[/tex]
Let's calculate.
a = [tex]\frac{32 \ cos 45}{21}[/tex]
a = 0.8 m / s²
In conclusion using Newton's second law we can find the result for the acceleration of the mower is:
a = 0.8 m / s²
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The acceleration of the mower is 1.1m/s^2. The normal force exerted on the mower by the lawn is 145.5 N.
a) The force that moves the lawn mower in the horizontal direction is Fcosθ.
Where;
F = 32 N
θ = 45∘
Effective force that moves the mower forward = 32 N cos 45∘ = 22.6 N
Now;
F = ma
m = mass of the lawn mower
a = acceleration
a = F/m
a = 22.6 N/21 kg
a = 1.1 m/s^2
b) The normal force = mgcosθ
FN = 21 kg × 9.80 m/s × cos 45 ∘
= 145.5 N
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Suppose an object is traveling in a circle of radius 10 m. if the object has a period of 6 s, what is its orbital speed (in m/s)
The orbital speed of the object moving around the circle is 10.5 m/s
Speed is the ratio of total distance to total time taken. Speed is given by:
Speed = distance / time
Given that the object is traveling in a circle of radius 10 m. The distance along the circle is:
Distance along circle = 2π * radius = 2π * 10 m = 62.83 m
The orbital speed = distance / time = 62.83 m / 6s = 10.5 m/s
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What is being transferred as you do work?
A. Energy
B. Power
C. Heat
D. Strength
[tex]\huge\bold{\purple{\bold{⚡A. Energy⚡}}} [/tex]
[tex]\huge\underline\mathtt\colorbox{cyan}{Reason:}[/tex]
When a force causes a body to move, work is done on the object by the force. Work is the measure of the energy transfer when a force 'F' moves an object through a distance 'd'. So we say that energy is transferred from one energy store to another when work is done, and therefore, energy transferred = work done.
no links never ever in the world give me a link just answer now without links What is the lithosphere? please write a full paragraph
Answer:
The lithosphere is the Earth's stable outer layer. The lithosphere is made from the brittle top mantle and the crust, which are the Earth's outermost layers. The atmosphere above it and the asthenosphere (another issue of the top mantle) underneath it define its limitations. even though the rocks of the lithosphere are nevertheless taken into consideration elastic, they may be not viscous. The asthenosphere is viscous, and the lithosphere-asthenosphere boundary (LAB) is the component in which geologists and rheologists—scientists who study the drift of depend—mark the difference in ductility among the 2 layers of the top mantle. Ductility measures a strong cloth’s ability to deform or stretch under strain. The lithosphere is a long way less ductile than the asthenosphere.
Explanation:
Plagarism checked, 100% unique [I think, if not sorryyyyeeeeee]
Hope this helps!
Byeeee have a nice day
I need HELP ASAP please!!!
Answer: A
Explanation:i took this one
Kaya is riding her dirt bike eastward on a dirt road. She spots a pothole ahead.
Kaya slows her car from 14.0 m/s to 5.5 m/s in 6.0 s. What is her acceleration?
Answer: The acceleration of Kaya is .
Explanation:
Answer:
Kaya's acceleration is 1.41666667.
Explanation:
To find the acceleration we need to subtract the starting speed to the slowed speed. So 14 - 5.5 = 8.5.
Now we divide 8.5 by the time, 6 seconds.
Our final answer is 1.41666667, or rounded, 1.42.
A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 280.5 meters from the wall and the sound of her voice travels at 340 m/s at that location. How long after she shouts will she hear her echo? (Be careful to consider why echoes happen.)
Answer:
4.80 seconds
Explanation:
The velocity of sound is obtained from;
V= 2d/t
Where;
V= velocity of sound = 329.2 ms-1
d= distance from the wall = 790.5 m
t= time = the unknown
t= 2d/V
t= 2 × 790.5/ 329.2
t= 4.80 seconds
The time is taken by the sound to reach the hiker will be t= 4.80 seconds
What is sound velocity?The sound velocity is defined as the distance traveled by the sound wave in a particular direction with respect to time.
The velocity of sound is given by the formula:
[tex]V=\dfrac{2d}{t}[/tex]
Here;
V= velocity of sound = 329.2 [tex]\frac{m}{s^2}[/tex]
d= distance from the wall = 790.5 m
t= time = the unknown
The time will be calculated as:
[tex]t=\dfrac{2d}{V}[/tex]
[tex]t=\dfrac{2\times 790.5}{329.2}[/tex]
[tex]t=4.80\ seconds[/tex]
Hence the time is taken by the sound to reach the hiker will be t= 4.80 seconds
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im board lolololololololololol
Answer:
noice me too U n U
Explanation:
Why did the brain name itself? 100 points
Answer:
In the remote past, people had no notion what function the brain has in the human organism. They saw “mush” and called it accordingly. Since brain was a borrowed word, those who began to use it, must at one time have had a native name for the content of heads.
does this help?
thanks for the points!
If the gas was instead in a cylinder with a floating, massless, frictionless piston, what would the volume of the gas be (in liters) at STP
The volume of the gas at standard temperature and pressure (STP) is 1,239.2 L.
The given parameters;
volume of the gas, V₁ = 9.5 Lpressure of the gas, P₁ = 140 atmtemperature of the gas, T₁ = 20 ⁰C = 273 + 20 = 293 Kpressure of gas at standard condition, P = 1 atmtemperature of gas at standard condition, T = 0⁰C = 273 KThe volume of the gas at standard condition is calculated by applying general gas law as shown below;
[tex]\frac{PV}{T} = \frac{P_1V_1}{T_1} \\\\V = \frac{P_1V_1T}{T_1P} \\\\V = \frac{140 \times 9.5 \times 273}{293 \times 1} \\\\V = 1,239.2 \ L[/tex]
Thus, the volume of the gas at standard temperature and pressure (STP) is 1,239.2 L.
"Your question is not complete, it seems be missing the following information;"
A compressed air tank carried by scuba divers has a volume of 9.5 L and a pressure of 140 atm at 20∘C.
If the gas was instead in a cylinder with a floating, massless, frictionless piston, what would the volume of the gas be (in liters) at STP.
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The chart shows data for a moving object.
Which conclusion is best supported by the information
in the chart?
Time (s)
Velocity (m/s)
2
4
6
8
8
8
O The object has negative displacement.
O The object has negative acceleration.
O The object does not have displacement
O The object is not accelerating
Mark this and return
Save and Exit
Next
Submit
Answer:
the object is not accelerating
please answer ASAP .
a body slides down an inclined plane which makes an angle of 30° with the horizontal, neglecting friction. calculate the velocity of the body after sliding 10 m from rest
Answer:
Explanation:
a = gsinθ
a = 9.8sin30
a = 4.9 m/s²
v² = u² + 2as
v² = 0² + 2(4.9)(10)
v² = 98
v = √98 = 9.8994949...
v = 9.9 m/s
A 100 Hz sound wave is traveling through the air. If we increase the frequency to 200 Hz, this will _____ the wavelength.
Answer:
reduce
Explanation:
It will reduce the wavelenth
The speed of a motorcycle changed from 5m/s to 20m/s the ratio of initial and final kinetic energy is?
Answer:
Explanation:
½m5² / ½m20² = 25/400 = 1/16 = 0.0625
The reaction is at dynamic equilibrium.
N2 + 3H2 = 2NH3
Which statement is correct?
(1 point)
a. The solution has the same concentrations of nitrogen gas and ammonia.
b. Nitrogen and hydrogen combine at the same rate that ammonia breaks down.
c. The solution has the same concentrations of nitrogen and hydrogen gases.
d. Both directions of the reaction have stopped.
Answer:
Nitrogen and hydrogen combine at the same rate that ammonia breaks down.
Explanation:
cells science crossword
where's the crossword?
3. How do you record your score in the 3-Minute Step Test? A record the 60-second heart rate before activity B. record the 30-second heart rate after the activity C. record the 60-second heart rate after the activity D. record the 60-second heart rate during7 the activity ?? plss po nid ko ngayon plsss free piont makakasagot neto
Answer:
d
Explanation:
you record it during the test
3. A ferry boat is 4.0 m wide and 6.0 m long. When a truck pulls onto it, the boat sinks 4.00 cm in the water. What is the weight of the truck?
Answer:
Explanation:
The weight of the truck will equal the weight of the displaced water.
Assuming fresh water and that the sides of the ferry are vertical,
The volume of the water displaced is
6.00(4.00)(0.0400) = 0.960 m³
that volume of water weighs
0.960 m³(1000 kg/m³)(9.81 N/kg) = 9,417.6 = 9.42 kN
How are the parts of birds and fish similar in structure and function?
Answer:
Birds and fish both have a backbone structure, which makes them structurally and functionally similar.
Explanation:
Where is a spinal tap usually taken?
This is between L3 and L4 and L4 and L5 of the lumbar Vertebrae of the vertebral column. The medical procedure is also called Lumbar Puncture, vertebral puncture.
The fluid collected is called Cerebrospinal fluid (CSF).It acts as shock absorber for the brain and spinal cord. It also contains some nutrients for these organs.
Procedure.
The patient or subject must lie by his side, and the knees draws up towards the chest. Alternatively, the subject can sit up or bent forward so that the vertebral column is bent and locations above revealed.
Then anesthesia is performed at the lower spine to neutralize the pain of the spine needle.
Finally, the spine needle is inserted between the L3 and L4 or L4 and L5 to draw a clear liquid; mostly water. This is CSF
The procedure may also be used to determine the pressure in the brain.
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What s the kinetic energy of a 0.100 kg baseball thrown at 20.0 m/s?
1: 40.0 J
2: 1.00 J
3: 2.00 J
4; 20.0 J
5: 4.00 J
Answer:
KE = ½mv² = ½(0.100)20.0² = 20.0 J
Explanation:
