A line has a slope of -


Which ordered pairs could be points on a line that is perpendicular to this line? Select


Which ordered pairs coul


two options

Answer:

Rate of speed = 480 feet per minutes

Step-by-step explanation:

Given:

Distance covered by bike = 960 feet

Time taken to covered distance = 2 minutes

Find:

Rate of speed = ?

Computation:

⇒ Speed = Distance / Time

⇒ Rate of speed = Distance covered by bike / Time taken to covered distance

⇒ Rate of speed = 960 / 2

⇒ Rate of speed = 480 feet per minutes

Answer:

Step-by-step explanation:

Mean = (11.4 + 13.9 + 11.2 + 14.5 + 15.2 + 8.1 + 12.4 + 8.6 + 10.5 + 17.1 + 9.8 + 15.9)/12 = 12.4

Standard deviation = √(summation(x - mean)²/n

n = 12

Summation(x - mean)² = (11.4 - 12.4)^2 + (13.9 - 12.4)^2 + (11.2 - 12.4)^2+ (14.5 - 12.4)^2 + (15.2 - 12.4)^2 + (8.1 - 12.4)^2 + (12.4 - 12.4)^2 + (8.6 - 12.4)^2 + (10.5 - 12.4)^2 + (17.1 - 12.4)^2 + (9.8 - 12.4)^2 + (15.1 - 12.4)^2 = 89.62

Standard deviation = √(89.62/13) = 2.7

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

a) For the null hypothesis,

µ ≤ 15

For the alternative hypothesis,

µ > 15

This is a right tailed test

b) Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 12,

Degrees of freedom, df = n - 1 = 12 - 1 = 11

t = (x - µ)/(s/√n)

Where

x = sample mean = 12.4

µ = population mean = 15

s = samples standard deviation = 2.7

t = (12.4 - 15)/(2.7/√12) = - 3.34

We would determine the p value using the t test calculator. It becomes

p = 0.0034

c) Assuming level of significance = 0.05.

Since alpha, 0.05 > than the p value, 0.0034, then we would reject the null hypothesis. Therefore, At a 5% level of significance, we can conclude that the water from this source does meets the EPA standard. They are higher than 15ppb

Using the t-distribution, we have that:

a)

The null hypothesis is: [tex]H_0: \mu \geq 15[/tex]

The alternative hypothesis is: [tex]H_1: \mu < 15[/tex]

b) The p-value is of 0.0051.

c) Since the p-value is of 0.0051, which is less than the standard significance level of 0.0051, it can be concluded that the mean is less than 15 ppb, and thus, this source meets the EPA standard.

Item a:

At the null hypothesis, it is tested if the mean is of at least 15 ppb, that is:

[tex]H_0: \mu \geq 15[/tex]

At the alternative hypothesis, it is tested if the mean is of less than 15 ppb, that is:

[tex]H_1: \mu < 15[/tex]

Item b:

We have the standard deviation for the sample, thus, the t-distribution is used. The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, we have that [tex]\mu = 15, n = 12[/tex]. Additionally, using a calculator, the other parameters are: [tex]\overline{x} = 12.38, s = 2.93[/tex]

Hence, the value of the test statistic is:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{12.38 - 15}{\frac{2.93}{\sqrt{12}}}[/tex]

[tex]t = -3.1[/tex]

The p-value is found using a left-tailed test, as we are testing if the mean is less than a value, with t = -3.1 and 12 - 1 = 11 df.

Item c:

Since the p-value is of 0.0051, which is less than the standard significance level of 0.0051, it can be concluded that the mean is less than 15 ppb, and thus, this source meets the EPA standard.

A similar problem is given at https://brainly.com/question/16194574

Answer:

A. -6 ≤ y ≤ 9

Step-by-step explanation:

→Looking at the graphed function, you can see that the line starts at when y = -6. Then the function slowly increases, until it finally stops when y = 9.

→This means that the range (y-values) of the function can be from -6 through 9.

The correct answer should be "A. -6 ≤ y ≤ 9."

Answer:

Volume of the machine part = 114π inches³

Step-by-step explanation:

Volume of the machine part = Volume of cylinder + Volume of hemisphere

Volume of cylinder = [tex]\pi r^{2}h[/tex]

Where r = radius of the cylinder

h = height of the cylinder

Volume of the cylinder = [tex]\pi(\frac{6}{2})^{2}(12)[/tex]

                                      = 108π inches³

Volume of the hemisphere = [tex]\frac{2}{3}\pi r^{3}[/tex]

                                             = [tex]\frac{2}{3}\pi (3)^{3}[/tex]

                                             = 6π inches³

Total area of the machine part = 108π + 6π

                                                   = 114π inches³

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

[tex]\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3[/tex]

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

[tex]H_0 :[/tex]  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

[tex]H_a:[/tex]  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

Answer:g=0 is not the solution

Step-byd-step explanation:

-1 1/2 is a negative number and 0 is not negative

Answer:

g=0

Step-by-step explanation:

happy to help ya :)

Answer:

1. 0.5 L; 2. 5.00 L  

Step-by-step explanation:

V = 5.00 - 0.5n

If you include units, the equation becomes

V(in litres) = 5.00 L - (0.5 L/day) × (n days)

1. Rate of evaporation

When you include the units, it becomes easier to see that the water is evaporating at a rate of 0.5 L/day.

That is, 0.5 L of water evaporates each day.

The negative sign shows that the volume of water is decreasing.

2. Volume at the beginning

At the beginning of the experiment, n = 0. Then

V = 5.00 -0.5×0 = 5.00 - 0 = 5.00 L

The bucket originally contained 5.00 L of water.

Answer:

all real numbers

Step-by-step explanation:

The domain is the input values

All values for x are valid as inputs to the function

Answer:

if the diagonals of a parallelogram are congruent, then it's a rectangle (neither the reverse of the definition nor the converse of a property). If a parallelogram contains a right angle, then it's a rectangle (neither the reverse of the definition nor the converse of a property).

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

C^2= A^2 + B^2

C^2 = (60)^2 + (25)^2

C^2 = 4225

Take the square root of C

C = 65

Answer:

65

Step-by-step explanation:

Use the Pythagorean Theorem to find the length of the hypotenuse.

[tex]a^2+b^2=c^2[/tex]

I'm assuming that '60' and '25' are measures of the legs, since the question asks to find the hypotenuse.

[tex]60^2+25^2=c^2\\\rightarrow 60^2=3600\\\rightarrow 25^2 = 625\\3600+625=c^2\\4225=c^2\\\sqrt{4225}=\sqrt{c^2}\\\boxed{65=c}[/tex]

The hypotenuse should measure 65 units.

Well lets see.

[tex]3(x+4)=3x+4\implies 12 = 4\implies x\notin\mathbb{C}[/tex].

There are no such x-es that satisfy the equation.

Answer:

[tex]4x -y = 5[/tex]

And if we rewrite this expression we got:

[tex] y= 4x -5[/tex]

If the system have just one solution then we need the slope different and for this reason we can discard the options:

y = 4x-5

-2y = -8x - 10 equivalent to y =4x+5

2y = 8x - 10  equivalent to y = 4x -5

And then the correct answer would be:

y=-4x + 5

Step-by-step explanation:

For this case we have the following equation given:

[tex]4x -y = 5[/tex]

And if we rewrite this expression we got:

[tex] y= 4x -5[/tex]

If the system have just one solution then we need the slope different and for this reason we can discard the options:

y = 4x-5

-2y = -8x - 10 equivalent to y =4x+5

2y = 8x - 10  equivalent to y = 4x -5

And then the correct answer would be:

y=-4x + 5

Answer:

A: y = –4x + 5

Step-by-step explanation:

I got it right on Edge

Answer:

[tex]-30[/tex]

Step-by-step explanation:

[tex]3\frac{3}{5} \times (-8 \frac{1}{3} )[/tex]

[tex]\frac{18}{5}\times \left(-\frac{25}{3}\right)[/tex]

[tex]\frac{18}{5}\times -\frac{25}{3}[/tex]

[tex]-\frac{18\times \:25}{5\times \:3}[/tex]

[tex]-\frac{450}{15}[/tex]

[tex]=-30[/tex]

Answer:-30

Step-by-step explanation:

3 3/5 x -8 1/3

18/5 x -25/3

-30

Answer:

A --- unless d is supposed to be "y= -7x + 2"

Step-by-step explanation:

The slope is m in y=mx + b

So:

a. y= -2x + 11 slope= -2

b. y= x + 4 slope= 1

c. y= -x + 7 slope= -1

d. y= -7 + 2 (I don's see an x but if there were an x I assume that the slope would equal -7)

The higher the m value, the steeper the slope because it is m/1

So, -2/1 is steeper than 1/1 or -1/1

Answer:

I think its 1/9

Answer:

B

Step-by-step explanation:

Answer:

76 cm

Step-by-step explanation:

To find the perimeter, add up all of the side lengths.

18 cm + 26 cm + 32 cm = 76 cm

I hope this helps :))

Answer:

The probability that a senior Physics major and then a sophomore Physics major are chosen at random is 0.0095.

Step-by-step explanation:

The complete question is:

There are 103 students in a physics class. The instructor must choose two students at random.

Students in a Physics Class

Academic Year          Physics majors           Non-Physics majors

Freshmen                              17                                     15

Sophomores                         20                                    14

Juniors                                   11                                      17

Seniors                                   5                                       4

What is the probability that a senior Physics major and then a sophomore Physics major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

Solution:

There are a total of N = 103 students present in a Physics class.

Some of the students are Physics Major and some are not.

The instructor has to select two students at random.

The instructor first selects a senior Physics major and then a sophomore Physics major.

Compute the probability of selecting a senior Physics major student as follows:

[tex]P(\text{Senior Physics Major})=\frac{n(\text{Senior Physics Major}) }{N}[/tex]

                                        [tex]=\frac{5}{103}\\\\=0.04854369\\\\\approx 0.0485[/tex]

Now he two students are selected without replacement.

So, after selecting a senior Physics major student there are 102 students remaining in the class.

Compute the probability of selecting a sophomore Physics major student as follows:

[tex]P(\text{Sophomore Physics Major})=\frac{n(\text{Sophomore Physics Major}) }{N}[/tex]

                                        [tex]=\frac{20}{102}\\\\=0.1960784314\\\\\approx 0.1961[/tex]

Compute the probability that a senior Physics major and then a sophomore Physics major are chosen at random as follows:

[tex]P(\text{Senior}\cap \text{Sophomore})=P(\text{Senior})\times P(\text{Sophomore})[/tex]

                                     [tex]=0.0485\times 0.1961\\\\=0.00951085\\\\\approx 0.0095[/tex]

Thus, the probability that a senior Physics major and then a sophomore Physics major are chosen at random is 0.0095.

Answer:

x=2

Step-by-step explanation:

Original width = 6

New width 6+x+x

Orignal length 12

New length  12+x+x

A = l*w

160 = ( 6+2x) ( 12+2x)

Factor

160 = 2( 3+x) 2(6+x)

Divide each side by 4

40 = (3+x) (6+x)

FOIL

40 = 18+ 6x+3x+ x^2

40 = 18 +9x+x^2

Subtract 40 from each side

0 = x^2 +9x -22

Factor

0 = (x +11) (x-2)

Using the zero product property

x +11 =0   x-2 =0

x= -11   x=2

Since we cannot have a negative  sidewalk

x =2

Answer:

2

Step-by-step explanation:

Original width = 6

New width = 6 + x + x = 6 + 2x

Orignal length = 12

New length = 12 + x + x = 12 + 2x

A = l * w

160 = (6 + 2x)(12 + 2x)

160 = 2(3+x) * 2(6+x)

160 = 4 * (3 + x)(6 + x)

160/4 = (3 + x)(6 + x)

40 = 18 + 6x + 3x + x^2

40 = 18 + 9x + x^2

x^2 + 9x - 22 = 0

= x^2 + 11x - 2x - 22 = 0

= x(x + 11) - 2(x + 11) = 0    

= (x + 11) (x - 2) = 0

x = - 11, 2

Since we cannot have a negative width because it's a dimension,

x = 2 is right

Answer:

1/2

Step-by-step explanation:

Find two points on the line

(2,0) and (4,1)

The slope is given by

m= (y2-y1)/(x2-x1)

   =(1-0)/(4-2)

   = 1/2

Answer:

Step-by-step explanation:

Hello!

So in the refrigerator factory there are three shifts. Each shift records their quality based on the quantity of defective and working parts assembled.

Using a Chi-Square test of independence you have to test the claim that quality and shifts are independent.

The hypotheses are:

H₀: The variables are independent.

H₁: The variables are not independent.

α: 0.05

[tex]X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~X_{(r-1)(c-1)}[/tex]

r= total number of rows

c= total number of columns

i= 1, 2 (categories in rows)

j=1, 2, 3 (categories in columns)

To calculate the statistic you have to calculate the expected frequencies for each category:

[tex]E_{ij}= \frac{O_{i.}*O_{.j}}{n}[/tex]

[tex]O_{i.}[/tex] Represents the marginal value of the i-row

[tex]O_{.j}[/tex] Represents the marginal value of the j-column

[tex]E_{11}= \frac{O_{1.}*O_{.1}}{n}= \frac{21*40}{120}= 7[/tex]

[tex]E_{12}= \frac{O_{1.}*O_{.2}}{n}= \frac{21*40}{120}= 7[/tex]

[tex]E_{13}= \frac{O_{1.}*O_{.3}}{n}= \frac{21*40}{120}= 7[/tex]

[tex]E_{21}= \frac{O_{2.}*O_{.1}}{n}= \frac{99*40}{120}= 33[/tex]

[tex]E_{22}= \frac{O_{2.}*O_{.2}}{n}= \frac{99*40}{120}= 33[/tex]

[tex]E_{23}= \frac{O_{2.}*O_{.3}}{n}= \frac{99*40}{120}= 33[/tex]

[tex]X^2_{H_0}= \frac{(7-7)^2}{7} + \frac{(5-7)^2}{7} + \frac{(9-7)^2}{7} + \frac{(33-33)^2}{33} + \frac{(35-33)^2}{33} + \frac{(31-33)^2}{33} = 1.385= 1.34[/tex]

Using the critical value approach, the rejection region for this test is one-tailed to the right, the critical value is:

[tex]X^2_{(c-1)(r-1);1-\alpha }= X^2_{2; 0.95}= 5.991[/tex]

Decision rule:

If [tex]X^2_{H_0}[/tex] ≥ 5.991, reject the null hypothesis.

If [tex]X^2_{H_0}[/tex] < 5.991, do not reject the null hypothesis.

The value of the statistic is less than the critical value, the decision is to not reject the null hypothesis.

At 5% significance level, you can conclude that the shift the pieces were assembled and the quality of said pieces are independent.

I hope this helps!

Answer:

The mode is 15

Step-by-step explanation:

The mode is the number which appears most often in a set of numbers. Example: in {6, 3, 9, 6, 6, 5, 9, 3} the Mode is 6 (it occurs most often).

Answer:

The mode of this set is 15.

Step-by-step explanation:

the mode is 15 bcoz 15 is repeated two times where as other numbers aren't repeated..

Answer:

[tex]Expected \ mean = \dfrac{sum \ of \ values }{n}[/tex]

[tex]Expected \ mean = \dfrac{315 }{7}[/tex]

Expected mean = 45

The Chi - Square Value = 15.556

Conclusion:

We conclude that there is equal number of average interest in the course across all regions.  

Thus, the CFO is correct, the the frequencies in the regions are not significantly different by using a Chi-Square Goodness of Fit Test with a 1% significance level.

Step-by-step explanation:

From the question; Let state our null hypothesis and alternative hypothesis

Null Hypothesis

[tex]\mathbf{H_0:}[/tex]There is equal number of average interest in the course across all regions.  

Alternative Hypothesis

[tex]\mathbf{H_a:}[/tex] At least one of the region differs in average number of interest in the course.

The table can be better structured as :

Region          Enrollment

1                       45

2                       60

3                       30

4                       40

5                       50

6                       55

7                       35

From above; we know the number of sample = 7

Then our expected mean can be calculated as :

[tex]Expected \ mean = \dfrac{sum \ of \ values }{n}[/tex]

[tex]Expected \ mean = \dfrac{315 }{7}[/tex]

Expected mean = 45

SO, let's construct our Chi-Square  Statistics Test Table as follows:

Observed       Expected       Expected       (O-E)²         [tex]\dfrac{(O-E)^2}{E}[/tex]

(O)                         (E)            proportion    

45                          45           0.142857          0                   0

60                          45           0.142857       225                 5

30                          45           0.142857        225                5

40                          45           0.142857          25               0.556

50                          45           0.142857          25               0.556

55                          45           0.142857         100               2.222

35                          45           0.142857          100              2.222

                                                                                          15.556

The Chi - Square Value = 15.556

Degree of freedom = n- 1

Degree of freedom = 7 - 1

Degree of freedom = 6

Level of significance ∝ = 1% = 0.01

The Critical value of Chi Square test statistic at df = 6 and 0.01 significance level is 16.812

The Decision rule is to reject the Null hypothesis if The Chi Square test statistic X² > 16.812

Thus , since  the Chi Square test statistic is lesser than the critical value,

i.e  15.556 < 16.812 ,we accept null hypothesis [tex]\mathbf{H_0}[/tex]

Conclusion:

We conclude that there is equal number of average interest in the course across all regions.  

Thus, the CFO is correct, the the frequencies in the regions are not significantly different by using a Chi-Square Goodness of Fit Test with a 1% significance level.

Answer: [tex]y=\frac{3}{2} x - 3[/tex]

Step-by-step explanation:

Looking at the  graph we could locate the y intercept at point (0,-3)  and we can locate another point (4,3) which also passes through the line.  So using these coordinates we already know the the y-intercept as -3 but we need to find the slope to write it in slope intercept form.

To find the slope, we will need to find the difference in the y values and divide it by the difference in the x values.

(0,-3)

(4,3)

-3 - 3 = -6

0-4 =  -4  

-6 /-4 =  3/2   so now we know that the slope is 3 over 2  

so we could write the equation as   y = 3/2x -3  

Answer: Thank you (nermay7)

Step-by-step explanation: They are correct!!!!!!!

Answer: 2

Step-by-step explanation:

9 × 2 - 16

18 - 16

2

Answer:

[tex] \frac{1}{9 - 4i} [/tex]

I'm not sure

Answer:

The probability of choosing a heart and not a club is

P =  0.1875

Step-by-step explanation:

There are 13 hearts in a deck of 52 cards. The probability that the chosen card will be a heart is given by

Probability = favorable outcome/ Total number of outcomes

P= 13/52= 1/4

There are 13 clubs in a deck of 52 cards.

The probability of not choosing a club would be

P = 52-13/52= 39/52= 3/4

So the  combined probability of choosing a heart and not a club is

P = 1/4 * 3/4= 0.25 * 0.75= 0.1875

Answer:ab

Step-by-step explanation:3-9=-6 +7=1 1ab also equals just ab

Answer:

Since its adding and subtracting just add the coefficients of similar terms (coefficient is the number in front, term is the coefficient. and variables, similar terms are terms that have the same variables)  

3ab-9ab+7ab

3-9=-6: -6ab+7ab

-6+7=1: 1ab or ab :)

Answer:

The unit circle centered at the origin in the Euclidean plane is defined by the equation:

[tex]x^2+y^2=1\\[/tex]

Given an angle , there is a unique point P on the unit circle at an angle θ from the x-axis, and the x- and y-coordinates of P are:

[tex]x=cos \theta \\y = sin \theta[/tex]

Consequently, from the equation for the unit circle:

[tex]cos^2\theta+sin^2\theta=1[/tex]  

the Pythagorean identity.

Answer:

The probability that at least one defective card appears in the sample

P(D) = 0.9644 or 96.44%

Step-by-step explanation:

Given;

Total number of cards t = 140

Number of defective cards = 20

Number of non defective cards x = 140-20 = 120

The probability that at least one defective card = 1 - The probability that none none is defective

P(D) = 1 - P(N) ........1

For 20 selections; r = 20

-- 20 cards are selected from the lot without replacement for functional testing

The probability that none none is defective is;

P(N) = (xPr)/(tPr)

P(N) = (120P20)/(140P20)

P(N) = (120!/(120-20)!)/(140!/(140-20)!)

P(N) = (120!/100!)/(140!/120!) = 0.035618370821

P(N) = 0.0356

The probability that at least one defective card appears in the sample is;

P(D) = 1 - P(N) = 1 - 0.0356 = 0.9644

P(D) = 0.9644 or 96.44%

Note: xPr = x permutation r